{"id":2894,"date":"2019-04-22T18:42:56","date_gmt":"2019-04-22T18:42:56","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/chapter\/electron-transfer-ionic-bonds-2\/"},"modified":"2019-04-29T12:46:09","modified_gmt":"2019-04-29T12:46:09","slug":"electron-transfer-ionic-bonds-2","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/chapter\/electron-transfer-ionic-bonds-2\/","title":{"raw":"Electron Transfer: Ionic Bonds","rendered":"Electron Transfer: Ionic Bonds"},"content":{"raw":"<div>\r\n<div id=\"ball-ch09_s02\" class=\"section\" lang=\"en\">\r\n<div id=\"ball-ch09_s02_n01\" class=\"learning_objectives editable block\">\r\n<div class=\"bcc-box bcc-highlight\">\r\n<h3>Learning Objectives<\/h3>\r\n<ol id=\"ball-ch09_s02_l01\">\r\n \t<li>State the octet rule.<\/li>\r\n \t<li>Define <em>ionic bond<\/em>.<\/li>\r\n \t<li>Demonstrate electron transfer between atoms to form ionic bonds.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<p id=\"ball-ch09_s02_p01\" class=\"para editable block\">In <a class=\"xref\" href=\"ball-ch09_s01#ball-ch09_s01\">Section 9.1 \"Lewis Electron Dot Diagrams,\"<\/a>\u00a0we saw how ions are formed by losing electrons to make cations or by gaining electrons to form anions. The astute reader may have noticed something: Many of the ions that form have eight electrons in their valence shell. Either atoms gain enough electrons to have eight electrons in the valence shell and become the appropriately charged anion, or they lose the electrons in their original valence shell. The <em class=\"emphasis\">lower<\/em> shell, now the valence shell, has eight electrons in it, so the atom becomes positively charged. For whatever reason, having eight electrons in a valence shell is a particularly energetically stable arrangement of electrons. The trend that atoms like to have eight electrons in their valence shell is called the <em><span class=\"margin_term\"><a class=\"glossterm\">octet rule<\/a><\/span><\/em>. When atoms form compounds, the octet rule is not always satisfied for all atoms at all times, but it is a very good rule of thumb for understanding the kinds of bonding arrangements that atoms can make.<\/p>\r\n<p id=\"ball-ch09_s02_p02\" class=\"para editable block\">It is not impossible to violate the octet rule. Consider sodium: in its elemental form, it has one valence electron and is stable. It is rather reactive, however, and does not require a lot of energy to remove that electron to make the Na<sup class=\"superscript\">+<\/sup> ion. We <em class=\"emphasis\">could<\/em> remove another electron by adding even more energy to the ion, to make the Na<sup class=\"superscript\">2+<\/sup> ion. However, that requires much more energy than is normally available in chemical reactions, so sodium stops at a 1+\u00a0charge after losing a single electron. It turns out that the Na<sup class=\"superscript\">+<\/sup> ion has a complete octet in its new valence shell, the <em class=\"emphasis\">n<\/em> = 2 shell, which satisfies the octet rule. The octet rule is a result of trends in energies and is useful in explaining why atoms form the ions that they do.<\/p>\r\n<p id=\"ball-ch09_s02_p03\" class=\"para editable block\">Now consider an Na atom in the presence of a Cl atom. The two atoms have these Lewis electron dot diagrams and electron configurations:<\/p>\r\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/NaCl-1.png\"><img class=\"alignnone wp-image-4387\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184210\/NaCl-1-1.png\" alt=\"NaCl-1\" width=\"400\" height=\"60\" \/><\/a><\/p>\r\n<p id=\"ball-ch09_s02_p04\" class=\"para editable block\">For the Na atom to obtain an octet, it must lose an electron; for the Cl atom to gain an octet, it must gain an electron. An electron transfers from the Na atom to the Cl atom:<\/p>\r\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/NaCl-2.png\"><img class=\"alignnone wp-image-4388\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184213\/NaCl-2-1.png\" alt=\"NaCl-2\" width=\"400\" height=\"60\" \/><\/a><\/p>\r\n<p id=\"ball-ch09_s02_p05\" class=\"para editable block\">resulting in two ions\u2014the Na<sup class=\"superscript\">+<\/sup> ion and the Cl<sup class=\"superscript\">\u2212<\/sup> ion:<\/p>\r\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/NaCl-3.png\"><img class=\"alignnone wp-image-4389\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184215\/NaCl-3-1.png\" alt=\"NaCl-3\" width=\"400\" height=\"70\" \/><\/a><\/p>\r\n<p id=\"ball-ch09_s02_p06\" class=\"para editable block\">Both species now have complete octets, and the electron shells are energetically stable. From basic physics, we know that opposite charges attract. This is what happens to the Na<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup> ions:<\/p>\r\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/NaCl-4.png\"><img class=\"alignnone wp-image-4390\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184227\/NaCl-4-1.png\" alt=\"NaCl-4\" width=\"400\" height=\"40\" \/><\/a><\/p>\r\n<p id=\"ball-ch09_s02_p07\" class=\"para editable block\">where we have written the final formula (the formula for sodium chloride) as per the convention for ionic compounds, without listing the charges explicitly. The attraction between oppositely charged ions is called an <em><span class=\"margin_term\"><a class=\"glossterm\">ionic bond<\/a><\/span><\/em>, and it is one of the main types of chemical bonds in chemistry. Ionic bonds are caused by electrons <em class=\"emphasis\">transferring<\/em> from one atom to another.