{"id":294,"date":"2017-12-14T21:32:00","date_gmt":"2017-12-14T21:32:00","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-mcc-introductorychemistry\/chapter\/stoichiometry-calculations-using-enthalpy\/"},"modified":"2017-12-19T15:18:01","modified_gmt":"2017-12-19T15:18:01","slug":"stoichiometry-calculations-using-enthalpy","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/chapter\/stoichiometry-calculations-using-enthalpy\/","title":{"raw":"Stoichiometry Calculations Using Enthalpy","rendered":"Stoichiometry Calculations Using Enthalpy"},"content":{"raw":"<div id=\"ball-ch07_s04\" class=\"section\" lang=\"en\">\r\n<div id=\"ball-ch07_s04_n01\" class=\"learning_objectives editable block\">\r\n<div class=\"bcc-box bcc-highlight\">\r\n<h3>Learning Objective<\/h3>\r\n1. Perform stoichiometry calculations using energy changes from thermochemical equations.\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"ball-ch07_s04_p01\" class=\"para editable block\">In <a class=\"xref\" href=\"https:\/\/courses.lumenlearning.com\/suny-mcc-introductorychemistry\/chapter\/introduction-to-stoichiometry-and-the-mole\/\">Chapter 5 \"Stoichiometry and the Mole\"<\/a>, we related quantities of one substance to another in a chemical equation by performing calculations that used the balanced chemical equation; the balanced chemical equation provided equivalences that we used to construct conversion factors. For example, in the balanced chemical equation<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">2 H<sub class=\"subscript\">2<\/sub>(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span>\r\n<p id=\"ball-ch07_s04_p02\" class=\"para editable block\">we recognized the equivalences<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">2 mol H<sub class=\"subscript\">2<\/sub> \u21d4 1 mol O<sub class=\"subscript\">2<\/sub> \u21d4 2 mol H<sub class=\"subscript\">2<\/sub>O<\/span><\/span>\r\n<p id=\"ball-ch07_s04_p03\" class=\"para editable block\">where \u21d4 is the mathematical symbol for \u201cis equivalent to.\u201d In our thermochemical equation, however, we have another quantity\u2014energy change:<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">2H<sub class=\"subscript\">2<\/sub>(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02H<sub class=\"subscript\">2<\/sub>O(\u2113) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u2212570 kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_p04\" class=\"para editable block\">This new quantity allows us to add another equivalence to our list:<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">2 mol H<sub class=\"subscript\">2<\/sub> \u21d4 1 mol O<sub class=\"subscript\">2<\/sub> \u21d4 2 mol H<sub class=\"subscript\">2<\/sub>O \u21d4 \u2212570 kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_p05\" class=\"para editable block\">That is, we can now add an energy amount to the equivalences\u2014the enthalpy change of a balanced chemical reaction. This equivalence can also be used to construct conversion factors so that we can relate enthalpy change to amounts of substances reacted or produced.<\/p>\r\n<p id=\"ball-ch07_s04_p06\" class=\"para editable block\">Note that these equivalences address a concern. When an amount of energy is listed for a balanced chemical reaction, what amount(s) of reactants or products does it refer to? The answer is that relates to the number of moles of the substance as indicated by its coefficient in the balanced chemical reaction. Thus, 2 mol of H<sub class=\"subscript\">2<\/sub> are related to \u2212570 kJ, while 1 mol of O<sub class=\"subscript\">2<\/sub> is related to \u2212570 kJ. This is why the unit on the energy change is kJ, not kJ\/mol.<\/p>\r\n<p id=\"ball-ch07_s04_p07\" class=\"para editable block\">For example, consider the thermochemical equation<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">H<sub class=\"subscript\">2<\/sub>(g) +\u00a0Cl<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 HCl(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u2212184.6 kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_p08\" class=\"para editable block\">The equivalences for this thermochemical equation are<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">1 mol H<sub class=\"subscript\">2<\/sub> \u21d4 1 mol Cl<sub class=\"subscript\">2<\/sub> \u21d4 2 mol HCl \u21d4 \u2212184.6 kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_p09\" class=\"para editable block\">Suppose we asked how much energy is given off when 8.22 mol of H<sub class=\"subscript\">2<\/sub> react. We would construct a conversion factor between the number of moles of H<sub class=\"subscript\">2<\/sub> and the energy given off, \u2212184.6 kJ:<\/p>\r\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/Screen-Shot-2014-07-22-at-7.37.43-PM.png\"><img class=\"aligncenter wp-image-3836\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213152\/Screen-Shot-2014-07-22-at-7.37.43-PM-1.png\" alt=\"Screen Shot 2014-07-22 at 7.37.43 PM\" width=\"318\" height=\"72\" \/><\/a>\r\n<p id=\"ball-ch07_s04_p10\" class=\"para editable block\">The negative sign means that this much energy is given off.