{"id":275,"date":"2016-04-21T22:43:41","date_gmt":"2016-04-21T22:43:41","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/introstats1xmaster\/?post_type=chapter&#038;p=275"},"modified":"2017-10-23T21:59:41","modified_gmt":"2017-10-23T21:59:41","slug":"section-exercises-8","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/chapter\/section-exercises-8\/","title":{"raw":"Section Exercises","rendered":"Section Exercises"},"content":{"raw":"<h2 id=\"fs-idm37731072\" class=\"problem\" data-type=\"problem\">The Central Limit Theorem for Sample Means (Averages)<\/h2>\r\n<div class=\"problem\" data-type=\"problem\"><\/div>\r\n<div class=\"problem\" data-type=\"problem\"><em data-effect=\"italics\">Use the following information to answer the next six exercises:<\/em> Yoonie is a personnel manager in a large corporation. Each month she must review 16 of the employees. From past experience, she has found that the reviews take her approximately four hours each to do with a population standard deviation of 1.2 hours. Let <em data-effect=\"italics\">\u03a7<\/em> be the random variable representing the time it takes her to complete one review. Assume <em data-effect=\"italics\">\u03a7<\/em> is normally distributed. Let[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0be the random variable representing the mean time to complete the 16 reviews. Assume that the 16 reviews represent a random set of reviews.<\/div>\r\n<div class=\"problem\" data-type=\"problem\"><\/div>\r\n<div class=\"problem\" data-type=\"problem\">1. What is the mean, standard deviation, and sample size?<\/div>\r\n<section>\r\n<div class=\"problem\" data-type=\"problem\"><\/div>\r\n<div id=\"fs-idm62741104\" class=\"problem\" data-type=\"problem\">\r\n\r\n2. Complete the distributions.\r\n<div id=\"fs-idm16577088\" data-type=\"list\" data-list-type=\"enumerated\" data-number-style=\"lower-alpha\">\r\n<div data-type=\"item\"><em data-effect=\"italics\">X<\/em> ~ _____(_____,_____)<\/div>\r\n<div data-type=\"item\">[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/section><section>\r\n<div id=\"id16709593\" class=\"problem\" data-type=\"problem\">\r\n\r\n3. Find the probability that <strong>one<\/strong> review will take Yoonie from 3.5 to 4.25 hours. Sketch the graph, labeling and scaling the horizontal axis. Shade the region corresponding to the probability.\r\n<div id=\"sublist1346264\" data-type=\"list\" data-list-type=\"enumerated\" data-number-style=\"lower-alpha\">\r\n<div data-type=\"item\">\r\n<figure id=\"fs-idm61024352\"><span id=\"id14288416\" data-type=\"media\" data-alt=\"This is a frequency curve for a normal distribution. It shows a single peak in the center with the curve tapering down to the horizontal axis on each side. The distribution is symmetrical. The horizontal axis represents the random variable X.\"> <img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/132\/2016\/04\/21214603\/fig-ch07_06_01.jpg\" alt=\"This is a frequency curve for a normal distribution. It shows a single peak in the center with the curve tapering down to the horizontal axis on each side. The distribution is symmetrical. The horizontal axis represents the random variable X.\" width=\"380\" data-media-type=\"image\/jpg\" \/><\/span><\/figure>\r\n<\/div>\r\n<div data-type=\"item\"><em data-effect=\"italics\">P<\/em>(________ &lt; <em data-effect=\"italics\">x<\/em> &lt; ________) = _______<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"id14567929\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><section>\r\n<div id=\"id14777355\" class=\"problem\" data-type=\"problem\">\r\n\r\n4. Find the probability that the <strong>mean<\/strong> of a month\u2019s reviews will take Yoonie from 3.5 to 4.25 hrs. Sketch the graph, labeling and scaling the horizontal axis. Shade the region corresponding to the probability.\r\n<div id=\"sublist27646547\" data-type=\"list\" data-list-type=\"enumerated\" data-number-style=\"lower-alpha\">\r\n<div data-type=\"item\">\r\n<figure id=\"fs-idm31915744\"><span id=\"fs-idm62152464\" data-type=\"media\" data-alt=\"This is a frequency curve for a normal distribution. It shows a single peak in the center with the curve tapering down to the horizontal axis on each side. The distribution is symmetrical. The horizontal axis represents the random variable X.\"> <img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/132\/2016\/04\/21214605\/fig-ch07_06_02.jpg\" alt=\"This is a frequency curve for a normal distribution. It shows a single peak in the center with the curve tapering down to the horizontal axis on each side. The distribution is symmetrical. The horizontal axis represents the random variable X.\" width=\"380\" data-media-type=\"image\/jpg\" \/><\/span><\/figure>\r\n<\/div>\r\n<div data-type=\"item\"><em data-effect=\"italics\">5. P<\/em>(________________) = _______<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/section><section>\r\n<div id=\"fs-idm42157728\" class=\"problem\" data-type=\"problem\">What causes the probabilities in 3, 4\u00a0to be different?<\/div>\r\n<div id=\"fs-idm43625488\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section>\r\n<div id=\"fs-idm42157984\" class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div id=\"fs-idm70816816\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm70816560\" class=\"problem\" data-type=\"problem\">6. Find the 95<sup>th<\/sup> percentile for the mean time to complete one month's reviews. Sketch the graph.<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/132\/2016\/04\/21214605\/fig-ch07_06_02.jpg\" alt=\"This is a frequency curve for a normal distribution. It shows a single peak in the center with the curve tapering down to the horizontal axis on each side. The distribution is symmetrical. The horizontal axis represents the random variable X.\" width=\"380\" data-media-type=\"image\/jpg\" \/>The 95<sup>th<\/sup> Percentile =____________<\/div>\r\n<\/section><\/div>\r\n<h1 data-type=\"title\"><\/h1>\r\n<div id=\"element-475\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id6273705\" class=\"problem\" data-type=\"problem\">\r\n\r\n7. Previously, De Anza statistics students estimated that the amount of change daytime statistics students carry is exponentially distributed with a mean of $0.88. Suppose that we randomly pick 25 daytime statistics students.\r\n<ol id=\"element-224\" data-number-style=\"lower-alpha\">\r\n \t<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = ____________<\/li>\r\n \t<li><em data-effect=\"italics\">\u03a7<\/em> ~ _____(_____,_____)<\/li>\r\n \t<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex]= ____________<\/li>\r\n \t<li>[latex]\\displaystyle\\overline{{X}}[\/latex]~ ______ (______, ______)<\/li>\r\n \t<li>Find the probability that an individual had between $0.80 and $1.00. Graph the situation, and shade in the area to be determined.<\/li>\r\n \t<li>Find the probability that the average of the 25 students was between $0.80 and $1.00. Graph the situation, and shade in the area to be determined.<\/li>\r\n \t<li>Explain why there is a difference in part e and part f.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"fs-idp10454080\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<section>\r\n<div id=\"id6273949\" class=\"problem\" data-type=\"problem\">\r\n\r\n8. Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 250 feet and a standard deviation of 50 feet. We randomly sample 49 fly balls.\r\n<ol data-number-style=\"lower-alpha\">\r\n \t<li>If[latex]\\displaystyle\\overline{{X}}[\/latex] = average distance in feet for 49 fly balls, then[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _______(_______,_______)<\/li>\r\n \t<li>What is the probability that the 49 balls traveled an average of less than 240 feet? Sketch the graph. Scale the horizontal axis for[latex]\\displaystyle\\overline{{X}}[\/latex]. \u00a0Shade the region corresponding to the probability. Find the probability.<\/li>\r\n \t<li>Find the 80<sup>th<\/sup> percentile of the distribution of the average of 49 fly balls.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><section>\r\n<div id=\"id6533450\" class=\"problem\" data-type=\"problem\">\r\n\r\n9. According to the Internal Revenue Service, the average length of time for an individual to complete (keep records for, learn, prepare, copy, assemble, and send) IRS Form 1040 is 10.53 hours (without any attached schedules). The distribution is unknown. Let us assume that the standard deviation is two hours. Suppose we randomly sample 36 taxpayers.\r\n<ol id=\"element-685\" data-number-style=\"lower-alpha\">\r\n \t<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = _____________<\/li>\r\n \t<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex]= _____________<\/li>\r\n \t<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\r\n \t<li>Would you be surprised if the 36 taxpayers finished their Form 1040s in an average of more than 12 hours? Explain why or why not in complete sentences.<\/li>\r\n \t<li>Would you be surprised if one taxpayer finished his or her Form 1040 in more than 12 hours? In a complete sentence, explain why.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"fs-idm166717360\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><section>\r\n<div id=\"id6533652\" class=\"problem\" data-type=\"problem\">\r\n\r\n10. Suppose that a category of world-class runners are known to run a marathon (26 miles) in an average of 145 minutes with a standard deviation of 14 minutes. Consider 49 of the races. Let[latex]\\displaystyle\\overline{{X}}[\/latex] the average of the 49 races.\r\n<ol id=\"element-45\" data-number-style=\"lower-alpha\">\r\n \t<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\r\n \t<li>Find the probability that the runner will average between 142 and 146 minutes in these 49 marathons.<\/li>\r\n \t<li>Find the 80<sup>th<\/sup> percentile for the average of these 49 marathons.<\/li>\r\n \t<li>Find the median of the average running times.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><section>\r\n<div id=\"id6534960\" class=\"problem\" data-type=\"problem\">\r\n\r\n11. The length of songs in a collector\u2019s iTunes album collection is uniformly distributed from two to 3.5 minutes. Suppose we randomly pick five albums from the collection. There are a total of 43 songs on the five albums.\r\n<ol data-number-style=\"lower-alpha\">\r\n \t<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = _________<\/li>\r\n \t<li><em data-effect=\"italics\">\u03a7<\/em> ~ _____________<\/li>\r\n \t<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex] = _____________<\/li>\r\n \t<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\r\n \t<li>Find the first quartile for the average song length.<\/li>\r\n \t<li>The IQR(interquartile range) for the average song length is from _______\u2013_______.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"fs-idm135637280\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><section>\r\n<div id=\"id6536525\" class=\"problem\" data-type=\"problem\">\r\n\r\n12. In 1940 the average size of a U.S. farm was 174 acres. Let\u2019s say that the standard deviation was 55 acres. Suppose we randomly survey 38 farmers from 1940.\r\n<ol id=\"madeup2\" data-number-style=\"lower-alpha\">\r\n \t<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = _____________<\/li>\r\n \t<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex] = _____________<\/li>\r\n \t<li>[latex]\\displaystyle\\overline{{X}}[\/latex]~ _____(_____,_____)<\/li>\r\n \t<li>The IQR for[latex]\\displaystyle\\overline{{X}}[\/latex] is from _______ acres to _______ acres.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><section>\r\n<div id=\"id6264723\" class=\"problem\" data-type=\"problem\">\r\n\r\n13. Determine which of the following are true and which are false. Then, in complete sentences, justify your answers.\r\n<ol id=\"fs-idm39736064\" data-number-style=\"lower-alpha\">\r\n \t<li>When the sample size is large, the mean of[latex]\\displaystyle\\overline{{X}}[\/latex] is approximately equal to the mean of <em data-effect=\"italics\">\u03a7<\/em>.<\/li>\r\n \t<li>When the sample size is large,[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0is approximately normally distributed.<\/li>\r\n \t<li>When the sample size is large, the standard deviation of[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0is approximately the same as the standard deviation of <em data-effect=\"italics\">\u03a7<\/em>.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"fs-idp58516336\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><section>\r\n<div id=\"id6272391\" class=\"problem\" data-type=\"problem\">\r\n\r\n14. The percent of fat calories that a person in America consumes each day is normally distributed with a mean of about 36 and a standard deviation of about ten. Suppose that 16 individuals are randomly chosen. Let[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0= average percent of fat calories.\r\n<ol id=\"eip-idm27753728\" data-number-style=\"lower-alpha\">\r\n \t<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ ______(______, ______)<\/li>\r\n \t<li>For the group of 16, find the probability that the average percent of fat calories consumed is more than five. Graph the situation and shade in the area to be determined.<\/li>\r\n \t<li>Find the first quartile for the average percent of fat calories.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><section>\r\n<div id=\"id6535840\" class=\"problem\" data-type=\"problem\">\r\n\r\n15. The distribution of income in some Third World countries is considered wedge shaped (many very poor people, very few middle income people, and even fewer wealthy people). Suppose we pick a country with a wedge shaped distribution. Let the average salary be $2,000 per year with a standard deviation of $8,000. We randomly survey 1,000 residents of that country.\r\n<ol data-number-style=\"lower-alpha\">\r\n \t<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = _____________<\/li>\r\n \t<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0= _____________<\/li>\r\n \t<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\r\n \t<li>How is it possible for the standard deviation to be greater than the average?<\/li>\r\n \t<li>Why is it more likely that the average of the 1,000 residents will be from $2,000 to $2,100 than from $2,100 to $2,200?<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"fs-idm50399184\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><section>\r\n<div id=\"id6538396\" class=\"problem\" data-type=\"problem\">\r\n\r\n16. Which of the following is NOT TRUE about the distribution for averages?\r\n<ol data-number-style=\"lower-alpha\">\r\n \t<li>The mean, median, and mode are equal.<\/li>\r\n \t<li>The area under the curve is one.<\/li>\r\n \t<li>The curve never touches the <em data-effect=\"italics\">x<\/em>-axis.<\/li>\r\n \t<li>The curve is skewed to the right.