{"id":479,"date":"2017-12-14T21:38:01","date_gmt":"2017-12-14T21:38:01","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-mcc-introductorychemistry\/chapter\/molecular-shapes-and-polarity\/"},"modified":"2017-12-14T21:38:01","modified_gmt":"2017-12-14T21:38:01","slug":"molecular-shapes-and-polarity","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-introductory-chemistry\/chapter\/molecular-shapes-and-polarity\/","title":{"raw":"Molecular Shapes and Polarity","rendered":"Molecular Shapes and Polarity"},"content":{"raw":"<div id=\"ball-ch09_s06\" class=\"section\" lang=\"en\">\n<div id=\"ball-ch09_s06_n01\" class=\"learning_objectives editable block\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objective<\/h3>\n<ol id=\"ball-ch09_s06_l01\"><li>Determine the shape of simple molecules.<\/li>\n\t<li>Determine the polarity of molecules using net molecular dipoles.<\/li>\n<\/ol><\/div>\n<\/div>\n<p id=\"ball-ch09_s06_p01\" class=\"para editable block\">Molecules have shapes. There is an abundance of experimental evidence to that effect\u2014from their physical properties to their chemical reactivity. Small molecules\u2014molecules with a single central atom\u2014have shapes that can be easily predicted.<\/p>\n<p id=\"ball-ch09_s06_p02\" class=\"para editable block\">The basic idea in molecular shapes is called <a class=\"glossary\">valence shell electron pair repulsion (VSEPR)<\/a>. It says that electron pairs, being composed of negatively charged particles, repel each other to get as far away from each other as possible. VSEPR makes a distinction between <a class=\"glossary\">electron group geometry<\/a>, which expresses how electron groups (bonding and nonbonding electron pairs) are arranged, and <a class=\"glossary\">molecular geometry<\/a>, which expresses how the atoms in a molecule are arranged. However, the two geometries are related.<\/p>\n<p id=\"ball-ch09_s06_p03\" class=\"para editable block\">There are two types of <a class=\"glossary\">electron groups<\/a>: any type of bond\u2014single, double, or triple\u2014and lone electron pairs. When applying VSEPR to simple molecules, the first thing to do is to count the number of electron groups around the central atom. Remember that a multiple bond counts as only <em class=\"emphasis\">one<\/em> electron group.<\/p>\n<p id=\"ball-ch09_s06_p04\" class=\"para editable block\">Any molecule with only two atoms is linear. A molecule whose central atom contains only two electron groups orients those two groups as far apart from each other as possible\u2014180\u00b0 apart. When the two electron groups are 180\u00b0 apart, the atoms attached to those electron groups are also 180\u00b0 apart, so the overall molecular shape is linear. Examples include BeH<sub class=\"subscript\">2<\/sub> and CO<sub class=\"subscript\">2<\/sub>:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/180.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213724\/180-1.png\" alt=\"180\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4516\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p05\" class=\"para editable block\">A molecule with three electron groups orients the three groups as far apart as possible. They adopt the positions of an equilateral triangle\u2014120\u00b0 apart and in a plane. The shape of such molecules is <em class=\"emphasis\">trigonal planar<\/em>. An example is BF<sub class=\"subscript\">3<\/sub>:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/120.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213726\/120-1.png\" alt=\"120\" width=\"400\" height=\"90\" class=\"alignnone wp-image-4517\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p06\" class=\"para editable block\">Some substances have a trigonal planar electron group distribution but have atoms bonded to only two of the three electron groups. An example is GeF<sub class=\"subscript\">2<\/sub>:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Ge-F.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213728\/Ge-F-1.png\" alt=\"Ge-F\" width=\"400\" height=\"59\" class=\"alignnone wp-image-4518\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p07\" class=\"para editable block\">From an electron-group-geometry perspective, GeF<sub class=\"subscript\">2<\/sub> has a trigonal planar shape, but its real shape is dictated by the positions of the atoms. This shape is called <em class=\"emphasis\">bent<\/em> or <em class=\"emphasis\">angular<\/em>.<\/p>\n<p id=\"ball-ch09_s06_p08\" class=\"para editable block\">A molecule with four electron groups around the central atom orients the four groups in the direction of a tetrahedron, as shown in <a class=\"xref\" href=\"#ball-ch09_s06_f01\">Figure 9.4 \"Tetrahedral Geometry.\"<\/a>\u00a0If there are four atoms attached to these electron groups, then the molecular shape is also <em class=\"emphasis\">tetrahedral<\/em>. Methane (CH<sub class=\"subscript\">4<\/sub>) is an example.<\/p>\n\n<div id=\"ball-ch09_s06_f01\" class=\"figure large medium-height editable block\">\n<p class=\"title\"><span class=\"title-prefix\">Figure 9.4<\/span>\u00a0Tetrahedral Geometry<\/p>\n<p class=\"title\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Tetrahedral.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213731\/Tetrahedral-1.png\" alt=\"Tetrahedral\" width=\"400\" height=\"391\" class=\"alignnone wp-image-4519\"\/><\/a><\/p>\n<p class=\"para\">Four electron groups orient themselves in the shape of a tetrahedron.<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H1.