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 8<\/h3>\r\n<p id=\"ball-ch07_s04_p11\" class=\"para\">Given the thermochemical equation<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">N<sub class=\"subscript\">2<\/sub>(g) +\u00a03 H<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 NH<sub class=\"subscript\">3<\/sub>(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u221291.8 kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_p12\" class=\"para\">how much energy is given off when 222.4 g of N<sub class=\"subscript\">2<\/sub> reacts?<\/p>\r\n<p class=\"simpara\">Solution<\/p>\r\n<p id=\"ball-ch07_s04_p13\" class=\"para\">The balanced thermochemical equation relates the energy change to moles, not grams, so we first convert the amount of N<sub class=\"subscript\">2<\/sub> to moles and then use the thermochemical equation to determine the energy change:<\/p>\r\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/2224g.png\"><img class=\"aligncenter wp-image-3837\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213154\/2224g-1.png\" alt=\"2224g\" width=\"406\" height=\"81\" \/><\/a>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch07_s04_p14\" class=\"para\">Given the thermochemical equation<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">N<sub class=\"subscript\">2<\/sub>(g) +\u00a03 H<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 NH<sub class=\"subscript\">3<\/sub>(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u221291.8 kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_p15\" class=\"para\">how much heat is given off when 1.00 g of H<sub class=\"subscript\">2<\/sub> reacts?<\/p>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\r\n<p id=\"ball-ch07_s04_p16\" class=\"para\">\u221215.1 kJ<\/p>\r\n\r\n<\/div>\r\n<p id=\"ball-ch07_s04_p17\" class=\"para editable block\">Like any stoichiometric quantity, we can start with energy and determine an amount, rather than the other way around.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 9<\/h3>\r\n<p id=\"ball-ch07_s04_p18\" class=\"para\">Given the thermochemical equation<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">N<sub class=\"subscript\">2<\/sub>(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 NO(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0180.6 kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_p19\" class=\"para\">if 558 kJ of energy are supplied, what mass of NO can be made?<\/p>\r\n<p class=\"simpara\">Solution<\/p>\r\n<p id=\"ball-ch07_s04_p20\" class=\"para\">This time, we start with an amount of energy:<\/p>\r\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/558kj.png\"><img class=\"aligncenter wp-image-3838\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213156\/558kj-1.png\" alt=\"558kj\" width=\"377\" height=\"80\" \/><\/a>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch07_s04_p21\" class=\"para\">How many grams of N<sub class=\"subscript\">2<\/sub> will react if 100.0 kJ of energy are supplied?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">N<sub class=\"subscript\">2<\/sub>(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 NO(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0180.6 kJ<\/span><\/span>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\r\n<p id=\"ball-ch07_s04_p22\" class=\"para\">15.5 g<\/p>\r\n\r\n<\/div>\r\n<div id=\"ball-ch07_s04_n04\" class=\"callout block\">\r\n<h3 class=\"title\">Chemistry Is Everywhere: Welding with Chemical Reactions<\/h3>\r\n<p id=\"ball-ch07_s04_p23\" class=\"para\">One very energetic reaction is called the <em class=\"emphasis\">thermite reaction<\/em>. Its classic reactants are aluminum metal and iron(III) oxide; the reaction produces iron metal and aluminum oxide:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">2 Al(s) +\u00a0Fe<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>(s) \u2192\u00a0Al<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>(s) +\u00a02 Fe(s) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u2212850.2 kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_p24\" class=\"para\">When properly done, the reaction gives off so much energy that the iron product comes off as a <em class=\"emphasis\">liquid<\/em>. (Iron normally melts at 1,536\u00b0C.) If carefully directed, the liquid iron can fill spaces between two or more metal parts and, after it quickly cools, can weld the metal parts together.<\/p>\r\n<p id=\"ball-ch07_s04_p25\" class=\"para\">Thermite reactions are used for this purpose even today. For civilian purposes, they are used to reweld broken locomotive axles that cannot be easily removed for repair. They are used to weld railroad tracks together. Thermite reactions can also be used to separate thin pieces of metal if, for whatever reason, a torch doesn\u2019t work.