<\/p>\r\n<p id=\"ball-ch09_s02_p08\" class=\"para editable block\">In electron transfer, the number of electrons lost must equal the number of electrons gained. We saw this in the formation of NaCl. A similar process occurs between Mg atoms and O atoms, except in this case two electrons are transferred:<\/p>\r\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/MgO-1.png\"><img class=\"alignnone wp-image-4385\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184230\/MgO-1-1.png\" alt=\"MgO-1\" width=\"400\" height=\"60\" \/><\/a><\/p>\r\n<p id=\"ball-ch09_s02_p09\" class=\"para editable block\">The two ions each have octets as their valence shell, and the two oppositely charged particles attract, making an ionic bond:<\/p>\r\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/MgO-2.png\"><img class=\"alignnone wp-image-4386\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184232\/MgO-2-1.png\" alt=\"MgO-2\" width=\"400\" height=\"40\" \/><\/a><\/p>\r\n<p id=\"ball-ch09_s02_p10\" class=\"para editable block\">Remember, in the final formula for the ionic compound, we do not write the charges on the ions.<\/p>\r\n<p id=\"ball-ch09_s02_p11\" class=\"para editable block\">What about when an Na atom interacts with an O atom? The O atom needs two electrons to complete its valence octet, but the Na atom supplies only one electron:<\/p>\r\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/NaO-1.png\"><img class=\"alignnone wp-image-4391\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184234\/NaO-1-1.png\" alt=\"NaO-1\" width=\"400\" height=\"40\" \/><\/a><\/p>\r\n<p id=\"ball-ch09_s02_p12\" class=\"para editable block\">The O atom still does not have an octet of electrons. What we need is a second Na atom to donate a second electron to the O atom:<\/p>\r\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/NaO-2.png\"><img class=\"alignnone wp-image-4392\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184237\/NaO-2-1.png\" alt=\"NaO-2\" width=\"400\" height=\"70\" \/><\/a><\/p>\r\n<p id=\"ball-ch09_s02_p13\" class=\"para editable block\">These three ions attract each other to give an overall neutral-charged ionic compound, which we write as Na<sub class=\"subscript\">2<\/sub>O. The need for the number of electrons lost being equal to the number of electrons gained explains why ionic compounds have the ratio of cations to anions that they do. This is required by the law of conservation of matter as well.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 3<\/h3>\r\n<p id=\"ball-ch09_s02_p14\" class=\"para\">With arrows, illustrate the transfer of electrons to form calcium chloride from Ca atoms and Cl atoms.<\/p>\r\n<p class=\"simpara\">Solution<\/p>\r\n<p id=\"ball-ch09_s02_p15\" class=\"para\">A Ca atom has two valence electrons, while a Cl atom has seven electrons. A Cl atom needs only one more to complete its octet, while Ca atoms have two electrons to lose. Thus we need two Cl atoms to accept the two electrons from one Ca atom. The transfer process looks like this:<\/p>\r\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/CaCl-1.png\"><img class=\"alignnone wp-image-4382\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184239\/CaCl-1-1.png\" alt=\"CaCl-1\" width=\"400\" height=\"80\" \/><\/a><\/p>\r\n\r\n<div class=\"informalfigure large\"><\/div>\r\n<p id=\"ball-ch09_s02_p16\" class=\"para\">The oppositely charged ions attract each other to make CaCl<sub class=\"subscript\">2<\/sub>.<\/p>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch09_s02_p17\" class=\"para\">With arrows, illustrate the transfer of electrons to form potassium sulfide from K atoms and S atoms.<\/p>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\r\n<p class=\"simpara\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/KS-1.png\"><img class=\"alignnone wp-image-4384\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184241\/KS-1-1.png\" alt=\"KS-1\" width=\"400\" height=\"80\" \/><\/a><\/p>\r\n\r\n<div class=\"informalfigure large\"><\/div>\r\n<\/div>\r\n<p id=\"ball-ch09_s02_p18\" class=\"para editable block\">The strength of ionic bonding depends on two major characteristics: the magnitude of the charges and the size of the ion. The greater the magnitude of the charge, the stronger the ionic bond. The smaller the ion, the stronger the ionic bond (because a smaller ion size allows the ions to get closer together). The measured strength of ionic bonding is called the <em><span class=\"margin_term\"><a class=\"glossterm\">lattice energy<\/a><\/span><\/em>. Some lattice energies are given in <a class=\"xref\" href=\"#ball-ch09_s02_t01\">Table 9.1 \"Lattice Energies of Some Ionic Compounds.