{"id":154,"date":"2017-12-14T21:27:23","date_gmt":"2017-12-14T21:27:23","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-mcc-introductorychemistry\/chapter\/the-mole\/"},"modified":"2017-12-14T21:27:23","modified_gmt":"2017-12-14T21:27:23","slug":"the-mole","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/chapter\/the-mole\/","title":{"raw":"The Mole","rendered":"The Mole"},"content":{"raw":"<div class=\"section\" id=\"ball-ch05_s02\" lang=\"en\">\n<div class=\"learning_objectives editable block\" id=\"ball-ch05_s02_n01\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<ol id=\"ball-ch05_s02_l01\"><li>Describe the unit <em>mole<\/em>.<\/li>\n\t<li>Relate the mole quantity of substance to its mass.<\/li>\n<\/ol><\/div>\n<\/div>\n<p id=\"ball-ch05_s02_p01\" class=\"para editable block\">So far, we have been talking about chemical substances in terms of individual atoms and molecules. Yet we don\u2019t typically deal with substances an atom or a molecule at a time; we work with millions, billions, and trillions of atoms and molecules at a time. What we need is a way to deal with macroscopic, rather than microscopic, amounts of matter. We need a unit of amount that relates quantities of substances on a scale that we can interact with.<\/p>\n<p id=\"ball-ch05_s02_p02\" class=\"para block\">Chemistry uses a unit called mole. A <span class=\"margin_term\"><a class=\"glossterm\">mole<\/a><\/span>\u00a0(mol) is a number of things equal to the number of atoms in exactly 12 g of carbon-12. Experimental measurements have determined that this number is very large:<\/p>\n<span class=\"informalequation block\"><span class=\"mathphrase\">1 mol = 6.02214179 \u00d7 10<sup class=\"superscript\">23<\/sup> things<\/span><\/span>\n<p id=\"ball-ch05_s02_p03\" class=\"para editable block\">Understand that a mole means a number of things, just like a dozen means a certain number of things\u2014twelve, in the case of a dozen. But a mole is a much larger number of things. These things can be atoms, or molecules, or eggs; however, in chemistry, we usually use the mole to refer to the amounts of atoms or molecules. Although the number of things in a mole is known to eight decimal places, it is usually fine to use only two or three decimal places in calculations. The numerical value of things in a mole is often called <em class=\"emphasis\">Avogadro\u2019s number<\/em> (<em class=\"emphasis\">N<\/em><sub class=\"subscript\">A<\/sub>), which is also known as the <em class=\"emphasis\">Avogadro constant<\/em>, after Amadeo Avogadro, an Italian chemist who first proposed its importance.<\/p>\n\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 3<\/h3>\n<p id=\"ball-ch05_s02_p04\" class=\"para\">How many molecules are present in 2.76 mol of H<sub class=\"subscript\">2<\/sub>O? How many atoms is this?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch05_s02_p05\" class=\"para\">The definition of a mole is an equality that can be used to construct a conversion factor. Also, because we know that there are three atoms in each molecule of H<sub class=\"subscript\">2<\/sub>O, we can also determine the number of atoms in the sample.<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/ss3.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212712\/ss3-1.png\" alt=\"ss3\" width=\"598\" height=\"80\" class=\"aligncenter wp-image-3634 size-full\"\/><\/a><\/p>\n\u00a0\n<p id=\"ball-ch05_s02_p06\" class=\"para\">To determine the total number of atoms, we have<\/p>\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/ss4.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212714\/ss4-1.png\" alt=\"ss4\" width=\"503\" height=\"85\" class=\"aligncenter wp-image-3635 size-full\"\/><\/a>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch05_s02_p07\" class=\"para\">How many molecules are present in 4.61 \u00d7 10<sup class=\"superscript\">\u22122<\/sup> mol of O<sub class=\"subscript\">2<\/sub>?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch05_s02_p08\" class=\"para\">2.78 \u00d7 10<sup class=\"superscript\">22<\/sup> molecules<\/p>\n\n<\/div>\n<p id=\"ball-ch05_s02_p09\" class=\"para editable block\">How big is a mole? It is very large. Suppose you had a mole of dollar bills that need to be counted. If everyone on earth (about 6 billion people) counted one bill per second, it would take about 3.2 million years to count all the bills. A mole of sand would fill a cube about 32 km on a side. A mole of pennies stacked on top of each other would have about the same diameter as our galaxy, the Milky Way. A mole is a lot of things\u2014but atoms and molecules are very tiny. One mole of carbon atoms would make a cube that is 1.74 cm on a side, small enough to carry in your pocket.<\/p>\n<p id=\"ball-ch05_s02_p10\" class=\"para editable block\">Why is the mole unit so important? It represents the link between the microscopic and the macroscopic, especially in terms of mass. <em class=\"emphasis\">A mole of a substance has the same mass in grams as one unit (atom or molecules) has in atomic mass units<\/em>. The mole unit allows us to express amounts of atoms and molecules in visible amounts that we can understand.