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><section>\r\n<div id=\"id6538522\" class=\"problem\" data-type=\"problem\">\r\n\r\n17. The cost of unleaded gasoline in the Bay Area once followed an unknown distribution with a mean of $4.59 and a standard deviation of $0.10. Sixteen gas stations from the Bay Area are randomly chosen. We are interested in the average cost of gasoline for the 16 gas stations. The distribution to use for the average cost of gasoline for the 16 gas stations is:\r\n<div id=\"element-728\" data-type=\"list\" data-list-type=\"enumerated\" data-number-style=\"lower-alpha\">\r\n<div data-type=\"item\">[latex]\\displaystyle\\overline{{X}}[\/latex] ~ <em data-effect=\"italics\">N<\/em>(4.59, 0.10)<\/div>\r\n<div data-type=\"item\">[latex]\\displaystyle\\overline{{X}}[\/latex] ~ <em data-effect=\"italics\">N<\/em>(4.59,\u00a0[latex]\\frac{{0.10}}{{\\sqrt{16}}}[\/latex])&gt;<\/div>\r\n<div data-type=\"item\">[latex]\\displaystyle\\overline{{X}}[\/latex] ~ <em data-effect=\"italics\">N<\/em>(4.59,\u00a0[latex]\\frac{{16}}{{0.10}}[\/latex])<\/div>\r\n<div data-type=\"item\">[latex]\\displaystyle\\overline{{X}}[\/latex] ~ <em data-effect=\"italics\">N<\/em>(4.59,\u00a0[latex]\\frac{{\\sqrt{16}}}{{0.10}}[\/latex])<\/div>\r\n<\/div>\r\n<div data-type=\"item\">\r\n<h2>The Central Limit Theorem for Sums<\/h2>\r\n<\/div>\r\n<\/div>\r\n<\/section>\r\n<div data-type=\"item\">\r\n\r\n<em data-effect=\"italics\">Use the following information to answer the next four exercises:<\/em> An unknown distribution has a mean of 80 and a standard deviation of 12. A sample size of 95 is drawn randomly from the population.\r\n\r\n<section>\r\n<div id=\"eip-202\" class=\"problem\" data-type=\"problem\">18. Find the probability that the sum of the 95 values is greater than 7,650.<\/div>\r\n<\/section><section>\r\n<div class=\"problem\" data-type=\"problem\">19. Find the probability that the sum of the 95 values is less than 7,400.<\/div>\r\n<\/section><section>\r\n<div id=\"eip-637\" class=\"problem\" data-type=\"problem\">20.Find the sum that is two standard deviations above the mean of the sums.<\/div>\r\n<\/section><section>\r\n<div class=\"problem\" data-type=\"problem\">21. Find the sum that is 1.5 standard deviations below the mean of the sums.<\/div>\r\n<\/section><em data-effect=\"italics\">Use the following information to answer the next five exercises:<\/em> The distribution of results from a cholesterol test has a mean of 180 and a standard deviation of 20. A sample size of 40 is drawn randomly.\r\n\r\n<section>\r\n<div class=\"problem\" data-type=\"problem\">22. Find the probability that the sum of the 40 values is greater than 7,500.<\/div>\r\n<\/section><section>\r\n<div id=\"eip-608\" class=\"problem\" data-type=\"problem\">23. Find the probability that the sum of the 40 values is less than 7,000.<\/div>\r\n<\/section><section>\r\n<div id=\"eip-399\" class=\"problem\" data-type=\"problem\">24. Find the sum that is one standard deviation above the mean of the sums.<\/div>\r\n<div id=\"eip-875\" class=\"solution\" data-type=\"solution\">\u00a025.\u00a0Find the sum that is 1.5 standard deviations below the mean of the sums.<\/div>\r\n<\/section><section>\r\n<div id=\"eip-726\" class=\"problem\" data-type=\"problem\">26. Find the percentage of sums between 1.5 standard deviations below the mean of the sums and one standard deviation above the mean of the sums.<\/div>\r\n<div id=\"eip-673\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><em data-effect=\"italics\">Use the following information to answer the next six exercises:<\/em> A researcher measures the amount of sugar in several cans of the same soda. The mean is 39.01 with a standard deviation of 0.5. The researcher randomly selects a sample of 100.\r\n\r\n<section>\r\n<div class=\"problem\" data-type=\"problem\">27. Find the probability that the sum of the 100 values is greater than 3,910.<\/div>\r\n<\/section><section>\r\n<div class=\"problem\" data-type=\"problem\">28. Find the probability that the sum of the 100 values is less than 3,900.<\/div>\r\n<div class=\"solution\" data-type=\"solution\">\u00a029.\u00a0Find the probability that the sum of the 100 values falls between the numbers you found in 28, 29.<\/div>\r\n<\/section><section>\r\n<div id=\"eip-662\" class=\"problem\" data-type=\"problem\">30. Find the sum with a <em data-effect=\"italics\">z<\/em>\u2013score of \u20132.5.<\/div>\r\n<div id=\"eip-650\" class=\"solution\" data-type=\"solution\">31. Find the sum with a <em data-effect=\"italics\">z<\/em>\u2013score of 0.5.<\/div>\r\n<\/section><section>\r\n<div id=\"eip-573\" class=\"problem\" data-type=\"problem\">32. Find the probability that the sums will fall between the <em data-effect=\"italics\">z<\/em>-scores \u20132 and 1.<\/div>\r\n<div id=\"eip-910\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section>\u00a0<em data-effect=\"italics\">Use the following information to answer the next four exercise:<\/em> An unknown distribution has a mean 12 and a standard deviation of one. A sample size of 25 is taken. Let <em data-effect=\"italics\">X<\/em> = the object of interest.\r\n\r\n<section>\r\n<div id=\"eip-37\" class=\"problem\" data-type=\"problem\">33. What is the mean of <em data-effect=\"italics\">\u03a3X<\/em>?<\/div>\r\n<\/section><section>\r\n<div class=\"problem\" data-type=\"problem\">34. What is the standard deviation of <em data-effect=\"italics\">\u03a3X<\/em>?<\/div>\r\n<div class=\"solution\" data-type=\"solution\">\u00a035.\u00a0What is <em data-effect=\"italics\">P<\/em>(<em data-effect=\"italics\">\u03a3x<\/em> = 290)?<\/div>\r\n<\/section><section>\r\n<div id=\"eip-587\" class=\"problem\" data-type=\"problem\">36. What is <em data-effect=\"italics\">P<\/em>(<em data-effect=\"italics\">\u03a3x<\/em> &gt; 290)?<\/div>\r\n<\/section>37. True or False: only the sums of normal distributions are also normal distributions.\r\n\r\n<section>\r\n<div id=\"eip-688\" class=\"problem\" data-type=\"problem\">38. In order for the sums of a distribution to approach a normal distribution, what must be true?<\/div>\r\n<div id=\"eip-227\" class=\"solution\" data-type=\"solution\">\u00a039.\u00a0What three things must you know about a distribution to find the probability of sums?<\/div>\r\n<\/section><section>\r\n<div id=\"eip-389\" class=\"problem\" data-type=\"problem\">40. An unknown distribution has a mean of 25 and a standard deviation of six. Let <em data-effect=\"italics\">X<\/em> = one object from this distribution. What is the sample size if the standard deviation of <em data-effect=\"italics\">\u03a3X<\/em> is 42?<\/div>\r\n<div id=\"eip-826\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section>41. An unknown distribution has a mean of 19 and a standard deviation of 20. Let <em data-effect=\"italics\">X<\/em> = the object of interest. What is the sample size if the mean of <em data-effect=\"italics\">\u03a3X<\/em> is 15,200?<em data-effect=\"italics\">\r\n<\/em><em data-effect=\"italics\">Use the following information to answer the next three exercises.<\/em> A market researcher analyzes how many electronics devices customers buy in a single purchase. The distribution has a mean of three with a standard deviation of 0.7. She samples 400 customers.\r\n\r\n<section>\r\n<div class=\"problem\" data-type=\"problem\">42. What is the <em data-effect=\"italics\">z<\/em>-score for <em data-effect=\"italics\">\u03a3x<\/em> = 840?<\/div>\r\n<div id=\"eip-263\" class=\"solution\" data-type=\"solution\">\u00a043.\u00a0What is the <em data-effect=\"italics\">z<\/em>-score for <em data-effect=\"italics\">\u03a3x<\/em> = 1,186?<\/div>\r\n<\/section><section>\r\n<div id=\"eip-893\" class=\"problem\" data-type=\"problem\">44. What is <em data-effect=\"italics\">P<\/em>(<em data-effect=\"italics\">\u03a3x<\/em> &lt; 1,186)?<\/div>\r\n<div class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><em data-effect=\"italics\">Use the following information to answer the next three exercises:<\/em> An unkwon distribution has a mean of 100, a standard deviation of 100, and a sample size of 100. Let <em data-effect=\"italics\">X<\/em> = one object of interest.\r\n\r\n<section>\r\n<div id=\"eip-217\" class=\"problem\" data-type=\"problem\">45. What is the mean of <em data-effect=\"italics\">\u03a3X<\/em>?<\/div>\r\n<\/section><section>\r\n<div class=\"problem\" data-type=\"problem\">46. What is the standard deviation of <em data-effect=\"italics\">\u03a3X<\/em>?<\/div>\r\n<div id=\"eip-891\" class=\"solution\" data-type=\"solution\">\u00a047.\u00a0What is <em data-effect=\"italics\">P<\/em>(<em data-effect=\"italics\">\u03a3x<\/em> &gt; 9,000)?<\/div>\r\n<\/section>\r\n<div id=\"fs-idm54402176\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm54401920\" class=\"problem\" data-type=\"problem\">48. Which of the following is NOT TRUE about the theoretical distribution of sums?<\/div>\r\n<\/section><\/div>\r\n<ol id=\"fs-idm98145264\" data-number-style=\"lower-alpha\">\r\n \t<li>The mean, median and mode are equal.<\/li>\r\n \t<li>The area under the curve is one.<\/li>\r\n \t<li>The curve never touches the <em data-effect=\"italics\">x<\/em>-axis.<\/li>\r\n \t<li>The curve is skewed to the right.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"element-119\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id6533195\" class=\"problem\" data-type=\"problem\">\r\n\r\n49. Suppose that the duration of a particular type of criminal trial is known to have a mean of 21 days and a standard deviation of seven days. We randomly sample nine trials.\r\n<ol id=\"element-645\" data-number-style=\"lower-alpha\">\r\n \t<li>In words, <em data-effect=\"italics\">\u03a3X<\/em> = ______________<\/li>\r\n \t<li><em data-effect=\"italics\">\u03a3X<\/em> ~ _____(_____,_____)<\/li>\r\n \t<li>Find the probability that the total length of the nine trials is at least 225 days.<\/li>\r\n \t<li>Ninety percent of the total of nine of these types of trials will last at least how long?<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"id6533339\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n50.Suppose that the weight of open boxes of cereal in a home with children is uniformly distributed from two to six pounds with a mean of four pounds and standard deviation of 1.1547. We randomly survey 64 homes with children.\r\n\r\n<section>\r\n<div id=\"id6532824\" class=\"problem\" data-type=\"problem\">\r\n<ol id=\"element-173\" data-number-style=\"lower-alpha\">\r\n \t<li>In words, <em data-effect=\"italics\">X<\/em> = _____________<\/li>\r\n \t<li>The distribution is _______.<\/li>\r\n \t<li>In words, <em data-effect=\"italics\">\u03a3X<\/em> = _______________<\/li>\r\n \t<li><em data-effect=\"italics\">\u03a3X<\/em> ~ _____(_____,_____)<\/li>\r\n \t<li>Find the probability that the total weight of open boxes is less than 250 pounds.<\/li>\r\n \t<li>Find the 35<sup>th<\/sup> percentile for the total weight of open boxes of cereal.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section>\r\n<div id=\"element-138\" class=\"exercise\" data-type=\"exercise\"><section>51. Salaries for teachers in a particular elementary school district are normally distributed with a mean of $44,000 and a standard deviation of $6,500. We randomly survey ten teachers from that district.<\/section><\/div>\r\n<ol id=\"fs-idm127251264\" data-number-style=\"lower-alpha\">\r\n \t<li>In words, <em data-effect=\"italics\">X<\/em> = ______________<\/li>\r\n \t<li><em data-effect=\"italics\">X<\/em> ~ _____(_____,_____)<\/li>\r\n \t<li>In words, <em data-effect=\"italics\">\u03a3X<\/em> = _____________<\/li>\r\n \t<li><em data-effect=\"italics\">\u03a3X<\/em> ~ _____(_____,_____)<\/li>\r\n \t<li>Find the probability that the teachers earn a total of over $400,000.<\/li>\r\n \t<li>Find the 90<sup>th<\/sup> percentile for an individual teacher's salary.<\/li>\r\n \t<li>Find the 90<sup>th<\/sup> percentile for the sum of ten teachers' salary.<\/li>\r\n \t<li>If we surveyed 70 teachers instead of ten, graphically, how would that change the distribution in part d?<\/li>\r\n \t<li>If each of the 70 teachers received a $3,000 raise, graphically, how would that change the distribution in part b?<\/li>\r\n<\/ol>\r\n<h2>Using the Central Limit Theorem<\/h2>\r\n<div id=\"fs-idm67922240\" class=\"solution\" data-type=\"solution\">\r\n<p data-type=\"glossary-title\">\u00a0<em data-effect=\"italics\">Use the following information to answer the next 8\u00a0exercises:<\/em> A manufacturer produces 25-pound lifting weights. The lowest actual weight is 24 pounds, and the highest is 26 pounds. Each weight is equally likely so the distribution of weights is uniform. A sample of 100 weights is taken.<\/p>\r\n<p data-type=\"glossary-title\">52. What is the distribution for the weights of one 25-pound lifting weight? What is the mean and standard deivation?<\/p>\r\n<p data-type=\"glossary-title\">53. What is the distribution for the mean weight of 100 25-pound lifting weights?<\/p>\r\n<p data-type=\"glossary-title\">54. Find the probability that the mean actual weight for the 100 weights is less than 24.9.<\/p>\r\n<p data-type=\"glossary-title\">55. Find the probability that the mean actual weight for the 100 weights is greater than 25.2.<\/p>\r\n\r\n<div class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm65102048\" class=\"problem\" data-type=\"problem\">56. Find the 90<sup>th<\/sup> percentile for the mean weight for the 100 weights.<\/div>\r\n<div id=\"fs-idm110485568\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<div class=\"solution\" data-type=\"solution\">57. What is the distribution for the sum of the weights of 100 25-pound lifting weights?<\/div>\r\n<div class=\"solution\" data-type=\"solution\">58. Find <em data-effect=\"italics\">P<\/em>(<em data-effect=\"italics\">\u03a3x<\/em> &lt; 2,450).<\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div id=\"exercise12\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm115316000\" class=\"problem\" data-type=\"problem\">59. Find the 90<sup>th<\/sup> percentile for the total weight of the 100 weights.<\/div>\r\n<div id=\"fs-idm57878688\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div data-type=\"newline\"><em data-effect=\"italics\">\u00a0<\/em><\/div>\r\n<p data-type=\"glossary-title\"><em data-effect=\"italics\">Use the following information to answer the next 9\u00a0exercises:<\/em> The length of time a particular smartphone's battery lasts follows an exponential distribution with a mean of ten months. A sample of 64 of these smartphones is taken.<\/p>\r\n<p data-type=\"glossary-title\">60. What is the standard deviation?<\/p>\r\n<p data-type=\"glossary-title\">61. What is the parameter <em data-effect=\"italics\">m<\/em>?<\/p>\r\n\r\n<div id=\"fs-idm110175696\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm119290064\" class=\"solution\" data-type=\"solution\">62. What is the distribution for the length of time one battery lasts?