{"id":436,"date":"2017-12-14T21:36:46","date_gmt":"2017-12-14T21:36:46","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-mcc-introductorychemistry\/chapter\/covalent-bonds\/"},"modified":"2017-12-14T21:36:46","modified_gmt":"2017-12-14T21:36:46","slug":"covalent-bonds","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/chapter\/covalent-bonds\/","title":{"raw":"Covalent Bonds","rendered":"Covalent Bonds"},"content":{"raw":"<div class=\"section\" id=\"ball-ch09_s03\" lang=\"en\">\n<div class=\"learning_objectives editable block\" id=\"ball-ch09_s03_n01\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<ol id=\"ball-ch09_s03_l01\"><li>Define <em>covalent bond<\/em>.<\/li>\n\t<li>Illustrate covalent bond formation with Lewis electron dot diagrams.<\/li>\n<\/ol><\/div>\n<\/div>\n<p id=\"ball-ch09_s03_p01\" class=\"para editable block\">Ionic bonding typically occurs when it is easy for one atom to lose one or more electrons and another atom to gain one or more electrons. However, some atoms won\u2019t give up or gain electrons easily. Yet they still participate in compound formation. How?<\/p>\n<p id=\"ball-ch09_s03_p02\" class=\"para editable block\">There is another mechanism for obtaining a complete valence shell: <em class=\"emphasis\">sharing<\/em> electrons. When electrons are shared between two atoms, they make a bond called a <span class=\"margin_term\"><a class=\"glossterm\">covalent bond<\/a><\/span>.<\/p>\n<p id=\"ball-ch09_s03_p03\" class=\"para editable block\">Let us illustrate a covalent bond by using H atoms, with the understanding that H atoms need only two electrons to fill the 1<em class=\"emphasis\">s<\/em> subshell. Each H atom starts with a single electron in its valence shell:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-H.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213516\/H-H-1.png\" alt=\"H-H\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4428\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p04\" class=\"para editable block\">The two H atoms can share their electrons:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-H-2.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213518\/H-H-2-1.png\" alt=\"H-H-2\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4429\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p05\" class=\"para editable block\">We can use circles to show that each H atom has two electrons around the nucleus, completely filling each atom\u2019s valence shell:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-H-3.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213520\/H-H-3-1.png\" alt=\"H-H-3\" width=\"400\" height=\"80\" class=\"alignnone wp-image-4430\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p06\" class=\"para editable block\">Because each H atom has a filled valence shell, this bond is stable, and we have made a diatomic hydrogen molecule. (This explains why hydrogen is one of the diatomic elements.) For simplicity\u2019s sake, it is not unusual to represent the covalent bond with a dash, instead of with two dots:<\/p>\n<span class=\"informalequation block\"><span class=\"mathphrase\">H\u2013H<\/span><\/span>\n<p id=\"ball-ch09_s03_p07\" class=\"para editable block\">Because two atoms are sharing one pair of electrons, this covalent bond is called a <span class=\"margin_term\"><a class=\"glossterm\">single bond<\/a><\/span>.<\/p>\n<p id=\"ball-ch09_s03_p08\" class=\"para editable block\">As another example, consider fluorine. F atoms have seven electrons in their valence shell:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-F.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213522\/F-F-1.png\" alt=\"F-F\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4431\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p09\" class=\"para editable block\">These two atoms can do the same thing that the H atoms did; they share their unpaired electrons to make a covalent bond.<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-F-2.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213524\/F-F-2-1.png\" alt=\"F-F-2\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4432\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p10\" class=\"para editable block\">Note that each F atom has a complete octet around it now:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-F-3.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213531\/F-F-3-1.png\" alt=\"F-F-3\" width=\"400\" height=\"80\" class=\"alignnone wp-image-4433\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p11\" class=\"para editable block\">We can also write this using a dash to represent the shared electron pair:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-F-4.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213533\/F-F-4-1.png\" alt=\"F-F-4\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4434\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p12\" class=\"para editable block\">There are two different types of electrons in the fluorine diatomic molecule. The <span class=\"margin_term\"><a class=\"glossterm\">bonding electron pair<\/a><\/span>\u00a0makes the covalent bond. Each F atom has three other pairs of electrons that do not participate in the bonding; they are called <span class=\"margin_term\"><a class=\"glossterm\">lone electron pairs<\/a><\/span>. Each F atom has one bonding pair and three lone pairs of electrons.<\/p>\n<p id=\"ball-ch09_s03_p13\" class=\"para editable block\">Covalent bonds can be made between different elements as well. One example is HF. Each atom starts out with an odd number of electrons in its valence shell:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-F.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213535\/H-F-1.png\" alt=\"H-F\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4437\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p14\" class=\"para editable block\">The two atoms can share their unpaired electrons to make a covalent bond:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-F-2.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213538\/H-F-2-1.png\" alt=\"H-F-2\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4438\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p15\" class=\"para editable block\">We note that the H atom has a full valence shell with two electrons, while the F atom has a complete octet of electrons.<\/p>\n\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 4<\/h3>\n<p id=\"ball-ch09_s03_p16\" class=\"para\">Use Lewis electron dot diagrams to illustrate the covalent bond formation in HBr.<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch09_s03_p17\" class=\"para\">HBr is very similar to HF, except that it has Br instead of F. The atoms are as follows:<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-Br.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213539\/H-Br-1.png\" alt=\"H-Br\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4439\"\/><\/a><\/p>\n\n<div class=\"informalfigure large\">\n<p id=\"ball-ch09_s03_p18\" class=\"para\">The two atoms can share their unpaired electron:<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-Br-2.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213541\/H-Br-2-1.png\" alt=\"H-Br-2\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4440\"\/><\/a><\/p>\n\n<div class=\"informalfigure large\">\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch09_s03_p19\" class=\"para\">Use Lewis electron dot diagrams to illustrate the covalent bond formation in Cl<sub class=\"subscript\">2<\/sub>.<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p class=\"simpara\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Cl-Cl.