\"<\/a><\/p>\r\n\r\n<div id=\"ball-ch09_s02_t01\" class=\"table block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Table 9.1<\/span> Lattice Energies of Some Ionic Compounds<\/p>\r\n\r\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Compound<\/th>\r\n<th align=\"right\">Lattice Energy (kJ\/mol)<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>LiF<\/td>\r\n<td align=\"right\">1,036<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>LiCl<\/td>\r\n<td align=\"right\">853<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>NaCl<\/td>\r\n<td align=\"right\">786<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>NaBr<\/td>\r\n<td align=\"right\">747<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>MgF<sub class=\"subscript\">2<\/sub><\/td>\r\n<td align=\"right\">2,957<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Na<sub class=\"subscript\">2<\/sub>O<\/td>\r\n<td align=\"right\">2,481<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>MgO<\/td>\r\n<td align=\"right\">3,791<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<div id=\"ball-ch09_s02_n03\" class=\"callout block\">\r\n<h3 class=\"title\">Chemistry Is Everywhere: Salt<\/h3>\r\n<p id=\"ball-ch09_s02_p19\" class=\"para\">The element sodium (part [a] in the accompanying figure) is a very reactive metal; given the opportunity, it will react with the sweat on your hands and form sodium hydroxide, which is a very corrosive substance. The element chlorine (part [b] in the accompanying figure) is a pale yellow, corrosive gas that should not be inhaled due to its poisonous nature. Bring these two hazardous substances together, however, and they react to make the ionic compound sodium chloride (part [c] in the accompanying figure), known simply as salt.<\/p>\r\n\r\n<div id=\"ball-ch09_s02_f01\" class=\"figure medium\">\r\n<p class=\"title\"><span class=\"title-prefix\">Figure 9.1<\/span> Sodium +\u00a0Chlorine = Sodium Chloride<\/p>\r\n\r\n<div class=\"copyright\">\r\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/element.png\"><img class=\"alignnone wp-image-3230\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184248\/element-1024x477-1.png\" alt=\"element\" width=\"400\" height=\"187\" \/><\/a><\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<p id=\"ball-ch09_s02_p21\" class=\"para\">(a) Sodium is a very reactive metal. (b) Chlorine is a pale yellow, noxious gas. (c) Together, sodium and chlorine make sodium chloride\u2014salt\u2014which is necessary for our survival.<\/p>\r\n<p class=\"para\">Salt is necessary for life. Na<sup class=\"superscript\">+<\/sup> ions are one of the main ions in the human body and are necessary to regulate the fluid balance in the body. Cl<sup class=\"superscript\">\u2212<\/sup> ions are necessary for proper nerve function and respiration. Both of these ions are supplied by salt. The taste of salt is one of the fundamental tastes; salt is probably the most ancient flavouring known, and one of the few rocks we eat.<\/p>\r\n<p id=\"ball-ch09_s02_p22\" class=\"para\">The health effects of too much salt are still under debate, although a 2010 report by the US Department of Agriculture concluded that \u201cexcessive sodium intake\u2026raises blood pressure, a well-accepted and extraordinarily common risk factor for stroke, coronary heart disease, and kidney disease.\u201d<span id=\"fwk-ball-fn09_001\" class=\"footnote\">[footnote]US Department of Agriculture Committee for Nutrition Policy and Promotion, \u201cReport of the Dietary Guidelines Advisory Committee on the Dietary Guidelines for Americans,\u201d accessed January 5, 2010, http:\/\/www.cnpp.usda.gov\/DGAs2010-DGACReport.htm[\/footnote]<\/span> It is clear that most people ingest more salt than their bodies need, and most nutritionists recommend curbing salt intake. Curiously, people who suffer from low salt (called <em class=\"emphasis\">hyponatria<\/em>) do so not because they ingest too little salt but because they drink too much water. Endurance athletes and others involved in extended strenuous exercise need to watch their water intake so their body\u2019s salt content is not diluted to dangerous levels.<\/p>\r\n\r\n<\/div>\r\n<div id=\"ball-ch09_s02_n04\" class=\"key_takeaways editable block\">\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Key Takeaways<\/h3>\r\n<ul id=\"ball-ch09_s02_l02\" class=\"itemizedlist\">\r\n \t<li>The tendency to form species that have eight electrons in the valence shell is called the octet rule.<\/li>\r\n \t<li>The attraction of oppositely charged ions caused by electron transfer is called an ionic bond.