{"id":3120,"date":"2019-04-22T18:51:33","date_gmt":"2019-04-22T18:51:33","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/chapter\/arrhenius-acids-and-bases-2\/"},"modified":"2019-04-29T12:55:49","modified_gmt":"2019-04-29T12:55:49","slug":"arrhenius-acids-and-bases-2","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/chapter\/arrhenius-acids-and-bases-2\/","title":{"raw":"Arrhenius Acids and Bases","rendered":"Arrhenius Acids and Bases"},"content":{"raw":"<div id=\"ball-ch12_s01\" class=\"section\" lang=\"en\">\r\n<div id=\"ball-ch12_s01_n01\" class=\"learning_objectives editable block\">\r\n<div class=\"bcc-box bcc-highlight\">\r\n<h3>Learning Objectives<\/h3>\r\n<ol id=\"ball-ch12_s01_l01\">\r\n \t<li>Identify an Arrhenius acid and an Arrhenius base.<\/li>\r\n \t<li>Write the chemical reaction between an Arrhenius acid and an Arrhenius base.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<p id=\"ball-ch12_s01_p01\" class=\"para editable block\">Historically, the first chemical definition of an acid and a base was put forward by Svante Arrhenius, a Swedish chemist, in 1884. An <span class=\"margin_term\"><a class=\"glossterm\">Arrhenius acid<\/a><\/span>\u00a0is a compound that increases the H<sup class=\"superscript\">+<\/sup> ion concentration in aqueous solution. The H<sup class=\"superscript\">+<\/sup> ion is just a bare proton, and it is rather clear that bare protons are not floating around in an aqueous solution. Instead, chemistry has defined the <span class=\"margin_term\"><a class=\"glossterm\">hydronium ion<\/a><\/span>\u00a0(H<sub class=\"subscript\">3<\/sub>O<sup class=\"superscript\">+<\/sup>) as the actual chemical species that represents an H<sup class=\"superscript\">+<\/sup> ion. H<sup class=\"superscript\">+<\/sup> ions and H<sub class=\"subscript\">3<\/sub>O<sup class=\"superscript\">+<\/sup> ions are often considered interchangeable when writing chemical equations (although a properly balanced chemical equation should also include the additional H<sub class=\"subscript\">2<\/sub>O). Classic Arrhenius acids can be considered ionic compounds in which H<sup class=\"superscript\">+<\/sup> is the cation. <a class=\"xref\" href=\"#ball-ch12_s01_t01\">Table 12.1 \"Some Arrhenius Acids\"<\/a> lists some Arrhenius acids and their names.<\/p>\r\n\r\n<div id=\"ball-ch12_s01_t01\" class=\"table block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Table 12.1<\/span> Some Arrhenius Acids<\/p>\r\n\r\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Formula<\/th>\r\n<th>Name<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>HC<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">2<\/sub> (also written CH<sub class=\"subscript\">3<\/sub>COOH)<\/td>\r\n<td>acetic acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HClO<sub class=\"subscript\">3<\/sub><\/td>\r\n<td>chloric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HCl<\/td>\r\n<td>hydrochloric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HBr<\/td>\r\n<td>hydrobromic acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HI<\/td>\r\n<td>hydriodic acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HF<\/td>\r\n<td>hydrofluoric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HNO<sub class=\"subscript\">3<\/sub><\/td>\r\n<td>nitric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>H<sub class=\"subscript\">2<\/sub>C<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub><\/td>\r\n<td>oxalic acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HClO<sub class=\"subscript\">4<\/sub><\/td>\r\n<td>perchloric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>H<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub><\/td>\r\n<td>phosphoric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/td>\r\n<td>sulfuric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">3<\/sub><\/td>\r\n<td>sulfurous acid<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<p id=\"ball-ch12_s01_p02\" class=\"para editable block\">An <span class=\"margin_term\"><a class=\"glossterm\">Arrhenius base<\/a><\/span>\u00a0is a compound that increases the OH<sup class=\"superscript\">\u2212<\/sup> ion concentration in aqueous solution. Ionic compounds of the OH<sup class=\"superscript\">\u2212<\/sup> ion are classic Arrhenius bases.