<\/p>\r\n\r\n<div id=\"ball-ch07_s04_f01\" class=\"informalfigure large\">\r\n\r\n<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213159\/c3e366ad3cf23dc1de728bb0e30e1e04-1.jpg\" alt=\"image\" \/>\r\n<p class=\"para\">A small clay pot contains a thermite mixture. It is reacting at high temperature in the photo and will eventually produce molten metal to join the railroad tracks below it.<\/p>\r\n\r\n<div class=\"copyright\">\r\n<p class=\"para\">Source: Photo courtesy of Skatebiker, <a class=\"link\" href=\"http:\/\/commons.wikimedia.org\/wiki\/File:Velp-thermitewelding-1.jpg\" target=\"_blank\" rel=\"noopener\">http:\/\/commons.wikimedia.org\/wiki\/File:Velp-thermitewelding-1.jpg<\/a>.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"ball-ch07_s04_p26\" class=\"para\">Thermite reactions are also used for military purposes. Thermite mixtures are frequently used with additional components as incendiary devices\u2014devices that start fires. Thermite reactions are also useful in disabling enemy weapons: a piece of artillery doesn\u2019t work so well when it has a hole melted into its barrel because of a thermite reaction!<\/p>\r\n\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Key Takeaway<\/h3>\r\n<ul>\r\n \t<li>The energy change of a chemical reaction can be used in stoichiometry calculations.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Exercises<\/h3>\r\n<div id=\"ball-ch07_s04_qs01\" class=\"qandaset block\">\r\n<ol id=\"ball-ch07_s04_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p1\" class=\"para\">Write the equivalences that this balanced thermochemical equation implies.<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">PCl<sub class=\"subscript\">3<\/sub>(g) +\u00a0Cl<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a0PCl<sub class=\"subscript\">5<\/sub>(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u221287.9\u00a0kJ<\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p3\" class=\"para\">Write the equivalences that this balanced thermochemical equation implies.<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">2 SO<sub class=\"subscript\">3<\/sub>(g) \u2192\u00a02 SO<sub class=\"subscript\">2<\/sub>(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0197.9\u00a0kJ<\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p5\" class=\"para\">How many kilojoules are given off when 17.8 mol of CH<sub class=\"subscript\">4<\/sub>(g) react?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">CH<sub class=\"subscript\">4<\/sub>(g) +\u00a02 O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a0CO<sub class=\"subscript\">2<\/sub>(g) +\u00a02 H<sub class=\"subscript\">2<\/sub>O(\u2113) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u2212890.1\u00a0kJ<\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p7\" class=\"para\">How many kilojoules are absorbed when 0.772 mol of N<sub class=\"subscript\">2<\/sub>(g) reacts?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">N<sub class=\"subscript\">2<\/sub>(g) +\u00a02 NO(g) \u2192\u00a02 N<sub class=\"subscript\">2<\/sub>O(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a073.8 kJ<\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p9\" class=\"para\">How many kilojoules are absorbed when 23.09 mol of C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">6<\/sub>(\u2113) are formed?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">6 C(s) +\u00a03 H<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a0C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">6<\/sub>(\u2113) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a049.0\u00a0kJ<\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa06\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p11\" class=\"para\">How many kilojoules are given off when 8.32 mol of Mg react?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">2 Mg(s) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 MgO(s) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u22121,213 kJ<\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa07\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p13\" class=\"para\">Glucose is the main fuel metabolized in animal cells:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub> +\u00a06 O<sub class=\"subscript\">2<\/sub> \u2192\u00a06 CO<sub class=\"subscript\">2<\/sub> +\u00a06 H<sub class=\"subscript\">2<\/sub>O \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u22122,799\u00a0kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_qs01_p14\" class=\"para\">How much energy is given off when 100.0 g of C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub> react?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa08\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p16\" class=\"para\">Given the thermochemical equation<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">2 Al(s) +\u00a0Fe<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>(s) \u2192\u00a0Al<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>(s) +\u00a02 Fe(s) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u2212850.2\u00a0kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_qs01_p17\" class=\"para\">how much energy is given off when 288 g of Fe are produced?