<\/li>\r\n \t<li>The strength of ionic bonding depends on the magnitude of the charges and the sizes of the ions.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Exercises<\/h3>\r\n<div id=\"ball-ch09_s02_qs01\" class=\"qandaset block\">\r\n<ol id=\"ball-ch09_s02_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p01\" class=\"para\">Comment on the possible formation of the K<sup class=\"superscript\">2+<\/sup> ion. Why is its formation unlikely?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p03\" class=\"para\">Comment on the possible formation of the Cl<sup class=\"superscript\">2\u2212<\/sup> ion. Why is its formation unlikely?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p05\" class=\"para\">How many electrons does a Ba atom have to lose to have a complete octet in its valence shell?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p07\" class=\"para\">How many electrons does a Pb atom have to lose to have a complete octet in its valence shell?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p09\" class=\"para\">How many electrons does an Se atom have to gain to have a complete octet in its valence shell?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa06\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p11\" class=\"para\">How many electrons does an N atom have to gain to have a complete octet in its valence shell?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa07\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p13\" class=\"para\">With arrows, illustrate the transfer of electrons to form potassium chloride from K atoms and Cl atoms.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa08\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p14\" class=\"para\">With arrows, illustrate the transfer of electrons to form magnesium sulfide from Mg atoms and S atoms.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa09\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p15\" class=\"para\">With arrows, illustrate the transfer of electrons to form scandium fluoride from Sc atoms and F atoms.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa10\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p16\" class=\"para\">With arrows, illustrate the transfer of electrons to form rubidium phosphide from Rb atoms and P atoms.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa11\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p17\" class=\"para\">Which ionic compound has the higher lattice energy\u2014KI or MgO? Why?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa12\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p19\" class=\"para\">Which ionic compound has the higher lattice energy\u2014KI or LiF? Why?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa13\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p21\" class=\"para\">Which ionic compound has the higher lattice energy\u2014BaS or MgO? Why?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch09_s02_qs01_qd01_qa14\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch09_s02_qs01_p23\" class=\"para\">Which ionic compound has the higher lattice energy\u2014NaCl or NaI? Why?<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<b>Answers<\/b>\r\n\r\n<strong>1.<\/strong>\r\n\r\nThe K<sup class=\"superscript\">2+<\/sup> ion is unlikely to form because the K<sup class=\"superscript\">+<\/sup> ion already satisfies the octet rule and is rather stable.\r\n\r\n<strong>3.<\/strong>\r\n\r\ntwo\r\n\r\n<strong>5.<\/strong>\r\n\r\ntwo\r\n\r\n<strong>7.<\/strong>\r\n\r\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/KCl-1.png\"><img class=\"alignnone wp-image-4383\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184251\/KCl-1-1.png\" alt=\"KCl-1\" width=\"400\" height=\"49\" \/><\/a>\r\n\r\n&nbsp;\r\n\r\n<strong>9.<\/strong>\r\n\r\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/ScF-1.png\"><img class=\"alignnone wp-image-4393\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184254\/ScF-1-1.png\" alt=\"ScF-1\" width=\"400\" height=\"94\" \/><\/a>\r\n\r\n&nbsp;\r\n\r\n<strong>11.<\/strong>\r\n\r\nMgO because the ions have a higher magnitude charge\r\n\r\n<strong>13.<\/strong>\r\n\r\nMgO because the ions are smaller\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div>\n<div id=\"ball-ch09_s02\" class=\"section\" lang=\"en\">\n<div id=\"ball-ch09_s02_n01\" class=\"learning_objectives editable block\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<ol id=\"ball-ch09_s02_l01\">\n<li>State the octet rule.<\/li>\n<li>Define <em>ionic bond<\/em>.<\/li>\n<li>Demonstrate electron transfer between atoms to form ionic bonds.