<\/div>\r\n<div class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div id=\"fs-idm151129248\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm53240800\" class=\"problem\" data-type=\"problem\">63. What is the distribution for the mean length of time 64 batteries last?<\/div>\r\n<div class=\"solution\" data-type=\"solution\"><\/div>\r\n<div id=\"fs-idm34212208\" class=\"solution\" data-type=\"solution\">64. What is the distribution for the total length of time 64 batteries last?<\/div>\r\n<div class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div id=\"fs-idm1366160\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm41789648\" class=\"problem\" data-type=\"problem\">65. Find the probability that the sample mean is between seven and 11.<\/div>\r\n<div id=\"fs-idm51974096\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\">66. Find the 80<sup>th<\/sup> percentile for the total length of time 64 batteries last.<\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div id=\"fs-idm41589104\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm45566256\" class=\"problem\" data-type=\"problem\">67. Find the <em data-effect=\"italics\">IQR<\/em> for the mean amount of time 64 batteries last.<\/div>\r\n<div class=\"problem\" data-type=\"problem\"><\/div>\r\n<div id=\"fs-idm46764496\" class=\"solution\" data-type=\"solution\">68.\u00a0Find the middle 80% for the total amount of time 64 batteries last.<\/div>\r\n<\/section><\/div>\r\n<div data-type=\"newline\"><em data-effect=\"italics\">\u00a0<\/em><\/div>\r\n<p data-type=\"glossary-title\"><em data-effect=\"italics\">Use the following information to answer the next 4 exercises:<\/em> A uniform distribution has a minimum of six and a maximum of ten. A sample of 50 is taken.<\/p>\r\n\r\n<div id=\"fs-idm1612656\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm47127360\" class=\"problem\" data-type=\"problem\">69. Find <em data-effect=\"italics\">P<\/em>(<em data-effect=\"italics\">\u03a3x<\/em> &gt; 420).<\/div>\r\n<div id=\"fs-idm7883840\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div id=\"fs-idm48638032\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm30917728\" class=\"problem\" data-type=\"problem\">70. a)Find the 90<sup>th<\/sup> percentile for the sums.<\/div>\r\n<\/section><\/div>\r\n<div id=\"fs-idm53694544\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm53230816\" class=\"problem\" data-type=\"problem\">b) Find the 15<sup>th<\/sup> percentile for the sums.<\/div>\r\n<div id=\"fs-idm143692576\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div id=\"fs-idm16561168\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm46777472\" class=\"problem\" data-type=\"problem\">71. a) Find the first quartile for the sums.<\/div>\r\n<\/section><\/div>\r\n<div id=\"fs-idp10404400\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm78936016\" class=\"problem\" data-type=\"problem\">b) Find the third quartile for the sums.<\/div>\r\n<div id=\"fs-idp671104\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<section id=\"fs-idm65344016\" class=\"practice\" data-depth=\"1\">\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div id=\"fs-idm111220240\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm73987984\" class=\"problem\" data-type=\"problem\">72. Find the 80<sup>th<\/sup> percentile for the sums.<\/div>\r\n<div class=\"problem\" data-type=\"problem\"><\/div>\r\n<\/section><\/div>\r\n<\/section><section id=\"fs-idm47834016\" class=\"free-response\" data-depth=\"1\">\r\n<div id=\"element-941\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id6533927\" class=\"problem\" data-type=\"problem\">\r\n\r\n73. The attention span of a two-year-old is exponentially distributed with a mean of about eight minutes. Suppose we randomly survey 60 two-year-olds.\r\n<ol data-number-style=\"lower-alpha\">\r\n \t<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = _______<\/li>\r\n \t<li><em data-effect=\"italics\">\u03a7<\/em> ~ _____(_____,_____)<\/li>\r\n \t<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex]= ____________<\/li>\r\n \t<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\r\n \t<li>Before doing any calculations, which do you think will be higher? Explain why.\r\n<ol data-number-style=\"lower-roman\">\r\n \t<li>The probability that an individual attention span is less than ten minutes.<\/li>\r\n \t<li>The probability that the average attention span for the 60 children is less than ten minutes?<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Calculate the probabilities in part e.<\/li>\r\n \t<li>Explain why the distribution for[latex]\\displaystyle\\overline{{X}}[\/latex] is not exponential.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id6536735\" class=\"problem\" data-type=\"problem\">\r\n\r\n74. The closing stock prices of 35 U.S. semiconductor manufacturers are given as follows.<span data-type=\"list\" data-list-type=\"labeled-item\" data-display=\"inline\"> <span data-type=\"item\">8.625<\/span> <span data-type=\"item\">30.25<\/span> <span data-type=\"item\">27.625<\/span> <span data-type=\"item\">46.75<\/span> <span data-type=\"item\">32.875<\/span> <span data-type=\"item\">18.25<\/span> <span data-type=\"item\">5<\/span> <span data-type=\"item\">0.125<\/span> <span data-type=\"item\">2.9375<\/span> <span data-type=\"item\">6.875<\/span> <span data-type=\"item\">28.25<\/span> <span data-type=\"item\">24.25<\/span> <span data-type=\"item\">21<\/span> <span data-type=\"item\">1.5<\/span> <span data-type=\"item\">30.25<\/span> <span data-type=\"item\">71<\/span> <span data-type=\"item\">43.5<\/span> <span data-type=\"item\">49.25<\/span> <span data-type=\"item\">2.5625<\/span> <span data-type=\"item\">31<\/span> <span data-type=\"item\">16.5<\/span> <span data-type=\"item\">9.5<\/span> <span data-type=\"item\">18.5<\/span> <span data-type=\"item\">18<\/span> <span data-type=\"item\">9<\/span> <span data-type=\"item\">10.5<\/span> <span data-type=\"item\">16.625<\/span> <span data-type=\"item\">1.25<\/span> <span data-type=\"item\">18<\/span> <span data-type=\"item\">12.87<\/span> <span data-type=\"item\">7<\/span> <span data-type=\"item\">12.875<\/span> <span data-type=\"item\">2.875<\/span> <span data-type=\"item\">60.25<\/span> <span data-type=\"item\">29.25<\/span> <\/span>\r\n<ol id=\"madeup9\" data-number-style=\"lower-alpha\">\r\n \t<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = ______________<\/li>\r\n \t<li>\r\n<ol id=\"list234325\" data-number-style=\"lower-roman\">\r\n \t<li>[latex]\\displaystyle\\overline{{x}}[\/latex] = _____<\/li>\r\n \t<li><em data-effect=\"italics\">s<sub>x<\/sub><\/em> = _____<\/li>\r\n \t<li><em data-effect=\"italics\">n<\/em> = _____<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Construct a histogram of the distribution of the averages. Start at <em data-effect=\"italics\">x<\/em> = \u20130.0005. Use bar widths of ten.<\/li>\r\n \t<li>In words, describe the distribution of stock prices.<\/li>\r\n \t<li>Randomly average five stock prices together. (Use a random number generator.) Continue averaging five pieces together until you have ten averages. List those ten averages.<\/li>\r\n \t<li>Use the ten averages from part e to calculate the following.\r\n<ol id=\"listhgklasdlfh11\" data-number-style=\"lower-roman\">\r\n \t<li>[latex]\\displaystyle\\overline{{x}}[\/latex] = _____<\/li>\r\n \t<li><em data-effect=\"italics\">s<sub>x<\/sub><\/em> = _____<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Construct a histogram of the distribution of the averages. Start at <em data-effect=\"italics\">x<\/em> = -0.0005. Use bar widths of ten.<\/li>\r\n \t<li>Does this histogram look like the graph in part c?<\/li>\r\n \t<li>In one or two complete sentences, explain why the graphs either look the same or look different?<\/li>\r\n \t<li>Based upon the theory of the <strong>central limit theorem<\/strong>,[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0~ _____(_____,____)<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"id6537488\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<\/section>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div data-type=\"newline\"><em data-effect=\"italics\">\u00a0<\/em><\/div>\r\n<p data-type=\"glossary-title\"><em data-effect=\"italics\">Use the following information to answer the next three exercises:<\/em> Richard\u2019s Furniture Company delivers furniture from 10 A.M. to 2 P.M. continuously and uniformly. We are interested in how long (in hours) past the 10 A.M. start time that individuals wait for their delivery.<\/p>\r\n\r\n<div class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id10684324\" class=\"problem\" data-type=\"problem\">\r\n\r\n<em data-effect=\"italics\">75. \u03a7<\/em> ~ _____(_____,_____)\r\n<ol id=\"element-596\" data-number-style=\"lower-alpha\">\r\n \t<li><em data-effect=\"italics\">U<\/em>(0,4)<\/li>\r\n \t<li><em data-effect=\"italics\">U<\/em>(10,2)<\/li>\r\n \t<li><em data-effect=\"italics\">E\u03c7p<\/em>(2)<\/li>\r\n \t<li><em data-effect=\"italics\">N<\/em>(2,1)<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><\/div>\r\n<div id=\"element-407\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id11298063\" class=\"problem\" data-type=\"problem\">\r\n\r\n76. The average wait time is:\r\n<ol data-number-style=\"lower-alpha\">\r\n \t<li>one hour.<\/li>\r\n \t<li>two hours.<\/li>\r\n \t<li>two and a half hours.<\/li>\r\n \t<li>four hours.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"id11298138\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div id=\"element-191\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id11298162\" class=\"problem\" data-type=\"problem\">\r\n\r\n77. Suppose that it is now past noon on a delivery day. The probability that a person must wait at least one and a half <strong>more<\/strong> hours is:\r\n<ol id=\"fs-idp191113008\" data-number-style=\"lower-alpha\">\r\n \t<li>[latex]\\frac{1}{4}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{1}{2}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{3}{4}[\/latex]<\/li>\r\n \t<li>[latex]\\frac{3}{8}[\/latex]<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><\/div>\r\n<p data-type=\"glossary-title\"><em data-effect=\"italics\">Use the following information to answer the next two exercises:<\/em> The time to wait for a particular rural bus is distributed uniformly from zero to 75 minutes. One hundred riders are randomly sampled to learn how long they waited.<\/p>\r\n\r\n<div id=\"element-620\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id6538203\" class=\"problem\" data-type=\"problem\">\r\n\r\n78. The 90<sup>th<\/sup> percentile sample average wait time (in minutes) for a sample of 100 riders is:\r\n<ol id=\"element-576\" data-number-style=\"lower-alpha\">\r\n \t<li>315.0<\/li>\r\n \t<li>40.3<\/li>\r\n \t<li>38.5<\/li>\r\n \t<li>65.2<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"id6538281\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div id=\"element-339\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id6538305\" class=\"problem\" data-type=\"problem\">\r\n\r\n79. Would you be surprised, based upon numerical calculations, if the sample average wait time (in minutes) for 100 riders was less than 30 minutes?\r\n<ol data-number-style=\"lower-alpha\">\r\n \t<li>yes<\/li>\r\n \t<li>no<\/li>\r\n \t<li>There is not enough information.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><\/div>\r\n<div data-type=\"newline\"><em data-effect=\"italics\">\u00a0<\/em><\/div>\r\n<p data-type=\"glossary-title\"><em data-effect=\"italics\">Use the following to answer the next two exercises:<\/em> The cost of unleaded gasoline in the Bay Area once followed an unknown distribution with a mean of $4.59 and a standard deviation of $0.10. Sixteen gas stations from the Bay Area are randomly chosen. We are interested in the average cost of gasoline for the 16 gas stations.<\/p>\r\n\r\n<div id=\"element-644\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id6538784\" class=\"problem\" data-type=\"problem\">\r\n\r\n80. What's the approximate probability that the average price for 16 gas stations is over $4.69?\r\n<ol data-number-style=\"lower-alpha\">\r\n \t<li>almost zero<\/li>\r\n \t<li>0.1587<\/li>\r\n \t<li>0.0943<\/li>\r\n \t<li>unknown<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"id6538862\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"eip-id1164882896740\" class=\"problem\" data-type=\"problem\">\r\n\r\n81. Find the probability that the average price for 30 gas stations is less than $4.55.\r\n<ol id=\"element-193\" data-number-style=\"lower-alpha\">\r\n \t<li>0.6554<\/li>\r\n \t<li>0.3446<\/li>\r\n \t<li>0.0142<\/li>\r\n \t<li>0.9858<\/li>\r\n \t<li>0<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><\/div>\r\n<div id=\"eip-786\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div class=\"problem\" data-type=\"problem\">\r\n\r\n82. Suppose in a local Kindergarten through 12<sup>th<\/sup> grade (K - 12) school district, 53 percent of the population favor a charter school for grades K through five. A simple random sample of 300 is surveyed. Calculate following using the normal approximation to the binomial distribution.\r\n<ol id=\"Charter_School\" data-number-style=\"lower-alpha\">\r\n \t<li>Find the probability that less than 100 favor a charter school for grades K through 5.<\/li>\r\n \t<li>Find the probability that 170 or more favor a charter school for grades K through 5.<\/li>\r\n \t<li>Find the probability that no more than 140 favor a charter school for grades K through 5.<\/li>\r\n \t<li>Find the probability that there are fewer than 130 that favor a charter school for grades K through 5.<\/li>\r\n \t<li>Find the probability that exactly 150 favor a charter school for grades K through 5.<\/li>\r\n<\/ol>\r\n83. If you have access to an appropriate calculator or computer software, try calculating these probabilities using the technology.\r\n\r\n<\/div>\r\n<div class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div id=\"eip-140\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"eip-821\" class=\"problem\" data-type=\"problem\">\r\n\r\n84. Four friends, Janice, Barbara, Kathy and Roberta, decided to carpool together to get to school. Each day the driver would be chosen by randomly selecting one of the four names. They carpool to school for 96 days. Use the normal approximation to the binomial to calculate the following probabilities. Round the standard deviation to four decimal places.\r\n<ol id=\"Carpool\" data-number-style=\"lower-alpha\">\r\n \t<li>Find the probability that Janice is the driver at most 20 days.<\/li>\r\n \t<li>Find the probability that Roberta is the driver more than 16 days.<\/li>\r\n \t<li>Find the probability that Barbara drives exactly 24 of those 96 days.