{"id":3048,"date":"2019-04-22T18:48:58","date_gmt":"2019-04-22T18:48:58","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/chapter\/phase-transitions-melting-boiling-and-subliming-2\/"},"modified":"2019-04-23T14:37:43","modified_gmt":"2019-04-23T14:37:43","slug":"phase-transitions-melting-boiling-and-subliming-2","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/chapter\/phase-transitions-melting-boiling-and-subliming-2\/","title":{"raw":"Phase Transitions: Melting, Boiling, and Subliming","rendered":"Phase Transitions: Melting, Boiling, and Subliming"},"content":{"raw":"<div id=\"ball-ch10_s02\" class=\"section\" lang=\"en\">\r\n<div id=\"ball-ch10_s02_n01\" class=\"learning_objectives editable block\">\r\n<div class=\"bcc-box bcc-highlight\">\r\n<h3>Learning Objectives<\/h3>\r\n<ol id=\"ball-ch10_s02_l01\">\r\n \t<li>Describe what happens during a phase change.<\/li>\r\n \t<li>Calculate the energy change needed for a phase change.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<p id=\"ball-ch10_s02_p01\" class=\"para editable block\">Substances can change phase\u2014often because of a temperature change. At low temperatures, most substances are solid; as the temperature increases, they become liquid; at higher temperatures still, they become gaseous.<\/p>\r\n<p id=\"ball-ch10_s02_p02\" class=\"para editable block\">The process of a solid becoming a liquid is called <span class=\"margin_term\"><a class=\"glossterm\">melting<\/a><span class=\"glossdef\">.<\/span><\/span> (an older term that you may see sometimes is <em class=\"emphasis\">fusion<\/em>). The opposite process, a liquid becoming a solid, is called <span class=\"margin_term\"><a class=\"glossterm\">solidification<\/a><\/span>. For any pure substance, the temperature at which melting occurs\u2014known as the <span class=\"margin_term\"><a class=\"glossterm\">melting point<\/a><\/span>\u2014is a characteristic of that substance. It requires energy for a solid to melt into a liquid. Every pure substance has a certain amount of energy it needs to change from a solid to a liquid. This amount is called the <span class=\"margin_term\"><a class=\"glossterm\">enthalpy of fusion (or heat of fusion)<\/a><\/span>\u00a0of the substance, represented as \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub>. Some \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> values are listed in <a class=\"xref\" href=\"#ball-ch10_s02_t01\">Table 10.2 \"Enthalpies of Fusion for Various Substances\"<\/a>; it is assumed that these values are for the melting point of the substance. Note that the unit of \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> is kilojoules per mole, so we need to know the quantity of material to know how much energy is involved. The \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> is always tabulated as a positive number. However, it can be used for both the melting and the solidification processes as long as you keep in mind that melting is always endothermic (so \u0394<em class=\"emphasis\">H<\/em> will be positive), while solidification is always exothermic (so \u0394<em class=\"emphasis\">H<\/em> will be negative).<\/p>\r\n\r\n<div id=\"ball-ch10_s02_t01\" class=\"table block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Table 10.2<\/span> Enthalpies of Fusion for Various Substances<\/p>\r\n\r\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Substance (Melting Point)<\/th>\r\n<th align=\"right\">\u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> (kJ\/mol)<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>Water (0\u00b0C)<\/td>\r\n<td align=\"right\">6.01<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Aluminum (660\u00b0C)<\/td>\r\n<td align=\"right\">10.7<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Benzene (5.5\u00b0C)<\/td>\r\n<td align=\"right\">9.95<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Ethanol (\u2212114.3\u00b0C)<\/td>\r\n<td align=\"right\">5.02<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Mercury (\u221238.8\u00b0C)<\/td>\r\n<td align=\"right\">2.29<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 2<\/h3>\r\n<p id=\"ball-ch10_s02_p03\" class=\"para\">What is the energy change when 45.7 g of H<sub class=\"subscript\">2<\/sub>O melt at 0\u00b0C?<\/p>\r\n<p class=\"simpara\">Solution<\/p>\r\n<p id=\"ball-ch10_s02_p04\" class=\"para\">The \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> of H<sub class=\"subscript\">2<\/sub>O is 6.01 kJ\/mol. However, our quantity is given in units of grams, not moles, so the first step is to convert grams to moles using the molar mass of H<sub class=\"subscript\">2<\/sub>O, which is 18.0 g\/mol. Then we can use \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> as a conversion factor. Because the substance is melting, the process is endothermic, so the energy change will have a positive sign.<\/p>\r\n<span class=\"informalequation\">45.7\u00a0g\u00a0H<sub>2<\/sub>O \u00d7 (1\u00a0mol\u00a0H<sub>2<\/sub>O\/18.0\u00a0g H<sub>2<\/sub>O) \u00d7 (6.01\u00a0kJ\/ 1\u00a0mol H<sub>2<\/sub>O) = 15.3\u00a0kJ<\/span>\r\n<p id=\"ball-ch10_s02_p05\" class=\"para\">Without a sign, the number is assumed to be positive.<\/p>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch10_s02_p06\" class=\"para\">What is the energy change when 108 g of C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">6<\/sub> freeze at 5.5\u00b0C?<\/p>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\r\n<p id=\"ball-ch10_s02_p07\" class=\"para\">\u221213.8 kJ<\/p>\r\n\r\n<\/div>\r\n<p id=\"ball-ch10_s02_p08\" class=\"para editable block\">During melting, energy goes exclusively to changing the phase of a substance; it does not go into changing the temperature of a substance. Hence melting is an <span class=\"margin_term\"><a class=\"glossterm\">isothermal<\/a><\/span>\u00a0process because a substance stays at the same temperature. Only when all of a substance is melted does any additional energy go to changing its temperature.