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 1<\/h3>\r\n<p id=\"ball-ch12_s01_p03\" class=\"para\">Identify each compound as an Arrhenius acid, an Arrhenius base, or neither.<\/p>\r\n\r\n<ol id=\"ball-ch12_s01_l02\" class=\"orderedlist\">\r\n \t<li>HNO<sub class=\"subscript\">3<\/sub><\/li>\r\n \t<li>CH<sub class=\"subscript\">3<\/sub>OH<\/li>\r\n \t<li>Mg(OH)<sub class=\"subscript\">2<\/sub><\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution<\/p>\r\n\r\n<ol id=\"ball-ch12_s01_l03\" class=\"orderedlist\">\r\n \t<li>This compound is an ionic compound between H<sup class=\"superscript\">+<\/sup> ions and NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup> ions, so it is an Arrhenius acid.<\/li>\r\n \t<li>Although this formula has an OH in it, we do not recognize the remaining part of the molecule as a cation. It is neither an acid nor a base. (In fact, it is the formula for methanol, an organic compound.)<\/li>\r\n \t<li>This formula also has an OH in it, but this time we recognize that the magnesium is present as Mg<sup class=\"superscript\">2+<\/sup> cations. As such, this is an ionic compound of the OH<sup class=\"superscript\">\u2212<\/sup> ion and is an Arrhenius base.<\/li>\r\n<\/ol>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch12_s01_p04\" class=\"para\">Identify each compound as an Arrhenius acid, an Arrhenius base, or neither.<\/p>\r\n\r\n<ol id=\"ball-ch12_s01_l04\" class=\"orderedlist\">\r\n \t<li>KOH<\/li>\r\n \t<li>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/li>\r\n \t<li>C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">6<\/sub><\/li>\r\n<\/ol>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\r\n\r\n<ol id=\"ball-ch12_s01_l05\" class=\"orderedlist\">\r\n \t<li>Arrhenius base<\/li>\r\n \t<li>Arrhenius acid<\/li>\r\n \t<li>neither<\/li>\r\n<\/ol>\r\n<\/div>\r\n<p id=\"ball-ch12_s01_p05\" class=\"para editable block\">Acids have some properties in common. They turn litmus, a plant extract, red. They react with some metals to give off H<sub class=\"subscript\">2<\/sub> gas. They react with carbonate and hydrogen carbonate salts to give off CO<sub class=\"subscript\">2<\/sub> gas. Acids that are ingested typically have a sour, sharp taste. (The name <em class=\"emphasis\">acid<\/em> comes from the Latin word <em class=\"emphasis\">acidus<\/em>, meaning \u201csour.\u201d) Bases also have some properties in common. They are slippery to the touch, turn litmus blue, and have a bitter flavour if ingested.<\/p>\r\n<p id=\"ball-ch12_s01_p06\" class=\"para editable block\">Acids and bases have another property: they react with each other to make water and an ionic compound called a salt. A <span class=\"margin_term\"><a class=\"glossterm\">salt<\/a><\/span>, in chemistry, is any ionic compound made by combining an acid with a base. A reaction between an acid and a base is called a <span class=\"margin_term\"><a class=\"glossterm\">neutralization reaction<\/a><\/span>\u00a0and can be represented as follows:<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">acid +\u00a0base \u2192\u00a0H<sub class=\"subscript\">2<\/sub>O +\u00a0salt<\/span><\/span>\r\n<p id=\"ball-ch12_s01_p07\" class=\"para editable block\">The stoichiometry of the balanced chemical equation depends on the number of H<sup class=\"superscript\">+<\/sup> ions in the acid and the number of OH<sup class=\"superscript\">\u2212<\/sup> ions in the base.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 2<\/h3>\r\n<p id=\"ball-ch12_s01_p08\" class=\"para\">Write the balanced chemical equation for the neutralization reaction between H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> and KOH. What is the name of the salt that is formed?<\/p>\r\n<p class=\"simpara\">Solution<\/p>\r\n<p id=\"ball-ch12_s01_p09\" class=\"para\">The general reaction is as follows:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> +\u00a0KOH \u2192\u00a0H<sub class=\"subscript\">2<\/sub>O +\u00a0salt<\/span><\/span>\r\n<p id=\"ball-ch12_s01_p10\" class=\"para\">Because the acid has two H<sup class=\"superscript\">+<\/sup> ions in its formula, we need two OH<sup class=\"superscript\">\u2212<\/sup> ions to react with it, making two H<sub class=\"subscript\">2<\/sub>O molecules as product. The remaining ions, K<sup class=\"superscript\">+<\/sup> and SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup>, make the salt potassium sulfate (K<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>). The balanced chemical reaction is as follows:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> +\u00a02 KOH \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O +\u00a0K<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/span><\/span>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch12_s01_p11\" class=\"para\">Write the balanced chemical equation for the neutralization reaction between HCl and Mg(OH)<sub class=\"subscript\">2<\/sub>. What is the name of the salt that is formed?