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213543\/Cl-Cl-1.png\" alt=\"Cl-Cl\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4441\"\/><\/a><\/p>\n\n<div class=\"informalfigure large\">\n<\/div>\n<p id=\"ball-ch09_s03_p20\" class=\"para editable block\">More than two atoms can participate in covalent bonding, although any given covalent bond will be between two atoms only. Consider H and O atoms:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-O.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213545\/H-O-1.png\" alt=\"H-O\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4443\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p21\" class=\"para editable block\">The H and O atoms can share an electron to form a covalent bond:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-O-2.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213546\/H-O-2-1.png\" alt=\"H-O-2\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4444\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p22\" class=\"para editable block\">The H atom has a complete valence shell. However, the O atom has only seven electrons around it, which is not a complete octet. We fix this by including a second H atom, whose single electron will make a second covalent bond with the O atom:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-O-3.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213548\/H-O-3-1.png\" alt=\"H-O-3\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4445\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p23\" class=\"para editable block\">(It does not matter on what side the second H atom is positioned.) Now the O atom has a complete octet around it, and each H atom has two electrons, filling its valence shell. This is how a water molecule, H<sub class=\"subscript\">2<\/sub>O, is made.<\/p>\n\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 5<\/h3>\n<p id=\"ball-ch09_s03_p24\" class=\"para\">Use a Lewis electron dot diagram to show the covalent bonding in NH<sub class=\"subscript\">3<\/sub>.<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch09_s03_p25\" class=\"para\">The N atom has the following Lewis electron dot diagram:<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/N.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213550\/N-1.png\" alt=\"N\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4446\"\/><\/a><\/p>\n\n<div class=\"informalfigure large\">\n<p id=\"ball-ch09_s03_p26\" class=\"para\">It has three unpaired electrons, each of which can make a covalent bond by sharing electrons with an H atom. The electron dot diagram of NH<sub class=\"subscript\">3<\/sub> is as follows:<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/N-H.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213552\/N-H-1.png\" alt=\"N-H\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4447\"\/><\/a><\/p>\n\n<div class=\"informalfigure large\">\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch09_s03_p27\" class=\"para\">Use a Lewis electron dot diagram to show the covalent bonding in PCl<sub class=\"subscript\">3<\/sub>.<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p class=\"simpara\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Cl-P.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213554\/Cl-P-1.png\" alt=\"Cl-P\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4448\"\/><\/a><\/p>\n\n<div class=\"informalfigure large\">\n<\/div>\n<p id=\"ball-ch09_s03_p28\" class=\"para editable block\">There is a simple set of steps for determining the Lewis electron dot diagram of a simple molecule. First, you must identify the central atom and the surrounding atoms. The <span class=\"margin_term\"><a class=\"glossterm\">central atom<\/a><\/span>\u00a0is the atom in the center of the molecule, while the <span class=\"margin_term\"><a class=\"glossterm\">surrounding atoms<\/a><\/span>\u00a0are the atoms making bonds to the central atom. The central atom is usually written first in the formula of the compound (H<sub class=\"subscript\">2<\/sub>O is the notable exception). After the central and surrounding atoms have been identified, follow these steps:<\/p>\n\n<ol id=\"ball-ch09_s03_l02\" class=\"orderedlist editable block\"><li>Count the total number of valence electrons. Add extra if the species has negative charges and remove some for every positive charge on the species.<\/li>\n\t<li>Write the central atom and surround it with the surrounding atoms.<\/li>\n\t<li>Put a pair of electrons between the central atom and each surrounding atom.<\/li>\n\t<li>Complete the octets around the surrounding atoms (except for H).<\/li>\n\t<li>Put the remaining electrons, if any, around the central atom.<\/li>\n\t<li>Check that every atom has a full valence shell.<\/li>\n<\/ol><p id=\"ball-ch09_s03_p29\" class=\"para editable block\">Let us try these steps to determine the electron dot diagram for BF<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup>. The B atom is the central atom, and the F atoms are the surrounding atoms. There is a negative sign on the species, so we have an extra electron to consider.<\/p>\n<p id=\"ball-ch09_s03_p30\" class=\"para editable block\">1. <strong class=\"emphasis bold\">Count the total number of valence electrons.<\/strong> B has 3, each F has 7, and there is one extra electron: 3 +\u00a07 +\u00a07 +\u00a07 +\u00a07 +\u00a01 = 32.<\/p>\n<p id=\"ball-ch09_s03_p31\" class=\"para editable block\">2. <strong class=\"emphasis bold\">Write the central atom surrounded by surrounding atoms.<\/strong><\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-B.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213556\/F-B-1.png\" alt=\"F-B\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4450\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p32\" class=\"para editable block\">3. <strong class=\"emphasis bold\">Put a pair of electrons between the central atom and each surrounding atom.<\/strong> This uses up eight electrons, so we have 32 \u2212 8 = 24 electrons left.<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-B-2.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213558\/F-B-2-1.png\" alt=\"F-B-2\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4451\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p33\" class=\"para editable block\">4. <strong class=\"emphasis bold\">Complete the octets around the surrounding atoms (except for H).<\/strong> This uses up 24 more electrons, leaving 24 \u2212 24 = 0 electrons left.<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-B-3.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213601\/F-B-3-1.png\" alt=\"F-B-3\" width=\"400\" height=\"80\" class=\"alignnone wp-image-4452\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p34\" class=\"para editable block\">5. <strong class=\"emphasis bold\">Put the remaining electrons, if any, around the central atom.<\/strong> There are no additional electrons to add to the central atom.<\/p>\n<p id=\"ball-ch09_s03_p35\" class=\"para editable block\">6. <strong class=\"emphasis bold\">Check.<\/strong> The B atom has eight electrons around it, as does each F atom. Each atom has a complete octet. This is a good Lewis electron dot diagram for BF<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup>.<\/p>\n<p id=\"ball-ch09_s03_p36\" class=\"para editable block\">Sometimes, however, these steps don\u2019t work. If we were to follow these steps for the compound formaldehyde (CH<sub class=\"subscript\">2<\/sub>O), we would get the following:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H-O.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213603\/C-H-O-1.png\" alt=\"C-H-O\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4453\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p37\" class=\"para editable block\">The H and O atoms have the proper number of electrons, but the C atom has only six electrons around it, not the eight electrons for an octet. How do we fix this?