{"id":3207,"date":"2019-04-22T18:53:46","date_gmt":"2019-04-22T18:53:46","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/chapter\/end-of-chapter-material-30\/"},"modified":"2019-04-29T13:09:30","modified_gmt":"2019-04-29T13:09:30","slug":"end-of-chapter-material-30","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/chapter\/end-of-chapter-material-30\/","title":{"raw":"End-of-Chapter Material","rendered":"End-of-Chapter Material"},"content":{"raw":"<div id=\"ball-ch14_s05\" class=\"section end-of-chapter\" lang=\"en\">\r\n<div id=\"ball-ch14_s05_qs01\" class=\"qandaset block\">\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Additional Exercises<\/h3>\r\n&nbsp;\r\n<ol id=\"ball-ch14_s05_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"ball-ch14_s05_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p01\" class=\"para\">Oxidation was once defined as chemically adding oxygen to a substance. Use this reaction to argue that this definition is consistent with the modern definition of oxidation.<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">2 Mg +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 MgO<\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s05_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p03\" class=\"para\">Reduction was once defined as chemically adding hydrogen to a substance. Use this reaction to argue that this definition is consistent with the modern definition of reduction.<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">2<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub> \u2192\u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">6<\/sub><\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s05_qs01_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p05\" class=\"para\">Assign oxidation numbers to the atoms in each substance.<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\na) \u00a0Kr (krypton)\r\n\r\nb) \u00a0krypton tetrafluoride (KrF<sub class=\"subscript\">4<\/sub>)\r\n\r\nc) \u00a0dioxygen difluoride (O<sub class=\"subscript\">2<\/sub>F<sub class=\"subscript\">2<\/sub>)\r\n\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p06\" class=\"para\">4. \u00a0Assign oxidation numbers to the atoms in each substance.<\/p>\r\na) \u00a0lithium hydride (LiH)\r\n\r\nb) \u00a0potassium peroxide (K<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">2<\/sub>)\r\n\r\nc) \u00a0potassium fluoride (KF)\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p07\" class=\"para\">5. \u00a0N atoms can have a wide range of oxidation numbers. Assign oxidation numbers for the N atom in each compound, all of which are known compounds.<\/p>\r\na) \u00a0N<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">5<\/sub>\r\n\r\nb) \u00a0N<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub>\r\n\r\nc) \u00a0NO<sub class=\"subscript\">2<\/sub>\r\n\r\nd) \u00a0NO\r\n\r\ne) \u00a0N<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub>\r\n\r\nf) \u00a0NH<sub class=\"subscript\">3<\/sub>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p08\" class=\"para\">6. \u00a0Cr atoms can have a wide range of oxidation numbers. Assign oxidation numbers for the Cr atom in each compound, all of which are known compounds.<\/p>\r\na) \u00a0Na<sub class=\"subscript\">2<\/sub>CrO<sub class=\"subscript\">4<\/sub>\r\n\r\nb) \u00a0Na<sub class=\"subscript\">2<\/sub>Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub>\r\n\r\nc) \u00a0CrF<sub class=\"subscript\">5<\/sub>\r\n\r\nd) \u00a0CrCl<sub class=\"subscript\">3<\/sub>\r\n\r\ne) \u00a0CrCl<sub class=\"subscript\">2<\/sub>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p09\" class=\"para\">7. \u00a0Balance this redox reaction by inspection.<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">S<sub class=\"subscript\">8<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0SO<sub class=\"subscript\">2<\/sub><\/span><\/span>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p11\" class=\"para\">8. \u00a0Balance this redox reaction by inspection.