{"id":2487,"date":"2019-04-22T18:11:07","date_gmt":"2019-04-22T18:11:07","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/chapter\/ions-and-ionic-compounds-2\/"},"modified":"2019-04-23T15:53:25","modified_gmt":"2019-04-23T15:53:25","slug":"ions-and-ionic-compounds-2","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/chapter\/ions-and-ionic-compounds-2\/","title":{"raw":"Ions and Ionic Compounds","rendered":"Ions and Ionic Compounds"},"content":{"raw":"<div>\r\n<div id=\"ball-ch03_s04\" class=\"section\" lang=\"en\">\r\n<div id=\"ball-ch03_s04_n01\" class=\"learning_objectives editable block\">\r\n<div class=\"bcc-box bcc-highlight\">\r\n<h3>Learning Objectives<\/h3>\r\n<ol id=\"ball-ch03_s04_l01\">\r\n \t<li>Know how ions form.<\/li>\r\n \t<li>Learn the characteristic charges that ions have.<\/li>\r\n \t<li>Construct a proper formula for an ionic compound.<\/li>\r\n \t<li>Generate a proper name for an ionic compound.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<p id=\"ball-ch03_s04_p01\" class=\"para editable block\">So far, we have discussed elements and compounds that are electrically neutral. They have the same number of electrons as protons, so the negative charges of the electrons is balanced by the positive charges of the protons. However, this is not always the case. Electrons can move from one atom to another; when they do, species with overall electric charges are formed. Such species are called <span class=\"margin_term\"><a class=\"glossterm\">ions<\/a><\/span>. Species with overall positive charges are termed <span class=\"margin_term\"><a class=\"glossterm\">cations<\/a><\/span>, while species with overall negative charges are called <span class=\"margin_term\"><a class=\"glossterm\">anions<\/a><\/span>. Remember that ions are formed only when <em class=\"emphasis\">electrons<\/em> move from one atom to another; a proton never moves from one atom to another. Compounds formed from positive and negative ions are called <span class=\"margin_term\"><a class=\"glossterm\">ionic compounds<\/a><\/span>.<\/p>\r\n<p id=\"ball-ch03_s04_p02\" class=\"para editable block\">Individual atoms can gain or lose electrons. When they do, they become <em class=\"emphasis\">monatomic<\/em> ions. When atoms gain or lose electrons, they usually gain or lose a characteristic number of electrons and so take on a characteristic overall charge. <a class=\"xref\" href=\"#ball-ch03_s04_t01\">Table 3.6 \"Monatomic Ions of Various Charges\"<\/a> lists some common ions in terms of how many electrons they lose (making cations) or gain (making anions). There are several things to notice about the ions in <a class=\"xref\" href=\"#ball-ch03_s04_t01\">Table 3.6 \"Monatomic Ions of Various Charges\"<\/a>. First, each element that forms cations is a metal, except for one (hydrogen), while each element that forms anions is a nonmetal. This is actually one of the chemical properties of metals and nonmetals: metals tend to form cations, while nonmetals tend to form anions. Second, most atoms form ions of a single characteristic charge. When sodium atoms form ions, they always form a 1+\u00a0charge, never a 2+\u00a0or 3+\u00a0or even 1\u2212 charge. Thus, if you commit the information in <a class=\"xref\" href=\"#ball-ch03_s04_t01\">Table 3.6 \"Monatomic Ions of Various Charges\"<\/a> to memory, you will always know what charges most atoms form. (In <a class=\"xref\" href=\"ball-ch09#ball-ch09\">Chapter 9 \"Chemical Bonds\"<\/a>, we will discuss <em class=\"emphasis\">why<\/em> atoms form the charges they do.)<\/p>\r\n\r\n<div id=\"ball-ch03_s04_t01\" class=\"table block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Table 3.6<\/span> Monatomic Ions of Various Charges<\/p>\r\n\r\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\r\n<tbody>\r\n<tr>\r\n<td rowspan=\"6\">Ions formed by losing a single electron<\/td>\r\n<td>H<sup class=\"superscript\">+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Na<sup class=\"superscript\">+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>K<sup class=\"superscript\">+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Rb<sup class=\"superscript\">+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Ag<sup class=\"superscript\">+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Au<sup class=\"superscript\">+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td rowspan=\"11\">Ions formed by losing two electrons<\/td>\r\n<td>Mg<sup class=\"superscript\">2+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Ca<sup class=\"superscript\">2+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sr<sup class=\"superscript\">2+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Fe<sup class=\"superscript\">2+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Co<sup class=\"superscript\">2+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Ni<sup class=\"superscript\">2+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Cu<sup class=\"superscript\">2+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Zn<sup class=\"superscript\">2+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sn<sup class=\"superscript\">2+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Hg<sup class=\"superscript\">2+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Pb<sup class=\"superscript\">2+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td rowspan=\"7\">Ions formed by losing three electrons<\/td>\r\n<td>Sc<sup class=\"superscript\">3+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Fe<sup class=\"superscript\">3+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Co<sup class=\"superscript\">3+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Ni<sup class=\"superscript\">3+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Au<sup class=\"superscript\">3+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Al<sup class=\"superscript\">3+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Cr<sup class=\"superscript\">3+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td rowspan=\"3\">Ions formed by losing four electrons<\/td>\r\n<td>Ti<sup class=\"superscript\">4+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sn<sup class=\"superscript\">4+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Pb<sup class=\"superscript\">4+<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td rowspan=\"4\">Ions formed by gaining a single electron<\/td>\r\n<td>F<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Cl<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Br<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>I<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td rowspan=\"3\">Ions formed by gaining two electrons<\/td>\r\n<td>O<sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>S<sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Se<sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td rowspan=\"2\">Ions formed by gaining three electrons<\/td>\r\n<td>N<sup class=\"superscript\">3\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>P<sup class=\"superscript\">3\u2212<\/sup><\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<p id=\"ball-ch03_s04_p03\" class=\"para editable block\">Third, there are some exceptions to the previous point. A few elements, all metals, can form more than one possible charge. For example, iron atoms can form 2+\u00a0cations or 3+\u00a0cations. Cobalt is another element that can form more than one possible charged ion (2+\u00a0and 3+), while lead can form 2+\u00a0or 4+\u00a0cations. Unfortunately, there is little understanding which two charges a metal atom may take, so it is best to just memorize the possible charges a particular element can have.<\/p>\r\n<p id=\"ball-ch03_s04_p04\" class=\"para editable block\">Note the convention for indicating an ion. The magnitude of the charge is listed as a right superscript next to the symbol of the element. If the charge is a single positive or negative one, the number 1 is not written; if the magnitude of the charge is greater than 1, then the number is written <em class=\"emphasis\">before<\/em> the +\u00a0or \u2212 sign. An element symbol without a charge written next to it is assumed to be the uncharged atom.<\/p>\r\n<p id=\"ball-ch03_s04_p05\" class=\"para editable block\">Naming an ion is straightforward. For a cation, simply use the name of the element and add the word <em class=\"emphasis\">ion<\/em> (or if you want to be more specific, add <em class=\"emphasis\">cation<\/em>) after the element\u2019s name. So Na<sup class=\"superscript\">+<\/sup> is the sodium ion; Ca<sup class=\"superscript\">2+<\/sup> is the calcium ion. If the element has more than one possible charge, the value of the charge comes after the element name and before the word <em class=\"emphasis\">ion<\/em>. Thus, Fe<sup class=\"superscript\">2+<\/sup> is the iron two ion, while Fe<sup class=\"superscript\">3+<\/sup> is the iron three ion. In print, we use roman numerals in parentheses to represent the charge on the ion, so these two iron ions would be represented as the iron(II) cation and the iron(III) cation, respectively.<\/p>\r\n<p id=\"ball-ch03_s04_p06\" class=\"para editable block\">For a monatomic anion, use the stem of the element name and append the suffix <em class=\"emphasis\">-ide<\/em> to it, and then add <em class=\"emphasis\">ion<\/em>. This is similar to how we named molecular compounds. Thus, Cl<sup class=\"superscript\">\u2212<\/sup> is the chloride ion, and N<sup class=\"superscript\">3\u2212<\/sup> is the nitride ion.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 6<\/h3>\r\n<p id=\"ball-ch03_s04_p07\" class=\"para\">Name each species.<\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l02\" class=\"orderedlist\">\r\n \t<li>O<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Co<\/li>\r\n \t<li>Co<sup class=\"superscript\">2+<\/sup><\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution<\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l03\" class=\"orderedlist\">\r\n \t<li>This species has a 2\u2212 charge on it, so it is an anion. Anions are named using the stem of the element name with the suffix <em class=\"emphasis\">-ide<\/em> added. This is the oxide anion.<\/li>\r\n \t<li>Because this species has no charge, it is an atom in its elemental form. This is cobalt.<\/li>\r\n \t<li>In this case, there is a 2+\u00a0charge on the atom, so it is a cation. We note from <a class=\"xref\" href=\"#ball-ch03_s04_t01\">Table 3.6 \"Monatomic Ions of Various Charges\"<\/a> that cobalt cations can have two possible charges, so the name of the ion must specify which charge the ion has. This is the cobalt(II) cation.<\/li>\r\n<\/ol>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch03_s04_p08\" class=\"para\">Name each species.