{"id":3217,"date":"2019-04-22T18:54:14","date_gmt":"2019-04-22T18:54:14","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/chapter\/applications-of-redox-reactions-voltaic-cells-2\/"},"modified":"2019-04-29T13:10:20","modified_gmt":"2019-04-29T13:10:20","slug":"applications-of-redox-reactions-voltaic-cells-2","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-introductorychemistry\/chapter\/applications-of-redox-reactions-voltaic-cells-2\/","title":{"raw":"Applications of Redox Reactions: Voltaic Cells","rendered":"Applications of Redox Reactions: Voltaic Cells"},"content":{"raw":"<div>\r\n<div id=\"ball-ch14_s03\" class=\"section\" lang=\"en\">\r\n<div id=\"ball-ch14_s03_n01\" class=\"learning_objectives editable block\">\r\n<div class=\"bcc-box bcc-highlight\">\r\n<h3>Learning Objectives<\/h3>\r\n<ol id=\"ball-ch14_s03_l01\">\r\n \t<li>Learn the parts of a voltaic cell.<\/li>\r\n \t<li>Combine half reactions to determine the voltage of a voltaic cell.<\/li>\r\n \t<li>Understand how voltaic cells are used as batteries.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<p id=\"ball-ch14_s03_p01\" class=\"para editable block\">Consider this redox reaction:<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">Zn +\u00a0Cu<sup class=\"superscript\">2+<\/sup> \u2192\u00a0Zn<sup class=\"superscript\">2+<\/sup> +\u00a0Cu<\/span><\/span>\r\n<p id=\"ball-ch14_s03_p02\" class=\"para editable block\">If you were to mix zinc metal and copper ions in a container, this reaction would proceed by itself; we say that this reaction is <em class=\"emphasis\">spontaneous<\/em>.<\/p>\r\n<p id=\"ball-ch14_s03_p03\" class=\"para editable block\">Suppose, however, we set up this reaction in a way depicted in <a class=\"xref\" href=\"#ball-ch14_s03_f01\">Figure 14.1 \"A Redox Reaction in Which the Two Half Reactions Are Physically Separated\"<\/a>. Zinc and zinc ions are on one side of the system, while copper and copper ions are on the other side of the system. The two parts are connected with a wire.<\/p>\r\n\r\n<div id=\"ball-ch14_s03_f01\" class=\"figure large editable block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Figure 14.1<\/span> A Redox Reaction in Which the Two Half Reactions Are Physically Separated<\/p>\r\n<p class=\"title\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Redox-Reaction-With-Voltmeter.png\"><img class=\"alignnone wp-image-4772\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22185356\/Redox-Reaction-With-Voltmeter-1.png\" alt=\"Redox Reaction With Voltmeter\" width=\"420\" height=\"365\" \/><\/a><\/p>\r\n<p class=\"para\">One application of redox reactions requires that they be physically separated.<\/p>\r\n\r\n<\/div>\r\n<p id=\"ball-ch14_s03_p04\" class=\"para editable block\">Even though the two half reactions are physically separated, a spontaneous redox reaction still occurs. However, in this case, the electrons transfer through the wire connecting the two half reactions; that is, this setup becomes a source of electricity. Useful work can be extracted from the electrons as they transfer from one side to the other\u2014for example, a light bulb can be lit, or a motor can be operated. The apparatus as a whole, which allows useful electrical work to be extracted from a redox reaction, is called a <span class=\"margin_term\"><a class=\"glossterm\">voltaic (galvanic) cell<\/a><\/span>.<\/p>\r\n<p id=\"ball-ch14_s03_p05\" class=\"para editable block\">Each individual system that contains a half reaction is called a <span class=\"margin_term\"><a class=\"glossterm\">half cell<\/a><\/span>. The half cell that contains the oxidation reaction is called the <span class=\"margin_term\"><a class=\"glossterm\">anode<\/a><\/span>, while the half cell that contains the reduction reaction is called the <span class=\"margin_term\"><a class=\"glossterm\">cathode<\/a><\/span>. The cathode and anode collectively are the <span class=\"margin_term\"><a class=\"glossterm\">electrodes<\/a><\/span>\u00a0of the voltaic cell. Because electrons are coming from the anode, the anode is considered the <em class=\"emphasis\">negative<\/em> electrode of the cell, while the cathode is considered the <em class=\"emphasis\">positive<\/em> electrode of the cell. Finally, because electrons are moving from one half cell to the other, a charge imbalance builds up as the reaction proceeds. To counter that, a <span class=\"margin_term\"><a class=\"glossterm\">salt bridge<\/a><\/span>\u00a0is used; the salt bridge contains a solution of some ionic compound whose ions migrate to either side of the voltaic cell to maintain the charge balance.<\/p>\r\n<p id=\"ball-ch14_s03_p06\" class=\"para editable block\">The tendency for electrons to go from one half cell to another is called the <span class=\"margin_term\"><a class=\"glossterm\">voltage<\/a><span class=\"glossdef\">The tendency for electrons to go from one half cell to another.<\/span><\/span> of the voltaic cell, represented by <em class=\"emphasis\">E<\/em>. Sometimes the term <em class=\"emphasis\">potential<\/em> is used to represent the voltage of a cell. Voltage is expressed in volts (V). The voltage of a voltaic cell is determined by the <em class=\"emphasis\">difference<\/em> in the tendencies of the individual half cells and is characteristic of a given redox reaction when concentrations are specific (1.0 M for dissolved species and 1.0 atm for gases). Because the voltage of a redox reaction is determined by the difference of the tendencies of the individual half reactions, absolute voltages are unnecessary; only relative voltages of each half reaction are needed. The relative voltage of each half cell is represented as <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> and is based on the standard that the <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> for the reaction<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">H<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a01\/2 H<sub class=\"subscript\">2<\/sub><\/span><\/span>\r\n<p id=\"ball-ch14_s03_p07\" class=\"para editable block\">is assigned to be exactly 0.000 V under standard conditions of pressure and concentration. <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 \"Standard Reduction Potentials of Half Reactions\"<\/a> lists some relative <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> values for some half reactions. Note that all half reactions are listed as reduction reactions, so these values are called the <span class=\"margin_term\"><a class=\"glossterm\">standard reduction potentials<\/a><span class=\"glossdef\">The voltage of a reduction half reaction relative to the hydrogen half reaction.<\/span><\/span> of each half reaction.<\/p>\r\n\r\n<div id=\"ball-ch14_s03_t01\" class=\"table block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Table 14.1<\/span> Standard Reduction Potentials of Half Reactions<\/p>\r\n\r\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Reduction Half Reaction<\/th>\r\n<th align=\"right\"><em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> (V)<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>F<sub class=\"subscript\">2<\/sub> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a02 F<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td align=\"right\">2.87<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Ce<sup class=\"superscript\">4+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Ce<sup class=\"superscript\">3+<\/sup><\/td>\r\n<td align=\"right\">1.61<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>MnO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup> +\u00a08 H<sup class=\"superscript\">+<\/sup> +\u00a05e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Mn<sup class=\"superscript\">2+<\/sup> +\u00a04 H<sub class=\"subscript\">2<\/sub>O<\/td>\r\n<td align=\"right\">1.51<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Cl<sub class=\"subscript\">2<\/sub> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a02Cl<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td align=\"right\">1.36<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>O<sub class=\"subscript\">2<\/sub> +\u00a04 H<sup class=\"superscript\">+<\/sup> +\u00a04e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O<\/td>\r\n<td align=\"right\">1.23<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Br<sub class=\"subscript\">2<\/sub> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a02 Br<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td align=\"right\">1.06<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup> +\u00a04 H<sup class=\"superscript\">+<\/sup> +\u00a03e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0NO +\u00a02 H<sub class=\"subscript\">2<\/sub>O<\/td>\r\n<td align=\"right\">0.96<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Ag<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Ag<\/td>\r\n<td align=\"right\">0.80<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Fe<sup class=\"superscript\">3+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Fe<sup class=\"superscript\">2+<\/sup><\/td>\r\n<td align=\"right\">0.77<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>I<sub class=\"subscript\">2<\/sub> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a02I<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td align=\"right\">0.54<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Cu<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cu<\/td>\r\n<td align=\"right\">0.34<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>AgCl +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Ag +\u00a0Cl<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td align=\"right\">0.222<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Sn<sup class=\"superscript\">4+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Sn<sup class=\"superscript\">2+<\/sup><\/td>\r\n<td align=\"right\">0.15<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>2H<sup