{"id":125,"date":"2017-12-14T21:26:45","date_gmt":"2017-12-14T21:26:45","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-mcc-introductorychemistry\/chapter\/composition-decomposition-and-combustion-reactions\/"},"modified":"2017-12-14T21:26:45","modified_gmt":"2017-12-14T21:26:45","slug":"composition-decomposition-and-combustion-reactions","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/chapter\/composition-decomposition-and-combustion-reactions\/","title":{"raw":"Composition, Decomposition, and Combustion Reactions","rendered":"Composition, Decomposition, and Combustion Reactions"},"content":{"raw":"<div>\n<div class=\"section\" id=\"ball-ch04_s04\" lang=\"en\">\n<div class=\"learning_objectives editable block\" id=\"ball-ch04_s04_n01\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<ol id=\"ball-ch04_s04_l01\"><li>Recognize composition, decomposition, and combustion reactions.<\/li>\n\t<li>Predict the products of a combustion reaction.<\/li>\n<\/ol><\/div>\n<\/div>\n<p id=\"ball-ch04_s04_p01\" class=\"para editable block\">Three classifications of chemical reactions will be reviewed in this section. Predicting the products in some of them may be difficult, but the reactions are still easy to recognize.<\/p>\n<p id=\"ball-ch04_s04_p02\" class=\"para editable block\">A <span class=\"margin_term\"><a class=\"glossterm\">composition reaction<\/a><\/span>\u00a0(sometimes also called a <em class=\"emphasis\">combination reaction<\/em> or a <em class=\"emphasis\">synthesis reaction<\/em>) produces a single substance from multiple reactants. A single substance as a product is the key characteristic of the composition reaction. There may be a coefficient other than one for the substance, but if the reaction has only a single substance as a product, it can be called a composition reaction. In the reaction<\/p>\n<span class=\"informalequation block\"><span class=\"mathphrase\">2 H<sub class=\"subscript\">2<\/sub>(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span>\n<p id=\"ball-ch04_s04_p03\" class=\"para editable block\">water is produced from hydrogen and oxygen. Although there are two molecules of water being produced, there is only one substance\u2014water\u2014as a product. So this is a composition reaction.<\/p>\n<p id=\"ball-ch04_s04_p04\" class=\"para editable block\">A <span class=\"margin_term\"><a class=\"glossterm\">decomposition reaction<\/a><\/span>\u00a0starts from a single substance and produces more than one substance; that is, it decomposes. One substance as a reactant and more than one substance as the products is the key characteristic of a decomposition reaction. For example, in the decomposition of sodium hydrogen carbonate (also known as sodium bicarbonate),<\/p>\n<span class=\"informalequation block\"><span class=\"mathphrase\">2 NaHCO<sub class=\"subscript\">3<\/sub>(s) \u2192\u00a0Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(s) +\u00a0CO<sub class=\"subscript\">2<\/sub>(g) +\u00a0H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span>\n<p id=\"ball-ch04_s04_p05\" class=\"para editable block\">sodium carbonate, carbon dioxide, and water are produced from the single substance sodium hydrogen carbonate.<\/p>\n<p id=\"ball-ch04_s04_p06\" class=\"para editable block\">Composition and decomposition reactions are difficult to predict; however, they should be easy to recognize.<\/p>\n\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 9<\/h3>\n<p id=\"ball-ch04_s04_p07\" class=\"para\">Identify each equation as a composition reaction, a decomposition reaction, or neither.<\/p>\n\n<ol id=\"ball-ch04_s04_l02\" class=\"orderedlist\"><li>Fe<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub> +\u00a03 SO<sub class=\"subscript\">3<\/sub> \u2192\u00a0Fe<sub class=\"subscript\">2<\/sub>(SO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\n\t<li>NaCl +\u00a0AgNO<sub class=\"subscript\">3<\/sub> \u2192\u00a0AgCl +\u00a0NaNO<sub class=\"subscript\">3<\/sub><\/li>\n\t<li>(NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub> \u2192\u00a0Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub> +\u00a04 H<sub class=\"subscript\">2<\/sub>O +\u00a0N<sub class=\"subscript\">2<\/sub><\/li>\n<\/ol><p class=\"simpara\">Solution<\/p>\n\n<ol id=\"ball-ch04_s04_l03\" class=\"orderedlist\"><li>In this equation, two substances combine to make a single substance. This is a composition reaction.<\/li>\n\t<li>Two different substances react to make two new substances. This does not fit the definition of either a composition reaction or a decomposition reaction, so it is neither. In fact, you may recognize this as a double-replacement reaction.<\/li>\n\t<li>A single substance reacts to make multiple substances. This is a decomposition reaction.<\/li>\n<\/ol><p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch04_s04_p08\" class=\"para\">Identify the equation as a composition reaction, a decomposition reaction, or neither.