<\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l04\" class=\"orderedlist\">\r\n \t<li>P<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Sr<sup class=\"superscript\">2+<\/sup><\/li>\r\n<\/ol>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answers<\/em><\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l05\" class=\"orderedlist\">\r\n \t<li>the phosphide anion<\/li>\r\n \t<li>the strontium cation<\/li>\r\n<\/ol>\r\n<\/div>\r\n<p id=\"ball-ch03_s04_p09\" class=\"para editable block\">Chemical formulas for ionic compounds are called <span class=\"margin_term\"><a class=\"glossterm\">ionic formulas<\/a><\/span>. A proper ionic formula has a cation and an anion in it; an ionic compound is never formed between two cations only or two anions only. The key to writing proper ionic formulas is simple: the total positive charge must balance the total negative charge. Because the charges on the ions are characteristic, sometimes we have to have more than one of a cation or an anion to balance the overall positive and negative charges. It is conventional to use the lowest ratio of ions that are needed to balance the charges.<\/p>\r\n<p id=\"ball-ch03_s04_p10\" class=\"para editable block\">For example, consider the ionic compound between Na<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup>. Each ion has a single charge, one positive and one negative, so we need only one ion of each to balance the overall charge. When writing the ionic formula, we follow two additional conventions: (1) write the formula for the cation first and the formula for the anion next, but (2) do not write the charges on the ions. Thus, for the compound between Na<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup>, we have the ionic formula NaCl (<a class=\"xref\" href=\"#ball-ch03_s04_f01\">Figure 3.5 \"NaCl = Table Salt\"<\/a>). The formula Na<sub class=\"subscript\">2<\/sub>Cl<sub class=\"subscript\">2<\/sub> also has balanced charges, but the convention is to use the lowest ratio of ions, which would be one of each. (Remember from our conventions for writing formulas that we don\u2019t write a 1 subscript if there is only one atom of a particular element present.) For the ionic compound between magnesium cations (Mg<sup class=\"superscript\">2+<\/sup>) and oxide anions (O<sup class=\"superscript\">2\u2212<\/sup>), again we need only one of each ion to balance the charges. By convention, the formula is MgO.<\/p>\r\n\r\n<div id=\"ball-ch03_s04_f01\" class=\"figure small editable block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Figure 3.5<\/span> NaCl = Table Salt<\/p>\r\n\r\n\r\n[caption id=\"attachment_3206\" align=\"alignnone\" width=\"400\"]<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/4377164898_fcc9a2407f_o.jpg\"><img class=\"wp-image-3206\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22181058\/4377164898_fcc9a2407f_o-1.jpg\" alt=\"The ionic compound NaCl is very common. Source: \u201cKosher Salt\u201d by stlbites.com is licensed under the Creative Commons Attribution-NoDerivs 2.0 Generic.\" width=\"400\" height=\"269\" \/><\/a> The ionic compound NaCl is very common.<br \/>Source: \u201cKosher Salt\u201d by stlbites.com is licensed under the Creative Commons Attribution-NoDerivs 2.0 Generic.[\/caption]\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"ball-ch03_s04_p11\" class=\"para editable block\">For the ionic compound between Mg<sup class=\"superscript\">2+<\/sup> ions and Cl<sup class=\"superscript\">\u2212<\/sup> ions, we now consider the fact that the charges have different magnitudes, 2+\u00a0on the magnesium ion and 1\u2212 on the chloride ion. To balance the charges with the lowest number of ions possible, we need to have two chloride ions to balance the charge on the one magnesium ion. Rather than write the formula MgClCl, we combine the two chloride ions and write it with a 2 subscript: MgCl<sub class=\"subscript\">2<\/sub>.<\/p>\r\n<p id=\"ball-ch03_s04_p12\" class=\"para editable block\">What is the formula MgCl<sub class=\"subscript\">2<\/sub> telling us? There are two chloride ions in the formula. Although chlorine as an element is a diatomic molecule, Cl<sub class=\"subscript\">2<\/sub>, elemental chlorine is not part of this ionic compound. The chlorine is in the form of a negatively charged <em class=\"emphasis\">ion<\/em>, not the neutral <em class=\"emphasis\">element<\/em>. The 2 subscript is in the ionic formula because we need two Cl<sup class=\"superscript\">\u2212<\/sup> ions to balance the charge on one Mg<sup class=\"superscript\">2+<\/sup> ion.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 7<\/h3>\r\n<p id=\"ball-ch03_s04_p13\" class=\"para\">Write the proper ionic formula for each of the two given ions.<\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l06\" class=\"orderedlist\">\r\n \t<li>Ca<sup class=\"superscript\">2+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Al<sup class=\"superscript\">3+<\/sup> and F<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Al<sup class=\"superscript\">3+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution<\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l07\" class=\"orderedlist\">\r\n \t<li>We need two Cl<sup class=\"superscript\">\u2212<\/sup> ions to balance the charge on one Ca<sup class=\"superscript\">2+<\/sup> ion, so the proper ionic formula is CaCl<sub class=\"subscript\">2<\/sub>.<\/li>\r\n \t<li>We need three F<sup class=\"superscript\">\u2212<\/sup> ions to balance the charge on the Al<sup class=\"superscript\">3+<\/sup> ion, so the proper ionic formula is AlF<sub class=\"subscript\">3<\/sub>.<\/li>\r\n \t<li>With Al<sup class=\"superscript\">3+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup>, note that neither charge is a perfect multiple of the other. This means we have to go to a least common multiple, which in this case will be six. To get a total of 6+, we need two Al<sup class=\"superscript\">3+<\/sup> ions; to get 6\u2212, we need three O<sup class=\"superscript\">2\u2212<\/sup> ions. Hence the proper ionic formula is Al<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>.<\/li>\r\n<\/ol>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch03_s04_p14\" class=\"para\">Write the proper ionic formulas for each of the two given ions.<\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l08\" class=\"orderedlist\">\r\n \t<li>Fe<sup class=\"superscript\">2+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Fe<sup class=\"superscript\">3+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answers<\/em><\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l09\" class=\"orderedlist\">\r\n \t<li>FeS<\/li>\r\n \t<li>Fe<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">3<\/sub><\/li>\r\n<\/ol>\r\n<\/div>\r\n<p id=\"ball-ch03_s04_p15\" class=\"para editable block\">Naming ionic compounds is simple: combine the name of the cation and the name of the anion, in both cases omitting the word <em class=\"emphasis\">ion<\/em>. <em class=\"emphasis\">Do not use numerical prefixes if there is more than one ion necessary to balance the charges.<\/em> NaCl is sodium chloride, a combination of the name of the cation (sodium) and the anion (chloride). MgO is magnesium oxide. MgCl<sub class=\"subscript\">2<\/sub> is magnesium chloride\u2014<em class=\"emphasis\">not<\/em> magnesium dichloride.<\/p>\r\n<p id=\"ball-ch03_s04_p16\" class=\"para editable block\">In naming ionic compounds whose cations can have more than one possible charge, we must also include the charge, in parentheses and in roman numerals, as part of the name. Hence FeS is iron(II) sulfide, while Fe<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">3<\/sub> is iron(III) sulfide. Again, no numerical prefixes appear in the name. The number of ions in the formula is dictated by the need to balance the positive and negative charges.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 8<\/h3>\r\n<p id=\"ball-ch03_s04_p17\" class=\"para\">Name each ionic compound.<\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l10\" class=\"orderedlist\">\r\n \t<li>CaCl<sub class=\"subscript\">2<\/sub><\/li>\r\n \t<li>AlF<sub class=\"subscript\">3<\/sub><\/li>\r\n \t<li>Co<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub><\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution<\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l11\" class=\"orderedlist\">\r\n \t<li>Using the names of the ions, this ionic compound is named calcium chloride. <em class=\"emphasis\">It is not calcium(II) chloride<\/em> because calcium forms only one cation when it forms an ion, and it has a characteristic charge of 2+.<\/li>\r\n \t<li>The name of this ionic compound is aluminum fluoride.<\/li>\r\n \t<li>We know that cobalt can have more than one possible charge; we just need to determine what it is. Oxide always has a 2\u2212 charge, so with three oxide ions, we have a total negative charge of 6\u2212. This means that the two cobalt ions have to contribute 6+, which for two cobalt ions means that each one is 3+. Therefore, the proper name for this ionic compound is cobalt(III) oxide.<\/li>\r\n<\/ol>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch03_s04_p18\" class=\"para\">Name each ionic compound.<\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l12\" class=\"orderedlist\">\r\n \t<li>Sc<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub><\/li>\r\n \t<li>AgCl<\/li>\r\n<\/ol>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answers<\/em><\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l13\" class=\"orderedlist\">\r\n \t<li>scandium oxide<\/li>\r\n \t<li>silver chloride<\/li>\r\n<\/ol>\r\n<\/div>\r\n<p id=\"ball-ch03_s04_p19\" class=\"para editable block\">How do you know whether a formula\u2014and by extension, a name\u2014is for a molecular compound or for an ionic compound? Molecular compounds form between nonmetals and nonmetals, while ionic compounds form between metals and nonmetals. The periodic table (<a class=\"xref\" href=\"ball-ch03_s01#ball-ch03_s01_f02\">Figure 3.2 \"A Simple Periodic Table\"<\/a>) can be used to determine which elements are metals and nonmetals.<\/p>\r\n<p id=\"ball-ch03_s04_p20\" class=\"para editable block\">There also exists a group of ions that contain more than one atom. These are called <span class=\"margin_term\"><a class=\"glossterm\">polyatomic ions<\/a><\/span>. <a class=\"xref\" href=\"#ball-ch03_s04_t02\">Table 3.7 \"Common Polyatomic Ions\"<\/a> lists the formulas, charges, and names of some common polyatomic ions. Only one of them, the ammonium ion, is a cation; the rest are anions. Most of them also contain oxygen atoms, so sometimes they are referred to as <em class=\"emphasis\">oxyanions<\/em>. Some of them, such as nitrate and nitrite, and sulfate and sulfite, have very similar formulas and names, so care must be taken to get the formulas and names correct. Note that the -ite polyatomic ion has one less oxygen atom in its formula than the -ate ion but with the same ionic charge.