<\/p>\r\n<p id=\"ball-ch10_s02_p09\" class=\"para editable block\">What happens when a solid becomes a liquid? In a solid, individual particles are stuck in place because the intermolecular forces cannot be overcome by the energy of the particles. When more energy is supplied (e.g., by raising the temperature), there comes a point at which the particles have enough energy to move around but not enough energy to separate. This is the liquid phase: particles are still in contact but are able to move around each other. This explains why liquids can assume the shape of their containers: the particles move around and, under the influence of gravity, fill the lowest volume possible (unless the liquid is in a zero-gravity environment\u2014see <a class=\"xref\" href=\"#ball-ch10_s02_f01\">Figure 10.3 \"Liquids and Gravity\"<\/a>).<\/p>\r\n\r\n<div id=\"ball-ch10_s02_f01\" class=\"figure large editable block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Figure 10.3<\/span> Liquids and Gravity<\/p>\r\n\r\n\r\n[caption id=\"attachment_3236\" align=\"alignnone\" width=\"400\"]<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/water.png\"><img class=\"wp-image-3236\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184850\/water-1024x539-1.png\" alt=\"(a) A liquid fills the bottom of its container as it is drawn downward by gravity and the particles slide over each other. (b) A liquid floats in a zero- gravity environment. The particles still slide over each other because they are in the liquid phase, but now there is no gravity to pull them down. Source: \u201cGlass of Water\u201d by Derek Jensen is in the public domain; \u201cClayton Anderson zero g\u201d s in the public domain because it was solely created by NASA.\" width=\"400\" height=\"211\" \/><\/a> (a) A liquid fills the bottom of its container as it is drawn downward by gravity and the particles slide over each other. (b) A liquid floats in a zero- gravity environment. The particles still slide over each other because they are in the liquid phase, but now there is no gravity to pull them down. Source: \u201cGlass of Water\u201d by Derek Jensen is in the public domain; \u201cClayton Anderson zero g\u201d s in the public domain because it was solely created by NASA.[\/caption]\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"ball-ch10_s02_p10\" class=\"para editable block\">The phase change between a liquid and a gas has some similarities to the phase change between a solid and a liquid. At a certain temperature, the particles in a liquid have enough energy to become a gas. The process of a liquid becoming a gas is called <span class=\"margin_term\"><a class=\"glossterm\">boiling (or vapourization)<\/a><\/span>, while the process of a gas becoming a liquid is called <span class=\"margin_term\"><a class=\"glossterm\">condensation<\/a><\/span>. However, unlike the solid\/liquid conversion process, the liquid\/gas conversion process is noticeably affected by the surrounding pressure on the liquid because gases are strongly affected by pressure. This means that the temperature at which a liquid becomes a gas, the <span class=\"margin_term\"><a class=\"glossterm\">boiling point<\/a><\/span>, can change with surrounding pressure. Therefore, we define the <span class=\"margin_term\"><a class=\"glossterm\">normal boiling point<\/a><\/span>\u00a0as the temperature at which a liquid changes to a gas when the surrounding pressure is exactly 1 atm, or 760 torr. Unless otherwise specified, it is assumed that a boiling point is for 1 atm of pressure.<\/p>\r\n<p id=\"ball-ch10_s02_p11\" class=\"para editable block\">Like the solid\/liquid phase change, the liquid\/gas phase change involves energy. The amount of energy required to convert a liquid to a gas is called the <span class=\"margin_term\"><a class=\"glossterm\">enthalpy of vapourization<\/a><\/span>\u00a0(or heat of vapourization), represented as \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub>. Some \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> values are listed in <a class=\"xref\" href=\"#ball-ch10_s02_t02\">Table 10.3 \"Enthalpies of Vaporization for Various Substances\"<\/a>; it is assumed that these values are for the normal boiling point temperature of the substance, which is also given in the table. The unit for \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> is also kilojoules per mole, so we need to know the quantity of material to know how much energy is involved. The \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> is also always tabulated as a positive number. It can be used for both the boiling and the condensation processes as long as you keep in mind that boiling is always endothermic (so \u0394<em class=\"emphasis\">H<\/em> will be positive), while condensation is always exothermic (so \u0394<em class=\"emphasis\">H<\/em> will be negative).<\/p>\r\n\r\n<div id=\"ball-ch10_s02_t02\" class=\"table block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Table 10.3<\/span> Enthalpies of Vaporization for Various Substances<\/p>\r\n\r\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Substance (Normal Boiling Point)<\/th>\r\n<th align=\"right\">\u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> (kJ\/mol)<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>Water (100\u00b0C)<\/td>\r\n<td align=\"right\">40.68<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Bromine (59.5\u00b0C)<\/td>\r\n<td align=\"right\">15.4<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Benzene (80.1\u00b0C)<\/td>\r\n<td align=\"right\">30.8<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Ethanol (78.3\u00b0C)<\/td>\r\n<td align=\"right\">38.6<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Mercury (357\u00b0C)<\/td>\r\n<td align=\"right\">59.23<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 3<\/h3>\r\n<p id=\"ball-ch10_s02_p12\" class=\"para\">What is the energy change when 66.7 g of Br<sub class=\"subscript\">2<\/sub>(g) condense to a liquid at 59.5\u00b0C?<\/p>\r\n<p class=\"simpara\">Solution<\/p>\r\n<p id=\"ball-ch10_s02_p13\" class=\"para\">The \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> of Br<sub class=\"subscript\">2<\/sub> is 15.4 kJ\/mol. Even though this is a condensation process, we can still use the numerical value of \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> as long as we realize that we must take energy out, so the \u0394<em class=\"emphasis\">H<\/em> value will be negative. To determine the magnitude of the energy change, we must first convert the amount of Br<sub class=\"subscript\">2<\/sub> to moles. Then we can use \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> as a conversion factor.