{"id":2057,"date":"2015-04-22T20:20:44","date_gmt":"2015-04-22T20:20:44","guid":{"rendered":"https:\/\/courses.candelalearning.com\/oschemtemp\/?post_type=chapter&#038;p=2057"},"modified":"2017-06-19T15:03:14","modified_gmt":"2017-06-19T15:03:14","slug":"molecular-orbital-theory","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/chapter\/molecular-orbital-theory\/","title":{"raw":"5.7 Molecular Orbital Theory","rendered":"5.7 Molecular Orbital Theory"},"content":{"raw":"<div class=\"textbox learning-objectives\">\r\n<h3>Learning Objectives<\/h3>\r\nBy the end of this section, you will be able to:\r\n<ul>\r\n \t<li>Outline the basic quantum-mechanical approach to deriving molecular orbitals from atomic orbitals<\/li>\r\n \t<li>Describe traits of bonding and anti-bonding molecular orbitals<\/li>\r\n \t<li>Calculate bond orders based on molecular electron configurations<\/li>\r\n \t<li>Write molecular electron configurations for H<sub>2<\/sub> and He<sub>2<\/sub> molecules<\/li>\r\n \t<li>Relate these electron configurations to the molecules\u2019 stabilities and magnetic properties<\/li>\r\n<\/ul>\r\n<\/div>\r\nFor almost every covalent molecule that exists, we can now draw the Lewis structure, predict the electron-pair geometry, predict the molecular geometry, and come close to predicting bond angles. However, one of the most important molecules we know, the oxygen molecule O<sub>2<\/sub>, presents a problem with respect to its Lewis structure. We would write the following Lewis structure for O<sub>2<\/sub>:\r\n\r\n<img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211927\/CNX_Chem_08_04_O2_img1.jpg\" alt=\"A Lewis structure is shown. It is made up of two oxygen atoms, each with two lone pairs of electrons, bonded together with a double bond.\" \/>\r\n\r\nThis electronic structure adheres to all the rules governing Lewis theory. There is an O=O double bond, and each oxygen atom has eight electrons around it. However, this picture is at odds with the magnetic behavior of oxygen. By itself, O<sub>2<\/sub> is not magnetic, but it is attracted to magnetic fields. Thus, when we pour liquid oxygen past a strong magnet, it collects between the poles of the magnet and defies gravity, as in Figure 1. Such attraction to a magnetic field is called <strong>paramagnetism<\/strong>, and it arises in molecules that have unpaired electrons. And yet, the Lewis structure of O<sub>2<\/sub> indicates that all electrons are paired. How do we account for this discrepancy?\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"750\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211747\/CNX_Chem_08_00_LiqO21.jpg\" alt=\"A pitcher is shown pouring liquid oxygen through the gap between two magnets, where it has formed a solid disk. A call out box near the stream of liquid oxygen shows an image of six pairs of spheres, spread apart from one another. Another call out box near the solid disk shows ten pairs of spheres much closer together.\" width=\"750\" height=\"346\" \/> Figure 1. Oxygen molecules orient randomly most of the time, as shown in the top magnified view. However, when we pour liquid oxygen through a magnet, the molecules line up with the magnetic field, and the attraction allows them to stay suspended between the poles of the magnet where the magnetic field is strongest. Other diatomic molecules (like N<sub>2<\/sub>) flow past the magnet. The detailed explanation of bonding described in this chapter allows us to understand this phenomenon. (credit: modification of work by Jefferson Lab)[\/caption]\r\n\r\nMagnetic susceptibility measures the force experienced by a substance in a magnetic field. When we compare the weight of a sample to the weight measured in a magnetic field (Figure 2), paramagnetic samples that are attracted to the magnet will appear heavier because of the force exerted by the magnetic field. We can calculate the number of unpaired electrons based on the increase in weight.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"800\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211928\/CNX_Chem_08_04_Gouy1.jpg\" alt=\"A diagram depicts a stand supporting two objects that are held in balance by a horizontal bar. On the right, the bar supports a dish that is holding two weights. On the left there is a line attached to a test tube labeled, \u201cSample tube.\u201d The test tube has been lowered into the space labeled, \u201cMagnetic field,\u201d between two structures labeled, \u201cElectromagnets.\u201d\" width=\"800\" height=\"601\" \/> Figure 2. A Gouy balance compares the mass of a sample in the presence of a magnetic field with the mass with the electromagnet turned off to determine the number of unpaired electrons in a sample.[\/caption]\r\n\r\nExperiments show that each O<sub>2<\/sub> molecule has two unpaired electrons. The Lewis-structure model does not predict the presence of these two unpaired electrons. Unlike oxygen, the apparent weight of most molecules decreases slightly in the presence of an inhomogeneous magnetic field. Materials in which all of the electrons are paired are <strong>diamagnetic<\/strong> and weakly repel a magnetic field. Paramagnetic and diamagnetic materials do not act as permanent magnets. Only in the presence of an applied magnetic field do they demonstrate attraction or repulsion.\r\n<div class=\"textbox\">Water, like most molecules, contains all paired electrons. Living things contain a large percentage of water, so they demonstrate diamagnetic behavior. If you place a frog near a sufficiently large magnet, it will levitate. You can see videos of diamagnetic floating frogs, strawberries, and more at the <a href=\"http:\/\/www.ru.nl\/hfml\/research\/levitation\/diamagnetic\/\" target=\"_blank\" rel=\"noopener noreferrer\">Radboud University Diamagnetic Levitation website<\/a>.