<\/p>\r\n\r\n<div id=\"ball-ch03_s04_t02\" class=\"table block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Table 3.7<\/span> Common Polyatomic Ions<\/p>\r\n\r\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Name<\/th>\r\n<th>Formula and Charge<\/th>\r\n<th><\/th>\r\n<th>Name<\/th>\r\n<th>Formula and Charge<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>ammonium<\/td>\r\n<td>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup><\/td>\r\n<td rowspan=\"9\"><\/td>\r\n<td>hydroxide<\/td>\r\n<td>OH<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>acetate<\/td>\r\n<td>C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup>, or CH<sub class=\"subscript\">3<\/sub>COO<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>nitrate<\/td>\r\n<td>NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>bicarbonate (hydrogen carbonate)<\/td>\r\n<td>HCO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>nitrite<\/td>\r\n<td>NO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>bisulfate (hydrogen sulfate)<\/td>\r\n<td>HSO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>peroxide<\/td>\r\n<td>O<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>carbonate<\/td>\r\n<td>CO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<td>perchlorate<\/td>\r\n<td>ClO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>chlorate<\/td>\r\n<td>ClO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>phosphate<\/td>\r\n<td>PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>chromate<\/td>\r\n<td>CrO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<td>sulfate<\/td>\r\n<td>SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>cyanide<\/td>\r\n<td>CN<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>sulfite<\/td>\r\n<td>SO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>dichromate<\/td>\r\n<td>Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<td>triiodide<\/td>\r\n<td>I<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<p id=\"ball-ch03_s04_p21\" class=\"para editable block\">The naming of ionic compounds that contain polyatomic ions follows the same rules as the naming for other ionic compounds: simply combine the name of the cation and the name of the anion. Do not use numerical prefixes in the name if there is more than one polyatomic ion; the only exception to this is if the name of the ion itself contains a numerical prefix, such as dichromate or triiodide.<\/p>\r\n<p id=\"ball-ch03_s04_p22\" class=\"para editable block\">Writing the formulas of ionic compounds has one important difference. If more than one polyatomic ion is needed to balance the overall charge in the formula, enclose the formula of the polyatomic ion in parentheses and write the proper numerical subscript to the right and <em class=\"emphasis\">outside<\/em> the parentheses. Thus, the formula between calcium ions, Ca<sup class=\"superscript\">2+<\/sup>, and nitrate ions, NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup>, is properly written Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>, not CaNO<sub class=\"subscript\">32<\/sub> or CaN<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">6<\/sub>. Use parentheses where required. The name of this ionic compound is simply calcium nitrate.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 9<\/h3>\r\n<p id=\"ball-ch03_s04_p23\" class=\"para\">Write the proper formula and give the proper name for each ionic compound formed between the two listed ions.<\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l14\" class=\"orderedlist\">\r\n \t<li>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Al<sup class=\"superscript\">3+<\/sup> and PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Fe<sup class=\"superscript\">2+<\/sup> and PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution<\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l15\" class=\"orderedlist\">\r\n \t<li>Because the ammonium ion has a 1+\u00a0charge and the sulfide ion has a 2\u2212 charge, we need two ammonium ions to balance the charge on a single sulfide ion. Enclosing the formula for the ammonium ion in parentheses, we have (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>S. The compound\u2019s name is ammonium sulfide.<\/li>\r\n \t<li>Because the ions have the same magnitude of charge, we need only one of each to balance the charges. The formula is AlPO<sub class=\"subscript\">4<\/sub>, and the name of the compound is aluminum phosphate.<\/li>\r\n \t<li>Neither charge is an exact multiple of the other, so we have to go to the least common multiple of 6. To get 6+, we need three iron(II) ions, and to get 6\u2212, we need two phosphate ions. The proper formula is Fe<sub class=\"subscript\">3<\/sub>(PO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>, and the compound\u2019s name is iron(II) phosphate.<\/li>\r\n<\/ol>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch03_s04_p24\" class=\"para\">Write the proper formula and give the proper name for each ionic compound formed between the two listed ions.<\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l16\" class=\"orderedlist\">\r\n \t<li>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Co<sup class=\"superscript\">3+<\/sup> and NO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\r\n<\/ol>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answers<\/em><\/p>\r\n\r\n<ol id=\"ball-ch03_s04_l17\" class=\"orderedlist\">\r\n \t<li>(NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub>, ammonium phosphate<\/li>\r\n \t<li>Co(NO<sub class=\"subscript\">2<\/sub>)<sub class=\"subscript\">3<\/sub>, cobalt(III) nitrite<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"ball-ch03_s04_n06\" class=\"callout block\">\r\n<h3 class=\"title\">Food and Drink App: Sodium in Your Food<\/h3>\r\n<p id=\"ball-ch03_s04_p25\" class=\"para\">The element sodium, at least in its ionic form as Na<sup class=\"superscript\">+<\/sup>, is a necessary nutrient for humans to live. In fact, the human body is approximately 0.15% sodium, with the average person having one-twentieth to one-tenth of a kilogram in their body at any given time, mostly in fluids outside cells and in other bodily fluids.<\/p>\r\n<p id=\"ball-ch03_s04_p26\" class=\"para\">Sodium is also present in our diet. The common table salt we use on our foods is an ionic sodium compound. Many processed foods also contain significant amounts of sodium added to them as a variety of ionic compounds. Why are sodium compounds used so much? Usually sodium compounds are inexpensive, but, more importantly, most ionic sodium compounds dissolve easily. This allows processed food manufacturers to add sodium-containing substances to food mixtures and know that the compound will dissolve and distribute evenly throughout the food. Simple ionic compounds such as sodium nitrite (NaNO<sub class=\"subscript\">2<\/sub>) are added to cured meats, such as bacon and deli-style meats, while a compound called sodium benzoate is added to many packaged foods as a preservative. <a class=\"xref\" href=\"#ball-ch03_s04_t03\">Table 3.8 \"Some Sodium Compounds Added to Food\"<\/a> is a partial list of some sodium additives used in food. Some of them you may recognize after reading this chapter. Others you may not recognize, but they are all ionic sodium compounds with some negatively charged ion also present.<\/p>\r\n\r\n<div id=\"ball-ch03_s04_t03\" class=\"table\">\r\n<p class=\"title\"><span class=\"title-prefix\">Table 3.8<\/span> Some Sodium Compounds Added to Food<\/p>\r\n\r\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Sodium Compound<\/th>\r\n<th>Use in Food<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>Sodium acetate<\/td>\r\n<td>preservative, acidity regulator<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium adipate<\/td>\r\n<td>food acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium alginate<\/td>\r\n<td>thickener, vegetable gum, stabilizer, gelling agent, emulsifier<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium aluminum phosphate<\/td>\r\n<td>acidity regulator, emulsifier<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium aluminosilicate<\/td>\r\n<td>anticaking agent<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium ascorbate<\/td>\r\n<td>antioxidant<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium benzoate<\/td>\r\n<td>preservative<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium bicarbonate<\/td>\r\n<td>mineral salt<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium bisulfite<\/td>\r\n<td>preservative, antioxidant<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium carbonate<\/td>\r\n<td>mineral salt<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium carboxymethylcellulose<\/td>\r\n<td>emulsifier<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium citrates<\/td>\r\n<td>food acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium dehydroacetate<\/td>\r\n<td>preservative<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium erythorbate<\/td>\r\n<td>antioxidant<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium erythorbin<\/td>\r\n<td>antioxidant<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium ethyl para-hydroxybenzoate<\/td>\r\n<td>preservative<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium ferrocyanide<\/td>\r\n<td>anticaking agent<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium formate<\/td>\r\n<td>preservative<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium fumarate<\/td>\r\n<td>food acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium gluconate<\/td>\r\n<td>stabilizer<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium hydrogen acetate<\/td>\r\n<td>preservative, acidity regulator<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium hydroxide<\/td>\r\n<td>mineral salt<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium lactate<\/td>\r\n<td>food acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium malate<\/td>\r\n<td>food acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium metabisulfite<\/td>\r\n<td>preservative, antioxidant, bleaching agent<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium methyl para-hydroxybenzoate<\/td>\r\n<td>preservative<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium nitrate<\/td>\r\n<td>preservative, color fixative<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium nitrite<\/td>\r\n<td>preservative, color fixative<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium orthophenyl phenol<\/td>\r\n<td>preservative<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium propionate<\/td>\r\n<td>preservative<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium