{"id":2359,"date":"2019-05-13T12:50:55","date_gmt":"2019-05-13T12:50:55","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/?post_type=chapter&p=2359"},"modified":"2019-05-13T12:51:52","modified_gmt":"2019-05-13T12:51:52","slug":"2-2-section-exercises","status":"web-only","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-dutchess-precalculus\/chapter\/2-2-section-exercises\/","title":{"raw":"2.2 Section Exercises","rendered":"2.2 Section Exercises"},"content":{"raw":"
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2.2 Section Exercises<\/h3>\r\n
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Verbal<\/h4>\r\n
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\r\n\r\n1. Explain why the values of an increasing exponential function will eventually overtake the values of an increasing linear function.\r\n\r\n<\/div>\r\n
[reveal-answer q=\"fs-id1165137406938\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137406938\"]\r\n

Linear functions have a constant rate of change. Exponential functions increase based on a percent of the original.<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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2. Given a formula for an exponential function, is it possible to determine whether the function grows or decays exponentially just by looking at the formula? Explain.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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3. The Oxford Dictionary defines the word nominal<\/em> as a value that is \u201cstated or expressed but not necessarily corresponding exactly to the real value.\u201d[footnote]Oxford Dictionary. http:\/\/oxforddictionaries.com\/us\/definition\/american_english\/nomina.[\/footnote] Develop a reasonable argument for why the term nominal rate<\/em> is used to describe the annual percentage rate of an investment account that compounds interest.<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135189885\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135189885\"]\r\n

When interest is compounded, the percentage of interest earned to principal ends up being greater than the annual percentage rate for the investment account. Thus, the annual percentage rate does not necessarily correspond to the real interest earned, which is the very definition of nominal<\/em>.<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n

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Algebraic<\/h4>\r\n

For the following exercises, identify whether the statement represents an exponential function. Explain.<\/p>\r\n\r\n

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4. The average annual population increase of a pack of wolves is 25.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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5. A population of bacteria decreases by a factor of[latex]\\text{ }\\frac{1}{8}\\text{ }[\/latex]every[latex]\\text{ }24\\text{ }[\/latex]hours.<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165137416069\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137416069\"]\r\n

exponential; the population decreases by a proportional rate. .<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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6. The value of a coin collection has increased by[latex]\\text{ }3.25%\\text{ }[\/latex]annually over the last[latex]\\text{ }20\\text{ }[\/latex]years.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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7. For each training session, a personal trainer charges his clients[latex]\\text{ }\\text{$}5\\text{ }[\/latex] less than the previous training session.<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135318995\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135318995\"]\r\n

not exponential; the charge decreases by a constant amount each visit, so the statement represents a linear function. .<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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8. The height of a projectile at time[latex]\\text{ }t\\text{ }[\/latex]is represented by the function[latex]\\text{ }h\\left(t\\right)=-4.9{t}^{2}+18t+40.[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

For the following exercises, consider this scenario: For each year[latex]\\text{ }t,[\/latex]the population of a forest of trees is represented by the function[latex]\\text{ }A\\left(t\\right)=115{\\left(1.025\\right)}^{t}.\\text{ }[\/latex]In a neighboring forest, the population of the same type of tree is represented by the function[latex]\\text{ }B\\left(t\\right)=82{\\left(1.029\\right)}^{t}.\\text{ }[\/latex](Round answers to the nearest whole number.)<\/p>\r\n\r\n

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9. Which forest\u2019s population is growing at a faster rate?<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135570352\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135570352\"]\r\n

The forest represented by the function[latex]\\text{ }B\\left(t\\right)=82{\\left(1.029\\right)}^{t}.[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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10. Which forest had a greater number of trees initially? By how many?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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11. Assuming the population growth models continue to represent the growth of the forests, which forest will have a greater number of trees after[latex]\\text{ }20\\text{ }[\/latex]years? By how many?<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165137761058\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137761058\"]\r\n

After[latex]\\text{ }t=20\\text{ }[\/latex]years, forest A will have[latex]\\text{ }43\\text{ }[\/latex]more trees than forest B.<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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12. Assuming the population growth models continue to represent the growth of the forests, which forest will have a greater number of trees after[latex]\\text{ }100\\text{ }[\/latex]years? By how many?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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13. Discuss the above results from the previous four exercises. Assuming the population growth models continue to represent the growth of the forests, which forest will have the greater number of trees in the long run? Why? What are some factors that might influence the long-term validity of the exponential growth model?<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165137407578\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137407578\"]\r\n

Answers will vary. Sample response: For a number of years, the population of forest A will increasingly exceed forest B, but because forest B actually grows at a faster rate, the population will eventually become larger than forest A and will remain that way as long as the population growth models hold. Some factors that might influence the long-term validity of the exponential growth model are drought, an epidemic that culls the population, and other environmental and biological factors.<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\nFor the following exercises, determine whether the equation represents exponential growth, exponential decay, or neither. Explain.\r\n

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14. [latex]y=300{\\left(1-t\\right)}^{5}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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15. [latex]y=220{\\left(1.06\\right)}^{x}[\/latex]<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135209944\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135209944\"]\r\n

exponential growth; The growth factor,[latex]\\text{ }1.06,[\/latex] is greater than[latex]\\text{ }1.[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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16. [latex]y=16.5{\\left(1.025\\right)}^{\\frac{1}{x}}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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17. [latex]y=11,701{\\left(0.97\\right)}^{t}[\/latex]<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135397288\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135397288\"]exponential decay; The decay factor,[latex]\\text{ }0.97,[\/latex] is between[latex]\\text{ }0\\text{ }[\/latex]and[latex]\\text{ }1.[\/latex][\/hidden-answer]<\/div>\r\n<\/div>\r\n

