{"id":2352,"date":"2019-05-13T12:40:18","date_gmt":"2019-05-13T12:40:18","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/?post_type=chapter&#038;p=2352"},"modified":"2019-05-13T12:41:13","modified_gmt":"2019-05-13T12:41:13","slug":"2-7-section-exercises","status":"web-only","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/chapter\/2-7-section-exercises\/","title":{"raw":"2.7 Section Exercises","rendered":"2.7 Section Exercises"},"content":{"raw":"<div class=\"textbox exercises\">\r\n<h3>2.7 Section Exercises<\/h3>\r\n<div class=\"bc-section section\">\r\n<h4>Verbal<\/h4>\r\n<div id=\"fs-id1165134047581\">\r\n<div id=\"fs-id1165134047584\">\r\n\r\n1. With what kind of exponential model would <em>half-life<\/em> be associated? What role does half-life play in these models?\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135487320\">[reveal-answer q=\"fs-id1165135487320\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135487320\"]\r\n<p id=\"fs-id1165135487321\">Half-life is a measure of decay and is thus associated with exponential decay models. The half-life of a substance or quantity is the amount of time it takes for half of the initial amount of that substance or quantity to decay.<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135487327\">\r\n<div id=\"fs-id1165135487330\">\r\n<p id=\"fs-id1165135487331\">2. What is carbon dating? Why does it work? Give an example in which carbon dating would be useful.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135487336\">\r\n<div id=\"fs-id1165135487338\">\r\n\r\n3. With what kind of exponential model would <em>doubling time<\/em> be associated? What role does doubling time play in these models?\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135177642\">[reveal-answer q=\"fs-id1165135177642\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135177642\"]\r\n<p id=\"fs-id1165135177644\">Doubling time is a measure of growth and is thus associated with exponential growth models. The doubling time of a substance or quantity is the amount of time it takes for the initial amount of that substance or quantity to double in size.<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div>\r\n<div>\r\n<p id=\"fs-id1165135177653\">4. Define Newton\u2019s Law of Cooling. Then name at least three real-world situations where Newton\u2019s Law of Cooling would be applied.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135177660\">\r\n<div id=\"fs-id1165135177662\">\r\n\r\n5. What is an order of magnitude? Why are orders of magnitude useful? Give an example to explain.\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135500868\">[reveal-answer q=\"fs-id1165135500868\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135500868\"]\r\n<p id=\"fs-id1165135500869\">An order of magnitude is the nearest power of ten by which a quantity exponentially grows. It is also an approximate position on a logarithmic scale; Sample response: Orders of magnitude are useful when making comparisons between numbers that differ by a great amount. For example, the mass of Saturn is 95 times greater than the mass of Earth. This is the same as saying that the mass of Saturn is about[latex]\\text{ }{10}^{\\text{2}}\\text{ }[\/latex]times, or <em>2 orders of magnitude<\/em> greater, than the mass of Earth.<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135448286\" class=\"bc-section section\">\r\n<h4>Numeric<\/h4>\r\n<div id=\"fs-id1165135448291\">\r\n<div id=\"fs-id1165135448292\">\r\n<p id=\"fs-id1165135448293\">6. The temperature of an object in degrees Fahrenheit after <em>t <\/em>minutes is represented by the equation[latex]\\text{ }T\\left(t\\right)=68{e}^{-0.0174t}+72.\\text{ }[\/latex]To the nearest degree, what is the temperature of the object after one and a half hours?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"fs-id1165135524408\">For the following exercises, use the logistic growth model[latex]\\text{ }f\\left(x\\right)=\\frac{150}{1+8{e}^{-2x}}.[\/latex]<\/p>\r\n\r\n<div id=\"fs-id1165134275330\">\r\n<div id=\"fs-id1165134275332\">\r\n<p id=\"fs-id1165134275333\">7. Find and interpret[latex]\\text{ }f\\left(0\\right).\\text{ }[\/latex]Round to the nearest tenth.<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135540046\">[reveal-answer q=\"fs-id1165135540046\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135540046\"]\r\n<p id=\"fs-id1165135540047\">[latex]f\\left(0\\right)\\approx 16.7;\\text{ }[\/latex]The amount initially present is about 16.7 units.<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165134350359\">\r\n<div id=\"fs-id1165134350361\">\r\n<p id=\"fs-id1165134350362\">8. Find and interpret[latex]\\text{ }f\\left(4\\right).\\text{ }[\/latex]Round to the nearest tenth.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165134350316\">\r\n<div id=\"fs-id1165134350318\">\r\n<p id=\"fs-id1165134350319\">9. Find the carrying capacity.<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165134256674\">[reveal-answer q=\"fs-id1165134256674\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165134256674\"]\r\n<p id=\"fs-id1165134256675\">150<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165134256679\">\r\n<div id=\"fs-id1165134256681\">\r\n<p id=\"fs-id1165134256682\">10. Graph the model.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165134256686\">\r\n<div id=\"fs-id1165134256688\">\r\n<p id=\"fs-id1165134256690\">11. Determine whether the data from the table could best be represented as a function that is linear, exponential, or logarithmic. Then write a formula for a model that represents the data.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165134256696\">\r\n<div id=\"fs-id1165134256698\">\r\n<table id=\"fs-id1165135415770\" class=\"unnumbered\" summary=\"..\">\r\n<tbody>\r\n<tr>\r\n<td class=\"border\"><strong>[latex]x[\/latex]<\/strong><\/td>\r\n<td class=\"border\"><strong>[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">\u20132<\/td>\r\n<td class=\"border\">0.694<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">\u20131<\/td>\r\n<td class=\"border\">0.833<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">0<\/td>\r\n<td class=\"border\">1<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">1<\/td>\r\n<td class=\"border\">1.2<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">2<\/td>\r\n<td class=\"border\">1.44<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">3<\/td>\r\n<td class=\"border\">1.728<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">4<\/td>\r\n<td class=\"border\">2.074<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">5<\/td>\r\n<td class=\"border\">2.488<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<div id=\"fs-id1165134054878\">[reveal-answer q=\"fs-id1165134054878\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165134054878\"]\r\n<p id=\"fs-id1165134054879\">exponential;[latex]\\text{ }f\\left(x\\right)={1.2}^{x}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137762564\">\r\n<div id=\"fs-id1165135309860\">\r\n<p id=\"fs-id1165135309863\">12. Rewrite[latex]\\text{ }f\\left(x\\right)=1.68{\\left(0.65\\right)}^{x}\\text{ }[\/latex]as an exponential equation with base[latex]\\text{ }e\\text{ }[\/latex]to five significant digits.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135154332\" class=\"bc-section section\">\r\n<h4>Technology<\/h4>\r\n<p id=\"fs-id1165135403321\">For the following exercises, enter the data from each table into a graphing calculator and graph the resulting scatter plots. Determine whether the data from the table could represent a function that is linear, exponential, or logarithmic.<\/p>\r\n\r\n<div>\r\n<div id=\"fs-id1165135403328\">\r\n\r\n13.\r\n<table id=\"fs-id1165135403332\" class=\"unnumbered\" summary=\"..\">\r\n<tbody>\r\n<tr>\r\n<td class=\"border\"><strong>[latex]x[\/latex]<\/strong><\/td>\r\n<td class=\"border\"><strong>[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">1<\/td>\r\n<td class=\"border\">2<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">2<\/td>\r\n<td class=\"border\">4.079<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">3<\/td>\r\n<td class=\"border\">5.296<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">4<\/td>\r\n<td class=\"border\">6.159<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">5<\/td>\r\n<td class=\"border\">6.828<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">6<\/td>\r\n<td class=\"border\">7.375<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">7<\/td>\r\n<td class=\"border\">7.838<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">8<\/td>\r\n<td class=\"border\">8.238<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">9<\/td>\r\n<td class=\"border\">8.592<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">10<\/td>\r\n<td class=\"border\">8.908<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<div id=\"fs-id1165137836553\">[reveal-answer q=\"fs-id1165137836553\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137836553\"]\r\n<p id=\"fs-id1165137836554\">logarithmic<\/p>\r\n<span id=\"fs-id1165137836562\"><img class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3896\/2019\/03\/07131446\/CNX_PreCalc_Figure_04_07_201.jpg\" alt=\"Graph of the question\u2019s table.