<\/p>\n<p id=\"ball-ch09_s03_p38\" class=\"para editable block\">We fix this by recognizing that two atoms can share more than one pair of electrons. In the case of CH<sub class=\"subscript\">2<\/sub>O, the O and C atoms share two pairs of electrons, with the following Lewis electron dot diagram as a result:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H-O-2.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213605\/C-H-O-2-1.png\" alt=\"C-H-O-2\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4454\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p39\" class=\"para editable block\">By circling the electrons around each atom, we can now see that the O and C atoms have octets, while each H atom has two electrons:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H-O-3.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213607\/C-H-O-3-1.png\" alt=\"C-H-O-3\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4455\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p40\" class=\"para editable block\">Each valence shell is full, so this is an acceptable Lewis electron dot diagram. If we were to use lines to represent the bonds, we would use two lines between the C and O atoms:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H-O-4.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213609\/C-H-O-4-1.png\" alt=\"C-H-O-4\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4456\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p41\" class=\"para editable block\">The bond between the C and O atoms is a <span class=\"margin_term\"><a class=\"glossterm\">double bond<\/a><\/span>\u00a0and represents two bonding pairs of electrons between the atoms. If using the rules for drawing Lewis electron dot diagrams don\u2019t work as written, a double bond may be required.<\/p>\n\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 6<\/h3>\n<p id=\"ball-ch09_s03_p42\" class=\"para\">What is the proper Lewis electron dot diagram for CO<sub class=\"subscript\">2<\/sub>?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch09_s03_p43\" class=\"para\">The central atom is a C atom, with O atoms as surrounding atoms. We have a total of 4 +\u00a06 +\u00a06 = 16 valence electrons. Following the rules for Lewis electron dot diagrams for compounds gives us<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-O.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213611\/C-O-1.png\" alt=\"C-O\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4457\"\/><\/a><\/p>\n\n<div class=\"informalfigure large\">\n<p id=\"ball-ch09_s03_p44\" class=\"para\">The O atoms have complete octets around them, but the C atom has only four electrons around it. The way to solve this dilemma is to make a double bond between carbon and <em class=\"emphasis\">each<\/em> O atom:<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-O-2.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213613\/C-O-2-1.png\" alt=\"C-O-2\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4458\"\/><\/a><\/p>\n\n<div class=\"informalfigure large\">\n<p id=\"ball-ch09_s03_p45\" class=\"para\">Each O atom still has eight electrons around it, but now the C atom also has a complete octet. This is an acceptable Lewis electron dot diagram for CO<sub class=\"subscript\">2<\/sub>.<\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch09_s03_p46\" class=\"para\">What is the proper Lewis electron dot diagram for carbonyl sulfide (COS)?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p class=\"simpara\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-S-O.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213615\/C-S-O-1.png\" alt=\"C-S-O\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4459\"\/><\/a><\/p>\n\n<div class=\"informalfigure large\">\n<\/div>\n<p id=\"ball-ch09_s03_p47\" class=\"para editable block\">It is also possible to have a <span class=\"margin_term\"><a class=\"glossterm\">triple bond<\/a><\/span>, in which there are three pairs of electrons between two atoms. Good examples of this are elemental nitrogen (N<sub class=\"subscript\">2<\/sub>) and acetylene (C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">2<\/sub>):<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Triple-Bond.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213617\/Triple-Bond-1.png\" alt=\"Triple-Bond\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4460\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p48\" class=\"para editable block\">Acetylene is an interesting example of a molecule with two central atoms, which are both C atoms.<\/p>\n<p id=\"ball-ch09_s03_p49\" class=\"para editable block\">Polyatomic ions are bonded together with covalent bonds. Because they are ions, however, they participate in ionic bonding with other ions. So both major types of bonding can occur at the same time.<\/p>\n\n<div class=\"callout block\" id=\"ball-ch09_s03_n05\">\n<h3 class=\"title\">Food and Drink App: Vitamins and Minerals<\/h3>\n<p id=\"ball-ch09_s03_p50\" class=\"para\">Vitamins are nutrients that our bodies need in small amounts but cannot synthesize; therefore, they must be obtained from the diet. The word <em class=\"emphasis\">vitamin<\/em> comes from \u201cvital amine\u201d because it was once thought that all these compounds had an amine group (NH<sub class=\"subscript\">2<\/sub>) in it. This is not actually true, but the name stuck anyway.<\/p>\n<p id=\"ball-ch09_s03_p51\" class=\"para\">All vitamins are covalently bonded molecules. Most of them are commonly named with a letter, although all of them also have formal chemical names. Thus vitamin A is also called retinol, vitamin C is called ascorbic acid, and vitamin E is called tocopherol. There is no single vitamin B; there is a group of substances called the <em class=\"emphasis\">B complex vitamins<\/em> that are all water soluble and participate in cell metabolism. If a diet is lacking in a vitamin, diseases such as scurvy or rickets develop. Luckily, all vitamins are available as supplements, so any dietary deficiency in a vitamin can be easily corrected.<\/p>\n<p id=\"ball-ch09_s03_p52\" class=\"para\">A mineral is any chemical element other than carbon, hydrogen, oxygen, or nitrogen that is needed by the body. Minerals that the body needs in quantity include sodium, potassium, magnesium, calcium, phosphorus, sulfur, and chlorine. Essential minerals that the body needs in tiny quantities (so-called <em class=\"emphasis\">trace elements<\/em>) include manganese, iron, cobalt, nickel, copper, zinc, molybdenum, selenium, and iodine. Minerals are also obtained from the diet. Interestingly, most minerals are consumed in ionic form, rather than as elements or from covalent molecules. Like vitamins, most minerals are available in pill form, so any deficiency can be compensated for by taking supplements.<\/p>\n<p class=\"para\">Figure 9.2 Vitamin and Mineral Supplements<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Nutrition-Facts.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213624\/Nutrition-Facts-1.png\" alt=\"Nutrition-Facts\" width=\"400\" height=\"811\" class=\"alignnone wp-image-4461\"\/><\/a><\/p>\n\n<div class=\"informalfigure medium\" id=\"ball-ch09_s03_f01\">\n<p class=\"para\">Every entry down through pantothenic acid is a vitamin, and everything from calcium and below is a mineral.<\/p>\n\n<\/div>\n<\/div>\n<div class=\"key_takeaways editable block\" id=\"ball-ch09_s03_n06\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul id=\"ball-ch09_s03_l04\" class=\"itemizedlist\"><li>Covalent bonds are formed when atoms share electrons.