<\/p>\n<span class=\"informalequation\"><span class=\"mathphrase\">C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">8<\/sub> \u2192\u00a0C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">4<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub><\/span><\/span>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch04_s04_p09\" class=\"para\">decomposition<\/p>\n\n<\/div>\n<p id=\"ball-ch04_s04_p10\" class=\"para editable block\">A <span class=\"margin_term\"><a class=\"glossterm\">combustion reaction<\/a><\/span>\u00a0occurs when a reactant combines with oxygen, many times from the atmosphere, to produce oxides of all other elements as products; any nitrogen in the reactant is converted to elemental nitrogen, N<sub class=\"subscript\">2<\/sub>. Many reactants, called <em class=\"emphasis\">fuels<\/em>, contain mostly carbon and hydrogen atoms, reacting with oxygen to produce CO<sub class=\"subscript\">2<\/sub> and H<sub class=\"subscript\">2<\/sub>O. For example, the balanced chemical equation for the combustion of methane, CH<sub class=\"subscript\">4<\/sub>, is as follows:<\/p>\n<span class=\"informalequation block\"><span class=\"mathphrase\">CH<sub class=\"subscript\">4<\/sub> +\u00a02 O<sub class=\"subscript\">2<\/sub> \u2192\u00a0CO<sub class=\"subscript\">2<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub>O<\/span><\/span>\n<p id=\"ball-ch04_s04_p11\" class=\"para editable block\">Kerosene can be approximated with the formula C<sub class=\"subscript\">12<\/sub>H<sub class=\"subscript\">26<\/sub>, and its combustion equation is<\/p>\n<span class=\"informalequation block\"><span class=\"mathphrase\">2 C<sub class=\"subscript\">12<\/sub>H<sub class=\"subscript\">26<\/sub> +\u00a037 O<sub class=\"subscript\">2<\/sub> \u2192\u00a024 CO<sub class=\"subscript\">2<\/sub> +\u00a026 H<sub class=\"subscript\">2<\/sub>O<\/span><\/span>\n<p id=\"ball-ch04_s04_p12\" class=\"para editable block\">Sometimes fuels contain oxygen atoms, which must be counted when balancing the chemical equation. One common fuel is ethanol, C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">5<\/sub>OH, whose combustion equation is<\/p>\n<span class=\"informalequation block\"><span class=\"mathphrase\">C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">5<\/sub>OH +\u00a03 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 CO<sub class=\"subscript\">2<\/sub> +\u00a03 H<sub class=\"subscript\">2<\/sub>O<\/span><\/span>\n<p id=\"ball-ch04_s04_p13\" class=\"para editable block\">If nitrogen is present in the original fuel, it is converted to N<sub class=\"subscript\">2<\/sub>, not to a nitrogen-oxygen compound. Thus, for the combustion of the fuel dinitroethylene, whose formula is C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">2<\/sub>N<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub>, we have<\/p>\n<span class=\"informalequation block\"><span class=\"mathphrase\">2 C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">2<\/sub>N<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a04 CO<sub class=\"subscript\">2<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub>O +\u00a02 N<sub class=\"subscript\">2<\/sub><\/span><\/span>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 10<\/h3>\n<p id=\"ball-ch04_s04_p14\" class=\"para\">Complete and balance each combustion equation.<\/p>\n\n<ol id=\"ball-ch04_s04_l04\" class=\"orderedlist\"><li>the combustion of propane, C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">8<\/sub><\/li>\n\t<li>the combustion of ammonia, NH<sub class=\"subscript\">3<\/sub><\/li>\n<\/ol><p class=\"simpara\">Solution<\/p>\n\n<ol id=\"ball-ch04_s04_l05\" class=\"orderedlist\"><li>\n<p class=\"para\">The products of the reaction are CO<sub class=\"subscript\">2<\/sub> and H<sub class=\"subscript\">2<\/sub>O, so our unbalanced equation is<\/p>\n<span class=\"informalequation\"><span class=\"mathphrase\">C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">8<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0CO<sub class=\"subscript\">2<\/sub> +\u00a0H<sub class=\"subscript\">2<\/sub>O<\/span><\/span>\n<p id=\"ball-ch04_s04_p15\" class=\"para\">Balancing (and you may have to go back and forth a few times to balance this), we get<\/p>\n<span class=\"informalequation\"><span class=\"mathphrase\">C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">8<\/sub> +\u00a05 O<sub class=\"subscript\">2<\/sub> \u2192\u00a03 CO<sub class=\"subscript\">2<\/sub> +\u00a04 H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/li>\n\t<li>\n<p class=\"para\">The nitrogen atoms in ammonia will react to make N<sub class=\"subscript\">2<\/sub>, while the hydrogen atoms will react with O<sub class=\"subscript\">2<\/sub> to make H<sub class=\"subscript\">2<\/sub>O:<\/p>\n<span class=\"informalequation\"><span class=\"mathphrase\">NH<sub class=\"subscript\">3<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0N<sub class=\"subscript\">2<\/sub> +\u00a0H<sub class=\"subscript\">2<\/sub>O<\/span><\/span>\n<p id=\"ball-ch04_s04_p16\" class=\"para\">To balance this equation without fractions (which is the convention), we get<\/p>\n<span class=\"informalequation\"><span class=\"mathphrase\">4 NH<sub class=\"subscript\">3<\/sub> +\u00a03 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 N<sub class=\"subscript\">2<\/sub> +\u00a06 H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/li>\n<\/ol><p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch04_s04_p17\" class=\"para\">Complete and balance the combustion equation for cyclopropanol, C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">6<\/sub>O.