\" width=\"233\" height=\"237\" \/><\/span>[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137836576\">\r\n<div id=\"fs-id1165135332894\">\r\n\r\n14.\r\n<table id=\"fs-id1165135332896\" class=\"unnumbered\" summary=\"..\">\r\n<tbody>\r\n<tr>\r\n<td class=\"border\"><strong>[latex]x[\/latex]<\/strong><\/td>\r\n<td class=\"border\"><strong>[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">1<\/td>\r\n<td class=\"border\">2.4<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">2<\/td>\r\n<td class=\"border\">2.88<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">3<\/td>\r\n<td class=\"border\">3.456<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">4<\/td>\r\n<td class=\"border\">4.147<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">5<\/td>\r\n<td class=\"border\">4.977<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">6<\/td>\r\n<td class=\"border\">5.972<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">7<\/td>\r\n<td class=\"border\">7.166<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">8<\/td>\r\n<td class=\"border\">8.6<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">9<\/td>\r\n<td class=\"border\">10.32<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">10<\/td>\r\n<td class=\"border\">12.383<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<\/div>\r\n<div>\r\n<div id=\"eip-id1165135393396\">\r\n\r\n15.\r\n<table id=\"eip-id1165135393398\" class=\"unnumbered\" summary=\"..\">\r\n<tbody>\r\n<tr>\r\n<td class=\"border\"><strong>[latex]x[\/latex]<\/strong><\/td>\r\n<td class=\"border\"><strong>[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">4<\/td>\r\n<td class=\"border\">9.429<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">5<\/td>\r\n<td class=\"border\">9.972<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">6<\/td>\r\n<td class=\"border\">10.415<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">7<\/td>\r\n<td class=\"border\">10.79<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">8<\/td>\r\n<td class=\"border\">11.115<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">9<\/td>\r\n<td class=\"border\">11.401<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">10<\/td>\r\n<td class=\"border\">11.657<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">11<\/td>\r\n<td class=\"border\">11.889<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">12<\/td>\r\n<td class=\"border\">12.101<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">13<\/td>\r\n<td class=\"border\">12.295<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<div id=\"fs-id1165134342556\">[reveal-answer q=\"fs-id1165134342556\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165134342556\"]\r\n<p id=\"fs-id1165134342557\">logarithmic<\/p>\r\n<span id=\"fs-id1165134342565\"><img class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3896\/2019\/03\/07131451\/CNX_PreCalc_Figure_04_07_203.jpg\" alt=\"Graph of the question\u2019s table.\" width=\"207\" height=\"309\" \/><\/span>[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135532481\">\r\n<div id=\"fs-id1165135532483\">\r\n\r\n16.\r\n<table id=\"fs-id1165135532486\" class=\"unnumbered\" summary=\"..\">\r\n<tbody>\r\n<tr>\r\n<td class=\"border\"><strong>[latex]x[\/latex]<\/strong><\/td>\r\n<td class=\"border\"><strong>[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">1.25<\/td>\r\n<td class=\"border\">5.75<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">2.25<\/td>\r\n<td class=\"border\">8.75<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">3.56<\/td>\r\n<td class=\"border\">12.68<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">4.2<\/td>\r\n<td class=\"border\">14.6<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">5.65<\/td>\r\n<td class=\"border\">18.95<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">6.75<\/td>\r\n<td class=\"border\">22.25<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">7.25<\/td>\r\n<td class=\"border\">23.75<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">8.6<\/td>\r\n<td class=\"border\">27.8<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">9.25<\/td>\r\n<td class=\"border\">29.75<\/td>\r\n<\/tr>\r\n<tr>\r\n<td class=\"border\">10.5<\/td>\r\n<td class=\"border\">33.5<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<\/div>\r\n<p id=\"fs-id1165135678730\">For the following exercises, use a graphing calculator and this scenario: the population of a fish farm in[latex]\\text{ }t\\text{ }[\/latex]years is modeled by the equation[latex]\\text{ }P\\left(t\\right)=\\frac{1000}{1+9{e}^{-0.6t}}.[\/latex]<\/p>\r\n\r\n<div>\r\n<div id=\"fs-id1165137611545\">\r\n\r\n17. Graph the function.\r\n\r\n<\/div>\r\n<div id=\"fs-id1165137611549\">[reveal-answer q=\"fs-id1165137611549\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137611549\"]<span id=\"fs-id1165137611556\"><img class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3896\/2019\/03\/07131455\/CNX_PreCalc_Figure_04_07_205.jpg\" alt=\"Graph of P(t)=1000\/(1+9e^(-0.6t))\" width=\"132\" height=\"148\" \/><\/span>[\/hidden-answer]<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165134275365\">\r\n<div id=\"fs-id1165134275367\">\r\n<p id=\"fs-id1165134275368\">18. What is the initial population of fish?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165134275373\">\r\n<div id=\"fs-id1165134275375\">\r\n<p id=\"fs-id1165134275376\">19. To the nearest tenth, what is the doubling time for the fish population?<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165134275379\">[reveal-answer q=\"fs-id1165134275379\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165134275379\"]\r\n<p id=\"fs-id1165134275380\">about[latex]\\text{ }1.4\\text{ }[\/latex]years<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135358889\">\r\n<div id=\"fs-id1165135358892\">\r\n<p id=\"fs-id1165135358893\">20. To the nearest whole number, what will the fish population be after[latex]\\text{ }2\\text{ }[\/latex]years?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135699221\">\r\n<div id=\"fs-id1165135699223\">\r\n<p id=\"fs-id1165135699224\">21. To the nearest tenth, how long will it take for the population to reach[latex]\\text{ }900?[\/latex]<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165137647572\">[reveal-answer q=\"fs-id1165137647572\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137647572\"]\r\n<p id=\"fs-id1165137647573\">about[latex]\\text{ }7.3\\text{ }[\/latex]years<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137647593\">\r\n<div id=\"fs-id1165135404200\">\r\n<p id=\"fs-id1165135404201\">22. What is the carrying capacity for the fish population? Justify your answer using the graph of[latex]\\text{ }P.[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135404218\" class=\"bc-section section\">\r\n<h4>Extensions<\/h4>\r\n<div id=\"fs-id1165135404224\">\r\n<div id=\"fs-id1165137589535\">\r\n<p id=\"fs-id1165137589536\">23. A substance has a half-life of 2.045 minutes. If the initial amount of the substance was 132.8 grams, how many half-lives will have passed before the substance decays to 8.3 grams? What is the total time of decay?<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165137589542\">[reveal-answer q=\"fs-id1165137589542\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137589542\"]\r\n<p id=\"fs-id1165137589543\">[latex]4\\text{ }[\/latex]half-lives;[latex]\\text{ }8.18\\text{ }[\/latex]minutes<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135169175\">\r\n<div id=\"fs-id1165135169177\">\r\n<p id=\"fs-id1165135169178\">24. The formula for an increasing population is given by[latex]\\text{ }P\\left(t\\right)={P}_{0}{e}^{rt}\\text{ }[\/latex]where[latex]\\text{ }{P}_{0}\\text{ }[\/latex]is the initial population and[latex]\\text{ }r&gt;0.\\text{ }[\/latex]Derive a general formula for the time <em>t<\/em> it takes for the population to increase by a factor of <em>M<\/em>.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135543184\">\r\n<div id=\"fs-id1165135543186\">\r\n<p id=\"fs-id1165135543188\">25. Recall the formula for calculating the magnitude of an earthquake,[latex]\\text{ }M=\\frac{2}{3}\\mathrm{log}\\left(\\frac{S}{{S}_{0}}\\right).