For the following exercises, find the formula for an exponential function that passes through the two points given.<\/p>\r\n\r\n

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18. [latex]\\left(0,6\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(3,750\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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19. [latex]\\left(0,2000\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(2,20\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165137735589\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137735589\"]\r\n

[latex]f\\left(x\\right)=2000{\\left(0.1\\right)}^{x}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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20. [latex]\\left(-1,\\frac{3}{2}\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(3,24\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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21. [latex]\\left(-2,6\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(3,1\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135187318\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135187318\"]\r\n

[latex]f\\left(x\\right)={\\left(\\frac{1}{6}\\right)}^{-\\frac{3}{5}}{\\left(\\frac{1}{6}\\right)}^{\\frac{x}{5}}\\approx 2.93{\\left(0.699\\right)}^{x}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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22. [latex]\\left(3,1\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(5,4\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

For the following exercises, determine whether the table could represent a function that is linear, exponential, or neither. If it appears to be exponential, find a function that passes through the points.<\/p>\r\n\r\n

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\r\n\r\n23.\r\n\r\n\r\n\r\n\r\n
[latex]x[\/latex]<\/strong><\/td>\r\n1<\/td>\r\n2<\/td>\r\n3<\/td>\r\n4<\/td>\r\n<\/tr>\r\n
[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\r\n70<\/td>\r\n40<\/td>\r\n10<\/td>\r\n-20<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n
[reveal-answer q=\"fs-id1165137680442\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137680442\"]\r\n

Linear<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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[latex]x[\/latex]<\/strong><\/td>\r\n1<\/td>\r\n2<\/td>\r\n3<\/td>\r\n4<\/td>\r\n<\/tr>\r\n
[latex]h\\left(x\\right)[\/latex]<\/strong><\/td>\r\n70<\/td>\r\n49<\/td>\r\n34.3<\/td>\r\n24.01<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<\/div>\r\n
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[latex]x[\/latex]<\/strong><\/td>\r\n1<\/td>\r\n2<\/td>\r\n3<\/td>\r\n4<\/td>\r\n<\/tr>\r\n
[latex]m\\left(x\\right)[\/latex]<\/strong><\/td>\r\n80<\/td>\r\n61<\/td>\r\n42.9<\/td>\r\n25.61<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n
[reveal-answer q=\"fs-id1165137761697\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137761697\"]\r\n

Neither<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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\r\n\r\n26.\r\n\r\n\r\n\r\n
\u00a0<\/caption>\r\n
[latex]x[\/latex]<\/strong><\/td>\r\n1<\/td>\r\n2<\/td>\r\n3<\/td>\r\n4<\/td>\r\n<\/tr>\r\n
[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\r\n10<\/td>\r\n20<\/td>\r\n40<\/td>\r\n80<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<\/div>\r\n
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[latex]x[\/latex]<\/strong><\/td>\r\n1<\/td>\r\n2<\/td>\r\n3<\/td>\r\n4<\/td>\r\n<\/tr>\r\n
[latex]g\\left(x\\right)[\/latex]<\/strong><\/td>\r\n-3.25<\/td>\r\n2<\/td>\r\n7.25<\/td>\r\n12.5<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n
[reveal-answer q=\"fs-id1165137874537\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137874537\"]\r\n

Linear<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

For the following exercises, use the compound interest formula,[latex]\\text{ }A\\left(t\\right)=P{\\left(1+\\frac{r}{n}\\right)}^{nt}.[\/latex]<\/p>\r\n\r\n

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28. After a certain number of years, the value of an investment account is represented by the equation[latex]\\text{ }10,250{\\left(1+\\frac{0.04}{12}\\right)}^{120}.\\text{ }[\/latex]What is the value of the account?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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29. What was the initial deposit made to the account in the previous exercise?<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135527084\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135527084\"]\r\n

[latex]$10,250[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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30. How many years had the account from the previous exercise been accumulating interest?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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31. An account is opened with an initial deposit of $6,500 and earns[latex]\\text{ }3.6%\\text{ }[\/latex]interest compounded semi-annually. What will the account be worth in[latex]\\text{ }20\\text{ }[\/latex]years?<\/p>\r\n\r\n<\/div>\r\n

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[reveal-answer q=\"653083\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"653083\"]<\/p>\r\n[latex]$13,268.58[\/latex][\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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32. How much more would the account in the previous exercise have been worth if the interest were compounding weekly?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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33. Solve the compound interest formula for the principal,[latex]\\text{ }P[\/latex].<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165137831975\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137831975\"]\r\n

[latex]P=A\\left(t\\right)\\cdot {\\left(1+\\frac{r}{n}\\right)}^{-nt}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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34. Use the formula found in the previous exercise to calculate the initial deposit of an account that is worth[latex]\\text{ }$14,472.74\\text{ }[\/latex]after earning[latex]\\text{ }5.5%\\text{ }[\/latex]interest compounded monthly for[latex]\\text{ }5\\text{ }[\/latex]years. (Round to the nearest dollar.)<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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35. How much more would the account in the previous two exercises be worth if it were earning interest for[latex]\\text{ }5\\text{ }[\/latex]more years?<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135415827\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135415827\"]\r\n