<\/div>\r\nMolecular orbital theory (MO theory) provides an explanation of chemical bonding that accounts for the paramagnetism of the oxygen molecule. It also explains the bonding in a number of other molecules, such as violations of the octet rule and more molecules with more complicated bonding (beyond the scope of this text) that are difficult to describe with Lewis structures. Additionally, it provides a model for describing the energies of electrons in a molecule and the probable location of these electrons. Unlike valence bond theory, which uses hybrid orbitals that are assigned to one specific atom, MO theory uses the combination of atomic orbitals to yield molecular orbitals that are <em>delocalized<\/em> over the entire molecule rather than being localized on its constituent atoms. MO theory also helps us understand why some substances are electrical conductors, others are semiconductors, and still others are insulators. Table 1 summarizes the main points of the two complementary bonding theories. Both theories provide different, useful ways of describing molecular structure.\r\n<table summary=\"A table is shown that is composed of two columns and six rows. The header row reads, \u201cValence Bond Theory,\u201d and, \u201cMolecular Orbital Theory.\u201d The first column contains the phrases: \u201cconsiders bonds as localized between one pair of atoms,\u201d \u201ccreates bonds from overlap of atomic orbitals ( s, p, d\u2026) and hybrid orbitals ( s p , s p superscript 2, s p superscript 3 \u2026 ) ,\u201d \u201cforms sigma or pi bonds,\u201d \u201cpredicts molecular shape based on the number of regions of electron density,\u201d and, \u201cneeds multiple structures are needed to describe resonance.\u201d The second column reads, \u201cconsiders electrons delocalized throughout the entire molecule,\u201d \u201ccombines atomic orbitals to form molecular orbitals ( sigma, sigma superscript asterik, pi, pi superscript asterisk ),\u201d \u201ccreates bonding and antibonding interactions based on which orbitals are filled,\u201d \u201cpredicts the arrangement of electrons in molecules.\u201d\">\r\n<thead>\r\n<tr>\r\n<th colspan=\"2\">Table 1. Comparison of Bonding Theories<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<th>Valence Bond Theory<\/th>\r\n<th>Molecular Orbital Theory<\/th>\r\n<\/tr>\r\n<tr>\r\n<td>considers bonds as localized between one pair of atoms<\/td>\r\n<td>considers electrons delocalized throughout the entire molecule<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>creates bonds from overlap of atomic orbitals (<em>s, p, d<\/em>\u2026) and hybrid orbitals (<em>sp, sp<\/em><sup>2<\/sup>, <em>sp<\/em><sup>3<\/sup>\u2026)<\/td>\r\n<td>combines atomic orbitals to form molecular orbitals (\u03c3, \u03c3*, \u03c0, \u03c0*)<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>forms \u03c3 or \u03c0 bonds<\/td>\r\n<td>creates bonding and antibonding interactions based on which orbitals are filled<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>predicts molecular shape based on the number of regions of electron density<\/td>\r\n<td>predicts the arrangement of electrons in molecules<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>needs multiple structures to describe resonance<\/td>\r\n<td><\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<strong>Molecular orbital theory <\/strong>describes the distribution of electrons in molecules in much the same way that the distribution of electrons in atoms is described using atomic orbitals. Using quantum mechanics, the behavior of an electron in a molecule is still described by a wave function, <em>\u03a8<\/em>, analogous to the behavior in an atom. Just like electrons around isolated atoms, electrons around atoms in molecules are limited to discrete (quantized) energies. The region of space in which a valence electron in a molecule is likely to be found is called a<strong> molecular orbital (<em>\u03a8<\/em><sup>2<\/sup>)<\/strong>. Like an atomic orbital, a molecular orbital is full when it contains two electrons with opposite spin.\r\n\r\nWe will consider the molecular orbitals in molecules composed of two identical atoms (H<sub>2<\/sub> or Cl<sub>2<\/sub>, for example). Such molecules are called <strong>homonuclear diatomic molecules<\/strong>. In these diatomic molecules, several types of molecular orbitals occur.\r\n\r\nThe mathematical process of combining atomic orbitals to generate molecular orbitals is called the <strong>linear combination of atomic orbitals (LCAO)<\/strong>. The wave function describes the wavelike properties of an electron. Molecular orbitals are combinations of atomic orbital wave functions. Combining waves can lead to constructive interference, in which peaks line up with peaks, or destructive interference, in which peaks line up with troughs (Figure 3). In orbitals, the waves are three dimensional, and they combine with in-phase waves producing regions with a higher probability of electron density and out-of-phase waves producing nodes, or regions of no electron density.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"882\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211931\/CNX_Chem_08_04_waveadd1.jpg\" alt=\"A pair of diagrams are shown and labeled, \u201ca\u201d and \u201cb.\u201d Diagram a shows two identical waves with two crests and two troughs. They are drawn one above the other with a plus sign in between and an equal sign to the right. To the right of the equal sign is a much taller wave with a same number of troughs and crests. Diagram b shows two waves with two crests and two troughs, but they are mirror images of one another rotated over a horizontal axis. They are drawn one above the other with a plus sign in between and an equal sign to the right. To the right of the equal sign is a flat line.