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa09\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p19\" class=\"para\">Given the thermochemical equation<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">2 CO<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 CO(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0566 kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_qs01_p20\" class=\"para\">how much energy is absorbed when 85.2 g of CO<sub class=\"subscript\">2<\/sub> are reacted?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa10\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p22\" class=\"para\">Given the thermochemical equation<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">2 Na<sup class=\"superscript\">+<\/sup>(aq) +\u00a0SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup>(aq) \u2192\u00a0Na<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>(s) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0819.8\u00a0kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_qs01_p23\" class=\"para\">how much energy is absorbed when 55.9 g of Na<sup class=\"superscript\">+<\/sup>(aq) are reacted?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa11\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p25\" class=\"para\">NaHCO<sub class=\"subscript\">3<\/sub> decomposes when exposed to heat:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">2 NaHCO<sub class=\"subscript\">3<\/sub>(s) \u2192\u00a0Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(s) +\u00a0CO<sub class=\"subscript\">2<\/sub>(g) +\u00a0H<sub class=\"subscript\">2<\/sub>O(\u2113) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a091.5\u00a0kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_qs01_p26\" class=\"para\">What mass of NaHCO<sub class=\"subscript\">3<\/sub> is decomposed by 256 kJ?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa12\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p28\" class=\"para\">HgO decomposes when exposed to heat:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">2 HgO(s) \u2192\u00a02 Hg(\u2113) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0181.6 kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_qs01_p29\" class=\"para\">What mass of O<sub class=\"subscript\">2<\/sub> can be made with 100.0 kJ?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa13\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p31\" class=\"para\">For the thermochemical equation<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Fe<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>(s) +\u00a03 SO<sub class=\"subscript\">3<\/sub>(g) \u2192\u00a0Fe<sub class=\"subscript\">2<\/sub>(SO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub> (s) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u2212570.2\u00a0kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_qs01_p32\" class=\"para\">what mass of SO<sub class=\"subscript\">3<\/sub> is needed to generate 1,566 kJ?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch07_s04_qs01_qd01_qa14\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch07_s04_qs01_p34\" class=\"para\">For the thermochemical equation<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">H<sub class=\"subscript\">2<\/sub>(g) +\u00a0Br<sub class=\"subscript\">2<\/sub>(\u2113) \u2192\u00a02 HBr(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u221272.6 kJ<\/span><\/span>\r\n<p id=\"ball-ch07_s04_qs01_p35\" class=\"para\">what mass of HBr will be formed when 553 kJ of energy are given off?<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<h4 class=\"title\">Answers<\/h4>\r\n<strong>1.<\/strong>\r\n\r\n1 mol of PCl<sub class=\"subscript\">3<\/sub> \u21d4 1 mol of Cl<sub class=\"subscript\">2<\/sub> \u21d4 1 mol of PCl<sub class=\"subscript\">5<\/sub> \u21d4\u00a0\u221287.9\u00a0kJ\r\n\r\n<strong>3.<\/strong>\r\n\r\n15,800 kJ\r\n\r\n<strong>5.<\/strong>\r\n\r\n1,130 kJ\r\n\r\n<strong>7.<\/strong>\r\n\r\n1,554 kJ\r\n\r\n<strong>9.<\/strong>\r\n\r\n548 kJ\r\n\r\n<strong>11.<\/strong>\r\n\r\n470 g\r\n\r\n<strong>13.<\/strong>\r\n\r\n6.60 \u00d7 10<sup class=\"superscript\">2<\/sup> g\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"ball-ch07_s04\" class=\"section\" lang=\"en\">\n<div id=\"ball-ch07_s04_n01\" class=\"learning_objectives editable block\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objective<\/h3>\n<p>1. Perform stoichiometry calculations using energy changes from thermochemical equations.