class=\"superscript\">+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0H<sub class=\"subscript\">2<\/sub><\/td>\r\n<td align=\"right\">0.000<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Pb<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Pb<\/td>\r\n<td align=\"right\">\u22120.126<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Ni<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Ni<\/td>\r\n<td align=\"right\">\u22120.25<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Cr<sup class=\"superscript\">3+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cr<sup class=\"superscript\">2+<\/sup><\/td>\r\n<td align=\"right\">\u22120.41<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Fe<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Fe<\/td>\r\n<td align=\"right\">\u22120.44<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Cr<sup class=\"superscript\">3+<\/sup> +\u00a03e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cr<\/td>\r\n<td align=\"right\">\u22120.74<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Zn<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Zn<\/td>\r\n<td align=\"right\">\u22120.76<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Cr<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cr<\/td>\r\n<td align=\"right\">\u22120.91<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Ba<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Ba<\/td>\r\n<td align=\"right\">\u22121.57<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Al<sup class=\"superscript\">3+<\/sup>+\u00a03e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Al<\/td>\r\n<td align=\"right\">\u22121.66<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Mg<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Mg<\/td>\r\n<td align=\"right\">\u22122.37<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Na<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Na<\/td>\r\n<td align=\"right\">\u22122.714<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Li<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Li<\/td>\r\n<td align=\"right\">\u22123.045<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<p id=\"ball-ch14_s03_p08\" class=\"para editable block\"><a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 \"Standard Reduction Potentials of Half Reactions\"<\/a> lists only reduction reactions, but a redox reaction has a reduction <em class=\"emphasis\">and<\/em> an oxidation. To make the oxidation reaction, simply reverse the reduction reaction in <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 \"Standard Reduction Potentials of Half Reactions\"<\/a> and change the sign on the <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> value. If the reduction potential is negative, make the voltage for the oxidation positive; if the reduction potential is positive, make the voltage for the oxidation negative.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 6<\/h3>\r\n<p id=\"ball-ch14_s03_p09\" class=\"para\">What is the value of <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> for this half reaction?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Ag +\u00a0Cl<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0AgCl +\u00a0e<sup class=\"superscript\">\u2212<\/sup><\/span><\/span>\r\n<p class=\"simpara\">Solution<\/p>\r\n<p id=\"ball-ch14_s03_p10\" class=\"para\">The given reaction is the reverse of this reaction:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">AgCl +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Ag +\u00a0Cl<sup class=\"superscript\">\u2212 \u00a0 \u00a0<\/sup><em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> = 0.222 V<\/span><\/span>\r\n<p id=\"ball-ch14_s03_p11\" class=\"para\">Therefore, the <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> of the given reaction is \u22120.222 V.<\/p>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch14_s03_p12\" class=\"para\">What is the value of <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> for this half reaction?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Na \u2192\u00a0Na<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup><\/span><\/span>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\r\n<p id=\"ball-ch14_s03_p13\" class=\"para\">2.714 V<\/p>\r\n\r\n<\/div>\r\n<p id=\"ball-ch14_s03_p14\" class=\"para editable block\">To determine the overall voltage of a particular voltaic cell, simply combine the voltages of the oxidation and reduction half reactions. Even if you need to take a multiple of a half reaction for the electrons to cancel, do not take the multiple of the <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub>. Use the values directly as is from <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 \"Standard Reduction Potentials of Half Reactions\"<\/a>.<\/p>\r\n<p id=\"ball-ch14_s03_p15\" class=\"para editable block\">Spontaneous redox reactions have positive overall voltages. If the voltage of the reaction as written is negative, it is not spontaneous in that direction. Rather, the reverse reaction is the spontaneous redox reaction.<\/p>\r\n\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Example 7<\/h3>\r\n<p id=\"ball-ch14_s03_p16\" class=\"para\">What is the voltage of a voltaic cell based on this reaction? Is the reaction spontaneous as written?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">2 NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup> +\u00a08 H<sup class=\"superscript\">+<\/sup> +\u00a03 Cu \u2192\u00a02 NO +\u00a04 H<sub class=\"subscript\">2<\/sub>O +\u00a03 Cu<sup class=\"superscript\">2+<\/sup><\/span><\/span>\r\n<p class=\"simpara\">Solution<\/p>\r\n<p id=\"ball-ch14_s03_p17\" class=\"para\">The overall redox reaction is formed from these two half reactions:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup> +\u00a04 H<sup class=\"superscript\">+<\/sup> +\u00a03e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0NO +\u00a02 H<sub class=\"subscript\">2<\/sub>O \u00a0 \u00a0\u00a0<em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> = 0.96 V<\/span><\/span>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Cu<sup class=\"superscript\">2+<\/sup> +\u00a02 e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cu \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0<em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> = 0.34 V<\/span><\/span>\r\n<p id=\"ball-ch14_s03_p18\" class=\"para\">The second reaction is reversed in the overall redox reaction, so its voltage changes sign from the reduction reaction:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Cu \u2192\u00a0Cu<sup class=\"superscript\">2+<\/sup> +\u00a02 e<sup class=\"superscript\">\u2212 \u00a0 \u00a0 \u00a0\u00a0<\/sup><em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> = \u22120.34 V<\/span><\/span>\r\n<p id=\"ball-ch14_s03_p19\" class=\"para\">To obtain the voltage of the voltaic cell based on the overall reaction, we simply combine the two voltages of the half reactions:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\"><em class=\"emphasis\">E<\/em> = 0.96 +\u00a0(\u22120.34) = 0.62 V<\/span><\/span>\r\n<p id=\"ball-ch14_s03_p20\" class=\"para\">Because the overall voltage is positive, the reaction is spontaneous as written.<\/p>\r\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\r\n<p id=\"ball-ch14_s03_p21\" class=\"para\">What is the voltage of a voltaic cell based on this reaction? Is the reaction spontaneous as written?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">5 Ni +\u00a02 MnO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup> +\u00a016 H<sup class=\"superscript\">+<\/sup> \u2192\u00a03 Mn<sup class=\"superscript\">2+<\/sup> +\u00a08 H<sub class=\"subscript\">2<\/sub>O +\u00a05 Ni<sup class=\"superscript\">2+<\/sup><\/span><\/span>\r\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\r\n<p id=\"ball-ch14_s03_p22\" class=\"para\">1.76 V; spontaneous<\/p>\r\n\r\n<\/div>\r\n<p id=\"ball-ch14_s03_p23\" class=\"para editable block\">Technically, any redox reaction can be set up to make a voltaic cell. In modern society, however, only certain redox reactions are put to practical use. A portable voltaic cell that generates electricity to power devices for our convenience is called a <span class=\"margin_term\"><a class=\"glossterm\">battery<\/a><\/span>. All batteries are based on redox reactions.<\/p>\r\n<p id=\"ball-ch14_s03_p24\" class=\"para editable block\">The first battery (called a \u201cvoltaic pile\u201d) was constructed by the Italian scientist Alessandro Volta in 1800 and was based on the copper\/zinc reaction depicted in <a class=\"xref\" href=\"#ball-ch14_s03_f01\">Figure 14.1 \"A Redox Reaction in Which the Two Half Reactions Are Physically Separated\"<\/a>. Unfortunately, it was messy, requiring quantities of copper and zinc salts dissolved in water. In 1866, the French scientist Georges Leclanch\u00e9 invented the <span class=\"margin_term\"><a class=\"glossterm\">dry cell<\/a><\/span>, a precursor to today\u2019s modern battery. A schematic of a dry cell is shown in <a class=\"xref\" href=\"#ball-ch14_s03_f02\">Figure 14.2 \"Dry Cells\"<\/a>. The zinc case and the central carbon rod serve as the anode and cathode, respectively. The other reactants are combined into a moist paste that minimizes free liquid, so the battery is less messy (hence the name <em class=\"emphasis\">dry cell<\/em>). The actual redox reaction is complex but can be represented by the following redox reaction:<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">Zn +\u00a02 MnO<sub class=\"subscript\">2<\/sub> +\u00a02 NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> \u2192\u00a0Zn<sup class=\"superscript\">2+<\/sup> +\u00a0Mn<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub> +\u00a02 NH<sub class=\"subscript\">3<\/sub> +\u00a0H<sub class=\"subscript\">2<\/sub>O<\/span><\/span>\r\n<p id=\"ball-ch14_s03_p25\" class=\"para editable block\">A dry cell has a voltage of about 1.56 V. While common and useful, dry cells have relatively short lifetimes and contain acidic components. They also cannot be recharged, so they are one-use only. Batteries that can be used only once are called <span class=\"margin_term\"><a class=\"glossterm\">primary batteries<\/a><\/span>.