<\/p>\n<p id=\"ball-ch05_s02_p11\" class=\"para editable block\">For example, we already know that, by definition, a mole of carbon has a mass of exactly 12 g. This means that exactly 12 g of C has 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> atoms:<\/p>\n<span class=\"informalequation block\"><span class=\"mathphrase\">12 g C = 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> atoms C<\/span><\/span>\n<p id=\"ball-ch05_s02_p12\" class=\"para editable block\">We can use this equality as a conversion factor between the number of atoms of carbon and the number of grams of carbon. How many grams are there, say, in 1.50 \u00d7 10<sup class=\"superscript\">25<\/sup> atoms of carbon? This is a one-step conversion:<\/p>\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/Screen-Shot-2014-07-20-at-3.09.54-PM.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212716\/Screen-Shot-2014-07-20-at-3.09.54-PM-1.png\" alt=\"Screen Shot 2014-07-20 at 3.09.54 PM\" width=\"489\" height=\"77\" class=\"aligncenter wp-image-3636\"\/><\/a>\n<p id=\"ball-ch05_s02_p13\" class=\"para editable block\">But it also goes beyond carbon. Previously we defined atomic and molecular masses as the number of atomic mass units per atom or molecule. Now we can do so in terms of grams. The atomic mass of an element is the number of grams in 1 mol of atoms of that element, while the molecular mass of a compound is the number of grams in 1 mol of molecules of that compound. Sometimes these masses are called <span class=\"margin_term\"><a class=\"glossterm\">molar masses<\/a><\/span>\u00a0to emphasize the fact that they are the mass for 1 mol of things. (The term <em class=\"emphasis\">molar<\/em> is the adjective form of mole and has nothing to do with teeth.)<\/p>\n<p id=\"ball-ch05_s02_p14\" class=\"para editable block\">Here are some examples. The mass of a hydrogen atom is 1.0079 u; the mass of 1 mol of hydrogen atoms is 1.0079 g. Elemental hydrogen exists as a diatomic molecule, H<sub class=\"subscript\">2<\/sub>. One molecule has a mass of 1.0079 +\u00a01.0079 = 2.0158 u, while 1 mol H<sub class=\"subscript\">2<\/sub> has a mass of 2.0158 g. A molecule of H<sub class=\"subscript\">2<\/sub>O has a mass of about 18.01 u; 1 mol H<sub class=\"subscript\">2<\/sub>O has a mass of 18.01 g. A single unit of NaCl has a mass of 58.45 u; NaCl has a molar mass of 58.45 g. In each of these moles of substances, there are 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> units: 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> atoms of H, 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> molecules of H<sub class=\"subscript\">2<\/sub> and H<sub class=\"subscript\">2<\/sub>O, 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> units of NaCl ions. These relationships give us plenty of opportunities to construct conversion factors for simple calculations.<\/p>\n\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 4<\/h3>\n<p id=\"ball-ch05_s02_p15\" class=\"para\">What is the molar mass of C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub>?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch05_s02_p16\" class=\"para\">To determine the molar mass, we simply add the atomic masses of the atoms in the molecular formula but express the total in grams per mole, not atomic mass units. The masses of the atoms can be taken from the periodic table or the list of elements in <a class=\"xref\" href=\"https:\/\/courses.lumenlearning.com\/suny-mcc-introductorychemistry\/back-matter\/appendix-periodic-table-of-the-elements\/\">Chapter 17 \"Appendix: Periodic Table of the Elements\"<\/a>:<\/p>\n\n<div class=\"informaltable\">\n<table cellpadding=\"0\" style=\"border-spacing: 0px;\"><tbody><tr><td>6 C = 6 \u00d7 12.011<\/td>\n<td>= 72.066<\/td>\n<\/tr><tr><td>12 H = 12 \u00d7 1.0079<\/td>\n<td>= 12.0948<\/td>\n<\/tr><tr><td>6 O = 6 \u00d7 15.999<\/td>\n<td>= 95.994<\/td>\n<\/tr><tr><td>TOTAL<\/td>\n<td>= 180.155 g\/mol<\/td>\n<\/tr><\/tbody><\/table><\/div>\n<p id=\"ball-ch05_s02_p17\" class=\"para\">Per convention, the unit <em class=\"emphasis\">grams per mole<\/em> is written as a fraction.<\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch05_s02_p18\" class=\"para\">What is the molar mass of AgNO<sub class=\"subscript\">3<\/sub>?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch05_s02_p19\" class=\"para\">169.87 g\/mol<\/p>\n\n<\/div>\n<p id=\"ball-ch05_s02_p20\" class=\"para editable block\">Knowing the molar mass of a substance, we can calculate the number of moles in a certain mass of a substance and vice versa, as these examples illustrate. The molar mass is used as the conversion factor.<\/p>\n\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 5<\/h3>\n<p id=\"ball-ch05_s02_p21\" class=\"para\">What is the mass of 3.56 mol of HgCl<sub class=\"subscript\">2<\/sub>? The molar mass of HgCl<sub class=\"subscript\">2<\/sub> is 271.49 g\/mol.