<\/p>\r\n<span class=\"informalequation\">66.7\u00a0g\u00a0Br<sub>2<\/sub>\u00d7 (1\u00a0mol\u00a0Br<sub>2\/<\/sub>159.8\u00a0g Br<sub>2<\/sub>) \u00d7 (15.4\u00a0kJ\/1 mol Br<sub>2<\/sub>) = 6.43\u00a0kJ<\/span>\r\n<p id=\"ball-ch10_s02_p14\" class=\"para\">Because the process is exothermic, the actual value will be negative: \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u22126.43 kJ.<\/p>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch10_s02_p15\" class=\"para\">What is the energy change when 822 g of C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">5<\/sub>OH(\u2113) boil at its normal boiling point of 78.3\u00b0C?<\/p>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\r\n<p id=\"ball-ch10_s02_p16\" class=\"para\">689 kJ<\/p>\r\n\r\n<\/div>\r\n<p id=\"ball-ch10_s02_p17\" class=\"para editable block\">As with melting, the energy in boiling goes exclusively to changing the phase of a substance; it does not go into changing the temperature of a substance. So boiling is also an isothermal process. Only when all of a substance has boiled does any additional energy go to changing its temperature.<\/p>\r\n<p id=\"ball-ch10_s02_p18\" class=\"para editable block\">What happens when a liquid becomes a gas? We have already established that a liquid is composed of particles in contact with each other. When a liquid becomes a gas, the particles separate from each other, with each particle going its own way in space. This is how gases tend to fill their containers. Indeed, in the gas phase most of the volume is empty space; only about 1\/1,000th of the volume is actually taken up by matter (<a class=\"xref\" href=\"#ball-ch10_s02_f02\">Figure 10.4 \"Liquids and Gases\"<\/a>). It is this property of gases that explains why they can be compressed, a fact that is considered in <a class=\"xref\" href=\"ball-ch06#ball-ch06\">Chapter 6 \"Gases\"<\/a>.<\/p>\r\n\r\n<div id=\"ball-ch10_s02_f02\" class=\"figure large editable block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Figure 10.4<\/span> Liquids and Gases<\/p>\r\n<p class=\"title\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Liquids-and-Gases.png\"><img class=\"alignnone size-full wp-image-4721\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184854\/Liquids-and-Gases-1.png\" alt=\"Liquids and Gases\" width=\"600\" height=\"218\" \/><\/a><\/p>\r\n<p class=\"para\">In (a), the particles are a liquid; the particles are in contact but are also able to move around each other. In (b), the particles are a gas, and most of the volume is actually empty space. The particles are not to scale; in reality, the dots representing the particles would be about 1\/100th the size as depicted.<\/p>\r\n\r\n<\/div>\r\n<p id=\"ball-ch10_s02_p19\" class=\"para editable block\">Under some circumstances, the solid phase can transition directly to the gas phase without going through a liquid phase, and a gas can directly become a solid. The solid-to-gas change is called <span class=\"margin_term\"><a class=\"glossterm\">sublimation<\/a><\/span>, while the reverse process is called <span class=\"margin_term\"><a class=\"glossterm\">deposition<\/a><\/span>. Sublimation is isothermal, like the other phase changes. There is a measurable energy change during sublimation; this energy change is called the <span class=\"margin_term\"><a class=\"glossterm\">enthalpy of sublimation<\/a><\/span>, represented as \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub>. The relationship between the \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub> and the other enthalpy changes is as follows:<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">\u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub> = \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> +\u00a0\u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub><\/span><\/span>\r\n<p id=\"ball-ch10_s02_p20\" class=\"para editable block\">As such, \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub> is not always tabulated because it can be simply calculated from \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> and \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub>.<\/p>\r\n<p id=\"ball-ch10_s02_p21\" class=\"para editable block\">There are several common examples of sublimation. A well-known product\u2014dry ice\u2014is actually solid CO<sub class=\"subscript\">2<\/sub>. Dry ice is dry because it sublimes, with the solid bypassing the liquid phase and going straight to the gas phase. The sublimation occurs at temperature of \u221277\u00b0C, so it must be handled with caution. If you have ever noticed that ice cubes in a freezer tend to get smaller over time, it is because the solid water is very slowly subliming. \u201cFreezer burn\u201d isn\u2019t actually a burn; it occurs when certain foods, such as meats, slowly lose solid water content because of sublimation. The food is still good but looks unappetizing. Reducing the temperature of a freezer will slow the sublimation of solid water.<\/p>\r\n<p id=\"ball-ch10_s02_p22\" class=\"para editable block\">Chemical equations can be used to represent a phase change. In such cases, it is crucial to use phase labels on the substances. For example, the chemical equation for the melting of ice to make liquid water is as follows:<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">H<sub class=\"subscript\">2<\/sub>O(s) \u2192\u00a0H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span>\r\n<p id=\"ball-ch10_s02_p23\" class=\"para editable block\">No chemical change is taking place; however, a physical change is taking place.<\/p>\r\n\r\n<h2>Heating Curves<\/h2>\r\nA plot of the temperature versus the amount of heat added is known as a <strong>heating curve<\/strong> (Figure 10.5). These are commonly used to visually show the relationship between phase changes and enthalpy for a given substance.\r\n\r\n[caption id=\"attachment_2962\" align=\"alignnone\" width=\"530\"]<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/heating-curve-diagram.jpg\"><img class=\"wp-image-2962 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184857\/heating-curve-diagram-1.jpg\" alt=\"Figure #.#. Generic heating curve diagram.\" width=\"530\" height=\"364\" \/><\/a> Figure 10.5. Generic heating curve diagram.