<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch04_s04_p18\" class=\"para\">C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">6<\/sub>O +\u00a04 O<sub class=\"subscript\">2<\/sub> \u2192\u00a03 CO<sub class=\"subscript\">2<\/sub> +\u00a03 H<sub class=\"subscript\">2<\/sub>O<\/p>\n\n<div class=\"informalfigure medium\" id=\"ball-ch04_s04_f01\">\n\n[caption id=\"attachment_3213\" align=\"alignnone\" width=\"400\"]<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/5345065044_0d15179564_b.jpg\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212643\/5345065044_0d15179564_b-1.jpg\" alt=\"Propane is a fuel used to provide heat for some homes. Propane is stored in large tanks like that shown here. Source: &#x201C;flowers and propane&#x201D; by vistavision is licensed under the Creative Commons Attribution-NonCommercial-NoDerivs 2.0 Generic\" class=\"wp-image-3213\" height=\"408\" width=\"400\"\/><\/a> Propane is a fuel used to provide heat for some homes. Propane is stored in large tanks like that shown here.<br\/> Source: \u201cflowers and propane\u201d by vistavision is licensed under the Creative Commons Attribution-NonCommercial-NoDerivs 2.0 Generic[\/caption]\n\n<\/div>\n<\/div>\n<div class=\"key_takeaways editable block\" id=\"ball-ch04_s04_n04\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul id=\"ball-ch04_s04_l06\" class=\"itemizedlist\"><li>A composition reaction produces a single substance from multiple reactants.<\/li>\n\t<li>A decomposition reaction produces multiple products from a single reactant.<\/li>\n\t<li>Combustion reactions are the combination of some compound with oxygen to make oxides of the other elements as products (although nitrogen atoms react to make N<sub class=\"subscript\">2<\/sub>).<\/li>\n<\/ul><\/div>\n\u00a0\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<ol id=\"ball-ch04_s04_qs01_qd01\" class=\"qandadiv\"><li id=\"ball-ch04_s04_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p1\" class=\"para\">Which is a composition reaction and which is not?<\/p>\n\n<\/div><\/li>\n<\/ol>\na) \u00a0NaCl +\u00a0AgNO<sub class=\"subscript\">3<\/sub> \u2192\u00a0AgCl +\u00a0NaNO<sub class=\"subscript\">3<\/sub>\n\nb) \u00a0CaO +\u00a0CO<sub class=\"subscript\">2<\/sub> \u2192\u00a0CaCO<sub class=\"subscript\">3<\/sub>\n\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p2\" class=\"para\">2. \u00a0Which is a composition reaction and which is not?<\/p>\na) \u00a0H<sub class=\"subscript\">2<\/sub> +\u00a0Cl<sub class=\"subscript\">2<\/sub> \u2192\u00a02 HCl\n\nb) \u00a02 HBr +\u00a0Cl<sub class=\"subscript\">2<\/sub> \u2192\u00a02 HCl +\u00a0Br<sub class=\"subscript\">2<\/sub><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p3\" class=\"para\">3. \u00a0Which is a composition reaction and which is not?<\/p>\na) \u00a02 SO<sub class=\"subscript\">2<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 SO<sub class=\"subscript\">3<\/sub>\n\nb) \u00a06 C +\u00a03 H<sub class=\"subscript\">2<\/sub> \u2192\u00a0C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">6<\/sub><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p4\" class=\"para\">4. \u00a0Which is a composition reaction and which is not?<\/p>\na) \u00a04 Na +\u00a02 C +\u00a03 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>\n\nb) \u00a0Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub> \u2192\u00a0Na<sub class=\"subscript\">2<\/sub>O +\u00a0CO<sub class=\"subscript\">2<\/sub><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p5\" class=\"para\">5. \u00a0Which is a decomposition reaction and which is not?<\/p>\na) \u00a0HCl +\u00a0NaOH \u2192\u00a0NaCl +\u00a0H<sub class=\"subscript\">2<\/sub>O\n\nb) \u00a0CaCO<sub class=\"subscript\">3<\/sub> \u2192\u00a0CaO +\u00a0CO<sub class=\"subscript\">2<\/sub><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p6\" class=\"para\">6. \u00a0Which is a decomposition reaction and which is not?<\/p>\na) \u00a03 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 O<sub class=\"subscript\">3<\/sub>\n\nb) \u00a02 KClO<sub class=\"subscript\">3<\/sub> \u2192\u00a02 KCl +\u00a03 O<sub class=\"subscript\">2<\/sub><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p7\" class=\"para\">7. \u00a0Which is a decomposition reaction and which is not?<\/p>\na) \u00a0Na<sub class=\"subscript\">2<\/sub>O +\u00a0CO<sub class=\"subscript\">2<\/sub> \u2192\u00a0Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>\n\nb) \u00a0H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">3<\/sub> \u2192\u00a0H<sub class=\"subscript\">2<\/sub>O +\u00a0SO<sub class=\"subscript\">2<\/sub><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p8\" class=\"para\">8. \u00a0Which is a decomposition reaction and which is not?