<\/p>\n<\/div>\n<\/div>\n<p id=\"ball-ch07_s04_p01\" class=\"para editable block\">In <a class=\"xref\" href=\"https:\/\/courses.lumenlearning.com\/suny-mcc-introductorychemistry\/chapter\/introduction-to-stoichiometry-and-the-mole\/\">Chapter 5 &#8220;Stoichiometry and the Mole&#8221;<\/a>, we related quantities of one substance to another in a chemical equation by performing calculations that used the balanced chemical equation; the balanced chemical equation provided equivalences that we used to construct conversion factors. For example, in the balanced chemical equation<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">2 H<sub class=\"subscript\">2<\/sub>(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_p02\" class=\"para editable block\">we recognized the equivalences<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">2 mol H<sub class=\"subscript\">2<\/sub> \u21d4 1 mol O<sub class=\"subscript\">2<\/sub> \u21d4 2 mol H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_p03\" class=\"para editable block\">where \u21d4 is the mathematical symbol for \u201cis equivalent to.\u201d In our thermochemical equation, however, we have another quantity\u2014energy change:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">2H<sub class=\"subscript\">2<\/sub>(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02H<sub class=\"subscript\">2<\/sub>O(\u2113) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u2212570 kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_p04\" class=\"para editable block\">This new quantity allows us to add another equivalence to our list:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">2 mol H<sub class=\"subscript\">2<\/sub> \u21d4 1 mol O<sub class=\"subscript\">2<\/sub> \u21d4 2 mol H<sub class=\"subscript\">2<\/sub>O \u21d4 \u2212570 kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_p05\" class=\"para editable block\">That is, we can now add an energy amount to the equivalences\u2014the enthalpy change of a balanced chemical reaction. This equivalence can also be used to construct conversion factors so that we can relate enthalpy change to amounts of substances reacted or produced.<\/p>\n<p id=\"ball-ch07_s04_p06\" class=\"para editable block\">Note that these equivalences address a concern. When an amount of energy is listed for a balanced chemical reaction, what amount(s) of reactants or products does it refer to? The answer is that relates to the number of moles of the substance as indicated by its coefficient in the balanced chemical reaction. Thus, 2 mol of H<sub class=\"subscript\">2<\/sub> are related to \u2212570 kJ, while 1 mol of O<sub class=\"subscript\">2<\/sub> is related to \u2212570 kJ. This is why the unit on the energy change is kJ, not kJ\/mol.<\/p>\n<p id=\"ball-ch07_s04_p07\" class=\"para editable block\">For example, consider the thermochemical equation<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">H<sub class=\"subscript\">2<\/sub>(g) +\u00a0Cl<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 HCl(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u2212184.6 kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_p08\" class=\"para editable block\">The equivalences for this thermochemical equation are<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">1 mol H<sub class=\"subscript\">2<\/sub> \u21d4 1 mol Cl<sub class=\"subscript\">2<\/sub> \u21d4 2 mol HCl \u21d4 \u2212184.6 kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_p09\" class=\"para editable block\">Suppose we asked how much energy is given off when 8.22 mol of H<sub class=\"subscript\">2<\/sub> react. We would construct a conversion factor between the number of moles of H<sub class=\"subscript\">2<\/sub> and the energy given off, \u2212184.6 kJ:<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/Screen-Shot-2014-07-22-at-7.37.43-PM.png\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-3836\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213152\/Screen-Shot-2014-07-22-at-7.37.43-PM-1.png\" alt=\"Screen Shot 2014-07-22 at 7.37.43 PM\" width=\"318\" height=\"72\" \/><\/a><\/p>\n<p id=\"ball-ch07_s04_p10\" class=\"para editable block\">The negative sign means that this much energy is given off.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 8<\/h3>\n<p id=\"ball-ch07_s04_p11\" class=\"para\">Given the thermochemical equation<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">N<sub class=\"subscript\">2<\/sub>(g) +\u00a03 H<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 NH<sub class=\"subscript\">3<\/sub>(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u221291.8 kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_p12\" class=\"para\">how much energy is given off when 222.4 g of N<sub class=\"subscript\">2<\/sub> reacts?