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"ball-ch09_s02_p01\" class=\"para editable block\">In <a class=\"xref\" href=\"ball-ch09_s01#ball-ch09_s01\">Section 9.1 &#8220;Lewis Electron Dot Diagrams,&#8221;<\/a>\u00a0we saw how ions are formed by losing electrons to make cations or by gaining electrons to form anions. The astute reader may have noticed something: Many of the ions that form have eight electrons in their valence shell. Either atoms gain enough electrons to have eight electrons in the valence shell and become the appropriately charged anion, or they lose the electrons in their original valence shell. The <em class=\"emphasis\">lower<\/em> shell, now the valence shell, has eight electrons in it, so the atom becomes positively charged. For whatever reason, having eight electrons in a valence shell is a particularly energetically stable arrangement of electrons. The trend that atoms like to have eight electrons in their valence shell is called the <em><span class=\"margin_term\"><a class=\"glossterm\">octet rule<\/a><\/span><\/em>. When atoms form compounds, the octet rule is not always satisfied for all atoms at all times, but it is a very good rule of thumb for understanding the kinds of bonding arrangements that atoms can make.<\/p>\n<p id=\"ball-ch09_s02_p02\" class=\"para editable block\">It is not impossible to violate the octet rule. Consider sodium: in its elemental form, it has one valence electron and is stable. It is rather reactive, however, and does not require a lot of energy to remove that electron to make the Na<sup class=\"superscript\">+<\/sup> ion. We <em class=\"emphasis\">could<\/em> remove another electron by adding even more energy to the ion, to make the Na<sup class=\"superscript\">2+<\/sup> ion. However, that requires much more energy than is normally available in chemical reactions, so sodium stops at a 1+\u00a0charge after losing a single electron. It turns out that the Na<sup class=\"superscript\">+<\/sup> ion has a complete octet in its new valence shell, the <em class=\"emphasis\">n<\/em> = 2 shell, which satisfies the octet rule. The octet rule is a result of trends in energies and is useful in explaining why atoms form the ions that they do.<\/p>\n<p id=\"ball-ch09_s02_p03\" class=\"para editable block\">Now consider an Na atom in the presence of a Cl atom. The two atoms have these Lewis electron dot diagrams and electron configurations:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/NaCl-1.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4387\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184210\/NaCl-1-1.png\" alt=\"NaCl-1\" width=\"400\" height=\"60\" \/><\/a><\/p>\n<p id=\"ball-ch09_s02_p04\" class=\"para editable block\">For the Na atom to obtain an octet, it must lose an electron; for the Cl atom to gain an octet, it must gain an electron. An electron transfers from the Na atom to the Cl atom:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/NaCl-2.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4388\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184213\/NaCl-2-1.png\" alt=\"NaCl-2\" width=\"400\" height=\"60\" \/><\/a><\/p>\n<p id=\"ball-ch09_s02_p05\" class=\"para editable block\">resulting in two ions\u2014the Na<sup class=\"superscript\">+<\/sup> ion and the Cl<sup class=\"superscript\">\u2212<\/sup> ion:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/NaCl-3.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4389\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184215\/NaCl-3-1.png\" alt=\"NaCl-3\" width=\"400\" height=\"70\" \/><\/a><\/p>\n<p id=\"ball-ch09_s02_p06\" class=\"para editable block\">Both species now have complete octets, and the electron shells are energetically stable. From basic physics, we know that opposite charges attract. This is what happens to the Na<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup> ions:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/NaCl-4.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4390\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184227\/NaCl-4-1.png\" alt=\"NaCl-4\" width=\"400\" height=\"40\" \/><\/a><\/p>\n<p id=\"ball-ch09_s02_p07\" class=\"para editable block\">where we have written the final formula (the formula for sodium chloride) as per the convention for ionic compounds, without listing the charges explicitly. The attraction between oppositely charged ions is called an <em><span class=\"margin_term\"><a class=\"glossterm\">ionic bond<\/a><\/span><\/em>, and it is one of the main types of chemical bonds in chemistry. Ionic bonds are caused by electrons <em class=\"emphasis\">transferring<\/em> from one atom to another.<\/p>\n<p id=\"ball-ch09_s02_p08\" class=\"para editable block\">In electron transfer, the number of electrons lost must equal the number of electrons gained. We saw this in the formation of NaCl. A similar process occurs between Mg atoms and O atoms, except in this case two electrons are transferred:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/MgO-1.