<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch05_s02_p22\" class=\"para\">Use the molar mass as a conversion factor between moles and grams. Because we want to cancel the mole unit and introduce the gram unit, we can use the molar mass as given:<\/p>\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/ss5.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212719\/ss5-1.png\" alt=\"ss5\" width=\"402\" height=\"73\" class=\"alignnone wp-image-3637 size-full\"\/><\/a>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch05_s02_p23\" class=\"para\">What is the mass of 33.7 mol of H<sub class=\"subscript\">2<\/sub>O?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch05_s02_p24\" class=\"para\">607 g<\/p>\n\n<\/div>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 6<\/h3>\n<p id=\"ball-ch05_s02_p25\" class=\"para\">How many moles of H<sub class=\"subscript\">2<\/sub>O are present in 240.0 g of water (about the mass of a cup of water)?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch05_s02_p26\" class=\"para\">Use the molar mass of H<sub class=\"subscript\">2<\/sub>O as a conversion factor from mass to moles. The molar mass of water is (1.0079 +\u00a01.0079 +\u00a015.999) = 18.015 g\/mol. However, because we want to cancel the gram unit and introduce moles, we need to take the reciprocal of this quantity, or 1 mol\/18.015 g:<\/p>\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/ss6.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212720\/ss6-1.png\" alt=\"ss6\" width=\"400\" height=\"69\" class=\"alignnone wp-image-3638 size-full\"\/><\/a>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch05_s02_p27\" class=\"para\">How many moles are present in 35.6 g of H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> (molar mass = 98.08 g\/mol)?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch05_s02_p28\" class=\"para\">0.363 mol<\/p>\n\n<\/div>\n<p id=\"ball-ch05_s02_p29\" class=\"para editable block\">Other conversion factors can be combined with the definition of mole\u2014density, for example.<\/p>\n\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 7<\/h3>\n<p id=\"ball-ch05_s02_p30\" class=\"para\">The density of ethanol is 0.789 g\/mL. How many moles are in 100.0 mL of ethanol? The molar mass of ethanol is 46.08 g\/mol.<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch05_s02_p31\" class=\"para\">Here, we use density to convert from volume to mass and then use the molar mass to determine the number of moles.<\/p>\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/ss7.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212722\/ss7-1.png\" alt=\"ss7\" width=\"475\" height=\"88\" class=\"alignnone wp-image-3639 size-full\"\/><\/a>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch05_s02_p32\" class=\"para\">If the density of benzene, C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">6<\/sub>, is 0.879 g\/mL, how many moles are present in 17.9 mL of benzene?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch05_s02_p33\" class=\"para\">0.201 mol<\/p>\n\n<\/div>\n<div class=\"key_takeaways editable block\" id=\"ball-ch05_s02_n07\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul id=\"ball-ch05_s02_l02\" class=\"itemizedlist\"><li>The mole is a key unit in chemistry.<\/li>\n\t<li>The molar mass of a substance, in grams, is numerically equal to one atom\u2019s or molecule\u2019s mass in atomic mass units.<\/li>\n<\/ul><\/div>\n\u00a0\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<div class=\"qandaset block\" id=\"ball-ch05_s02_qs01\">\n<ol id=\"ball-ch05_s02_qs01_qd01\" class=\"qandadiv\"><li id=\"ball-ch05_s02_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p1\" class=\"para\">How many atoms are present in 4.55 mol of Fe?<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch05_s02_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p3\" class=\"para\">How many atoms are present in 0.0665 mol of K?<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch05_s02_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p5\" class=\"para\">How many molecules are present in 2.509 mol of H<sub class=\"subscript\">2<\/sub>S?<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch05_s02_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p7\" class=\"para\">How many molecules are present in 0.336 mol of acetylene (C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">2<\/sub>)?<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch05_s02_qs01_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p9\" class=\"para\">How many moles are present in 3.55 \u00d7 10<sup class=\"superscript\">24<\/sup> Pb atoms?<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch05_s02_qs01_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p11\" class=\"para\">How many moles are present in 2.09 \u00d7 10<sup class=\"superscript\">22<\/sup> Ti atoms?<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch05_s02_qs01_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p13\" class=\"para\">How many moles are present in 1.00 \u00d7 10<sup class=\"superscript\">23<\/sup> PF<sub class=\"subscript\">3<\/sub> molecules?