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213733\/C-H1-1.png\" alt=\"C-H\" width=\"400\" height=\"80\" class=\"alignnone wp-image-4520\"\/><\/a><\/p>\n\n<\/div>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p09\" class=\"para editable block\">This diagram of CH<sub class=\"subscript\">4<\/sub> illustrates the standard convention of displaying a three-dimensional molecule on a two-dimensional surface. The straight lines are in the plane of the page, the solid wedged line is coming out of the plane toward the reader, and the dashed wedged line is going out of the plane away from the reader.<\/p>\n<p id=\"ball-ch09_s06_p10\" class=\"para editable block\">NH<sub class=\"subscript\">3<\/sub> is an example of a molecule whose central atom has four electron groups but only three of them are bonded to surrounding atoms.<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/N-H1.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213735\/N-H1-1.png\" alt=\"N-H\" width=\"400\" height=\"49\" class=\"alignnone wp-image-4522\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p11\" class=\"para editable block\">Although the electron groups are oriented in the shape of a tetrahedron, from a molecular geometry perspective, the shape of NH<sub class=\"subscript\">3<\/sub> is <em class=\"emphasis\">trigonal pyramidal<\/em>.<\/p>\n<p id=\"ball-ch09_s06_p12\" class=\"para editable block\">H<sub class=\"subscript\">2<\/sub>O is an example of a molecule with a central atom that has four electron groups but only two of them are bonded to surrounding atoms.<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/O-H.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213737\/O-H-1.png\" alt=\"O-H\" width=\"400\" height=\"49\" class=\"alignnone wp-image-4523\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p13\" class=\"para editable block\">Although the electron groups are oriented in the shape of a tetrahedron, the shape of the molecule is <em class=\"emphasis\">bent<\/em> or <em class=\"emphasis\">angular<\/em>. A molecule with four electron groups around\u00a0the central atom but only one electron group bonded to another atom is linear because there are only two atoms in the molecule.<\/p>\n<p id=\"ball-ch09_s06_p14\" class=\"para editable block\">Double or triple bonds count as a single electron group. CH<sub class=\"subscript\">2<\/sub>O has the following Lewis electron dot diagram.<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H-O1.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213739\/C-H-O1-1.png\" alt=\"C-H-O\" width=\"400\" height=\"49\" class=\"alignnone wp-image-4524\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p15\" class=\"para editable block\">The central C atom has three electron groups around it because the double bond counts as one electron group. The three electron groups repel each other to adopt a trigonal planar shape:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H-O-21.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213741\/C-H-O-21-1.png\" alt=\"C-H-O-2\" width=\"400\" height=\"71\" class=\"alignnone wp-image-4525\"\/><\/a><\/p>\n\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p16\" class=\"para editable block\">(The lone electron pairs on the O atom are omitted for clarity.) The molecule will not be a perfect equilateral triangle because the C\u2013O double bond is different from the two C\u2013H bonds, but both <em>planar<\/em> and <em>triangular<\/em> describe the appropriate approximate shape of this molecule.<\/p>\n\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 10<\/h3>\n<p id=\"ball-ch09_s06_p17\" class=\"para\">What is the approximate shape of each molecule?<\/p>\n\n<ol id=\"ball-ch09_s06_l02\" class=\"orderedlist\"><li>PCl<sub class=\"subscript\">3<\/sub><\/li>\n\t<li>NOF<\/li>\n<\/ol><p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch09_s06_p18\" class=\"para\">The first step is to draw the Lewis electron dot diagram of the molecule.<\/p>\n\n<ol id=\"ball-ch09_s06_l03\" class=\"orderedlist\"><li>\n<p class=\"para\">For PCl<sub class=\"subscript\">3<\/sub>, the Lewis electron dot diagram is as follows:<\/p>\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/P-Cl.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213742\/P-Cl-1.png\" alt=\"P-Cl\" width=\"400\" height=\"49\" class=\"alignnone wp-image-4526\"\/><\/a>\n<div class=\"informalfigure large\">\n<p id=\"ball-ch09_s06_p19\" class=\"para\">The lone electron pairs on the Cl atoms are omitted for clarity. The P atom has four electron groups with three of them bonded to surrounding atoms, so the molecular shape is trigonal pyramidal.<\/p>\n<\/div><\/li>\n\t<li>\n<p class=\"para\">The Lewis\u00a0diagram for NOF is as follows:<\/p>\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/N-F-O.png\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213744\/N-F-O-1.png\" alt=\"N-F-O\" width=\"400\" height=\"49\" class=\"alignnone wp-image-4527\"\/><\/a>\n<div class=\"informalfigure large\">\n<p id=\"ball-ch09_s06_p20\" class=\"para\">The N atom has three electron groups on it, two of which are bonded to other atoms. The molecular shape is bent.<\/p>\n<\/div><\/li>\n<\/ol><p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch09_s06_p21\" class=\"para\">What is the approximate molecular shape of CH<sub class=\"subscript\">2<\/sub>Cl<sub class=\"subscript\">2<\/sub>?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch09_s06_p22\" class=\"para\">Tetrahedral<\/p>\n\n<\/div>\n<p id=\"ball-ch09_s06_p23\" class=\"para editable block\"><a class=\"xref\" href=\"#ball-ch09_s06_t01\">Table 9.4 \"Summary of Molecular Shapes\"<\/a> summarizes the shapes of molecules based on their number of electron groups and surrounding atoms.