\" width=\"882\" height=\"186\" \/> Figure 3. (a) When in-phase waves combine, constructive interference produces a wave with greater amplitude. (b) When out-of-phase waves combine, destructive interference produces a wave with less (or no) amplitude.[\/caption]\r\n\r\nThere are two types of molecular orbitals that can form from the overlap of two atomic <em>s<\/em> orbitals on adjacent atoms. The two types are illustrated in Figure 4. The in-phase combination produces a lower energy <strong>\u03c3<sub><em>s<\/em><\/sub> molecular orbital<\/strong> (read as \"sigma-s\") in which most of the electron density is directly between the nuclei. The out-of-phase addition (which can also be thought of as subtracting the wave functions) produces a higher energy [latex]{\\sigma}_{s}^\\ast[\/latex] <strong>molecular orbital<\/strong> (read as \"sigma-s-star\") molecular orbital in which there is a node between the nuclei. The asterisk signifies that the orbital is an antibonding orbital. Electrons in a \u03c3<em><sub>s<\/sub><\/em> orbital are attracted by both nuclei at the same time and are more stable (of lower energy) than they would be in the isolated atoms. Adding electrons to these orbitals creates a force that holds the two nuclei together, so we call these orbitals <strong>bonding orbitals<\/strong>. Electrons in the [latex]{\\sigma}_{s}^\\ast[\/latex] orbitals are located well away from the region between the two nuclei. The attractive force between the nuclei and these electrons pulls the two nuclei apart. Hence, these orbitals are called<strong> antibonding orbitals<\/strong>. Electrons fill the lower-energy bonding orbital before the higher-energy antibonding orbital, just as they fill lower-energy atomic orbitals before they fill higher-energy atomic orbitals.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"879\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211933\/CNX_Chem_08_04_ssigma1.jpg\" alt=\"A diagram is shown that depicts a vertical upward-facing arrow that lies to the left of all the other portions of the diagram and is labeled, \u201cE.\u201d To the immediate right of the midpoint of the arrow are two circles each labeled with a positive sign, the letter S, and the phrase, \u201cAtomic orbitals.\u201d These are followed by a right-facing horizontal arrow that points to the same two circles labeled with plus signs, but they are now touching and are labeled, \u201cCombine atomic orbitals.\u201d Two right-facing arrows lead to the last portion of the diagram, one facing upward and one facing downward. The upper arrow is labeled, \u201cSubtract,\u201d and points to two oblong ovals labeled with plus signs, and the phrase, \u201cAntibonding orbitals sigma subscript s superscript asterisk.\u201d The lower arrow is labeled, \u201cAdd,\u201d and points to an elongated oval with two plus signs that is labeled, \u201cBonding orbital sigma subscript s.\u201d The heading over the last section of the diagram are the words, \u201cMolecular orbitals.\u201d\" width=\"879\" height=\"358\" \/> Figure 4. Sigma (\u03c3) and sigma-star (\u03c3*) molecular orbitals are formed by the combination of two s atomic orbitals. The dots (\u2022)\u00a0indicate the locations of nuclei.[\/caption]\r\n\r\nYou can watch animations visualizing the calculated atomic orbitals combining to form various molecular orbitals at the <a href=\"https:\/\/winter.group.shef.ac.uk\/orbitron\/MOs\/N2\/2s2s-sigma\/index.html\" target=\"_blank\" rel=\"noopener noreferrer\">University of Sheffield's Orbitron website<\/a>.\r\n\r\nIn <em>p<\/em> orbitals, the wave function gives rise to two lobes with opposite phases, analogous to how a two-dimensional wave has both parts above and below the average. We indicate the phases by shading the orbital lobes different colors. When orbital lobes of the same phase overlap, constructive wave interference increases the electron density. When regions of opposite phase overlap, the destructive wave interference decreases electron density and creates nodes. When <em>p<\/em> orbitals overlap end to end, they create \u03c3 and \u03c3* orbitals (Figure 5). If two atoms are located along the <em>x<\/em>-axis in a Cartesian coordinate system, the two <em>p<sub>x<\/sub><\/em> orbitals overlap end to end and form \u03c3<em><sub>px<\/sub><\/em> (bonding) and [latex]{\\sigma}_{px}^\\ast[\/latex] (antibonding) (read as \"sigma-p-x\" and \"sigma-p-x star,\" respectively). Just as with <em>s<\/em>-orbital overlap, the asterisk indicates the orbital with a node between the nuclei, which is a higher-energy, antibonding orbital.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"881\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211934\/CNX_Chem_08_04_pMOsigma1.jpg\" alt=\"Two horizontal rows of diagrams are shown. The upper diagram shows two equally-sized peanut-shaped orbitals with a plus sign in between them connected to a merged orbital diagram by a right facing arrow. The merged diagram has a much larger oval at the center and much smaller ovular orbitals on the edge. It is labeled, \u201csigma subscript p x.\u201d The lower diagram shows two equally-sized peanut-shaped orbitals with a plus sign in between them connected to a split orbital diagram by a right facing arrow. The split diagram has a much larger oval at the outer ends and much smaller ovular orbitals on the inner edges. It is labeled, \u201csigma subscript p x superscript asterisk\u201d.\" width=\"881\" height=\"235\" \/> Figure 5. Combining wave functions of two p atomic orbitals along the internuclear axis creates two molecular orbitals, \u03c3<sub>p<\/sub> and \u03c3<sup>\u2217<\/sup><sub>p<\/sub>.