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><\/div>\r\n<div id=\"element-440\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id6182284\" class=\"problem\" data-type=\"problem\">\r\n\r\n<em data-effect=\"italics\">85. X<\/em> ~ <em data-effect=\"italics\">N<\/em>(60, 9). Suppose that you form random samples of 25 from this distribution. Let[latex]\\displaystyle\\overline{{X}}[\/latex] be the random variable of averages. Let <em data-effect=\"italics\">\u03a3X<\/em> be the random variable of sums. For parts c through f, sketch the graph, shade the region, label and scale the horizontal axis for[latex]\\displaystyle\\overline{{X}}[\/latex], and find the probability.\r\n<ol id=\"element-455\" data-number-style=\"lower-alpha\">\r\n \t<li>Sketch the distributions of <em data-effect=\"italics\">X<\/em> and[latex]\\displaystyle\\overline{{X}}[\/latex]on the same graph.<\/li>\r\n \t<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\r\n \t<li><em data-effect=\"italics\">P<\/em>([latex]\\displaystyle\\overline{{x}}[\/latex]&lt; 60) = _____<\/li>\r\n \t<li>Find the 30<sup>th<\/sup> percentile for the mean.<\/li>\r\n \t<li><em data-effect=\"italics\">P<\/em>(56 &lt;[latex]\\displaystyle\\overline{{x}}[\/latex]&lt; 62) = _____<\/li>\r\n \t<li><em data-effect=\"italics\">P<\/em>(18 &lt;[latex]\\displaystyle\\overline{{x}}[\/latex]\u00a0&lt; 58) = _____<\/li>\r\n \t<li><em data-effect=\"italics\">\u03a3x<\/em> ~ _____(_____,_____)<\/li>\r\n \t<li>Find the minimum value for the upper quartile for the sum.<\/li>\r\n \t<li><em data-effect=\"italics\">P<\/em>(1,400 &lt; <em data-effect=\"italics\">\u03a3x<\/em> &lt; 1,550) = _____<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"id6009706\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id6534247\" class=\"problem\" data-type=\"problem\">\r\n\r\n86. Suppose that the length of research papers is uniformly distributed from ten to 25 pages. We survey a class in which 55 research papers were turned in to a professor. The 55 research papers are considered a random collection of all papers. We are interested in the average length of the research papers.\r\n<ol id=\"element-826\" data-number-style=\"lower-alpha\">\r\n \t<li>In words, <em data-effect=\"italics\">X<\/em> = _____________<\/li>\r\n \t<li><em data-effect=\"italics\">X<\/em> ~ _____(_____,_____)<\/li>\r\n \t<li><em data-effect=\"italics\">\u03bc<sub>x<\/sub><\/em> = _____<\/li>\r\n \t<li><em data-effect=\"italics\">\u03c3<sub>x<\/sub><\/em> = _____<\/li>\r\n \t<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex]= ______________<\/li>\r\n \t<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\r\n \t<li>In words, <em data-effect=\"italics\">\u03a3X<\/em> = _____________<\/li>\r\n \t<li><em data-effect=\"italics\">\u03a3X<\/em> ~ _____(_____,_____)<\/li>\r\n \t<li>Without doing any calculations, do you think that it\u2019s likely that the professor will need to read a total of more than 1,050 pages? Why?<\/li>\r\n \t<li>Calculate the probability that the professor will need to read a total of more than 1,050 pages.<\/li>\r\n \t<li>Why is it so unlikely that the average length of the papers will be less than 12 pages?<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id6535223\" class=\"problem\" data-type=\"problem\">\r\n\r\n87. Salaries for teachers in a particular elementary school district are normally distributed with a mean of $44,000 and a standard deviation of $6,500. We randomly survey ten teachers from that district.\r\n<ol data-number-style=\"lower-alpha\">\r\n \t<li>Find the 90<sup>th<\/sup> percentile for an individual teacher\u2019s salary.<\/li>\r\n \t<li>Find the 90<sup>th<\/sup> percentile for the average teacher\u2019s salary.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"fs-idm1040896\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div id=\"element-566\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"id6536038\" class=\"problem\" data-type=\"problem\">\r\n\r\n88. The average length of a maternity stay in a U.S. hospital is said to be 2.4 days with a standard deviation of 0.9 days. We randomly survey 80 women who recently bore children in a U.S. hospital.\r\n<ol id=\"madeup\" data-number-style=\"lower-alpha\">\r\n \t<li>In words, <em data-effect=\"italics\">X<\/em> = _____________<\/li>\r\n \t<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0= ___________________<\/li>\r\n \t<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\r\n \t<li>In words, <em data-effect=\"italics\">\u03a3X<\/em> = _______________<\/li>\r\n \t<li><em data-effect=\"italics\">\u03a3X<\/em> ~ _____(_____,_____)<\/li>\r\n \t<li>Is it likely that an individual stayed more than five days in the hospital? Why or why not?<\/li>\r\n \t<li>Is it likely that the average stay for the 80 women was more than five days? Why or why not?<\/li>\r\n \t<li>Which is more likely:\r\n<ol id=\"sublist\" data-number-style=\"lower-roman\">\r\n \t<li>An individual stayed more than five days.<\/li>\r\n \t<li>the average stay of 80 women was more than five days.<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>If we were to sum up the women\u2019s stays, is it likely that, collectively they spent more than a year in the hospital? Why or why not?<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><\/div>\r\n<div data-type=\"newline\"><\/div>\r\n<p data-type=\"glossary-title\"><em data-effect=\"italics\">For each problem, wherever possible, provide graphs and use the calculator.<\/em><\/p>\r\n\r\n<div id=\"fs-idm4142208\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm4141952\" class=\"problem\" data-type=\"problem\">89. NeverReady batteries has engineered a newer, longer lasting AAA battery. The company claims this battery has an average life span of 17 hours with a standard deviation of 0.8 hours. Your statistics class questions this claim. As a class, you randomly select 30 batteries and find that the sample mean life span is 16.7 hours. If the process is working properly, what is the probability of getting a random sample of 30 batteries in which the sample mean lifetime is 16.7 hours or less? Is the company\u2019s claim reasonable?<\/div>\r\n<div id=\"fs-idm4141184\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\">90. Men have an average weight of 172 pounds with a standard deviation of 29 pounds.<\/div>\r\n<div id=\"fs-idm165833488\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm165833232\" class=\"problem\" data-type=\"problem\">\r\n<ol id=\"fs-idm165831968\" data-number-style=\"lower-alpha\">\r\n \t<li>Find the probability that 20 randomly selected men will have a sum weight greater than 3600 lbs.<\/li>\r\n \t<li>If 20 men have a sum weight greater than 3500 lbs, then their total weight exceeds the safety limits for water taxis. Based on (a), is this a safety concern? Explain.<\/li>\r\n<\/ol>\r\nM&amp;M candies large candy bags have a claimed net weight of 396.9 g. The standard deviation for the weight of the individual candies is 0.017 g. The following table is from a stats experiment conducted by a statistics class.\r\n\r\n<\/div>\r\n<\/section><\/div>\r\n<div id=\"fs-idp87424832\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idp87425088\" class=\"problem\" data-type=\"problem\">\r\n\r\n\u00a0\u00a0\u00a00.8030.865\u00a0\u00a0\u00a00.9320.848\u00a0\u00a0\u00a00.8420.940\u00a0\u00a0\u00a00.8320.833\u00a0\u00a0\u00a00.8070.845\u00a0\u00a0\u00a0\u00a00.8410.852\u00a0\u00a0\u00a0\u00a00.9320.778\u00a0\u00a0\u00a0\u00a00.8330.814\u00a0\u00a0\u00a0\u00a00.8810.791\u00a0\u00a0\u00a0\u00a00.8180.810\u00a0\u00a0\u00a0\u00a00.8640.881\u00a0\u00a0\u00a0\u00a00.825\u00a0\u00a0\u00a0\u00a0\u00a00.855\u00a0\u00a0\u00a0\u00a0\u00a00.942\u00a0\u00a0\u00a0\u00a0\u00a00.825\u00a0\u00a0\u00a0\u00a0\u00a00.869\u00a0\u00a0\u00a0\u00a0\u00a00.912\r\n<table id=\"fs-idm55488384\" summary=\"\">\r\n<thead>\r\n<tr>\r\n<th>Red<\/th>\r\n<th>Orange<\/th>\r\n<th>Yellow<\/th>\r\n<th>Brown<\/th>\r\n<th>Blue<\/th>\r\n<th>Green<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>0.751<\/td>\r\n<td>0.735<\/td>\r\n<td>0.883<\/td>\r\n<td>0.696<\/td>\r\n<td>0.881<\/td>\r\n<td>0.925<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.841<\/td>\r\n<td>0.895<\/td>\r\n<td>0.769<\/td>\r\n<td>0.876<\/td>\r\n<td>0.863<\/td>\r\n<td>0.914<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.856<\/td>\r\n<td>0.865<\/td>\r\n<td>0.859<\/td>\r\n<td>0.855<\/td>\r\n<td>0.775<\/td>\r\n<td>0.881<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.799<\/td>\r\n<td>0.864<\/td>\r\n<td>0.784<\/td>\r\n<td>0.806<\/td>\r\n<td>0.854<\/td>\r\n<td>0.865<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.966<\/td>\r\n<td>0.852<\/td>\r\n<td>0.824<\/td>\r\n<td>0.840<\/td>\r\n<td>0.810<\/td>\r\n<td>0.865<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.859<\/td>\r\n<td>0.866<\/td>\r\n<td>0.858<\/td>\r\n<td>0.868<\/td>\r\n<td>0.858<\/td>\r\n<td>1.015<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.857<\/td>\r\n<td>0.859<\/td>\r\n<td>0.848<\/td>\r\n<td>0.859<\/td>\r\n<td>0.818<\/td>\r\n<td>0.876<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.942<\/td>\r\n<td>0.838<\/td>\r\n<td>0.851<\/td>\r\n<td>0.982<\/td>\r\n<td>0.868<\/td>\r\n<td>0.809<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.873<\/td>\r\n<td>0.863<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.809<\/td>\r\n<td>0.888<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.890<\/td>\r\n<td>0.925<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.878<\/td>\r\n<td>0.793<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.905<\/td>\r\n<td>0.977<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>0.850<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>0.830<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>0.856<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>0.842<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>0.778<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>0.786<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>0.853<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>0.864<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>0.873<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>0.880<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>0.882<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>0.931<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td><\/td>\r\n<td><\/td>\r\n<td><\/td>\r\n<td>0.887<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n91. The bag contained 465 candies and he listed weights in the table came from randomly selected candies. Count the weights.\r\n<ol id=\"fs-idm5281504\" data-number-style=\"lower-alpha\">\r\n \t<li>Find the mean sample weight and the standard deviation of the sample weights of candies in the table.<\/li>\r\n \t<li>Find the sum of the sample weights in the table and the standard deviation of the sum the of the weights.<\/li>\r\n \t<li>If 465 M&amp;Ms are randomly selected, find the probability that their weights sum to at least 396.9.<\/li>\r\n \t<li>Is the Mars Company\u2019s M&amp;M labeling accurate?<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"fs-idm20614304\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div id=\"fs-idp89909664\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idp89909920\" class=\"problem\" data-type=\"problem\">\r\n\r\n92. The Screw Right Company claims their <span id=\"MathJax-Element-474-Frame\" class=\"MathJax\"><span id=\"MathJax-Span-5631\" class=\"math\"><span id=\"MathJax-Span-5632\" class=\"mrow\"><span id=\"MathJax-Span-5633\" class=\"semantics\"><span id=\"MathJax-Span-5634\" class=\"mrow\"><span id=\"MathJax-Span-5635\" class=\"mrow\"><span id=\"MathJax-Span-5636\" class=\"mfrac\"><span id=\"MathJax-Span-5637\" class=\"mn\">3<\/span><span id=\"MathJax-Span-5638\" class=\"mn\">4<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span> inch screws are within \u00b10.23 of the claimed mean diameter of 0.750 inches with a standard deviation of 0.115 inches. The following data were recorded.\r\n<table id=\"fs-idm10579216\" summary=\"\">\r\n<tbody>\r\n<tr>\r\n<td>0.757<\/td>\r\n<td>0.723<\/td>\r\n<td>0.754<\/td>\r\n<td>0.737<\/td>\r\n<td>0.757<\/td>\r\n<td>0.741<\/td>\r\n<td>0.722<\/td>\r\n<td>0.741<\/td>\r\n<td>0.743<\/td>\r\n<td>0.742<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.740<\/td>\r\n<td>0.758<\/td>\r\n<td>0.724<\/td>\r\n<td>0.739<\/td>\r\n<td>0.736<\/td>\r\n<td>0.735<\/td>\r\n<td>0.760<\/td>\r\n<td>0.750<\/td>\r\n<td>0.759<\/td>\r\n<td>0.754<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.744<\/td>\r\n<td>0.758<\/td>\r\n<td>0.765<\/td>\r\n<td>0.756<\/td>\r\n<td>0.738<\/td>\r\n<td>0.742<\/td>\r\n<td>0.758<\/td>\r\n<td>0.757<\/td>\r\n<td>0.724<\/td>\r\n<td>0.757<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.744<\/td>\r\n<td>0.738<\/td>\r\n<td>0.763<\/td>\r\n<td>0.756<\/td>\r\n<td>0.760<\/td>\r\n<td>0.768<\/td>\r\n<td>0.761<\/td>\r\n<td>0.742<\/td>\r\n<td>0.734<\/td>\r\n<td>0.754<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>0.758<\/td>\r\n<td>0.735<\/td>\r\n<td>0.740<\/td>\r\n<td>0.743<\/td>\r\n<td>0.737<\/td>\r\n<td>0.737<\/td>\r\n<td>0.725<\/td>\r\n<td>0.761<\/td>\r\n<td>0.758<\/td>\r\n<td>0.756<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\nThe screws were randomly selected from the local home repair store.\r\n<ol id=\"fs-idm59306112\" data-number-style=\"lower-alpha\">\r\n \t<li>Find the mean diameter and standard deviation for the sample<\/li>\r\n \t<li>Find the probability that 50 randomly selected screws will be within the stated tolerance levels. Is the company\u2019s diameter claim plausible?<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/section><\/div>\r\n<div id=\"fs-idm3642992\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm3642736\" class=\"problem\" data-type=\"problem\">93. Your company has a contract to perform preventive maintenance on thousands of air-conditioners in a large city. Based on service records from previous years, the time that a technician spends servicing a unit averages one hour with a standard deviation of one hour. In the coming week, your company will service a simple random sample of 70 units in the city. You plan to budget an average of 1.1 hours per technician to complete the work. Will this be enough time?<\/div>\r\n<div id=\"fs-idm3641488\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<div id=\"fs-idm37303792\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm37303536\" class=\"problem\" data-type=\"problem\">94. A typical adult has an average IQ score of 105 with a standard deviation of 20. If 20 randomly selected adults are given an IQ tesst, what is the probability that the sample mean scores will be between 85 and 125 points?<\/div>\r\n<\/section><\/div>\r\n<div id=\"fs-idm31585616\" class=\"exercise\" data-type=\"exercise\"><section>\r\n<div id=\"fs-idm31585360\" class=\"problem\" data-type=\"problem\">Certain coins have an average weight of 5.201 grams with a standard deviation of 0.065 g. If a vending machine is designed to accept coins whose weights range from 5.111 g to 5.291 g, what is the expected number of rejected coins when 280 randomly selected coins are inserted into the machine?