[\/caption]\r\n\r\n[footnote]Courtesy UC Davis Chemwiki\\CC-BY-NC-SA-3.0[\/footnote]\r\n\r\nIn Figure 10.5, the solid gains kinetic energy and consequently rises in temperature as heat is added. At the melting point, the heat added is used to break the attractive intermolecular forces of the solid instead of increasing kinetic energy, and therefore the temperature remains constant. After all the solid has melted, once again, the heat added goes to increasing the kinetic energy (and temperature) of the liquid molecules until the boiling point. At the boiling point, once again, the heat added is used to break the attractive intermolecular forces instead of supplying kinetic energy, and the temperature remains constant until all liquid has been turned to gas.\r\n<div id=\"ball-ch10_s02_n04\" class=\"key_takeaways editable block\">\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Key Takeaways<\/h3>\r\n<ul>\r\n \t<li>Phase changes can occur between any two phases of matter.<\/li>\r\n \t<li>All phase changes occur with a simultaneous change in energy.<\/li>\r\n \t<li>All phase changes are isothermal.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<div id=\"ball-ch10_s02_qs01\" class=\"qandaset block\">\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Exercises<\/h3>\r\n&nbsp;\r\n<ol id=\"ball-ch10_s02_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"ball-ch10_s02_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p01\" class=\"para\">What is the difference between <em class=\"emphasis\">melting<\/em> and <em class=\"emphasis\">solidification<\/em>?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch10_s02_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p03\" class=\"para\">What is the difference between <em class=\"emphasis\">boiling<\/em> and <em class=\"emphasis\">condensation<\/em>?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch10_s02_qs01_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p05\" class=\"para\">Describe the molecular changes when a solid becomes a liquid.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch10_s02_qs01_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p07\" class=\"para\">Describe the molecular changes when a liquid becomes a gas.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch10_s02_qs01_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p09\" class=\"para\">What is the energy change when 78.0 g of Hg melt at \u221238.8\u00b0C?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch10_s02_qs01_qd01_qa06\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p11\" class=\"para\">What is the energy change when 30.8 g of Al solidify at 660\u00b0C?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch10_s02_qs01_qd01_qa07\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p13\" class=\"para\">What is the energy change when 111 g of Br<sub class=\"subscript\">2<\/sub> boil at 59.5\u00b0C?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch10_s02_qs01_qd01_qa08\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p15\" class=\"para\">What is the energy change when 98.6 g of H<sub class=\"subscript\">2<\/sub>O condense at 100\u00b0C?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch10_s02_qs01_qd01_qa09\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p17\" class=\"para\">Each of the following statements is incorrect. Rewrite them so they are correct.<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\na) \u00a0Temperature changes during a phase change.\r\n\r\nb) \u00a0The process of a liquid becoming a gas is called sublimation.\r\n\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p18\" class=\"para\">10. \u00a0Each of the following statements is incorrect. Rewrite them so they are correct.<\/p>\r\na) \u00a0The volume of a gas contains only about 10% matter, with the rest being empty space.\r\n\r\nb) \u00a0\u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub> is equal to \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub>.\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p19\" class=\"para\">11. \u00a0Write the chemical equation for the melting of elemental sodium.<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p21\" class=\"para\">12. \u00a0Write the chemical equation for the solidification of benzene (C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">6<\/sub>).<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p23\" class=\"para\">13. \u00a0Write the chemical equation for the sublimation of CO<sub class=\"subscript\">2<\/sub>.<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p25\" class=\"para\">14. \u00a0Write the chemical equation for the boiling of propanol (C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">7<\/sub>OH).<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p27\" class=\"para\">What is the \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub> of H<sub class=\"subscript\">2<\/sub>O? (Hint: see <a class=\"xref\" href=\"#ball-ch10_s02_t01\">Table 10.2 \"Enthalpies of Fusion for Various Substances\"<\/a> and <a class=\"xref\" href=\"#ball-ch10_s02_t02\">Table 10.3 \"Enthalpies of Vaporization for Various Substances\"<\/a>.)<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch10_s02_qs01_p29\" class=\"para\">The \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub> of I<sub class=\"subscript\">2<\/sub> is 60.46 kJ\/mol, while its \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> is 41.71 kJ\/mol. What is the \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> of I<sub class=\"subscript\">2<\/sub>?<\/p>\r\n\r\n<\/div>\r\n<b>Answers<\/b>\r\n\r\n<strong>1.<\/strong>\r\n\r\nMelting is the phase change from a solid to a liquid, whereas solidification is the phase change from a liquid to a solid.\r\n\r\n<strong>3.<\/strong>\r\n\r\nThe molecules have enough energy to move about each other but not enough to completely separate from each other.\r\n\r\n<strong>5.<\/strong>\r\n\r\n890 J\r\n\r\n<strong>7.<\/strong>\r\n\r\n10.7 kJ\r\n\r\n<strong>9.<\/strong>\r\n\r\na) \u00a0Temperature does not change during a phase change.\r\n\r\nb) \u00a0The process of a liquid becoming a gas is called boiling; the process of a solid becoming a gas is called sublimation.\r\n\r\n<strong>11.<\/strong>\r\n\r\nNa(s) \u2192\u00a0Na(\u2113)\r\n<strong>13.<\/strong>\r\n\r\nCO<sub class=\"subscript\">2<\/sub>(s) \u2192\u00a0CO<sub class=\"subscript\">2<\/sub>(g)\r\n<strong>15.<\/strong>\r\n\r\n46.69 kJ\/mol\r\n\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"ball-ch10_s02\" class=\"section\" lang=\"en\">\n<div id=\"ball-ch10_s02_n01\" class=\"learning_objectives editable block\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<ol id=\"ball-ch10_s02_l01\">\n<li>Describe what happens during a phase change.