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch07_s04_p13\" class=\"para\">The balanced thermochemical equation relates the energy change to moles, not grams, so we first convert the amount of N<sub class=\"subscript\">2<\/sub> to moles and then use the thermochemical equation to determine the energy change:<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/2224g.png\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-3837\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213154\/2224g-1.png\" alt=\"2224g\" width=\"406\" height=\"81\" \/><\/a><\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch07_s04_p14\" class=\"para\">Given the thermochemical equation<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">N<sub class=\"subscript\">2<\/sub>(g) +\u00a03 H<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 NH<sub class=\"subscript\">3<\/sub>(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u221291.8 kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_p15\" class=\"para\">how much heat is given off when 1.00 g of H<sub class=\"subscript\">2<\/sub> reacts?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch07_s04_p16\" class=\"para\">\u221215.1 kJ<\/p>\n<\/div>\n<p id=\"ball-ch07_s04_p17\" class=\"para editable block\">Like any stoichiometric quantity, we can start with energy and determine an amount, rather than the other way around.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 9<\/h3>\n<p id=\"ball-ch07_s04_p18\" class=\"para\">Given the thermochemical equation<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">N<sub class=\"subscript\">2<\/sub>(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 NO(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0180.6 kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_p19\" class=\"para\">if 558 kJ of energy are supplied, what mass of NO can be made?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch07_s04_p20\" class=\"para\">This time, we start with an amount of energy:<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/558kj.png\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-3838\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213156\/558kj-1.png\" alt=\"558kj\" width=\"377\" height=\"80\" \/><\/a><\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch07_s04_p21\" class=\"para\">How many grams of N<sub class=\"subscript\">2<\/sub> will react if 100.0 kJ of energy are supplied?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">N<sub class=\"subscript\">2<\/sub>(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 NO(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0180.6 kJ<\/span><\/span><\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch07_s04_p22\" class=\"para\">15.5 g<\/p>\n<\/div>\n<div id=\"ball-ch07_s04_n04\" class=\"callout block\">\n<h3 class=\"title\">Chemistry Is Everywhere: Welding with Chemical Reactions<\/h3>\n<p id=\"ball-ch07_s04_p23\" class=\"para\">One very energetic reaction is called the <em class=\"emphasis\">thermite reaction<\/em>. Its classic reactants are aluminum metal and iron(III) oxide; the reaction produces iron metal and aluminum oxide:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">2 Al(s) +\u00a0Fe<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>(s) \u2192\u00a0Al<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>(s) +\u00a02 Fe(s) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u2212850.2 kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_p24\" class=\"para\">When properly done, the reaction gives off so much energy that the iron product comes off as a <em class=\"emphasis\">liquid<\/em>. (Iron normally melts at 1,536\u00b0C.) If carefully directed, the liquid iron can fill spaces between two or more metal parts and, after it quickly cools, can weld the metal parts together.<\/p>\n<p id=\"ball-ch07_s04_p25\" class=\"para\">Thermite reactions are used for this purpose even today. For civilian purposes, they are used to reweld broken locomotive axles that cannot be easily removed for repair. They are used to weld railroad tracks together. Thermite reactions can also be used to separate thin pieces of metal if, for whatever reason, a torch doesn\u2019t work.<\/p>\n<div id=\"ball-ch07_s04_f01\" class=\"informalfigure large\">\n<p><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213159\/c3e366ad3cf23dc1de728bb0e30e1e04-1.jpg\" alt=\"image\" \/><\/p>\n<p class=\"para\">A small clay pot contains a thermite mixture. It is reacting at high temperature in the photo and will eventually produce molten metal to join the railroad tracks below it.<\/p>\n<div class=\"copyright\">\n<p class=\"para\">Source: Photo courtesy of Skatebiker, <a class=\"link\" href=\"http:\/\/commons.wikimedia.org\/wiki\/File:Velp-thermitewelding-1.jpg\" target=\"_blank\" rel=\"noopener\">http:\/\/commons.wikimedia.org\/wiki\/File:Velp-thermitewelding-1.jpg<\/a>.<\/p>\n<\/div>\n<\/div>\n<p id=\"ball-ch07_s04_p26\" class=\"para\">Thermite reactions are also used for military purposes. Thermite mixtures are frequently used with additional components as incendiary devices\u2014devices that start fires. Thermite reactions are also useful in disabling enemy weapons: a piece of artillery doesn\u2019t work so well when it has a hole melted into its barrel because of a thermite reaction!