[\/caption]\r\n\r\nThe side-by-side overlap of two <em>p<\/em> orbitals gives rise to a <strong>pi (\u03c0) bonding molecular orbital <\/strong>and a <strong>\u03c0* antibonding molecular orbital<\/strong>, as shown in Figure 6. In valence bond theory, we describe \u03c0 bonds as containing a nodal plane containing the internuclear axis and perpendicular to the lobes of the p\u2013 \u03c0 orbitals, with electron density on either side of the node. In molecular orbital theory, we describe the \u03c0 orbital by this same shape, and a \u03c0 bond exists when this orbital contains electrons. Electrons in this orbital interact with both nuclei and help hold the two atoms together, making it a bonding orbital. For the out-of-phase combination, there are two nodal planes created, one along the internuclear axis and a perpendicular one between the nuclei.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"650\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211935\/CNX_Chem_08_04_pMOpi1.jpg\" alt=\"Two horizontal rows of diagrams are shown. The upper and lower diagrams both begin with two vertical peanut-shaped orbitals with a plus sign in between followed by a right-facing arrow. The upper diagram shows the same vertical peanut orbitals bending slightly away from one another and separated by a dotted line. It is labeled, \u201cpi subscript p superscript asterisk.\u201d The lower diagram shows the horizontal overlap of the two orbitals and is labeled, \u201cpi subscript p.\u201d\" width=\"650\" height=\"511\" \/> Figure 6. Side-by-side overlap of each two p orbitals results in the formation of two \u03c0 molecular orbitals. Combining the out-of-phase orbitals results in an antibonding molecular orbital with two nodes. One contains the axis, and one contains the perpendicular. Combining the in-phase orbitals results in a bonding orbital. There is a node (blue line) directly along the internuclear axis, but the orbital is located between the nuclei (dots) above and below this node.[\/caption]\r\n\r\nIn the molecular orbitals of diatomic molecules, each atom also has two sets of <em>p<\/em> orbitals oriented side by side (<em>p<sub>y<\/sub><\/em> and <em>p<sub>z<\/sub><\/em>), so these four atomic orbitals combine pairwise to create two \u03c0 orbitals and two \u03c0* orbitals. The \u03c0<em><sub>py<\/sub><\/em> and [latex]{\\pi}_{py}^\\ast[\/latex] orbitals are oriented at right angles to the \u03c0<em><sub>pz<\/sub><\/em> and [latex]{\\pi}_{pz}^\\ast[\/latex] orbitals. Except for their orientation, the \u03c0<em><sub>py<\/sub><\/em> and \u03c0<em><sub>pz<\/sub><\/em> orbitals are identical and have the same energy; they are <strong>degenerate orbitals<\/strong>. The [latex]{\\pi}_{py}^\\ast[\/latex] and [latex]{\\pi}_{pz}^\\ast[\/latex] antibonding orbitals are also degenerate and identical except for their orientation. A total of six molecular orbitals results from the combination of the six atomic <em>p<\/em> orbitals in two atoms: \u03c3<em><sub>px<\/sub><\/em> and [latex]{\\sigma}_{px}^\\ast[\/latex], \u03c0<em><sub>py<\/sub><\/em> and [latex]{\\pi}_{py}^\\ast,[\/latex] \u03c0<em><sub>pz<\/sub><\/em> and [latex]{\\pi}_{pz}^\\ast[\/latex].\r\n<div class=\"textbox examples\">\r\n<h3>Example 1:\u00a0Molecular Orbitals<\/h3>\r\nPredict what type (if any) of molecular orbital would result from adding the wave functions so each pair of orbitals shown overlap. The orbitals are all similar in energy.\r\n\r\n<img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211937\/CNX_Chem_08_04_AOtype_img1.jpg\" alt=\"Three diagrams are shown and labeled \u201ca,\u201d \u201cb,\u201d and \u201cc.\u201d Diagram a shows two horizontal peanut-shaped orbitals laying side-by-side. They are labeled, \u201c3 p subscript x and 3 p subscript x.\u201d Diagram b shows one vertical and one horizontal peanut-shaped orbital which are at right angles to one another. They are labeled, \u201c3 p subscript x and 3 p subscript y.\u201d Diagram c shows two vertical peanut-shaped orbitals laying side-by-side and labeled, \u201c3 p subscript y and 3 p subscript y.\u201d\" width=\"799\" height=\"247\" \/>\r\n[reveal-answer q=\"150712\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"150712\"]\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>is an in-phase combination, resulting in a \u03c3<sub>3<em>p<\/em><\/sub> orbital<\/li>\r\n \t<li>will not result in a new orbital, because the in-phase component (bottom) and out-of-phase component (top) cancel out. Only orbitals with the correct alignment can combine.<\/li>\r\n \t<li>is an out-of-phase combination, resulting in a [latex]{\\pi}_{3p}^\\ast[\/latex] orbital.<\/li>\r\n<\/ol>\r\n[\/hidden-answer]\r\n<h4><strong>Check Your Learning<\/strong><\/h4>\r\nLabel the molecular orbital shown as <em>s<\/em> or \u03c0, bonding or antibonding. Indicate where the nuclei and nodes occur.\r\n\r\n<img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211938\/CNX_Chem_08_04_siganti_img1.jpg\" alt=\"Two orbitals are shown lying end-to-end. Each has one enlarged and one small side. The small sides are facing one another\" \/>\r\n[reveal-answer q=\"606234\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"606234\"]\r\nNuclei are shown by plus signs. The orbital is along the internuclear axis, so it is a \u03c3 orbital. There is a node bisecting the internuclear axis, so it is an antibonding orbital.\r\n\r\n<img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211940\/CNX_Chem_08_04_salabel_img1.jpg\" alt=\"Two orbitals are shown lying end-to-end. Each has one enlarged and one small side. The small sides are facing one another and are separated by a vertical dotted line.