[\/latex] Show each step for solving this equation algebraically for the seismic moment[latex]\\text{ }S.[\/latex]<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135208571\">[reveal-answer q=\"fs-id1165135208571\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135208571\"]\r\n<p id=\"fs-id1165135208572\">[latex]\\begin{array}{l}\\text{ }M=\\frac{2}{3}\\mathrm{log}\\left(\\frac{S}{{S}_{0}}\\right)\\hfill \\\\ \\mathrm{log}\\left(\\frac{S}{{S}_{0}}\\right)=\\frac{3}{2}M\\hfill \\\\ \\text{ }\\frac{S}{{S}_{0}}={10}^{\\frac{3M}{2}}\\hfill \\\\ \\text{ }S={S}_{0}{10}^{\\frac{3M}{2}}\\hfill \\end{array}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137476953\">\r\n<div id=\"fs-id1165137476955\">\r\n<p id=\"fs-id1165137476956\">26. What is the <em>y<\/em>-intercept of the logistic growth model[latex]\\text{ }y=\\frac{c}{1+a{e}^{-rx}}?\\text{ }[\/latex]Show the steps for calculation. What does this point tell us about the population?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165134056896\">\r\n<div id=\"fs-id1165134056898\">\r\n<p id=\"fs-id1165134056899\">27. Prove that[latex]\\text{ }{b}^{x}={e}^{x\\mathrm{ln}\\left(b\\right)}\\text{ }[\/latex]for positive[latex]\\text{ }b\\ne 1.[\/latex]<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135555464\">[reveal-answer q=\"fs-id1165135555464\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135555464\"]\r\n<p id=\"fs-id1165135555466\">Let[latex]\\text{ }y={b}^{x}\\text{ }[\/latex]for some non-negative real number[latex]\\text{ }b\\text{ }[\/latex]such that[latex]\\text{ }b\\ne 1.\\text{ }[\/latex]Then,<\/p>\r\n<p id=\"eip-id1165135332843\">[latex]\\begin{array}{l}\\mathrm{ln}\\left(y\\right)=\\mathrm{ln}\\left({b}^{x}\\right)\\hfill \\\\ \\mathrm{ln}\\left(y\\right)=x\\mathrm{ln}\\left(b\\right)\\hfill \\\\ {e}^{\\mathrm{ln}\\left(y\\right)}={e}^{x\\mathrm{ln}\\left(b\\right)}\\hfill \\\\ y={e}^{x\\mathrm{ln}\\left(b\\right)}\\hfill \\end{array}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135456884\" class=\"bc-section section\">\r\n<h4>Real-World Applications<\/h4>\r\n<p id=\"fs-id1165137740750\">For the following exercises, use this scenario: A doctor prescribes 125 milligrams of a therapeutic drug that decays by about 30% each hour.<\/p>\r\n\r\n<div id=\"fs-id1165137740755\">\r\n<div id=\"fs-id1165137740757\">\r\n<p id=\"fs-id1165137740759\">28. To the nearest hour, what is the half-life of the drug?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"Exercise_04_07_030\">\r\n<div id=\"fs-id1165137740769\">\r\n\r\n29. Write an exponential model representing the amount of the drug remaining in the patient\u2019s system after[latex]\\text{ }t\\text{ }[\/latex]hours. Then use the formula to find the amount of the drug that would remain in the patient\u2019s system after 3 hours. Round to the nearest milligram.\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135440471\">[reveal-answer q=\"fs-id1165135440471\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135440471\"]\r\n<p id=\"fs-id1165135440472\">[latex]A=125{e}^{\\left(-0.3567t\\right)};A\\approx 43\\text{ }[\/latex]mg<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137823258\">\r\n<div id=\"fs-id1165135459770\">\r\n<p id=\"fs-id1165135459771\">30. Using the model found in the previous exercise, find[latex]\\text{ }f\\left(10\\right)\\text{ }[\/latex]and interpret the result. Round to the nearest hundredth.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"fs-id1165135530652\">For the following exercises, use this scenario: A tumor is injected with[latex]\\text{ }0.5\\text{ }[\/latex]grams of Iodine-125, which has a decay rate of[latex]\\text{ }1.15%\\text{ }[\/latex]per day.<\/p>\r\n\r\n<div id=\"fs-id1165135532373\">\r\n<div id=\"fs-id1165135532375\">\r\n<p id=\"fs-id1165135532376\">31. To the nearest day, how long will it take for half of the Iodine-125 to decay?<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135532379\">[reveal-answer q=\"fs-id1165135532379\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135532379\"]\r\n<p id=\"fs-id1165135532380\">about[latex]\\text{ }60\\text{ }[\/latex]days<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"Exercise_04_07_033\">\r\n<div id=\"fs-id1165134306669\">\r\n<p id=\"fs-id1165134306670\">32. Write an exponential model representing the amount of Iodine-125 remaining in the tumor after[latex]\\text{ }t\\text{ }[\/latex]days. Then use the formula to find the amount of Iodine-125 that would remain in the tumor after 60 days. Round to the nearest tenth of a gram.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"Exercise_04_07_034\">\r\n<div id=\"fs-id1165135678596\">\r\n<p id=\"fs-id1165135678598\">33. A scientist begins with[latex]\\text{ }\\text{250}\\text{ }[\/latex]grams of a radioactive substance. After[latex]\\text{ }\\text{250}\\text{ }[\/latex]minutes, the sample has decayed to[latex]\\text{ }\\text{32}\\text{ }[\/latex]grams. Rounding to five significant digits, write an exponential equation representing this situation. To the nearest minute, what is the half-life of this substance?<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165134069337\">[reveal-answer q=\"fs-id1165134069337\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165134069337\"]\r\n<p id=\"fs-id1165134069338\">[latex]f\\left(t\\right)=250{e}^{\\left(-0.00914t\\right)};\\text{ }[\/latex]half-life: about[latex]\\text{ }\\text{76}\\text{ }[\/latex]minutes<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137749954\">\r\n<div id=\"fs-id1165137749956\">\r\n\r\n34. The half-life of Radium-226 is[latex]\\text{ }1590\\text{ }[\/latex]years. What is the annual decay rate? Express the decimal result to four significant digits and the percentage to two significant digits.\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137656769\">\r\n<div id=\"fs-id1165137656771\">\r\n<p id=\"fs-id1165137656772\">35. The half-life of Erbium-165 is[latex]\\text{ }\\text{10}\\text{.4}\\text{ }[\/latex]hours. What is the hourly decay rate? Express the decimal result to four significant digits and the percentage to two significant digits.<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165137851455\">[reveal-answer q=\"fs-id1165137851455\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137851455\"]\r\n<p id=\"fs-id1165137851456\">[latex]r\\approx -0.0667,[\/latex] So the hourly decay rate is about[latex]\\text{ }6.67%[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135508223\">\r\n<div id=\"fs-id1165135508226\">\r\n<p id=\"fs-id1165135508227\">36. A wooden artifact from an archeological dig contains 60 percent of the carbon-14 that is present in living trees. To the nearest year, about how many years old is the artifact? (The half-life of carbon-14 is[latex]\\text{ }\\text{573}0\\text{ }[\/latex]years.)<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"Exercise_04_07_038\">\r\n<div id=\"fs-id1165137400153\">\r\n<p id=\"fs-id1165135191027\">37. A research student is working with a culture of bacteria that doubles in size every twenty minutes. The initial population count was[latex]\\text{ }1350\\text{ }[\/latex]bacteria. Rounding to five significant digits, write an exponential equation representing this situation. To the nearest whole number, what is the population size after[latex]\\text{ 3 }[\/latex]hours?<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135306876\">[reveal-answer q=\"fs-id1165135306876\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135306876\"]\r\n<p id=\"fs-id1165135306878\">[latex]f\\left(t\\right)=1350{e}^{\\left(0.03466t\\right)};\\text{ }[\/latex]after 3 hours:[latex]\\text{ }P\\left(180\\right)\\approx 691,200[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"fs-id1165135339542\">For the following exercises, use this scenario: A biologist recorded a count of[latex]\\text{ }360\\text{ }[\/latex]bacteria present in a culture after[latex]\\text{ }5\\text{ }[\/latex]minutes and[latex]\\text{ }1000\\text{ }[\/latex]bacteria present after[latex]\\text{ }20\\text{ }[\/latex]minutes.<\/p>\r\n\r\n<div id=\"fs-id1165135189888\">\r\n<div id=\"fs-id1165137834291\">\r\n<p id=\"fs-id1165137834292\">38. To the nearest whole number, what was the initial population in the culture?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137834297\">\r\n<div id=\"fs-id1165137834299\">\r\n<p id=\"fs-id1165137834300\">39. Rounding to six significant digits, write an exponential equation representing this situation. To the nearest minute, how long did it take the population to double?