<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch05_s02_qs01_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p15\" class=\"para\">How many moles are present in 5.52 \u00d7 10<sup class=\"superscript\">25<\/sup> penicillin molecules?<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch05_s02_qs01_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p17\" class=\"para\">Determine the molar mass of each substance.<\/p>\n\n<\/div><\/li>\n<\/ol>\na) \u00a0Si\n\nb) \u00a0SiH<sub class=\"subscript\">4<\/sub>\n\nc) \u00a0K<sub class=\"subscript\">2<\/sub>O\n\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p18\" class=\"para\">10. \u00a0Determine the molar mass of each substance.<\/p>\na) \u00a0Cl<sub class=\"subscript\">2<\/sub>\n\nb) \u00a0SeCl<sub class=\"subscript\">2<\/sub>\n\nc) \u00a0Ca(C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">2<\/sub>)<sub class=\"subscript\">2<\/sub>\n\n11. \u00a0Determine the molar mass of each substance.\n\n<\/div>\na) \u00a0Al\n\nb) \u00a0Al<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>\n\nc) \u00a0CoCl<sub class=\"subscript\">3<\/sub>\n\n12. \u00a0Determine the molar mass of each substance.\n\na) \u00a0O<sub class=\"subscript\">3<\/sub>\n\nb) \u00a0NaI\n\nc) \u00a0C<sub class=\"subscript\">12<\/sub>H<sub class=\"subscript\">22<\/sub>O<sub class=\"subscript\">11<\/sub>\n\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p21\" class=\"para\">13. \u00a0What is the mass of 4.44 mol of Rb?<\/p>\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p23\" class=\"para\">14. \u00a0What is the mass of 0.311 mol of Xe?<\/p>\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p25\" class=\"para\">15. \u00a0What is the mass of 12.34 mol of Al<sub class=\"subscript\">2<\/sub>(SO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>?<\/p>\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p27\" class=\"para\">16. \u00a0What is the mass of 0.0656 mol of PbCl<sub class=\"subscript\">2<\/sub>?<\/p>\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p29\" class=\"para\">17. \u00a0How many moles are present in 45.6 g of CO?<\/p>\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p31\" class=\"para\">18. \u00a0How many moles are present in 0.00339 g of LiF?<\/p>\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p33\" class=\"para\">19. \u00a0How many moles are present in 1.223 g of SF<sub class=\"subscript\">6<\/sub>?<\/p>\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p35\" class=\"para\">20. \u00a0How many moles are present in 48.8 g of BaCO<sub class=\"subscript\">3<\/sub>?<\/p>\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p37\" class=\"para\">21. \u00a0How many moles are present in 54.8 mL of mercury if the density of mercury is 13.6 g\/mL?<\/p>\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p39\" class=\"para\">22. \u00a0How many moles are present in 56.83 mL of O<sub class=\"subscript\">2<\/sub> if the density of O<sub class=\"subscript\">2<\/sub> is 0.00133 g\/mL?<\/p>\n\n<\/div>\n<\/div>\n<b>Answers<\/b>\n<div class=\"answer\"><strong>1.\n<\/strong>\n2.74 \u00d7 10<sup class=\"superscript\">24<\/sup> atoms<\/div>\n<div class=\"answer\">\n<div class=\"answer\"><strong><strong>3. \u00a0<\/strong><\/strong>1.511 \u00d7 10<sup class=\"superscript\">24<\/sup> molecules<\/div>\n<div class=\"answer\"><strong><strong>5. \u00a0<\/strong><\/strong>90 mol<\/div>\n<div class=\"answer\"><strong><strong>\n7. \u00a0<\/strong><\/strong>0.166 mol<\/div>\n<div class=\"answer\">\n\n<strong>9.<\/strong>\n\na) \u00a028.086 g\n\nb) \u00a032.118 g\n\nc) \u00a094.195 g\n\n<\/div>\n<div class=\"answer\">\n\n<strong>11.<\/strong>\n\na) \u00a026.981 g\n\nb) \u00a0101.959 g\n\nc) \u00a0165.292 g\n\n<\/div>\n<div class=\"answer\"><strong><strong><strong><strong>13. \u00a0<\/strong><\/strong><\/strong><\/strong>379 g<\/div>\n<div class=\"answer\">\n<div class=\"answer\"><strong><strong><strong><strong>15. \u00a0<\/strong><\/strong><\/strong><\/strong>4,222 g<\/div>\n<div class=\"answer\">\n<div class=\"answer\"><strong><strong><strong><strong>17. \u00a0<\/strong><\/strong><\/strong><\/strong>1.63 mol<\/div>\n<div class=\"answer\">\n<div class=\"answer\"><strong><strong><strong><strong>19. \u00a0<\/strong><\/strong><\/strong><\/strong>0.008374 mol<\/div>\n<div class=\"answer\">\n<div class=\"answer\"><strong><strong><strong><strong>21. \u00a0<\/strong><\/strong><\/strong><\/strong>3.72 mol<\/div>\n<\/div>\n<\/div>\n<\/div><\/div><\/div><\/div><\/div><\/div>","rendered":"<div class=\"section\" id=\"ball-ch05_s02\" lang=\"en\">\n<div class=\"learning_objectives editable block\" id=\"ball-ch05_s02_n01\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<ol id=\"ball-ch05_s02_l01\">\n<li>Describe the unit <em>mole<\/em>.<\/li>\n<li>Relate the mole quantity of substance to its mass.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"ball-ch05_s02_p01\" class=\"para editable block\">So far, we have been talking about chemical substances in terms of individual atoms and molecules. Yet we don\u2019t typically deal with substances an atom or a molecule at a time; we work with millions, billions, and trillions of atoms and molecules at a time. What we need is a way to deal with macroscopic, rather than microscopic, amounts of matter. We need a unit of amount that relates quantities of substances on a scale that we can interact with.