<\/p>\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaway<\/h3>\n<ul>\n<li>The energy change of a chemical reaction can be used in stoichiometry calculations.<\/li>\n<\/ul>\n<\/div>\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<div id=\"ball-ch07_s04_qs01\" class=\"qandaset block\">\n<ol id=\"ball-ch07_s04_qs01_qd01\" class=\"qandadiv\">\n<li id=\"ball-ch07_s04_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p1\" class=\"para\">Write the equivalences that this balanced thermochemical equation implies.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">PCl<sub class=\"subscript\">3<\/sub>(g) +\u00a0Cl<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a0PCl<sub class=\"subscript\">5<\/sub>(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u221287.9\u00a0kJ<\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p3\" class=\"para\">Write the equivalences that this balanced thermochemical equation implies.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">2 SO<sub class=\"subscript\">3<\/sub>(g) \u2192\u00a02 SO<sub class=\"subscript\">2<\/sub>(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0197.9\u00a0kJ<\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p5\" class=\"para\">How many kilojoules are given off when 17.8 mol of CH<sub class=\"subscript\">4<\/sub>(g) react?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">CH<sub class=\"subscript\">4<\/sub>(g) +\u00a02 O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a0CO<sub class=\"subscript\">2<\/sub>(g) +\u00a02 H<sub class=\"subscript\">2<\/sub>O(\u2113) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u2212890.1\u00a0kJ<\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p7\" class=\"para\">How many kilojoules are absorbed when 0.772 mol of N<sub class=\"subscript\">2<\/sub>(g) reacts?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">N<sub class=\"subscript\">2<\/sub>(g) +\u00a02 NO(g) \u2192\u00a02 N<sub class=\"subscript\">2<\/sub>O(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a073.8 kJ<\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p9\" class=\"para\">How many kilojoules are absorbed when 23.09 mol of C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">6<\/sub>(\u2113) are formed?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">6 C(s) +\u00a03 H<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a0C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">6<\/sub>(\u2113) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a049.0\u00a0kJ<\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p11\" class=\"para\">How many kilojoules are given off when 8.32 mol of Mg react?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">2 Mg(s) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 MgO(s) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u22121,213 kJ<\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p13\" class=\"para\">Glucose is the main fuel metabolized in animal cells:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub> +\u00a06 O<sub class=\"subscript\">2<\/sub> \u2192\u00a06 CO<sub class=\"subscript\">2<\/sub> +\u00a06 H<sub class=\"subscript\">2<\/sub>O \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u22122,799\u00a0kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_qs01_p14\" class=\"para\">How much energy is given off when 100.0 g of C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub> react?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p16\" class=\"para\">Given the thermochemical equation<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">2 Al(s) +\u00a0Fe<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>(s) \u2192\u00a0Al<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>(s) +\u00a02 Fe(s) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u2212850.2\u00a0kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_qs01_p17\" class=\"para\">how much energy is given off when 288 g of Fe are produced?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p19\" class=\"para\">Given the thermochemical equation<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">2 CO<sub class=\"subscript\">2<\/sub>(g) \u2192\u00a02 CO(g) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0566 kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_qs01_p20\" class=\"para\">how much energy is absorbed when 85.2 g of CO<sub class=\"subscript\">2<\/sub> are reacted?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa10\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p22\" class=\"para\">Given the thermochemical equation<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">2 Na<sup class=\"superscript\">+<\/sup>(aq) +\u00a0SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup>(aq) \u2192\u00a0Na<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>(s) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0819.8\u00a0kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_qs01_p23\" class=\"para\">how much energy is absorbed when 55.9 g of Na<sup class=\"superscript\">+<\/sup>(aq) are reacted?