<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">C<sub class=\"subscript\">18<\/sub>H<sub class=\"subscript\">38<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0CO<sub class=\"subscript\">2<\/sub> +\u00a0H<sub class=\"subscript\">2<\/sub>O<\/span><\/span>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p13\" class=\"para\">9. \u00a0Balance this redox reaction by the half reaction method by assuming an acidic solution.<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><sup class=\"superscript\">2\u2212<\/sup> +\u00a0Fe \u2192\u00a0Cr<sup class=\"superscript\">3+<\/sup> +\u00a0Fe<sup class=\"superscript\">3+<\/sup><\/span><\/span>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p15\" class=\"para\">10. \u00a0Balance the redox reaction in Exercise 9 by the half reaction method by assuming a basic solution.<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p17\" class=\"para\">11. \u00a0The uranyl ion (UO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2+<\/sup>) is a fairly stable ion of uranium that requires strong reducers to reduce the oxidation number of uranium further. Balance this redox reaction using the half reaction method by assuming an acidic solution.<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">UO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2+<\/sup> +\u00a0HN<sub class=\"subscript\">3<\/sub> \u2192\u00a0U +\u00a0N<sub class=\"subscript\">2<\/sub><\/span><\/span>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p19\" class=\"para\">12. \u00a0Balance the redox reaction in Exercise 11 by the half reaction method by assuming a basic solution.<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p21\" class=\"para\">13. \u00a0Zinc metal can be dissolved by acid, which contains H<sup class=\"superscript\">+<\/sup> ions. Demonstrate that this is consistent with the fact that this reaction has a spontaneous voltage:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Zn +\u00a02 H<sup class=\"superscript\">+<\/sup> \u2192\u00a0Zn<sup class=\"superscript\">2+<\/sup> +\u00a0H<sub class=\"subscript\">2<\/sub><\/span><\/span>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p23\" class=\"para\">14. \u00a0Copper metal cannot be dissolved by acid, which contains H<sup class=\"superscript\">+<\/sup> ions. Demonstrate that this is consistent with the fact that this reaction has a nonspontaneous voltage:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Cu +\u00a02 H<sup class=\"superscript\">+<\/sup> \u2192\u00a0Cu<sup class=\"superscript\">2+<\/sup> +\u00a0H<sub class=\"subscript\">2<\/sub><\/span><\/span>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p25\" class=\"para\">15. \u00a0A disproportionation reaction occurs when a single reactant is both oxidized and reduced. Balance and determine the voltage of this disproportionation reaction. Use the data in <a class=\"xref\" href=\"ball-ch14_s03#ball-ch14_s03_t01\">Table 14.1 \"Standard Reduction Potentials of Half Reactions\"<\/a>.<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Cr<sup class=\"superscript\">2+<\/sup> \u2192\u00a0Cr +\u00a0Cr<sup class=\"superscript\">3+<\/sup><\/span><\/span>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p27\" class=\"para\">16. \u00a0A disproportionation reaction occurs when a single reactant is both oxidized and reduced. Balance and determine the voltage of this disproportionation reaction. Use the data in <a class=\"xref\" href=\"ball-ch14_s03#ball-ch14_s03_t01\">Table 14.1 \"Standard Reduction Potentials of Half Reactions\"<\/a>.<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Fe<sup class=\"superscript\">2+<\/sup> \u2192\u00a0Fe +\u00a0Fe<sup class=\"superscript\">3+<\/sup><\/span><\/span>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p29\" class=\"para\">17. \u00a0What would be overall reaction for a fuel cell that uses CH<sub class=\"subscript\">4<\/sub> as the fuel?