<\/p>\n<p id=\"ball-ch05_s02_p02\" class=\"para block\">Chemistry uses a unit called mole. A <span class=\"margin_term\"><a class=\"glossterm\">mole<\/a><\/span>\u00a0(mol) is a number of things equal to the number of atoms in exactly 12 g of carbon-12. Experimental measurements have determined that this number is very large:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">1 mol = 6.02214179 \u00d7 10<sup class=\"superscript\">23<\/sup> things<\/span><\/span><\/p>\n<p id=\"ball-ch05_s02_p03\" class=\"para editable block\">Understand that a mole means a number of things, just like a dozen means a certain number of things\u2014twelve, in the case of a dozen. But a mole is a much larger number of things. These things can be atoms, or molecules, or eggs; however, in chemistry, we usually use the mole to refer to the amounts of atoms or molecules. Although the number of things in a mole is known to eight decimal places, it is usually fine to use only two or three decimal places in calculations. The numerical value of things in a mole is often called <em class=\"emphasis\">Avogadro\u2019s number<\/em> (<em class=\"emphasis\">N<\/em><sub class=\"subscript\">A<\/sub>), which is also known as the <em class=\"emphasis\">Avogadro constant<\/em>, after Amadeo Avogadro, an Italian chemist who first proposed its importance.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 3<\/h3>\n<p id=\"ball-ch05_s02_p04\" class=\"para\">How many molecules are present in 2.76 mol of H<sub class=\"subscript\">2<\/sub>O? How many atoms is this?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch05_s02_p05\" class=\"para\">The definition of a mole is an equality that can be used to construct a conversion factor. Also, because we know that there are three atoms in each molecule of H<sub class=\"subscript\">2<\/sub>O, we can also determine the number of atoms in the sample.<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/ss3.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212712\/ss3-1.png\" alt=\"ss3\" width=\"598\" height=\"80\" class=\"aligncenter wp-image-3634 size-full\" \/><\/a><\/p>\n<p>\u00a0<\/p>\n<p id=\"ball-ch05_s02_p06\" class=\"para\">To determine the total number of atoms, we have<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/ss4.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212714\/ss4-1.png\" alt=\"ss4\" width=\"503\" height=\"85\" class=\"aligncenter wp-image-3635 size-full\" \/><\/a><\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch05_s02_p07\" class=\"para\">How many molecules are present in 4.61 \u00d7 10<sup class=\"superscript\">\u22122<\/sup> mol of O<sub class=\"subscript\">2<\/sub>?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch05_s02_p08\" class=\"para\">2.78 \u00d7 10<sup class=\"superscript\">22<\/sup> molecules<\/p>\n<\/div>\n<p id=\"ball-ch05_s02_p09\" class=\"para editable block\">How big is a mole? It is very large. Suppose you had a mole of dollar bills that need to be counted. If everyone on earth (about 6 billion people) counted one bill per second, it would take about 3.2 million years to count all the bills. A mole of sand would fill a cube about 32 km on a side. A mole of pennies stacked on top of each other would have about the same diameter as our galaxy, the Milky Way. A mole is a lot of things\u2014but atoms and molecules are very tiny. One mole of carbon atoms would make a cube that is 1.74 cm on a side, small enough to carry in your pocket.<\/p>\n<p id=\"ball-ch05_s02_p10\" class=\"para editable block\">Why is the mole unit so important? It represents the link between the microscopic and the macroscopic, especially in terms of mass. <em class=\"emphasis\">A mole of a substance has the same mass in grams as one unit (atom or molecules) has in atomic mass units<\/em>. The mole unit allows us to express amounts of atoms and molecules in visible amounts that we can understand.<\/p>\n<p id=\"ball-ch05_s02_p11\" class=\"para editable block\">For example, we already know that, by definition, a mole of carbon has a mass of exactly 12 g. This means that exactly 12 g of C has 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> atoms:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">12 g C = 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> atoms C<\/span><\/span><\/p>\n<p id=\"ball-ch05_s02_p12\" class=\"para editable block\">We can use this equality as a conversion factor between the number of atoms of carbon and the number of grams of carbon. How many grams are there, say, in 1.50 \u00d7 10<sup class=\"superscript\">25<\/sup> atoms of carbon? This is a one-step conversion:<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/Screen-Shot-2014-07-20-at-3.09.54-PM.