<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165137834305\">[reveal-answer q=\"fs-id1165137834305\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137834305\"]\r\n<p id=\"fs-id1165137834306\">[latex]f\\left(t\\right)=256{e}^{\\left(0.068110t\\right)};\\text{ }[\/latex]doubling time: about[latex]\\text{ }10\\text{ }[\/latex]minutes<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"fs-id1165134108595\">For the following exercises, use this scenario: A pot of boiling soup with an internal temperature of[latex]\\text{ }\\text{100\u00b0}\\text{ }[\/latex]Fahrenheit was taken off the stove to cool in a[latex]\\text{ }\\text{69\u00b0 F}\\text{ }[\/latex]room. After fifteen minutes, the internal temperature of the soup was[latex]\\text{ }\\text{95\u00b0 F}\\text{.}[\/latex]<\/p>\r\n\r\n<div>\r\n<div>\r\n<p id=\"fs-id1165137642591\">40. Use Newton\u2019s Law of Cooling to write a formula that models this situation.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137642597\">\r\n<div id=\"fs-id1165137642599\">\r\n<p id=\"fs-id1165137642600\">41. To the nearest minute, how long will it take the soup to cool to[latex]\\text{ }\\text{80\u00b0 F?}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135536453\">[reveal-answer q=\"fs-id1165135536453\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135536453\"]\r\n<p id=\"fs-id1165135536454\">about[latex]\\text{ }\\text{88}\\text{ }[\/latex]minutes<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135252212\">\r\n<div id=\"fs-id1165135252213\">\r\n<p id=\"fs-id1165135252214\">42. To the nearest degree, what will the temperature be after[latex]\\text{ }2\\text{ }[\/latex]and a half hours?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"fs-id1165135353712\">For the following exercises, use this scenario: A turkey is taken out of the oven with an internal temperature of[latex]\\text{ }\\text{165\u00b0F}\\text{ }[\/latex] and is allowed to cool in a[latex]\\text{ }\\text{75\u00b0F}\\text{ }[\/latex]room. After half an hour, the internal temperature of the turkey is[latex]\\text{ }\\text{145\u00b0F}\\text{.}[\/latex]<\/p>\r\n\r\n<div id=\"fs-id1165135503869\">\r\n<div id=\"fs-id1165135503871\">\r\n<p id=\"fs-id1165135503872\">43. Write a formula that models this situation.<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135503876\">[reveal-answer q=\"fs-id1165135503876\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135503876\"]\r\n<p id=\"fs-id1165135503877\">[latex]T\\left(t\\right)=90{e}^{\\left(-0.008377t\\right)}+75,[\/latex] where[latex]\\text{ }t\\text{ }[\/latex]is in minutes.<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165134130934\">\r\n<div id=\"fs-id1165134130937\">\r\n<p id=\"fs-id1165134130938\">44. To the nearest degree, what will the temperature be after 50 minutes?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165134130942\">\r\n<div id=\"fs-id1165134394566\">\r\n<p id=\"fs-id1165134394567\">45. To the nearest minute, how long will it take the turkey to cool to[latex]\\text{ }\\text{110\u00b0 F?}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165134394590\">[reveal-answer q=\"fs-id1165134394590\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165134394590\"]\r\n<p id=\"fs-id1165134394591\">about[latex]\\text{ }\\text{113}\\text{ }[\/latex]minutes<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"fs-id1165137580701\">For the following exercises, find the value of the number shown on each logarithmic scale. Round all answers to the nearest thousandth.<\/p>\r\n\r\n<div id=\"fs-id1165137580706\">\r\n<div id=\"fs-id1165137580708\"><span id=\"fs-id1165137428096\">46.\u00a0<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3896\/2019\/03\/07131458\/CNX_PreCalc_Figure_04_07_206.jpg\" alt=\"Number line to show log(x) is between -1 and 0.\" \/><\/span><\/div>\r\n<\/div>\r\n<div id=\"fs-id1165137428110\">\r\n<div id=\"fs-id1165137428113\"><span id=\"fs-id1165134085824\">47.\u00a0<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3896\/2019\/03\/07131501\/CNX_PreCalc_Figure_04_07_207.jpg\" alt=\"Number line to show log(x) is between 1 and 2.\" \/><\/span><\/div>\r\n<div id=\"fs-id1165134085837\">[reveal-answer q=\"fs-id1165134085837\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165134085837\"]\r\n<p id=\"fs-id1165134085838\">[latex]\\mathrm{log}\\left(x\\right)=1.5;\\text{ }x\\approx 31.623[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135395316\">\r\n<div id=\"fs-id1165135395318\">\r\n<p id=\"fs-id1165135395320\">48. Plot each set of approximate values of intensity of sounds on a logarithmic scale: Whisper:[latex]\\text{ }{10}^{-10} \\frac{W}{{m}^{2}},[\/latex]Vacuum:[latex]\\text{ }{10}^{-4}\\frac{W}{{m}^{2}},[\/latex]Jet:[latex]\\text{ }{10}^{2} \\frac{W}{{m}^{2}}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165134486756\">\r\n<div>\r\n<p id=\"fs-id1165134486760\">49. Recall the formula for calculating the magnitude of an earthquake,[latex]\\text{ }M=\\frac{2}{3}\\mathrm{log}\\left(\\frac{S}{{S}_{0}}\\right).\\text{ }[\/latex]One earthquake has magnitude[latex]\\text{ }\\text{3}.\\text{9}\\text{ }[\/latex]on the MMS scale. If a second earthquake has[latex]\\text{ }\\text{75}0\\text{ }[\/latex]times as much energy as the first, find the magnitude of the second quake. Round to the nearest hundredth.<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165135517147\">[reveal-answer q=\"fs-id1165135517147\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135517147\"]\r\n<p id=\"fs-id1165135517148\">MMS magnitude:[latex]\\text{ }5.82[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"fs-id1165135517163\">For the following exercises, use this scenario: The equation[latex]\\text{ }N\\left(t\\right)=\\frac{500}{1+49{e}^{-0.7t}}\\text{ }[\/latex]models the number of people in a town who have heard a rumor after <em>t<\/em> days.<\/p>\r\n\r\n<div id=\"fs-id1165135332961\">\r\n<div id=\"fs-id1165135332963\">\r\n<p id=\"fs-id1165135332964\">50. How many people started the rumor?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165135332968\">\r\n<div id=\"fs-id1165134059773\">\r\n<p id=\"fs-id1165134059774\">51. To the nearest whole number, how many people will have heard the rumor after 3 days?<\/p>\r\n\r\n<\/div>\r\n<div id=\"fs-id1165134059778\">[reveal-answer q=\"fs-id1165134059778\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165134059778\"]\r\n<p id=\"fs-id1165134059779\">[latex]N\\left(3\\right)\\approx 71[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"fs-id1165134106004\">\r\n<div>\r\n\r\n52. As[latex]\\text{ }t\\text{ }[\/latex]increases without bound, what value does[latex]\\text{ }N\\left(t\\right)\\text{ }[\/latex]approach? Interpret your answer.\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"eip-137\">For the following exercise, choose the correct answer choice.<\/p>\r\n\r\n<div id=\"fs-id1165135689474\">\r\n<div id=\"fs-id1165135689476\">\r\n<p id=\"fs-id1165135689477\">53. A doctor and injects a patient with[latex]\\text{ }13\\text{ }[\/latex]milligrams of radioactive dye that decays exponentially. After[latex]\\text{ }12\\text{ }[\/latex]minutes, there are[latex]\\text{ }4.75\\text{ }[\/latex]milligrams of dye remaining in the patient\u2019s system. Which is an appropriate model for this situation?<\/p>\r\n\r\n<ol type=\"A\">\r\n \t<li>[latex]f\\left(t\\right)=13{\\left(0.0805\\right)}^{t}[\/latex]<\/li>\r\n \t<li>[latex]f\\left(t\\right)=13{e}^{0.9195t}[\/latex]<\/li>\r\n \t<li>[latex]f\\left(t\\right)=13{e}^{\\left(-0.0839t\\right)}[\/latex]<\/li>\r\n \t<li>[latex]f\\left(t\\right)=\\frac{4.75}{1+13{e}^{-0.83925t}}[\/latex]<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"fs-id1165137835581\">[reveal-answer q=\"fs-id1165137835581\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137835581\"]\r\n<p id=\"fs-id1165137835582\">C<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n&nbsp;","rendered":"<div class=\"textbox exercises\">\n<h3>2.7 Section Exercises<\/h3>\n<div class=\"bc-section section\">\n<h4>Verbal<\/h4>\n<div id=\"fs-id1165134047581\">\n<div id=\"fs-id1165134047584\">\n<p>1. With what kind of exponential model would <em>half-life<\/em> be associated? What role does half-life play in these models?<\/p>\n<\/div>\n<div id=\"fs-id1165135487320\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165135487320\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165135487320\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165135487321\">Half-life is a measure of decay and is thus associated with exponential decay models. The half-life of a substance or quantity is the amount of time it takes for half of the initial amount of that substance or quantity to decay.