<\/p>\n\n<div id=\"ball-ch09_s06_t01\" class=\"table block\">\n<p class=\"title\"><span class=\"title-prefix\">Table 9.4<\/span> Summary of Molecular Shapes<\/p>\n\n<table style=\"height: 168px; width: 648px; border-spacing: 0px;\" cellpadding=\"0\"><thead><tr><th align=\"center\">Number of Electron Groups on Central Atom<\/th>\n<th align=\"center\">Number of Surrounding Atoms<\/th>\n<th>Molecular Shape<\/th>\n<\/tr><\/thead><tbody><tr><td align=\"center\">any<\/td>\n<td align=\"center\">1<\/td>\n<td>linear<\/td>\n<\/tr><tr><td align=\"center\">2<\/td>\n<td align=\"center\">2<\/td>\n<td>linear<\/td>\n<\/tr><tr><td align=\"center\">3<\/td>\n<td align=\"center\">3<\/td>\n<td>trigonal planar<\/td>\n<\/tr><tr><td align=\"center\">3<\/td>\n<td align=\"center\">2<\/td>\n<td>bent<\/td>\n<\/tr><tr><td align=\"center\">4<\/td>\n<td align=\"center\">4<\/td>\n<td>tetrahedral<\/td>\n<\/tr><tr><td align=\"center\">4<\/td>\n<td align=\"center\">3<\/td>\n<td>trigonal pyramidal<\/td>\n<\/tr><tr><td align=\"center\">4<\/td>\n<td align=\"center\">2<\/td>\n<td>bent<\/td>\n<\/tr><\/tbody><\/table><h2>Molecular Polarity<\/h2>\nThe overall polarity of molecules with more than one bond is determined from both the polarity of the individual bonds and the shape of the molecule. Each bond\u2019s dipole moment can be treated as a <a class=\"glossary\">vector quantity<\/a>, having a magnitude and direction. Therefore the molecular polarity is the vector sum of the individual bond dipoles.\n<h3>\u00a0How to determine the vector sum<\/h3>\nOne method to determine the vector sum of dipole arrows is known as the tail-to-head method. Let\u2019s examine this method for a molecule of water. 1. First draw the Lewis electron dot diagram for water and determine its molecular shape. Water has four electron groups, but only two atoms attached to the central atom so it is bent.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/water_lewis_structure.png\"><img class=\"size-full wp-image-2478 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213746\/water_lewis_structure-1.png\" alt=\"water_lewis_structure\" height=\"152\" width=\"209\"\/><\/a> 2. Draw in dipole arrows for all polar covalent bonds, starting the arrow at the more electropositive atom, and ending at the more electronegative atom.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/water_dipoles.png\"><img class=\"size-full wp-image-2479 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213747\/water_dipoles-1.png\" alt=\"water_dipoles\" height=\"167\" width=\"242\"\/><\/a> 3. Connect the dipole arrows tail-to-head.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/tailtohead1.png\"><img class=\"size-full wp-image-2480 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213748\/tailtohead1-1.png\" alt=\"tailtohead1\" height=\"155\" width=\"114\"\/><\/a> 4. Draw a new line connecting the tail of the first vector. This is the net molecular dipole.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/net_dipole_tailtohead.png\"><img class=\"size-full wp-image-2481 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213750\/net_dipole_tailtohead-1.png\" alt=\"net_dipole_tailtohead\" height=\"218\" width=\"281\"\/><\/a> 5. Now superimpose the net molecular dipole arrow onto the molecule.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/net_molecular_dipole.png\"><img class=\"size-full wp-image-2482 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213751\/net_molecular_dipole-1.png\" alt=\"net_molecular_dipole\" height=\"153\" width=\"189\"\/><\/a> An alternative method to determine the vector sum of dipole arrows is known as the vector component method. Let\u2019s examine this method again for a molecule of water. The first two steps remain the same as the tail-to-head method: 1. First draw the Lewis electron dot diagram for water and determine its molecular shape. Water has four electron groups, but only two atoms attached to the central atom so it is bent.\n\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/water_lewis_structure.png\"><img class=\"alignnone size-full wp-image-2478\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213746\/water_lewis_structure-1.png\" alt=\"water_lewis_structure\" height=\"152\" width=\"209\"\/><\/a>\n\n2. Draw in dipole arrows for all polar covalent bonds, starting the arrow at the more electropositive atom, and ending at the more electronegative atom.\n\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/water_dipoles.png\"><img class=\"alignnone size-full wp-image-2479\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213747\/water_dipoles-1.png\" alt=\"water_dipoles\" height=\"167\" width=\"242\"\/><\/a>\n\n3.\u00a0For dipole arrows at an angle, separate them into horizontal and vertical vector components. <a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/vector_components.png\"><img class=\"alignnone size-full wp-image-2483\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213752\/vector_components-1.png\" alt=\"vector_components\" height=\"128\" width=\"345\"\/><\/a>\n\n<\/div>\n<div class=\"table block\">4. Superimpose the vector components onto the molecule.<\/div>\n<div class=\"table block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/vector_components_2.png\"><img class=\"alignnone size-full wp-image-2485\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213754\/vector_components_2-1.png\" alt=\"vector_components_2\" height=\"186\" width=\"345\"\/><\/a><\/div>\n<div class=\"table block\">5. Cancel out any vector components that are of equal magnitude and pointing in the opposite direction. <img class=\"alignnone size-full wp-image-2484\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213755\/vector_components_3-1.png\" alt=\"vector_components_3\" height=\"190\" width=\"358\"\/><\/div>\n<div class=\"table block\">6. The remaining vector components both point vertically, showing the net molecular dipole. <a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/net_molecular_dipole.png\"><img class=\"alignnone size-full wp-image-2482\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213751\/net_molecular_dipole-1.png\" alt=\"net_molecular_dipole\" height=\"153\" width=\"189\"\/><\/a><\/div>\n<div class=\"table block\">\n<div class=\"table block\">As a result of the vector quantity nature of bond dipoles, some molecules may contain polar bonds, yet have no net molecular dipole moment. For example, CO<sub>2<\/sub>:<\/div>\n<div class=\"table block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/CO2_no_net_dipole.png\"><img class=\"alignnone size-full wp-image-2487\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213757\/CO2_no_net_dipole-1.png\" alt=\"CO2_no_net_dipole\" height=\"174\" width=\"279\"\/><\/a><\/div>\n<div id=\"ball-ch09_s06_n03\" class=\"key_takeaways editable block\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul><li>The approximate shape of a molecule can be predicted from the number of electron groups and the number of surrounding atoms.