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212716\/Screen-Shot-2014-07-20-at-3.09.54-PM-1.png\" alt=\"Screen Shot 2014-07-20 at 3.09.54 PM\" width=\"489\" height=\"77\" class=\"aligncenter wp-image-3636\" \/><\/a><\/p>\n<p id=\"ball-ch05_s02_p13\" class=\"para editable block\">But it also goes beyond carbon. Previously we defined atomic and molecular masses as the number of atomic mass units per atom or molecule. Now we can do so in terms of grams. The atomic mass of an element is the number of grams in 1 mol of atoms of that element, while the molecular mass of a compound is the number of grams in 1 mol of molecules of that compound. Sometimes these masses are called <span class=\"margin_term\"><a class=\"glossterm\">molar masses<\/a><\/span>\u00a0to emphasize the fact that they are the mass for 1 mol of things. (The term <em class=\"emphasis\">molar<\/em> is the adjective form of mole and has nothing to do with teeth.)<\/p>\n<p id=\"ball-ch05_s02_p14\" class=\"para editable block\">Here are some examples. The mass of a hydrogen atom is 1.0079 u; the mass of 1 mol of hydrogen atoms is 1.0079 g. Elemental hydrogen exists as a diatomic molecule, H<sub class=\"subscript\">2<\/sub>. One molecule has a mass of 1.0079 +\u00a01.0079 = 2.0158 u, while 1 mol H<sub class=\"subscript\">2<\/sub> has a mass of 2.0158 g. A molecule of H<sub class=\"subscript\">2<\/sub>O has a mass of about 18.01 u; 1 mol H<sub class=\"subscript\">2<\/sub>O has a mass of 18.01 g. A single unit of NaCl has a mass of 58.45 u; NaCl has a molar mass of 58.45 g. In each of these moles of substances, there are 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> units: 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> atoms of H, 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> molecules of H<sub class=\"subscript\">2<\/sub> and H<sub class=\"subscript\">2<\/sub>O, 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> units of NaCl ions. These relationships give us plenty of opportunities to construct conversion factors for simple calculations.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 4<\/h3>\n<p id=\"ball-ch05_s02_p15\" class=\"para\">What is the molar mass of C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub>?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch05_s02_p16\" class=\"para\">To determine the molar mass, we simply add the atomic masses of the atoms in the molecular formula but express the total in grams per mole, not atomic mass units. The masses of the atoms can be taken from the periodic table or the list of elements in <a class=\"xref\" href=\"https:\/\/courses.lumenlearning.com\/suny-mcc-introductorychemistry\/back-matter\/appendix-periodic-table-of-the-elements\/\">Chapter 17 &#8220;Appendix: Periodic Table of the Elements&#8221;<\/a>:<\/p>\n<div class=\"informaltable\">\n<table cellpadding=\"0\" style=\"border-spacing: 0px;\">\n<tbody>\n<tr>\n<td>6 C = 6 \u00d7 12.011<\/td>\n<td>= 72.066<\/td>\n<\/tr>\n<tr>\n<td>12 H = 12 \u00d7 1.0079<\/td>\n<td>= 12.0948<\/td>\n<\/tr>\n<tr>\n<td>6 O = 6 \u00d7 15.999<\/td>\n<td>= 95.994<\/td>\n<\/tr>\n<tr>\n<td>TOTAL<\/td>\n<td>= 180.155 g\/mol<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p id=\"ball-ch05_s02_p17\" class=\"para\">Per convention, the unit <em class=\"emphasis\">grams per mole<\/em> is written as a fraction.<\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch05_s02_p18\" class=\"para\">What is the molar mass of AgNO<sub class=\"subscript\">3<\/sub>?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch05_s02_p19\" class=\"para\">169.87 g\/mol<\/p>\n<\/div>\n<p id=\"ball-ch05_s02_p20\" class=\"para editable block\">Knowing the molar mass of a substance, we can calculate the number of moles in a certain mass of a substance and vice versa, as these examples illustrate. The molar mass is used as the conversion factor.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 5<\/h3>\n<p id=\"ball-ch05_s02_p21\" class=\"para\">What is the mass of 3.56 mol of HgCl<sub class=\"subscript\">2<\/sub>? The molar mass of HgCl<sub class=\"subscript\">2<\/sub> is 271.49 g\/mol.<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch05_s02_p22\" class=\"para\">Use the molar mass as a conversion factor between moles and grams. Because we want to cancel the mole unit and introduce the gram unit, we can use the molar mass as given:<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/ss5.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212719\/ss5-1.png\" alt=\"ss5\" width=\"402\" height=\"73\" class=\"alignnone wp-image-3637 size-full\" \/><\/a><\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch05_s02_p23\" class=\"para\">What is the mass of 33.7 mol of H<sub class=\"subscript\">2<\/sub>O?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch05_s02_p24\" class=\"para\">607 g<\/p>\n<\/div>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 6<\/h3>\n<p id=\"ball-ch05_s02_p25\" class=\"para\">How many moles of H<sub class=\"subscript\">2<\/sub>O are present in 240.0 g of water (about the mass of a cup of water)?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch05_s02_p26\" class=\"para\">Use the molar mass of H<sub class=\"subscript\">2<\/sub>O as a conversion factor from mass to moles. The molar mass of water is (1.0079 +\u00a01.0079 +\u00a015.999) = 18.015 g\/mol. However, because we want to cancel the gram unit and introduce moles, we need to take the reciprocal of this quantity, or 1 mol\/18.015 g:<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/ss6.