<\/li>\n\t<li>Lewis electron dot diagrams can be drawn to illustrate covalent bond formation.<\/li>\n\t<li>Double bonds or triple bonds between atoms may be necessary to properly represent the bonding in some molecules.<\/li>\n<\/ul><\/div>\n<\/div>\n<div class=\"qandaset block\" id=\"ball-ch09_s03_qs01\">\n<div class=\"bcc-box bcc-info\" style=\"padding-left: 30px\">\n<h3>Exercises<\/h3>\n<ol id=\"ball-ch09_s03_qs01_qd01\" class=\"qandadiv\"><li id=\"ball-ch09_s03_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p01\" class=\"para\">How many electrons will be in the valence shell of H atoms when it makes a covalent bond?<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch09_s03_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p03\" class=\"para\">How many electrons will be in the valence shell of non-H atoms when they make covalent bonds?<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch09_s03_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p05\" class=\"para\">What is the Lewis electron dot diagram of I<sub class=\"subscript\">2<\/sub>? Circle the electrons around each atom to verify that each valence shell is filled.<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch09_s03_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p06\" class=\"para\">What is the Lewis electron dot diagram of H<sub class=\"subscript\">2<\/sub>S? Circle the electrons around each atom to verify that each valence shell is filled.<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch09_s03_qs01_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p07\" class=\"para\">What is the Lewis electron dot diagram of NCl<sub class=\"subscript\">3<\/sub>? Circle the electrons around each atom to verify that each valence shell is filled.<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch09_s03_qs01_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p08\" class=\"para\">What is the Lewis electron dot diagram of SiF<sub class=\"subscript\">4<\/sub>? Circle the electrons around each atom to verify that each valence shell is filled.<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch09_s03_qs01_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p09\" class=\"para\">Draw the Lewis electron dot diagram for each substance.<\/p>\n\n<\/div><\/li>\n<\/ol>\na) \u00a0SF<sub class=\"subscript\">2<\/sub>\n\nb) \u00a0BH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup>\n\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p10\" class=\"para\">8. \u00a0Draw the Lewis electron dot diagram for each substance.<\/p>\na) \u00a0PI<sub class=\"subscript\">3<\/sub>\n\nb) \u00a0OH<sup class=\"superscript\">\u2212<\/sup><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p11\" class=\"para\">9. \u00a0Draw the Lewis electron dot diagram for each substance.<\/p>\na) \u00a0GeH<sub class=\"subscript\">4<\/sub>\n\nb) \u00a0ClF\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p12\" class=\"para\">10. \u00a0Draw the Lewis electron dot diagram for each substance.<\/p>\na) \u00a0AsF<sub class=\"subscript\">3<\/sub>\n\nb) \u00a0NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p13\" class=\"para\">11. \u00a0Draw the Lewis electron dot diagram for each substance. Double or triple bonds may be needed.<\/p>\na) \u00a0SiO<sub class=\"subscript\">2<\/sub>\n\nb) \u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub> (assume two central atoms)\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p14\" class=\"para\">12. \u00a0Draw the Lewis electron dot diagram for each substance. Double or triple bonds may be needed.<\/p>\na) \u00a0CN<sup class=\"superscript\">\u2212<\/sup>\n\nb) \u00a0C<sub class=\"subscript\">2<\/sub>Cl<sub class=\"subscript\">2<\/sub> (assume two central atoms)\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p15\" class=\"para\">13. \u00a0Draw the Lewis electron dot diagram for each substance. Double or triple bonds may be needed.<\/p>\na) \u00a0CS<sub class=\"subscript\">2<\/sub>\n\nb) \u00a0NH<sub class=\"subscript\">2<\/sub>CONH<sub class=\"subscript\">2<\/sub> (assume that the N and C atoms are the central atoms)\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p16\" class=\"para\">14. \u00a0Draw the Lewis electron dot diagram for each substance. Double or triple bonds may be needed.<\/p>\na) \u00a0POCl\n\nb) \u00a0HCOOH (assume that the C atom and one O atom are the central atoms)\n\n<\/div>\n<b>Answers<\/b>\n<strong>1.<\/strong> two\n\n<strong>3.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/I-I.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213628\/I-I-1.png\" alt=\"I-I\" width=\"400\" height=\"98\" class=\"alignnone wp-image-4462\"\/><\/a><\/strong>\n\n<strong>5.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/N-Cl.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213630\/N-Cl-1.png\" alt=\"N-Cl\" width=\"400\" height=\"119\" class=\"alignnone wp-image-4463\"\/><\/a><\/strong>\n\n<strong>7.<\/strong>\n<p style=\"padding-left: 30px\">a) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/S-F.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213632\/S-F-1.png\" alt=\"S-F\" width=\"400\" height=\"119\" class=\"alignnone wp-image-4464\"\/><\/a><\/p>\n<p style=\"padding-left: 30px\">b) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-B.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213634\/H-B-1.png\" alt=\"H-B\" width=\"400\" height=\"162\" class=\"alignnone wp-image-4465\"\/><\/a><\/p>\n<strong>9.<\/strong>\n<p style=\"padding-left: 30px\">a) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-Ge.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213636\/H-Ge-1.png\" alt=\"H-Ge\" width=\"400\" height=\"162\" class=\"alignnone wp-image-4467\"\/><\/a><\/p>\n<p style=\"padding-left: 30px\">b) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Cl-F.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213637\/Cl-F-1.png\" alt=\"Cl-F\" width=\"400\" height=\"98\" class=\"alignnone wp-image-4468\"\/><\/a><\/p>\n<strong>11.<\/strong>\n<p style=\"padding-left: 30px\">a) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Si-O.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213639\/Si-O-1.png\" alt=\"Si-O\" width=\"400\" height=\"98\" class=\"alignnone wp-image-4469\"\/><\/a><\/p>\n<p style=\"padding-left: 30px\">b) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213641\/C-H-1.png\" alt=\"C-H\" width=\"400\" height=\"162\" class=\"alignnone wp-image-4470\"\/><\/a><\/p>\n<strong>13.<\/strong>\n<p style=\"padding-left: 30px\">a) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/S-C.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213643\/S-C-1.png\" alt=\"S-C\" width=\"400\" height=\"98\" class=\"alignnone wp-image-4471\"\/><\/a><\/p>\n<p style=\"padding-left: 30px\">b) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-N-H-O.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213645\/C-N-H-O-1.png\" alt=\"C-N-H-O\" width=\"400\" height=\"205\" class=\"alignnone wp-image-4472\"\/><\/a><\/p>\n\n<\/div>\n<\/div>\n<\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div>","rendered":"<div class=\"section\" id=\"ball-ch09_s03\" lang=\"en\">\n<div class=\"learning_objectives editable block\" id=\"ball-ch09_s03_n01\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<ol id=\"ball-ch09_s03_l01\">\n<li>Define <em>covalent bond<\/em>.<\/li>\n<li>Illustrate covalent bond formation with Lewis electron dot diagrams.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"ball-ch09_s03_p01\" class=\"para editable block\">Ionic bonding typically occurs when it is easy for one atom to lose one or more electrons and another atom to gain one or more electrons. However, some atoms won\u2019t give up or gain electrons easily. Yet they still participate in compound formation. How?