<\/div>\r\n<div id=\"fs-idm31584288\" class=\"solution\" data-type=\"solution\"><\/div>\r\n<\/section><\/div>\r\n<section class=\"free-response\" data-depth=\"1\">\r\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\r\n<\/section><\/div>","rendered":"<h2 id=\"fs-idm37731072\" class=\"problem\" data-type=\"problem\">The Central Limit Theorem for Sample Means (Averages)<\/h2>\n<div class=\"problem\" data-type=\"problem\"><\/div>\n<div class=\"problem\" data-type=\"problem\"><em data-effect=\"italics\">Use the following information to answer the next six exercises:<\/em> Yoonie is a personnel manager in a large corporation. Each month she must review 16 of the employees. From past experience, she has found that the reviews take her approximately four hours each to do with a population standard deviation of 1.2 hours. Let <em data-effect=\"italics\">\u03a7<\/em> be the random variable representing the time it takes her to complete one review. Assume <em data-effect=\"italics\">\u03a7<\/em> is normally distributed. Let[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0be the random variable representing the mean time to complete the 16 reviews. Assume that the 16 reviews represent a random set of reviews.<\/div>\n<div class=\"problem\" data-type=\"problem\"><\/div>\n<div class=\"problem\" data-type=\"problem\">1. What is the mean, standard deviation, and sample size?<\/div>\n<section>\n<div class=\"problem\" data-type=\"problem\"><\/div>\n<div id=\"fs-idm62741104\" class=\"problem\" data-type=\"problem\">\n<p>2. Complete the distributions.<\/p>\n<div id=\"fs-idm16577088\" data-type=\"list\" data-list-type=\"enumerated\" data-number-style=\"lower-alpha\">\n<div data-type=\"item\"><em data-effect=\"italics\">X<\/em> ~ _____(_____,_____)<\/div>\n<div data-type=\"item\">[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/div>\n<\/div>\n<\/div>\n<\/section>\n<section>\n<div id=\"id16709593\" class=\"problem\" data-type=\"problem\">\n<p>3. Find the probability that <strong>one<\/strong> review will take Yoonie from 3.5 to 4.25 hours. Sketch the graph, labeling and scaling the horizontal axis. Shade the region corresponding to the probability.<\/p>\n<div id=\"sublist1346264\" data-type=\"list\" data-list-type=\"enumerated\" data-number-style=\"lower-alpha\">\n<div data-type=\"item\">\n<figure id=\"fs-idm61024352\"><span id=\"id14288416\" data-type=\"media\" data-alt=\"This is a frequency curve for a normal distribution. It shows a single peak in the center with the curve tapering down to the horizontal axis on each side. The distribution is symmetrical. The horizontal axis represents the random variable X.\"> <img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/132\/2016\/04\/21214603\/fig-ch07_06_01.jpg\" alt=\"This is a frequency curve for a normal distribution. It shows a single peak in the center with the curve tapering down to the horizontal axis on each side. The distribution is symmetrical. The horizontal axis represents the random variable X.\" width=\"380\" data-media-type=\"image\/jpg\" \/><\/span><\/figure>\n<\/div>\n<div data-type=\"item\"><em data-effect=\"italics\">P<\/em>(________ &lt; <em data-effect=\"italics\">x<\/em> &lt; ________) = _______<\/div>\n<\/div>\n<\/div>\n<div id=\"id14567929\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<section>\n<div id=\"id14777355\" class=\"problem\" data-type=\"problem\">\n<p>4. Find the probability that the <strong>mean<\/strong> of a month\u2019s reviews will take Yoonie from 3.5 to 4.25 hrs. Sketch the graph, labeling and scaling the horizontal axis. Shade the region corresponding to the probability.<\/p>\n<div id=\"sublist27646547\" data-type=\"list\" data-list-type=\"enumerated\" data-number-style=\"lower-alpha\">\n<div data-type=\"item\">\n<figure id=\"fs-idm31915744\"><span id=\"fs-idm62152464\" data-type=\"media\" data-alt=\"This is a frequency curve for a normal distribution. It shows a single peak in the center with the curve tapering down to the horizontal axis on each side. The distribution is symmetrical. The horizontal axis represents the random variable X.\"> <img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/132\/2016\/04\/21214605\/fig-ch07_06_02.jpg\" alt=\"This is a frequency curve for a normal distribution. It shows a single peak in the center with the curve tapering down to the horizontal axis on each side. The distribution is symmetrical. The horizontal axis represents the random variable X.\" width=\"380\" data-media-type=\"image\/jpg\" \/><\/span><\/figure>\n<\/div>\n<div data-type=\"item\"><em data-effect=\"italics\">5. P<\/em>(________________) = _______<\/div>\n<\/div>\n<\/div>\n<\/section>\n<section>\n<div id=\"fs-idm42157728\" class=\"problem\" data-type=\"problem\">What causes the probabilities in 3, 4\u00a0to be different?<\/div>\n<div id=\"fs-idm43625488\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<div id=\"fs-idm42157984\" class=\"exercise\" data-type=\"exercise\"><\/div>\n<div id=\"fs-idm70816816\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm70816560\" class=\"problem\" data-type=\"problem\">6. Find the 95<sup>th<\/sup> percentile for the mean time to complete one month&#8217;s reviews. Sketch the graph.<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/132\/2016\/04\/21214605\/fig-ch07_06_02.jpg\" alt=\"This is a frequency curve for a normal distribution. It shows a single peak in the center with the curve tapering down to the horizontal axis on each side. The distribution is symmetrical. The horizontal axis represents the random variable X.\" width=\"380\" data-media-type=\"image\/jpg\" \/>The 95<sup>th<\/sup> Percentile =____________<\/div>\n<\/section>\n<\/div>\n<h1 data-type=\"title\"><\/h1>\n<div id=\"element-475\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id6273705\" class=\"problem\" data-type=\"problem\">\n<p>7. Previously, De Anza statistics students estimated that the amount of change daytime statistics students carry is exponentially distributed with a mean of $0.88. Suppose that we randomly pick 25 daytime statistics students.<\/p>\n<ol id=\"element-224\" data-number-style=\"lower-alpha\">\n<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = ____________<\/li>\n<li><em data-effect=\"italics\">\u03a7<\/em> ~ _____(_____,_____)<\/li>\n<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex]= ____________<\/li>\n<li>[latex]\\displaystyle\\overline{{X}}[\/latex]~ ______ (______, ______)<\/li>\n<li>Find the probability that an individual had between $0.80 and $1.00. Graph the situation, and shade in the area to be determined.<\/li>\n<li>Find the probability that the average of the 25 students was between $0.80 and $1.00. Graph the situation, and shade in the area to be determined.<\/li>\n<li>Explain why there is a difference in part e and part f.<\/li>\n<\/ol>\n<\/div>\n<div id=\"fs-idp10454080\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<section>\n<div id=\"id6273949\" class=\"problem\" data-type=\"problem\">\n<p>8. Suppose that the distance of fly balls hit to the outfield (in baseball) is normally distributed with a mean of 250 feet and a standard deviation of 50 feet. We randomly sample 49 fly balls.<\/p>\n<ol data-number-style=\"lower-alpha\">\n<li>If[latex]\\displaystyle\\overline{{X}}[\/latex] = average distance in feet for 49 fly balls, then[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _______(_______,_______)<\/li>\n<li>What is the probability that the 49 balls traveled an average of less than 240 feet? Sketch the graph. Scale the horizontal axis for[latex]\\displaystyle\\overline{{X}}[\/latex]. \u00a0Shade the region corresponding to the probability. Find the probability.<\/li>\n<li>Find the 80<sup>th<\/sup> percentile of the distribution of the average of 49 fly balls.<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<section>\n<div id=\"id6533450\" class=\"problem\" data-type=\"problem\">\n<p>9. According to the Internal Revenue Service, the average length of time for an individual to complete (keep records for, learn, prepare, copy, assemble, and send) IRS Form 1040 is 10.53 hours (without any attached schedules). The distribution is unknown. Let us assume that the standard deviation is two hours. Suppose we randomly sample 36 taxpayers.<\/p>\n<ol id=\"element-685\" data-number-style=\"lower-alpha\">\n<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = _____________<\/li>\n<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex]= _____________<\/li>\n<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\n<li>Would you be surprised if the 36 taxpayers finished their Form 1040s in an average of more than 12 hours? Explain why or why not in complete sentences.<\/li>\n<li>Would you be surprised if one taxpayer finished his or her Form 1040 in more than 12 hours? In a complete sentence, explain why.<\/li>\n<\/ol>\n<\/div>\n<div id=\"fs-idm166717360\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<section>\n<div id=\"id6533652\" class=\"problem\" data-type=\"problem\">\n<p>10. Suppose that a category of world-class runners are known to run a marathon (26 miles) in an average of 145 minutes with a standard deviation of 14 minutes. Consider 49 of the races. Let[latex]\\displaystyle\\overline{{X}}[\/latex] the average of the 49 races.<\/p>\n<ol id=\"element-45\" data-number-style=\"lower-alpha\">\n<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\n<li>Find the probability that the runner will average between 142 and 146 minutes in these 49 marathons.<\/li>\n<li>Find the 80<sup>th<\/sup> percentile for the average of these 49 marathons.<\/li>\n<li>Find the median of the average running times.<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<section>\n<div id=\"id6534960\" class=\"problem\" data-type=\"problem\">\n<p>11. The length of songs in a collector\u2019s iTunes album collection is uniformly distributed from two to 3.5 minutes. Suppose we randomly pick five albums from the collection. There are a total of 43 songs on the five albums.<\/p>\n<ol data-number-style=\"lower-alpha\">\n<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = _________<\/li>\n<li><em data-effect=\"italics\">\u03a7<\/em> ~ _____________<\/li>\n<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex] = _____________<\/li>\n<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\n<li>Find the first quartile for the average song length.<\/li>\n<li>The IQR(interquartile range) for the average song length is from _______\u2013_______.<\/li>\n<\/ol>\n<\/div>\n<div id=\"fs-idm135637280\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<section>\n<div id=\"id6536525\" class=\"problem\" data-type=\"problem\">\n<p>12. In 1940 the average size of a U.S. farm was 174 acres. Let\u2019s say that the standard deviation was 55 acres. Suppose we randomly survey 38 farmers from 1940.<\/p>\n<ol id=\"madeup2\" data-number-style=\"lower-alpha\">\n<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = _____________<\/li>\n<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex] = _____________<\/li>\n<li>[latex]\\displaystyle\\overline{{X}}[\/latex]~ _____(_____,_____)<\/li>\n<li>The IQR for[latex]\\displaystyle\\overline{{X}}[\/latex] is from _______ acres to _______ acres.<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<section>\n<div id=\"id6264723\" class=\"problem\" data-type=\"problem\">\n<p>13. Determine which of the following are true and which are false. Then, in complete sentences, justify your answers.<\/p>\n<ol id=\"fs-idm39736064\" data-number-style=\"lower-alpha\">\n<li>When the sample size is large, the mean of[latex]\\displaystyle\\overline{{X}}[\/latex] is approximately equal to the mean of <em data-effect=\"italics\">\u03a7<\/em>.<\/li>\n<li>When the sample size is large,[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0is approximately normally distributed.<\/li>\n<li>When the sample size is large, the standard deviation of[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0is approximately the same as the standard deviation of <em data-effect=\"italics\">\u03a7<\/em>.<\/li>\n<\/ol>\n<\/div>\n<div id=\"fs-idp58516336\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<section>\n<div id=\"id6272391\" class=\"problem\" data-type=\"problem\">\n<p>14. The percent of fat calories that a person in America consumes each day is normally distributed with a mean of about 36 and a standard deviation of about ten. Suppose that 16 individuals are randomly chosen. Let[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0= average percent of fat calories.<\/p>\n<ol id=\"eip-idm27753728\" data-number-style=\"lower-alpha\">\n<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ ______(______, ______)<\/li>\n<li>For the group of 16, find the probability that the average percent of fat calories consumed is more than five. Graph the situation and shade in the area to be determined.<\/li>\n<li>Find the first quartile for the average percent of fat calories.<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<section>\n<div id=\"id6535840\" class=\"problem\" data-type=\"problem\">\n<p>15. The distribution of income in some Third World countries is considered wedge shaped (many very poor people, very few middle income people, and even fewer wealthy people). Suppose we pick a country with a wedge shaped distribution. Let the average salary be $2,000 per year with a standard deviation of $8,000. We randomly survey 1,000 residents of that country.<\/p>\n<ol data-number-style=\"lower-alpha\">\n<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = _____________<\/li>\n<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0= _____________<\/li>\n<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\n<li>How is it possible for the standard deviation to be greater than the average?<\/li>\n<li>Why is it more likely that the average of the 1,000 residents will be from $2,000 to $2,100 than from $2,100 to $2,200?<\/li>\n<\/ol>\n<\/div>\n<div id=\"fs-idm50399184\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<section>\n<div id=\"id6538396\" class=\"problem\" data-type=\"problem\">\n<p>16. Which of the following is NOT TRUE about the distribution for averages?<\/p>\n<ol data-number-style=\"lower-alpha\">\n<li>The mean, median, and mode are equal.<\/li>\n<li>The area under the curve is one.<\/li>\n<li>The curve never touches the <em data-effect=\"italics\">x<\/em>-axis.<\/li>\n<li>The curve is skewed to the right.