<\/li>\n\t<li>The molecular polarity can be established by determining the vector sum of all bond dipoles.<\/li>\n<\/ul><\/div>\n<\/div>\n<div id=\"ball-ch09_s06_qs01\" class=\"qandaset block\">\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<ol id=\"ball-ch09_s06_qs01_qd01\" class=\"qandadiv\"><li id=\"ball-ch09_s06_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p01\" class=\"para\">What is the basic premise behind VSEPR?<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch09_s06_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p03\" class=\"para\">What is the difference between electron group geometry and molecular geometry?<\/p>\n\n<\/div><\/li>\n\t<li id=\"ball-ch09_s06_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p05\" class=\"para\">Identify the electron group geometry and molecular geometry of each molecule.<\/p>\n\n<\/div><\/li>\n<\/ol>\na) \u00a0H<sub class=\"subscript\">2<\/sub>S\n\nb) \u00a0POCl<sub class=\"subscript\">3<\/sub>\n\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p06\" class=\"para\">4. \u00a0Identify the electron group geometry and the molecular geometry of each molecule.<\/p>\na) \u00a0CS<sub class=\"subscript\">2<\/sub>\n\nb) \u00a0H<sub class=\"subscript\">2<\/sub>S\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p07\" class=\"para\">5. \u00a0Identify the electron group geometry and the molecular geometry of each molecule.<\/p>\na) \u00a0HCN\n\nb) \u00a0CCl<sub class=\"subscript\">4<\/sub><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p08\" class=\"para\">6. \u00a0Identify the electron group geometry and the molecular geometry of each molecule.<\/p>\na) \u00a0BI<sub class=\"subscript\">3<\/sub>\n\nb) \u00a0PH<sub class=\"subscript\">3<\/sub><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p09\" class=\"para\">7. \u00a0What is the geometry of each species?<\/p>\na) \u00a0CN<sup class=\"superscript\">\u2212<\/sup>\n\nb) \u00a0PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p10\" class=\"para\">8. \u00a0What is the geometry of each species?<\/p>\na) \u00a0PO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">3\u2212<\/sup>\n\nb) \u00a0NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p11\" class=\"para\">9. \u00a0What is the geometry of each species?<\/p>\na) \u00a0COF<sub class=\"subscript\">2<\/sub>\n\nb) \u00a0C<sub class=\"subscript\">2<\/sub>Cl<sub class=\"subscript\">2<\/sub> (both C atoms are central atoms and are bonded to each other)\n\n<\/div>\n\u00a0\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p12\" class=\"para\">10. \u00a0What is the geometry of each species?<\/p>\na) \u00a0CO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup>\n\nb) \u00a0N<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub> (both N atoms are central atoms and are bonded to each other)\n\n<\/div>\n<p class=\"title\">\u00a011. Determine the net molecular dipole of each species:<\/p>\n<p style=\"padding-left: 30px\">a) BF<sub>3<\/sub><\/p>\n<p style=\"padding-left: 30px\">b)\u00a0NH<sub>3<\/sub><\/p>\n<b>Answers<\/b>\n\n<strong>1.<\/strong> Electron pairs repel each other.\n\n<strong>3.<\/strong>\n<p style=\"padding-left: 30px\">a)\u00a0electron group geometry: tetrahedral; molecular geometry: bent<\/p>\n<p style=\"padding-left: 30px\">b)\u00a0electron group geometry: tetrahedral; molecular geometry: tetrahedral<\/p>\n<strong>5.<\/strong>\n<p style=\"padding-left: 30px\">a)\u00a0electron group geometry: linear; molecular geometry: linear<\/p>\n<p style=\"padding-left: 30px\">b)\u00a0electron group geometry: tetrahedral; molecular geometry: tetrahedral<\/p>\n<strong>7.<\/strong>\n<p style=\"padding-left: 30px\">a)\u00a0linear<\/p>\n<p style=\"padding-left: 30px\">b)\u00a0tetrahedral<\/p>\n<strong>9.<\/strong>\n<p style=\"padding-left: 30px\">a)\u00a0trigonal planar<\/p>\n<p style=\"padding-left: 30px\">b)\u00a0linear and linear about each central atom<\/p>\n<strong>11.<\/strong>\n<p style=\"padding-left: 30px\">a) \u00a0\u00a0BF<sub>3<\/sub> = No net dipole moment\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/BF3_dipoles_cancel.png\"><img class=\"alignnone size-full wp-image-2488\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213759\/BF3_dipoles_cancel-1.png\" alt=\"BF3_dipoles_cancel\" height=\"233\" width=\"301\"\/><\/a><\/p>\n<p style=\"padding-left: 30px\">b) \u00a0\u00a0NH<sub>3<\/sub> =\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/NH3_dipole.png\"><img class=\"alignnone size-full wp-image-2489\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213800\/NH3_dipole-1.png\" alt=\"NH3_dipole\" height=\"203\" width=\"202\"\/><\/a><\/p>\n\n<\/div>\n<\/div>\n<\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div><\/div>","rendered":"<div id=\"ball-ch09_s06\" class=\"section\" lang=\"en\">\n<div id=\"ball-ch09_s06_n01\" class=\"learning_objectives editable block\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objective<\/h3>\n<ol id=\"ball-ch09_s06_l01\">\n<li>Determine the shape of simple molecules.