<\/p>\r\n\r\n<div id=\"ball-ch14_s03_f02\" class=\"figure large editable block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Figure 14.2<\/span> Dry Cells<\/p>\r\n<p class=\"title\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Dry-Cell.png\"><img class=\"alignnone wp-image-4774 \" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22185400\/Dry-Cell-1.png\" alt=\"Dry Cell\" width=\"433\" height=\"450\" \/><\/a><\/p>\r\n<p class=\"para\">The Leclanch\u00e9 dry cell is a common type of battery.<\/p>\r\n\r\n<\/div>\r\n<p id=\"ball-ch14_s03_p26\" class=\"para editable block\">In the late 1950s, Lewis Urry of the Eveready Battery Company in Ohio invented the <span class=\"margin_term\"><a class=\"glossterm\">alkaline battery<\/a><\/span>\u00a0(still marketed today under the trade name <em class=\"emphasis\">Energizer<\/em>). Alkaline batteries are similar to dry cells, but they use a basic moist paste rather than an acidic one. Moreover, the net amount of base does not change during the course of the redox reaction. The overall redox reaction is as follows:<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">Zn +\u00a02MnO<sub class=\"subscript\">2<\/sub> \u2192\u00a0ZnO +\u00a0Mn<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub><\/span><\/span>\r\n<p id=\"ball-ch14_s03_p27\" class=\"para editable block\">Alkaline batteries have the advantage of being longer lasting and holding their voltage better\u2014about 1.54\u00a0V\u2014throughout their lifetime.<\/p>\r\n<p id=\"ball-ch14_s03_p28\" class=\"para editable block\">A common type of battery, especially with the increased popularity of personal electronic devices, is the button battery (<a class=\"xref\" href=\"#ball-ch14_s03_f03\">Figure 14.3 \"Button Batteries\"<\/a>). A button battery is a small battery that can power small electronic devices; the batteries can be as small as 5 mm across. Two popular redox reactions used for button batteries are the alkaline dry-cell reaction and a silver oxide-based reaction:<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">Zn +\u00a0Ag<sub class=\"subscript\">2<\/sub>O \u2192\u00a0ZnO +\u00a02 Ag<\/span><\/span>\r\n<p id=\"ball-ch14_s03_p29\" class=\"para editable block\">Some button batteries use a lithium-based redox reaction, typified by this anode reaction:<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">Li \u2192\u00a0Li<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup><em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> = 3.045 V<\/span><\/span>\r\n<p id=\"ball-ch14_s03_p30\" class=\"para editable block\">The actual redox reaction depends on the composition of the cathode and is variable depending on voltage. Lithium batteries can also be used for applications that require more energy, such as portable computers and electric vehicles. Some lithium-based batteries are rechargeable and can be used over and over again; such batteries are called <span class=\"margin_term\"><a class=\"glossterm\">secondary batteries<\/a><\/span>.<\/p>\r\n\r\n<div id=\"ball-ch14_s03_f03\" class=\"figure small editable block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Figure 14.3<\/span> Button Batteries<\/p>\r\n\r\n\r\n[caption id=\"attachment_3262\" align=\"alignnone\" width=\"511\"]<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/Coin-cells.jpg\"><img class=\"wp-image-3262 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22185402\/Coin-cells-1.jpg\" alt=\"Button batteries like those seen here can be used for a variety of portable electronics, from watches and hearing aids to handheld gaming devices. Source: \u201cCoin Cells\u201d by Gerhard H Wrodnigg is licensed under the Creative Commons Attribution-Share Alike 2.5 Generic license.\" width=\"511\" height=\"363\" \/><\/a> Button batteries like those seen here can be used for a variety of portable electronics, from watches and hearing aids to handheld gaming devices.<br \/>Source: \u201cCoin Cells\u201d by Gerhard H Wrodnigg is licensed under the Creative Commons Attribution-Share Alike 2.5 Generic license.[\/caption]\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"ball-ch14_s03_p31\" class=\"para editable block\">An important secondary battery is the lead storage battery. The lead storage battery is based on this redox reaction:<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">Pb +\u00a0PbO<sub class=\"subscript\">2<\/sub> +\u00a04 H<sup class=\"superscript\">+<\/sup> +\u00a0SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup> \u2192\u00a02 PbSO<sub class=\"subscript\">4<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub>O<\/span><\/span>\r\n<p id=\"ball-ch14_s03_p32\" class=\"para editable block\">The redox reaction produces about 2 V, but it is typical to tie several individual batteries together to generate a larger voltage. The lead storage battery has the distinction that the product of both half reactions is PbSO<sub class=\"subscript\">4<\/sub>, which as a solid accumulates on the many plates within each cell. The lead storage battery is a secondary battery, as it can be recharged and reused many times. Because it is based on lead, these batteries are rather heavy. They should also be recycled when replaced so that potentially dangerous lead does not escape into the environment. Because of their characteristics, lead storage batteries are used to start large engines in automobiles, boats, and airplanes.<\/p>\r\n\r\n<\/div>\r\n<div id=\"ball-ch14_s03_n04\" class=\"callout block\">\r\n<h3 class=\"title\">Chemistry Is Everywhere: Fuel Cells<\/h3>\r\n<p id=\"ball-ch14_s03_p33\" class=\"para\">A <em class=\"emphasis\">fuel cell<\/em> is a type of battery in which reactants flow continuously into a specialized reaction chamber, and products flow out continuously while electrons are extracted from the reaction. Because all reactions in a fuel cell consist of a fuel and an oxidizer undergoing a redox reaction, an introduction of fuel cells is at home in a discussion of redox chemistry.<\/p>\r\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Fuel-Cell.png\"><img class=\"alignnone wp-image-4775\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22185405\/Fuel-Cell-1.png\" alt=\"Fuel Cell\" width=\"428\" height=\"414\" \/><\/a><\/p>\r\n\r\n<div class=\"informalfigure large\">\r\n<p class=\"para\">This fuel cell uses H<sub class=\"subscript\">2<\/sub> as the fuel and O<sub class=\"subscript\">2<\/sub> as the oxidizer.<\/p>\r\n\r\n<\/div>\r\n<p id=\"ball-ch14_s03_p34\" class=\"para\">By far the most common fuel cell reaction is based on hydrogen and oxygen:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">2 H<sub class=\"subscript\">2<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O \u00a0 \u00a0<em class=\"emphasis\">E<\/em> = 1.23 V under standard conditions<\/span><\/span>\r\n<p id=\"ball-ch14_s03_p35\" class=\"para\">However, fuel cells typically do not work under standard nor even optimal conditions, so they typically generate about 0.6\u20130.7 V. In this fuel cell, the only two products are water and electricity, so the fuel cell not only does not create pollution but also makes a by-product that in some environments is a valuable commodity (water). Other fuels can be used besides hydrogen; fuel cells have been developed that work on methane, methyl alcohol, ethyl alcohol, carbon-rich materials, and even magnesium metal.<\/p>\r\n<p id=\"ball-ch14_s03_p36\" class=\"para\">Hydrogen-based fuel cells were and are used to provide electricity for manned space vehicles, partly because their only chemical product is water, which could be used for drinking. However, there has been a recent resurgence in interest in fuel cells because of their potential use in electric cars. Most electric cars run on conventional batteries, which can be very heavy and expensive to replace. It is thought that fuel cells, rather than conventional batteries, might be better sources of electricity for automobiles.<\/p>\r\n<p id=\"ball-ch14_s03_p37\" class=\"para\">Several current barriers to fuel cell use in electric cars include capacity, cost, and overall energy efficiency. The 2008 Honda FCX, the first production model of a vehicle powered with a fuel cell, can hold 4.1 kg (just under 9\u00a0lb) of highly pressured H<sub class=\"subscript\">2<\/sub> gas and has a range of 450 km (280 mi). It costs about $120,000\u2013$140,000 to build, making the vehicle beyond the ability of most people to own. Finally, it always requires more energy to produce elemental hydrogen as a fuel than can be extracted from hydrogen as a fuel. As such, hydrogen is described as an energy carrier (like electricity) rather than an energy source (like oil and gas). This distinction points out a fundamental argument against fuel cells as a \u201cbetter\u201d power source.<\/p>\r\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Honda-FCX.png\"><img class=\"alignnone wp-image-4776\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22185409\/Honda-FCX-1.png\" alt=\"Honda FCX\" width=\"494\" height=\"242\" \/><\/a><\/p>\r\n\r\n<div class=\"informalfigure large\">\r\n<p class=\"para\">The 2008 Honda FCX was the first production car to use a fuel cell as a power source. Nonetheless, the car is in very limited service because of its need for relatively large quantities of elemental hydrogen as fuel.<\/p>\r\n\r\n<div class=\"copyright\">\r\n<p class=\"para\">Source: Photo courtesy of vernieman, <a class=\"link\" href=\"http:\/\/commons.wikimedia.org\/wiki\/File:Honda_FCX_2006_KLIMS_front.jpg\" target=\"_blank\" rel=\"noopener\">http:\/\/commons.wikimedia.org\/wiki\/File:Honda_FCX_2006_KLIMS_front.jpg<\/a>.