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135487327\">\n<div id=\"fs-id1165135487330\">\n<p id=\"fs-id1165135487331\">2. What is carbon dating? Why does it work? Give an example in which carbon dating would be useful.<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135487336\">\n<div id=\"fs-id1165135487338\">\n<p>3. With what kind of exponential model would <em>doubling time<\/em> be associated? What role does doubling time play in these models?<\/p>\n<\/div>\n<div id=\"fs-id1165135177642\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165135177642\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165135177642\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165135177644\">Doubling time is a measure of growth and is thus associated with exponential growth models. The doubling time of a substance or quantity is the amount of time it takes for the initial amount of that substance or quantity to double in size.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div>\n<div>\n<p id=\"fs-id1165135177653\">4. Define Newton\u2019s Law of Cooling. Then name at least three real-world situations where Newton\u2019s Law of Cooling would be applied.<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135177660\">\n<div id=\"fs-id1165135177662\">\n<p>5. What is an order of magnitude? Why are orders of magnitude useful? Give an example to explain.<\/p>\n<\/div>\n<div id=\"fs-id1165135500868\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165135500868\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165135500868\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165135500869\">An order of magnitude is the nearest power of ten by which a quantity exponentially grows. It is also an approximate position on a logarithmic scale; Sample response: Orders of magnitude are useful when making comparisons between numbers that differ by a great amount. For example, the mass of Saturn is 95 times greater than the mass of Earth. This is the same as saying that the mass of Saturn is about[latex]\\text{ }{10}^{\\text{2}}\\text{ }[\/latex]times, or <em>2 orders of magnitude<\/em> greater, than the mass of Earth.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135448286\" class=\"bc-section section\">\n<h4>Numeric<\/h4>\n<div id=\"fs-id1165135448291\">\n<div id=\"fs-id1165135448292\">\n<p id=\"fs-id1165135448293\">6. The temperature of an object in degrees Fahrenheit after <em>t <\/em>minutes is represented by the equation[latex]\\text{ }T\\left(t\\right)=68{e}^{-0.0174t}+72.\\text{ }[\/latex]To the nearest degree, what is the temperature of the object after one and a half hours?<\/p>\n<\/div>\n<\/div>\n<p id=\"fs-id1165135524408\">For the following exercises, use the logistic growth model[latex]\\text{ }f\\left(x\\right)=\\frac{150}{1+8{e}^{-2x}}.[\/latex]<\/p>\n<div id=\"fs-id1165134275330\">\n<div id=\"fs-id1165134275332\">\n<p id=\"fs-id1165134275333\">7. Find and interpret[latex]\\text{ }f\\left(0\\right).\\text{ }[\/latex]Round to the nearest tenth.<\/p>\n<\/div>\n<div id=\"fs-id1165135540046\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165135540046\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165135540046\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165135540047\">[latex]f\\left(0\\right)\\approx 16.7;\\text{ }[\/latex]The amount initially present is about 16.7 units.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165134350359\">\n<div id=\"fs-id1165134350361\">\n<p id=\"fs-id1165134350362\">8. Find and interpret[latex]\\text{ }f\\left(4\\right).\\text{ }[\/latex]Round to the nearest tenth.<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165134350316\">\n<div id=\"fs-id1165134350318\">\n<p id=\"fs-id1165134350319\">9. Find the carrying capacity.<\/p>\n<\/div>\n<div id=\"fs-id1165134256674\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165134256674\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165134256674\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165134256675\">150<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165134256679\">\n<div id=\"fs-id1165134256681\">\n<p id=\"fs-id1165134256682\">10. Graph the model.<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165134256686\">\n<div id=\"fs-id1165134256688\">\n<p id=\"fs-id1165134256690\">11. Determine whether the data from the table could best be represented as a function that is linear, exponential, or logarithmic. Then write a formula for a model that represents the data.<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165134256696\">\n<div id=\"fs-id1165134256698\">\n<table id=\"fs-id1165135415770\" class=\"unnumbered\" summary=\"..\">\n<tbody>\n<tr>\n<td class=\"border\"><strong>[latex]x[\/latex]<\/strong><\/td>\n<td class=\"border\"><strong>[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"border\">\u20132<\/td>\n<td class=\"border\">0.694<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">\u20131<\/td>\n<td class=\"border\">0.833<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">0<\/td>\n<td class=\"border\">1<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">1<\/td>\n<td class=\"border\">1.2<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">2<\/td>\n<td class=\"border\">1.44<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">3<\/td>\n<td class=\"border\">1.728<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">4<\/td>\n<td class=\"border\">2.074<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">5<\/td>\n<td class=\"border\">2.488<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<div id=\"fs-id1165134054878\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165134054878\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165134054878\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165134054879\">exponential;[latex]\\text{ }f\\left(x\\right)={1.2}^{x}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165137762564\">\n<div id=\"fs-id1165135309860\">\n<p id=\"fs-id1165135309863\">12. Rewrite[latex]\\text{ }f\\left(x\\right)=1.68{\\left(0.65\\right)}^{x}\\text{ }[\/latex]as an exponential equation with base[latex]\\text{ }e\\text{ }[\/latex]to five significant digits.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135154332\" class=\"bc-section section\">\n<h4>Technology<\/h4>\n<p id=\"fs-id1165135403321\">For the following exercises, enter the data from each table into a graphing calculator and graph the resulting scatter plots. Determine whether the data from the table could represent a function that is linear, exponential, or logarithmic.<\/p>\n<div>\n<div id=\"fs-id1165135403328\">\n<p>13.<\/p>\n<table id=\"fs-id1165135403332\" class=\"unnumbered\" summary=\"..\">\n<tbody>\n<tr>\n<td class=\"border\"><strong>[latex]x[\/latex]<\/strong><\/td>\n<td class=\"border\"><strong>[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"border\">1<\/td>\n<td class=\"border\">2<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">2<\/td>\n<td class=\"border\">4.079<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">3<\/td>\n<td class=\"border\">5.296<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">4<\/td>\n<td class=\"border\">6.159<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">5<\/td>\n<td class=\"border\">6.828<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">6<\/td>\n<td class=\"border\">7.375<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">7<\/td>\n<td class=\"border\">7.838<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">8<\/td>\n<td class=\"border\">8.238<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">9<\/td>\n<td class=\"border\">8.592<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">10<\/td>\n<td class=\"border\">8.908<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<div id=\"fs-id1165137836553\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165137836553\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165137836553\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165137836554\">logarithmic<\/p>\n<p><span id=\"fs-id1165137836562\"><img loading=\"lazy\" decoding=\"async\" class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3896\/2019\/03\/07131446\/CNX_PreCalc_Figure_04_07_201.jpg\" alt=\"Graph of the question\u2019s table.\" width=\"233\" height=\"237\" \/><\/span><\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165137836576\">\n<div id=\"fs-id1165135332894\">\n<p>14.<\/p>\n<table id=\"fs-id1165135332896\" class=\"unnumbered\" summary=\"..