<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<section>\n<div id=\"id6538522\" class=\"problem\" data-type=\"problem\">\n<p>17. The cost of unleaded gasoline in the Bay Area once followed an unknown distribution with a mean of $4.59 and a standard deviation of $0.10. Sixteen gas stations from the Bay Area are randomly chosen. We are interested in the average cost of gasoline for the 16 gas stations. The distribution to use for the average cost of gasoline for the 16 gas stations is:<\/p>\n<div id=\"element-728\" data-type=\"list\" data-list-type=\"enumerated\" data-number-style=\"lower-alpha\">\n<div data-type=\"item\">[latex]\\displaystyle\\overline{{X}}[\/latex] ~ <em data-effect=\"italics\">N<\/em>(4.59, 0.10)<\/div>\n<div data-type=\"item\">[latex]\\displaystyle\\overline{{X}}[\/latex] ~ <em data-effect=\"italics\">N<\/em>(4.59,\u00a0[latex]\\frac{{0.10}}{{\\sqrt{16}}}[\/latex])&gt;<\/div>\n<div data-type=\"item\">[latex]\\displaystyle\\overline{{X}}[\/latex] ~ <em data-effect=\"italics\">N<\/em>(4.59,\u00a0[latex]\\frac{{16}}{{0.10}}[\/latex])<\/div>\n<div data-type=\"item\">[latex]\\displaystyle\\overline{{X}}[\/latex] ~ <em data-effect=\"italics\">N<\/em>(4.59,\u00a0[latex]\\frac{{\\sqrt{16}}}{{0.10}}[\/latex])<\/div>\n<\/div>\n<div data-type=\"item\">\n<h2>The Central Limit Theorem for Sums<\/h2>\n<\/div>\n<\/div>\n<\/section>\n<div data-type=\"item\">\n<p><em data-effect=\"italics\">Use the following information to answer the next four exercises:<\/em> An unknown distribution has a mean of 80 and a standard deviation of 12. A sample size of 95 is drawn randomly from the population.<\/p>\n<section>\n<div id=\"eip-202\" class=\"problem\" data-type=\"problem\">18. Find the probability that the sum of the 95 values is greater than 7,650.<\/div>\n<\/section>\n<section>\n<div class=\"problem\" data-type=\"problem\">19. Find the probability that the sum of the 95 values is less than 7,400.<\/div>\n<\/section>\n<section>\n<div id=\"eip-637\" class=\"problem\" data-type=\"problem\">20.Find the sum that is two standard deviations above the mean of the sums.<\/div>\n<\/section>\n<section>\n<div class=\"problem\" data-type=\"problem\">21. Find the sum that is 1.5 standard deviations below the mean of the sums.<\/div>\n<\/section>\n<p><em data-effect=\"italics\">Use the following information to answer the next five exercises:<\/em> The distribution of results from a cholesterol test has a mean of 180 and a standard deviation of 20. A sample size of 40 is drawn randomly.<\/p>\n<section>\n<div class=\"problem\" data-type=\"problem\">22. Find the probability that the sum of the 40 values is greater than 7,500.<\/div>\n<\/section>\n<section>\n<div id=\"eip-608\" class=\"problem\" data-type=\"problem\">23. Find the probability that the sum of the 40 values is less than 7,000.<\/div>\n<\/section>\n<section>\n<div id=\"eip-399\" class=\"problem\" data-type=\"problem\">24. Find the sum that is one standard deviation above the mean of the sums.<\/div>\n<div id=\"eip-875\" class=\"solution\" data-type=\"solution\">\u00a025.\u00a0Find the sum that is 1.5 standard deviations below the mean of the sums.<\/div>\n<\/section>\n<section>\n<div id=\"eip-726\" class=\"problem\" data-type=\"problem\">26. Find the percentage of sums between 1.5 standard deviations below the mean of the sums and one standard deviation above the mean of the sums.<\/div>\n<div id=\"eip-673\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<p><em data-effect=\"italics\">Use the following information to answer the next six exercises:<\/em> A researcher measures the amount of sugar in several cans of the same soda. The mean is 39.01 with a standard deviation of 0.5. The researcher randomly selects a sample of 100.<\/p>\n<section>\n<div class=\"problem\" data-type=\"problem\">27. Find the probability that the sum of the 100 values is greater than 3,910.<\/div>\n<\/section>\n<section>\n<div class=\"problem\" data-type=\"problem\">28. Find the probability that the sum of the 100 values is less than 3,900.<\/div>\n<div class=\"solution\" data-type=\"solution\">\u00a029.\u00a0Find the probability that the sum of the 100 values falls between the numbers you found in 28, 29.<\/div>\n<\/section>\n<section>\n<div id=\"eip-662\" class=\"problem\" data-type=\"problem\">30. Find the sum with a <em data-effect=\"italics\">z<\/em>\u2013score of \u20132.5.<\/div>\n<div id=\"eip-650\" class=\"solution\" data-type=\"solution\">31. Find the sum with a <em data-effect=\"italics\">z<\/em>\u2013score of 0.5.<\/div>\n<\/section>\n<section>\n<div id=\"eip-573\" class=\"problem\" data-type=\"problem\">32. Find the probability that the sums will fall between the <em data-effect=\"italics\">z<\/em>-scores \u20132 and 1.<\/div>\n<div id=\"eip-910\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<p>\u00a0<em data-effect=\"italics\">Use the following information to answer the next four exercise:<\/em> An unknown distribution has a mean 12 and a standard deviation of one. A sample size of 25 is taken. Let <em data-effect=\"italics\">X<\/em> = the object of interest.<\/p>\n<section>\n<div id=\"eip-37\" class=\"problem\" data-type=\"problem\">33. What is the mean of <em data-effect=\"italics\">\u03a3X<\/em>?<\/div>\n<\/section>\n<section>\n<div class=\"problem\" data-type=\"problem\">34. What is the standard deviation of <em data-effect=\"italics\">\u03a3X<\/em>?<\/div>\n<div class=\"solution\" data-type=\"solution\">\u00a035.\u00a0What is <em data-effect=\"italics\">P<\/em>(<em data-effect=\"italics\">\u03a3x<\/em> = 290)?<\/div>\n<\/section>\n<section>\n<div id=\"eip-587\" class=\"problem\" data-type=\"problem\">36. What is <em data-effect=\"italics\">P<\/em>(<em data-effect=\"italics\">\u03a3x<\/em> &gt; 290)?<\/div>\n<\/section>\n<p>37. True or False: only the sums of normal distributions are also normal distributions.<\/p>\n<section>\n<div id=\"eip-688\" class=\"problem\" data-type=\"problem\">38. In order for the sums of a distribution to approach a normal distribution, what must be true?<\/div>\n<div id=\"eip-227\" class=\"solution\" data-type=\"solution\">\u00a039.\u00a0What three things must you know about a distribution to find the probability of sums?<\/div>\n<\/section>\n<section>\n<div id=\"eip-389\" class=\"problem\" data-type=\"problem\">40. An unknown distribution has a mean of 25 and a standard deviation of six. Let <em data-effect=\"italics\">X<\/em> = one object from this distribution. What is the sample size if the standard deviation of <em data-effect=\"italics\">\u03a3X<\/em> is 42?<\/div>\n<div id=\"eip-826\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<p>41. An unknown distribution has a mean of 19 and a standard deviation of 20. Let <em data-effect=\"italics\">X<\/em> = the object of interest. What is the sample size if the mean of <em data-effect=\"italics\">\u03a3X<\/em> is 15,200?<em data-effect=\"italics\"><br \/>\n<\/em><em data-effect=\"italics\">Use the following information to answer the next three exercises.<\/em> A market researcher analyzes how many electronics devices customers buy in a single purchase. The distribution has a mean of three with a standard deviation of 0.7. She samples 400 customers.<\/p>\n<section>\n<div class=\"problem\" data-type=\"problem\">42. What is the <em data-effect=\"italics\">z<\/em>-score for <em data-effect=\"italics\">\u03a3x<\/em> = 840?<\/div>\n<div id=\"eip-263\" class=\"solution\" data-type=\"solution\">\u00a043.\u00a0What is the <em data-effect=\"italics\">z<\/em>-score for <em data-effect=\"italics\">\u03a3x<\/em> = 1,186?<\/div>\n<\/section>\n<section>\n<div id=\"eip-893\" class=\"problem\" data-type=\"problem\">44. What is <em data-effect=\"italics\">P<\/em>(<em data-effect=\"italics\">\u03a3x<\/em> &lt; 1,186)?<\/div>\n<div class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<p><em data-effect=\"italics\">Use the following information to answer the next three exercises:<\/em> An unkwon distribution has a mean of 100, a standard deviation of 100, and a sample size of 100. Let <em data-effect=\"italics\">X<\/em> = one object of interest.<\/p>\n<section>\n<div id=\"eip-217\" class=\"problem\" data-type=\"problem\">45. What is the mean of <em data-effect=\"italics\">\u03a3X<\/em>?<\/div>\n<\/section>\n<section>\n<div class=\"problem\" data-type=\"problem\">46. What is the standard deviation of <em data-effect=\"italics\">\u03a3X<\/em>?<\/div>\n<div id=\"eip-891\" class=\"solution\" data-type=\"solution\">\u00a047.\u00a0What is <em data-effect=\"italics\">P<\/em>(<em data-effect=\"italics\">\u03a3x<\/em> &gt; 9,000)?<\/div>\n<\/section>\n<div id=\"fs-idm54402176\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm54401920\" class=\"problem\" data-type=\"problem\">48. Which of the following is NOT TRUE about the theoretical distribution of sums?<\/div>\n<\/section>\n<\/div>\n<ol id=\"fs-idm98145264\" data-number-style=\"lower-alpha\">\n<li>The mean, median and mode are equal.<\/li>\n<li>The area under the curve is one.<\/li>\n<li>The curve never touches the <em data-effect=\"italics\">x<\/em>-axis.<\/li>\n<li>The curve is skewed to the right.<\/li>\n<\/ol>\n<\/div>\n<div id=\"element-119\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id6533195\" class=\"problem\" data-type=\"problem\">\n<p>49. Suppose that the duration of a particular type of criminal trial is known to have a mean of 21 days and a standard deviation of seven days. We randomly sample nine trials.<\/p>\n<ol id=\"element-645\" data-number-style=\"lower-alpha\">\n<li>In words, <em data-effect=\"italics\">\u03a3X<\/em> = ______________<\/li>\n<li><em data-effect=\"italics\">\u03a3X<\/em> ~ _____(_____,_____)<\/li>\n<li>Find the probability that the total length of the nine trials is at least 225 days.<\/li>\n<li>Ninety percent of the total of nine of these types of trials will last at least how long?<\/li>\n<\/ol>\n<\/div>\n<div id=\"id6533339\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<p>50.Suppose that the weight of open boxes of cereal in a home with children is uniformly distributed from two to six pounds with a mean of four pounds and standard deviation of 1.1547. We randomly survey 64 homes with children.<\/p>\n<section>\n<div id=\"id6532824\" class=\"problem\" data-type=\"problem\">\n<ol id=\"element-173\" data-number-style=\"lower-alpha\">\n<li>In words, <em data-effect=\"italics\">X<\/em> = _____________<\/li>\n<li>The distribution is _______.<\/li>\n<li>In words, <em data-effect=\"italics\">\u03a3X<\/em> = _______________<\/li>\n<li><em data-effect=\"italics\">\u03a3X<\/em> ~ _____(_____,_____)<\/li>\n<li>Find the probability that the total weight of open boxes is less than 250 pounds.<\/li>\n<li>Find the 35<sup>th<\/sup> percentile for the total weight of open boxes of cereal.<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<div id=\"element-138\" class=\"exercise\" data-type=\"exercise\">\n<section>51. Salaries for teachers in a particular elementary school district are normally distributed with a mean of $44,000 and a standard deviation of $6,500. We randomly survey ten teachers from that district.<\/section>\n<\/div>\n<ol id=\"fs-idm127251264\" data-number-style=\"lower-alpha\">\n<li>In words, <em data-effect=\"italics\">X<\/em> = ______________<\/li>\n<li><em data-effect=\"italics\">X<\/em> ~ _____(_____,_____)<\/li>\n<li>In words, <em data-effect=\"italics\">\u03a3X<\/em> = _____________<\/li>\n<li><em data-effect=\"italics\">\u03a3X<\/em> ~ _____(_____,_____)<\/li>\n<li>Find the probability that the teachers earn a total of over $400,000.<\/li>\n<li>Find the 90<sup>th<\/sup> percentile for an individual teacher&#8217;s salary.<\/li>\n<li>Find the 90<sup>th<\/sup> percentile for the sum of ten teachers&#8217; salary.<\/li>\n<li>If we surveyed 70 teachers instead of ten, graphically, how would that change the distribution in part d?<\/li>\n<li>If each of the 70 teachers received a $3,000 raise, graphically, how would that change the distribution in part b?<\/li>\n<\/ol>\n<h2>Using the Central Limit Theorem<\/h2>\n<div id=\"fs-idm67922240\" class=\"solution\" data-type=\"solution\">\n<p data-type=\"glossary-title\">\u00a0<em data-effect=\"italics\">Use the following information to answer the next 8\u00a0exercises:<\/em> A manufacturer produces 25-pound lifting weights. The lowest actual weight is 24 pounds, and the highest is 26 pounds. Each weight is equally likely so the distribution of weights is uniform. A sample of 100 weights is taken.<\/p>\n<p data-type=\"glossary-title\">52. What is the distribution for the weights of one 25-pound lifting weight? What is the mean and standard deivation?<\/p>\n<p data-type=\"glossary-title\">53. What is the distribution for the mean weight of 100 25-pound lifting weights?<\/p>\n<p data-type=\"glossary-title\">54. Find the probability that the mean actual weight for the 100 weights is less than 24.9.<\/p>\n<p data-type=\"glossary-title\">55. Find the probability that the mean actual weight for the 100 weights is greater than 25.2.<\/p>\n<div class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm65102048\" class=\"problem\" data-type=\"problem\">56. Find the 90<sup>th<\/sup> percentile for the mean weight for the 100 weights.<\/div>\n<div id=\"fs-idm110485568\" class=\"solution\" data-type=\"solution\"><\/div>\n<div class=\"solution\" data-type=\"solution\">57. What is the distribution for the sum of the weights of 100 25-pound lifting weights?<\/div>\n<div class=\"solution\" data-type=\"solution\">58. Find <em data-effect=\"italics\">P<\/em>(<em data-effect=\"italics\">\u03a3x<\/em> &lt; 2,450).<\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div id=\"exercise12\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm115316000\" class=\"problem\" data-type=\"problem\">59. Find the 90<sup>th<\/sup> percentile for the total weight of the 100 weights.<\/div>\n<div id=\"fs-idm57878688\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div data-type=\"newline\"><em data-effect=\"italics\">\u00a0<\/em><\/div>\n<p data-type=\"glossary-title\"><em data-effect=\"italics\">Use the following information to answer the next 9\u00a0exercises:<\/em> The length of time a particular smartphone&#8217;s battery lasts follows an exponential distribution with a mean of ten months. A sample of 64 of these smartphones is taken.<\/p>\n<p data-type=\"glossary-title\">60. What is the standard deviation?<\/p>\n<p data-type=\"glossary-title\">61. What is the parameter <em data-effect=\"italics\">m<\/em>?<\/p>\n<div id=\"fs-idm110175696\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm119290064\" class=\"solution\" data-type=\"solution\">62. What is the distribution for the length of time one battery lasts?<\/div>\n<div class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div id=\"fs-idm151129248\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm53240800\" class=\"problem\" data-type=\"problem\">63. What is the distribution for the mean length of time 64 batteries last?<\/div>\n<div class=\"solution\" data-type=\"solution\"><\/div>\n<div id=\"fs-idm34212208\" class=\"solution\" data-type=\"solution\">64. What is the distribution for the total length of time 64 batteries last?<\/div>\n<div class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div id=\"fs-idm1366160\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm41789648\" class=\"problem\" data-type=\"problem\">65. Find the probability that the sample mean is between seven and 11.<\/div>\n<div id=\"fs-idm51974096\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\">66. Find the 80<sup>th<\/sup> percentile for the total length of time 64 batteries last.