[latex]$4,572.56[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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36. Use properties of rational exponents to solve the compound interest formula for the interest rate,[latex]\\text{ }r.[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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37. Use the formula found in the previous exercise to calculate the interest rate for an account that was compounded semi-annually, had an initial deposit of $9,000 and was worth $13,373.53 after 10 years.<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135487075\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135487075\"]\r\n

[latex]4%[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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38. Use the formula found in the previous exercise to calculate the interest rate for an account that was compounded monthly, had an initial deposit of $5,500, and was worth $38,455 after 30 years.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\nFor the following exercises, determine whether the equation represents continuous growth, continuous decay, or neither. Explain.\r\n

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39. [latex]y=3742{\\left(e\\right)}^{0.75t}[\/latex]<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135336087\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135336087\"]\r\n

continuous growth; the growth rate is greater than[latex]\\text{ }0.[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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40. [latex]y=150{\\left(e\\right)}^{\\frac{3.25}{t}}[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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41. [latex]y=2.25{\\left(e\\right)}^{-2t}[\/latex]<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135191882\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135191882\"]\r\n

continuous decay; the growth rate is less than[latex]\\text{ }0.[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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42. Suppose an investment account is opened with an initial deposit of[latex]\\text{ }$12,000\\text{ }[\/latex]earning[latex]\\text{ }7.2%\\text{ }[\/latex]interest compounded continuously. How much will the account be worth after[latex]\\text{ }30\\text{ }[\/latex]years?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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43. How much less would the account from Exercise 42 be worth after[latex]\\text{ }30\\text{ }[\/latex]years if it were compounded monthly instead?<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135190851\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135190851\"]\r\n

[latex]$669.42[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n

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Numeric<\/h4>\r\n

For the following exercises, evaluate each function. Round answers to four decimal places, if necessary.<\/p>\r\n\r\n

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44. [latex]f\\left(x\\right)=2{\\left(5\\right)}^{x},[\/latex] for[latex]\\text{ }f\\left(-3\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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45. [latex]f\\left(x\\right)=-{4}^{2x+3},[\/latex] for[latex]\\text{ }f\\left(-1\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135415781\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135415781\"]\r\n

[latex]f\\left(-1\\right)=-4[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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\r\n\r\n46. [latex]f\\left(x\\right)={e}^{x},[\/latex] for[latex]\\text{ }f\\left(3\\right)[\/latex]\r\n\r\n<\/div>\r\n<\/div>\r\n
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[latex]f\\left(x\\right)=-2{e}^{x-1},[\/latex] for[latex]\\text{ }f\\left(-1\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135500970\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135500970\"]\r\n

[latex]f\\left(-1\\right)\\approx -0.2707[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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47. [latex]f\\left(x\\right)=2.7{\\left(4\\right)}^{-x+1}+1.5,[\/latex] for[latex]f\\left(-2\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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48. [latex]f\\left(x\\right)=1.2{e}^{2x}-0.3,[\/latex] for[latex]\\text{ }f\\left(3\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135510681\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135510681\"]\r\n

[latex]f\\left(3\\right)\\approx 483.8146[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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49. [latex]f\\left(x\\right)=-\\frac{3}{2}{\\left(3\\right)}^{-x}+\\frac{3}{2},[\/latex] for[latex]\\text{ }f\\left(2\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n

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Technology<\/h4>\r\n

For the following exercises, use a graphing calculator to find the equation of an exponential function given the points on the curve.<\/p>\r\n\r\n

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50. [latex]\\left(0,3\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(3,375\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165137715431\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165137715431\"]\r\n

[latex]y=3\\cdot {5}^{x}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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51. [latex]\\left(3,222.62\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(10,77.456\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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52. [latex]\\left(20,29.495\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(150,730.89\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135347282\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135347282\"]\r\n

[latex]y\\approx 18\\cdot {1.025}^{x}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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53. [latex]\\left(5,2.909\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(13,0.005\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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54. [latex]\\left(11,310.035\\right)\\text{ }[\/latex] and [latex]\\left(25,356.3652\\right)[\/latex]<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135255110\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135255110\"]\r\n

[latex]y\\approx 0.2\\cdot {1.95}^{x}[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n

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Extensions<\/h4>\r\n
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\r\n\r\n55. The annual percentage yield<\/em> (APY) of an investment account is a representation of the actual interest rate earned on a compounding account. It is based on a compounding period of one year. Show that the APY of an account that compounds monthly can be found with the formula[latex]\\text{ }\\text{APY}={\\left(1+\\frac{r}{12}\\right)}^{12}-1.[\/latex]\r\n\r\n<\/div>\r\n<\/div>\r\n
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56. Repeat the previous exercise to find the formula for the APY of an account that compounds daily. Use the results from this and the previous exercise to develop a function[latex]\\text{ }I\\left(n\\right)\\text{ }[\/latex]for the APY of any account that compounds[latex]\\text{ }n\\text{ }[\/latex]times per year.<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135530489\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135530489\"]\r\n