<\/li>\n<li>Calculate the energy change needed for a phase change.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"ball-ch10_s02_p01\" class=\"para editable block\">Substances can change phase\u2014often because of a temperature change. At low temperatures, most substances are solid; as the temperature increases, they become liquid; at higher temperatures still, they become gaseous.<\/p>\n<p id=\"ball-ch10_s02_p02\" class=\"para editable block\">The process of a solid becoming a liquid is called <span class=\"margin_term\"><a class=\"glossterm\">melting<\/a><span class=\"glossdef\">.<\/span><\/span> (an older term that you may see sometimes is <em class=\"emphasis\">fusion<\/em>). The opposite process, a liquid becoming a solid, is called <span class=\"margin_term\"><a class=\"glossterm\">solidification<\/a><\/span>. For any pure substance, the temperature at which melting occurs\u2014known as the <span class=\"margin_term\"><a class=\"glossterm\">melting point<\/a><\/span>\u2014is a characteristic of that substance. It requires energy for a solid to melt into a liquid. Every pure substance has a certain amount of energy it needs to change from a solid to a liquid. This amount is called the <span class=\"margin_term\"><a class=\"glossterm\">enthalpy of fusion (or heat of fusion)<\/a><\/span>\u00a0of the substance, represented as \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub>. Some \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> values are listed in <a class=\"xref\" href=\"#ball-ch10_s02_t01\">Table 10.2 &#8220;Enthalpies of Fusion for Various Substances&#8221;<\/a>; it is assumed that these values are for the melting point of the substance. Note that the unit of \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> is kilojoules per mole, so we need to know the quantity of material to know how much energy is involved. The \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> is always tabulated as a positive number. However, it can be used for both the melting and the solidification processes as long as you keep in mind that melting is always endothermic (so \u0394<em class=\"emphasis\">H<\/em> will be positive), while solidification is always exothermic (so \u0394<em class=\"emphasis\">H<\/em> will be negative).<\/p>\n<div id=\"ball-ch10_s02_t01\" class=\"table block\">\n<p class=\"title\"><span class=\"title-prefix\">Table 10.2<\/span> Enthalpies of Fusion for Various Substances<\/p>\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\n<thead>\n<tr>\n<th>Substance (Melting Point)<\/th>\n<th align=\"right\">\u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> (kJ\/mol)<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>Water (0\u00b0C)<\/td>\n<td align=\"right\">6.01<\/td>\n<\/tr>\n<tr>\n<td>Aluminum (660\u00b0C)<\/td>\n<td align=\"right\">10.7<\/td>\n<\/tr>\n<tr>\n<td>Benzene (5.5\u00b0C)<\/td>\n<td align=\"right\">9.95<\/td>\n<\/tr>\n<tr>\n<td>Ethanol (\u2212114.3\u00b0C)<\/td>\n<td align=\"right\">5.02<\/td>\n<\/tr>\n<tr>\n<td>Mercury (\u221238.8\u00b0C)<\/td>\n<td align=\"right\">2.29<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 2<\/h3>\n<p id=\"ball-ch10_s02_p03\" class=\"para\">What is the energy change when 45.7 g of H<sub class=\"subscript\">2<\/sub>O melt at 0\u00b0C?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch10_s02_p04\" class=\"para\">The \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> of H<sub class=\"subscript\">2<\/sub>O is 6.01 kJ\/mol. However, our quantity is given in units of grams, not moles, so the first step is to convert grams to moles using the molar mass of H<sub class=\"subscript\">2<\/sub>O, which is 18.0 g\/mol. Then we can use \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> as a conversion factor. Because the substance is melting, the process is endothermic, so the energy change will have a positive sign.<\/p>\n<p><span class=\"informalequation\">45.7\u00a0g\u00a0H<sub>2<\/sub>O \u00d7 (1\u00a0mol\u00a0H<sub>2<\/sub>O\/18.0\u00a0g H<sub>2<\/sub>O) \u00d7 (6.01\u00a0kJ\/ 1\u00a0mol H<sub>2<\/sub>O) = 15.3\u00a0kJ<\/span><\/p>\n<p id=\"ball-ch10_s02_p05\" class=\"para\">Without a sign, the number is assumed to be positive.<\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch10_s02_p06\" class=\"para\">What is the energy change when 108 g of C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">6<\/sub> freeze at 5.5\u00b0C?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch10_s02_p07\" class=\"para\">\u221213.8 kJ<\/p>\n<\/div>\n<p id=\"ball-ch10_s02_p08\" class=\"para editable block\">During melting, energy goes exclusively to changing the phase of a substance; it does not go into changing the temperature of a substance. Hence melting is an <span class=\"margin_term\"><a class=\"glossterm\">isothermal<\/a><\/span>\u00a0process because a substance stays at the same temperature. Only when all of a substance is melted does any additional energy go to changing its temperature.<\/p>\n<p id=\"ball-ch10_s02_p09\" class=\"para editable block\">What happens when a solid becomes a liquid? In a solid, individual particles are stuck in place because the intermolecular forces cannot be overcome by the energy of the particles. When more energy is supplied (e.g., by raising the temperature), there comes a point at which the particles have enough energy to move around but not enough energy to separate. This is the liquid phase: particles are still in contact but are able to move around each other. This explains why liquids can assume the shape of their containers: the particles move around and, under the influence of gravity, fill the lowest volume possible (unless the liquid is in a zero-gravity environment\u2014see <a class=\"xref\" href=\"#ball-ch10_s02_f01\">Figure 10.3 &#8220;Liquids and Gravity&#8221;<\/a>).