<\/p>\na) \u00a02 C<sub class=\"subscript\">7<\/sub>H<sub class=\"subscript\">5<\/sub>N<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">6<\/sub> \u2192\u00a03 N<sub class=\"subscript\">2<\/sub> +\u00a05 H<sub class=\"subscript\">2<\/sub>O +\u00a07 CO +\u00a07 C\n\nb) \u00a0C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub> +\u00a06 O<sub class=\"subscript\">2<\/sub> \u2192\u00a06 CO<sub class=\"subscript\">2<\/sub> +\u00a06 H<sub class=\"subscript\">2<\/sub>O\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p9\" class=\"para\">9. \u00a0Which is a combustion reaction and which is not?<\/p>\na) \u00a0C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub> +\u00a06 O<sub class=\"subscript\">2<\/sub> \u2192\u00a06 CO<sub class=\"subscript\">2<\/sub> +\u00a06 H<sub class=\"subscript\">2<\/sub>O\n\nb) \u00a02 Fe<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">3<\/sub> +\u00a09 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 Fe<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub> +\u00a06 SO<sub class=\"subscript\">2<\/sub><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p10\" class=\"para\">10. \u00a0Which is a combustion reaction and which is not?<\/p>\na) \u00a0CH<sub class=\"subscript\">4<\/sub> +\u00a02 F<sub class=\"subscript\">2<\/sub> \u2192\u00a0CF<sub class=\"subscript\">4<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub>\n\nb) \u00a02 H<sub class=\"subscript\">2<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p11\" class=\"para\">11. \u00a0Which is a combustion reaction and which is not?<\/p>\na) \u00a0P<sub class=\"subscript\">4<\/sub> +\u00a05 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 P<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">5<\/sub>\n\nb) \u00a02 Al<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">3<\/sub> +\u00a09 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 Al<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub> +\u00a06 SO<sub class=\"subscript\">2<\/sub><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p12\" class=\"para\">12. \u00a0Which is a combustion reaction and which is not?<\/p>\na) \u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub>O<sub class=\"subscript\">2<\/sub>\n\nb) \u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub> +\u00a0Cl<sub class=\"subscript\">2<\/sub> \u2192\u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub>Cl<sub class=\"subscript\">2<\/sub><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p13\" class=\"para\">13. \u00a0Is it possible for a composition reaction to also be a combustion reaction? Give an example to support your case.<\/p>\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p15\" class=\"para\">14. \u00a0Is it possible for a decomposition reaction to also be a combustion reaction? Give an example to support your case.<\/p>\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p17\" class=\"para\">15. \u00a0Complete and balance each combustion equation.<\/p>\na) \u00a0C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">9<\/sub>OH +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0?\n\nb) \u00a0CH<sub class=\"subscript\">3<\/sub>NO<sub class=\"subscript\">2<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0?\n\n<\/div>\n16. \u00a0Complete and balance each combustion equation.\n\na) \u00a0B<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">6<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0? (The oxide of boron formed is B<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>.)\n\nb) \u00a0Al<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">3<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0? (The oxide of sulfur formed is SO<sub class=\"subscript\">2<\/sub>.)\n\nc) \u00a0Al<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">3<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0? (The oxide of sulfur formed is SO<sub class=\"subscript\">3<\/sub>.)\n\n<strong>Answers<\/strong>\n<div class=\"qandaset block\" id=\"ball-ch04_s04_qs01_ans\">\n\n<strong>1.<\/strong>\n\na) \u00a0not composition\n<div class=\"answer\">\nb) \u00a0composition\n\n<\/div>\n<strong>3.<\/strong>\n\na) \u00a0composition\n<div class=\"answer\">\nb) \u00a0composition\n\n<strong>5.<\/strong>\n\na) \u00a0not decomposition\n<div class=\"answer\">\nb) \u00a0decomposition\n\n<strong>7.<\/strong>\n\na) \u00a0not decomposition\n<div class=\"answer\">\nb) \u00a0decomposition\n\n<strong>9.<\/strong>\n\na) \u00a0combustion\n<div class=\"answer\">\nb) \u00a0combustion\n\n<strong>11.<\/strong>\n\na) \u00a0combustion\n<div class=\"answer\">\nb) \u00a0combustion\n\n<strong>13.<\/strong>\n\nYes; 2 H<sub class=\"subscript\">2<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O (answers will vary)\n\n<strong>15.<\/strong>\n\na) \u00a0C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">9<\/sub>OH +\u00a06 O<sub class=\"subscript\">2<\/sub> \u2192\u00a04 CO<sub class=\"subscript\">2<\/sub> +\u00a05 H<sub class=\"subscript\">2<\/sub>O\n<div class=\"answer\">\nb) \u00a04 CH<sub class=\"subscript\">3<\/sub>NO<sub class=\"subscript\">2<\/sub> +\u00a03 O<sub class=\"subscript\">2<\/sub> \u2192\u00a04 CO<sub class=\"subscript\">2<\/sub> +\u00a06 H<sub class=\"subscript\">2<\/sub>O +\u00a02 N<sub class=\"subscript\">2<\/sub><\/div>\n\u00a0\n\n<\/div>\n<div class=\"para\">\n<\/div>\n<\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div>","rendered":"<div>\n<div class=\"section\" id=\"ball-ch04_s04\" lang=\"en\">\n<div class=\"learning_objectives editable block\" id=\"ball-ch04_s04_n01\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<ol id=\"ball-ch04_s04_l01\">\n<li>Recognize composition, decomposition, and combustion reactions.