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"ball-ch14_s03_p38\" class=\"para\">The limitations notwithstanding, there is a lot of interest in fuel cell research. If ways can be found to circumvent their current limitations, fuel cells may become more and more common as power sources.<\/p>\r\n\r\n<\/div>\r\n<div id=\"ball-ch14_s03_n05\" class=\"key_takeaways editable block\">\r\n<div class=\"bcc-box bcc-success\">\r\n<h3>Key Takeaways<\/h3>\r\n<ul id=\"ball-ch14_s03_l02\" class=\"itemizedlist\">\r\n \t<li>A voltaic cell produces electricity as a redox reaction occurs.<\/li>\r\n \t<li>The voltage of a voltaic cell can be determined by the reduction potentials of the half reactions.<\/li>\r\n \t<li>Voltaic cells are fashioned into batteries, which are a convenient source of electricity.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<div class=\"bcc-box bcc-info\">\r\n<h3>Exercises<\/h3>\r\n<div id=\"ball-ch14_s03_qs01\" class=\"qandaset block\">\r\n<h3 class=\"title\"><\/h3>\r\n<ol id=\"ball-ch14_s03_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p01\" class=\"para\">Draw the voltaic cell represented by this reaction and label the cathode, the anode, the salt bridge, the oxidation half cell, the reduction half cell, the positive electrode, and the negative electrode. Use <a class=\"xref\" href=\"#ball-ch14_s03_f01\">Figure 14.1 \"A Redox Reaction in Which the Two Half Reactions Are Physically Separated\"<\/a> as a guide.<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Zn +\u00a02 Ag<sup class=\"superscript\">+<\/sup> \u2192\u00a0Zn<sup class=\"superscript\">2+<\/sup> +\u00a02 Ag<\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p02\" class=\"para\">Draw the voltaic cell represented by this reaction and label the cathode, the anode, the salt bridge, the oxidation half cell, the reduction half cell, the positive electrode, and the negative electrode. Use <a class=\"xref\" href=\"#ball-ch14_s03_f01\">Figure 14.1 \"A Redox Reaction in Which the Two Half Reactions Are Physically Separated\"<\/a> as a guide.<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">3 Mg +\u00a02 Cr<sup class=\"superscript\">3+<\/sup> \u2192\u00a03 Mg<sup class=\"superscript\">2+<\/sup> +\u00a02 Cr<\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p03\" class=\"para\">What is the voltage of this half reaction?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">2F<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0F<sub class=\"subscript\">2<\/sub> +\u00a02e<sup class=\"superscript\">\u2212<\/sup><\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p05\" class=\"para\">What is the voltage of this half reaction?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Na \u2192\u00a0Na<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup><\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p07\" class=\"para\">What is the voltage of the voltaic cell in Exercise 1? Consult <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 \"Standard Reduction Potentials of Half Reactions\"<\/a> for data.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa06\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p09\" class=\"para\">What is the voltage of the voltaic cell in Exercise 2? Consult <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 \"Standard Reduction Potentials of Half Reactions\"<\/a> for data.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa07\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p11\" class=\"para\">Balance this redox reaction and determine its voltage. Is it spontaneous?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Li<sup class=\"superscript\">+<\/sup> +\u00a0Al \u2192\u00a0Li +\u00a0Al<sup class=\"superscript\">3+<\/sup><\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa08\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p13\" class=\"para\">Balance this redox reaction and determine its voltage. Is it spontaneous?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Pb<sup class=\"superscript\">2+<\/sup> +\u00a0Ni \u2192\u00a0Pb +\u00a0Ni<sup class=\"superscript\">2+<\/sup><\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa09\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p15\" class=\"para\">Balance this redox reaction and determine its voltage. Is it spontaneous?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Cu<sup class=\"superscript\">2+<\/sup> +\u00a0Ag +\u00a0Cl<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cu +\u00a0AgCl<\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa10\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p17\" class=\"para\">Balance this redox reaction and determine its voltage. Is it spontaneous?<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Mn<sup class=\"superscript\">2+<\/sup> +\u00a0Br<sub class=\"subscript\">2<\/sub> \u2192\u00a0MnO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup> +\u00a0Br<sup class=\"superscript\">\u2212<\/sup><\/span><\/span>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa11\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p19\" class=\"para\">Which reaction represents the cathode reaction in Exercise 7? The anode reaction?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa12\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p21\" class=\"para\">Which reaction represents the cathode reaction in Exercise 8? The anode reaction?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa13\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p23\" class=\"para\">Which reaction represents the cathode reaction in Exercise 9? The anode reaction?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa14\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p25\" class=\"para\">Which reaction represents the cathode reaction in Exercise 10? The anode reaction?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa15\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p27\" class=\"para\">A voltaic cell is based on this reaction:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Ni +\u00a02 Au<sup class=\"superscript\">+<\/sup> \u2192\u00a0Ni<sup class=\"superscript\">2+<\/sup> +\u00a02 Au<\/span><\/span>\r\n<p id=\"ball-ch14_s03_qs01_p28\" class=\"para\">If the voltage of the cell is 0.33 V, what is the standard reduction potential of the Au<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Au half reaction?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa16\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p30\" class=\"para\">A voltaic cell is based on this reaction:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">3 Pb +\u00a02 V<sup class=\"superscript\">3+<\/sup> \u2192\u00a03 Pb<sup class=\"superscript\">2+<\/sup> +\u00a02 V<\/span><\/span>\r\n<p id=\"ball-ch14_s03_qs01_p31\" class=\"para\">If the voltage of the cell is \u22120.72 V, what is the standard reduction potential of the V<sup class=\"superscript\">3+<\/sup> +\u00a03e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0V half reaction?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa17\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p33\" class=\"para\">What species is being oxidized and what species is being reduced in a dry cell?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa18\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p35\" class=\"para\">What species is being oxidized and what species is being reduced in an alkaline battery?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa19\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p37\" class=\"para\">What species is being oxidized and what species is being reduced in a silver oxide button battery?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa20\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p39\" class=\"para\">What species is being oxidized and what species is being reduced in a lead storage battery?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa21\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p41\" class=\"para\">Based on the data in <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 \"Standard Reduction Potentials of Half Reactions\"<\/a>, what is the highest voltage battery you can construct?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"ball-ch14_s03_qs01_qd01_qa22\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"ball-ch14_s03_qs01_p43\" class=\"para\">Based on the data in <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 \"Standard Reduction Potentials of Half Reactions\"<\/a>, what is the lowest voltage battery you can construct? (This may be more challenging to answer than Exercise 21.)<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<b>Answers<\/b>\r\n\r\n1.\r\n\r\n<a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Zinc-Silver-Reaction.png\"><img class=\"alignnone wp-image-4777 \" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22185412\/Zinc-Silver-Reaction-1.png\" alt=\"Zinc Silver Reaction\" width=\"385\" height=\"226\" \/><\/a>\r\n\r\n&nbsp;\r\n\r\n<strong>3.<\/strong>\r\n\r\n\u22122.87 V\r\n\r\n<strong>5.<\/strong>\r\n\r\n1.56 V\r\n\r\n<strong>7.<\/strong>\r\n\r\n3 Li<sup class=\"superscript\">+<\/sup> +\u00a0Al \u2192\u00a03 Li +\u00a0Al<sup class=\"superscript\">3+<\/sup>; \u22121.39 V; not spontaneous\r\n\r\n<strong>9.<\/strong>\r\n\r\nCu<sup class=\"superscript\">2+<\/sup> +\u00a02 Ag +\u00a02 Cl<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cu +\u00a02 AgCl; 0.12 V; spontaneous\r\n\r\n<strong>11.<\/strong>\r\n\r\ncathode reaction: Li<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Li; anode reaction: Al \u2192\u00a0Al<sup class=\"superscript\">3+<\/sup> +\u00a03e<sup class=\"superscript\">\u2212<\/sup><strong>13.<\/strong>\r\n\r\ncathode reaction: Cu<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cu; anode reaction: Ag +\u00a0Cl<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0AgCl +\u00a0e<sup class=\"superscript\">\u2212<\/sup><strong>15.