<\/li>\n<li>Determine the polarity of molecules using net molecular dipoles.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"ball-ch09_s06_p01\" class=\"para editable block\">Molecules have shapes. There is an abundance of experimental evidence to that effect\u2014from their physical properties to their chemical reactivity. Small molecules\u2014molecules with a single central atom\u2014have shapes that can be easily predicted.<\/p>\n<p id=\"ball-ch09_s06_p02\" class=\"para editable block\">The basic idea in molecular shapes is called <a class=\"glossary\">valence shell electron pair repulsion (VSEPR)<\/a>. It says that electron pairs, being composed of negatively charged particles, repel each other to get as far away from each other as possible. VSEPR makes a distinction between <a class=\"glossary\">electron group geometry<\/a>, which expresses how electron groups (bonding and nonbonding electron pairs) are arranged, and <a class=\"glossary\">molecular geometry<\/a>, which expresses how the atoms in a molecule are arranged. However, the two geometries are related.<\/p>\n<p id=\"ball-ch09_s06_p03\" class=\"para editable block\">There are two types of <a class=\"glossary\">electron groups<\/a>: any type of bond\u2014single, double, or triple\u2014and lone electron pairs. When applying VSEPR to simple molecules, the first thing to do is to count the number of electron groups around the central atom. Remember that a multiple bond counts as only <em class=\"emphasis\">one<\/em> electron group.<\/p>\n<p id=\"ball-ch09_s06_p04\" class=\"para editable block\">Any molecule with only two atoms is linear. A molecule whose central atom contains only two electron groups orients those two groups as far apart from each other as possible\u2014180\u00b0 apart. When the two electron groups are 180\u00b0 apart, the atoms attached to those electron groups are also 180\u00b0 apart, so the overall molecular shape is linear. Examples include BeH<sub class=\"subscript\">2<\/sub> and CO<sub class=\"subscript\">2<\/sub>:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/180.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213724\/180-1.png\" alt=\"180\" width=\"400\" height=\"60\" class=\"alignnone wp-image-4516\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p05\" class=\"para editable block\">A molecule with three electron groups orients the three groups as far apart as possible. They adopt the positions of an equilateral triangle\u2014120\u00b0 apart and in a plane. The shape of such molecules is <em class=\"emphasis\">trigonal planar<\/em>. An example is BF<sub class=\"subscript\">3<\/sub>:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/120.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213726\/120-1.png\" alt=\"120\" width=\"400\" height=\"90\" class=\"alignnone wp-image-4517\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p06\" class=\"para editable block\">Some substances have a trigonal planar electron group distribution but have atoms bonded to only two of the three electron groups. An example is GeF<sub class=\"subscript\">2<\/sub>:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Ge-F.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213728\/Ge-F-1.png\" alt=\"Ge-F\" width=\"400\" height=\"59\" class=\"alignnone wp-image-4518\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p07\" class=\"para editable block\">From an electron-group-geometry perspective, GeF<sub class=\"subscript\">2<\/sub> has a trigonal planar shape, but its real shape is dictated by the positions of the atoms. This shape is called <em class=\"emphasis\">bent<\/em> or <em class=\"emphasis\">angular<\/em>.<\/p>\n<p id=\"ball-ch09_s06_p08\" class=\"para editable block\">A molecule with four electron groups around the central atom orients the four groups in the direction of a tetrahedron, as shown in <a class=\"xref\" href=\"#ball-ch09_s06_f01\">Figure 9.4 &#8220;Tetrahedral Geometry.&#8221;<\/a>\u00a0If there are four atoms attached to these electron groups, then the molecular shape is also <em class=\"emphasis\">tetrahedral<\/em>. Methane (CH<sub class=\"subscript\">4<\/sub>) is an example.<\/p>\n<div id=\"ball-ch09_s06_f01\" class=\"figure large medium-height editable block\">\n<p class=\"title\"><span class=\"title-prefix\">Figure 9.4<\/span>\u00a0Tetrahedral Geometry<\/p>\n<p class=\"title\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Tetrahedral.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213731\/Tetrahedral-1.png\" alt=\"Tetrahedral\" width=\"400\" height=\"391\" class=\"alignnone wp-image-4519\" \/><\/a><\/p>\n<p class=\"para\">Four electron groups orient themselves in the shape of a tetrahedron.<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H1.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213733\/C-H1-1.png\" alt=\"C-H\" width=\"400\" height=\"80\" class=\"alignnone wp-image-4520\" \/><\/a><\/p>\n<\/div>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p09\" class=\"para editable block\">This diagram of CH<sub class=\"subscript\">4<\/sub> illustrates the standard convention of displaying a three-dimensional molecule on a two-dimensional surface. The straight lines are in the plane of the page, the solid wedged line is coming out of the plane toward the reader, and the dashed wedged line is going out of the plane away from the reader.<\/p>\n<p id=\"ball-ch09_s06_p10\" class=\"para editable block\">NH<sub class=\"subscript\">3<\/sub> is an example of a molecule whose central atom has four electron groups but only three of them are bonded to surrounding atoms.<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/N-H1.