<\/p>\n<div id=\"ball-ch10_s02_f01\" class=\"figure large editable block\">\n<p class=\"title\"><span class=\"title-prefix\">Figure 10.3<\/span> Liquids and Gravity<\/p>\n<div id=\"attachment_3236\" style=\"width: 410px\" class=\"wp-caption alignnone\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/water.png\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-3236\" class=\"wp-image-3236\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184850\/water-1024x539-1.png\" alt=\"(a) A liquid fills the bottom of its container as it is drawn downward by gravity and the particles slide over each other. (b) A liquid floats in a zero- gravity environment. The particles still slide over each other because they are in the liquid phase, but now there is no gravity to pull them down. Source: \u201cGlass of Water\u201d by Derek Jensen is in the public domain; \u201cClayton Anderson zero g\u201d s in the public domain because it was solely created by NASA.\" width=\"400\" height=\"211\" \/><\/a><\/p>\n<p id=\"caption-attachment-3236\" class=\"wp-caption-text\">(a) A liquid fills the bottom of its container as it is drawn downward by gravity and the particles slide over each other. (b) A liquid floats in a zero- gravity environment. The particles still slide over each other because they are in the liquid phase, but now there is no gravity to pull them down. Source: \u201cGlass of Water\u201d by Derek Jensen is in the public domain; \u201cClayton Anderson zero g\u201d s in the public domain because it was solely created by NASA.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p id=\"ball-ch10_s02_p10\" class=\"para editable block\">The phase change between a liquid and a gas has some similarities to the phase change between a solid and a liquid. At a certain temperature, the particles in a liquid have enough energy to become a gas. The process of a liquid becoming a gas is called <span class=\"margin_term\"><a class=\"glossterm\">boiling (or vapourization)<\/a><\/span>, while the process of a gas becoming a liquid is called <span class=\"margin_term\"><a class=\"glossterm\">condensation<\/a><\/span>. However, unlike the solid\/liquid conversion process, the liquid\/gas conversion process is noticeably affected by the surrounding pressure on the liquid because gases are strongly affected by pressure. This means that the temperature at which a liquid becomes a gas, the <span class=\"margin_term\"><a class=\"glossterm\">boiling point<\/a><\/span>, can change with surrounding pressure. Therefore, we define the <span class=\"margin_term\"><a class=\"glossterm\">normal boiling point<\/a><\/span>\u00a0as the temperature at which a liquid changes to a gas when the surrounding pressure is exactly 1 atm, or 760 torr. Unless otherwise specified, it is assumed that a boiling point is for 1 atm of pressure.<\/p>\n<p id=\"ball-ch10_s02_p11\" class=\"para editable block\">Like the solid\/liquid phase change, the liquid\/gas phase change involves energy. The amount of energy required to convert a liquid to a gas is called the <span class=\"margin_term\"><a class=\"glossterm\">enthalpy of vapourization<\/a><\/span>\u00a0(or heat of vapourization), represented as \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub>. Some \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> values are listed in <a class=\"xref\" href=\"#ball-ch10_s02_t02\">Table 10.3 &#8220;Enthalpies of Vaporization for Various Substances&#8221;<\/a>; it is assumed that these values are for the normal boiling point temperature of the substance, which is also given in the table. The unit for \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> is also kilojoules per mole, so we need to know the quantity of material to know how much energy is involved. The \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> is also always tabulated as a positive number. It can be used for both the boiling and the condensation processes as long as you keep in mind that boiling is always endothermic (so \u0394<em class=\"emphasis\">H<\/em> will be positive), while condensation is always exothermic (so \u0394<em class=\"emphasis\">H<\/em> will be negative).<\/p>\n<div id=\"ball-ch10_s02_t02\" class=\"table block\">\n<p class=\"title\"><span class=\"title-prefix\">Table 10.3<\/span> Enthalpies of Vaporization for Various Substances<\/p>\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\n<thead>\n<tr>\n<th>Substance (Normal Boiling Point)<\/th>\n<th align=\"right\">\u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> (kJ\/mol)<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>Water (100\u00b0C)<\/td>\n<td align=\"right\">40.68<\/td>\n<\/tr>\n<tr>\n<td>Bromine (59.5\u00b0C)<\/td>\n<td align=\"right\">15.4<\/td>\n<\/tr>\n<tr>\n<td>Benzene (80.1\u00b0C)<\/td>\n<td align=\"right\">30.8<\/td>\n<\/tr>\n<tr>\n<td>Ethanol (78.3\u00b0C)<\/td>\n<td align=\"right\">38.6<\/td>\n<\/tr>\n<tr>\n<td>Mercury (357\u00b0C)<\/td>\n<td align=\"right\">59.23<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 3<\/h3>\n<p id=\"ball-ch10_s02_p12\" class=\"para\">What is the energy change when 66.7 g of Br<sub class=\"subscript\">2<\/sub>(g) condense to a liquid at 59.5\u00b0C?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch10_s02_p13\" class=\"para\">The \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> of Br<sub class=\"subscript\">2<\/sub> is 15.4 kJ\/mol. Even though this is a condensation process, we can still use the numerical value of \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> as long as we realize that we must take energy out, so the \u0394<em class=\"emphasis\">H<\/em> value will be negative. To determine the magnitude of the energy change, we must first convert the amount of Br<sub class=\"subscript\">2<\/sub> to moles. Then we can use \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> as a conversion factor.<\/p>\n<p><span class=\"informalequation\">66.7\u00a0g\u00a0Br<sub>2<\/sub>\u00d7 (1\u00a0mol\u00a0Br<sub>2\/<\/sub>159.8\u00a0g Br<sub>2<\/sub>) \u00d7 (15.4\u00a0kJ\/1 mol Br<sub>2<\/sub>) = 6.43\u00a0kJ<\/span><\/p>\n<p id=\"ball-ch10_s02_p14\" class=\"para\">Because the process is exothermic, the actual value will be negative: \u0394<em class=\"emphasis\">H<\/em>\u00a0=\u00a0\u22126.43 kJ.<\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch10_s02_p15\" class=\"para\">What is the energy change when 822 g of C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">5<\/sub>OH(\u2113) boil at its normal boiling point of 78.3\u00b0C?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch10_s02_p16\" class=\"para\">689 kJ<\/p>\n<\/div>\n<p id=\"ball-ch10_s02_p17\" class=\"para editable block\">As with melting, the energy in boiling goes exclusively to changing the phase of a substance; it does not go into changing the temperature of a substance. So boiling is also an isothermal process. Only when all of a substance has boiled does any additional energy go to changing its temperature.