<\/p>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\r\n<p id=\"ball-ch12_s01_p12\" class=\"para\">2 HCl +\u00a0Mg(OH)<sub class=\"subscript\">2<\/sub> \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O +\u00a0MgCl<sub class=\"subscript\">2<\/sub>; magnesium chloride<\/p>\r\n\r\n<\/div>\r\n<div id=\"ball-ch12_s01_n04\" class=\"key_takeaways editable block\">\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Key Takeaways<\/h3>\r\n<ul id=\"ball-ch12_s01_l06\" class=\"itemizedlist\">\r\n \t<li>An Arrhenius acid is a compound that increases the H<sup class=\"superscript\">+<\/sup> ion concentration in aqueous solution.<\/li>\r\n \t<li>An Arrhenius base is a compound that increases the OH<sup class=\"superscript\">\u2212<\/sup> ion concentration in aqueous solution.<\/li>\r\n \t<li>The reaction between an Arrhenius acid and an Arrhenius base is called neutralization and results in the formation of water and a salt.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Exercises<\/h3>\r\n<div id=\"ball-ch12_s01_qs01\" class=\"qandaset block\">\r\n<ol id=\"ball-ch12_s01_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"ball-ch12_s01_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p01\" class=\"para\">Define <em class=\"emphasis\">Arrhenius acid<\/em>.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch12_s01_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p03\" class=\"para\">Define <em class=\"emphasis\">Arrhenius base<\/em>.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch12_s01_qs01_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p05\" class=\"para\">What are some general properties of Arrhenius acids?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch12_s01_qs01_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p07\" class=\"para\">What are some general properties of Arrhenius bases?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch12_s01_qs01_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p09\" class=\"para\">Identify each substance as an Arrhenius acid, an Arrhenius base, or neither.<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\na) \u00a0NaOH\r\n\r\nb) \u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">5<\/sub>OH\r\n\r\nc) \u00a0H<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub>\r\n\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p10\" class=\"para\">6. \u00a0Identify each substance as an Arrhenius acid, an Arrhenius base, or neither.<\/p>\r\na) \u00a0C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub>\r\n\r\nb) \u00a0HNO<sub class=\"subscript\">2<\/sub>\r\n\r\nc) \u00a0Ba(OH)<sub class=\"subscript\">2<\/sub>\r\n\r\n7. \u00a0Write the balanced chemical equation for the neutralization reaction between KOH and H<sub class=\"subscript\">2<\/sub>C<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub>. What is the salt?\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p13\" class=\"para\">8. \u00a0Write the balanced chemical equation for the neutralization reaction between Sr(OH)<sub class=\"subscript\">2<\/sub> and H<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub>. What is the salt?<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p15\" class=\"para\">9. \u00a0Write the balanced chemical equation for the neutralization reaction between HCl and Fe(OH)<sub class=\"subscript\">3<\/sub>. What is the salt?<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p17\" class=\"para\">10. \u00a0Write the balanced chemical equation for the neutralization reaction between H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> and Cr(OH)<sub class=\"subscript\">3<\/sub>. What is the salt?