<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p31\" class=\"para\">18. \u00a0What would be overall reaction for a fuel cell that uses gasoline (general formula C<sub class=\"subscript\">8<\/sub>H<sub class=\"subscript\">18<\/sub>) as the fuel?<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p33\" class=\"para\">19. \u00a0When NaCl undergoes electrolysis, sodium appears at the cathode. Is the definition of cathode the same for an electrolytic cell as it is for a voltaic cell?<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p35\" class=\"para\">20. \u00a0When NaCl undergoes electrolysis, chlorine appears at the anode. Is the definition of anode the same for an electrolytic cell as it is for a voltaic cell?<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p37\" class=\"para\">21. \u00a0An award is being plated with pure gold before it is presented to a recipient. If the area of the award is 55.0 cm<sup class=\"superscript\">2<\/sup> and will be plated with 3.00 \u00b5m of Au, what mass of Au will be plated on the award? The density of Au is 19.3 g\/cm<sup class=\"superscript\">3<\/sup>.<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s05_qs01_p39\" class=\"para\">22. \u00a0The unit of electrical charge is called the coulomb (C). It takes 96,500 coulombs of charge to reduce 27.0 g of Al from Al<sup class=\"superscript\">3+<\/sup> to Al metal. At 1,040 cm<sup class=\"superscript\">3<\/sup>, how many coulombs of charge were needed to reduce the aluminum in the cap of the Washington monument, assuming the cap is pure Al? The density of Al is 2.70 g\/cm<sup class=\"superscript\">3<\/sup>.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"ball-ch14_s05_qs01_ans\" class=\"qandaset block\">\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Answers<\/h3>\r\n<strong>1.<\/strong>\r\n\r\nAs oxygen is added to magnesium, it is being oxidized. In modern terms, the Mg atoms are losing electrons and being oxidized, while the electrons are going to the O atoms.\r\n\r\n<strong>3.<\/strong>\r\n\r\na) \u00a0Kr: 0\r\n\r\nb) \u00a0Kr: +4; F: \u22121\r\n\r\nc) \u00a0O: +1; F: \u22121\r\n\r\n<strong>5.<\/strong>\r\n\r\na) \u00a0+5\r\n\r\nb) \u00a0+4\r\n\r\nc) \u00a0+4\r\n\r\nd) \u00a0+2\r\n\r\ne) \u00a0\u22122\r\n\r\nf) \u00a0\u22123\r\n\r\n<strong>7.<\/strong>\r\n\r\nS<sub class=\"subscript\">8<\/sub> +\u00a08 O<sub class=\"subscript\">2<\/sub> \u2192\u00a08 SO<sub class=\"subscript\">2<\/sub><strong>9.<\/strong>\r\n\r\n14 H<sup class=\"superscript\">+<\/sup> +\u00a0Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><sup class=\"superscript\">2\u2212<\/sup> +\u00a02 Fe \u2192\u00a02 Cr<sup class=\"superscript\">3+<\/sup> +\u00a07 H<sub class=\"subscript\">2<\/sub>O +\u00a02 Fe<sup class=\"superscript\">3+<\/sup><strong>11.<\/strong>\r\n\r\n6 HN<sub class=\"subscript\">3<\/sub> +\u00a0UO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2+<\/sup> \u2192\u00a0U +\u00a02 H<sub class=\"subscript\">2<\/sub>O +\u00a09 N<sub class=\"subscript\">2<\/sub> +\u00a02 H<sup class=\"superscript\">+<\/sup><strong>13.<\/strong>\r\n\r\nThe voltage of the reaction is +0.76 V, which implies a spontaneous reaction.\r\n\r\n<strong>15.<\/strong>\r\n\r\n3 Cr<sup class=\"superscript\">2+<\/sup> \u2192\u00a0Cr +\u00a02 Cr<sup class=\"superscript\">3+<\/sup>; \u22120.50 V\r\n\r\n<strong>17.<\/strong>\r\n\r\nCH<sub class=\"subscript\">4<\/sub> +\u00a02 O<sub class=\"subscript\">2<\/sub> \u2192\u00a0CO<sub class=\"subscript\">2<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub>O\r\n\r\n<strong>19.<\/strong>\r\n\r\nyes because reduction occurs at the cathode\r\n\r\n<strong>21.