<\/strong>\r\n\r\n0.08 V\r\n\r\n<strong>17.<\/strong>\r\n\r\noxidized: Zn; reduced: Mn\r\n\r\n<strong>19.<\/strong>\r\n\r\noxidized: Zn; reduced: Ag\r\n\r\n<strong>21.<\/strong>\r\n\r\n5.92 V from the reaction of F<sub class=\"subscript\">2<\/sub> and Li\r\n\r\n<\/div>\r\n<\/div>","rendered":"<div>\n<div id=\"ball-ch14_s03\" class=\"section\" lang=\"en\">\n<div id=\"ball-ch14_s03_n01\" class=\"learning_objectives editable block\">\n<div class=\"bcc-box bcc-highlight\">\n<h3>Learning Objectives<\/h3>\n<ol id=\"ball-ch14_s03_l01\">\n<li>Learn the parts of a voltaic cell.<\/li>\n<li>Combine half reactions to determine the voltage of a voltaic cell.<\/li>\n<li>Understand how voltaic cells are used as batteries.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"ball-ch14_s03_p01\" class=\"para editable block\">Consider this redox reaction:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">Zn +\u00a0Cu<sup class=\"superscript\">2+<\/sup> \u2192\u00a0Zn<sup class=\"superscript\">2+<\/sup> +\u00a0Cu<\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_p02\" class=\"para editable block\">If you were to mix zinc metal and copper ions in a container, this reaction would proceed by itself; we say that this reaction is <em class=\"emphasis\">spontaneous<\/em>.<\/p>\n<p id=\"ball-ch14_s03_p03\" class=\"para editable block\">Suppose, however, we set up this reaction in a way depicted in <a class=\"xref\" href=\"#ball-ch14_s03_f01\">Figure 14.1 &#8220;A Redox Reaction in Which the Two Half Reactions Are Physically Separated&#8221;<\/a>. Zinc and zinc ions are on one side of the system, while copper and copper ions are on the other side of the system. The two parts are connected with a wire.<\/p>\n<div id=\"ball-ch14_s03_f01\" class=\"figure large editable block\">\n<p class=\"title\"><span class=\"title-prefix\">Figure 14.1<\/span> A Redox Reaction in Which the Two Half Reactions Are Physically Separated<\/p>\n<p class=\"title\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Redox-Reaction-With-Voltmeter.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4772\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22185356\/Redox-Reaction-With-Voltmeter-1.png\" alt=\"Redox Reaction With Voltmeter\" width=\"420\" height=\"365\" \/><\/a><\/p>\n<p class=\"para\">One application of redox reactions requires that they be physically separated.<\/p>\n<\/div>\n<p id=\"ball-ch14_s03_p04\" class=\"para editable block\">Even though the two half reactions are physically separated, a spontaneous redox reaction still occurs. However, in this case, the electrons transfer through the wire connecting the two half reactions; that is, this setup becomes a source of electricity. Useful work can be extracted from the electrons as they transfer from one side to the other\u2014for example, a light bulb can be lit, or a motor can be operated. The apparatus as a whole, which allows useful electrical work to be extracted from a redox reaction, is called a <span class=\"margin_term\"><a class=\"glossterm\">voltaic (galvanic) cell<\/a><\/span>.<\/p>\n<p id=\"ball-ch14_s03_p05\" class=\"para editable block\">Each individual system that contains a half reaction is called a <span class=\"margin_term\"><a class=\"glossterm\">half cell<\/a><\/span>. The half cell that contains the oxidation reaction is called the <span class=\"margin_term\"><a class=\"glossterm\">anode<\/a><\/span>, while the half cell that contains the reduction reaction is called the <span class=\"margin_term\"><a class=\"glossterm\">cathode<\/a><\/span>. The cathode and anode collectively are the <span class=\"margin_term\"><a class=\"glossterm\">electrodes<\/a><\/span>\u00a0of the voltaic cell. Because electrons are coming from the anode, the anode is considered the <em class=\"emphasis\">negative<\/em> electrode of the cell, while the cathode is considered the <em class=\"emphasis\">positive<\/em> electrode of the cell. Finally, because electrons are moving from one half cell to the other, a charge imbalance builds up as the reaction proceeds. To counter that, a <span class=\"margin_term\"><a class=\"glossterm\">salt bridge<\/a><\/span>\u00a0is used; the salt bridge contains a solution of some ionic compound whose ions migrate to either side of the voltaic cell to maintain the charge balance.<\/p>\n<p id=\"ball-ch14_s03_p06\" class=\"para editable block\">The tendency for electrons to go from one half cell to another is called the <span class=\"margin_term\"><a class=\"glossterm\">voltage<\/a><span class=\"glossdef\">The tendency for electrons to go from one half cell to another.<\/span><\/span> of the voltaic cell, represented by <em class=\"emphasis\">E<\/em>. Sometimes the term <em class=\"emphasis\">potential<\/em> is used to represent the voltage of a cell. Voltage is expressed in volts (V). The voltage of a voltaic cell is determined by the <em class=\"emphasis\">difference<\/em> in the tendencies of the individual half cells and is characteristic of a given redox reaction when concentrations are specific (1.0 M for dissolved species and 1.0 atm for gases). Because the voltage of a redox reaction is determined by the difference of the tendencies of the individual half reactions, absolute voltages are unnecessary; only relative voltages of each half reaction are needed. The relative voltage of each half cell is represented as <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> and is based on the standard that the <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> for the reaction<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">H<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a01\/2 H<sub class=\"subscript\">2<\/sub><\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_p07\" class=\"para editable block\">is assigned to be exactly 0.000 V under standard conditions of pressure and concentration. <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 &#8220;Standard Reduction Potentials of Half Reactions&#8221;<\/a> lists some relative <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> values for some half reactions. Note that all half reactions are listed as reduction reactions, so these values are called the <span class=\"margin_term\"><a class=\"glossterm\">standard reduction potentials<\/a><span class=\"glossdef\">The voltage of a reduction half reaction relative to the hydrogen half reaction.<\/span><\/span> of each half reaction.<\/p>\n<div id=\"ball-ch14_s03_t01\" class=\"table block\">\n<p class=\"title\"><span class=\"title-prefix\">Table 14.1<\/span> Standard Reduction Potentials of Half Reactions<\/p>\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\n<thead>\n<tr>\n<th>Reduction Half Reaction<\/th>\n<th align=\"right\"><em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> (V)<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>F<sub class=\"subscript\">2<\/sub> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a02 F<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td align=\"right\">2.87<\/td>\n<\/tr>\n<tr>\n<td>Ce<sup class=\"superscript\">4+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Ce<sup class=\"superscript\">3+<\/sup><\/td>\n<td align=\"right\">1.61<\/td>\n<\/tr>\n<tr>\n<td>MnO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup> +\u00a08 H<sup class=\"superscript\">+<\/sup> +\u00a05e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Mn<sup class=\"superscript\">2+<\/sup> +\u00a04 H<sub class=\"subscript\">2<\/sub>O<\/td>\n<td align=\"right\">1.51<\/td>\n<\/tr>\n<tr>\n<td>Cl<sub class=\"subscript\">2<\/sub> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a02Cl<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td align=\"right\">1.36<\/td>\n<\/tr>\n<tr>\n<td>O<sub class=\"subscript\">2<\/sub> +\u00a04 H<sup class=\"superscript\">+<\/sup> +\u00a04e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O<\/td>\n<td align=\"right\">1.23<\/td>\n<\/tr>\n<tr>\n<td>Br<sub class=\"subscript\">2<\/sub> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a02 Br<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td align=\"right\">1.06<\/td>\n<\/tr>\n<tr>\n<td>NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup> +\u00a04 H<sup class=\"superscript\">+<\/sup> +\u00a03e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0NO +\u00a02 H<sub class=\"subscript\">2<\/sub>O<\/td>\n<td align=\"right\">0.96<\/td>\n<\/tr>\n<tr>\n<td>Ag<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Ag<\/td>\n<td align=\"right\">0.80<\/td>\n<\/tr>\n<tr>\n<td>Fe<sup class=\"superscript\">3+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Fe<sup class=\"superscript\">2+<\/sup><\/td>\n<td align=\"right\">0.77<\/td>\n<\/tr>\n<tr>\n<td>I<sub class=\"subscript\">2<\/sub> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a02I<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td align=\"right\">0.54<\/td>\n<\/tr>\n<tr>\n<td>Cu<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cu<\/td>\n<td align=\"right\">0.34<\/td>\n<\/tr>\n<tr>\n<td>AgCl +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Ag +\u00a0Cl<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td align=\"right\">0.222<\/td>\n<\/tr>\n<tr>\n<td>Sn<sup class=\"superscript\">4+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Sn<sup class=\"superscript\">2+<\/sup><\/td>\n<td align=\"right\">0.15<\/td>\n<\/tr>\n<tr>\n<td>2H<sup class=\"superscript\">+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0H<sub class=\"subscript\">2<\/sub><\/td>\n<td align=\"right\">0.000<\/td>\n<\/tr>\n<tr>\n<td>Pb<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Pb<\/td>\n<td align=\"right\">\u22120.126<\/td>\n<\/tr>\n<tr>\n<td>Ni<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Ni<\/td>\n<td align=\"right\">\u22120.25<\/td>\n<\/tr>\n<tr>\n<td>Cr<sup class=\"superscript\">3+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cr<sup