<\/p>\n<p id=\"ball-ch10_s02_p18\" class=\"para editable block\">What happens when a liquid becomes a gas? We have already established that a liquid is composed of particles in contact with each other. When a liquid becomes a gas, the particles separate from each other, with each particle going its own way in space. This is how gases tend to fill their containers. Indeed, in the gas phase most of the volume is empty space; only about 1\/1,000th of the volume is actually taken up by matter (<a class=\"xref\" href=\"#ball-ch10_s02_f02\">Figure 10.4 &#8220;Liquids and Gases&#8221;<\/a>). It is this property of gases that explains why they can be compressed, a fact that is considered in <a class=\"xref\" href=\"ball-ch06#ball-ch06\">Chapter 6 &#8220;Gases&#8221;<\/a>.<\/p>\n<div id=\"ball-ch10_s02_f02\" class=\"figure large editable block\">\n<p class=\"title\"><span class=\"title-prefix\">Figure 10.4<\/span> Liquids and Gases<\/p>\n<p class=\"title\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Liquids-and-Gases.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-4721\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184854\/Liquids-and-Gases-1.png\" alt=\"Liquids and Gases\" width=\"600\" height=\"218\" \/><\/a><\/p>\n<p class=\"para\">In (a), the particles are a liquid; the particles are in contact but are also able to move around each other. In (b), the particles are a gas, and most of the volume is actually empty space. The particles are not to scale; in reality, the dots representing the particles would be about 1\/100th the size as depicted.<\/p>\n<\/div>\n<p id=\"ball-ch10_s02_p19\" class=\"para editable block\">Under some circumstances, the solid phase can transition directly to the gas phase without going through a liquid phase, and a gas can directly become a solid. The solid-to-gas change is called <span class=\"margin_term\"><a class=\"glossterm\">sublimation<\/a><\/span>, while the reverse process is called <span class=\"margin_term\"><a class=\"glossterm\">deposition<\/a><\/span>. Sublimation is isothermal, like the other phase changes. There is a measurable energy change during sublimation; this energy change is called the <span class=\"margin_term\"><a class=\"glossterm\">enthalpy of sublimation<\/a><\/span>, represented as \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub>. The relationship between the \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub> and the other enthalpy changes is as follows:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">\u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub> = \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> +\u00a0\u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub><\/span><\/span><\/p>\n<p id=\"ball-ch10_s02_p20\" class=\"para editable block\">As such, \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub> is not always tabulated because it can be simply calculated from \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> and \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub>.<\/p>\n<p id=\"ball-ch10_s02_p21\" class=\"para editable block\">There are several common examples of sublimation. A well-known product\u2014dry ice\u2014is actually solid CO<sub class=\"subscript\">2<\/sub>. Dry ice is dry because it sublimes, with the solid bypassing the liquid phase and going straight to the gas phase. The sublimation occurs at temperature of \u221277\u00b0C, so it must be handled with caution. If you have ever noticed that ice cubes in a freezer tend to get smaller over time, it is because the solid water is very slowly subliming. \u201cFreezer burn\u201d isn\u2019t actually a burn; it occurs when certain foods, such as meats, slowly lose solid water content because of sublimation. The food is still good but looks unappetizing. Reducing the temperature of a freezer will slow the sublimation of solid water.<\/p>\n<p id=\"ball-ch10_s02_p22\" class=\"para editable block\">Chemical equations can be used to represent a phase change. In such cases, it is crucial to use phase labels on the substances. For example, the chemical equation for the melting of ice to make liquid water is as follows:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">H<sub class=\"subscript\">2<\/sub>O(s) \u2192\u00a0H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span><\/p>\n<p id=\"ball-ch10_s02_p23\" class=\"para editable block\">No chemical change is taking place; however, a physical change is taking place.<\/p>\n<h2>Heating Curves<\/h2>\n<p>A plot of the temperature versus the amount of heat added is known as a <strong>heating curve<\/strong> (Figure 10.5). These are commonly used to visually show the relationship between phase changes and enthalpy for a given substance.<\/p>\n<div id=\"attachment_2962\" style=\"width: 540px\" class=\"wp-caption alignnone\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/heating-curve-diagram.jpg\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-2962\" class=\"wp-image-2962 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22184857\/heating-curve-diagram-1.jpg\" alt=\"Figure #.#. Generic heating curve diagram.\" width=\"530\" height=\"364\" \/><\/a><\/p>\n<p id=\"caption-attachment-2962\" class=\"wp-caption-text\">Figure 10.5. Generic heating curve diagram.<\/p>\n<\/div>\n<p><a class=\"footnote\" title=\"Courtesy UC Davis Chemwiki\\CC-BY-NC-SA-3.0\" id=\"return-footnote-3048-1\" href=\"#footnote-3048-1\" aria-label=\"Footnote 1\"><sup class=\"footnote\">[1]<\/sup><\/a><\/p>\n<p>In Figure 10.5, the solid gains kinetic energy and consequently rises in temperature as heat is added. At the melting point, the heat added is used to break the attractive intermolecular forces of the solid instead of increasing kinetic energy, and therefore the temperature remains constant. After all the solid has melted, once again, the heat added goes to increasing the kinetic energy (and temperature) of the liquid molecules until the boiling point. At the boiling point, once again, the heat added is used to break the attractive intermolecular forces instead of supplying kinetic energy, and the temperature remains constant until all liquid has been turned to gas.<\/p>\n<div id=\"ball-ch10_s02_n04\" class=\"key_takeaways editable block\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul>\n<li>Phase changes can occur between any two phases of matter.