\">\n<tbody>\n<tr>\n<td class=\"border\"><strong>[latex]x[\/latex]<\/strong><\/td>\n<td class=\"border\"><strong>[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"border\">1<\/td>\n<td class=\"border\">2.4<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">2<\/td>\n<td class=\"border\">2.88<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">3<\/td>\n<td class=\"border\">3.456<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">4<\/td>\n<td class=\"border\">4.147<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">5<\/td>\n<td class=\"border\">4.977<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">6<\/td>\n<td class=\"border\">5.972<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">7<\/td>\n<td class=\"border\">7.166<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">8<\/td>\n<td class=\"border\">8.6<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">9<\/td>\n<td class=\"border\">10.32<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">10<\/td>\n<td class=\"border\">12.383<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<\/div>\n<div>\n<div id=\"eip-id1165135393396\">\n<p>15.<\/p>\n<table id=\"eip-id1165135393398\" class=\"unnumbered\" summary=\"..\">\n<tbody>\n<tr>\n<td class=\"border\"><strong>[latex]x[\/latex]<\/strong><\/td>\n<td class=\"border\"><strong>[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"border\">4<\/td>\n<td class=\"border\">9.429<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">5<\/td>\n<td class=\"border\">9.972<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">6<\/td>\n<td class=\"border\">10.415<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">7<\/td>\n<td class=\"border\">10.79<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">8<\/td>\n<td class=\"border\">11.115<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">9<\/td>\n<td class=\"border\">11.401<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">10<\/td>\n<td class=\"border\">11.657<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">11<\/td>\n<td class=\"border\">11.889<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">12<\/td>\n<td class=\"border\">12.101<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">13<\/td>\n<td class=\"border\">12.295<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<div id=\"fs-id1165134342556\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165134342556\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165134342556\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165134342557\">logarithmic<\/p>\n<p><span id=\"fs-id1165134342565\"><img loading=\"lazy\" decoding=\"async\" class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3896\/2019\/03\/07131451\/CNX_PreCalc_Figure_04_07_203.jpg\" alt=\"Graph of the question\u2019s table.\" width=\"207\" height=\"309\" \/><\/span><\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135532481\">\n<div id=\"fs-id1165135532483\">\n<p>16.<\/p>\n<table id=\"fs-id1165135532486\" class=\"unnumbered\" summary=\"..\">\n<tbody>\n<tr>\n<td class=\"border\"><strong>[latex]x[\/latex]<\/strong><\/td>\n<td class=\"border\"><strong>[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\n<\/tr>\n<tr>\n<td class=\"border\">1.25<\/td>\n<td class=\"border\">5.75<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">2.25<\/td>\n<td class=\"border\">8.75<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">3.56<\/td>\n<td class=\"border\">12.68<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">4.2<\/td>\n<td class=\"border\">14.6<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">5.65<\/td>\n<td class=\"border\">18.95<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">6.75<\/td>\n<td class=\"border\">22.25<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">7.25<\/td>\n<td class=\"border\">23.75<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">8.6<\/td>\n<td class=\"border\">27.8<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">9.25<\/td>\n<td class=\"border\">29.75<\/td>\n<\/tr>\n<tr>\n<td class=\"border\">10.5<\/td>\n<td class=\"border\">33.5<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<\/div>\n<p id=\"fs-id1165135678730\">For the following exercises, use a graphing calculator and this scenario: the population of a fish farm in[latex]\\text{ }t\\text{ }[\/latex]years is modeled by the equation[latex]\\text{ }P\\left(t\\right)=\\frac{1000}{1+9{e}^{-0.6t}}.[\/latex]<\/p>\n<div>\n<div id=\"fs-id1165137611545\">\n<p>17. Graph the function.<\/p>\n<\/div>\n<div id=\"fs-id1165137611549\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165137611549\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165137611549\" class=\"hidden-answer\" style=\"display: none\"><span id=\"fs-id1165137611556\"><img loading=\"lazy\" decoding=\"async\" class=\"\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3896\/2019\/03\/07131455\/CNX_PreCalc_Figure_04_07_205.jpg\" alt=\"Graph of P(t)=1000\/(1+9e^(-0.6t))\" width=\"132\" height=\"148\" \/><\/span><\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165134275365\">\n<div id=\"fs-id1165134275367\">\n<p id=\"fs-id1165134275368\">18. What is the initial population of fish?<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165134275373\">\n<div id=\"fs-id1165134275375\">\n<p id=\"fs-id1165134275376\">19. To the nearest tenth, what is the doubling time for the fish population?<\/p>\n<\/div>\n<div id=\"fs-id1165134275379\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165134275379\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165134275379\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165134275380\">about[latex]\\text{ }1.4\\text{ }[\/latex]years<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135358889\">\n<div id=\"fs-id1165135358892\">\n<p id=\"fs-id1165135358893\">20. To the nearest whole number, what will the fish population be after[latex]\\text{ }2\\text{ }[\/latex]years?<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135699221\">\n<div id=\"fs-id1165135699223\">\n<p id=\"fs-id1165135699224\">21. To the nearest tenth, how long will it take for the population to reach[latex]\\text{ }900?[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1165137647572\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165137647572\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165137647572\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165137647573\">about[latex]\\text{ }7.3\\text{ }[\/latex]years<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165137647593\">\n<div id=\"fs-id1165135404200\">\n<p id=\"fs-id1165135404201\">22. What is the carrying capacity for the fish population? Justify your answer using the graph of[latex]\\text{ }P.[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135404218\" class=\"bc-section section\">\n<h4>Extensions<\/h4>\n<div id=\"fs-id1165135404224\">\n<div id=\"fs-id1165137589535\">\n<p id=\"fs-id1165137589536\">23. A substance has a half-life of 2.045 minutes. If the initial amount of the substance was 132.8 grams, how many half-lives will have passed before the substance decays to 8.3 grams? What is the total time of decay?<\/p>\n<\/div>\n<div id=\"fs-id1165137589542\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165137589542\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165137589542\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165137589543\">[latex]4\\text{ }[\/latex]half-lives;[latex]\\text{ }8.18\\text{ }[\/latex]minutes<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135169175\">\n<div id=\"fs-id1165135169177\">\n<p id=\"fs-id1165135169178\">24. The formula for an increasing population is given by[latex]\\text{ }P\\left(t\\right)={P}_{0}{e}^{rt}\\text{ }[\/latex]where[latex]\\text{ }{P}_{0}\\text{ }[\/latex]is the initial population and[latex]\\text{ }r>0.\\text{ }[\/latex]Derive a general formula for the time <em>t<\/em> it takes for the population to increase by a factor of <em>M<\/em>.<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135543184\">\n<div id=\"fs-id1165135543186\">\n<p id=\"fs-id1165135543188\">25. Recall the formula for calculating the magnitude of an earthquake,[latex]\\text{ }M=\\frac{2}{3}\\mathrm{log}\\left(\\frac{S}{{S}_{0}}\\right).[\/latex] Show each step for solving this equation algebraically for the seismic moment[latex]\\text{ }S.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1165135208571\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165135208571\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165135208571\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165135208572\">[latex]\\begin{array}{l}\\text{ }M=\\frac{2}{3}\\mathrm{log}\\left(\\frac{S}{{S}_{0}}\\right)\\hfill \\\\ \\mathrm{log}\\left(\\frac{S}{{S}_{0}}\\right)=\\frac{3}{2}M\\hfill \\\\ \\text{ }\\frac{S}{{S}_{0}}={10}^{\\frac{3M}{2}}\\hfill \\\\ \\text{ }S={S}_{0}{10}^{\\frac{3M}{2}}\\hfill \\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165137476953\">\n<div id=\"fs-id1165137476955\">\n<p id=\"fs-id1165137476956\">26. What is the <em>y<\/em>-intercept of the logistic growth model[latex]\\text{ }y=\\frac{c}{1+a{e}^{-rx}}?