class=\"superscript\">2+<\/sup><\/td>\n<td align=\"right\">\u22120.41<\/td>\n<\/tr>\n<tr>\n<td>Fe<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Fe<\/td>\n<td align=\"right\">\u22120.44<\/td>\n<\/tr>\n<tr>\n<td>Cr<sup class=\"superscript\">3+<\/sup> +\u00a03e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cr<\/td>\n<td align=\"right\">\u22120.74<\/td>\n<\/tr>\n<tr>\n<td>Zn<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Zn<\/td>\n<td align=\"right\">\u22120.76<\/td>\n<\/tr>\n<tr>\n<td>Cr<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cr<\/td>\n<td align=\"right\">\u22120.91<\/td>\n<\/tr>\n<tr>\n<td>Ba<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Ba<\/td>\n<td align=\"right\">\u22121.57<\/td>\n<\/tr>\n<tr>\n<td>Al<sup class=\"superscript\">3+<\/sup>+\u00a03e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Al<\/td>\n<td align=\"right\">\u22121.66<\/td>\n<\/tr>\n<tr>\n<td>Mg<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Mg<\/td>\n<td align=\"right\">\u22122.37<\/td>\n<\/tr>\n<tr>\n<td>Na<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Na<\/td>\n<td align=\"right\">\u22122.714<\/td>\n<\/tr>\n<tr>\n<td>Li<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Li<\/td>\n<td align=\"right\">\u22123.045<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p id=\"ball-ch14_s03_p08\" class=\"para editable block\"><a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 &#8220;Standard Reduction Potentials of Half Reactions&#8221;<\/a> lists only reduction reactions, but a redox reaction has a reduction <em class=\"emphasis\">and<\/em> an oxidation. To make the oxidation reaction, simply reverse the reduction reaction in <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 &#8220;Standard Reduction Potentials of Half Reactions&#8221;<\/a> and change the sign on the <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> value. If the reduction potential is negative, make the voltage for the oxidation positive; if the reduction potential is positive, make the voltage for the oxidation negative.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 6<\/h3>\n<p id=\"ball-ch14_s03_p09\" class=\"para\">What is the value of <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> for this half reaction?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Ag +\u00a0Cl<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0AgCl +\u00a0e<sup class=\"superscript\">\u2212<\/sup><\/span><\/span><\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch14_s03_p10\" class=\"para\">The given reaction is the reverse of this reaction:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">AgCl +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Ag +\u00a0Cl<sup class=\"superscript\">\u2212 \u00a0 \u00a0<\/sup><em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> = 0.222 V<\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_p11\" class=\"para\">Therefore, the <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> of the given reaction is \u22120.222 V.<\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch14_s03_p12\" class=\"para\">What is the value of <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> for this half reaction?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Na \u2192\u00a0Na<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup><\/span><\/span><\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch14_s03_p13\" class=\"para\">2.714 V<\/p>\n<\/div>\n<p id=\"ball-ch14_s03_p14\" class=\"para editable block\">To determine the overall voltage of a particular voltaic cell, simply combine the voltages of the oxidation and reduction half reactions. Even if you need to take a multiple of a half reaction for the electrons to cancel, do not take the multiple of the <em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub>. Use the values directly as is from <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 &#8220;Standard Reduction Potentials of Half Reactions&#8221;<\/a>.<\/p>\n<p id=\"ball-ch14_s03_p15\" class=\"para editable block\">Spontaneous redox reactions have positive overall voltages. If the voltage of the reaction as written is negative, it is not spontaneous in that direction. Rather, the reverse reaction is the spontaneous redox reaction.<\/p>\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Example 7<\/h3>\n<p id=\"ball-ch14_s03_p16\" class=\"para\">What is the voltage of a voltaic cell based on this reaction? Is the reaction spontaneous as written?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">2 NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup> +\u00a08 H<sup class=\"superscript\">+<\/sup> +\u00a03 Cu \u2192\u00a02 NO +\u00a04 H<sub class=\"subscript\">2<\/sub>O +\u00a03 Cu<sup class=\"superscript\">2+<\/sup><\/span><\/span><\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"ball-ch14_s03_p17\" class=\"para\">The overall redox reaction is formed from these two half reactions:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup> +\u00a04 H<sup class=\"superscript\">+<\/sup> +\u00a03e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0NO +\u00a02 H<sub class=\"subscript\">2<\/sub>O \u00a0 \u00a0\u00a0<em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> = 0.96 V<\/span><\/span><br \/>\n<span class=\"informalequation\"><span class=\"mathphrase\">Cu<sup class=\"superscript\">2+<\/sup> +\u00a02 e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cu \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0\u00a0<em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> = 0.34 V<\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_p18\" class=\"para\">The second reaction is reversed in the overall redox reaction, so its voltage changes sign from the reduction reaction:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Cu \u2192\u00a0Cu<sup class=\"superscript\">2+<\/sup> +\u00a02 e<sup class=\"superscript\">\u2212 \u00a0 \u00a0 \u00a0\u00a0<\/sup><em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> = \u22120.34 V<\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_p19\" class=\"para\">To obtain the voltage of the voltaic cell based on the overall reaction, we simply combine the two voltages of the half reactions:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\"><em class=\"emphasis\">E<\/em> = 0.96 +\u00a0(\u22120.34) = 0.62 V<\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_p20\" class=\"para\">Because the overall voltage is positive, the reaction is spontaneous as written.<\/p>\n<p class=\"simpara\"><em class=\"emphasis bolditalic\">Test Yourself<\/em><\/p>\n<p id=\"ball-ch14_s03_p21\" class=\"para\">What is the voltage of a voltaic cell based on this reaction? Is the reaction spontaneous as written?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">5 Ni +\u00a02 MnO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup> +\u00a016 H<sup class=\"superscript\">+<\/sup> \u2192\u00a03 Mn<sup class=\"superscript\">2+<\/sup> +\u00a08 H<sub class=\"subscript\">2<\/sub>O +\u00a05 Ni<sup class=\"superscript\">2+<\/sup><\/span><\/span><\/p>\n<p class=\"simpara\"><em class=\"emphasis\">Answer<\/em><\/p>\n<p id=\"ball-ch14_s03_p22\" class=\"para\">1.76 V; spontaneous<\/p>\n<\/div>\n<p id=\"ball-ch14_s03_p23\" class=\"para editable block\">Technically, any redox reaction can be set up to make a voltaic cell. In modern society, however, only certain redox reactions are put to practical use. A portable voltaic cell that generates electricity to power devices for our convenience is called a <span class=\"margin_term\"><a class=\"glossterm\">battery<\/a><\/span>. All batteries are based on redox reactions.<\/p>\n<p id=\"ball-ch14_s03_p24\" class=\"para editable block\">The first battery (called a \u201cvoltaic pile\u201d) was constructed by the Italian scientist Alessandro Volta in 1800 and was based on the copper\/zinc reaction depicted in <a class=\"xref\" href=\"#ball-ch14_s03_f01\">Figure 14.1 &#8220;A Redox Reaction in Which the Two Half Reactions Are Physically Separated&#8221;<\/a>. Unfortunately, it was messy, requiring quantities of copper and zinc salts dissolved in water. In 1866, the French scientist Georges Leclanch\u00e9 invented the <span class=\"margin_term\"><a class=\"glossterm\">dry cell<\/a><\/span>, a precursor to today\u2019s modern battery. A schematic of a dry cell is shown in <a class=\"xref\" href=\"#ball-ch14_s03_f02\">Figure 14.2 &#8220;Dry Cells&#8221;<\/a>. The zinc case and the central carbon rod serve as the anode and cathode, respectively. The other reactants are combined into a moist paste that minimizes free liquid, so the battery is less messy (hence the name <em class=\"emphasis\">dry cell<\/em>). The actual redox reaction is complex but can be represented by the following redox reaction:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">Zn +\u00a02 MnO<sub class=\"subscript\">2<\/sub> +\u00a02 NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> \u2192\u00a0Zn<sup class=\"superscript\">2+<\/sup> +\u00a0Mn<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub> +\u00a02 NH<sub class=\"subscript\">3<\/sub> +\u00a0H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_p25\" class=\"para editable block\">A dry cell has a voltage of about 1.56 V. While common and useful, dry cells have relatively short lifetimes and contain acidic components. They also cannot be recharged, so they are one-use only. Batteries that can be used only once are called <span class=\"margin_term\"><a class=\"glossterm\">primary batteries<\/a><\/span>.<\/p>\n<div id=\"ball-ch14_s03_f02\" class=\"figure large editable block\">\n<p class=\"title\"><span class=\"title-prefix\">Figure 14.2<\/span> Dry Cells<\/p>\n<p class=\"title\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Dry-Cell.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4774\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22185400\/Dry-Cell-1.png\" alt=\"Dry Cell\" width=\"433\" height=\"450\" \/><\/a><\/p>\n<p class=\"para\">The Leclanch\u00e9 dry cell is a common type of battery.