\" \/>\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>Portrait of a Chemist: Walter Kohn: Nobel Laureate<\/h3>\r\n[caption id=\"\" align=\"alignright\" width=\"200\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211941\/CNX_Chem_08_04_Kohn1.jpg\" alt=\"A photograph of Walter Kohn is shown.\" width=\"200\" height=\"233\" \/> Figure 7. Walter Kohn developed methods to describe molecular orbitals. (credit: image courtesy of Walter Kohn)[\/caption]\r\n\r\nWalter Kohn (Figure 7) is a theoretical physicist who studies the electronic structure of solids. His work combines the principles of quantum mechanics with advanced mathematical techniques. This technique, called density functional theory, makes it possible to compute properties of molecular orbitals, including their shape and energies.\r\n\r\nKohn and mathematician John Pople were awarded the Nobel Prize in Chemistry in 1998 for their contributions to our understanding of electronic structure. Kohn also made significant contributions to the physics of semiconductors.Kohn\u2019s biography has been remarkable outside the realm of physical chemistry as well. He was born in Austria, and during World War II he was part of the Kindertransport program that rescued 10,000 children from the Nazi regime. His summer jobs included discovering gold deposits in Canada and helping Polaroid explain how its instant film worked. Although he is now an emeritus professor, he is still actively working on projects involving global warming and renewable energy.\r\n\r\n<\/div>\r\n<div class=\"textbox shaded\">\r\n<h3>How Sciences Interconnect: Computational Chemistry in Drug Design<\/h3>\r\nWhile the descriptions of bonding described in this chapter involve many theoretical concepts, they also have many practical, real-world applications. For example, drug design is an important field that uses our understanding of chemical bonding to develop pharmaceuticals. This interdisciplinary area of study uses biology (understanding diseases and how they operate) to identify specific targets, such as a binding site that is involved in a disease pathway. By modeling the structures of the binding site and potential drugs, computational chemists can predict which structures can fit together and how effectively they will bind (see Figure 8). Thousands of potential candidates can be narrowed down to a few of the most promising candidates. These candidate molecules are then carefully tested to determine side effects, how effectively they can be transported through the body, and other factors. Dozens of important new pharmaceuticals have been discovered with the aid of computational chemistry, and new research projects are underway.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"650\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211943\/CNX_Chem_08_04_HIVProteas1.jpg\" alt=\"A diagram of a molecule is shown. The image shows a tangle of ribbon-like, intertwined, pink and green curling lines with a complex ball and stick model in the center.\" width=\"650\" height=\"353\" \/> Figure 8. The molecule shown, HIV-1 protease, is an important target for pharmaceutical research. By designing molecules that bind to this protein, scientists are able to drastically inhibit the progress of the disease.[\/caption]\r\n\r\n<\/div>\r\n<h2>Molecular Orbital Energy Diagrams<\/h2>\r\nThe relative energy levels of atomic and molecular orbitals are typically shown in a <strong>molecular orbital diagram <\/strong>(Figure 9). For a diatomic molecule, the atomic orbitals of one atom are shown on the left, and those of the other atom are shown on the right. Each horizontal line represents one orbital that can hold two electrons. The molecular orbitals formed by the combination of the atomic orbitals are shown in the center. Dashed lines show which of the atomic orbitals combine to form the molecular orbitals. For each pair of atomic orbitals that combine, one lower-energy (bonding) molecular orbital and one higher-energy (antibonding) orbital result. Thus we can see that combining the six 2<em>p<\/em> atomic orbitals results in three bonding orbitals (one \u03c3 and two \u03c0) and three antibonding orbitals (one \u03c3* and two \u03c0*).We predict the distribution of electrons in these molecular orbitals by filling the orbitals in the same way that we fill atomic orbitals, by the Aufbau principle. Lower-energy orbitals fill first, electrons spread out among degenerate orbitals before pairing, and each orbital can hold a maximum of two electrons with opposite spins (Figure 9). Just as we write electron configurations for atoms, we can write the molecular electronic configuration by listing the orbitals with superscripts indicating the number of electrons present. For clarity, we place parentheses around molecular orbitals with the same energy. In this case, each orbital is at a different energy, so parentheses separate each orbital. Thus we would expect a diatomic molecule or ion containing seven electrons (such as [latex]{\\text{Be}}_{2}^{+}[\/latex] ) would have the molecular electron configuration [latex]{\\left({\\sigma}_{1s}\\right)}^{2}{\\left({\\sigma}_{1s}^\\ast\\right)}^{2}{\\left({\\sigma}_{2s}\\right)}^{2}{\\left({\\sigma}_{2s}^\\ast\\right)}^{1}.[\/latex] It is common to omit the core electrons from molecular orbital diagrams and configurations and include only the valence electrons.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"800\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211945\/CNX_Chem_08_04_FillMo1.jpg\" alt=\"A diagram is shown that has an upward-facing vertical arrow running along the left side labeled, \u201cE.