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213735\/N-H1-1.png\" alt=\"N-H\" width=\"400\" height=\"49\" class=\"alignnone wp-image-4522\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p11\" class=\"para editable block\">Although the electron groups are oriented in the shape of a tetrahedron, from a molecular geometry perspective, the shape of NH<sub class=\"subscript\">3<\/sub> is <em class=\"emphasis\">trigonal pyramidal<\/em>.<\/p>\n<p id=\"ball-ch09_s06_p12\" class=\"para editable block\">H<sub class=\"subscript\">2<\/sub>O is an example of a molecule with a central atom that has four electron groups but only two of them are bonded to surrounding atoms.<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/O-H.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213737\/O-H-1.png\" alt=\"O-H\" width=\"400\" height=\"49\" class=\"alignnone wp-image-4523\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p13\" class=\"para editable block\">Although the electron groups are oriented in the shape of a tetrahedron, the shape of the molecule is <em class=\"emphasis\">bent<\/em> or <em class=\"emphasis\">angular<\/em>. A molecule with four electron groups around\u00a0the central atom but only one electron group bonded to another atom is linear because there are only two atoms in the molecule.<\/p>\n<p id=\"ball-ch09_s06_p14\" class=\"para editable block\">Double or triple bonds count as a single electron group. CH<sub class=\"subscript\">2<\/sub>O has the following Lewis electron dot diagram.<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H-O1.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213739\/C-H-O1-1.png\" alt=\"C-H-O\" width=\"400\" height=\"49\" class=\"alignnone wp-image-4524\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p15\" class=\"para editable block\">The central C atom has three electron groups around it because the double bond counts as one electron group. The three electron groups repel each other to adopt a trigonal planar shape:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/C-H-O-21.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213741\/C-H-O-21-1.png\" alt=\"C-H-O-2\" width=\"400\" height=\"71\" class=\"alignnone wp-image-4525\" \/><\/a><\/p>\n<div class=\"informalfigure large block\">\n<p id=\"ball-ch09_s06_p16\" class=\"para editable block\">(The lone electron pairs on the O atom are omitted for clarity.) The molecule will not be a perfect equilateral triangle because the C\u2013O double bond is different from the two C\u2013H bonds, but both <em>planar<\/em> and <em>triangular<\/em> describe the appropriate approximate shape of this molecule.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 10<\/h3>\n<p id=\"ball-ch09_s06_p17\" class=\"para\">What is the approximate shape of each molecule?<\/p>\n<ol id=\"ball-ch09_s06_l02\" class=\"orderedlist\">\n<li>PCl<sub class=\"subscript\">3<\/sub><\/li>\n<li>NOF<\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch09_s06_p18\" class=\"para\">The first step is to draw the Lewis electron dot diagram of the molecule.<\/p>\n<ol id=\"ball-ch09_s06_l03\" class=\"orderedlist\">\n<li>\n<p class=\"para\">For PCl<sub class=\"subscript\">3<\/sub>, the Lewis electron dot diagram is as follows:<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/P-Cl.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213742\/P-Cl-1.png\" alt=\"P-Cl\" width=\"400\" height=\"49\" class=\"alignnone wp-image-4526\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<p id=\"ball-ch09_s06_p19\" class=\"para\">The lone electron pairs on the Cl atoms are omitted for clarity. The P atom has four electron groups with three of them bonded to surrounding atoms, so the molecular shape is trigonal pyramidal.<\/p>\n<\/div>\n<\/li>\n<li>\n<p class=\"para\">The Lewis\u00a0diagram for NOF is as follows:<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/N-F-O.png\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213744\/N-F-O-1.png\" alt=\"N-F-O\" width=\"400\" height=\"49\" class=\"alignnone wp-image-4527\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<p id=\"ball-ch09_s06_p20\" class=\"para\">The N atom has three electron groups on it, two of which are bonded to other atoms. The molecular shape is bent.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch09_s06_p21\" class=\"para\">What is the approximate molecular shape of CH<sub class=\"subscript\">2<\/sub>Cl<sub class=\"subscript\">2<\/sub>?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch09_s06_p22\" class=\"para\">Tetrahedral<\/p>\n<\/div>\n<p id=\"ball-ch09_s06_p23\" class=\"para editable block\"><a class=\"xref\" href=\"#ball-ch09_s06_t01\">Table 9.4 &#8220;Summary of Molecular Shapes&#8221;<\/a> summarizes the shapes of molecules based on their number of electron groups and surrounding atoms.<\/p>\n<div id=\"ball-ch09_s06_t01\" class=\"table block\">\n<p class=\"title\"><span class=\"title-prefix\">Table 9.4<\/span> Summary of Molecular Shapes<\/p>\n<table style=\"height: 168px; width: 648px; border-spacing: 0px;\" cellpadding=\"0\">\n<thead>\n<tr>\n<th align=\"center\">Number of Electron Groups on Central Atom<\/th>\n<th align=\"center\">Number of Surrounding Atoms<\/th>\n<th>Molecular Shape<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td align=\"center\">any<\/td>\n<td align=\"center\">1<\/td>\n<td>linear<\/td>\n<\/tr>\n<tr>\n<td align=\"center\">2<\/td>\n<td align=\"center\">2<\/td>\n<td>linear<\/td>\n<\/tr>\n<tr>\n<td align=\"center\">3<\/td>\n<td align=\"center\">3<\/td>\n<td>trigonal planar<\/td>\n<\/tr>\n<tr>\n<td align=\"center\">3<\/td>\n<td align=\"center\">2<\/td>\n<td>bent<\/td>\n<\/tr>\n<tr>\n<td align=\"center\">4<\/td>\n<td align=\"center\">4<\/td>\n<td>tetrahedral<\/td>\n<\/tr>\n<tr>\n<td align=\"center\">4<\/td>\n<td align=\"center\">3<\/td>\n<td>trigonal pyramidal<\/td>\n<\/tr>\n<tr>\n<td align=\"center\">4<\/td>\n<td align=\"center\">2<\/td>\n<td>bent<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h2>Molecular Polarity<\/h2>\n<p>The overall polarity of molecules with more than one bond is determined from both the polarity of the individual bonds and the shape of the molecule. Each bond\u2019s dipole moment can be treated as a <a class=\"glossary\">vector quantity<\/a>, having a magnitude and direction. Therefore the molecular polarity is the vector sum of the individual bond dipoles.