\\text{ }[\/latex]Show the steps for calculation. What does this point tell us about the population?<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165134056896\">\n<div id=\"fs-id1165134056898\">\n<p id=\"fs-id1165134056899\">27. Prove that[latex]\\text{ }{b}^{x}={e}^{x\\mathrm{ln}\\left(b\\right)}\\text{ }[\/latex]for positive[latex]\\text{ }b\\ne 1.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1165135555464\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165135555464\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165135555464\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165135555466\">Let[latex]\\text{ }y={b}^{x}\\text{ }[\/latex]for some non-negative real number[latex]\\text{ }b\\text{ }[\/latex]such that[latex]\\text{ }b\\ne 1.\\text{ }[\/latex]Then,<\/p>\n<p id=\"eip-id1165135332843\">[latex]\\begin{array}{l}\\mathrm{ln}\\left(y\\right)=\\mathrm{ln}\\left({b}^{x}\\right)\\hfill \\\\ \\mathrm{ln}\\left(y\\right)=x\\mathrm{ln}\\left(b\\right)\\hfill \\\\ {e}^{\\mathrm{ln}\\left(y\\right)}={e}^{x\\mathrm{ln}\\left(b\\right)}\\hfill \\\\ y={e}^{x\\mathrm{ln}\\left(b\\right)}\\hfill \\end{array}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135456884\" class=\"bc-section section\">\n<h4>Real-World Applications<\/h4>\n<p id=\"fs-id1165137740750\">For the following exercises, use this scenario: A doctor prescribes 125 milligrams of a therapeutic drug that decays by about 30% each hour.<\/p>\n<div id=\"fs-id1165137740755\">\n<div id=\"fs-id1165137740757\">\n<p id=\"fs-id1165137740759\">28. To the nearest hour, what is the half-life of the drug?<\/p>\n<\/div>\n<\/div>\n<div id=\"Exercise_04_07_030\">\n<div id=\"fs-id1165137740769\">\n<p>29. Write an exponential model representing the amount of the drug remaining in the patient\u2019s system after[latex]\\text{ }t\\text{ }[\/latex]hours. Then use the formula to find the amount of the drug that would remain in the patient\u2019s system after 3 hours. Round to the nearest milligram.<\/p>\n<\/div>\n<div id=\"fs-id1165135440471\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165135440471\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165135440471\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165135440472\">[latex]A=125{e}^{\\left(-0.3567t\\right)};A\\approx 43\\text{ }[\/latex]mg<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165137823258\">\n<div id=\"fs-id1165135459770\">\n<p id=\"fs-id1165135459771\">30. Using the model found in the previous exercise, find[latex]\\text{ }f\\left(10\\right)\\text{ }[\/latex]and interpret the result. Round to the nearest hundredth.<\/p>\n<\/div>\n<\/div>\n<p id=\"fs-id1165135530652\">For the following exercises, use this scenario: A tumor is injected with[latex]\\text{ }0.5\\text{ }[\/latex]grams of Iodine-125, which has a decay rate of[latex]\\text{ }1.15%\\text{ }[\/latex]per day.<\/p>\n<div id=\"fs-id1165135532373\">\n<div id=\"fs-id1165135532375\">\n<p id=\"fs-id1165135532376\">31. To the nearest day, how long will it take for half of the Iodine-125 to decay?<\/p>\n<\/div>\n<div id=\"fs-id1165135532379\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165135532379\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165135532379\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165135532380\">about[latex]\\text{ }60\\text{ }[\/latex]days<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"Exercise_04_07_033\">\n<div id=\"fs-id1165134306669\">\n<p id=\"fs-id1165134306670\">32. Write an exponential model representing the amount of Iodine-125 remaining in the tumor after[latex]\\text{ }t\\text{ }[\/latex]days. Then use the formula to find the amount of Iodine-125 that would remain in the tumor after 60 days. Round to the nearest tenth of a gram.<\/p>\n<\/div>\n<\/div>\n<div id=\"Exercise_04_07_034\">\n<div id=\"fs-id1165135678596\">\n<p id=\"fs-id1165135678598\">33. A scientist begins with[latex]\\text{ }\\text{250}\\text{ }[\/latex]grams of a radioactive substance. After[latex]\\text{ }\\text{250}\\text{ }[\/latex]minutes, the sample has decayed to[latex]\\text{ }\\text{32}\\text{ }[\/latex]grams. Rounding to five significant digits, write an exponential equation representing this situation. To the nearest minute, what is the half-life of this substance?<\/p>\n<\/div>\n<div id=\"fs-id1165134069337\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165134069337\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165134069337\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165134069338\">[latex]f\\left(t\\right)=250{e}^{\\left(-0.00914t\\right)};\\text{ }[\/latex]half-life: about[latex]\\text{ }\\text{76}\\text{ }[\/latex]minutes<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165137749954\">\n<div id=\"fs-id1165137749956\">\n<p>34. The half-life of Radium-226 is[latex]\\text{ }1590\\text{ }[\/latex]years. What is the annual decay rate? Express the decimal result to four significant digits and the percentage to two significant digits.<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165137656769\">\n<div id=\"fs-id1165137656771\">\n<p id=\"fs-id1165137656772\">35. The half-life of Erbium-165 is[latex]\\text{ }\\text{10}\\text{.4}\\text{ }[\/latex]hours. What is the hourly decay rate? Express the decimal result to four significant digits and the percentage to two significant digits.<\/p>\n<\/div>\n<div id=\"fs-id1165137851455\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165137851455\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165137851455\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165137851456\">[latex]r\\approx -0.0667,[\/latex] So the hourly decay rate is about[latex]\\text{ }6.67%[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135508223\">\n<div id=\"fs-id1165135508226\">\n<p id=\"fs-id1165135508227\">36. A wooden artifact from an archeological dig contains 60 percent of the carbon-14 that is present in living trees. To the nearest year, about how many years old is the artifact? (The half-life of carbon-14 is[latex]\\text{ }\\text{573}0\\text{ }[\/latex]years.)<\/p>\n<\/div>\n<\/div>\n<div id=\"Exercise_04_07_038\">\n<div id=\"fs-id1165137400153\">\n<p id=\"fs-id1165135191027\">37. A research student is working with a culture of bacteria that doubles in size every twenty minutes. The initial population count was[latex]\\text{ }1350\\text{ }[\/latex]bacteria. Rounding to five significant digits, write an exponential equation representing this situation. To the nearest whole number, what is the population size after[latex]\\text{ 3 }[\/latex]hours?<\/p>\n<\/div>\n<div id=\"fs-id1165135306876\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165135306876\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165135306876\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165135306878\">[latex]f\\left(t\\right)=1350{e}^{\\left(0.03466t\\right)};\\text{ }[\/latex]after 3 hours:[latex]\\text{ }P\\left(180\\right)\\approx 691,200[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p id=\"fs-id1165135339542\">For the following exercises, use this scenario: A biologist recorded a count of[latex]\\text{ }360\\text{ }[\/latex]bacteria present in a culture after[latex]\\text{ }5\\text{ }[\/latex]minutes and[latex]\\text{ }1000\\text{ }[\/latex]bacteria present after[latex]\\text{ }20\\text{ }[\/latex]minutes.<\/p>\n<div id=\"fs-id1165135189888\">\n<div id=\"fs-id1165137834291\">\n<p id=\"fs-id1165137834292\">38. To the nearest whole number, what was the initial population in the culture?<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165137834297\">\n<div id=\"fs-id1165137834299\">\n<p id=\"fs-id1165137834300\">39. Rounding to six significant digits, write an exponential equation representing this situation. To the nearest minute, how long did it take the population to double?<\/p>\n<\/div>\n<div id=\"fs-id1165137834305\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165137834305\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165137834305\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165137834306\">[latex]f\\left(t\\right)=256{e}^{\\left(0.068110t\\right)};\\text{ }[\/latex]doubling time: about[latex]\\text{ }10\\text{ }[\/latex]minutes<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p id=\"fs-id1165134108595\">For the following exercises, use this scenario: A pot of boiling soup with an internal temperature of[latex]\\text{ }\\text{100\u00b0}\\text{ }[\/latex]Fahrenheit was taken off the stove to cool in a[latex]\\text{ }\\text{69\u00b0 F}\\text{ }[\/latex]room. After fifteen minutes, the internal temperature of the soup was[latex]\\text{ }\\text{95\u00b0 F}\\text{.