propyl para-hydroxybenzoate<\/td>\r\n<td>preservative<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium sorbate<\/td>\r\n<td>preservative<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium stearoyl lactylate<\/td>\r\n<td>emulsifier<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium succinates<\/td>\r\n<td>acidity regulator, flavour enhancer<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium salts of fatty acids<\/td>\r\n<td>emulsifier, stabilizer, anticaking agent<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium sulfite<\/td>\r\n<td>mineral salt, preservative, antioxidant<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium sulfite<\/td>\r\n<td>preservative, antioxidant<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium tartrate<\/td>\r\n<td>food acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sodium tetraborate<\/td>\r\n<td>preservative<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<p id=\"ball-ch03_s04_p27\" class=\"para\">The use of so many sodium compounds in prepared and processed foods has alarmed some physicians and nutritionists. They argue that the average person consumes too much sodium from his or her diet. The average person needs only about 500 mg of sodium every day; most people consume more than this\u2014up to 10 times as much. Some studies have implicated increased sodium intake with high blood pressure; newer studies suggest that the link is questionable. However, there has been a push to reduce the amount of sodium most people ingest every day: avoid processed and manufactured foods, read labels on packaged foods (which include an indication of the sodium content), don\u2019t oversalt foods, and use other herbs and spices besides salt in cooking.<\/p>\r\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Nutrition-Facts1.png\"><img class=\"alignnone wp-image-4635\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22181104\/Nutrition-Facts1-1.png\" alt=\"Nutrition Facts\" width=\"258\" height=\"608\" \/><\/a><\/p>\r\n\r\n<div id=\"ball-ch03_s04_f02\" class=\"informalfigure medium\">\r\n<p class=\"para\">Food labels include the amount of sodium per serving. This particular label shows that there are 75 mg of sodium in one serving of this particular food item.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"ball-ch03_s04_n07\" class=\"key_takeaways editable block\">\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Key Takeaways<\/h3>\r\n<ul id=\"ball-ch03_s04_l18\" class=\"itemizedlist\">\r\n \t<li>Ions form when atoms lose or gain electrons.<\/li>\r\n \t<li>Ionic compounds have positive ions and negative ions.<\/li>\r\n \t<li>Ionic formulas balance the total positive and negative charges.<\/li>\r\n \t<li>Ionic compounds have a simple system of naming.<\/li>\r\n \t<li>Groups of atoms can have an overall charge and make ionic compounds.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Exercises<\/h3>\r\n<div id=\"ball-ch03_s04_qs01\" class=\"qandaset block\">\r\n<ol id=\"ball-ch03_s04_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"ball-ch03_s04_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p1\" class=\"para\">Explain how cations form.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch03_s04_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p3\" class=\"para\">Explain how anions form.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch03_s04_qs01_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p5\" class=\"para\">Give the charge each atom takes when it forms an ion. If more than one charge is possible, list both.<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\na) \u00a0K\r\n\r\nb) \u00a0O\r\n\r\nc) \u00a0Co\r\n\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p6\" class=\"para\">4. \u00a0Give the charge each atom takes when it forms an ion. If more than one charge is possible, list both.<\/p>\r\na) \u00a0Ca\r\n\r\nb) \u00a0I\r\n\r\nc) \u00a0Fe\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p7\" class=\"para\">5. \u00a0Give the charge each atom takes when it forms an ion. If more than one charge is possible, list both.<\/p>\r\na) \u00a0Ag\r\n\r\nb) \u00a0Au\r\n\r\nc) \u00a0Br\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p8\" class=\"para\">6. \u00a0Give the charge each atom takes when it forms an ion. If more than one charge is possible, list both.<\/p>\r\na) \u00a0S\r\n\r\nb) \u00a0Na\r\n\r\nc) \u00a0H\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p9\" class=\"para\">7. \u00a0Name the ions from Exercise 3.<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p10\" class=\"para\">8. \u00a0Name the ions from Exercise 4.<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p11\" class=\"para\">9 \u00a0Name the ions from Exercise 5.<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p12\" class=\"para\">10. \u00a0Name the ions from Exercise 6.<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p13\" class=\"para\">11. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\r\na) \u00a0Mg<sup class=\"superscript\">2+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup>\r\n\r\nb) \u00a0Fe<sup class=\"superscript\">2+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup>\r\n\r\nc) \u00a0Fe<sup class=\"superscript\">3+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p14\" class=\"para\">12. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\r\na) \u00a0K<sup class=\"superscript\">+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup>\r\n\r\nb) \u00a0Ag<sup class=\"superscript\">+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup>\r\n\r\nc) \u00a0Sr<sup class=\"superscript\">2+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p15\" class=\"para\">13. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\r\na) \u00a0Cu<sup class=\"superscript\">2+<\/sup> and F<sup class=\"superscript\">\u2212<\/sup>\r\n\r\nb) \u00a0Ca<sup class=\"superscript\">2+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup>\r\n\r\nc) \u00a0K<sup class=\"superscript\">+<\/sup> and P<sup class=\"superscript\">3\u2212<\/sup>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p16\" class=\"para\">14. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\r\na) \u00a0Na<sup class=\"superscript\">+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup>\r\n\r\nb) \u00a0Co<sup class=\"superscript\">2+<\/sup> and I<sup class=\"superscript\">\u2212<\/sup>\r\n\r\nc) \u00a0Au<sup class=\"superscript\">3+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p17\" class=\"para\">15. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\r\na) \u00a0K<sup class=\"superscript\">+<\/sup> and SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup>\r\n\r\nb) \u00a0NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup>\r\n\r\nc) \u00a0NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p18\" class=\"para\">16. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\r\na) \u00a0Ca<sup class=\"superscript\">2+<\/sup> and NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup>\r\n\r\nb) \u00a0Ca<sup class=\"superscript\">2+<\/sup> and NO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup>\r\n\r\nc) \u00a0Sc<sup class=\"superscript\">3+<\/sup> and C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p19\" class=\"para\">17. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\r\na) \u00a0Pb<sup class=\"superscript\">4+<\/sup> and SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup>\r\n\r\nb) \u00a0Na<sup class=\"superscript\">+<\/sup> and I<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup>\r\n\r\nc) \u00a0Li<sup class=\"superscript\">+<\/sup> and Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><sup class=\"superscript\">2\u2212<\/sup>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p20\" class=\"para\">18. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\r\na) \u00a0NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup>\r\n\r\nb) \u00a0Mg<sup class=\"superscript\">2+<\/sup> and CO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup>\r\n\r\nc) \u00a0Al<sup class=\"superscript\">3+<\/sup> and OH<sup class=\"superscript\">\u2212<\/sup>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p21\" class=\"para\">19. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\r\na) \u00a0Ag<sup class=\"superscript\">+<\/sup> and SO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup>\r\n\r\nb) \u00a0Na<sup class=\"superscript\">+<\/sup> and HCO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup>\r\n\r\nc) \u00a0Fe<sup class=\"superscript\">3+<\/sup> and ClO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p22\" class=\"para\">20. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\r\na) \u00a0Rb<sup class=\"superscript\">+<\/sup> and O<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2\u2212<\/sup>\r\n\r\nb) \u00a0Au<sup class=\"superscript\">3+<\/sup> and HSO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup>\r\n\r\nc) \u00a0Sr<sup class=\"superscript\">2+<\/sup> and NO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p23\" class=\"para\">21. \u00a0What is the difference between SO<sub class=\"subscript\">3<\/sub> and SO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup>?<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch03_s04_qs01_p25\" class=\"para\">22. \u00a0What is the difference between NO<sub class=\"subscript\">2<\/sub> and NO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup>?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<b>Answers<\/b>\r\n\r\n<strong>1.<\/strong>\r\n\r\nCations form by losing electrons.\r\n\r\n<strong>3.<\/strong>\r\n\r\na) \u00a01+\r\n\r\nb) \u00a02\u2212\r\n\r\nc) \u00a02+, 3+\r\n\r\n<strong>5.<\/strong>\r\n\r\na) \u00a01+\r\n\r\nb) \u00a01+, 3+\r\n\r\nc) \u00a01\u2212\r\n\r\n<strong>7.<\/strong>\r\n\r\na) \u00a0the potassium ion\r\n\r\nb) \u00a0the oxide ion\r\n\r\nc) \u00a0the cobalt(II) and cobalt(III) ions, respectively\r\n\r\n<strong>9.<\/strong>\r\n\r\na) \u00a0the silver ion\r\n\r\nb) \u00a0the gold(I) and gold(III) ions, respectively\r\n\r\nc) \u00a0the bromide ion\r\n\r\n<strong>11.<\/strong>\r\n\r\na) \u00a0magnesium chloride, MgCl<sub class=\"subscript\">2<\/sub>\r\n\r\nb) \u00a0iron(II) oxide, FeO\r\n\r\nc) \u00a0iron(III) oxide, Fe<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub><strong>13.<\/strong>\r\n\r\na) \u00a0copper(II) fluoride, CuF<sub class=\"subscript\">2<\/sub>\r\n\r\nb) \u00a0calcium oxide, CaO\r\n\r\nc) \u00a0potassium phosphide, K<sub class=\"subscript\">3<\/sub>P\r\n\r\n<strong>15.<\/strong>\r\n\r\na) \u00a0potassium sulfate, K<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>\r\n\r\nb) \u00a0ammonium sulfide, (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>S\r\n\r\nc) \u00a0ammonium phosphate, (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub><strong>17.