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212720\/ss6-1.png\" alt=\"ss6\" width=\"400\" height=\"69\" class=\"alignnone wp-image-3638 size-full\" \/><\/a><\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch05_s02_p27\" class=\"para\">How many moles are present in 35.6 g of H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> (molar mass = 98.08 g\/mol)?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch05_s02_p28\" class=\"para\">0.363 mol<\/p>\n<\/div>\n<p id=\"ball-ch05_s02_p29\" class=\"para editable block\">Other conversion factors can be combined with the definition of mole\u2014density, for example.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 7<\/h3>\n<p id=\"ball-ch05_s02_p30\" class=\"para\">The density of ethanol is 0.789 g\/mL. How many moles are in 100.0 mL of ethanol? The molar mass of ethanol is 46.08 g\/mol.<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch05_s02_p31\" class=\"para\">Here, we use density to convert from volume to mass and then use the molar mass to determine the number of moles.<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/ss7.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14212722\/ss7-1.png\" alt=\"ss7\" width=\"475\" height=\"88\" class=\"alignnone wp-image-3639 size-full\" \/><\/a><\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch05_s02_p32\" class=\"para\">If the density of benzene, C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">6<\/sub>, is 0.879 g\/mL, how many moles are present in 17.9 mL of benzene?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch05_s02_p33\" class=\"para\">0.201 mol<\/p>\n<\/div>\n<div class=\"key_takeaways editable block\" id=\"ball-ch05_s02_n07\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul id=\"ball-ch05_s02_l02\" class=\"itemizedlist\">\n<li>The mole is a key unit in chemistry.<\/li>\n<li>The molar mass of a substance, in grams, is numerically equal to one atom\u2019s or molecule\u2019s mass in atomic mass units.<\/li>\n<\/ul>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<div class=\"qandaset block\" id=\"ball-ch05_s02_qs01\">\n<ol id=\"ball-ch05_s02_qs01_qd01\" class=\"qandadiv\">\n<li id=\"ball-ch05_s02_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p1\" class=\"para\">How many atoms are present in 4.55 mol of Fe?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch05_s02_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p3\" class=\"para\">How many atoms are present in 0.0665 mol of K?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch05_s02_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p5\" class=\"para\">How many molecules are present in 2.509 mol of H<sub class=\"subscript\">2<\/sub>S?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch05_s02_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p7\" class=\"para\">How many molecules are present in 0.336 mol of acetylene (C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">2<\/sub>)?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch05_s02_qs01_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p9\" class=\"para\">How many moles are present in 3.55 \u00d7 10<sup class=\"superscript\">24<\/sup> Pb atoms?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch05_s02_qs01_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p11\" class=\"para\">How many moles are present in 2.09 \u00d7 10<sup class=\"superscript\">22<\/sup> Ti atoms?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch05_s02_qs01_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p13\" class=\"para\">How many moles are present in 1.00 \u00d7 10<sup class=\"superscript\">23<\/sup> PF<sub class=\"subscript\">3<\/sub> molecules?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch05_s02_qs01_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p15\" class=\"para\">How many moles are present in 5.52 \u00d7 10<sup class=\"superscript\">25<\/sup> penicillin molecules?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch05_s02_qs01_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p17\" class=\"para\">Determine the molar mass of each substance.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<p>a) \u00a0Si<\/p>\n<p>b) \u00a0SiH<sub class=\"subscript\">4<\/sub><\/p>\n<p>c) \u00a0K<sub class=\"subscript\">2<\/sub>O<\/p>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p18\" class=\"para\">10. \u00a0Determine the molar mass of each substance.<\/p>\n<p>a) \u00a0Cl<sub class=\"subscript\">2<\/sub><\/p>\n<p>b) \u00a0SeCl<sub class=\"subscript\">2<\/sub><\/p>\n<p>c) \u00a0Ca(C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">2<\/sub>)<sub class=\"subscript\">2<\/sub><\/p>\n<p>11. \u00a0Determine the molar mass of each substance.<\/p>\n<\/div>\n<p>a) \u00a0Al<\/p>\n<p>b) \u00a0Al<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub><\/p>\n<p>c) \u00a0CoCl<sub class=\"subscript\">3<\/sub><\/p>\n<p>12. \u00a0Determine the molar mass of each substance.