<\/p>\n<p id=\"ball-ch09_s03_p02\" class=\"para editable block\">There is another mechanism for obtaining a complete valence shell: <em class=\"emphasis\">sharing<\/em> electrons. When electrons are shared between two atoms, they make a bond called a <span class=\"margin_term\"><a class=\"glossterm\">covalent bond<\/a><\/span>.<\/p>\n<p id=\"ball-ch09_s03_p03\" class=\"para editable block\">Let us illustrate a covalent bond by using H atoms, with the understanding that H atoms need only two electrons to fill the 1<em class=\"emphasis\">s<\/em> subshell. Each H atom starts with a single electron in its valence shell:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-H.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213516\/H-H-1.png\" alt=\"H-H\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4428\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p04\" class=\"para editable block\">The two H atoms can share their electrons:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-H-2.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213518\/H-H-2-1.png\" alt=\"H-H-2\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4429\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p05\" class=\"para editable block\">We can use circles to show that each H atom has two electrons around the nucleus, completely filling each atom\u2019s valence shell:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-H-3.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213520\/H-H-3-1.png\" alt=\"H-H-3\" width=\"400\" height=\"80\" class=\"alignnone wp-image-4430\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p06\" class=\"para editable block\">Because each H atom has a filled valence shell, this bond is stable, and we have made a diatomic hydrogen molecule. (This explains why hydrogen is one of the diatomic elements.) For simplicity\u2019s sake, it is not unusual to represent the covalent bond with a dash, instead of with two dots:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">H\u2013H<\/span><\/span><\/p>\n<p id=\"ball-ch09_s03_p07\" class=\"para editable block\">Because two atoms are sharing one pair of electrons, this covalent bond is called a <span class=\"margin_term\"><a class=\"glossterm\">single bond<\/a><\/span>.<\/p>\n<p id=\"ball-ch09_s03_p08\" class=\"para editable block\">As another example, consider fluorine. F atoms have seven electrons in their valence shell:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-F.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213522\/F-F-1.png\" alt=\"F-F\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4431\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p09\" class=\"para editable block\">These two atoms can do the same thing that the H atoms did; they share their unpaired electrons to make a covalent bond.<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-F-2.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213524\/F-F-2-1.png\" alt=\"F-F-2\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4432\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p10\" class=\"para editable block\">Note that each F atom has a complete octet around it now:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-F-3.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213531\/F-F-3-1.png\" alt=\"F-F-3\" width=\"400\" height=\"80\" class=\"alignnone wp-image-4433\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p11\" class=\"para editable block\">We can also write this using a dash to represent the shared electron pair:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-F-4.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213533\/F-F-4-1.png\" alt=\"F-F-4\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4434\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p12\" class=\"para editable block\">There are two different types of electrons in the fluorine diatomic molecule. The <span class=\"margin_term\"><a class=\"glossterm\">bonding electron pair<\/a><\/span>\u00a0makes the covalent bond. Each F atom has three other pairs of electrons that do not participate in the bonding; they are called <span class=\"margin_term\"><a class=\"glossterm\">lone electron pairs<\/a><\/span>. Each F atom has one bonding pair and three lone pairs of electrons.<\/p>\n<p id=\"ball-ch09_s03_p13\" class=\"para editable block\">Covalent bonds can be made between different elements as well. One example is HF. Each atom starts out with an odd number of electrons in its valence shell:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-F.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213535\/H-F-1.png\" alt=\"H-F\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4437\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p14\" class=\"para editable block\">The two atoms can share their unpaired electrons to make a covalent bond:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-F-2.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213538\/H-F-2-1.png\" alt=\"H-F-2\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4438\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p15\" class=\"para editable block\">We note that the H atom has a full valence shell with two electrons, while the F atom has a complete octet of electrons.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 4<\/h3>\n<p id=\"ball-ch09_s03_p16\" class=\"para\">Use Lewis electron dot diagrams to illustrate the covalent bond formation in HBr.<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch09_s03_p17\" class=\"para\">HBr is very similar to HF, except that it has Br instead of F. The atoms are as follows:<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-Br.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213539\/H-Br-1.png\" alt=\"H-Br\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4439\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<p id=\"ball-ch09_s03_p18\" class=\"para\">The two atoms can share their unpaired electron:<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-Br-2.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213541\/H-Br-2-1.png\" alt=\"H-Br-2\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4440\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch09_s03_p19\" class=\"para\">Use Lewis electron dot diagrams to illustrate the covalent bond formation in Cl<sub class=\"subscript\">2<\/sub>.<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p class=\"simpara\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Cl-Cl.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213543\/Cl-Cl-1.png\" alt=\"Cl-Cl\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4441\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<\/div>\n<p id=\"ball-ch09_s03_p20\" class=\"para editable block\">More than two atoms can participate in covalent bonding, although any given covalent bond will be between two atoms only. Consider H and O atoms:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-O.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213545\/H-O-1.png\" alt=\"H-O\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4443\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p21\" class=\"para editable block\">The H and O atoms can share an electron to form a covalent bond:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-O-2.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213546\/H-O-2-1.png\" alt=\"H-O-2\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4444\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p22\" class=\"para editable block\">The H atom has a complete valence shell. However, the O atom has only seven electrons around it, which is not a complete octet. We fix this by including a second H atom, whose single electron will make a second covalent bond with the O atom:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-O-3.