<\/li>\n<li>Predict the products of a combustion reaction.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"ball-ch04_s04_p01\" class=\"para editable block\">Three classifications of chemical reactions will be reviewed in this section. Predicting the products in some of them may be difficult, but the reactions are still easy to recognize.<\/p>\n<p id=\"ball-ch04_s04_p02\" class=\"para editable block\">A <span class=\"margin_term\"><a class=\"glossterm\">composition reaction<\/a><\/span>\u00a0(sometimes also called a <em class=\"emphasis\">combination reaction<\/em> or a <em class=\"emphasis\">synthesis reaction<\/em>) produces a single substance from multiple reactants. A single substance as a product is the key characteristic of the composition reaction. There may be a coefficient other than one for the substance, but if the reaction has only a single substance as a product, it can be called a composition reaction. In the reaction<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">2 H<sub class=\"subscript\">2<\/sub>(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span><\/p>\n<p id=\"ball-ch04_s04_p03\" class=\"para editable block\">water is produced from hydrogen and oxygen. Although there are two molecules of water being produced, there is only one substance\u2014water\u2014as a product. So this is a composition reaction.<\/p>\n<p id=\"ball-ch04_s04_p04\" class=\"para editable block\">A <span class=\"margin_term\"><a class=\"glossterm\">decomposition reaction<\/a><\/span>\u00a0starts from a single substance and produces more than one substance; that is, it decomposes. One substance as a reactant and more than one substance as the products is the key characteristic of a decomposition reaction. For example, in the decomposition of sodium hydrogen carbonate (also known as sodium bicarbonate),<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">2 NaHCO<sub class=\"subscript\">3<\/sub>(s) \u2192\u00a0Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(s) +\u00a0CO<sub class=\"subscript\">2<\/sub>(g) +\u00a0H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span><\/p>\n<p id=\"ball-ch04_s04_p05\" class=\"para editable block\">sodium carbonate, carbon dioxide, and water are produced from the single substance sodium hydrogen carbonate.<\/p>\n<p id=\"ball-ch04_s04_p06\" class=\"para editable block\">Composition and decomposition reactions are difficult to predict; however, they should be easy to recognize.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 9<\/h3>\n<p id=\"ball-ch04_s04_p07\" class=\"para\">Identify each equation as a composition reaction, a decomposition reaction, or neither.<\/p>\n<ol id=\"ball-ch04_s04_l02\" class=\"orderedlist\">\n<li>Fe<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub> +\u00a03 SO<sub class=\"subscript\">3<\/sub> \u2192\u00a0Fe<sub class=\"subscript\">2<\/sub>(SO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\n<li>NaCl +\u00a0AgNO<sub class=\"subscript\">3<\/sub> \u2192\u00a0AgCl +\u00a0NaNO<sub class=\"subscript\">3<\/sub><\/li>\n<li>(NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub> \u2192\u00a0Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub> +\u00a04 H<sub class=\"subscript\">2<\/sub>O +\u00a0N<sub class=\"subscript\">2<\/sub><\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<ol id=\"ball-ch04_s04_l03\" class=\"orderedlist\">\n<li>In this equation, two substances combine to make a single substance. This is a composition reaction.<\/li>\n<li>Two different substances react to make two new substances. This does not fit the definition of either a composition reaction or a decomposition reaction, so it is neither. In fact, you may recognize this as a double-replacement reaction.<\/li>\n<li>A single substance reacts to make multiple substances. This is a decomposition reaction.<\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch04_s04_p08\" class=\"para\">Identify the equation as a composition reaction, a decomposition reaction, or neither.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">8<\/sub> \u2192\u00a0C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">4<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub><\/span><\/span><\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch04_s04_p09\" class=\"para\">decomposition<\/p>\n<\/div>\n<p id=\"ball-ch04_s04_p10\" class=\"para editable block\">A <span class=\"margin_term\"><a class=\"glossterm\">combustion reaction<\/a><\/span>\u00a0occurs when a reactant combines with oxygen, many times from the atmosphere, to produce oxides of all other elements as products; any nitrogen in the reactant is converted to elemental nitrogen, N<sub class=\"subscript\">2<\/sub>. Many reactants, called <em class=\"emphasis\">fuels<\/em>, contain mostly carbon and hydrogen atoms, reacting with oxygen to produce CO<sub class=\"subscript\">2<\/sub> and H<sub class=\"subscript\">2<\/sub>O. For example, the balanced chemical equation for the combustion