<\/p>\n<\/div>\n<p id=\"ball-ch14_s03_p26\" class=\"para editable block\">In the late 1950s, Lewis Urry of the Eveready Battery Company in Ohio invented the <span class=\"margin_term\"><a class=\"glossterm\">alkaline battery<\/a><\/span>\u00a0(still marketed today under the trade name <em class=\"emphasis\">Energizer<\/em>). Alkaline batteries are similar to dry cells, but they use a basic moist paste rather than an acidic one. Moreover, the net amount of base does not change during the course of the redox reaction. The overall redox reaction is as follows:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">Zn +\u00a02MnO<sub class=\"subscript\">2<\/sub> \u2192\u00a0ZnO +\u00a0Mn<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">3<\/sub><\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_p27\" class=\"para editable block\">Alkaline batteries have the advantage of being longer lasting and holding their voltage better\u2014about 1.54\u00a0V\u2014throughout their lifetime.<\/p>\n<p id=\"ball-ch14_s03_p28\" class=\"para editable block\">A common type of battery, especially with the increased popularity of personal electronic devices, is the button battery (<a class=\"xref\" href=\"#ball-ch14_s03_f03\">Figure 14.3 &#8220;Button Batteries&#8221;<\/a>). A button battery is a small battery that can power small electronic devices; the batteries can be as small as 5 mm across. Two popular redox reactions used for button batteries are the alkaline dry-cell reaction and a silver oxide-based reaction:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">Zn +\u00a0Ag<sub class=\"subscript\">2<\/sub>O \u2192\u00a0ZnO +\u00a02 Ag<\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_p29\" class=\"para editable block\">Some button batteries use a lithium-based redox reaction, typified by this anode reaction:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">Li \u2192\u00a0Li<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup><em class=\"emphasis\">E<\/em><sub class=\"subscript\">1\/2<\/sub> = 3.045 V<\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_p30\" class=\"para editable block\">The actual redox reaction depends on the composition of the cathode and is variable depending on voltage. Lithium batteries can also be used for applications that require more energy, such as portable computers and electric vehicles. Some lithium-based batteries are rechargeable and can be used over and over again; such batteries are called <span class=\"margin_term\"><a class=\"glossterm\">secondary batteries<\/a><\/span>.<\/p>\n<div id=\"ball-ch14_s03_f03\" class=\"figure small editable block\">\n<p class=\"title\"><span class=\"title-prefix\">Figure 14.3<\/span> Button Batteries<\/p>\n<div id=\"attachment_3262\" style=\"width: 521px\" class=\"wp-caption alignnone\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/07\/Coin-cells.jpg\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-3262\" class=\"wp-image-3262 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22185402\/Coin-cells-1.jpg\" alt=\"Button batteries like those seen here can be used for a variety of portable electronics, from watches and hearing aids to handheld gaming devices. Source: \u201cCoin Cells\u201d by Gerhard H Wrodnigg is licensed under the Creative Commons Attribution-Share Alike 2.5 Generic license.\" width=\"511\" height=\"363\" \/><\/a><\/p>\n<p id=\"caption-attachment-3262\" class=\"wp-caption-text\">Button batteries like those seen here can be used for a variety of portable electronics, from watches and hearing aids to handheld gaming devices.<br \/>Source: \u201cCoin Cells\u201d by Gerhard H Wrodnigg is licensed under the Creative Commons Attribution-Share Alike 2.5 Generic license.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p id=\"ball-ch14_s03_p31\" class=\"para editable block\">An important secondary battery is the lead storage battery. The lead storage battery is based on this redox reaction:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">Pb +\u00a0PbO<sub class=\"subscript\">2<\/sub> +\u00a04 H<sup class=\"superscript\">+<\/sup> +\u00a0SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup> \u2192\u00a02 PbSO<sub class=\"subscript\">4<\/sub> +\u00a02 H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_p32\" class=\"para editable block\">The redox reaction produces about 2 V, but it is typical to tie several individual batteries together to generate a larger voltage. The lead storage battery has the distinction that the product of both half reactions is PbSO<sub class=\"subscript\">4<\/sub>, which as a solid accumulates on the many plates within each cell. The lead storage battery is a secondary battery, as it can be recharged and reused many times. Because it is based on lead, these batteries are rather heavy. They should also be recycled when replaced so that potentially dangerous lead does not escape into the environment. Because of their characteristics, lead storage batteries are used to start large engines in automobiles, boats, and airplanes.<\/p>\n<\/div>\n<div id=\"ball-ch14_s03_n04\" class=\"callout block\">\n<h3 class=\"title\">Chemistry Is Everywhere: Fuel Cells<\/h3>\n<p id=\"ball-ch14_s03_p33\" class=\"para\">A <em class=\"emphasis\">fuel cell<\/em> is a type of battery in which reactants flow continuously into a specialized reaction chamber, and products flow out continuously while electrons are extracted from the reaction. Because all reactions in a fuel cell consist of a fuel and an oxidizer undergoing a redox reaction, an introduction of fuel cells is at home in a discussion of redox chemistry.<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Fuel-Cell.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4775\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22185405\/Fuel-Cell-1.png\" alt=\"Fuel Cell\" width=\"428\" height=\"414\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<p class=\"para\">This fuel cell uses H<sub class=\"subscript\">2<\/sub> as the fuel and O<sub class=\"subscript\">2<\/sub> as the oxidizer.<\/p>\n<\/div>\n<p id=\"ball-ch14_s03_p34\" class=\"para\">By far the most common fuel cell reaction is based on hydrogen and oxygen:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">2 H<sub class=\"subscript\">2<\/sub> +\u00a0O<sub class=\"subscript\">2<\/sub> \u2192\u00a02 H<sub class=\"subscript\">2<\/sub>O \u00a0 \u00a0<em class=\"emphasis\">E<\/em> = 1.23 V under standard conditions<\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_p35\" class=\"para\">However, fuel cells typically do not work under standard nor even optimal conditions, so they typically generate about 0.6\u20130.7 V. In this fuel cell, the only two products are water and electricity, so the fuel cell not only does not create pollution but also makes a by-product that in some environments is a valuable commodity (water). Other fuels can be used besides hydrogen; fuel cells have been developed that work on methane, methyl alcohol, ethyl alcohol, carbon-rich materials, and even magnesium metal.<\/p>\n<p id=\"ball-ch14_s03_p36\" class=\"para\">Hydrogen-based fuel cells were and are used to provide electricity for manned space vehicles, partly because their only chemical product is water, which could be used for drinking. However, there has been a recent resurgence in interest in fuel cells because of their potential use in electric cars. Most electric cars run on conventional batteries, which can be very heavy and expensive to replace. It is thought that fuel cells, rather than conventional batteries, might be better sources of electricity for automobiles.<\/p>\n<p id=\"ball-ch14_s03_p37\" class=\"para\">Several current barriers to fuel cell use in electric cars include capacity, cost, and overall energy efficiency. The 2008 Honda FCX, the first production model of a vehicle powered with a fuel cell, can hold 4.1 kg (just under 9\u00a0lb) of highly pressured H<sub class=\"subscript\">2<\/sub> gas and has a range of 450 km (280 mi). It costs about $120,000\u2013$140,000 to build, making the vehicle beyond the ability of most people to own. Finally, it always requires more energy to produce elemental hydrogen as a fuel than can be extracted from hydrogen as a fuel. As such, hydrogen is described as an energy carrier (like electricity) rather than an energy source (like oil and gas). This distinction points out a fundamental argument against fuel cells as a \u201cbetter\u201d power source.<\/p>\n<p class=\"para\"><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Honda-FCX.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4776\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22185409\/Honda-FCX-1.png\" alt=\"Honda FCX\" width=\"494\" height=\"242\" \/><\/a><\/p>\n<div class=\"informalfigure large\">\n<p class=\"para\">The 2008 Honda FCX was the first production car to use a fuel cell as a power source. Nonetheless, the car is in very limited service because of its need for relatively large quantities of elemental hydrogen as fuel.<\/p>\n<div class=\"copyright\">\n<p class=\"para\">Source: Photo courtesy of vernieman, <a class=\"link\" href=\"http:\/\/commons.wikimedia.org\/wiki\/File:Honda_FCX_2006_KLIMS_front.jpg\" target=\"_blank\" rel=\"noopener\">http:\/\/commons.wikimedia.org\/wiki\/File:Honda_FCX_2006_KLIMS_front.jpg<\/a>.<\/p>\n<\/div>\n<\/div>\n<p id=\"ball-ch14_s03_p38\" class=\"para\">The limitations notwithstanding, there is a lot of interest in fuel cell research. If ways can be found to circumvent their current limitations, fuel cells may become more and more common as power sources.<\/p>\n<\/div>\n<div id=\"ball-ch14_s03_n05\" class=\"key_takeaways editable block\">\n<div class=\"bcc-box bcc-success\">\n<h3>Key Takeaways<\/h3>\n<ul id=\"ball-ch14_s03_l02\" class=\"itemizedlist\">\n<li>A voltaic cell produces electricity as a redox reaction occurs.