[latex]\\text{APY}=\\frac{A\\left(t\\right)-a}{a}=\\frac{a{\\left(1+\\frac{r}{365}\\right)}^{365\\left(1\\right)}-a}{a}=\\frac{a\\left[{\\left(1+\\frac{r}{365}\\right)}^{365}-1\\right]}{a}={\\left(1+\\frac{r}{365}\\right)}^{365}-1;[\/latex][latex]I\\left(n\\right)={\\left(1+\\frac{r}{n}\\right)}^{n}-1[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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57. Recall that an exponential function is any equation written in the form[latex]\\text{ }f\\left(x\\right)=a\\cdot {b}^{x}\\text{ }[\/latex]such that[latex] a [\/latex]and[latex] b [\/latex]are positive numbers and[latex] b\\ne 1. [\/latex]Any positive number[latex] b [\/latex]can be written as[latex] b={e}^{n} [\/latex]for some value of[latex] n[\/latex]. Use this fact to rewrite the formula for an exponential function that uses the number[latex] e [\/latex]as a base.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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58. In an exponential decay function, the base of the exponent is a value between 0 and 1. Thus, for some number[latex]\\text{ }b>1,[\/latex] the exponential decay function can be written as[latex]\\text{ }f\\left(x\\right)=a\\cdot {\\left(\\frac{1}{b}\\right)}^{x}.\\text{ }[\/latex]Use this formula, along with the fact that[latex]\\text{ }b={e}^{n},[\/latex] to show that an exponential decay function takes the form[latex]\\text{ }f\\left(x\\right)=a{\\left(e\\right)}^{-nx}\\text{ }[\/latex]for some positive number[latex]\\text{ }n\\text{ }[\/latex].<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135661465\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135661465\"]\r\n

Let[latex]\\text{ }f\\text{ }[\/latex]be the exponential decay function[latex]\\text{ }f\\left(x\\right)=a\\cdot {\\left(\\frac{1}{b}\\right)}^{x}\\text{ }[\/latex]such that[latex]\\text{ }b>1.\\text{ }[\/latex]Then for some number[latex]\\text{ }n>0,[\/latex][latex]f\\left(x\\right)=a\\cdot {\\left(\\frac{1}{b}\\right)}^{x}=a{\\left({b}^{-1}\\right)}^{x}=a{\\left({\\left({e}^{n}\\right)}^{-1}\\right)}^{x}=a{\\left({e}^{-n}\\right)}^{x}=a{\\left(e\\right)}^{-nx}.[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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59. The formula for the amount[latex]\\text{ }A\\text{ }[\/latex]in an investment account with a nominal interest rate[latex]\\text{ }r\\text{ }[\/latex]at any time[latex]\\text{ }t\\text{ }[\/latex]is given by[latex]\\text{ }A\\left(t\\right)=a{\\left(e\\right)}^{rt},[\/latex]where[latex]\\text{ }a\\text{ }[\/latex]is the amount of principal initially deposited into an account that compounds continuously. Prove that the percentage of interest earned to principal at any time[latex]\\text{ }t\\text{ }[\/latex]can be calculated with the formula[latex]\\text{ }I\\left(t\\right)={e}^{rt}-1.[\/latex]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n

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Real-World Applications<\/h4>\r\n
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60. The fox population in a certain region has an annual growth rate of 9% per year. In the year 2012, there were 23,900 fox counted in the area. What is the fox population predicted to be in the year 2020?<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135205873\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135205873\"]\r\n

[latex]47,622\\text{ }[\/latex]fox<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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61. A scientist begins with 100 milligrams of a radioactive substance that decays exponentially. After 35 hours, 50mg of the substance remains. How many milligrams will remain after 54 hours?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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62. In the year 1985, a house was valued at $110,000. By the year 2005, the value had appreciated to $145,000. What was the annual growth rate between 1985 and 2005? Assume that the value continued to grow by the same percentage. What was the value of the house in the year 2010?<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165134086071\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165134086071\"]\r\n

[latex]1.39%;\\text{ }[\/latex][latex]$155,368.09[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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63. A car was valued at $38,000 in the year 2007. By 2013, the value had depreciated to $11,000 If the car\u2019s value continues to drop by the same percentage, what will it be worth by 2017?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n

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64. Jamal wants to save $54,000 for a down payment on a home. How much will he need to invest in an account with 8.2% APR, compounding daily, in order to reach his goal in 5 years?<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135208510\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135208510\"]\r\n

[latex]$35,838.76[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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\r\n\r\n65. Kyoko has $10,000 that she wants to invest. Her bank has several investment accounts to choose from, all compounding daily. Her goal is to have $15,000 by the time she finishes graduate school in 6 years. To the nearest hundredth of a percent, what should her minimum annual interest rate be in order to reach her goal? (Hint<\/em>: solve the compound interest formula for the interest rate.)\r\n\r\n<\/div>\r\n<\/div>\r\n
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66. Alyssa opened a retirement account with 7.25% APR in the year 2000. Her initial deposit was $13,500. How much will the account be worth in 2025 if interest compounds monthly? How much more would she make if interest compounded continuously?<\/p>\r\n\r\n<\/div>\r\n

[reveal-answer q=\"fs-id1165135567423\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"fs-id1165135567423\"]\r\n

[latex]$82,247.78;\\text{ }[\/latex][latex]$449.75[\/latex]<\/p>\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n

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67. An investment account with an annual interest rate of 7% was opened with an initial deposit of $4,000 Compare the values of the account after 9 years when the interest is compounded annually, quarterly, monthly, and continuously.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n ","rendered":"