of methane, CH<sub class=\"subscript\">4<\/sub>, is as follows:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">CH<sub class=\"subscript\">4<\/sub> +\u00a02 O<sub class=\"subscript\">2<\/sub> \u2192\u00a0CO<sub class=\"subscript\">2<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/p>\n<p id=\"ball-ch04_s04_p11\" class=\"para editable block\">Kerosene can be approximated with the formula C<sub class=\"subscript\">12<\/sub>H<sub class=\"subscript\">26<\/sub>, and its combustion equation is<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">2 C<sub class=\"subscript\">12<\/sub>H<sub class=\"subscript\">26<\/sub> +\u00a037 O<sub class=\"subscript\">2<\/sub> \u2192\u00a024 CO<sub class=\"subscript\">2<\/sub> +\u00a026 H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/p>\n<p id=\"ball-ch04_s04_p12\" class=\"para editable block\">Sometimes fuels contain oxygen atoms, which must be counted when balancing the chemical equation. One common fuel is ethanol, C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">5<\/sub>OH, whose combustion equation is<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">5<\/sub>OH +\u00a03 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 CO<sub class=\"subscript\">2<\/sub> +\u00a03 H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/p>\n<p id=\"ball-ch04_s04_p13\" class=\"para editable block\">If nitrogen is present in the original fuel, it is converted to N<sub class=\"subscript\">2<\/sub>, not to a nitrogen-oxygen compound. Thus, for the combustion of the fuel dinitroethylene, whose formula is C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">2<\/sub>N<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub>, we have<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">2 C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">2<\/sub>N<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a04 CO<sub class=\"subscript\">2<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub>O +\u00a02 N<sub class=\"subscript\">2<\/sub><\/span><\/span><\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 10<\/h3>\n<p id=\"ball-ch04_s04_p14\" class=\"para\">Complete and balance each combustion equation.<\/p>\n<ol id=\"ball-ch04_s04_l04\" class=\"orderedlist\">\n<li>the combustion of propane, C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">8<\/sub><\/li>\n<li>the combustion of ammonia, NH<sub class=\"subscript\">3<\/sub><\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<ol id=\"ball-ch04_s04_l05\" class=\"orderedlist\">\n<li>\n<p class=\"para\">The products of the reaction are CO<sub class=\"subscript\">2<\/sub> and H<sub class=\"subscript\">2<\/sub>O, so our unbalanced equation is<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">8<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0CO<sub class=\"subscript\">2<\/sub> +\u00a0H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/p>\n<p id=\"ball-ch04_s04_p15\" class=\"para\">Balancing (and you may have to go back and forth a few times to balance this), we get<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">8<\/sub> +\u00a05 O<sub class=\"subscript\">2<\/sub> \u2192\u00a03 CO<sub class=\"subscript\">2<\/sub> +\u00a04 H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/li>\n<li>\n<p class=\"para\">The nitrogen atoms in ammonia will react to make N<sub class=\"subscript\">2<\/sub>, while the hydrogen atoms will react with O<sub class=\"subscript\">2<\/sub> to make H<sub class=\"subscript\">2<\/sub>O:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">NH<sub class=\"subscript\">3<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0N<sub class=\"subscript\">2<\/sub> +\u00a0H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/p>\n<p id=\"ball-ch04_s04_p16\" class=\"para\">To balance this equation without fractions (which is the convention), we get<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">4 NH<sub class=\"subscript\">3<\/sub> +\u00a03 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 N<sub class=\"subscript\">2<\/sub> +\u00a06 H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch04_s04_p17\" class=\"para\">Complete and balance the combustion equation for cyclopropanol, C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">6<\/sub>O.<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch04_s04_p18\" class=\"para\">C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">6<\/sub>O +\u00a04 O<sub class=\"subscript\">2<\/sub> \u2192\u00a03 CO<sub class=\"subscript\">2<\/sub> +\u00a03 H<sub class=\"subscript\">2<\/sub>O<\/p>\n<div class=\"informalfigure medium\" id=\"ball-ch04_s04_f01\">\n<div id=\"attachment_3213\" style=\"width: 410px\" class=\"wp-caption alignnone\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/5345065044_0d15179564_b.jpg\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-3213\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212643\/5345065044_0d15179564_b-1.jpg\" alt=\"Propane is a fuel used to provide heat for some homes. Propane is stored in large tanks like that shown here. Source: &#x201c;flowers and propane&#x201d; by vistavision is licensed under the Creative Commons Attribution-NonCommercial-NoDerivs 2.0 Generic\" class=\"wp-image-3213\" height=\"408\" width=\"400\" \/><\/a><\/p>\n<p id=\"caption-attachment-3213\" class=\"wp-caption-text\">Propane is a fuel used to provide heat for some homes. Propane is stored in large tanks like that shown here.