<\/li>\n<li>The voltage of a voltaic cell can be determined by the reduction potentials of the half reactions.<\/li>\n<li>Voltaic cells are fashioned into batteries, which are a convenient source of electricity.<\/li>\n<\/ul>\n<\/div>\n<div class=\"bcc-box bcc-info\">\n<h3>Exercises<\/h3>\n<div id=\"ball-ch14_s03_qs01\" class=\"qandaset block\">\n<h3 class=\"title\"><\/h3>\n<ol id=\"ball-ch14_s03_qs01_qd01\" class=\"qandadiv\">\n<li id=\"ball-ch14_s03_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p01\" class=\"para\">Draw the voltaic cell represented by this reaction and label the cathode, the anode, the salt bridge, the oxidation half cell, the reduction half cell, the positive electrode, and the negative electrode. Use <a class=\"xref\" href=\"#ball-ch14_s03_f01\">Figure 14.1 &#8220;A Redox Reaction in Which the Two Half Reactions Are Physically Separated&#8221;<\/a> as a guide.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Zn +\u00a02 Ag<sup class=\"superscript\">+<\/sup> \u2192\u00a0Zn<sup class=\"superscript\">2+<\/sup> +\u00a02 Ag<\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p02\" class=\"para\">Draw the voltaic cell represented by this reaction and label the cathode, the anode, the salt bridge, the oxidation half cell, the reduction half cell, the positive electrode, and the negative electrode. Use <a class=\"xref\" href=\"#ball-ch14_s03_f01\">Figure 14.1 &#8220;A Redox Reaction in Which the Two Half Reactions Are Physically Separated&#8221;<\/a> as a guide.<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">3 Mg +\u00a02 Cr<sup class=\"superscript\">3+<\/sup> \u2192\u00a03 Mg<sup class=\"superscript\">2+<\/sup> +\u00a02 Cr<\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p03\" class=\"para\">What is the voltage of this half reaction?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">2F<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0F<sub class=\"subscript\">2<\/sub> +\u00a02e<sup class=\"superscript\">\u2212<\/sup><\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p05\" class=\"para\">What is the voltage of this half reaction?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Na \u2192\u00a0Na<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup><\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p07\" class=\"para\">What is the voltage of the voltaic cell in Exercise 1? Consult <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 &#8220;Standard Reduction Potentials of Half Reactions&#8221;<\/a> for data.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p09\" class=\"para\">What is the voltage of the voltaic cell in Exercise 2? Consult <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 &#8220;Standard Reduction Potentials of Half Reactions&#8221;<\/a> for data.<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p11\" class=\"para\">Balance this redox reaction and determine its voltage. Is it spontaneous?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Li<sup class=\"superscript\">+<\/sup> +\u00a0Al \u2192\u00a0Li +\u00a0Al<sup class=\"superscript\">3+<\/sup><\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p13\" class=\"para\">Balance this redox reaction and determine its voltage. Is it spontaneous?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Pb<sup class=\"superscript\">2+<\/sup> +\u00a0Ni \u2192\u00a0Pb +\u00a0Ni<sup class=\"superscript\">2+<\/sup><\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p15\" class=\"para\">Balance this redox reaction and determine its voltage. Is it spontaneous?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Cu<sup class=\"superscript\">2+<\/sup> +\u00a0Ag +\u00a0Cl<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cu +\u00a0AgCl<\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa10\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p17\" class=\"para\">Balance this redox reaction and determine its voltage. Is it spontaneous?<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Mn<sup class=\"superscript\">2+<\/sup> +\u00a0Br<sub class=\"subscript\">2<\/sub> \u2192\u00a0MnO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup> +\u00a0Br<sup class=\"superscript\">\u2212<\/sup><\/span><\/span><\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa11\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p19\" class=\"para\">Which reaction represents the cathode reaction in Exercise 7? The anode reaction?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa12\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p21\" class=\"para\">Which reaction represents the cathode reaction in Exercise 8? The anode reaction?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa13\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p23\" class=\"para\">Which reaction represents the cathode reaction in Exercise 9? The anode reaction?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa14\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p25\" class=\"para\">Which reaction represents the cathode reaction in Exercise 10? The anode reaction?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa15\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p27\" class=\"para\">A voltaic cell is based on this reaction:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Ni +\u00a02 Au<sup class=\"superscript\">+<\/sup> \u2192\u00a0Ni<sup class=\"superscript\">2+<\/sup> +\u00a02 Au<\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_qs01_p28\" class=\"para\">If the voltage of the cell is 0.33 V, what is the standard reduction potential of the Au<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Au half reaction?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa16\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p30\" class=\"para\">A voltaic cell is based on this reaction:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">3 Pb +\u00a02 V<sup class=\"superscript\">3+<\/sup> \u2192\u00a03 Pb<sup class=\"superscript\">2+<\/sup> +\u00a02 V<\/span><\/span><\/p>\n<p id=\"ball-ch14_s03_qs01_p31\" class=\"para\">If the voltage of the cell is \u22120.72 V, what is the standard reduction potential of the V<sup class=\"superscript\">3+<\/sup> +\u00a03e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0V half reaction?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa17\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p33\" class=\"para\">What species is being oxidized and what species is being reduced in a dry cell?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa18\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p35\" class=\"para\">What species is being oxidized and what species is being reduced in an alkaline battery?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa19\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p37\" class=\"para\">What species is being oxidized and what species is being reduced in a silver oxide button battery?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa20\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p39\" class=\"para\">What species is being oxidized and what species is being reduced in a lead storage battery?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa21\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p41\" class=\"para\">Based on the data in <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 &#8220;Standard Reduction Potentials of Half Reactions&#8221;<\/a>, what is the highest voltage battery you can construct?<\/p>\n<\/div>\n<\/li>\n<li id=\"ball-ch14_s03_qs01_qd01_qa22\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"ball-ch14_s03_qs01_p43\" class=\"para\">Based on the data in <a class=\"xref\" href=\"#ball-ch14_s03_t01\">Table 14.1 &#8220;Standard Reduction Potentials of Half Reactions&#8221;<\/a>, what is the lowest voltage battery you can construct? (This may be more challenging to answer than Exercise 21.)<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<p><b>Answers<\/b><\/p>\n<p>1.<\/p>\n<p><a href=\"http:\/\/opentextbc.ca\/introductorychemistry\/wp-content\/uploads\/sites\/17\/2014\/09\/Zinc-Silver-Reaction.png\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-4777\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/4084\/2019\/04\/22185412\/Zinc-Silver-Reaction-1.png\" alt=\"Zinc Silver Reaction\" width=\"385\" height=\"226\" \/><\/a><\/p>\n<p>&nbsp;<\/p>\n<p><strong>3.<\/strong><\/p>\n<p>\u22122.87 V<\/p>\n<p><strong>5.<\/strong><\/p>\n<p>1.56 V<\/p>\n<p><strong>7.<\/strong><\/p>\n<p>3 Li<sup class=\"superscript\">+<\/sup> +\u00a0Al \u2192\u00a03 Li +\u00a0Al<sup class=\"superscript\">3+<\/sup>; \u22121.39 V; not spontaneous<\/p>\n<p><strong>9.<\/strong><\/p>\n<p>Cu<sup class=\"superscript\">2+<\/sup> +\u00a02 Ag +\u00a02 Cl<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cu +\u00a02 AgCl; 0.12 V; spontaneous<\/p>\n<p><strong>11.<\/strong><\/p>\n<p>cathode reaction: Li<sup class=\"superscript\">+<\/sup> +\u00a0e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Li; anode reaction: Al \u2192\u00a0Al<sup class=\"superscript\">3+<\/sup> +\u00a03e<sup class=\"superscript\">\u2212<\/sup><strong>13.<\/strong><\/p>\n<p>cathode reaction: Cu<sup class=\"superscript\">2+<\/sup> +\u00a02e<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0Cu; anode reaction: Ag +\u00a0Cl<sup class=\"superscript\">\u2212<\/sup> \u2192\u00a0AgCl +\u00a0e<sup class=\"superscript\">\u2212<\/sup><strong>15.<\/strong><\/p>\n<p>0.08 V<\/p>\n<p><strong>17.<\/strong><\/p>\n<p>oxidized: Zn; reduced: Mn<\/p>\n<p><strong>19.<\/strong><\/p>\n<p>oxidized: Zn; reduced: Ag<\/p>\n<p><strong>21.<\/strong><\/p>\n<p>5.92 V from the reaction of F<sub class=\"subscript\">2<\/sub> and Li<\/p>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-3217\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li><strong>Authored by<\/strong>: Jessie A. 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