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4385\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184230\/MgO-1-1.png\" alt=\"MgO-1\" width=\"400\" height=\"60\" \/><\/a><\/p>\n<p id=\"ball-ch09_s02_p09\" class=\"para editable block\">The two ions each have octets as their valence shell, and the two oppositely charged particles attract, making an ionic bond:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/MgO-2.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4386\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184232\/MgO-2-1.png\" alt=\"MgO-2\" width=\"400\" height=\"40\" \/><\/a><\/p>\n<p id=\"ball-ch09_s02_p10\" class=\"para editable block\">Remember, in the final formula for the ionic compound, we do not write the charges on the ions.<\/p>\n<p id=\"ball-ch09_s02_p11\" class=\"para editable block\">What about when an Na atom interacts with an O atom? The O atom needs two electrons to complete its valence octet, but the Na atom supplies only one electron:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/NaO-1.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4391\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184234\/NaO-1-1.png\" alt=\"NaO-1\" width=\"400\" height=\"40\" \/><\/a><\/p>\n<p id=\"ball-ch09_s02_p12\" class=\"para editable block\">The O atom still does not have an octet of electrons. What we need is a second Na atom to donate a second electron to the O atom:<\/p>\n<p class=\"para editable block\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/NaO-2.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4392\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184237\/NaO-2-1.png\" alt=\"NaO-2\" width=\"400\" height=\"70\" \/><\/a><\/p>\n<p id=\"ball-ch09_s02_p13\" class=\"para editable block\">These three ions attract each other to give an overall neutral-charged ionic compound, which we write as Na<sub class=\"subscript\">2<\/sub>O. The need for the number of electrons lost being equal to the number of electrons gained explains why ionic compounds have the ratio of cations to anions that they do. This is required by the law of conservation of matter as well.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 3<\/h3>\n<p id=\"ball-ch09_s02_p14\" class=\"para\">With arrows, illustrate the transfer of electrons to form calcium chloride from Ca atoms and Cl atoms.<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch09_s02_p15\" class=\"para\">A Ca atom has two valence electrons, while a Cl atom has seven electrons. A Cl atom needs only one more to complete its octet, while Ca atoms have two electrons to lose. Thus we need two Cl atoms to accept the two electrons from one Ca atom. The transfer process looks like this:<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/CaCl-1.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4382\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184239\/CaCl-1-1.png\" alt=\"CaCl-1\" width=\"400\" height=\"80\" \/><\/a><\/p>\n<div class=\"informalfigure large\"><\/div>\n<p id=\"ball-ch09_s02_p16\" class=\"para\">The oppositely charged ions attract each other to make CaCl<sub class=\"subscript\">2<\/sub>.<\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch09_s02_p17\" class=\"para\">With arrows, illustrate the transfer of electrons to form potassium sulfide from K atoms and S atoms.<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p class=\"simpara\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/KS-1.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4384\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184241\/KS-1-1.png\" alt=\"KS-1\" width=\"400\" height=\"80\" \/><\/a><\/p>\n<div class=\"informalfigure large\"><\/div>\n<\/div>\n<p id=\"ball-ch09_s02_p18\" class=\"para editable block\">The strength of ionic bonding depends on two major characteristics: the magnitude of the charges and the size of the ion. The greater the magnitude of the charge, the stronger the ionic bond. The smaller the ion, the stronger the ionic bond (because a smaller ion size allows the ions to get closer together). The measured strength of ionic bonding is called the <em><span class=\"margin_term\"><a class=\"glossterm\">lattice energy<\/a><\/span><\/em>. Some lattice energies are given in <a class=\"xref\" href=\"#ball-ch09_s02_t01\">Table 9.1 &#8220;Lattice Energies of Some Ionic Compounds.&#8221;<\/a><\/p>\n<div id=\"ball-ch09_s02_t01\" class=\"table block\">\n<p class=\"title\"><span class=\"title-prefix\">Table 9.1<\/span> Lattice Energies of Some Ionic Compounds<\/p>\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\n<thead>\n<tr>\n<th>Compound<\/th>\n<th align=\"right\">Lattice Energy (kJ\/mol)<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>LiF<\/td>\n<td align=\"right\">1,036<\/td>\n<\/tr>\n<tr>\n<td>LiCl<\/td>\n<td align=\"right\">853<\/td>\n<\/tr>\n<tr>\n<td>NaCl<\/td>\n<td align=\"right\">786<\/td>\n<\/tr>\n<tr>\n<td>NaBr<\/td>\n<td align=\"right\">747<\/td>\n<\/tr>\n<tr>\n<td>MgF<sub class=\"subscript\">2<\/sub><\/td>\n<td align=\"right\">2,957<\/td>\n<\/tr>\n<tr>\n<td>Na<sub class=\"subscript\">2<\/sub>O<\/td>\n<td