<\/p>\n<p>a) \u00a0O<sub class=\"subscript\">3<\/sub><\/p>\n<p>b) \u00a0NaI<\/p>\n<p>c) \u00a0C<sub class=\"subscript\">12<\/sub>H<sub class=\"subscript\">22<\/sub>O<sub class=\"subscript\">11<\/sub><\/p>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p21\" class=\"para\">13. \u00a0What is the mass of 4.44 mol of Rb?<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p23\" class=\"para\">14. \u00a0What is the mass of 0.311 mol of Xe?<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p25\" class=\"para\">15. \u00a0What is the mass of 12.34 mol of Al<sub class=\"subscript\">2<\/sub>(SO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>?<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p27\" class=\"para\">16. \u00a0What is the mass of 0.0656 mol of PbCl<sub class=\"subscript\">2<\/sub>?<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p29\" class=\"para\">17. \u00a0How many moles are present in 45.6 g of CO?<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p31\" class=\"para\">18. \u00a0How many moles are present in 0.00339 g of LiF?<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p33\" class=\"para\">19. \u00a0How many moles are present in 1.223 g of SF<sub class=\"subscript\">6<\/sub>?<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p35\" class=\"para\">20. \u00a0How many moles are present in 48.8 g of BaCO<sub class=\"subscript\">3<\/sub>?<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p37\" class=\"para\">21. \u00a0How many moles are present in 54.8 mL of mercury if the density of mercury is 13.6 g\/mL?<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch05_s02_qs01_p39\" class=\"para\">22. \u00a0How many moles are present in 56.83 mL of O<sub class=\"subscript\">2<\/sub> if the density of O<sub class=\"subscript\">2<\/sub> is 0.00133 g\/mL?<\/p>\n<\/div>\n<\/div>\n<p><b>Answers<\/b><\/p>\n<div class=\"answer\"><strong>1.<br \/>\n<\/strong><br \/>\n2.74 \u00d7 10<sup class=\"superscript\">24<\/sup> atoms<\/div>\n<div class=\"answer\">\n<div class=\"answer\"><strong><strong>3. \u00a0<\/strong><\/strong>1.511 \u00d7 10<sup class=\"superscript\">24<\/sup> molecules<\/div>\n<div class=\"answer\"><strong><strong>5. \u00a0<\/strong><\/strong>90 mol<\/div>\n<div class=\"answer\"><strong><strong><br \/>\n7. \u00a0<\/strong><\/strong>0.166 mol<\/div>\n<div class=\"answer\">\n<p><strong>9.<\/strong><\/p>\n<p>a) \u00a028.086 g<\/p>\n<p>b) \u00a032.118 g<\/p>\n<p>c) \u00a094.195 g<\/p>\n<\/div>\n<div class=\"answer\">\n<p><strong>11.<\/strong><\/p>\n<p>a) \u00a026.981 g<\/p>\n<p>b) \u00a0101.959 g<\/p>\n<p>c) \u00a0165.292 g<\/p>\n<\/div>\n<div class=\"answer\"><strong><strong><strong><strong>13. \u00a0<\/strong><\/strong><\/strong><\/strong>379 g<\/div>\n<div class=\"answer\">\n<div class=\"answer\"><strong><strong><strong><strong>15. \u00a0<\/strong><\/strong><\/strong><\/strong>4,222 g<\/div>\n<div class=\"answer\">\n<div class=\"answer\"><strong><strong><strong><strong>17. \u00a0<\/strong><\/strong><\/strong><\/strong>1.63 mol<\/div>\n<div class=\"answer\">\n<div class=\"answer\"><strong><strong><strong><strong>19. \u00a0<\/strong><\/strong><\/strong><\/strong>0.008374 mol<\/div>\n<div class=\"answer\">\n<div class=\"answer\"><strong><strong><strong><strong>21. \u00a0<\/strong><\/strong><\/strong><\/strong>3.72 mol<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-154\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Introductory Chemistry- 1st Canadian Edition . <strong>Authored by<\/strong>: Jessie A. Key and David W. Ball. <strong>Provided by<\/strong>: BCCampus. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/opentextbc.ca\/introductorychemistry\/\">https:\/\/opentextbc.ca\/introductorychemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em>. <strong>License Terms<\/strong>: Download this book for free at http:\/\/open.bccampus.ca<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":23485,"menu_order":3,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Introductory Chemistry- 1st Canadian Edition \",\"author\":\"Jessie A. Key and David W. Ball\",\"organization\":\"BCCampus\",\"url\":\"https:\/\/opentextbc.ca\/introductorychemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc-sa\",\"license_terms\":\"Download this book for free at http:\/\/open.bccampus.ca\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-154","chapter","type-chapter","status-publish","hentry"],"part":132,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters\/154","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/users\/23485"}],"version-history":[{"count":0,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters\/154\/revisions"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/parts\/132"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters\/154\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/media?parent=154"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=154"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/contributor?post=154"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/license?post=154"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}