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213548\/H-O-3-1.png\" alt=\"H-O-3\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4445\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p23\" class=\"para editable block\">(It does not matter on what side the second H atom is positioned.) Now the O atom has a complete octet around it, and each H atom has two electrons, filling its valence shell. This is how a water molecule, H<sub class=\"subscript\">2<\/sub>O, is made.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 5<\/h3>\n<p id=\"ball-ch09_s03_p24\" class=\"para\">Use a Lewis electron dot diagram to show the covalent bonding in NH<sub class=\"subscript\">3<\/sub>.<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch09_s03_p25\" class=\"para\">The N atom has the following Lewis electron dot diagram:<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/N.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213550\/N-1.png\" alt=\"N\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4446\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<p id=\"ball-ch09_s03_p26\" class=\"para\">It has three unpaired electrons, each of which can make a covalent bond by sharing electrons with an H atom. The electron dot diagram of NH<sub class=\"subscript\">3<\/sub> is as follows:<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/N-H.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213552\/N-H-1.png\" alt=\"N-H\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4447\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch09_s03_p27\" class=\"para\">Use a Lewis electron dot diagram to show the covalent bonding in PCl<sub class=\"subscript\">3<\/sub>.<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p class=\"simpara\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Cl-P.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213554\/Cl-P-1.png\" alt=\"Cl-P\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4448\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<\/div>\n<p id=\"ball-ch09_s03_p28\" class=\"para editable block\">There is a simple set of steps for determining the Lewis electron dot diagram of a simple molecule. First, you must identify the central atom and the surrounding atoms. The <span class=\"margin_term\"><a class=\"glossterm\">central atom<\/a><\/span>\u00a0is the atom in the center of the molecule, while the <span class=\"margin_term\"><a class=\"glossterm\">surrounding atoms<\/a><\/span>\u00a0are the atoms making bonds to the central atom. The central atom is usually written first in the formula of the compound (H<sub class=\"subscript\">2<\/sub>O is the notable exception). After the central and surrounding atoms have been identified, follow these steps:<\/p>\n<ol id=\"ball-ch09_s03_l02\" class=\"orderedlist editable block\">\n<li>Count the total number of valence electrons. Add extra if the species has negative charges and remove some for every positive charge on the species.<\/li>\n<li>Write the central atom and surround it with the surrounding atoms.<\/li>\n<li>Put a pair of electrons between the central atom and each surrounding atom.<\/li>\n<li>Complete the octets around the surrounding atoms (except for H).<\/li>\n<li>Put the remaining electrons, if any, around the central atom.<\/li>\n<li>Check that every atom has a full valence shell.<\/li>\n<\/ol>\n<p id=\"ball-ch09_s03_p29\" class=\"para editable block\">Let us try these steps to determine the electron dot diagram for BF<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup>. The B atom is the central atom, and the F atoms are the surrounding atoms. There is a negative sign on the species, so we have an extra electron to consider.<\/p>\n<p id=\"ball-ch09_s03_p30\" class=\"para editable block\">1. <strong class=\"emphasis bold\">Count the total number of valence electrons.<\/strong> B has 3, each F has 7, and there is one extra electron: 3 +\u00a07 +\u00a07 +\u00a07 +\u00a07 +\u00a01 = 32.<\/p>\n<p id=\"ball-ch09_s03_p31\" class=\"para editable block\">2. <strong class=\"emphasis bold\">Write the central atom surrounded by surrounding atoms.<\/strong><\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-B.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213556\/F-B-1.png\" alt=\"F-B\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4450\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p32\" class=\"para editable block\">3. <strong class=\"emphasis bold\">Put a pair of electrons between the central atom and each surrounding atom.<\/strong> This uses up eight electrons, so we have 32 \u2212 8 = 24 electrons left.<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-B-2.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213558\/F-B-2-1.png\" alt=\"F-B-2\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4451\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p33\" class=\"para editable block\">4. <strong class=\"emphasis bold\">Complete the octets around the surrounding atoms (except for H).<\/strong> This uses up 24 more electrons, leaving 24 \u2212 24 = 0 electrons left.<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/F-B-3.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213601\/F-B-3-1.png\" alt=\"F-B-3\" width=\"400\" height=\"80\" class=\"alignnone wp-image-4452\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p34\" class=\"para editable block\">5. <strong class=\"emphasis bold\">Put the remaining electrons, if any, around the central atom.<\/strong> There are no additional electrons to add to the central atom.<\/p>\n<p id=\"ball-ch09_s03_p35\" class=\"para editable block\">6. <strong class=\"emphasis bold\">Check.<\/strong> The B atom has eight electrons around it, as does each F atom. Each atom has a complete octet. This is a good Lewis electron dot diagram for BF<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup>.<\/p>\n<p id=\"ball-ch09_s03_p36\" class=\"para editable block\">Sometimes, however, these steps don\u2019t work. If we were to follow these steps for the compound formaldehyde (CH<sub class=\"subscript\">2<\/sub>O), we would get the following:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H-O.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213603\/C-H-O-1.png\" alt=\"C-H-O\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4453\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p37\" class=\"para editable block\">The H and O atoms have the proper number of electrons, but the C atom has only six electrons around it, not the eight electrons for an octet. How do we fix this?<\/p>\n<p id=\"ball-ch09_s03_p38\" class=\"para editable block\">We fix this by recognizing that two atoms can share more than one pair of electrons. In the case of CH<sub class=\"subscript\">2<\/sub>O, the O and C atoms share two pairs of electrons, with the following Lewis electron dot diagram as a result:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H-O-2.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213605\/C-H-O-2-1.png\" alt=\"C-H-O-2\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4454\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p39\" class=\"para editable block\">By circling the electrons around each atom, we can now see that the O and C atoms have octets, while each H atom has two electrons:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H-O-3.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213607\/C-H-O-3-1.png\" alt=\"C-H-O-3\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4455\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p40\" class=\"para editable block\">Each valence shell is full, so this is an acceptable Lewis electron dot diagram. If we were to use lines to represent the bonds, we would use two lines between the C and O atoms:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H-O-4.