}[\/latex]<\/p>\n<div>\n<div>\n<p id=\"fs-id1165137642591\">40. Use Newton\u2019s Law of Cooling to write a formula that models this situation.<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165137642597\">\n<div id=\"fs-id1165137642599\">\n<p id=\"fs-id1165137642600\">41. To the nearest minute, how long will it take the soup to cool to[latex]\\text{ }\\text{80\u00b0 F?}[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1165135536453\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165135536453\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165135536453\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165135536454\">about[latex]\\text{ }\\text{88}\\text{ }[\/latex]minutes<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135252212\">\n<div id=\"fs-id1165135252213\">\n<p id=\"fs-id1165135252214\">42. To the nearest degree, what will the temperature be after[latex]\\text{ }2\\text{ }[\/latex]and a half hours?<\/p>\n<\/div>\n<\/div>\n<p id=\"fs-id1165135353712\">For the following exercises, use this scenario: A turkey is taken out of the oven with an internal temperature of[latex]\\text{ }\\text{165\u00b0F}\\text{ }[\/latex] and is allowed to cool in a[latex]\\text{ }\\text{75\u00b0F}\\text{ }[\/latex]room. After half an hour, the internal temperature of the turkey is[latex]\\text{ }\\text{145\u00b0F}\\text{.}[\/latex]<\/p>\n<div id=\"fs-id1165135503869\">\n<div id=\"fs-id1165135503871\">\n<p id=\"fs-id1165135503872\">43. Write a formula that models this situation.<\/p>\n<\/div>\n<div id=\"fs-id1165135503876\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165135503876\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165135503876\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165135503877\">[latex]T\\left(t\\right)=90{e}^{\\left(-0.008377t\\right)}+75,[\/latex] where[latex]\\text{ }t\\text{ }[\/latex]is in minutes.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165134130934\">\n<div id=\"fs-id1165134130937\">\n<p id=\"fs-id1165134130938\">44. To the nearest degree, what will the temperature be after 50 minutes?<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165134130942\">\n<div id=\"fs-id1165134394566\">\n<p id=\"fs-id1165134394567\">45. To the nearest minute, how long will it take the turkey to cool to[latex]\\text{ }\\text{110\u00b0 F?}[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1165134394590\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165134394590\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165134394590\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165134394591\">about[latex]\\text{ }\\text{113}\\text{ }[\/latex]minutes<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p id=\"fs-id1165137580701\">For the following exercises, find the value of the number shown on each logarithmic scale. Round all answers to the nearest thousandth.<\/p>\n<div id=\"fs-id1165137580706\">\n<div id=\"fs-id1165137580708\"><span id=\"fs-id1165137428096\">46.\u00a0<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3896\/2019\/03\/07131458\/CNX_PreCalc_Figure_04_07_206.jpg\" alt=\"Number line to show log(x) is between -1 and 0.\" \/><\/span><\/div>\n<\/div>\n<div id=\"fs-id1165137428110\">\n<div id=\"fs-id1165137428113\"><span id=\"fs-id1165134085824\">47.\u00a0<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3896\/2019\/03\/07131501\/CNX_PreCalc_Figure_04_07_207.jpg\" alt=\"Number line to show log(x) is between 1 and 2.\" \/><\/span><\/div>\n<div id=\"fs-id1165134085837\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165134085837\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165134085837\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165134085838\">[latex]\\mathrm{log}\\left(x\\right)=1.5;\\text{ }x\\approx 31.623[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135395316\">\n<div id=\"fs-id1165135395318\">\n<p id=\"fs-id1165135395320\">48. Plot each set of approximate values of intensity of sounds on a logarithmic scale: Whisper:[latex]\\text{ }{10}^{-10} \\frac{W}{{m}^{2}},[\/latex]Vacuum:[latex]\\text{ }{10}^{-4}\\frac{W}{{m}^{2}},[\/latex]Jet:[latex]\\text{ }{10}^{2} \\frac{W}{{m}^{2}}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165134486756\">\n<div>\n<p id=\"fs-id1165134486760\">49. Recall the formula for calculating the magnitude of an earthquake,[latex]\\text{ }M=\\frac{2}{3}\\mathrm{log}\\left(\\frac{S}{{S}_{0}}\\right).\\text{ }[\/latex]One earthquake has magnitude[latex]\\text{ }\\text{3}.\\text{9}\\text{ }[\/latex]on the MMS scale. If a second earthquake has[latex]\\text{ }\\text{75}0\\text{ }[\/latex]times as much energy as the first, find the magnitude of the second quake. Round to the nearest hundredth.<\/p>\n<\/div>\n<div id=\"fs-id1165135517147\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165135517147\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165135517147\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165135517148\">MMS magnitude:[latex]\\text{ }5.82[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p id=\"fs-id1165135517163\">For the following exercises, use this scenario: The equation[latex]\\text{ }N\\left(t\\right)=\\frac{500}{1+49{e}^{-0.7t}}\\text{ }[\/latex]models the number of people in a town who have heard a rumor after <em>t<\/em> days.<\/p>\n<div id=\"fs-id1165135332961\">\n<div id=\"fs-id1165135332963\">\n<p id=\"fs-id1165135332964\">50. How many people started the rumor?<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1165135332968\">\n<div id=\"fs-id1165134059773\">\n<p id=\"fs-id1165134059774\">51. To the nearest whole number, how many people will have heard the rumor after 3 days?<\/p>\n<\/div>\n<div id=\"fs-id1165134059778\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165134059778\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165134059778\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165134059779\">[latex]N\\left(3\\right)\\approx 71[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1165134106004\">\n<div>\n<p>52. As[latex]\\text{ }t\\text{ }[\/latex]increases without bound, what value does[latex]\\text{ }N\\left(t\\right)\\text{ }[\/latex]approach? Interpret your answer.<\/p>\n<\/div>\n<\/div>\n<p id=\"eip-137\">For the following exercise, choose the correct answer choice.<\/p>\n<div id=\"fs-id1165135689474\">\n<div id=\"fs-id1165135689476\">\n<p id=\"fs-id1165135689477\">53. A doctor and injects a patient with[latex]\\text{ }13\\text{ }[\/latex]milligrams of radioactive dye that decays exponentially. After[latex]\\text{ }12\\text{ }[\/latex]minutes, there are[latex]\\text{ }4.75\\text{ }[\/latex]milligrams of dye remaining in the patient\u2019s system. Which is an appropriate model for this situation?<\/p>\n<ol type=\"A\">\n<li>[latex]f\\left(t\\right)=13{\\left(0.0805\\right)}^{t}[\/latex]<\/li>\n<li>[latex]f\\left(t\\right)=13{e}^{0.9195t}[\/latex]<\/li>\n<li>[latex]f\\left(t\\right)=13{e}^{\\left(-0.0839t\\right)}[\/latex]<\/li>\n<li>[latex]f\\left(t\\right)=\\frac{4.75}{1+13{e}^{-0.83925t}}[\/latex]<\/li>\n<\/ol>\n<\/div>\n<div id=\"fs-id1165137835581\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"qfs-id1165137835581\">Show Solution<\/span><\/p>\n<div id=\"qfs-id1165137835581\" class=\"hidden-answer\" style=\"display: none\">\n<p id=\"fs-id1165137835582\">C<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p>&nbsp;<\/p>\n","protected":false},"author":158108,"menu_order":14,"template":"","meta":{"_candela_citation":"[]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-2352","chapter","type-chapter","status-web-only","hentry"],"part":223,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/wp-json\/pressbooks\/v2\/chapters\/2352","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/wp-json\/wp\/v2\/users\/158108"}],"version-history":[{"count":2,"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/wp-json\/pressbooks\/v2\/chapters\/2352\/revisions"}],"predecessor-version":[{"id":2354,"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/wp-json\/pressbooks\/v2\/chapters\/2352\/revisions\/2354"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/wp-json\/pressbooks\/v2\/parts\/223"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/wp-json\/pressbooks\/v2\/chapters\/2352\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/wp-json\/wp\/v2\/media?parent=2352"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/wp-json\/pressbooks\/v2\/chapter-type?post=2352"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/wp-json\/wp\/v2\/contributor?post=2352"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/wp-json\/wp\/v2\/license?post=2352"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}