<\/strong>\r\n\r\na) \u00a0lead(IV) sulfate, Pb(SO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>\r\n\r\nb) \u00a0sodium triiodide, NaI<sub class=\"subscript\">3<\/sub>\r\n\r\nc) \u00a0lithium dichromate, Li<sub class=\"subscript\">2<\/sub>Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><strong>19.<\/strong>\r\n\r\na) \u00a0silver sulfite, Ag<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">3<\/sub>\r\n\r\nb) \u00a0sodium hydrogen carbonate, NaHCO<sub class=\"subscript\">3<\/sub>\r\n\r\nc) \u00a0iron(III) chlorate, Fe(ClO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">3<\/sub><strong>21.<\/strong>\r\nSO<sub class=\"subscript\">3<\/sub> is sulfur trioxide, while SO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup> is the sulfite ion.\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div>\n<div id=\"ball-ch03_s04\" class=\"section\" lang=\"en\">\n<div id=\"ball-ch03_s04_n01\" class=\"learning_objectives editable block\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<ol id=\"ball-ch03_s04_l01\">\n<li>Know how ions form.<\/li>\n<li>Learn the characteristic charges that ions have.<\/li>\n<li>Construct a proper formula for an ionic compound.<\/li>\n<li>Generate a proper name for an ionic compound.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"ball-ch03_s04_p01\" class=\"para editable block\">So far, we have discussed elements and compounds that are electrically neutral. They have the same number of electrons as protons, so the negative charges of the electrons is balanced by the positive charges of the protons. However, this is not always the case. Electrons can move from one atom to another; when they do, species with overall electric charges are formed. Such species are called <span class=\"margin_term\"><a class=\"glossterm\">ions<\/a><\/span>. Species with overall positive charges are termed <span class=\"margin_term\"><a class=\"glossterm\">cations<\/a><\/span>, while species with overall negative charges are called <span class=\"margin_term\"><a class=\"glossterm\">anions<\/a><\/span>. Remember that ions are formed only when <em class=\"emphasis\">electrons<\/em> move from one atom to another; a proton never moves from one atom to another. Compounds formed from positive and negative ions are called <span class=\"margin_term\"><a class=\"glossterm\">ionic compounds<\/a><\/span>.<\/p>\n<p id=\"ball-ch03_s04_p02\" class=\"para editable block\">Individual atoms can gain or lose electrons. When they do, they become <em class=\"emphasis\">monatomic<\/em> ions. When atoms gain or lose electrons, they usually gain or lose a characteristic number of electrons and so take on a characteristic overall charge. <a class=\"xref\" href=\"#ball-ch03_s04_t01\">Table 3.6 &#8220;Monatomic Ions of Various Charges&#8221;<\/a> lists some common ions in terms of how many electrons they lose (making cations) or gain (making anions). There are several things to notice about the ions in <a class=\"xref\" href=\"#ball-ch03_s04_t01\">Table 3.6 &#8220;Monatomic Ions of Various Charges&#8221;<\/a>. First, each element that forms cations is a metal, except for one (hydrogen), while each element that forms anions is a nonmetal. This is actually one of the chemical properties of metals and nonmetals: metals tend to form cations, while nonmetals tend to form anions. Second, most atoms form ions of a single characteristic charge. When sodium atoms form ions, they always form a 1+\u00a0charge, never a 2+\u00a0or 3+\u00a0or even 1\u2212 charge. Thus, if you commit the information in <a class=\"xref\" href=\"#ball-ch03_s04_t01\">Table 3.6 &#8220;Monatomic Ions of Various Charges&#8221;<\/a> to memory, you will always know what charges most atoms form. (In <a class=\"xref\" href=\"ball-ch09#ball-ch09\">Chapter 9 &#8220;Chemical Bonds&#8221;<\/a>, we will discuss <em class=\"emphasis\">why<\/em> atoms form the charges they do.)<\/p>\n<div id=\"ball-ch03_s04_t01\" class=\"table block\">\n<p class=\"title\"><span class=\"title-prefix\">Table 3.6<\/span> Monatomic Ions of Various Charges<\/p>\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\n<tbody>\n<tr>\n<td rowspan=\"6\">Ions formed by losing a single electron<\/td>\n<td>H<sup class=\"superscript\">+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Na<sup class=\"superscript\">+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>K<sup class=\"superscript\">+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Rb<sup class=\"superscript\">+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Ag<sup class=\"superscript\">+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Au<sup class=\"superscript\">+<\/sup><\/td>\n<\/tr>\n<tr>\n<td rowspan=\"11\">Ions formed by losing two electrons<\/td>\n<td>Mg<sup class=\"superscript\">2+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Ca<sup class=\"superscript\">2+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Sr<sup class=\"superscript\">2+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Fe<sup class=\"superscript\">2+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Co<sup class=\"superscript\">2+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Ni<sup class=\"superscript\">2+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Cu<sup class=\"superscript\">2+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Zn<sup class=\"superscript\">2+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Sn<sup class=\"superscript\">2+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Hg<sup class=\"superscript\">2+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Pb<sup class=\"superscript\">2+<\/sup><\/td>\n<\/tr>\n<tr>\n<td rowspan=\"7\">Ions formed by losing three electrons<\/td>\n<td>Sc<sup class=\"superscript\">3+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Fe<sup class=\"superscript\">3+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Co<sup class=\"superscript\">3+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Ni<sup class=\"superscript\">3+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Au<sup class=\"superscript\">3+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Al<sup class=\"superscript\">3+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Cr<sup class=\"superscript\">3+<\/sup><\/td>\n<\/tr>\n<tr>\n<td rowspan=\"3\">Ions formed by losing four electrons<\/td>\n<td>Ti<sup class=\"superscript\">4+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Sn<sup class=\"superscript\">4+<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Pb<sup class=\"superscript\">4+<\/sup><\/td>\n<\/tr>\n<tr>\n<td rowspan=\"4\">Ions formed by gaining a single electron<\/td>\n<td>F<sup class=\"superscript\">\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Cl<sup class=\"superscript\">\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Br<sup class=\"superscript\">\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>I<sup class=\"superscript\">\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td rowspan=\"3\">Ions formed by gaining two electrons<\/td>\n<td>O<sup class=\"superscript\">2\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>S<sup class=\"superscript\">2\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>Se<sup class=\"superscript\">2\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td rowspan=\"2\">Ions formed by gaining three electrons<\/td>\n<td>N<sup class=\"superscript\">3\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>P<sup class=\"superscript\">3\u2212<\/sup><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p id=\"ball-ch03_s04_p03\" class=\"para editable block\">Third, there are some exceptions to the previous point. A few elements, all metals, can form more than one possible charge. For example, iron atoms can form 2+\u00a0cations or 3+\u00a0cations. Cobalt is another element that can form more than one possible charged ion (2+\u00a0and 3+), while lead can form 2+\u00a0or 4+\u00a0cations. Unfortunately, there is little understanding which two charges a metal atom may take, so it is best to just memorize the possible charges a particular element can have.<\/p>\n<p id=\"ball-ch03_s04_p04\" class=\"para editable block\">Note the convention for indicating an ion. The magnitude of the charge is listed as a right superscript next to the symbol of the element. If the charge is a single positive or negative one, the number 1 is not written; if the magnitude of the charge is greater than 1, then the number is written <em class=\"emphasis\">before<\/em> the +\u00a0or \u2212 sign. An element symbol without a charge written next to it is assumed to be the uncharged atom.<\/p>\n<p id=\"ball-ch03_s04_p05\" class=\"para editable block\">Naming an ion is straightforward. For a cation, simply use the name of the element and add the word <em class=\"emphasis\">ion<\/em> (or if you want to be more specific, add <em class=\"emphasis\">cation<\/em>) after the element\u2019s name. So Na<sup class=\"superscript\">+<\/sup> is the sodium ion; Ca<sup class=\"superscript\">2+<\/sup> is the calcium ion. If the element has more than one possible charge, the value of the charge comes after the element name and before the word <em class=\"emphasis\">ion<\/em>. Thus, Fe<sup class=\"superscript\">2+<\/sup> is the iron two ion, while Fe<sup class=\"superscript\">3+<\/sup> is the iron three ion. In print, we use roman numerals in parentheses to represent the charge on the ion, so these two iron ions would be represented as the iron(II) cation and the iron(III) cation, respectively.<\/p>\n<p id=\"ball-ch03_s04_p06\" class=\"para editable block\">For a monatomic anion, use the stem of the element name and append the suffix <em class=\"emphasis\">-ide<\/em> to it, and then add <em class=\"emphasis\">ion<\/em>. This is similar to how we named molecular compounds. Thus, Cl<sup class=\"superscript\">\u2212<\/sup> is the chloride ion, and N<sup class=\"superscript\">3\u2212<\/sup> is the nitride ion.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 6<\/h3>\n<p id=\"ball-ch03_s04_p07\" class=\"para\">Name each species.<\/p>\n<ol id=\"ball-ch03_s04_l02\" class=\"orderedlist\">\n<li>O<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Co<\/li>\n<li>Co<sup class=\"superscript\">2+<\/sup><\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<ol id=\"ball-ch03_s04_l03\" class=\"orderedlist\">\n<li>This species has a 2\u2212 charge on it, so it is an anion. Anions are named using the stem of the element name with the suffix <em class=\"emphasis\">-ide<\/em> added. This is the oxide anion.<\/li>\n<li>Because this species has no charge, it is an atom in its elemental form. This is cobalt.<\/li>\n<li>In this case, there is a 2+\u00a0charge on the atom, so it is a cation. We note from <a class=\"xref\" href=\"#ball-ch03_s04_t01\">Table 3.6 &#8220;Monatomic Ions of Various Charges&#8221;<\/a> that cobalt cations can have two possible charges, so the name of the ion must specify which charge the ion has. This is the cobalt(II) cation.