<\/strong>\r\n\r\n0.318 g\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"ball-ch14_s05\" class=\"section end-of-chapter\" lang=\"en\">\n<div id=\"ball-ch14_s05_qs01\" class=\"qandaset block\">\n<div class=\"bcc-box bcc-info\">\n<h3>Additional Exercises<\/h3>\n<p>&nbsp;<\/p>\n<ol id=\"ball-ch14_s05_qs01_qd01\" class=\"qandadiv\">\n<li id=\"ball-ch14_s05_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p01\" class=\"para\">Oxidation was once defined as chemically adding oxygen to a substance. Use this reaction to argue that this definition is consistent with the modern definition of oxidation.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">2 Mg +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 MgO<\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s05_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p03\" class=\"para\">Reduction was once defined as chemically adding hydrogen to a substance. Use this reaction to argue that this definition is consistent with the modern definition of reduction.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">2<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub> \u2192\u00a0C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">6<\/sub><\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s05_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p05\" class=\"para\">Assign oxidation numbers to the atoms in each substance.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<p>a) \u00a0Kr (krypton)<\/p>\n<p>b) \u00a0krypton tetrafluoride (KrF<sub class=\"subscript\">4<\/sub>)<\/p>\n<p>c) \u00a0dioxygen difluoride (O<sub class=\"subscript\">2<\/sub>F<sub class=\"subscript\">2<\/sub>)<\/p>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p06\" class=\"para\">4. \u00a0Assign oxidation numbers to the atoms in each substance.<\/p>\n<p>a) \u00a0lithium hydride (LiH)<\/p>\n<p>b) \u00a0potassium peroxide (K<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">2<\/sub>)<\/p>\n<p>c) \u00a0potassium fluoride (KF)<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p07\" class=\"para\">5. \u00a0N atoms can have a wide range of oxidation numbers. Assign oxidation numbers for the N atom in each compound, all of which are known compounds.<\/p>\n<p>a) \u00a0N<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">5<\/sub><\/p>\n<p>b) \u00a0N<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">4<\/sub><\/p>\n<p>c) \u00a0NO<sub class=\"subscript\">2<\/sub><\/p>\n<p>d) \u00a0NO<\/p>\n<p>e) \u00a0N<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">4<\/sub><\/p>\n<p>f) \u00a0NH<sub class=\"subscript\">3<\/sub><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p08\" class=\"para\">6. \u00a0Cr atoms can have a wide range of oxidation numbers. Assign oxidation numbers for the Cr atom in each compound, all of which are known compounds.<\/p>\n<p>a) \u00a0Na<sub class=\"subscript\">2<\/sub>CrO<sub class=\"subscript\">4<\/sub><\/p>\n<p>b) \u00a0Na<sub class=\"subscript\">2<\/sub>Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><\/p>\n<p>c) \u00a0CrF<sub class=\"subscript\">5<\/sub><\/p>\n<p>d) \u00a0CrCl<sub class=\"subscript\">3<\/sub><\/p>\n<p>e) \u00a0CrCl<sub class=\"subscript\">2<\/sub><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p09\" class=\"para\">7. \u00a0Balance this redox reaction by inspection.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">S<sub class=\"subscript\">8<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0SO<sub class=\"subscript\">2<\/sub><\/span><\/span><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p11\" class=\"para\">8. \u00a0Balance this redox reaction by inspection.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">C<sub class=\"subscript\">18<\/sub>H<sub class=\"subscript\">38<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a0CO<sub class=\"subscript\">2<\/sub> +\u00a0H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p13\" class=\"para\">9. \u00a0Balance this redox reaction by the half reaction method by assuming an acidic solution.