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa11\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p25\" class=\"para\">NaHCO<sub class=\"subscript\">3<\/sub> decomposes when exposed to heat:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">2 NaHCO<sub class=\"subscript\">3<\/sub>(s) \u2192\u00a0Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(s) +\u00a0CO<sub class=\"subscript\">2<\/sub>(g) +\u00a0H<sub class=\"subscript\">2<\/sub>O(\u2113) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a091.5\u00a0kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_qs01_p26\" class=\"para\">What mass of NaHCO<sub class=\"subscript\">3<\/sub> is decomposed by 256 kJ?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa12\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p28\" class=\"para\">HgO decomposes when exposed to heat:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">2 HgO(s) \u2192\u00a02 Hg(\u2113) +\u00a0O<sub class=\"subscript\">2<\/sub>(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0181.6 kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_qs01_p29\" class=\"para\">What mass of O<sub class=\"subscript\">2<\/sub> can be made with 100.0 kJ?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa13\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p31\" class=\"para\">For the thermochemical equation<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Fe<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>(s) +\u00a03 SO<sub class=\"subscript\">3<\/sub>(g) \u2192\u00a0Fe<sub class=\"subscript\">2<\/sub>(SO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub> (s) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u2212570.2\u00a0kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_qs01_p32\" class=\"para\">what mass of SO<sub class=\"subscript\">3<\/sub> is needed to generate 1,566 kJ?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch07_s04_qs01_qd01_qa14\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch07_s04_qs01_p34\" class=\"para\">For the thermochemical equation<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">H<sub class=\"subscript\">2<\/sub>(g) +\u00a0Br<sub class=\"subscript\">2<\/sub>(\u2113) \u2192\u00a02 HBr(g) \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u221272.6 kJ<\/span><\/span><\/p>\n<p id=\"ball-ch07_s04_qs01_p35\" class=\"para\">what mass of HBr will be formed when 553 kJ of energy are given off?<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<h4 class=\"title\">Answers<\/h4>\n<p><strong>1.<\/strong><\/p>\n<p>1 mol of PCl<sub class=\"subscript\">3<\/sub> \u21d4 1 mol of Cl<sub class=\"subscript\">2<\/sub> \u21d4 1 mol of PCl<sub class=\"subscript\">5<\/sub> \u21d4\u00a0\u221287.9\u00a0kJ<\/p>\n<p><strong>3.<\/strong><\/p>\n<p>15,800 kJ<\/p>\n<p><strong>5.<\/strong><\/p>\n<p>1,130 kJ<\/p>\n<p><strong>7.<\/strong><\/p>\n<p>1,554 kJ<\/p>\n<p><strong>9.<\/strong><\/p>\n<p>548 kJ<\/p>\n<p><strong>11.<\/strong><\/p>\n<p>470 g<\/p>\n<p><strong>13.<\/strong><\/p>\n<p>6.60 \u00d7 10<sup class=\"superscript\">2<\/sup> g<\/p>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-294\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Introductory Chemistry- 1st Canadian Edition . <strong>Authored by<\/strong>: Jessie A. Key and David W. Ball. <strong>Provided by<\/strong>: BCCampus. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/opentextbc.ca\/introductorychemistry\/\">https:\/\/opentextbc.ca\/introductorychemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em>. <strong>License Terms<\/strong>: Download this book for free at http:\/\/open.bccampus.ca<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":23485,"menu_order":4,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Introductory Chemistry- 1st Canadian Edition \",\"author\":\"Jessie A. Key and David W. Ball\",\"organization\":\"BCCampus\",\"url\":\"https:\/\/opentextbc.ca\/introductorychemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc-sa\",\"license_terms\":\"Download this book for free at http:\/\/open.bccampus.ca\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-294","chapter","type-chapter","status-publish","hentry"],"part":275,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters\/294","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/users\/23485"}],"version-history":[{"count":1,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters\/294\/revisions"}],"predecessor-version":[{"id":995,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters\/294\/revisions\/995"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/parts\/275"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters\/294\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/media?parent=294"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=294"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/contributor?post=294"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/license?post=294"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}