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213609\/C-H-O-4-1.png\" alt=\"C-H-O-4\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4456\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p41\" class=\"para editable block\">The bond between the C and O atoms is a <span class=\"margin_term\"><a class=\"glossterm\">double bond<\/a><\/span>\u00a0and represents two bonding pairs of electrons between the atoms. If using the rules for drawing Lewis electron dot diagrams don\u2019t work as written, a double bond may be required.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 6<\/h3>\n<p id=\"ball-ch09_s03_p42\" class=\"para\">What is the proper Lewis electron dot diagram for CO<sub class=\"subscript\">2<\/sub>?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch09_s03_p43\" class=\"para\">The central atom is a C atom, with O atoms as surrounding atoms. We have a total of 4 +\u00a06 +\u00a06 = 16 valence electrons. Following the rules for Lewis electron dot diagrams for compounds gives us<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-O.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213611\/C-O-1.png\" alt=\"C-O\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4457\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<p id=\"ball-ch09_s03_p44\" class=\"para\">The O atoms have complete octets around them, but the C atom has only four electrons around it. The way to solve this dilemma is to make a double bond between carbon and <em class=\"emphasis\">each<\/em> O atom:<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-O-2.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213613\/C-O-2-1.png\" alt=\"C-O-2\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4458\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<p id=\"ball-ch09_s03_p45\" class=\"para\">Each O atom still has eight electrons around it, but now the C atom also has a complete octet. This is an acceptable Lewis electron dot diagram for CO<sub class=\"subscript\">2<\/sub>.<\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch09_s03_p46\" class=\"para\">What is the proper Lewis electron dot diagram for carbonyl sulfide (COS)?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p class=\"simpara\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-S-O.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213615\/C-S-O-1.png\" alt=\"C-S-O\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4459\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<\/div>\n<p id=\"ball-ch09_s03_p47\" class=\"para editable block\">It is also possible to have a <span class=\"margin_term\"><a class=\"glossterm\">triple bond<\/a><\/span>, in which there are three pairs of electrons between two atoms. Good examples of this are elemental nitrogen (N<sub class=\"subscript\">2<\/sub>) and acetylene (C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">2<\/sub>):<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Triple-Bond.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213617\/Triple-Bond-1.png\" alt=\"Triple-Bond\" width=\"400\" height=\"40\" class=\"alignnone wp-image-4460\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s03_p48\" class=\"para editable block\">Acetylene is an interesting example of a molecule with two central atoms, which are both C atoms.<\/p>\n<p id=\"ball-ch09_s03_p49\" class=\"para editable block\">Polyatomic ions are bonded together with covalent bonds. Because they are ions, however, they participate in ionic bonding with other ions. So both major types of bonding can occur at the same time.<\/p>\n<div class=\"callout block\" id=\"ball-ch09_s03_n05\">\n<h3 class=\"title\">Food and Drink App: Vitamins and Minerals<\/h3>\n<p id=\"ball-ch09_s03_p50\" class=\"para\">Vitamins are nutrients that our bodies need in small amounts but cannot synthesize; therefore, they must be obtained from the diet. The word <em class=\"emphasis\">vitamin<\/em> comes from \u201cvital amine\u201d because it was once thought that all these compounds had an amine group (NH<sub class=\"subscript\">2<\/sub>) in it. This is not actually true, but the name stuck anyway.<\/p>\n<p id=\"ball-ch09_s03_p51\" class=\"para\">All vitamins are covalently bonded molecules. Most of them are commonly named with a letter, although all of them also have formal chemical names. Thus vitamin A is also called retinol, vitamin C is called ascorbic acid, and vitamin E is called tocopherol. There is no single vitamin B; there is a group of substances called the <em class=\"emphasis\">B complex vitamins<\/em> that are all water soluble and participate in cell metabolism. If a diet is lacking in a vitamin, diseases such as scurvy or rickets develop. Luckily, all vitamins are available as supplements, so any dietary deficiency in a vitamin can be easily corrected.<\/p>\n<p id=\"ball-ch09_s03_p52\" class=\"para\">A mineral is any chemical element other than carbon, hydrogen, oxygen, or nitrogen that is needed by the body. Minerals that the body needs in quantity include sodium, potassium, magnesium, calcium, phosphorus, sulfur, and chlorine. Essential minerals that the body needs in tiny quantities (so-called <em class=\"emphasis\">trace elements<\/em>) include manganese, iron, cobalt, nickel, copper, zinc, molybdenum, selenium, and iodine. Minerals are also obtained from the diet. Interestingly, most minerals are consumed in ionic form, rather than as elements or from covalent molecules. Like vitamins, most minerals are available in pill form, so any deficiency can be compensated for by taking supplements.<\/p>\n<p class=\"para\">Figure 9.2 Vitamin and Mineral Supplements<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Nutrition-Facts.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213624\/Nutrition-Facts-1.png\" alt=\"Nutrition-Facts\" width=\"400\" height=\"811\" class=\"alignnone wp-image-4461\" \/><\/a><\/p>\n<div class=\"informalfigure medium\" id=\"ball-ch09_s03_f01\">\n<p class=\"para\">Every entry down through pantothenic acid is a vitamin, and everything from calcium and below is a mineral.<\/p>\n<\/div>\n<\/div>\n<div class=\"key_takeaways editable block\" id=\"ball-ch09_s03_n06\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul id=\"ball-ch09_s03_l04\" class=\"itemizedlist\">\n<li>Covalent bonds are formed when atoms share electrons.<\/li>\n<li>Lewis electron dot diagrams can be drawn to illustrate covalent bond formation.<\/li>\n<li>Double bonds or triple bonds between atoms may be necessary to properly represent the bonding in some molecules.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div class=\"qandaset block\" id=\"ball-ch09_s03_qs01\">\n<div class=\"bcc-box bcc-info\" style=\"padding-left: 30px\">\n<h3>Exercises<\/h3>\n<ol id=\"ball-ch09_s03_qs01_qd01\" class=\"qandadiv\">\n<li id=\"ball-ch09_s03_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p01\" class=\"para\">How many electrons will be in the valence shell of H atoms when it makes a covalent bond?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s03_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p03\" class=\"para\">How many electrons will be in the valence shell of non-H atoms when they make covalent bonds?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s03_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p05\" class=\"para\">What is the Lewis electron dot diagram of I<sub class=\"subscript\">2<\/sub>? Circle the electrons around each atom to verify that each valence shell is filled.