<\/div>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div id=\"fs-idm41589104\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm45566256\" class=\"problem\" data-type=\"problem\">67. Find the <em data-effect=\"italics\">IQR<\/em> for the mean amount of time 64 batteries last.<\/div>\n<div class=\"problem\" data-type=\"problem\"><\/div>\n<div id=\"fs-idm46764496\" class=\"solution\" data-type=\"solution\">68.\u00a0Find the middle 80% for the total amount of time 64 batteries last.<\/div>\n<\/section>\n<\/div>\n<div data-type=\"newline\"><em data-effect=\"italics\">\u00a0<\/em><\/div>\n<p data-type=\"glossary-title\"><em data-effect=\"italics\">Use the following information to answer the next 4 exercises:<\/em> A uniform distribution has a minimum of six and a maximum of ten. A sample of 50 is taken.<\/p>\n<div id=\"fs-idm1612656\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm47127360\" class=\"problem\" data-type=\"problem\">69. Find <em data-effect=\"italics\">P<\/em>(<em data-effect=\"italics\">\u03a3x<\/em> &gt; 420).<\/div>\n<div id=\"fs-idm7883840\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div id=\"fs-idm48638032\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm30917728\" class=\"problem\" data-type=\"problem\">70. a)Find the 90<sup>th<\/sup> percentile for the sums.<\/div>\n<\/section>\n<\/div>\n<div id=\"fs-idm53694544\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm53230816\" class=\"problem\" data-type=\"problem\">b) Find the 15<sup>th<\/sup> percentile for the sums.<\/div>\n<div id=\"fs-idm143692576\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div id=\"fs-idm16561168\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm46777472\" class=\"problem\" data-type=\"problem\">71. a) Find the first quartile for the sums.<\/div>\n<\/section>\n<\/div>\n<div id=\"fs-idp10404400\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm78936016\" class=\"problem\" data-type=\"problem\">b) Find the third quartile for the sums.<\/div>\n<div id=\"fs-idp671104\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<section id=\"fs-idm65344016\" class=\"practice\" data-depth=\"1\">\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div id=\"fs-idm111220240\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm73987984\" class=\"problem\" data-type=\"problem\">72. Find the 80<sup>th<\/sup> percentile for the sums.<\/div>\n<div class=\"problem\" data-type=\"problem\"><\/div>\n<\/section>\n<\/div>\n<\/section>\n<section id=\"fs-idm47834016\" class=\"free-response\" data-depth=\"1\">\n<div id=\"element-941\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id6533927\" class=\"problem\" data-type=\"problem\">\n<p>73. The attention span of a two-year-old is exponentially distributed with a mean of about eight minutes. Suppose we randomly survey 60 two-year-olds.<\/p>\n<ol data-number-style=\"lower-alpha\">\n<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = _______<\/li>\n<li><em data-effect=\"italics\">\u03a7<\/em> ~ _____(_____,_____)<\/li>\n<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex]= ____________<\/li>\n<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\n<li>Before doing any calculations, which do you think will be higher? Explain why.\n<ol data-number-style=\"lower-roman\">\n<li>The probability that an individual attention span is less than ten minutes.<\/li>\n<li>The probability that the average attention span for the 60 children is less than ten minutes?<\/li>\n<\/ol>\n<\/li>\n<li>Calculate the probabilities in part e.<\/li>\n<li>Explain why the distribution for[latex]\\displaystyle\\overline{{X}}[\/latex] is not exponential.<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id6536735\" class=\"problem\" data-type=\"problem\">\n<p>74. The closing stock prices of 35 U.S. semiconductor manufacturers are given as follows.<span data-type=\"list\" data-list-type=\"labeled-item\" data-display=\"inline\"> <span data-type=\"item\">8.625<\/span> <span data-type=\"item\">30.25<\/span> <span data-type=\"item\">27.625<\/span> <span data-type=\"item\">46.75<\/span> <span data-type=\"item\">32.875<\/span> <span data-type=\"item\">18.25<\/span> <span data-type=\"item\">5<\/span> <span data-type=\"item\">0.125<\/span> <span data-type=\"item\">2.9375<\/span> <span data-type=\"item\">6.875<\/span> <span data-type=\"item\">28.25<\/span> <span data-type=\"item\">24.25<\/span> <span data-type=\"item\">21<\/span> <span data-type=\"item\">1.5<\/span> <span data-type=\"item\">30.25<\/span> <span data-type=\"item\">71<\/span> <span data-type=\"item\">43.5<\/span> <span data-type=\"item\">49.25<\/span> <span data-type=\"item\">2.5625<\/span> <span data-type=\"item\">31<\/span> <span data-type=\"item\">16.5<\/span> <span data-type=\"item\">9.5<\/span> <span data-type=\"item\">18.5<\/span> <span data-type=\"item\">18<\/span> <span data-type=\"item\">9<\/span> <span data-type=\"item\">10.5<\/span> <span data-type=\"item\">16.625<\/span> <span data-type=\"item\">1.25<\/span> <span data-type=\"item\">18<\/span> <span data-type=\"item\">12.87<\/span> <span data-type=\"item\">7<\/span> <span data-type=\"item\">12.875<\/span> <span data-type=\"item\">2.875<\/span> <span data-type=\"item\">60.25<\/span> <span data-type=\"item\">29.25<\/span> <\/span><\/p>\n<ol id=\"madeup9\" data-number-style=\"lower-alpha\">\n<li>In words, <em data-effect=\"italics\">\u03a7<\/em> = ______________<\/li>\n<li>\n<ol id=\"list234325\" data-number-style=\"lower-roman\">\n<li>[latex]\\displaystyle\\overline{{x}}[\/latex] = _____<\/li>\n<li><em data-effect=\"italics\">s<sub>x<\/sub><\/em> = _____<\/li>\n<li><em data-effect=\"italics\">n<\/em> = _____<\/li>\n<\/ol>\n<\/li>\n<li>Construct a histogram of the distribution of the averages. Start at <em data-effect=\"italics\">x<\/em> = \u20130.0005. Use bar widths of ten.<\/li>\n<li>In words, describe the distribution of stock prices.<\/li>\n<li>Randomly average five stock prices together. (Use a random number generator.) Continue averaging five pieces together until you have ten averages. List those ten averages.<\/li>\n<li>Use the ten averages from part e to calculate the following.\n<ol id=\"listhgklasdlfh11\" data-number-style=\"lower-roman\">\n<li>[latex]\\displaystyle\\overline{{x}}[\/latex] = _____<\/li>\n<li><em data-effect=\"italics\">s<sub>x<\/sub><\/em> = _____<\/li>\n<\/ol>\n<\/li>\n<li>Construct a histogram of the distribution of the averages. Start at <em data-effect=\"italics\">x<\/em> = -0.0005. Use bar widths of ten.<\/li>\n<li>Does this histogram look like the graph in part c?<\/li>\n<li>In one or two complete sentences, explain why the graphs either look the same or look different?<\/li>\n<li>Based upon the theory of the <strong>central limit theorem<\/strong>,[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0~ _____(_____,____)<\/li>\n<\/ol>\n<\/div>\n<div id=\"id6537488\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<\/section>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div data-type=\"newline\"><em data-effect=\"italics\">\u00a0<\/em><\/div>\n<p data-type=\"glossary-title\"><em data-effect=\"italics\">Use the following information to answer the next three exercises:<\/em> Richard\u2019s Furniture Company delivers furniture from 10 A.M. to 2 P.M. continuously and uniformly. We are interested in how long (in hours) past the 10 A.M. start time that individuals wait for their delivery.<\/p>\n<div class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id10684324\" class=\"problem\" data-type=\"problem\">\n<p><em data-effect=\"italics\">75. \u03a7<\/em> ~ _____(_____,_____)<\/p>\n<ol id=\"element-596\" data-number-style=\"lower-alpha\">\n<li><em data-effect=\"italics\">U<\/em>(0,4)<\/li>\n<li><em data-effect=\"italics\">U<\/em>(10,2)<\/li>\n<li><em data-effect=\"italics\">E\u03c7p<\/em>(2)<\/li>\n<li><em data-effect=\"italics\">N<\/em>(2,1)<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<\/div>\n<div id=\"element-407\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id11298063\" class=\"problem\" data-type=\"problem\">\n<p>76. The average wait time is:<\/p>\n<ol data-number-style=\"lower-alpha\">\n<li>one hour.<\/li>\n<li>two hours.<\/li>\n<li>two and a half hours.<\/li>\n<li>four hours.<\/li>\n<\/ol>\n<\/div>\n<div id=\"id11298138\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div id=\"element-191\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id11298162\" class=\"problem\" data-type=\"problem\">\n<p>77. Suppose that it is now past noon on a delivery day. The probability that a person must wait at least one and a half <strong>more<\/strong> hours is:<\/p>\n<ol id=\"fs-idp191113008\" data-number-style=\"lower-alpha\">\n<li>[latex]\\frac{1}{4}[\/latex]<\/li>\n<li>[latex]\\frac{1}{2}[\/latex]<\/li>\n<li>[latex]\\frac{3}{4}[\/latex]<\/li>\n<li>[latex]\\frac{3}{8}[\/latex]<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<\/div>\n<p data-type=\"glossary-title\"><em data-effect=\"italics\">Use the following information to answer the next two exercises:<\/em> The time to wait for a particular rural bus is distributed uniformly from zero to 75 minutes. One hundred riders are randomly sampled to learn how long they waited.<\/p>\n<div id=\"element-620\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id6538203\" class=\"problem\" data-type=\"problem\">\n<p>78. The 90<sup>th<\/sup> percentile sample average wait time (in minutes) for a sample of 100 riders is:<\/p>\n<ol id=\"element-576\" data-number-style=\"lower-alpha\">\n<li>315.0<\/li>\n<li>40.3<\/li>\n<li>38.5<\/li>\n<li>65.2<\/li>\n<\/ol>\n<\/div>\n<div id=\"id6538281\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div id=\"element-339\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id6538305\" class=\"problem\" data-type=\"problem\">\n<p>79. Would you be surprised, based upon numerical calculations, if the sample average wait time (in minutes) for 100 riders was less than 30 minutes?<\/p>\n<ol data-number-style=\"lower-alpha\">\n<li>yes<\/li>\n<li>no<\/li>\n<li>There is not enough information.<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<\/div>\n<div data-type=\"newline\"><em data-effect=\"italics\">\u00a0<\/em><\/div>\n<p data-type=\"glossary-title\"><em data-effect=\"italics\">Use the following to answer the next two exercises:<\/em> The cost of unleaded gasoline in the Bay Area once followed an unknown distribution with a mean of $4.59 and a standard deviation of $0.10. Sixteen gas stations from the Bay Area are randomly chosen. We are interested in the average cost of gasoline for the 16 gas stations.<\/p>\n<div id=\"element-644\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id6538784\" class=\"problem\" data-type=\"problem\">\n<p>80. What&#8217;s the approximate probability that the average price for 16 gas stations is over $4.69?<\/p>\n<ol data-number-style=\"lower-alpha\">\n<li>almost zero<\/li>\n<li>0.1587<\/li>\n<li>0.0943<\/li>\n<li>unknown<\/li>\n<\/ol>\n<\/div>\n<div id=\"id6538862\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"eip-id1164882896740\" class=\"problem\" data-type=\"problem\">\n<p>81. Find the probability that the average price for 30 gas stations is less than $4.55.<\/p>\n<ol id=\"element-193\" data-number-style=\"lower-alpha\">\n<li>0.6554<\/li>\n<li>0.3446<\/li>\n<li>0.0142<\/li>\n<li>0.9858<\/li>\n<li>0<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<\/div>\n<div id=\"eip-786\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div class=\"problem\" data-type=\"problem\">\n<p>82. Suppose in a local Kindergarten through 12<sup>th<\/sup> grade (K &#8211; 12) school district, 53 percent of the population favor a charter school for grades K through five. A simple random sample of 300 is surveyed. Calculate following using the normal approximation to the binomial distribution.<\/p>\n<ol id=\"Charter_School\" data-number-style=\"lower-alpha\">\n<li>Find the probability that less than 100 favor a charter school for grades K through 5.<\/li>\n<li>Find the probability that 170 or more favor a charter school for grades K through 5.<\/li>\n<li>Find the probability that no more than 140 favor a charter school for grades K through 5.<\/li>\n<li>Find the probability that there are fewer than 130 that favor a charter school for grades K through 5.<\/li>\n<li>Find the probability that exactly 150 favor a charter school for grades K through 5.<\/li>\n<\/ol>\n<p>83. If you have access to an appropriate calculator or computer software, try calculating these probabilities using the technology.<\/p>\n<\/div>\n<div class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div id=\"eip-140\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"eip-821\" class=\"problem\" data-type=\"problem\">\n<p>84. Four friends, Janice, Barbara, Kathy and Roberta, decided to carpool together to get to school. Each day the driver would be chosen by randomly selecting one of the four names. They carpool to school for 96 days. Use the normal approximation to the binomial to calculate the following probabilities. Round the standard deviation to four decimal places.<\/p>\n<ol id=\"Carpool\" data-number-style=\"lower-alpha\">\n<li>Find the probability that Janice is the driver at most 20 days.<\/li>\n<li>Find the probability that Roberta is the driver more than 16 days.<\/li>\n<li>Find the probability that Barbara drives exactly 24 of those 96 days.<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<\/div>\n<div id=\"element-440\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id6182284\" class=\"problem\" data-type=\"problem\">\n<p><em data-effect=\"italics\">85. X<\/em> ~ <em data-effect=\"italics\">N<\/em>(60, 9). Suppose that you form random samples of 25 from this distribution. Let[latex]\\displaystyle\\overline{{X}}[\/latex] be the random variable of averages. Let <em data-effect=\"italics\">\u03a3X<\/em> be the random variable of sums. For parts c through f, sketch the graph, shade the region, label and scale the horizontal axis for[latex]\\displaystyle\\overline{{X}}[\/latex], and find the probability.<\/p>\n<ol id=\"element-455\" data-number-style=\"lower-alpha\">\n<li>Sketch the distributions of <em data-effect=\"italics\">X<\/em> and[latex]\\displaystyle\\overline{{X}}[\/latex]on the same graph.<\/li>\n<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\n<li><em data-effect=\"italics\">P<\/em>([latex]\\displaystyle\\overline{{x}}[\/latex]&lt; 60) = _____<\/li>\n<li>Find the 30<sup>th<\/sup> percentile for the mean.<\/li>\n<li><em data-effect=\"italics\">P<\/em>(56 &lt;[latex]\\displaystyle\\overline{{x}}[\/latex]&lt; 62) = _____<\/li>\n<li><em data-effect=\"italics\">P<\/em>(18 &lt;[latex]\\displaystyle\\overline{{x}}[\/latex]\u00a0&lt; 58) = _____<\/li>\n<li><em data-effect=\"italics\">\u03a3x<\/em> ~ _____(_____,_____)<\/li>\n<li>Find the minimum value for the upper quartile for the sum.