<br \/> Source: \u201cflowers and propane\u201d by vistavision is licensed under the Creative Commons Attribution-NonCommercial-NoDerivs 2.0 Generic<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"key_takeaways editable block\" id=\"ball-ch04_s04_n04\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul id=\"ball-ch04_s04_l06\" class=\"itemizedlist\">\n<li>A composition reaction produces a single substance from multiple reactants.<\/li>\n<li>A decomposition reaction produces multiple products from a single reactant.<\/li>\n<li>Combustion reactions are the combination of some compound with oxygen to make oxides of the other elements as products (although nitrogen atoms react to make N<sub class=\"subscript\">2<\/sub>).<\/li>\n<\/ul>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<ol id=\"ball-ch04_s04_qs01_qd01\" class=\"qandadiv\">\n<li id=\"ball-ch04_s04_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p1\" class=\"para\">Which is a composition reaction and which is not?<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<p>a) \u00a0NaCl +\u00a0AgNO<sub class=\"subscript\">3<\/sub> \u2192\u00a0AgCl +\u00a0NaNO<sub class=\"subscript\">3<\/sub><\/p>\n<p>b) \u00a0CaO +\u00a0CO<sub class=\"subscript\">2<\/sub> \u2192\u00a0CaCO<sub class=\"subscript\">3<\/sub><\/p>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p2\" class=\"para\">2. \u00a0Which is a composition reaction and which is not?<\/p>\n<p>a) \u00a0H<sub class=\"subscript\">2<\/sub> +\u00a0Cl<sub class=\"subscript\">2<\/sub> \u2192\u00a02 HCl<\/p>\n<p>b) \u00a02 HBr +\u00a0Cl<sub class=\"subscript\">2<\/sub> \u2192\u00a02 HCl +\u00a0Br<sub class=\"subscript\">2<\/sub><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p3\" class=\"para\">3. \u00a0Which is a composition reaction and which is not?<\/p>\n<p>a) \u00a02 SO<sub class=\"subscript\">2<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 SO<sub class=\"subscript\">3<\/sub><\/p>\n<p>b) \u00a06 C +\u00a03 H<sub class=\"subscript\">2<\/sub> \u2192\u00a0C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">6<\/sub><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p4\" class=\"para\">4. \u00a0Which is a composition reaction and which is not?<\/p>\n<p>a) \u00a04 Na +\u00a02 C +\u00a03 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub><\/p>\n<p>b) \u00a0Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub> \u2192\u00a0Na<sub class=\"subscript\">2<\/sub>O +\u00a0CO<sub class=\"subscript\">2<\/sub><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p5\" class=\"para\">5. \u00a0Which is a decomposition reaction and which is not?<\/p>\n<p>a) \u00a0HCl +\u00a0NaOH \u2192\u00a0NaCl +\u00a0H<sub class=\"subscript\">2<\/sub>O<\/p>\n<p>b) \u00a0CaCO<sub class=\"subscript\">3<\/sub> \u2192\u00a0CaO +\u00a0CO<sub class=\"subscript\">2<\/sub><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p6\" class=\"para\">6. \u00a0Which is a decomposition reaction and which is not?<\/p>\n<p>a) \u00a03 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 O<sub class=\"subscript\">3<\/sub><\/p>\n<p>b) \u00a02 KClO<sub class=\"subscript\">3<\/sub> \u2192\u00a02 KCl +\u00a03 O<sub class=\"subscript\">2<\/sub><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p7\" class=\"para\">7. \u00a0Which is a decomposition reaction and which is not?<\/p>\n<p>a) \u00a0Na<sub class=\"subscript\">2<\/sub>O +\u00a0CO<sub class=\"subscript\">2<\/sub> \u2192\u00a0Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub><\/p>\n<p>b) \u00a0H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">3<\/sub> \u2192\u00a0H<sub class=\"subscript\">2<\/sub>O +\u00a0SO<sub class=\"subscript\">2<\/sub><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p8\" class=\"para\">8. \u00a0Which is a decomposition reaction and which is not?<\/p>\n<p>a) \u00a02 C<sub class=\"subscript\">7<\/sub>H<sub class=\"subscript\">5<\/sub>N<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">6<\/sub> \u2192\u00a03 N<sub class=\"subscript\">2<\/sub> +\u00a05 H<sub class=\"subscript\">2<\/sub>O +\u00a07 CO +\u00a07 C<\/p>\n<p>b) \u00a0C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub> +\u00a06 O<sub class=\"subscript\">2<\/sub> \u2192\u00a06 CO<sub class=\"subscript\">2<\/sub> +\u00a06 H<sub class=\"subscript\">2<\/sub>O<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p9\" class=\"para\">9. \u00a0Which is a combustion reaction and which is not?<\/p>\n<p>a) \u00a0C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub> +\u00a06 O<sub class=\"subscript\">2<\/sub> \u2192\u00a06 CO<sub class=\"subscript\">2<\/sub> +\u00a06 H<sub class=\"subscript\">2<\/sub>O<\/p>\n<p>b) \u00a02 Fe<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">3<\/sub> +\u00a09 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 Fe<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub> +\u00a06 SO<sub class=\"subscript\">2<\/sub><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p10\" class=\"para\">10. \u00a0Which is a combustion reaction and which is not?