<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p19\" class=\"para\">11. \u00a0CaCl<sub class=\"subscript\">2<\/sub> would be the product of the reaction of what acid and what base?<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p21\" class=\"para\">12. \u00a0Zn(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> would be product of the reaction of what acid and what base?<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p23\" class=\"para\">13. \u00a0BaSO<sub class=\"subscript\">4<\/sub> would be product of the reaction of what acid and what base?<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch12_s01_qs01_p25\" class=\"para\">14. \u00a0Na<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub> would be product of the reaction of what acid and what base?<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<b>Answers<\/b>\r\n\r\n<strong>1.<\/strong>\r\n\r\na compound that increases the H<sup class=\"superscript\">+<\/sup> concentration in water\r\n\r\n<strong>3.<\/strong>\r\n\r\nsour taste, react with metals, and turn litmus red\r\n\r\n<strong>5.<\/strong>\r\n\r\na) \u00a0Arrhenius base\r\n\r\nb) \u00a0neither\r\n\r\nc) \u00a0Arrhenius acid\r\n\r\n<strong>7.<\/strong>\r\n\r\n2 KOH +\u00a0H<sub class=\"subscript\">2<\/sub>C<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub> \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O +\u00a0K<sub class=\"subscript\">2<\/sub>C<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub>; K<sub class=\"subscript\">2<\/sub>C<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub><strong>9.<\/strong>\r\n\r\n3 HCl +\u00a0Fe(OH)<sub class=\"subscript\">3<\/sub> \u2192\u00a03 H<sub class=\"subscript\">2<\/sub>O +\u00a0FeCl<sub class=\"subscript\">3<\/sub>; FeCl<sub class=\"subscript\">3<\/sub><strong>11.<\/strong>\r\n\r\nHCl and Ca(OH)<sub class=\"subscript\">2<\/sub><strong>13.<\/strong>\r\n\r\nH<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> and Ba(OH)<sub class=\"subscript\">2<\/sub>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"ball-ch12_s01\" class=\"section\" lang=\"en\">\n<div id=\"ball-ch12_s01_n01\" class=\"learning_objectives editable block\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<ol id=\"ball-ch12_s01_l01\">\n<li>Identify an Arrhenius acid and an Arrhenius base.<\/li>\n<li>Write the chemical reaction between an Arrhenius acid and an Arrhenius base.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"ball-ch12_s01_p01\" class=\"para editable block\">Historically, the first chemical definition of an acid and a base was put forward by Svante Arrhenius, a Swedish chemist, in 1884. An <span class=\"margin_term\"><a class=\"glossterm\">Arrhenius acid<\/a><\/span>\u00a0is a compound that increases the H<sup class=\"superscript\">+<\/sup> ion concentration in aqueous solution. The H<sup class=\"superscript\">+<\/sup> ion is just a bare proton, and it is rather clear that bare protons are not floating around in an aqueous solution. Instead, chemistry has defined the <span class=\"margin_term\"><a class=\"glossterm\">hydronium ion<\/a><\/span>\u00a0(H<sub class=\"subscript\">3<\/sub>O<sup class=\"superscript\">+<\/sup>) as the actual chemical species that represents an H<sup class=\"superscript\">+<\/sup> ion. H<sup class=\"superscript\">+<\/sup> ions and H<sub class=\"subscript\">3<\/sub>O<sup class=\"superscript\">+<\/sup> ions are often considered interchangeable when writing chemical equations (although a properly balanced chemical equation should also include the additional H<sub class=\"subscript\">2<\/sub>O). Classic Arrhenius acids can be considered ionic compounds in which H<sup class=\"superscript\">+<\/sup> is the cation. <a class=\"xref\" href=\"#ball-ch12_s01_t01\">Table 12.1 &#8220;Some Arrhenius Acids&#8221;<\/a> lists some Arrhenius acids and their names.