<\/li>\n<li><em data-effect=\"italics\">P<\/em>(1,400 &lt; <em data-effect=\"italics\">\u03a3x<\/em> &lt; 1,550) = _____<\/li>\n<\/ol>\n<\/div>\n<div id=\"id6009706\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id6534247\" class=\"problem\" data-type=\"problem\">\n<p>86. Suppose that the length of research papers is uniformly distributed from ten to 25 pages. We survey a class in which 55 research papers were turned in to a professor. The 55 research papers are considered a random collection of all papers. We are interested in the average length of the research papers.<\/p>\n<ol id=\"element-826\" data-number-style=\"lower-alpha\">\n<li>In words, <em data-effect=\"italics\">X<\/em> = _____________<\/li>\n<li><em data-effect=\"italics\">X<\/em> ~ _____(_____,_____)<\/li>\n<li><em data-effect=\"italics\">\u03bc<sub>x<\/sub><\/em> = _____<\/li>\n<li><em data-effect=\"italics\">\u03c3<sub>x<\/sub><\/em> = _____<\/li>\n<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex]= ______________<\/li>\n<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\n<li>In words, <em data-effect=\"italics\">\u03a3X<\/em> = _____________<\/li>\n<li><em data-effect=\"italics\">\u03a3X<\/em> ~ _____(_____,_____)<\/li>\n<li>Without doing any calculations, do you think that it\u2019s likely that the professor will need to read a total of more than 1,050 pages? Why?<\/li>\n<li>Calculate the probability that the professor will need to read a total of more than 1,050 pages.<\/li>\n<li>Why is it so unlikely that the average length of the papers will be less than 12 pages?<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id6535223\" class=\"problem\" data-type=\"problem\">\n<p>87. Salaries for teachers in a particular elementary school district are normally distributed with a mean of $44,000 and a standard deviation of $6,500. We randomly survey ten teachers from that district.<\/p>\n<ol data-number-style=\"lower-alpha\">\n<li>Find the 90<sup>th<\/sup> percentile for an individual teacher\u2019s salary.<\/li>\n<li>Find the 90<sup>th<\/sup> percentile for the average teacher\u2019s salary.<\/li>\n<\/ol>\n<\/div>\n<div id=\"fs-idm1040896\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div id=\"element-566\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"id6536038\" class=\"problem\" data-type=\"problem\">\n<p>88. The average length of a maternity stay in a U.S. hospital is said to be 2.4 days with a standard deviation of 0.9 days. We randomly survey 80 women who recently bore children in a U.S. hospital.<\/p>\n<ol id=\"madeup\" data-number-style=\"lower-alpha\">\n<li>In words, <em data-effect=\"italics\">X<\/em> = _____________<\/li>\n<li>In words,[latex]\\displaystyle\\overline{{X}}[\/latex]\u00a0= ___________________<\/li>\n<li>[latex]\\displaystyle\\overline{{X}}[\/latex] ~ _____(_____,_____)<\/li>\n<li>In words, <em data-effect=\"italics\">\u03a3X<\/em> = _______________<\/li>\n<li><em data-effect=\"italics\">\u03a3X<\/em> ~ _____(_____,_____)<\/li>\n<li>Is it likely that an individual stayed more than five days in the hospital? Why or why not?<\/li>\n<li>Is it likely that the average stay for the 80 women was more than five days? Why or why not?<\/li>\n<li>Which is more likely:\n<ol id=\"sublist\" data-number-style=\"lower-roman\">\n<li>An individual stayed more than five days.<\/li>\n<li>the average stay of 80 women was more than five days.<\/li>\n<\/ol>\n<\/li>\n<li>If we were to sum up the women\u2019s stays, is it likely that, collectively they spent more than a year in the hospital? Why or why not?<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<\/div>\n<div data-type=\"newline\"><\/div>\n<p data-type=\"glossary-title\"><em data-effect=\"italics\">For each problem, wherever possible, provide graphs and use the calculator.<\/em><\/p>\n<div id=\"fs-idm4142208\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm4141952\" class=\"problem\" data-type=\"problem\">89. NeverReady batteries has engineered a newer, longer lasting AAA battery. The company claims this battery has an average life span of 17 hours with a standard deviation of 0.8 hours. Your statistics class questions this claim. As a class, you randomly select 30 batteries and find that the sample mean life span is 16.7 hours. If the process is working properly, what is the probability of getting a random sample of 30 batteries in which the sample mean lifetime is 16.7 hours or less? Is the company\u2019s claim reasonable?<\/div>\n<div id=\"fs-idm4141184\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\">90. Men have an average weight of 172 pounds with a standard deviation of 29 pounds.<\/div>\n<div id=\"fs-idm165833488\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm165833232\" class=\"problem\" data-type=\"problem\">\n<ol id=\"fs-idm165831968\" data-number-style=\"lower-alpha\">\n<li>Find the probability that 20 randomly selected men will have a sum weight greater than 3600 lbs.<\/li>\n<li>If 20 men have a sum weight greater than 3500 lbs, then their total weight exceeds the safety limits for water taxis. Based on (a), is this a safety concern? Explain.<\/li>\n<\/ol>\n<p>M&amp;M candies large candy bags have a claimed net weight of 396.9 g. The standard deviation for the weight of the individual candies is 0.017 g. The following table is from a stats experiment conducted by a statistics class.<\/p>\n<\/div>\n<\/section>\n<\/div>\n<div id=\"fs-idp87424832\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idp87425088\" class=\"problem\" data-type=\"problem\">\n<p>\u00a0\u00a0\u00a00.8030.865\u00a0\u00a0\u00a00.9320.848\u00a0\u00a0\u00a00.8420.940\u00a0\u00a0\u00a00.8320.833\u00a0\u00a0\u00a00.8070.845\u00a0\u00a0\u00a0\u00a00.8410.852\u00a0\u00a0\u00a0\u00a00.9320.778\u00a0\u00a0\u00a0\u00a00.8330.814\u00a0\u00a0\u00a0\u00a00.8810.791\u00a0\u00a0\u00a0\u00a00.8180.810\u00a0\u00a0\u00a0\u00a00.8640.881\u00a0\u00a0\u00a0\u00a00.825\u00a0\u00a0\u00a0\u00a0\u00a00.855\u00a0\u00a0\u00a0\u00a0\u00a00.942\u00a0\u00a0\u00a0\u00a0\u00a00.825\u00a0\u00a0\u00a0\u00a0\u00a00.869\u00a0\u00a0\u00a0\u00a0\u00a00.912<\/p>\n<table id=\"fs-idm55488384\" summary=\"\">\n<thead>\n<tr>\n<th>Red<\/th>\n<th>Orange<\/th>\n<th>Yellow<\/th>\n<th>Brown<\/th>\n<th>Blue<\/th>\n<th>Green<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>0.751<\/td>\n<td>0.735<\/td>\n<td>0.883<\/td>\n<td>0.696<\/td>\n<td>0.881<\/td>\n<td>0.925<\/td>\n<\/tr>\n<tr>\n<td>0.841<\/td>\n<td>0.895<\/td>\n<td>0.769<\/td>\n<td>0.876<\/td>\n<td>0.863<\/td>\n<td>0.914<\/td>\n<\/tr>\n<tr>\n<td>0.856<\/td>\n<td>0.865<\/td>\n<td>0.859<\/td>\n<td>0.855<\/td>\n<td>0.775<\/td>\n<td>0.881<\/td>\n<\/tr>\n<tr>\n<td>0.799<\/td>\n<td>0.864<\/td>\n<td>0.784<\/td>\n<td>0.806<\/td>\n<td>0.854<\/td>\n<td>0.865<\/td>\n<\/tr>\n<tr>\n<td>0.966<\/td>\n<td>0.852<\/td>\n<td>0.824<\/td>\n<td>0.840<\/td>\n<td>0.810<\/td>\n<td>0.865<\/td>\n<\/tr>\n<tr>\n<td>0.859<\/td>\n<td>0.866<\/td>\n<td>0.858<\/td>\n<td>0.868<\/td>\n<td>0.858<\/td>\n<td>1.015<\/td>\n<\/tr>\n<tr>\n<td>0.857<\/td>\n<td>0.859<\/td>\n<td>0.848<\/td>\n<td>0.859<\/td>\n<td>0.818<\/td>\n<td>0.876<\/td>\n<\/tr>\n<tr>\n<td>0.942<\/td>\n<td>0.838<\/td>\n<td>0.851<\/td>\n<td>0.982<\/td>\n<td>0.868<\/td>\n<td>0.809<\/td>\n<\/tr>\n<tr>\n<td>0.873<\/td>\n<td>0.863<\/td>\n<\/tr>\n<tr>\n<td>0.809<\/td>\n<td>0.888<\/td>\n<\/tr>\n<tr>\n<td>0.890<\/td>\n<td>0.925<\/td>\n<\/tr>\n<tr>\n<td>0.878<\/td>\n<td>0.793<\/td>\n<\/tr>\n<tr>\n<td>0.905<\/td>\n<td>0.977<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>0.850<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>0.830<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>0.856<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>0.842<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>0.778<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>0.786<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>0.853<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>0.864<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>0.873<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>0.880<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>0.882<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>0.931<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td>0.887<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>91. The bag contained 465 candies and he listed weights in the table came from randomly selected candies. Count the weights.<\/p>\n<ol id=\"fs-idm5281504\" data-number-style=\"lower-alpha\">\n<li>Find the mean sample weight and the standard deviation of the sample weights of candies in the table.<\/li>\n<li>Find the sum of the sample weights in the table and the standard deviation of the sum the of the weights.<\/li>\n<li>If 465 M&amp;Ms are randomly selected, find the probability that their weights sum to at least 396.9.<\/li>\n<li>Is the Mars Company\u2019s M&amp;M labeling accurate?<\/li>\n<\/ol>\n<\/div>\n<div id=\"fs-idm20614304\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div id=\"fs-idp89909664\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idp89909920\" class=\"problem\" data-type=\"problem\">\n<p>92. The Screw Right Company claims their <span id=\"MathJax-Element-474-Frame\" class=\"MathJax\"><span id=\"MathJax-Span-5631\" class=\"math\"><span id=\"MathJax-Span-5632\" class=\"mrow\"><span id=\"MathJax-Span-5633\" class=\"semantics\"><span id=\"MathJax-Span-5634\" class=\"mrow\"><span id=\"MathJax-Span-5635\" class=\"mrow\"><span id=\"MathJax-Span-5636\" class=\"mfrac\"><span id=\"MathJax-Span-5637\" class=\"mn\">3<\/span><span id=\"MathJax-Span-5638\" class=\"mn\">4<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span> inch screws are within \u00b10.23 of the claimed mean diameter of 0.750 inches with a standard deviation of 0.115 inches. The following data were recorded.<\/p>\n<table id=\"fs-idm10579216\" summary=\"\">\n<tbody>\n<tr>\n<td>0.757<\/td>\n<td>0.723<\/td>\n<td>0.754<\/td>\n<td>0.737<\/td>\n<td>0.757<\/td>\n<td>0.741<\/td>\n<td>0.722<\/td>\n<td>0.741<\/td>\n<td>0.743<\/td>\n<td>0.742<\/td>\n<\/tr>\n<tr>\n<td>0.740<\/td>\n<td>0.758<\/td>\n<td>0.724<\/td>\n<td>0.739<\/td>\n<td>0.736<\/td>\n<td>0.735<\/td>\n<td>0.760<\/td>\n<td>0.750<\/td>\n<td>0.759<\/td>\n<td>0.754<\/td>\n<\/tr>\n<tr>\n<td>0.744<\/td>\n<td>0.758<\/td>\n<td>0.765<\/td>\n<td>0.756<\/td>\n<td>0.738<\/td>\n<td>0.742<\/td>\n<td>0.758<\/td>\n<td>0.757<\/td>\n<td>0.724<\/td>\n<td>0.757<\/td>\n<\/tr>\n<tr>\n<td>0.744<\/td>\n<td>0.738<\/td>\n<td>0.763<\/td>\n<td>0.756<\/td>\n<td>0.760<\/td>\n<td>0.768<\/td>\n<td>0.761<\/td>\n<td>0.742<\/td>\n<td>0.734<\/td>\n<td>0.754<\/td>\n<\/tr>\n<tr>\n<td>0.758<\/td>\n<td>0.735<\/td>\n<td>0.740<\/td>\n<td>0.743<\/td>\n<td>0.737<\/td>\n<td>0.737<\/td>\n<td>0.725<\/td>\n<td>0.761<\/td>\n<td>0.758<\/td>\n<td>0.756<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>The screws were randomly selected from the local home repair store.<\/p>\n<ol id=\"fs-idm59306112\" data-number-style=\"lower-alpha\">\n<li>Find the mean diameter and standard deviation for the sample<\/li>\n<li>Find the probability that 50 randomly selected screws will be within the stated tolerance levels. Is the company\u2019s diameter claim plausible?<\/li>\n<\/ol>\n<\/div>\n<\/section>\n<\/div>\n<div id=\"fs-idm3642992\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm3642736\" class=\"problem\" data-type=\"problem\">93. Your company has a contract to perform preventive maintenance on thousands of air-conditioners in a large city. Based on service records from previous years, the time that a technician spends servicing a unit averages one hour with a standard deviation of one hour. In the coming week, your company will service a simple random sample of 70 units in the city. You plan to budget an average of 1.1 hours per technician to complete the work. Will this be enough time?<\/div>\n<div id=\"fs-idm3641488\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<div id=\"fs-idm37303792\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm37303536\" class=\"problem\" data-type=\"problem\">94. A typical adult has an average IQ score of 105 with a standard deviation of 20. If 20 randomly selected adults are given an IQ tesst, what is the probability that the sample mean scores will be between 85 and 125 points?<\/div>\n<\/section>\n<\/div>\n<div id=\"fs-idm31585616\" class=\"exercise\" data-type=\"exercise\">\n<section>\n<div id=\"fs-idm31585360\" class=\"problem\" data-type=\"problem\">Certain coins have an average weight of 5.201 grams with a standard deviation of 0.065 g. If a vending machine is designed to accept coins whose weights range from 5.111 g to 5.291 g, what is the expected number of rejected coins when 280 randomly selected coins are inserted into the machine?<\/div>\n<div id=\"fs-idm31584288\" class=\"solution\" data-type=\"solution\"><\/div>\n<\/section>\n<\/div>\n<section class=\"free-response\" data-depth=\"1\">\n<div class=\"exercise\" data-type=\"exercise\"><\/div>\n<\/section>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-275\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Introductory Statistics . <strong>Authored by<\/strong>: Barbara Illowski, Susan Dean. <strong>Provided by<\/strong>: Open Stax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/30189442-6998-4686-ac05-ed152b91b9de@17.44\">http:\/\/cnx.org\/contents\/30189442-6998-4686-ac05-ed152b91b9de@17.44<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download for free at http:\/\/cnx.org\/contents\/30189442-6998-4686-ac05-ed152b91b9de@17.44<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":21,"menu_order":4,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Introductory Statistics \",\"author\":\"Barbara Illowski, Susan Dean\",\"organization\":\"Open Stax\",\"url\":\"http:\/\/cnx.org\/contents\/30189442-6998-4686-ac05-ed152b91b9de@17.44\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download for free at http:\/\/cnx.org\/contents\/30189442-6998-4686-ac05-ed152b91b9de@17.44\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-275","chapter","type-chapter","status-publish","hentry"],"part":256,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/wp-json\/pressbooks\/v2\/chapters\/275","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/wp-json\/wp\/v2\/users\/21"}],"version-history":[{"count":4,"href":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/wp-json\/pressbooks\/v2\/chapters\/275\/revisions"}],"predecessor-version":[{"id":1618,"href":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/wp-json\/pressbooks\/v2\/chapters\/275\/revisions\/1618"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/wp-json\/pressbooks\/v2\/parts\/256"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/wp-json\/pressbooks\/v2\/chapters\/275\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/wp-json\/wp\/v2\/media?parent=275"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/wp-json\/pressbooks\/v2\/chapter-type?post=275"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/wp-json\/wp\/v2\/contributor?post=275"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-fmcc-introstats1\/wp-json\/wp\/v2\/license?post=275"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}