<\/p>\n<h3>\u00a0How to determine the vector sum<\/h3>\n<p>One method to determine the vector sum of dipole arrows is known as the tail-to-head method. Let\u2019s examine this method for a molecule of water. 1. First draw the Lewis electron dot diagram for water and determine its molecular shape. Water has four electron groups, but only two atoms attached to the central atom so it is bent.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/water_lewis_structure.png\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-2478 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213746\/water_lewis_structure-1.png\" alt=\"water_lewis_structure\" height=\"152\" width=\"209\" \/><\/a> 2. Draw in dipole arrows for all polar covalent bonds, starting the arrow at the more electropositive atom, and ending at the more electronegative atom.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/water_dipoles.png\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-2479 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213747\/water_dipoles-1.png\" alt=\"water_dipoles\" height=\"167\" width=\"242\" \/><\/a> 3. Connect the dipole arrows tail-to-head.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/tailtohead1.png\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-2480 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213748\/tailtohead1-1.png\" alt=\"tailtohead1\" height=\"155\" width=\"114\" \/><\/a> 4. Draw a new line connecting the tail of the first vector. This is the net molecular dipole.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/net_dipole_tailtohead.png\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-2481 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213750\/net_dipole_tailtohead-1.png\" alt=\"net_dipole_tailtohead\" height=\"218\" width=\"281\" \/><\/a> 5. Now superimpose the net molecular dipole arrow onto the molecule.<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/net_molecular_dipole.png\"><img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-2482 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213751\/net_molecular_dipole-1.png\" alt=\"net_molecular_dipole\" height=\"153\" width=\"189\" \/><\/a> An alternative method to determine the vector sum of dipole arrows is known as the vector component method. Let\u2019s examine this method again for a molecule of water. The first two steps remain the same as the tail-to-head method: 1. First draw the Lewis electron dot diagram for water and determine its molecular shape. Water has four electron groups, but only two atoms attached to the central atom so it is bent.<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/water_lewis_structure.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2478\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213746\/water_lewis_structure-1.png\" alt=\"water_lewis_structure\" height=\"152\" width=\"209\" \/><\/a><\/p>\n<p>2. Draw in dipole arrows for all polar covalent bonds, starting the arrow at the more electropositive atom, and ending at the more electronegative atom.<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/water_dipoles.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2479\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213747\/water_dipoles-1.png\" alt=\"water_dipoles\" height=\"167\" width=\"242\" \/><\/a><\/p>\n<p>3.\u00a0For dipole arrows at an angle, separate them into horizontal and vertical vector components. <a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/vector_components.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2483\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213752\/vector_components-1.png\" alt=\"vector_components\" height=\"128\" width=\"345\" \/><\/a><\/p>\n<\/div>\n<div class=\"table block\">4. Superimpose the vector components onto the molecule.<\/div>\n<div class=\"table block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/vector_components_2.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2485\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213754\/vector_components_2-1.png\" alt=\"vector_components_2\" height=\"186\" width=\"345\" \/><\/a><\/div>\n<div class=\"table block\">5. Cancel out any vector components that are of equal magnitude and pointing in the opposite direction. <img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2484\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213755\/vector_components_3-1.png\" alt=\"vector_components_3\" height=\"190\" width=\"358\" \/><\/div>\n<div class=\"table block\">6. The remaining vector components both point vertically, showing the net molecular dipole. <a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/net_molecular_dipole.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2482\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213751\/net_molecular_dipole-1.png\" alt=\"net_molecular_dipole\" height=\"153\" width=\"189\" \/><\/a><\/div>\n<div class=\"table block\">\n<div class=\"table block\">As a result of the vector quantity nature of bond dipoles, some molecules may contain polar bonds, yet have no net molecular dipole moment. For example, CO<sub>2<\/sub>:<\/div>\n<div class=\"table block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/CO2_no_net_dipole.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2487\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213757\/CO2_no_net_dipole-1.png\" alt=\"CO2_no_net_dipole\" height=\"174\" width=\"279\" \/><\/a><\/div>\n<div id=\"ball-ch09_s06_n03\" class=\"key_takeaways editable block\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul>\n<li>The approximate shape of a molecule can be predicted from the number of electron groups and the number of surrounding atoms.