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2.2 Section Exercises<\/h3>\n
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Verbal<\/h4>\n
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1. Explain why the values of an increasing exponential function will eventually overtake the values of an increasing linear function.<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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Linear functions have a constant rate of change. Exponential functions increase based on a percent of the original.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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2. Given a formula for an exponential function, is it possible to determine whether the function grows or decays exponentially just by looking at the formula? Explain.<\/p>\n<\/div>\n<\/div>\n

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3. The Oxford Dictionary defines the word nominal<\/em> as a value that is \u201cstated or expressed but not necessarily corresponding exactly to the real value.\u201d[1]<\/sup><\/a> Develop a reasonable argument for why the term nominal rate<\/em> is used to describe the annual percentage rate of an investment account that compounds interest.<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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When interest is compounded, the percentage of interest earned to principal ends up being greater than the annual percentage rate for the investment account. Thus, the annual percentage rate does not necessarily correspond to the real interest earned, which is the very definition of nominal<\/em>.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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Algebraic<\/h4>\n

For the following exercises, identify whether the statement represents an exponential function. Explain.<\/p>\n

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4. The average annual population increase of a pack of wolves is 25.<\/p>\n<\/div>\n<\/div>\n

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5. A population of bacteria decreases by a factor of[latex]\\text{ }\\frac{1}{8}\\text{ }[\/latex]every[latex]\\text{ }24\\text{ }[\/latex]hours.<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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exponential; the population decreases by a proportional rate. .<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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6. The value of a coin collection has increased by[latex]\\text{ }3.25%\\text{ }[\/latex]annually over the last[latex]\\text{ }20\\text{ }[\/latex]years.<\/p>\n<\/div>\n<\/div>\n

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7. For each training session, a personal trainer charges his clients[latex]\\text{ }\\text{$}5\\text{ }[\/latex] less than the previous training session.<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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not exponential; the charge decreases by a constant amount each visit, so the statement represents a linear function. .<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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8. The height of a projectile at time[latex]\\text{ }t\\text{ }[\/latex]is represented by the function[latex]\\text{ }h\\left(t\\right)=-4.9{t}^{2}+18t+40.[\/latex]<\/p>\n<\/div>\n<\/div>\n

For the following exercises, consider this scenario: For each year[latex]\\text{ }t,[\/latex]the population of a forest of trees is represented by the function[latex]\\text{ }A\\left(t\\right)=115{\\left(1.025\\right)}^{t}.\\text{ }[\/latex]In a neighboring forest, the population of the same type of tree is represented by the function[latex]\\text{ }B\\left(t\\right)=82{\\left(1.029\\right)}^{t}.\\text{ }[\/latex](Round answers to the nearest whole number.)<\/p>\n

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9. Which forest\u2019s population is growing at a faster rate?<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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The forest represented by the function[latex]\\text{ }B\\left(t\\right)=82{\\left(1.029\\right)}^{t}.[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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10. Which forest had a greater number of trees initially? By how many?<\/p>\n<\/div>\n<\/div>\n

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11. Assuming the population growth models continue to represent the growth of the forests, which forest will have a greater number of trees after[latex]\\text{ }20\\text{ }[\/latex]years? By how many?<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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After[latex]\\text{ }t=20\\text{ }[\/latex]years, forest A will have[latex]\\text{ }43\\text{ }[\/latex]more trees than forest B.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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12. Assuming the population growth models continue to represent the growth of the forests, which forest will have a greater number of trees after[latex]\\text{ }100\\text{ }[\/latex]years? By how many?<\/p>\n<\/div>\n<\/div>\n

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13. Discuss the above results from the previous four exercises. Assuming the population growth models continue to represent the growth of the forests, which forest will have the greater number of trees in the long run? Why? What are some factors that might influence the long-term validity of the exponential growth model?<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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Answers will vary. Sample response: For a number of years, the population of forest A will increasingly exceed forest B, but because forest B actually grows at a faster rate, the population will eventually become larger than forest A and will remain that way as long as the population growth models hold. Some factors that might influence the long-term validity of the exponential growth model are drought, an epidemic that culls the population, and other environmental and biological factors.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

For the following exercises, determine whether the equation represents exponential growth, exponential decay, or neither. Explain.<\/p>\n

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14. [latex]y=300{\\left(1-t\\right)}^{5}[\/latex]<\/p>\n<\/div>\n<\/div>\n

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15. [latex]y=220{\\left(1.06\\right)}^{x}[\/latex]<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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exponential growth; The growth factor,[latex]\\text{ }1.06,[\/latex] is greater than[latex]\\text{ }1.[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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16. [latex]y=16.5{\\left(1.025\\right)}^{\\frac{1}{x}}[\/latex]<\/p>\n<\/div>\n<\/div>\n

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17. [latex]y=11,701{\\left(0.97\\right)}^{t}[\/latex]<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
exponential decay; The decay factor,[latex]\\text{ }0.97,[\/latex] is between[latex]\\text{ }0\\text{ }[\/latex]and[latex]\\text{ }1.[\/latex]<\/div>\n<\/div>\n<\/div>\n<\/div>\n

For the following exercises, find the formula for an exponential function that passes through the two points given.<\/p>\n

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18. [latex]\\left(0,6\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(3,750\\right)[\/latex]<\/p>\n<\/div>\n<\/div>\n