<\/p>\n<div id=\"ball-ch12_s01_t01\" class=\"table block\">\n<p class=\"title\"><span class=\"title-prefix\">Table 12.1<\/span> Some Arrhenius Acids<\/p>\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\n<thead>\n<tr>\n<th>Formula<\/th>\n<th>Name<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>HC<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">2<\/sub> (also written CH<sub class=\"subscript\">3<\/sub>COOH)<\/td>\n<td>acetic acid<\/td>\n<\/tr>\n<tr>\n<td>HClO<sub class=\"subscript\">3<\/sub><\/td>\n<td>chloric acid<\/td>\n<\/tr>\n<tr>\n<td>HCl<\/td>\n<td>hydrochloric acid<\/td>\n<\/tr>\n<tr>\n<td>HBr<\/td>\n<td>hydrobromic acid<\/td>\n<\/tr>\n<tr>\n<td>HI<\/td>\n<td>hydriodic acid<\/td>\n<\/tr>\n<tr>\n<td>HF<\/td>\n<td>hydrofluoric acid<\/td>\n<\/tr>\n<tr>\n<td>HNO<sub class=\"subscript\">3<\/sub><\/td>\n<td>nitric acid<\/td>\n<\/tr>\n<tr>\n<td>H<sub class=\"subscript\">2<\/sub>C<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub><\/td>\n<td>oxalic acid<\/td>\n<\/tr>\n<tr>\n<td>HClO<sub class=\"subscript\">4<\/sub><\/td>\n<td>perchloric acid<\/td>\n<\/tr>\n<tr>\n<td>H<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub><\/td>\n<td>phosphoric acid<\/td>\n<\/tr>\n<tr>\n<td>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/td>\n<td>sulfuric acid<\/td>\n<\/tr>\n<tr>\n<td>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">3<\/sub><\/td>\n<td>sulfurous acid<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p id=\"ball-ch12_s01_p02\" class=\"para editable block\">An <span class=\"margin_term\"><a class=\"glossterm\">Arrhenius base<\/a><\/span>\u00a0is a compound that increases the OH<sup class=\"superscript\">\u2212<\/sup> ion concentration in aqueous solution. Ionic compounds of the OH<sup class=\"superscript\">\u2212<\/sup> ion are classic Arrhenius bases.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 1<\/h3>\n<p id=\"ball-ch12_s01_p03\" class=\"para\">Identify each compound as an Arrhenius acid, an Arrhenius base, or neither.<\/p>\n<ol id=\"ball-ch12_s01_l02\" class=\"orderedlist\">\n<li>HNO<sub class=\"subscript\">3<\/sub><\/li>\n<li>CH<sub class=\"subscript\">3<\/sub>OH<\/li>\n<li>Mg(OH)<sub class=\"subscript\">2<\/sub><\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<ol id=\"ball-ch12_s01_l03\" class=\"orderedlist\">\n<li>This compound is an ionic compound between H<sup class=\"superscript\">+<\/sup> ions and NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup> ions, so it is an Arrhenius acid.<\/li>\n<li>Although this formula has an OH in it, we do not recognize the remaining part of the molecule as a cation. It is neither an acid nor a base. (In fact, it is the formula for methanol, an organic compound.)<\/li>\n<li>This formula also has an OH in it, but this time we recognize that the magnesium is present as Mg<sup class=\"superscript\">2+<\/sup> cations. As such, this is an ionic compound of the OH<sup class=\"superscript\">\u2212<\/sup> ion and is an Arrhenius base.<\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch12_s01_p04\" class=\"para\">Identify each compound as an Arrhenius acid, an Arrhenius base, or neither.<\/p>\n<ol id=\"ball-ch12_s01_l04\" class=\"orderedlist\">\n<li>KOH<\/li>\n<li>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/li>\n<li>C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">6<\/sub><\/li>\n<\/ol>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<ol id=\"ball-ch12_s01_l05\" class=\"orderedlist\">\n<li>Arrhenius base<\/li>\n<li>Arrhenius acid<\/li>\n<li>neither<\/li>\n<\/ol>\n<\/div>\n<p id=\"ball-ch12_s01_p05\" class=\"para editable block\">Acids have some properties in common. They turn litmus, a plant extract, red. They react with some metals to give off H<sub class=\"subscript\">2<\/sub> gas. They react with carbonate and hydrogen carbonate salts to give off CO<sub class=\"subscript\">2<\/sub> gas. Acids that are ingested typically have a sour, sharp taste. (The name <em class=\"emphasis\">acid<\/em> comes from the Latin word <em class=\"emphasis\">acidus<\/em>, meaning \u201csour.\u201d) Bases also have some properties in common. They are slippery to the touch, turn litmus blue, and have a bitter flavour if ingested.<\/p>\n<p id=\"ball-ch12_s01_p06\" class=\"para editable block\">Acids and bases have another property: they react with each other to make water and an ionic compound called a salt. A <span class=\"margin_term\"><a class=\"glossterm\">salt<\/a><\/span>, in chemistry, is any ionic compound made by combining an acid with a base. A reaction between an acid and a base is called a <span class=\"margin_term\"><a class=\"glossterm\">neutralization reaction<\/a><\/span>\u00a0and can be represented as follows:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">acid +\u00a0base \u2192\u00a0H<sub class=\"subscript\">2<\/sub>O +\u00a0salt<\/span><\/span><\/p>\n<p id=\"ball-ch12_s01_p07\" class=\"para editable block\">The stoichiometry of the balanced chemical equation depends on the number of H<sup class=\"superscript\">+<\/sup> ions in the acid and the number of OH<sup class=\"superscript\">\u2212<\/sup> ions in the base.