<\/li>\n<li>All phase changes occur with a simultaneous change in energy.<\/li>\n<li>All phase changes are isothermal.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div id=\"ball-ch10_s02_qs01\" class=\"qandaset block\">\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<p>&nbsp;<\/p>\n<ol id=\"ball-ch10_s02_qs01_qd01\" class=\"qandadiv\">\n<li id=\"ball-ch10_s02_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p01\" class=\"para\">What is the difference between <em class=\"emphasis\">melting<\/em> and <em class=\"emphasis\">solidification<\/em>?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch10_s02_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p03\" class=\"para\">What is the difference between <em class=\"emphasis\">boiling<\/em> and <em class=\"emphasis\">condensation<\/em>?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch10_s02_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p05\" class=\"para\">Describe the molecular changes when a solid becomes a liquid.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch10_s02_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p07\" class=\"para\">Describe the molecular changes when a liquid becomes a gas.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch10_s02_qs01_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p09\" class=\"para\">What is the energy change when 78.0 g of Hg melt at \u221238.8\u00b0C?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch10_s02_qs01_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p11\" class=\"para\">What is the energy change when 30.8 g of Al solidify at 660\u00b0C?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch10_s02_qs01_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p13\" class=\"para\">What is the energy change when 111 g of Br<sub class=\"subscript\">2<\/sub> boil at 59.5\u00b0C?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch10_s02_qs01_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p15\" class=\"para\">What is the energy change when 98.6 g of H<sub class=\"subscript\">2<\/sub>O condense at 100\u00b0C?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch10_s02_qs01_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p17\" class=\"para\">Each of the following statements is incorrect. Rewrite them so they are correct.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<p>a) \u00a0Temperature changes during a phase change.<\/p>\n<p>b) \u00a0The process of a liquid becoming a gas is called sublimation.<\/p>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p18\" class=\"para\">10. \u00a0Each of the following statements is incorrect. Rewrite them so they are correct.<\/p>\n<p>a) \u00a0The volume of a gas contains only about 10% matter, with the rest being empty space.<\/p>\n<p>b) \u00a0\u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub> is equal to \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub>.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p19\" class=\"para\">11. \u00a0Write the chemical equation for the melting of elemental sodium.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p21\" class=\"para\">12. \u00a0Write the chemical equation for the solidification of benzene (C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">6<\/sub>).<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p23\" class=\"para\">13. \u00a0Write the chemical equation for the sublimation of CO<sub class=\"subscript\">2<\/sub>.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p25\" class=\"para\">14. \u00a0Write the chemical equation for the boiling of propanol (C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">7<\/sub>OH).<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p27\" class=\"para\">What is the \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub> of H<sub class=\"subscript\">2<\/sub>O? (Hint: see <a class=\"xref\" href=\"#ball-ch10_s02_t01\">Table 10.2 &#8220;Enthalpies of Fusion for Various Substances&#8221;<\/a> and <a class=\"xref\" href=\"#ball-ch10_s02_t02\">Table 10.3 &#8220;Enthalpies of Vaporization for Various Substances&#8221;<\/a>.)<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch10_s02_qs01_p29\" class=\"para\">The \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">sub<\/sub> of I<sub class=\"subscript\">2<\/sub> is 60.46 kJ\/mol, while its \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">vap<\/sub> is 41.71 kJ\/mol. What is the \u0394<em class=\"emphasis\">H<\/em><sub class=\"subscript\">fus<\/sub> of I<sub class=\"subscript\">2<\/sub>?<\/p>\n<\/div>\n<p><b>Answers<\/b><\/p>\n<p><strong>1.<\/strong><\/p>\n<p>Melting is the phase change from a solid to a liquid, whereas solidification is the phase change from a liquid to a solid.<\/p>\n<p><strong>3.<\/strong><\/p>\n<p>The molecules have enough energy to move about each other but not enough to completely separate from each other.<\/p>\n<p><strong>5.<\/strong><\/p>\n<p>890 J<\/p>\n<p><strong>7.<\/strong><\/p>\n<p>10.7 kJ<\/p>\n<p><strong>9.<\/strong><\/p>\n<p>a) \u00a0Temperature does not change during a phase change.<\/p>\n<p>b) \u00a0The process of a liquid becoming a gas is called boiling; the process of a solid becoming a gas is called sublimation.<\/p>\n<p><strong>11.<\/strong><\/p>\n<p>Na(s) \u2192\u00a0Na(\u2113)<br \/>\n<strong>13.<\/strong><\/p>\n<p>CO<sub class=\"subscript\">2<\/sub>(s) \u2192\u00a0CO<sub class=\"subscript\">2<\/sub>(g)<br \/>\n<strong>15.<\/strong><\/p>\n<p>46.69 kJ\/mol<\/p>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-3048\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li><strong>Authored by<\/strong>: David W. Ball and Jessie A. Key. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/opentextbc.ca\/introductorychemistry\/\">https:\/\/opentextbc.ca\/introductorychemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section><hr class=\"before-footnotes clear\" \/><div class=\"footnotes\"><ol><li id=\"footnote-3048-1\">Courtesy UC Davis Chemwiki\\CC-BY-NC-SA-3.0 <a href=\"#return-footnote-3048-1\" class=\"return-footnote\" aria-label=\"Return to footnote 1\">&crarr;<\/a><\/li><\/ol><\/div>","protected":false},"author":89971,"menu_order":4,"template":"","meta":{"_candela_citation":"[{\"type\":\"original\",\"description\":\"\",\"author\":\"David W. Ball and Jessie A. 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