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><sup class=\"superscript\">2\u2212<\/sup> +\u00a0Fe \u2192\u00a0Cr<sup class=\"superscript\">3+<\/sup> +\u00a0Fe<sup class=\"superscript\">3+<\/sup><\/span><\/span><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p15\" class=\"para\">10. \u00a0Balance the redox reaction in Exercise 9 by the half reaction method by assuming a basic solution.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p17\" class=\"para\">11. \u00a0The uranyl ion (UO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2+<\/sup>) is a fairly stable ion of uranium that requires strong reducers to reduce the oxidation number of uranium further. Balance this redox reaction using the half reaction method by assuming an acidic solution.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">UO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2+<\/sup> +\u00a0HN<sub class=\"subscript\">3<\/sub> \u2192\u00a0U +\u00a0N<sub class=\"subscript\">2<\/sub><\/span><\/span><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p19\" class=\"para\">12. \u00a0Balance the redox reaction in Exercise 11 by the half reaction method by assuming a basic solution.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p21\" class=\"para\">13. \u00a0Zinc metal can be dissolved by acid, which contains H<sup class=\"superscript\">+<\/sup> ions. Demonstrate that this is consistent with the fact that this reaction has a spontaneous voltage:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Zn +\u00a02 H<sup class=\"superscript\">+<\/sup> \u2192\u00a0Zn<sup class=\"superscript\">2+<\/sup> +\u00a0H<sub class=\"subscript\">2<\/sub><\/span><\/span><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p23\" class=\"para\">14. \u00a0Copper metal cannot be dissolved by acid, which contains H<sup class=\"superscript\">+<\/sup> ions. Demonstrate that this is consistent with the fact that this reaction has a nonspontaneous voltage:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Cu +\u00a02 H<sup class=\"superscript\">+<\/sup> \u2192\u00a0Cu<sup class=\"superscript\">2+<\/sup> +\u00a0H<sub class=\"subscript\">2<\/sub><\/span><\/span><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p25\" class=\"para\">15. \u00a0A disproportionation reaction occurs when a single reactant is both oxidized and reduced. Balance and determine the voltage of this disproportionation reaction. Use the data in <a class=\"xref\" href=\"ball-ch14_s03#ball-ch14_s03_t01\">Table 14.1 &#8220;Standard Reduction Potentials of Half Reactions&#8221;<\/a>.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Cr<sup class=\"superscript\">2+<\/sup> \u2192\u00a0Cr +\u00a0Cr<sup class=\"superscript\">3+<\/sup><\/span><\/span><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p27\" class=\"para\">16. \u00a0A disproportionation reaction occurs when a single reactant is both oxidized and reduced. Balance and determine the voltage of this disproportionation reaction. Use the data in <a class=\"xref\" href=\"ball-ch14_s03#ball-ch14_s03_t01\">Table 14.1 &#8220;Standard Reduction Potentials of Half Reactions&#8221;<\/a>.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Fe<sup class=\"superscript\">2+<\/sup> \u2192\u00a0Fe +\u00a0Fe<sup class=\"superscript\">3+<\/sup><\/span><\/span><\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p29\" class=\"para\">17. \u00a0What would be overall reaction for a fuel cell that uses CH<sub class=\"subscript\">4<\/sub> as the fuel?<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p31\" class=\"para\">18. \u00a0What would be overall reaction for a fuel cell that uses gasoline (general formula C<sub class=\"subscript\">8<\/sub>H<sub class=\"subscript\">18<\/sub>) as the fuel?