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 2<\/h3>\n<p id=\"ball-ch12_s01_p08\" class=\"para\">Write the balanced chemical equation for the neutralization reaction between H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> and KOH. What is the name of the salt that is formed?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch12_s01_p09\" class=\"para\">The general reaction is as follows:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> +\u00a0KOH \u2192\u00a0H<sub class=\"subscript\">2<\/sub>O +\u00a0salt<\/span><\/span><\/p>\n<p id=\"ball-ch12_s01_p10\" class=\"para\">Because the acid has two H<sup class=\"superscript\">+<\/sup> ions in its formula, we need two OH<sup class=\"superscript\">\u2212<\/sup> ions to react with it, making two H<sub class=\"subscript\">2<\/sub>O molecules as product. The remaining ions, K<sup class=\"superscript\">+<\/sup> and SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup>, make the salt potassium sulfate (K<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>). The balanced chemical reaction is as follows:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> +\u00a02 KOH \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O +\u00a0K<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/span><\/span><\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch12_s01_p11\" class=\"para\">Write the balanced chemical equation for the neutralization reaction between HCl and Mg(OH)<sub class=\"subscript\">2<\/sub>. What is the name of the salt that is formed?<\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch12_s01_p12\" class=\"para\">2 HCl +\u00a0Mg(OH)<sub class=\"subscript\">2<\/sub> \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O +\u00a0MgCl<sub class=\"subscript\">2<\/sub>; magnesium chloride<\/p>\n<\/div>\n<div id=\"ball-ch12_s01_n04\" class=\"key_takeaways editable block\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul id=\"ball-ch12_s01_l06\" class=\"itemizedlist\">\n<li>An Arrhenius acid is a compound that increases the H<sup class=\"superscript\">+<\/sup> ion concentration in aqueous solution.<\/li>\n<li>An Arrhenius base is a compound that increases the OH<sup class=\"superscript\">\u2212<\/sup> ion concentration in aqueous solution.<\/li>\n<li>The reaction between an Arrhenius acid and an Arrhenius base is called neutralization and results in the formation of water and a salt.<\/li>\n<\/ul>\n<\/div>\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<div id=\"ball-ch12_s01_qs01\" class=\"qandaset block\">\n<ol id=\"ball-ch12_s01_qs01_qd01\" class=\"qandadiv\">\n<li id=\"ball-ch12_s01_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p01\" class=\"para\">Define <em class=\"emphasis\">Arrhenius acid<\/em>.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch12_s01_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p03\" class=\"para\">Define <em class=\"emphasis\">Arrhenius base<\/em>.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch12_s01_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p05\" class=\"para\">What are some general properties of Arrhenius acids?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch12_s01_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p07\" class=\"para\">What are some general properties of Arrhenius bases?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch12_s01_qs01_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p09\" class=\"para\">Identify each substance as an Arrhenius acid, an Arrhenius base, or neither.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<p>a) \u00a0NaOH<\/p>\n<p>b) \u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">5<\/sub>OH<\/p>\n<p>c) \u00a0H<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub><\/p>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p10\" class=\"para\">6. \u00a0Identify each substance as an Arrhenius acid, an Arrhenius base, or neither.