\u201d At the bottom center of the diagram is a horizontal line labeled, \u201csigma subscript 2 s,\u201d that has two vertical half arrows drawn on it, one facing up and one facing down. This line is connected to the right and left by upward-facing, dotted lines to two more horizontal lines, each labeled, \u201c2 s.\u201d The line on the left has two vertical half arrows drawn on it, one facing up and one facing down while the line of the right has one half arrow facing up drawn on it. These two lines are connected by upward-facing dotted lines to another line in the center of the diagram, but further up from the first. It is labeled, \u201csigma subscript 2 s superscript asterisk.\u201d This horizontal line has one upward-facing vertical half-arrow drawn on it. Moving farther up the center of the diagram is a long horizontal line labeled, \u201csigma subscript 2 p subscript x,\u201d which lies below two horizontal lines. These two horizontal lines lie side-by-side, and labeled, \u201cpi subscript 2 p subscript y,\u201d and, \u201cpi subscript 2 p subscript z.\u201d Both the bottom and top lines are connected to the right and left by upward-facing, dotted lines to three more horizontal lines, each labeled, \u201c2 p.\u201d These sets of lines are connected by upward-facing dotted lines to another single line and then pair of double lines in the center of the diagram, but farther up from the lower lines. They are labeled, \u201csigma subscript 2 p subscript x superscript asterisk,\u201d and, \u201c\u201cpi subscript 2 p subscript y superscript asterisk,\u201d and, \u201cpi subscript 2 p subscript z superscript asterisk,\u201d respectively. The left and right sides of the diagram have headers that read, \u201dAtomic orbitals,\u201d while the center is header reads \u201cMolecular orbitals\u201d.\" width=\"800\" height=\"524\" \/> Figure 9. This is the molecular orbital diagram for the homonuclear diatomic Be<sub>2<\/sub><sup>+<\/sup>, showing the molecular orbitals of the valence shell only. The molecular orbitals are filled in the same manner as atomic orbitals, using the Aufbau principle and Hund\u2019s rule.[\/caption]\r\n<h2>Bond Order<\/h2>\r\nThe filled molecular orbital diagram shows the number of electrons in both bonding and antibonding molecular orbitals. The net contribution of the electrons to the bond strength of a molecule is identified by determining the <strong>bond order<\/strong> that results from the filling of the molecular orbitals by electrons.\r\n\r\nWhen using Lewis structures to describe the distribution of electrons in molecules, we define bond order as the number of bonding pairs of electrons between two atoms. Thus a single bond has a bond order of 1, a double bond has a bond order of 2, and a triple bond has a bond order of 3. We define bond order differently when we use the molecular orbital description of the distribution of electrons, but the resulting bond order is usually the same. The MO technique is more accurate and can handle cases when the Lewis structure method fails, but both methods describe the same phenomenon.\r\n\r\nIn the molecular orbital model, an electron contributes to a bonding interaction if it occupies a bonding orbital and it contributes to an antibonding interaction if it occupies an antibonding orbital. The bond order is calculated by subtracting the destabilizing (antibonding) electrons from the stabilizing (bonding) electrons. Since a bond consists of two electrons, we divide by two to get the bond order. We can determine bond order with the following equation:\r\n<p style=\"text-align: center\">[latex]\\text{bond order}=\\frac{\\left(\\text{number of bonding electrons}\\right)-\\left(\\text{number of antibonding electrons}\\right)}{2f}[\/latex]<\/p>\r\nThe order of a covalent bond is a guide to its strength; a bond between two given atoms becomes stronger as the bond order increases (Table 1). If the distribution of electrons in the molecular orbitals between two atoms is such that the resulting bond would have a bond order of zero, a stable bond does not form. We next look at some specific examples of MO diagrams and bond orders.\r\n<h2>Bonding in Diatomic Molecules<\/h2>\r\nA dihydrogen molecule (H<sub>2<\/sub>) forms from two hydrogen atoms. When the atomic orbitals of the two atoms combine, the electrons occupy the molecular orbital of lowest energy, the \u03c3<sub>1<em>s<\/em><\/sub> bonding orbital. A dihydrogen molecule, H<sub>2<\/sub>, readily forms, because the energy of a H<sub>2<\/sub> molecule is lower than that of two H atoms. The \u03c3<sub>1<em>s<\/em><\/sub> orbital that contains both electrons is lower in energy than either of the two 1<em>s<\/em> atomic orbitals.\r\n\r\nA molecular orbital can hold two electrons, so both electrons in the H<sub>2<\/sub> molecule are in the \u03c3<sub>1<em>s<\/em><\/sub> bonding orbital; the electron configuration is [latex]{\\left({\\sigma}_{1s}\\right)}^{2}.[\/latex] We represent this configuration by a molecular orbital energy diagram (Figure 10) in which a single upward arrow indicates one electron in an orbital, and two (upward and downward) arrows indicate two electrons of opposite spin.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"879\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211946\/CNX_Chem_08_04_H2MO1.jpg\" alt=\"A diagram is shown that has an upward-facing vertical arrow running along the left side labeled \u201cE.\u201d At the bottom center of the diagram is a horizontal line labeled, \u201csigma subscript 1 s,\u201d that has two vertical half arrows drawn on it, one facing up and one facing down. This line is connected to the right and left by upward-facing, dotted lines to two more horizontal lines, each labeled, \u201c1 s,\u201d and each with one vertical half-arrow facing up drawn on it. These two lines are connected by upward-facing dotted lines to another line in the center of the diagram, but farther up from the first, and labeled, \u201csigma subscript 1 s superscript asterisk.