<\/li>\n<li>The molecular polarity can be established by determining the vector sum of all bond dipoles.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div id=\"ball-ch09_s06_qs01\" class=\"qandaset block\">\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<ol id=\"ball-ch09_s06_qs01_qd01\" class=\"qandadiv\">\n<li id=\"ball-ch09_s06_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p01\" class=\"para\">What is the basic premise behind VSEPR?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s06_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p03\" class=\"para\">What is the difference between electron group geometry and molecular geometry?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s06_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p05\" class=\"para\">Identify the electron group geometry and molecular geometry of each molecule.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<p>a) \u00a0H<sub class=\"subscript\">2<\/sub>S<\/p>\n<p>b) \u00a0POCl<sub class=\"subscript\">3<\/sub><\/p>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p06\" class=\"para\">4. \u00a0Identify the electron group geometry and the molecular geometry of each molecule.<\/p>\n<p>a) \u00a0CS<sub class=\"subscript\">2<\/sub><\/p>\n<p>b) \u00a0H<sub class=\"subscript\">2<\/sub>S<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p07\" class=\"para\">5. \u00a0Identify the electron group geometry and the molecular geometry of each molecule.<\/p>\n<p>a) \u00a0HCN<\/p>\n<p>b) \u00a0CCl<sub class=\"subscript\">4<\/sub><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p08\" class=\"para\">6. \u00a0Identify the electron group geometry and the molecular geometry of each molecule.<\/p>\n<p>a) \u00a0BI<sub class=\"subscript\">3<\/sub><\/p>\n<p>b) \u00a0PH<sub class=\"subscript\">3<\/sub><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p09\" class=\"para\">7. \u00a0What is the geometry of each species?<\/p>\n<p>a) \u00a0CN<sup class=\"superscript\">\u2212<\/sup><\/p>\n<p>b) \u00a0PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p10\" class=\"para\">8. \u00a0What is the geometry of each species?<\/p>\n<p>a) \u00a0PO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/p>\n<p>b) \u00a0NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p11\" class=\"para\">9. \u00a0What is the geometry of each species?<\/p>\n<p>a) \u00a0COF<sub class=\"subscript\">2<\/sub><\/p>\n<p>b) \u00a0C<sub class=\"subscript\">2<\/sub>Cl<sub class=\"subscript\">2<\/sub> (both C atoms are central atoms and are bonded to each other)<\/p>\n<\/div>\n<p>\u00a0<\/p>\n<div class=\"question\">\n<p id=\"ball-ch09_s06_qs01_p12\" class=\"para\">10. \u00a0What is the geometry of each species?<\/p>\n<p>a) \u00a0CO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/p>\n<p>b) \u00a0N<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub> (both N atoms are central atoms and are bonded to each other)<\/p>\n<\/div>\n<p class=\"title\">\u00a011. Determine the net molecular dipole of each species:<\/p>\n<p style=\"padding-left: 30px\">a) BF<sub>3<\/sub><\/p>\n<p style=\"padding-left: 30px\">b)\u00a0NH<sub>3<\/sub><\/p>\n<p><b>Answers<\/b><\/p>\n<p><strong>1.<\/strong> Electron pairs repel each other.<\/p>\n<p><strong>3.<\/strong><\/p>\n<p style=\"padding-left: 30px\">a)\u00a0electron group geometry: tetrahedral; molecular geometry: bent<\/p>\n<p style=\"padding-left: 30px\">b)\u00a0electron group geometry: tetrahedral; molecular geometry: tetrahedral<\/p>\n<p><strong>5.<\/strong><\/p>\n<p style=\"padding-left: 30px\">a)\u00a0electron group geometry: linear; molecular geometry: linear<\/p>\n<p style=\"padding-left: 30px\">b)\u00a0electron group geometry: tetrahedral; molecular geometry: tetrahedral<\/p>\n<p><strong>7.<\/strong><\/p>\n<p style=\"padding-left: 30px\">a)\u00a0linear<\/p>\n<p style=\"padding-left: 30px\">b)\u00a0tetrahedral<\/p>\n<p><strong>9.<\/strong><\/p>\n<p style=\"padding-left: 30px\">a)\u00a0trigonal planar<\/p>\n<p style=\"padding-left: 30px\">b)\u00a0linear and linear about each central atom<\/p>\n<p><strong>11.<\/strong><\/p>\n<p style=\"padding-left: 30px\">a) \u00a0\u00a0BF<sub>3<\/sub> = No net dipole moment\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/BF3_dipoles_cancel.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2488\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213759\/BF3_dipoles_cancel-1.png\" alt=\"BF3_dipoles_cancel\" height=\"233\" width=\"301\" \/><\/a><\/p>\n<p style=\"padding-left: 30px\">b) \u00a0\u00a0NH<sub>3<\/sub> =\u00a0<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/06\/NH3_dipole.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2489\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2835\/2017\/12\/14213800\/NH3_dipole-1.png\" alt=\"NH3_dipole\" height=\"203\" width=\"202\" \/><\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-479\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Introductory Chemistry- 1st Canadian Edition . <strong>Authored by<\/strong>: Jessie A. Key and David W. Ball. <strong>Provided by<\/strong>: BCCampus. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/opentextbc.ca\/introductorychemistry\/\">https:\/\/opentextbc.ca\/introductorychemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em>. <strong>License Terms<\/strong>: Download this book for free at http:\/\/open.bccampus.ca<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":23485,"menu_order":7,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Introductory Chemistry- 1st Canadian Edition \",\"author\":\"Jessie A. Key and David W. 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