<\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch03_s04_p08\" class=\"para\">Name each species.<\/p>\n<ol id=\"ball-ch03_s04_l04\" class=\"orderedlist\">\n<li>P<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Sr<sup class=\"superscript\">2+<\/sup><\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis\">Answers<\/em><\/p>\n<ol id=\"ball-ch03_s04_l05\" class=\"orderedlist\">\n<li>the phosphide anion<\/li>\n<li>the strontium cation<\/li>\n<\/ol>\n<\/div>\n<p id=\"ball-ch03_s04_p09\" class=\"para editable block\">Chemical formulas for ionic compounds are called <span class=\"margin_term\"><a class=\"glossterm\">ionic formulas<\/a><\/span>. A proper ionic formula has a cation and an anion in it; an ionic compound is never formed between two cations only or two anions only. The key to writing proper ionic formulas is simple: the total positive charge must balance the total negative charge. Because the charges on the ions are characteristic, sometimes we have to have more than one of a cation or an anion to balance the overall positive and negative charges. It is conventional to use the lowest ratio of ions that are needed to balance the charges.<\/p>\n<p id=\"ball-ch03_s04_p10\" class=\"para editable block\">For example, consider the ionic compound between Na<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup>. Each ion has a single charge, one positive and one negative, so we need only one ion of each to balance the overall charge. When writing the ionic formula, we follow two additional conventions: (1) write the formula for the cation first and the formula for the anion next, but (2) do not write the charges on the ions. Thus, for the compound between Na<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup>, we have the ionic formula NaCl (<a class=\"xref\" href=\"#ball-ch03_s04_f01\">Figure 3.5 &#8220;NaCl = Table Salt&#8221;<\/a>). The formula Na<sub class=\"subscript\">2<\/sub>Cl<sub class=\"subscript\">2<\/sub> also has balanced charges, but the convention is to use the lowest ratio of ions, which would be one of each. (Remember from our conventions for writing formulas that we don\u2019t write a 1 subscript if there is only one atom of a particular element present.) For the ionic compound between magnesium cations (Mg<sup class=\"superscript\">2+<\/sup>) and oxide anions (O<sup class=\"superscript\">2\u2212<\/sup>), again we need only one of each ion to balance the charges. By convention, the formula is MgO.<\/p>\n<div id=\"ball-ch03_s04_f01\" class=\"figure small editable block\">\n<p class=\"title\"><span class=\"title-prefix\">Figure 3.5<\/span> NaCl = Table Salt<\/p>\n<div id=\"attachment_3206\" style=\"width: 410px\" class=\"wp-caption alignnone\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/4377164898_fcc9a2407f_o.jpg\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-3206\" class=\"wp-image-3206\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22181058\/4377164898_fcc9a2407f_o-1.jpg\" alt=\"The ionic compound NaCl is very common. Source: \u201cKosher Salt\u201d by stlbites.com is licensed under the Creative Commons Attribution-NoDerivs 2.0 Generic.\" width=\"400\" height=\"269\" \/><\/a><\/p>\n<p id=\"caption-attachment-3206\" class=\"wp-caption-text\">The ionic compound NaCl is very common.<br \/>Source: \u201cKosher Salt\u201d by stlbites.com is licensed under the Creative Commons Attribution-NoDerivs 2.0 Generic.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p id=\"ball-ch03_s04_p11\" class=\"para editable block\">For the ionic compound between Mg<sup class=\"superscript\">2+<\/sup> ions and Cl<sup class=\"superscript\">\u2212<\/sup> ions, we now consider the fact that the charges have different magnitudes, 2+\u00a0on the magnesium ion and 1\u2212 on the chloride ion. To balance the charges with the lowest number of ions possible, we need to have two chloride ions to balance the charge on the one magnesium ion. Rather than write the formula MgClCl, we combine the two chloride ions and write it with a 2 subscript: MgCl<sub class=\"subscript\">2<\/sub>.<\/p>\n<p id=\"ball-ch03_s04_p12\" class=\"para editable block\">What is the formula MgCl<sub class=\"subscript\">2<\/sub> telling us? There are two chloride ions in the formula. Although chlorine as an element is a diatomic molecule, Cl<sub class=\"subscript\">2<\/sub>, elemental chlorine is not part of this ionic compound. The chlorine is in the form of a negatively charged <em class=\"emphasis\">ion<\/em>, not the neutral <em class=\"emphasis\">element<\/em>. The 2 subscript is in the ionic formula because we need two Cl<sup class=\"superscript\">\u2212<\/sup> ions to balance the charge on one Mg<sup class=\"superscript\">2+<\/sup> ion.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 7<\/h3>\n<p id=\"ball-ch03_s04_p13\" class=\"para\">Write the proper ionic formula for each of the two given ions.<\/p>\n<ol id=\"ball-ch03_s04_l06\" class=\"orderedlist\">\n<li>Ca<sup class=\"superscript\">2+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Al<sup class=\"superscript\">3+<\/sup> and F<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Al<sup class=\"superscript\">3+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<ol id=\"ball-ch03_s04_l07\" class=\"orderedlist\">\n<li>We need two Cl<sup class=\"superscript\">\u2212<\/sup> ions to balance the charge on one Ca<sup class=\"superscript\">2+<\/sup> ion, so the proper ionic formula is CaCl<sub class=\"subscript\">2<\/sub>.<\/li>\n<li>We need three F<sup class=\"superscript\">\u2212<\/sup> ions to balance the charge on the Al<sup class=\"superscript\">3+<\/sup> ion, so the proper ionic formula is AlF<sub class=\"subscript\">3<\/sub>.<\/li>\n<li>With Al<sup class=\"superscript\">3+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup>, note that neither charge is a perfect multiple of the other. This means we have to go to a least common multiple, which in this case will be six. To get a total of 6+, we need two Al<sup class=\"superscript\">3+<\/sup> ions; to get 6\u2212, we need three O<sup class=\"superscript\">2\u2212<\/sup> ions. Hence the proper ionic formula is Al<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub>.<\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch03_s04_p14\" class=\"para\">Write the proper ionic formulas for each of the two given ions.<\/p>\n<ol id=\"ball-ch03_s04_l08\" class=\"orderedlist\">\n<li>Fe<sup class=\"superscript\">2+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Fe<sup class=\"superscript\">3+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis\">Answers<\/em><\/p>\n<ol id=\"ball-ch03_s04_l09\" class=\"orderedlist\">\n<li>FeS<\/li>\n<li>Fe<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">3<\/sub><\/li>\n<\/ol>\n<\/div>\n<p id=\"ball-ch03_s04_p15\" class=\"para editable block\">Naming ionic compounds is simple: combine the name of the cation and the name of the anion, in both cases omitting the word <em class=\"emphasis\">ion<\/em>. <em class=\"emphasis\">Do not use numerical prefixes if there is more than one ion necessary to balance the charges.<\/em> NaCl is sodium chloride, a combination of the name of the cation (sodium) and the anion (chloride). MgO is magnesium oxide. MgCl<sub class=\"subscript\">2<\/sub> is magnesium chloride\u2014<em class=\"emphasis\">not<\/em> magnesium dichloride.<\/p>\n<p id=\"ball-ch03_s04_p16\" class=\"para editable block\">In naming ionic compounds whose cations can have more than one possible charge, we must also include the charge, in parentheses and in roman numerals, as part of the name. Hence FeS is iron(II) sulfide, while Fe<sub class=\"subscript\">2<\/sub>S<sub class=\"subscript\">3<\/sub> is iron(III) sulfide. Again, no numerical prefixes appear in the name. The number of ions in the formula is dictated by the need to balance the positive and negative charges.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 8<\/h3>\n<p id=\"ball-ch03_s04_p17\" class=\"para\">Name each ionic compound.<\/p>\n<ol id=\"ball-ch03_s04_l10\" class=\"orderedlist\">\n<li>CaCl<sub class=\"subscript\">2<\/sub><\/li>\n<li>AlF<sub class=\"subscript\">3<\/sub><\/li>\n<li>Co<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub><\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<ol id=\"ball-ch03_s04_l11\" class=\"orderedlist\">\n<li>Using the names of the ions, this ionic compound is named calcium chloride. <em class=\"emphasis\">It is not calcium(II) chloride<\/em> because calcium forms only one cation when it forms an ion, and it has a characteristic charge of 2+.<\/li>\n<li>The name of this ionic compound is aluminum fluoride.<\/li>\n<li>We know that cobalt can have more than one possible charge; we just need to determine what it is. Oxide always has a 2\u2212 charge, so with three oxide ions, we have a total negative charge of 6\u2212. This means that the two cobalt ions have to contribute 6+, which for two cobalt ions means that each one is 3+. Therefore, the proper name for this ionic compound is cobalt(III) oxide.<\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch03_s04_p18\" class=\"para\">Name each ionic compound.<\/p>\n<ol id=\"ball-ch03_s04_l12\" class=\"orderedlist\">\n<li>Sc<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub><\/li>\n<li>AgCl<\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis\">Answers<\/em><\/p>\n<ol id=\"ball-ch03_s04_l13\" class=\"orderedlist\">\n<li>scandium oxide<\/li>\n<li>silver chloride<\/li>\n<\/ol>\n<\/div>\n<p id=\"ball-ch03_s04_p19\" class=\"para editable block\">How do you know whether a formula\u2014and by extension, a name\u2014is for a molecular compound or for an ionic compound? Molecular compounds form between nonmetals and nonmetals, while ionic compounds form between metals and nonmetals. The periodic table (<a class=\"xref\" href=\"ball-ch03_s01#ball-ch03_s01_f02\">Figure 3.2 &#8220;A Simple Periodic Table&#8221;<\/a>) can be used to determine which elements are metals and nonmetals.<\/p>\n<p id=\"ball-ch03_s04_p20\" class=\"para editable block\">There also exists a group of ions that contain more than one atom. These are called <span class=\"margin_term\"><a class=\"glossterm\">polyatomic ions<\/a><\/span>. <a class=\"xref\" href=\"#ball-ch03_s04_t02\">Table 3.7 &#8220;Common Polyatomic Ions&#8221;<\/a> lists the formulas, charges, and names of some common polyatomic ions. Only one of them, the ammonium ion, is a cation; the rest are anions. Most of them also contain oxygen atoms, so sometimes they are referred to as <em class=\"emphasis\">oxyanions<\/em>. Some of them, such as nitrate and nitrite, and sulfate and sulfite, have very similar formulas and names, so care must be taken to get the formulas and names correct. Note that the -ite polyatomic ion has one less oxygen atom in its formula than the -ate ion but with the same ionic charge.