<\/p>\n<p>a) \u00a0CH<sub class=\"subscript\">4<\/sub> +\u00a02 F<sub class=\"subscript\">2<\/sub> \u2192\u00a0CF<sub class=\"subscript\">4<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub><\/p>\n<p>b) \u00a02 H<sub class=\"subscript\">2<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p11\" class=\"para\">11. \u00a0Which is a combustion reaction and which is not?<\/p>\n<p>a) \u00a0P<sub class=\"subscript\">4<\/sub> +\u00a05 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 P<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">5<\/sub><\/p>\n<p>b) \u00a02 Al<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">3<\/sub> +\u00a09 O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 Al<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub> +\u00a06 SO<sub class=\"subscript\">2<\/sub><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p12\" class=\"para\">12. \u00a0Which is a combustion reaction and which is not?<\/p>\n<p>a) \u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub>O<sub class=\"subscript\">2<\/sub><\/p>\n<p>b) \u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub> +\u00a0Cl<sub class=\"subscript\">2<\/sub> \u2192\u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub>Cl<sub class=\"subscript\">2<\/sub><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p13\" class=\"para\">13. \u00a0Is it possible for a composition reaction to also be a combustion reaction? Give an example to support your case.<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p15\" class=\"para\">14. \u00a0Is it possible for a decomposition reaction to also be a combustion reaction? Give an example to support your case.<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch04_s04_qs01_p17\" class=\"para\">15. \u00a0Complete and balance each combustion equation.<\/p>\n<p>a) \u00a0C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">9<\/sub>OH +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0?<\/p>\n<p>b) \u00a0CH<sub class=\"subscript\">3<\/sub>NO<sub class=\"subscript\">2<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0?<\/p>\n<\/div>\n<p>16. \u00a0Complete and balance each combustion equation.<\/p>\n<p>a) \u00a0B<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">6<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0? (The oxide of boron formed is B<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>.)<\/p>\n<p>b) \u00a0Al<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">3<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0? (The oxide of sulfur formed is SO<sub class=\"subscript\">2<\/sub>.)<\/p>\n<p>c) \u00a0Al<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">3<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0? (The oxide of sulfur formed is SO<sub class=\"subscript\">3<\/sub>.)<\/p>\n<p><strong>Answers<\/strong><\/p>\n<div class=\"qandaset block\" id=\"ball-ch04_s04_qs01_ans\">\n<p><strong>1.<\/strong><\/p>\n<p>a) \u00a0not composition<\/p>\n<div class=\"answer\">\nb) \u00a0composition<\/p>\n<\/div>\n<p><strong>3.<\/strong><\/p>\n<p>a) \u00a0composition<\/p>\n<div class=\"answer\">\nb) \u00a0composition<\/p>\n<p><strong>5.<\/strong><\/p>\n<p>a) \u00a0not decomposition<\/p>\n<div class=\"answer\">\nb) \u00a0decomposition<\/p>\n<p><strong>7.<\/strong><\/p>\n<p>a) \u00a0not decomposition<\/p>\n<div class=\"answer\">\nb) \u00a0decomposition<\/p>\n<p><strong>9.<\/strong><\/p>\n<p>a) \u00a0combustion<\/p>\n<div class=\"answer\">\nb) \u00a0combustion<\/p>\n<p><strong>11.<\/strong><\/p>\n<p>a) \u00a0combustion<\/p>\n<div class=\"answer\">\nb) \u00a0combustion<\/p>\n<p><strong>13.<\/strong><\/p>\n<p>Yes; 2 H<sub class=\"subscript\">2<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O (answers will vary)<\/p>\n<p><strong>15.<\/strong><\/p>\n<p>a) \u00a0C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">9<\/sub>OH +\u00a06 O<sub class=\"subscript\">2<\/sub> \u2192\u00a04 CO<sub class=\"subscript\">2<\/sub> +\u00a05 H<sub class=\"subscript\">2<\/sub>O<\/p>\n<div class=\"answer\">\nb) \u00a04 CH<sub class=\"subscript\">3<\/sub>NO<sub class=\"subscript\">2<\/sub> +\u00a03 O<sub class=\"subscript\">2<\/sub> \u2192\u00a04 CO<sub class=\"subscript\">2<\/sub> +\u00a06 H<sub class=\"subscript\">2<\/sub>O +\u00a02 N<sub class=\"subscript\">2<\/sub><\/div>\n<p>\u00a0<\/p>\n<\/div>\n<div class=\"para\">\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-125\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Introductory Chemistry- 1st Canadian Edition . <strong>Authored by<\/strong>: Jessie A. Key and David W. Ball. <strong>Provided by<\/strong>: BCCampus. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/opentextbc.ca\/introductorychemistry\/\">https:\/\/opentextbc.ca\/introductorychemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em>. <strong>License Terms<\/strong>: Download this book for free at http:\/\/open.bccampus.ca<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":23485,"menu_order":5,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Introductory Chemistry- 1st Canadian Edition \",\"author\":\"Jessie A. Key and David W. 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