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19. [latex]\\left(0,2000\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(2,20\\right)[\/latex]<\/p>\n<\/div>\n

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[latex]f\\left(x\\right)=2000{\\left(0.1\\right)}^{x}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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20. [latex]\\left(-1,\\frac{3}{2}\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(3,24\\right)[\/latex]<\/p>\n<\/div>\n<\/div>\n

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21. [latex]\\left(-2,6\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(3,1\\right)[\/latex]<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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[latex]f\\left(x\\right)={\\left(\\frac{1}{6}\\right)}^{-\\frac{3}{5}}{\\left(\\frac{1}{6}\\right)}^{\\frac{x}{5}}\\approx 2.93{\\left(0.699\\right)}^{x}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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22. [latex]\\left(3,1\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(5,4\\right)[\/latex]<\/p>\n<\/div>\n<\/div>\n

For the following exercises, determine whether the table could represent a function that is linear, exponential, or neither. If it appears to be exponential, find a function that passes through the points.<\/p>\n

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23.<\/p>\n\n\n\n\n
[latex]x[\/latex]<\/strong><\/td>\n1<\/td>\n2<\/td>\n3<\/td>\n4<\/td>\n<\/tr>\n
[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\n70<\/td>\n40<\/td>\n10<\/td>\n-20<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n
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Show Solution<\/span><\/p>\n
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Linear<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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24.<\/p>\n\n\n\n\n
[latex]x[\/latex]<\/strong><\/td>\n1<\/td>\n2<\/td>\n3<\/td>\n4<\/td>\n<\/tr>\n
[latex]h\\left(x\\right)[\/latex]<\/strong><\/td>\n70<\/td>\n49<\/td>\n34.3<\/td>\n24.01<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<\/div>\n
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25.<\/p>\n\n\n\n\n
[latex]x[\/latex]<\/strong><\/td>\n1<\/td>\n2<\/td>\n3<\/td>\n4<\/td>\n<\/tr>\n
[latex]m\\left(x\\right)[\/latex]<\/strong><\/td>\n80<\/td>\n61<\/td>\n42.9<\/td>\n25.61<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n
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Show Solution<\/span><\/p>\n
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Neither<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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26.<\/p>\n\n\n\n\n
\u00a0<\/caption>\n
[latex]x[\/latex]<\/strong><\/td>\n1<\/td>\n2<\/td>\n3<\/td>\n4<\/td>\n<\/tr>\n
[latex]f\\left(x\\right)[\/latex]<\/strong><\/td>\n10<\/td>\n20<\/td>\n40<\/td>\n80<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<\/div>\n
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27.<\/p>\n\n\n\n\n
[latex]x[\/latex]<\/strong><\/td>\n1<\/td>\n2<\/td>\n3<\/td>\n4<\/td>\n<\/tr>\n
[latex]g\\left(x\\right)[\/latex]<\/strong><\/td>\n-3.25<\/td>\n2<\/td>\n7.25<\/td>\n12.5<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n
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Show Solution<\/span><\/p>\n
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Linear<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

For the following exercises, use the compound interest formula,[latex]\\text{ }A\\left(t\\right)=P{\\left(1+\\frac{r}{n}\\right)}^{nt}.[\/latex]<\/p>\n

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28. After a certain number of years, the value of an investment account is represented by the equation[latex]\\text{ }10,250{\\left(1+\\frac{0.04}{12}\\right)}^{120}.\\text{ }[\/latex]What is the value of the account?<\/p>\n<\/div>\n<\/div>\n

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29. What was the initial deposit made to the account in the previous exercise?<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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[latex]$10,250[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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30. How many years had the account from the previous exercise been accumulating interest?<\/p>\n<\/div>\n<\/div>\n

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31. An account is opened with an initial deposit of $6,500 and earns[latex]\\text{ }3.6%\\text{ }[\/latex]interest compounded semi-annually. What will the account be worth in[latex]\\text{ }20\\text{ }[\/latex]years?<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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[latex]$13,268.58[\/latex]<\/p><\/div>\n<\/div>\n<\/div>\n<\/div>\n

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32. How much more would the account in the previous exercise have been worth if the interest were compounding weekly?<\/p>\n<\/div>\n<\/div>\n

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33. Solve the compound interest formula for the principal,[latex]\\text{ }P[\/latex].<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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[latex]P=A\\left(t\\right)\\cdot {\\left(1+\\frac{r}{n}\\right)}^{-nt}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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34. Use the formula found in the previous exercise to calculate the initial deposit of an account that is worth[latex]\\text{ }$14,472.74\\text{ }[\/latex]after earning[latex]\\text{ }5.5%\\text{ }[\/latex]interest compounded monthly for[latex]\\text{ }5\\text{ }[\/latex]years. (Round to the nearest dollar.)<\/p>\n<\/div>\n<\/div>\n

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35. How much more would the account in the previous two exercises be worth if it were earning interest for[latex]\\text{ }5\\text{ }[\/latex]more years?<\/p>\n<\/div>\n

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[latex]$4,572.56[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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36. Use properties of rational exponents to solve the compound interest formula for the interest rate,[latex]\\text{ }r.[\/latex]<\/p>\n<\/div>\n<\/div>\n

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37. Use the formula found in the previous exercise to calculate the interest rate for an account that was compounded semi-annually, had an initial deposit of $9,000 and was worth $13,373.53 after 10 years.<\/p>\n<\/div>\n