<\/p>\n<div id=\"ball-ch03_s04_t02\" class=\"table block\">\n<p class=\"title\"><span class=\"title-prefix\">Table 3.7<\/span> Common Polyatomic Ions<\/p>\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\n<thead>\n<tr>\n<th>Name<\/th>\n<th>Formula and Charge<\/th>\n<th><\/th>\n<th>Name<\/th>\n<th>Formula and Charge<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>ammonium<\/td>\n<td>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup><\/td>\n<td rowspan=\"9\"><\/td>\n<td>hydroxide<\/td>\n<td>OH<sup class=\"superscript\">\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>acetate<\/td>\n<td>C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup>, or CH<sub class=\"subscript\">3<\/sub>COO<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>nitrate<\/td>\n<td>NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>bicarbonate (hydrogen carbonate)<\/td>\n<td>HCO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>nitrite<\/td>\n<td>NO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>bisulfate (hydrogen sulfate)<\/td>\n<td>HSO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>peroxide<\/td>\n<td>O<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>carbonate<\/td>\n<td>CO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/td>\n<td>perchlorate<\/td>\n<td>ClO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>chlorate<\/td>\n<td>ClO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>phosphate<\/td>\n<td>PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>chromate<\/td>\n<td>CrO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/td>\n<td>sulfate<\/td>\n<td>SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>cyanide<\/td>\n<td>CN<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>sulfite<\/td>\n<td>SO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/td>\n<\/tr>\n<tr>\n<td>dichromate<\/td>\n<td>Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/td>\n<td>triiodide<\/td>\n<td>I<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p id=\"ball-ch03_s04_p21\" class=\"para editable block\">The naming of ionic compounds that contain polyatomic ions follows the same rules as the naming for other ionic compounds: simply combine the name of the cation and the name of the anion. Do not use numerical prefixes in the name if there is more than one polyatomic ion; the only exception to this is if the name of the ion itself contains a numerical prefix, such as dichromate or triiodide.<\/p>\n<p id=\"ball-ch03_s04_p22\" class=\"para editable block\">Writing the formulas of ionic compounds has one important difference. If more than one polyatomic ion is needed to balance the overall charge in the formula, enclose the formula of the polyatomic ion in parentheses and write the proper numerical subscript to the right and <em class=\"emphasis\">outside<\/em> the parentheses. Thus, the formula between calcium ions, Ca<sup class=\"superscript\">2+<\/sup>, and nitrate ions, NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup>, is properly written Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>, not CaNO<sub class=\"subscript\">32<\/sub> or CaN<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">6<\/sub>. Use parentheses where required. The name of this ionic compound is simply calcium nitrate.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 9<\/h3>\n<p id=\"ball-ch03_s04_p23\" class=\"para\">Write the proper formula and give the proper name for each ionic compound formed between the two listed ions.<\/p>\n<ol id=\"ball-ch03_s04_l14\" class=\"orderedlist\">\n<li>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Al<sup class=\"superscript\">3+<\/sup> and PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Fe<sup class=\"superscript\">2+<\/sup> and PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<ol id=\"ball-ch03_s04_l15\" class=\"orderedlist\">\n<li>Because the ammonium ion has a 1+\u00a0charge and the sulfide ion has a 2\u2212 charge, we need two ammonium ions to balance the charge on a single sulfide ion. Enclosing the formula for the ammonium ion in parentheses, we have (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>S. The compound\u2019s name is ammonium sulfide.<\/li>\n<li>Because the ions have the same magnitude of charge, we need only one of each to balance the charges. The formula is AlPO<sub class=\"subscript\">4<\/sub>, and the name of the compound is aluminum phosphate.<\/li>\n<li>Neither charge is an exact multiple of the other, so we have to go to the least common multiple of 6. To get 6+, we need three iron(II) ions, and to get 6\u2212, we need two phosphate ions. The proper formula is Fe<sub class=\"subscript\">3<\/sub>(PO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>, and the compound\u2019s name is iron(II) phosphate.<\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch03_s04_p24\" class=\"para\">Write the proper formula and give the proper name for each ionic compound formed between the two listed ions.<\/p>\n<ol id=\"ball-ch03_s04_l16\" class=\"orderedlist\">\n<li>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Co<sup class=\"superscript\">3+<\/sup> and NO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis\">Answers<\/em><\/p>\n<ol id=\"ball-ch03_s04_l17\" class=\"orderedlist\">\n<li>(NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub>, ammonium phosphate<\/li>\n<li>Co(NO<sub class=\"subscript\">2<\/sub>)<sub class=\"subscript\">3<\/sub>, cobalt(III) nitrite<\/li>\n<\/ol>\n<\/div>\n<div id=\"ball-ch03_s04_n06\" class=\"callout block\">\n<h3 class=\"title\">Food and Drink App: Sodium in Your Food<\/h3>\n<p id=\"ball-ch03_s04_p25\" class=\"para\">The element sodium, at least in its ionic form as Na<sup class=\"superscript\">+<\/sup>, is a necessary nutrient for humans to live. In fact, the human body is approximately 0.15% sodium, with the average person having one-twentieth to one-tenth of a kilogram in their body at any given time, mostly in fluids outside cells and in other bodily fluids.<\/p>\n<p id=\"ball-ch03_s04_p26\" class=\"para\">Sodium is also present in our diet. The common table salt we use on our foods is an ionic sodium compound. Many processed foods also contain significant amounts of sodium added to them as a variety of ionic compounds. Why are sodium compounds used so much? Usually sodium compounds are inexpensive, but, more importantly, most ionic sodium compounds dissolve easily. This allows processed food manufacturers to add sodium-containing substances to food mixtures and know that the compound will dissolve and distribute evenly throughout the food. Simple ionic compounds such as sodium nitrite (NaNO<sub class=\"subscript\">2<\/sub>) are added to cured meats, such as bacon and deli-style meats, while a compound called sodium benzoate is added to many packaged foods as a preservative. <a class=\"xref\" href=\"#ball-ch03_s04_t03\">Table 3.8 &#8220;Some Sodium Compounds Added to Food&#8221;<\/a> is a partial list of some sodium additives used in food. Some of them you may recognize after reading this chapter. Others you may not recognize, but they are all ionic sodium compounds with some negatively charged ion also present.<\/p>\n<div id=\"ball-ch03_s04_t03\" class=\"table\">\n<p class=\"title\"><span class=\"title-prefix\">Table 3.8<\/span> Some Sodium Compounds Added to Food<\/p>\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\n<thead>\n<tr>\n<th>Sodium Compound<\/th>\n<th>Use in Food<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>Sodium acetate<\/td>\n<td>preservative, acidity regulator<\/td>\n<\/tr>\n<tr>\n<td>Sodium adipate<\/td>\n<td>food acid<\/td>\n<\/tr>\n<tr>\n<td>Sodium alginate<\/td>\n<td>thickener, vegetable gum, stabilizer, gelling agent, emulsifier<\/td>\n<\/tr>\n<tr>\n<td>Sodium aluminum phosphate<\/td>\n<td>acidity regulator, emulsifier<\/td>\n<\/tr>\n<tr>\n<td>Sodium aluminosilicate<\/td>\n<td>anticaking agent<\/td>\n<\/tr>\n<tr>\n<td>Sodium ascorbate<\/td>\n<td>antioxidant<\/td>\n<\/tr>\n<tr>\n<td>Sodium benzoate<\/td>\n<td>preservative<\/td>\n<\/tr>\n<tr>\n<td>Sodium bicarbonate<\/td>\n<td>mineral salt<\/td>\n<\/tr>\n<tr>\n<td>Sodium bisulfite<\/td>\n<td>preservative, antioxidant<\/td>\n<\/tr>\n<tr>\n<td>Sodium carbonate<\/td>\n<td>mineral salt<\/td>\n<\/tr>\n<tr>\n<td>Sodium carboxymethylcellulose<\/td>\n<td>emulsifier<\/td>\n<\/tr>\n<tr>\n<td>Sodium citrates<\/td>\n<td>food acid<\/td>\n<\/tr>\n<tr>\n<td>Sodium dehydroacetate<\/td>\n<td>preservative<\/td>\n<\/tr>\n<tr>\n<td>Sodium erythorbate<\/td>\n<td>antioxidant<\/td>\n<\/tr>\n<tr>\n<td>Sodium erythorbin<\/td>\n<td>antioxidant<\/td>\n<\/tr>\n<tr>\n<td>Sodium ethyl para-hydroxybenzoate<\/td>\n<td>preservative<\/td>\n<\/tr>\n<tr>\n<td>Sodium ferrocyanide<\/td>\n<td>anticaking agent<\/td>\n<\/tr>\n<tr>\n<td>Sodium formate<\/td>\n<td>preservative<\/td>\n<\/tr>\n<tr>\n<td>Sodium fumarate<\/td>\n<td>food acid<\/td>\n<\/tr>\n<tr>\n<td>Sodium gluconate<\/td>\n<td>stabilizer<\/td>\n<\/tr>\n<tr>\n<td>Sodium hydrogen acetate<\/td>\n<td>preservative, acidity regulator<\/td>\n<\/tr>\n<tr>\n<td>Sodium hydroxide<\/td>\n<td>mineral salt<\/td>\n<\/tr>\n<tr>\n<td>Sodium lactate<\/td>\n<td>food acid<\/td>\n<\/tr>\n<tr>\n<td>Sodium malate<\/td>\n<td>food acid<\/td>\n<\/tr>\n<tr>\n<td>Sodium metabisulfite<\/td>\n<td>preservative, antioxidant, bleaching agent<\/td>\n<\/tr>\n<tr>\n<td>Sodium methyl para-hydroxybenzoate<\/td>\n<td>preservative<\/td>\n<\/tr>\n<tr>\n<td>Sodium nitrate<\/td>\n<td>preservative, color fixative<\/td>\n<\/tr>\n<tr>\n<td>Sodium nitrite<\/td>\n<td>preservative, color fixative<\/td>\n<\/tr>\n<tr>\n<td>Sodium orthophenyl phenol<\/td>\n<td>preservative<\/td>\n<\/tr>\n<tr>\n<td>Sodium propionate<\/td>\n<td>preservative<\/td>\n<\/tr>\n<tr>\n<td>Sodium propyl para-hydroxybenzoate<\/td>\n<td>preservative<\/td>\n<\/tr>\n<tr>\n<td>Sodium sorbate<\/td>\n<td>preservative<\/td>\n<\/tr>\n<tr>\n<td>Sodium stearoyl lactylate<\/td>\n<td>emulsifier<\/td>\n<\/tr>\n<tr>\n<td>Sodium succinates<\/td>\n<td>acidity regulator, flavour enhancer<\/td>\n<\/tr>\n<tr>\n<td>Sodium salts of fatty acids<\/td>\n<td>emulsifier, stabilizer, anticaking agent<\/td>\n<\/tr>\n<tr>\n<td>Sodium sulfite<\/td>\n<td>mineral salt, preservative, antioxidant<\/td>\n<\/tr>\n<tr>\n<td>Sodium sulfite<\/td>\n<td>preservative, antioxidant<\/td>\n<\/tr>\n<tr>\n<td>Sodium tartrate<\/td>\n<td>food acid<\/td>\n<\/tr>\n<tr>\n<td>Sodium tetraborate<\/td>\n<td>preservative<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p id=\"ball-ch03_s04_p27\" class=\"para\">The use of so many sodium compounds in prepared and processed foods has alarmed some physicians and nutritionists. They argue that the average person consumes too much sodium from his or her diet. The average person needs only about 500 mg of sodium every day; most people consume more than this\u2014up to 10 times as much. Some studies have implicated increased sodium intake with high blood pressure; newer studies suggest that the link is questionable. However, there has been a push to reduce the amount of sodium most people ingest every day: avoid processed and manufactured foods, read labels on packaged foods (which include an indication of the sodium content), don\u2019t oversalt foods, and use other herbs and spices besides salt in cooking.