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s03_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p06\" class=\"para\">What is the Lewis electron dot diagram of H<sub class=\"subscript\">2<\/sub>S? Circle the electrons around each atom to verify that each valence shell is filled.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s03_qs01_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p07\" class=\"para\">What is the Lewis electron dot diagram of NCl<sub class=\"subscript\">3<\/sub>? Circle the electrons around each atom to verify that each valence shell is filled.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s03_qs01_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p08\" class=\"para\">What is the Lewis electron dot diagram of SiF<sub class=\"subscript\">4<\/sub>? Circle the electrons around each atom to verify that each valence shell is filled.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s03_qs01_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p09\" class=\"para\">Draw the Lewis electron dot diagram for each substance.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<p>a) \u00a0SF<sub class=\"subscript\">2<\/sub><\/p>\n<p>b) \u00a0BH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/p>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p10\" class=\"para\">8. \u00a0Draw the Lewis electron dot diagram for each substance.<\/p>\n<p>a) \u00a0PI<sub class=\"subscript\">3<\/sub><\/p>\n<p>b) \u00a0OH<sup class=\"superscript\">\u2212<\/sup><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p11\" class=\"para\">9. \u00a0Draw the Lewis electron dot diagram for each substance.<\/p>\n<p>a) \u00a0GeH<sub class=\"subscript\">4<\/sub><\/p>\n<p>b) \u00a0ClF<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p12\" class=\"para\">10. \u00a0Draw the Lewis electron dot diagram for each substance.<\/p>\n<p>a) \u00a0AsF<sub class=\"subscript\">3<\/sub><\/p>\n<p>b) \u00a0NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p13\" class=\"para\">11. \u00a0Draw the Lewis electron dot diagram for each substance. Double or triple bonds may be needed.<\/p>\n<p>a) \u00a0SiO<sub class=\"subscript\">2<\/sub><\/p>\n<p>b) \u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub> (assume two central atoms)<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p14\" class=\"para\">12. \u00a0Draw the Lewis electron dot diagram for each substance. Double or triple bonds may be needed.<\/p>\n<p>a) \u00a0CN<sup class=\"superscript\">\u2212<\/sup><\/p>\n<p>b) \u00a0C<sub class=\"subscript\">2<\/sub>Cl<sub class=\"subscript\">2<\/sub> (assume two central atoms)<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p15\" class=\"para\">13. \u00a0Draw the Lewis electron dot diagram for each substance. Double or triple bonds may be needed.<\/p>\n<p>a) \u00a0CS<sub class=\"subscript\">2<\/sub><\/p>\n<p>b) \u00a0NH<sub class=\"subscript\">2<\/sub>CONH<sub class=\"subscript\">2<\/sub> (assume that the N and C atoms are the central atoms)<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s03_qs01_p16\" class=\"para\">14. \u00a0Draw the Lewis electron dot diagram for each substance. Double or triple bonds may be needed.<\/p>\n<p>a) \u00a0POCl<\/p>\n<p>b) \u00a0HCOOH (assume that the C atom and one O atom are the central atoms)<\/p>\n<\/div>\n<p><b>Answers<\/b><br \/>\n<strong>1.<\/strong> two<\/p>\n<p><strong>3.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/I-I.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213628\/I-I-1.png\" alt=\"I-I\" width=\"400\" height=\"98\" class=\"alignnone wp-image-4462\" \/><\/a><\/strong><\/p>\n<p><strong>5.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/N-Cl.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213630\/N-Cl-1.png\" alt=\"N-Cl\" width=\"400\" height=\"119\" class=\"alignnone wp-image-4463\" \/><\/a><\/strong><\/p>\n<p><strong>7.<\/strong><\/p>\n<p style=\"padding-left: 30px\">a) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/S-F.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213632\/S-F-1.png\" alt=\"S-F\" width=\"400\" height=\"119\" class=\"alignnone wp-image-4464\" \/><\/a><\/p>\n<p style=\"padding-left: 30px\">b) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-B.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213634\/H-B-1.png\" alt=\"H-B\" width=\"400\" height=\"162\" class=\"alignnone wp-image-4465\" \/><\/a><\/p>\n<p><strong>9.<\/strong><\/p>\n<p style=\"padding-left: 30px\">a) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/H-Ge.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213636\/H-Ge-1.png\" alt=\"H-Ge\" width=\"400\" height=\"162\" class=\"alignnone wp-image-4467\" \/><\/a><\/p>\n<p style=\"padding-left: 30px\">b) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Cl-F.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213637\/Cl-F-1.png\" alt=\"Cl-F\" width=\"400\" height=\"98\" class=\"alignnone wp-image-4468\" \/><\/a><\/p>\n<p><strong>11.<\/strong><\/p>\n<p style=\"padding-left: 30px\">a) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Si-O.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213639\/Si-O-1.png\" alt=\"Si-O\" width=\"400\" height=\"98\" class=\"alignnone wp-image-4469\" \/><\/a><\/p>\n<p style=\"padding-left: 30px\">b) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213641\/C-H-1.png\" alt=\"C-H\" width=\"400\" height=\"162\" class=\"alignnone wp-image-4470\" \/><\/a><\/p>\n<p><strong>13.<\/strong><\/p>\n<p style=\"padding-left: 30px\">a) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/S-C.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213643\/S-C-1.png\" alt=\"S-C\" width=\"400\" height=\"98\" class=\"alignnone wp-image-4471\" \/><\/a><\/p>\n<p style=\"padding-left: 30px\">b) \u00a0\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-N-H-O.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213645\/C-N-H-O-1.png\" alt=\"C-N-H-O\" width=\"400\" height=\"205\" class=\"alignnone wp-image-4472\" \/><\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-436\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Introductory Chemistry- 1st Canadian Edition . <strong>Authored by<\/strong>: Jessie A. Key and David W. Ball. <strong>Provided by<\/strong>: BCCampus. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/opentextbc.ca\/introductorychemistry\/\">https:\/\/opentextbc.ca\/introductorychemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em>. <strong>License Terms<\/strong>: Download this book for free at http:\/\/open.bccampus.ca<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":23485,"menu_order":4,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Introductory Chemistry- 1st Canadian Edition \",\"author\":\"Jessie A. Key and David W. Ball\",\"organization\":\"BCCampus\",\"url\":\"https:\/\/opentextbc.ca\/introductorychemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc-sa\",\"license_terms\":\"Download this book for free at http:\/\/open.bccampus.ca\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-436","chapter","type-chapter","status-publish","hentry"],"part":352,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters\/436","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/users\/23485"}],"version-history":[{"count":0,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters\/436\/revisions"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/parts\/352"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapters\/436\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/media?parent=436"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=436"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/contributor?post=436"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/wp-json\/wp\/v2\/license?post=436"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}