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Show Solution<\/span><\/p>\n
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[latex]4%[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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38. Use the formula found in the previous exercise to calculate the interest rate for an account that was compounded monthly, had an initial deposit of $5,500, and was worth $38,455 after 30 years.<\/p>\n<\/div>\n<\/div>\n

For the following exercises, determine whether the equation represents continuous growth, continuous decay, or neither. Explain.<\/p>\n

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39. [latex]y=3742{\\left(e\\right)}^{0.75t}[\/latex]<\/p>\n<\/div>\n

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continuous growth; the growth rate is greater than[latex]\\text{ }0.[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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40. [latex]y=150{\\left(e\\right)}^{\\frac{3.25}{t}}[\/latex]<\/p>\n<\/div>\n<\/div>\n

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41. [latex]y=2.25{\\left(e\\right)}^{-2t}[\/latex]<\/p>\n<\/div>\n

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continuous decay; the growth rate is less than[latex]\\text{ }0.[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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42. Suppose an investment account is opened with an initial deposit of[latex]\\text{ }$12,000\\text{ }[\/latex]earning[latex]\\text{ }7.2%\\text{ }[\/latex]interest compounded continuously. How much will the account be worth after[latex]\\text{ }30\\text{ }[\/latex]years?<\/p>\n<\/div>\n<\/div>\n

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43. How much less would the account from Exercise 42 be worth after[latex]\\text{ }30\\text{ }[\/latex]years if it were compounded monthly instead?<\/p>\n<\/div>\n

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[latex]$669.42[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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Numeric<\/h4>\n

For the following exercises, evaluate each function. Round answers to four decimal places, if necessary.<\/p>\n

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44. [latex]f\\left(x\\right)=2{\\left(5\\right)}^{x},[\/latex] for[latex]\\text{ }f\\left(-3\\right)[\/latex]<\/p>\n<\/div>\n<\/div>\n

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45. [latex]f\\left(x\\right)=-{4}^{2x+3},[\/latex] for[latex]\\text{ }f\\left(-1\\right)[\/latex]<\/p>\n<\/div>\n

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[latex]f\\left(-1\\right)=-4[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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46. [latex]f\\left(x\\right)={e}^{x},[\/latex] for[latex]\\text{ }f\\left(3\\right)[\/latex]<\/p>\n<\/div>\n<\/div>\n

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[latex]f\\left(x\\right)=-2{e}^{x-1},[\/latex] for[latex]\\text{ }f\\left(-1\\right)[\/latex]<\/p>\n<\/div>\n

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[latex]f\\left(-1\\right)\\approx -0.2707[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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47. [latex]f\\left(x\\right)=2.7{\\left(4\\right)}^{-x+1}+1.5,[\/latex] for[latex]f\\left(-2\\right)[\/latex]<\/p>\n<\/div>\n<\/div>\n

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48. [latex]f\\left(x\\right)=1.2{e}^{2x}-0.3,[\/latex] for[latex]\\text{ }f\\left(3\\right)[\/latex]<\/p>\n<\/div>\n

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[latex]f\\left(3\\right)\\approx 483.8146[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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49. [latex]f\\left(x\\right)=-\\frac{3}{2}{\\left(3\\right)}^{-x}+\\frac{3}{2},[\/latex] for[latex]\\text{ }f\\left(2\\right)[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n

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Technology<\/h4>\n

For the following exercises, use a graphing calculator to find the equation of an exponential function given the points on the curve.<\/p>\n

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50. [latex]\\left(0,3\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(3,375\\right)[\/latex]<\/p>\n<\/div>\n

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[latex]y=3\\cdot {5}^{x}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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51. [latex]\\left(3,222.62\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(10,77.456\\right)[\/latex]<\/p>\n<\/div>\n<\/div>\n

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52. [latex]\\left(20,29.495\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(150,730.89\\right)[\/latex]<\/p>\n<\/div>\n

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[latex]y\\approx 18\\cdot {1.025}^{x}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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53. [latex]\\left(5,2.909\\right)\\text{ }[\/latex]and[latex]\\text{ }\\left(13,0.005\\right)[\/latex]<\/p>\n<\/div>\n<\/div>\n

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54. [latex]\\left(11,310.035\\right)\\text{ }[\/latex] and [latex]\\left(25,356.3652\\right)[\/latex]<\/p>\n<\/div>\n

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[latex]y\\approx 0.2\\cdot {1.95}^{x}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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Extensions<\/h4>\n
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55. The annual percentage yield<\/em> (APY) of an investment account is a representation of the actual interest rate earned on a compounding account. It is based on a compounding period of one year. Show that the APY of an account that compounds monthly can be found with the formula[latex]\\text{ }\\text{APY}={\\left(1+\\frac{r}{12}\\right)}^{12}-1.[\/latex]<\/p>\n<\/div>\n<\/div>\n

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56. Repeat the previous exercise to find the formula for the APY of an account that compounds daily. Use the results from this and the previous exercise to develop a function[latex]\\text{ }I\\left(n\\right)\\text{ }[\/latex]for the APY of any account that compounds[latex]\\text{ }n\\text{ }[\/latex]times per year.<\/p>\n<\/div>\n