<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Nutrition-Facts1.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4635\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22181104\/Nutrition-Facts1-1.png\" alt=\"Nutrition Facts\" width=\"258\" height=\"608\" \/><\/a><\/p>\n<div id=\"ball-ch03_s04_f02\" class=\"informalfigure medium\">\n<p class=\"para\">Food labels include the amount of sodium per serving. This particular label shows that there are 75 mg of sodium in one serving of this particular food item.<\/p>\n<\/div>\n<\/div>\n<div id=\"ball-ch03_s04_n07\" class=\"key_takeaways editable block\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul id=\"ball-ch03_s04_l18\" class=\"itemizedlist\">\n<li>Ions form when atoms lose or gain electrons.<\/li>\n<li>Ionic compounds have positive ions and negative ions.<\/li>\n<li>Ionic formulas balance the total positive and negative charges.<\/li>\n<li>Ionic compounds have a simple system of naming.<\/li>\n<li>Groups of atoms can have an overall charge and make ionic compounds.<\/li>\n<\/ul>\n<\/div>\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<div id=\"ball-ch03_s04_qs01\" class=\"qandaset block\">\n<ol id=\"ball-ch03_s04_qs01_qd01\" class=\"qandadiv\">\n<li id=\"ball-ch03_s04_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p1\" class=\"para\">Explain how cations form.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch03_s04_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p3\" class=\"para\">Explain how anions form.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch03_s04_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p5\" class=\"para\">Give the charge each atom takes when it forms an ion. If more than one charge is possible, list both.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<p>a) \u00a0K<\/p>\n<p>b) \u00a0O<\/p>\n<p>c) \u00a0Co<\/p>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p6\" class=\"para\">4. \u00a0Give the charge each atom takes when it forms an ion. If more than one charge is possible, list both.<\/p>\n<p>a) \u00a0Ca<\/p>\n<p>b) \u00a0I<\/p>\n<p>c) \u00a0Fe<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p7\" class=\"para\">5. \u00a0Give the charge each atom takes when it forms an ion. If more than one charge is possible, list both.<\/p>\n<p>a) \u00a0Ag<\/p>\n<p>b) \u00a0Au<\/p>\n<p>c) \u00a0Br<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p8\" class=\"para\">6. \u00a0Give the charge each atom takes when it forms an ion. If more than one charge is possible, list both.<\/p>\n<p>a) \u00a0S<\/p>\n<p>b) \u00a0Na<\/p>\n<p>c) \u00a0H<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p9\" class=\"para\">7. \u00a0Name the ions from Exercise 3.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p10\" class=\"para\">8. \u00a0Name the ions from Exercise 4.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p11\" class=\"para\">9 \u00a0Name the ions from Exercise 5.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p12\" class=\"para\">10. \u00a0Name the ions from Exercise 6.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p13\" class=\"para\">11. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\n<p>a) \u00a0Mg<sup class=\"superscript\">2+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/p>\n<p>b) \u00a0Fe<sup class=\"superscript\">2+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/p>\n<p>c) \u00a0Fe<sup class=\"superscript\">3+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p14\" class=\"para\">12. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\n<p>a) \u00a0K<sup class=\"superscript\">+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/p>\n<p>b) \u00a0Ag<sup class=\"superscript\">+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/p>\n<p>c) \u00a0Sr<sup class=\"superscript\">2+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p15\" class=\"para\">13. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\n<p>a) \u00a0Cu<sup class=\"superscript\">2+<\/sup> and F<sup class=\"superscript\">\u2212<\/sup><\/p>\n<p>b) \u00a0Ca<sup class=\"superscript\">2+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/p>\n<p>c) \u00a0K<sup class=\"superscript\">+<\/sup> and P<sup class=\"superscript\">3\u2212<\/sup><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p16\" class=\"para\">14. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\n<p>a) \u00a0Na<sup class=\"superscript\">+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/p>\n<p>b) \u00a0Co<sup class=\"superscript\">2+<\/sup> and I<sup class=\"superscript\">\u2212<\/sup><\/p>\n<p>c) \u00a0Au<sup class=\"superscript\">3+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p17\" class=\"para\">15. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\n<p>a) \u00a0K<sup class=\"superscript\">+<\/sup> and SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/p>\n<p>b) \u00a0NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/p>\n<p>c) \u00a0NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p18\" class=\"para\">16. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\n<p>a) \u00a0Ca<sup class=\"superscript\">2+<\/sup> and NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/p>\n<p>b) \u00a0Ca<sup class=\"superscript\">2+<\/sup> and NO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup><\/p>\n<p>c) \u00a0Sc<sup class=\"superscript\">3+<\/sup> and C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p19\" class=\"para\">17. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\n<p>a) \u00a0Pb<sup class=\"superscript\">4+<\/sup> and SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/p>\n<p>b) \u00a0Na<sup class=\"superscript\">+<\/sup> and I<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/p>\n<p>c) \u00a0Li<sup class=\"superscript\">+<\/sup> and Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p20\" class=\"para\">18. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\n<p>a) \u00a0NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/p>\n<p>b) \u00a0Mg<sup class=\"superscript\">2+<\/sup> and CO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/p>\n<p>c) \u00a0Al<sup class=\"superscript\">3+<\/sup> and OH<sup class=\"superscript\">\u2212<\/sup><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p21\" class=\"para\">19. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\n<p>a) \u00a0Ag<sup class=\"superscript\">+<\/sup> and SO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/p>\n<p>b) \u00a0Na<sup class=\"superscript\">+<\/sup> and HCO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/p>\n<p>c) \u00a0Fe<sup class=\"superscript\">3+<\/sup> and ClO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p22\" class=\"para\">20. \u00a0Give the formula and name for each ionic compound formed between the two listed ions.<\/p>\n<p>a) \u00a0Rb<sup class=\"superscript\">+<\/sup> and O<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/p>\n<p>b) \u00a0Au<sup class=\"superscript\">3+<\/sup> and HSO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/p>\n<p>c) \u00a0Sr<sup class=\"superscript\">2+<\/sup> and NO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p23\" class=\"para\">21. \u00a0What is the difference between SO<sub class=\"subscript\">3<\/sub> and SO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup>?<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch03_s04_qs01_p25\" class=\"para\">22. \u00a0What is the difference between NO<sub class=\"subscript\">2<\/sub> and NO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">\u2212<\/sup>?<\/p>\n<\/div>\n<\/div>\n<p><b>Answers<\/b><\/p>\n<p><strong>1.<\/strong><\/p>\n<p>Cations form by losing electrons.<\/p>\n<p><strong>3.<\/strong><\/p>\n<p>a) \u00a01+<\/p>\n<p>b) \u00a02\u2212<\/p>\n<p>c) \u00a02+, 3+<\/p>\n<p><strong>5.<\/strong><\/p>\n<p>a) \u00a01+<\/p>\n<p>b) \u00a01+, 3+<\/p>\n<p>c) \u00a01\u2212<\/p>\n<p><strong>7.<\/strong><\/p>\n<p>a) \u00a0the potassium ion<\/p>\n<p>b) \u00a0the oxide ion<\/p>\n<p>c) \u00a0the cobalt(II) and cobalt(III) ions, respectively<\/p>\n<p><strong>9.<\/strong><\/p>\n<p>a) \u00a0the silver ion<\/p>\n<p>b) \u00a0the gold(I) and gold(III) ions, respectively<\/p>\n<p>c) \u00a0the bromide ion<\/p>\n<p><strong>11.<\/strong><\/p>\n<p>a) \u00a0magnesium chloride, MgCl<sub class=\"subscript\">2<\/sub><\/p>\n<p>b) \u00a0iron(II) oxide, FeO<\/p>\n<p>c) \u00a0iron(III) oxide, Fe<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub><strong>13.<\/strong><\/p>\n<p>a) \u00a0copper(II) fluoride, CuF<sub class=\"subscript\">2<\/sub><\/p>\n<p>b) \u00a0calcium oxide, CaO<\/p>\n<p>c) \u00a0potassium phosphide, K<sub class=\"subscript\">3<\/sub>P<\/p>\n<p><strong>15.<\/strong><\/p>\n<p>a) \u00a0potassium sulfate, K<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/p>\n<p>b) \u00a0ammonium sulfide, (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>S<\/p>\n<p>c) \u00a0ammonium phosphate, (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub><strong>17.<\/strong><\/p>\n<p>a) \u00a0lead(IV) sulfate, Pb(SO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub><\/p>\n<p>b) \u00a0sodium triiodide, NaI<sub class=\"subscript\">3<\/sub><\/p>\n<p>c) \u00a0lithium dichromate, Li<sub class=\"subscript\">2<\/sub>Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><strong>19.<\/strong><\/p>\n<p>a) \u00a0silver sulfite, Ag<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">3<\/sub><\/p>\n<p>b) \u00a0sodium hydrogen carbonate, NaHCO<sub class=\"subscript\">3<\/sub><\/p>\n<p>c) \u00a0iron(III) chlorate, Fe(ClO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">3<\/sub><strong>21.<\/strong><br \/>\nSO<sub class=\"subscript\">3<\/sub> is sulfur trioxide, while SO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup> is the sulfite ion.<\/p>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-2487\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li><strong>Authored by<\/strong>: Jessie A. Key. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/opentextbc.ca\/introductorychemistry\/\">https:\/\/opentextbc.ca\/introductorychemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":89971,"menu_order":3,"template":"","meta":{"_candela_citation":"[{\"type\":\"original\",\"description\":\"\",\"author\":\"Jessie A. 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