<\/p>\n<p>a) \u00a0C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub><\/p>\n<p>b) \u00a0HNO<sub class=\"subscript\">2<\/sub><\/p>\n<p>c) \u00a0Ba(OH)<sub class=\"subscript\">2<\/sub><\/p>\n<p>7. \u00a0Write the balanced chemical equation for the neutralization reaction between KOH and H<sub class=\"subscript\">2<\/sub>C<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub>. What is the salt?<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p13\" class=\"para\">8. \u00a0Write the balanced chemical equation for the neutralization reaction between Sr(OH)<sub class=\"subscript\">2<\/sub> and H<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub>. What is the salt?<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p15\" class=\"para\">9. \u00a0Write the balanced chemical equation for the neutralization reaction between HCl and Fe(OH)<sub class=\"subscript\">3<\/sub>. What is the salt?<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p17\" class=\"para\">10. \u00a0Write the balanced chemical equation for the neutralization reaction between H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> and Cr(OH)<sub class=\"subscript\">3<\/sub>. What is the salt?<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p19\" class=\"para\">11. \u00a0CaCl<sub class=\"subscript\">2<\/sub> would be the product of the reaction of what acid and what base?<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p21\" class=\"para\">12. \u00a0Zn(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> would be product of the reaction of what acid and what base?<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p23\" class=\"para\">13. \u00a0BaSO<sub class=\"subscript\">4<\/sub> would be product of the reaction of what acid and what base?<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch12_s01_qs01_p25\" class=\"para\">14. \u00a0Na<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub> would be product of the reaction of what acid and what base?<\/p>\n<\/div>\n<\/div>\n<p><b>Answers<\/b><\/p>\n<p><strong>1.<\/strong><\/p>\n<p>a compound that increases the H<sup class=\"superscript\">+<\/sup> concentration in water<\/p>\n<p><strong>3.<\/strong><\/p>\n<p>sour taste, react with metals, and turn litmus red<\/p>\n<p><strong>5.<\/strong><\/p>\n<p>a) \u00a0Arrhenius base<\/p>\n<p>b) \u00a0neither<\/p>\n<p>c) \u00a0Arrhenius acid<\/p>\n<p><strong>7.<\/strong><\/p>\n<p>2 KOH +\u00a0H<sub class=\"subscript\">2<\/sub>C<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub> \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O +\u00a0K<sub class=\"subscript\">2<\/sub>C<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub>; K<sub class=\"subscript\">2<\/sub>C<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub><strong>9.<\/strong><\/p>\n<p>3 HCl +\u00a0Fe(OH)<sub class=\"subscript\">3<\/sub> \u2192\u00a03 H<sub class=\"subscript\">2<\/sub>O +\u00a0FeCl<sub class=\"subscript\">3<\/sub>; FeCl<sub class=\"subscript\">3<\/sub><strong>11.<\/strong><\/p>\n<p>HCl and Ca(OH)<sub class=\"subscript\">2<\/sub><strong>13.<\/strong><\/p>\n<p>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> and Ba(OH)<sub class=\"subscript\">2<\/sub><\/p>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-3120\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li><strong>Authored by<\/strong>: Jessie A. 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Key\",\"organization\":\"\",\"url\":\"https:\/\/opentextbc.ca\/introductorychemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc-sa\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-3120","chapter","type-chapter","status-publish","hentry"],"part":3103,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/3120","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/wp\/v2\/users\/89971"}],"version-history":[{"count":2,"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/3120\/revisions"}],"predecessor-version":[{"id":3850,"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/3120\/revisions\/3850"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/parts\/3103"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/chapters\/3120\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/wp\/v2\/media?parent=3120"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=3120"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/wp\/v2\/contributor?post=3120"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/wp-json\/wp\/v2\/license?post=3120"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}