\u201d The left and right sides of the diagram have headers that read, \u201dAtomic orbitals,\u201d while the center header reads, \u201cMolecular orbitals.\u201d The bottom left and right are labeled \u201cH\u201d while the center is labeled \u201cH subscript 2.\u201d\" width=\"879\" height=\"253\" \/> Figure 10. The molecular orbital energy diagram predicts that H<sub>2<\/sub> will be a stable molecule with lower energy than the separated atoms.[\/caption]\r\n\r\nA dihydrogen molecule contains two bonding electrons and no antibonding electrons so we have\r\n<p style=\"text-align: center\">[latex]{\\text{bond order in H}}_{2}=\\frac{\\left(2-0\\right)}{2}=1[\/latex]<\/p>\r\nBecause the bond order for the H\u2013H bond is equal to 1, the bond is a single bond.\r\n\r\nA helium atom has two electrons, both of which are in its 1<em>s<\/em> orbital. Two helium atoms do not combine to form a dihelium molecule, He<sub>2<\/sub>, with four electrons, because the stabilizing effect of the two electrons in the lower-energy bonding orbital would be offset by the destabilizing effect of the two electrons in the higher-energy antibonding molecular orbital. We would write the hypothetical electron configuration of He<sub>2<\/sub> as [latex]{\\left({\\sigma}_{1s}\\right)}^{2}{\\left({\\sigma}_{1s}^\\ast\\right)}^{2}[\/latex] as in Figure 11.\u00a0The net energy change would be zero, so there is no driving force for helium atoms to form the diatomic molecule. In fact, helium exists as discrete atoms rather than as diatomic molecules. The bond order in a hypothetical dihelium molecule would be zero.\r\n<p style=\"text-align: center\">[latex]{\\text{bond order in He}}_{2}=\\frac{\\left(2-2\\right)}{2}=0[\/latex]<\/p>\r\nA bond order of zero indicates that no bond is formed between two atoms.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"879\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211948\/CNX_Chem_08_04_He2MO1.jpg\" alt=\"A diagram is shown that has an upward-facing vertical arrow running along the left side labeled, \u201cE.\u201d At the bottom center of the diagram is a horizontal line labeled, \u201csigma subscript 1 s,\u201d that has two vertical half arrows drawn on it, one facing up and one facing down. This line is connected to the right and left by upward-facing, dotted lines to two more horizontal lines, each labeled, \u201c1 s,\u201d and each with one vertical half-arrow facing up and one facing down drawn on it. These two lines are connected by upward-facing dotted lines to another line in the center of the diagram, but farther up from the first, and labeled, \u201csigma subscript 1 s superscript asterisk.\u201d This line has one upward-facing and one downward-facing vertical arrow drawn on it. The left and right sides of the diagram have headers that read, \u201cAtomic orbitals,\u201d while the center header reads, \u201cMolecular orbitals.\u201d The bottom left and right are labeled, \u201cH e,\u201d while the center is labeled, \u201cH e subscript 2.\u201d\" width=\"879\" height=\"297\" \/> Figure 11. The molecular orbital energy diagram predicts that He<sub>2<\/sub> will not be a stable molecule, since it has equal numbers of bonding and antibonding electrons.[\/caption]\r\n<h3><\/h3>\r\n<div class=\"textbox key-takeaways\">\r\n<h3>Key Concepts and Summary<\/h3>\r\nMolecular orbital (MO) theory describes the behavior of electrons in a molecule in terms of combinations of the atomic wave functions. The resulting molecular orbitals may extend over all the atoms in the molecule. Bonding molecular orbitals are formed by in-phase combinations of atomic wave functions, and electrons in these orbitals stabilize a molecule. Antibonding molecular orbitals result from out-of-phase combinations of atomic wave functions and electrons in these orbitals make a molecule less stable. Molecular orbitals located along an internuclear axis are called \u03c3 MOs. They can be formed from <em>s<\/em> orbitals or from <em>p<\/em> orbitals oriented in an end-to-end fashion. Molecular orbitals formed from <em>p<\/em> orbitals oriented in a side-by-side fashion have electron density on opposite sides of the internuclear axis and are called \u03c0 orbitals.\r\n\r\nWe can describe the electronic structure of diatomic molecules by applying molecular orbital theory to the valence electrons of the atoms. Electrons fill molecular orbitals following the same rules that apply to filling atomic orbitals; Hund\u2019s rule and the Aufbau principle tell us that lower-energy orbitals will fill first, electrons will spread out before they pair up, and each orbital can hold a maximum of two electrons with opposite spins. Materials with unpaired electrons are paramagnetic and attracted to a magnetic field, while those with all-paired electrons are diamagnetic and repelled by a magnetic field. Correctly predicting the magnetic properties of molecules is in advantage of molecular orbital theory over Lewis structures and valence bond theory.\r\n<h4>Key Equations<\/h4>\r\n<ul>\r\n \t<li>[latex]\\text{bond order}=\\frac{\\left(\\text{number of bonding electron}\\right)-\\left(\\text{number of antibonding electrons}\\right)}{2}[\/latex]<\/li>\r\n<\/ul>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<h3>Exercises<\/h3>\r\n<ol>\r\n \t<li>Sketch the distribution of electron density in the bonding and antibonding molecular orbitals formed from two <em>s<\/em> orbitals and from two <em>p<\/em> orbitals.<\/li>\r\n \t<li>How are the following similar, and how do they differ?