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[latex]\\text{APY}=\\frac{A\\left(t\\right)-a}{a}=\\frac{a{\\left(1+\\frac{r}{365}\\right)}^{365\\left(1\\right)}-a}{a}=\\frac{a\\left[{\\left(1+\\frac{r}{365}\\right)}^{365}-1\\right]}{a}={\\left(1+\\frac{r}{365}\\right)}^{365}-1;[\/latex][latex]I\\left(n\\right)={\\left(1+\\frac{r}{n}\\right)}^{n}-1[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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57. Recall that an exponential function is any equation written in the form[latex]\\text{ }f\\left(x\\right)=a\\cdot {b}^{x}\\text{ }[\/latex]such that[latex]a[\/latex]and[latex]b[\/latex]are positive numbers and[latex]b\\ne 1.[\/latex]Any positive number[latex]b[\/latex]can be written as[latex]b={e}^{n}[\/latex]for some value of[latex]n[\/latex]. Use this fact to rewrite the formula for an exponential function that uses the number[latex]e[\/latex]as a base.<\/p>\n<\/div>\n<\/div>\n

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58. In an exponential decay function, the base of the exponent is a value between 0 and 1. Thus, for some number[latex]\\text{ }b>1,[\/latex] the exponential decay function can be written as[latex]\\text{ }f\\left(x\\right)=a\\cdot {\\left(\\frac{1}{b}\\right)}^{x}.\\text{ }[\/latex]Use this formula, along with the fact that[latex]\\text{ }b={e}^{n},[\/latex] to show that an exponential decay function takes the form[latex]\\text{ }f\\left(x\\right)=a{\\left(e\\right)}^{-nx}\\text{ }[\/latex]for some positive number[latex]\\text{ }n\\text{ }[\/latex].<\/p>\n<\/div>\n

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Let[latex]\\text{ }f\\text{ }[\/latex]be the exponential decay function[latex]\\text{ }f\\left(x\\right)=a\\cdot {\\left(\\frac{1}{b}\\right)}^{x}\\text{ }[\/latex]such that[latex]\\text{ }b>1.\\text{ }[\/latex]Then for some number[latex]\\text{ }n>0,[\/latex][latex]f\\left(x\\right)=a\\cdot {\\left(\\frac{1}{b}\\right)}^{x}=a{\\left({b}^{-1}\\right)}^{x}=a{\\left({\\left({e}^{n}\\right)}^{-1}\\right)}^{x}=a{\\left({e}^{-n}\\right)}^{x}=a{\\left(e\\right)}^{-nx}.[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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59. The formula for the amount[latex]\\text{ }A\\text{ }[\/latex]in an investment account with a nominal interest rate[latex]\\text{ }r\\text{ }[\/latex]at any time[latex]\\text{ }t\\text{ }[\/latex]is given by[latex]\\text{ }A\\left(t\\right)=a{\\left(e\\right)}^{rt},[\/latex]where[latex]\\text{ }a\\text{ }[\/latex]is the amount of principal initially deposited into an account that compounds continuously. Prove that the percentage of interest earned to principal at any time[latex]\\text{ }t\\text{ }[\/latex]can be calculated with the formula[latex]\\text{ }I\\left(t\\right)={e}^{rt}-1.[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n

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Real-World Applications<\/h4>\n
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60. The fox population in a certain region has an annual growth rate of 9% per year. In the year 2012, there were 23,900 fox counted in the area. What is the fox population predicted to be in the year 2020?<\/p>\n<\/div>\n

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[latex]47,622\\text{ }[\/latex]fox<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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61. A scientist begins with 100 milligrams of a radioactive substance that decays exponentially. After 35 hours, 50mg of the substance remains. How many milligrams will remain after 54 hours?<\/p>\n<\/div>\n<\/div>\n

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62. In the year 1985, a house was valued at $110,000. By the year 2005, the value had appreciated to $145,000. What was the annual growth rate between 1985 and 2005? Assume that the value continued to grow by the same percentage. What was the value of the house in the year 2010?<\/p>\n<\/div>\n

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[latex]1.39%;\\text{ }[\/latex][latex]$155,368.09[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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63. A car was valued at $38,000 in the year 2007. By 2013, the value had depreciated to $11,000 If the car\u2019s value continues to drop by the same percentage, what will it be worth by 2017?<\/p>\n<\/div>\n<\/div>\n

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64. Jamal wants to save $54,000 for a down payment on a home. How much will he need to invest in an account with 8.2% APR, compounding daily, in order to reach his goal in 5 years?<\/p>\n<\/div>\n

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[latex]$35,838.76[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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65. Kyoko has $10,000 that she wants to invest. Her bank has several investment accounts to choose from, all compounding daily. Her goal is to have $15,000 by the time she finishes graduate school in 6 years. To the nearest hundredth of a percent, what should her minimum annual interest rate be in order to reach her goal? (Hint<\/em>: solve the compound interest formula for the interest rate.)<\/p>\n<\/div>\n<\/div>\n

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66. Alyssa opened a retirement account with 7.25% APR in the year 2000. Her initial deposit was $13,500. How much will the account be worth in 2025 if interest compounds monthly? How much more would she make if interest compounded continuously?<\/p>\n<\/div>\n

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[latex]$82,247.78;\\text{ }[\/latex][latex]$449.75[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

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67. An investment account with an annual interest rate of 7% was opened with an initial deposit of $4,000 Compare the values of the account after 9 years when the interest is compounded annually, quarterly, monthly, and continuously.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n

 <\/p>\n

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