align=\"right\">2,481<\/td>\n<\/tr>\n<tr>\n<td>MgO<\/td>\n<td align=\"right\">3,791<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<div id=\"ball-ch09_s02_n03\" class=\"callout block\">\n<h3 class=\"title\">Chemistry Is Everywhere: Salt<\/h3>\n<p id=\"ball-ch09_s02_p19\" class=\"para\">The element sodium (part [a] in the accompanying figure) is a very reactive metal; given the opportunity, it will react with the sweat on your hands and form sodium hydroxide, which is a very corrosive substance. The element chlorine (part [b] in the accompanying figure) is a pale yellow, corrosive gas that should not be inhaled due to its poisonous nature. Bring these two hazardous substances together, however, and they react to make the ionic compound sodium chloride (part [c] in the accompanying figure), known simply as salt.<\/p>\n<div id=\"ball-ch09_s02_f01\" class=\"figure medium\">\n<p class=\"title\"><span class=\"title-prefix\">Figure 9.1<\/span> Sodium +\u00a0Chlorine = Sodium Chloride<\/p>\n<div class=\"copyright\">\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/element.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-3230\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184248\/element-1024x477-1.png\" alt=\"element\" width=\"400\" height=\"187\" \/><\/a><\/p>\n<\/div>\n<\/div>\n<\/div>\n<p id=\"ball-ch09_s02_p21\" class=\"para\">(a) Sodium is a very reactive metal. (b) Chlorine is a pale yellow, noxious gas. (c) Together, sodium and chlorine make sodium chloride\u2014salt\u2014which is necessary for our survival.<\/p>\n<p class=\"para\">Salt is necessary for life. Na<sup class=\"superscript\">+<\/sup> ions are one of the main ions in the human body and are necessary to regulate the fluid balance in the body. Cl<sup class=\"superscript\">\u2212<\/sup> ions are necessary for proper nerve function and respiration. Both of these ions are supplied by salt. The taste of salt is one of the fundamental tastes; salt is probably the most ancient flavouring known, and one of the few rocks we eat.<\/p>\n<p id=\"ball-ch09_s02_p22\" class=\"para\">The health effects of too much salt are still under debate, although a 2010 report by the US Department of Agriculture concluded that \u201cexcessive sodium intake\u2026raises blood pressure, a well-accepted and extraordinarily common risk factor for stroke, coronary heart disease, and kidney disease.\u201d<span id=\"fwk-ball-fn09_001\" class=\"footnote\"><a class=\"footnote\" title=\"US Department of Agriculture Committee for Nutrition Policy and Promotion, \u201cReport of the Dietary Guidelines Advisory Committee on the Dietary Guidelines for Americans,\u201d accessed January 5, 2010, http:\/\/www.cnpp.usda.gov\/DGAs2010-DGACReport.htm\" id=\"return-footnote-2894-1\" href=\"#footnote-2894-1\" aria-label=\"Footnote 1\"><sup class=\"footnote\">[1]<\/sup><\/a><\/span> It is clear that most people ingest more salt than their bodies need, and most nutritionists recommend curbing salt intake. Curiously, people who suffer from low salt (called <em class=\"emphasis\">hyponatria<\/em>) do so not because they ingest too little salt but because they drink too much water. Endurance athletes and others involved in extended strenuous exercise need to watch their water intake so their body\u2019s salt content is not diluted to dangerous levels.<\/p>\n<\/div>\n<div id=\"ball-ch09_s02_n04\" class=\"key_takeaways editable block\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul id=\"ball-ch09_s02_l02\" class=\"itemizedlist\">\n<li>The tendency to form species that have eight electrons in the valence shell is called the octet rule.<\/li>\n<li>The attraction of oppositely charged ions caused by electron transfer is called an ionic bond.<\/li>\n<li>The strength of ionic bonding depends on the magnitude of the charges and the sizes of the ions.<\/li>\n<\/ul>\n<\/div>\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<div id=\"ball-ch09_s02_qs01\" class=\"qandaset block\">\n<ol id=\"ball-ch09_s02_qs01_qd01\" class=\"qandadiv\">\n<li id=\"ball-ch09_s02_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p01\" class=\"para\">Comment on the possible formation of the K<sup class=\"superscript\">2+<\/sup> ion. Why is its formation unlikely?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p03\" class=\"para\">Comment on the possible formation of the Cl<sup class=\"superscript\">2\u2212<\/sup> ion. Why is its formation unlikely?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p05\" class=\"para\">How many electrons does a Ba atom have to lose to have a complete octet in its valence shell?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p07\" class=\"para\">How many electrons does a Pb atom have to lose to have a complete octet in its valence shell?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p09\" class=\"para\">How many electrons does an Se atom have to gain to have a complete octet in its valence shell?