<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p33\" class=\"para\">19. \u00a0When NaCl undergoes electrolysis, sodium appears at the cathode. Is the definition of cathode the same for an electrolytic cell as it is for a voltaic cell?<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p35\" class=\"para\">20. \u00a0When NaCl undergoes electrolysis, chlorine appears at the anode. Is the definition of anode the same for an electrolytic cell as it is for a voltaic cell?<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p37\" class=\"para\">21. \u00a0An award is being plated with pure gold before it is presented to a recipient. If the area of the award is 55.0 cm<sup class=\"superscript\">2<\/sup> and will be plated with 3.00 \u00b5m of Au, what mass of Au will be plated on the award? The density of Au is 19.3 g\/cm<sup class=\"superscript\">3<\/sup>.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"question\">\n<p id=\"ball-ch14_s05_qs01_p39\" class=\"para\">22. \u00a0The unit of electrical charge is called the coulomb (C). It takes 96,500 coulombs of charge to reduce 27.0 g of Al from Al<sup class=\"superscript\">3+<\/sup> to Al metal. At 1,040 cm<sup class=\"superscript\">3<\/sup>, how many coulombs of charge were needed to reduce the aluminum in the cap of the Washington monument, assuming the cap is pure Al? The density of Al is 2.70 g\/cm<sup class=\"superscript\">3<\/sup>.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"ball-ch14_s05_qs01_ans\" class=\"qandaset block\">\n<div class=\"bcc-box bcc-info\">\n<h3>Answers<\/h3>\n<p><strong>1.<\/strong><\/p>\n<p>As oxygen is added to magnesium, it is being oxidized. In modern terms, the Mg atoms are losing electrons and being oxidized, while the electrons are going to the O atoms.<\/p>\n<p><strong>3.<\/strong><\/p>\n<p>a) \u00a0Kr: 0<\/p>\n<p>b) \u00a0Kr: +4; F: \u22121<\/p>\n<p>c) \u00a0O: +1; F: \u22121<\/p>\n<p><strong>5.<\/strong><\/p>\n<p>a) \u00a0+5<\/p>\n<p>b) \u00a0+4<\/p>\n<p>c) \u00a0+4<\/p>\n<p>d) \u00a0+2<\/p>\n<p>e) \u00a0\u22122<\/p>\n<p>f) \u00a0\u22123<\/p>\n<p><strong>7.<\/strong><\/p>\n<p>S<sub class=\"subscript\">8<\/sub> +\u00a08 O<sub class=\"subscript\">2<\/sub> \u2192\u00a08 SO<sub class=\"subscript\">2<\/sub><strong>9.<\/strong><\/p>\n<p>14 H<sup class=\"superscript\">+<\/sup> +\u00a0Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><sup class=\"superscript\">2\u2212<\/sup> +\u00a02 Fe \u2192\u00a02 Cr<sup class=\"superscript\">3+<\/sup> +\u00a07 H<sub class=\"subscript\">2<\/sub>O +\u00a02 Fe<sup class=\"superscript\">3+<\/sup><strong>11.<\/strong><\/p>\n<p>6 HN<sub class=\"subscript\">3<\/sub> +\u00a0UO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2+<\/sup> \u2192\u00a0U +\u00a02 H<sub class=\"subscript\">2<\/sub>O +\u00a09 N<sub class=\"subscript\">2<\/sub> +\u00a02 H<sup class=\"superscript\">+<\/sup><strong>13.<\/strong><\/p>\n<p>The voltage of the reaction is +0.76 V, which implies a spontaneous reaction.<\/p>\n<p><strong>15.<\/strong><\/p>\n<p>3 Cr<sup class=\"superscript\">2+<\/sup> \u2192\u00a0Cr +\u00a02 Cr<sup class=\"superscript\">3+<\/sup>; \u22120.50 V<\/p>\n<p><strong>17.<\/strong><\/p>\n<p>CH<sub class=\"subscript\">4<\/sub> +\u00a02 O<sub class=\"subscript\">2<\/sub> \u2192\u00a0CO<sub class=\"subscript\">2<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub>O<\/p>\n<p><strong>19.<\/strong><\/p>\n<p>yes because reduction occurs at the cathode<\/p>\n<p><strong>21.<\/strong><\/p>\n<p>0.318 g<\/p>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-3207\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li><strong>Authored by<\/strong>: Jessie A. Key. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/opentextbc.ca\/introductorychemistry\/\">https:\/\/opentextbc.ca\/introductorychemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":89971,"menu_order":3,"template":"","meta":{"_candela_citation":"[{\"type\":\"original\",\"description\":\"\",\"author\":\"Jessie A. 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