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p11\" class=\"para\">How many electrons does an N atom have to gain to have a complete octet in its valence shell?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p13\" class=\"para\">With arrows, illustrate the transfer of electrons to form potassium chloride from K atoms and Cl atoms.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p14\" class=\"para\">With arrows, illustrate the transfer of electrons to form magnesium sulfide from Mg atoms and S atoms.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p15\" class=\"para\">With arrows, illustrate the transfer of electrons to form scandium fluoride from Sc atoms and F atoms.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa10\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p16\" class=\"para\">With arrows, illustrate the transfer of electrons to form rubidium phosphide from Rb atoms and P atoms.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa11\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p17\" class=\"para\">Which ionic compound has the higher lattice energy\u2014KI or MgO? Why?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa12\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p19\" class=\"para\">Which ionic compound has the higher lattice energy\u2014KI or LiF? Why?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa13\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p21\" class=\"para\">Which ionic compound has the higher lattice energy\u2014BaS or MgO? Why?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch09_s02_qs01_qd01_qa14\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch09_s02_qs01_p23\" class=\"para\">Which ionic compound has the higher lattice energy\u2014NaCl or NaI? Why?<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<p><b>Answers<\/b><\/p>\n<p><strong>1.<\/strong><\/p>\n<p>The K<sup class=\"superscript\">2+<\/sup> ion is unlikely to form because the K<sup class=\"superscript\">+<\/sup> ion already satisfies the octet rule and is rather stable.<\/p>\n<p><strong>3.<\/strong><\/p>\n<p>two<\/p>\n<p><strong>5.<\/strong><\/p>\n<p>two<\/p>\n<p><strong>7.<\/strong><\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/KCl-1.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4383\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184251\/KCl-1-1.png\" alt=\"KCl-1\" width=\"400\" height=\"49\" \/><\/a><\/p>\n<p>&nbsp;<\/p>\n<p><strong>9.<\/strong><\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/ScF-1.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4393\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184254\/ScF-1-1.png\" alt=\"ScF-1\" width=\"400\" height=\"94\" \/><\/a><\/p>\n<p>&nbsp;<\/p>\n<p><strong>11.<\/strong><\/p>\n<p>MgO because the ions have a higher magnitude charge<\/p>\n<p><strong>13.<\/strong><\/p>\n<p>MgO because the ions are smaller<\/p>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-2894\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li><strong>Authored by<\/strong>: Jessie A. Key. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/opentextbc.ca\/introductorychemistry\/\">https:\/\/opentextbc.ca\/introductorychemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section><hr class=\"before-footnotes clear\" \/><div class=\"footnotes\"><ol><li id=\"footnote-2894-1\">US Department of Agriculture Committee for Nutrition Policy and Promotion, \u201cReport of the Dietary Guidelines Advisory Committee on the Dietary Guidelines for Americans,\u201d accessed January 5, 2010, http:\/\/www.cnpp.usda.gov\/DGAs2010-DGACReport.htm <a href=\"#return-footnote-2894-1\" class=\"return-footnote\" aria-label=\"Return to footnote 1\">&crarr;<\/a><\/li><\/ol><\/div>","protected":false},"author":89971,"menu_order":3,"template":"","meta":{"_candela_citation":"[{\"type\":\"original\",\"description\":\"\",\"author\":\"Jessie A. Key\",\"organization\":\"\",\"url\":\"https:\/\/opentextbc.ca\/introductorychemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc-sa\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-2894","chapter","type-chapter","status-publish","hentry"],"part":2851,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/2894","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/wp\/v2\/users\/89971"}],"version-history":[{"count":2,"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/2894\/revisions"}],"predecessor-version":[{"id":3825,"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/2894\/revisions\/3825"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/parts\/2851"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/2894\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/wp\/v2\/media?parent=2894"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=2894"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/wp\/v2\/contributor?post=2894"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/wp\/v2\/license?post=2894"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}