\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>\u03c3 molecular orbitals and \u03c0 molecular orbitals<\/li>\r\n \t<li>\u03c8 for an atomic orbital and \u03c8 for a molecular orbital<\/li>\r\n \t<li>bonding orbitals and antibonding orbitals<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>If molecular orbitals are created by combining five atomic orbitals from atom A and five atomic orbitals from atom B combine, how many molecular orbitals will result?<\/li>\r\n \t<li>Can a molecule with an odd number of electrons ever be diamagnetic? Explain why or why not.<\/li>\r\n \t<li>Can a molecule with an even number of electrons ever be paramagnetic? Explain why or why not.<\/li>\r\n \t<li>Why are bonding molecular orbitals lower in energy than the parent atomic orbitals?<\/li>\r\n \t<li>Calculate the bond order for an ion with this configuration: [latex]{\\left({\\sigma}_{2s}\\right)}^{2}{\\left({\\sigma}_{2s}^\\ast\\right)}^{2}{\\left({\\sigma}_{2px}\\right)}^{2}{\\left({\\pi}_{2py},{\\pi}_{2pz}\\right)}^{4}{\\left({\\pi}_{2py}^\\ast,{\\pi}_{2pz}^\\ast\\right)}^{3}[\/latex]<\/li>\r\n \t<li>Explain why an electron in the bonding molecular orbital in the H<sub>2<\/sub> molecule has a lower energy than an electron in the 1<em>s<\/em> atomic orbital of either of the separated hydrogen atoms.<\/li>\r\n \t<li>Predict the valence electron molecular orbital configurations for the following, and state whether they will be stable or unstable ions.\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>[latex]{\\text{Na}}_{2}^{\\text{2+}}[\/latex]<\/li>\r\n \t<li>[latex]{\\text{Mg}}_{2}^{\\text{2+}}[\/latex]<\/li>\r\n \t<li>[latex]{\\text{Al}}_{2}^{\\text{2+}}[\/latex]<\/li>\r\n \t<li>[latex]{\\text{Si}}_{2}^{\\text{2+}}[\/latex]<\/li>\r\n \t<li>[latex]{\\text{P}}_{2}^{\\text{2+}}[\/latex]<\/li>\r\n \t<li>[latex]{\\text{S}}_{2}^{\\text{2+}}[\/latex]<\/li>\r\n \t<li>[latex]{\\text{F}}_{2}^{\\text{2+}}[\/latex]<\/li>\r\n \t<li>[latex]{\\text{Ar}}_{2}^{\\text{2+}}[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Determine the bond order of each member of the following groups, and determine which member of each group is predicted by the molecular orbital model to have the strongest bond.\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>H<sub>2<\/sub>, [latex]{\\text{H}}_{2}^{\\text{+}},[\/latex] [latex]{\\text{H}}_{2}^{-}[\/latex]<\/li>\r\n \t<li>O<sub>2<\/sub>, [latex]{\\text{O}}_{2}^{\\text{2+}},[\/latex] [latex]{\\text{O}}_{2}^{2-}[\/latex]<\/li>\r\n \t<li>Li<sub>2<\/sub>, [latex]{\\text{Be}}_{2}^{\\text{+}},[\/latex] Be<sub>2\u00a0<\/sub><\/li>\r\n \t<li>F<sub>2<\/sub>, [latex]{\\text{F}}_{2}^{\\text{+}},[\/latex] [latex]{\\text{F}}_{2}^{-}[\/latex]<\/li>\r\n \t<li>N<sub>2<\/sub>, [latex]{\\text{N}}_{2}^{\\text{+}},[\/latex] [latex]{\\text{N}}_{2}^{-}[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>For the first ionization energy for an N<sub>2<\/sub> molecule, what molecular orbital is the electron removed from?<\/li>\r\n \t<li>Compare the atomic and molecular orbital diagrams to identify the member of each of the following pairs that has the highest first ionization energy (the most tightly bound electron) in the gas phase:\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>H and H<sub>2\u00a0<\/sub><\/li>\r\n \t<li>N and N<sub>2\u00a0<\/sub><\/li>\r\n \t<li>O and O<sub>2\u00a0<\/sub><\/li>\r\n \t<li>C and C<sub>2\u00a0<\/sub><\/li>\r\n \t<li>B and B<sub>2<\/sub><\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>Which of the period 2 homonuclear diatomic molecules are predicted to be paramagnetic?<\/li>\r\n \t<li>A friend tells you that the 2<em>s<\/em> orbital for fluorine starts off at a much lower energy than the 2<em>s<\/em> orbital for lithium, so the resulting \u03c3<sub>2<em>s<\/em><\/sub> molecular orbital in F<sub>2<\/sub> is more stable than in Li<sub>2<\/sub>. Do you agree?<\/li>\r\n \t<li>True or false: Boron contains 2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>1<\/sup> valence electrons, so only one <em>p<\/em> orbital is needed to form molecular orbitals.<\/li>\r\n \t<li>What charge would be needed on F<sub>2<\/sub> to generate an ion with a bond order of 2?<\/li>\r\n \t<li>Predict whether the MO diagram for S<sub>2<\/sub> would show s-p mixing or not.<\/li>\r\n \t<li>Explain why [latex]{\\text{N}}_{2}^{\\text{2+}}[\/latex] is diamagnetic, while [latex]{\\text{O}}_{2}^{\\text{4+}},[\/latex] which has the same number of valence electrons, is paramagnetic.<\/li>\r\n \t<li>Using the MO diagrams, predict the bond order for the stronger bond in each pair:\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>B<sub>2<\/sub> or [latex]{\\text{B}}_{2}^{+}[\/latex]<\/li>\r\n \t<li>F<sub>2<\/sub> or [latex]{\\text{F}}_{2}^{+}[\/latex]<\/li>\r\n \t<li>O<sub>2<\/sub> or [latex]{\\text{O}}_{2}^{\\text{2+}}[\/latex]<\/li>\r\n \t<li>[latex]{\\text{C}}_{2}^{+}[\/latex] or [latex]{\\text{C}}_{2}^{-}[\/latex]<\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"503798\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"503798\"]\r\n\r\n2. The similarities and differences are as follows:\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>Similarities: Both are bonding orbitals that can contain a maximum of two electrons. Differences: <em>\u03c3<\/em> orbitals are end-to-end combinations of atomic orbitals, whereas <em>\u03c0<\/em> orbitals are formed by side-by-side overlap of orbitals.<\/li>\r\n \t<li>Similarities: Both are quantum-mechanical constructs that represent the probability of finding the electron about the atom or the molecule. Differences: <em>\u03c8<\/em> for an atomic orbital describes the behavior of only one electron at a time based on the atom. For a molecule, <em>\u03c8<\/em> represents either a mathematical combination of atomic orbitals.<\/li>\r\n \t<li>Similarities: Both are orbitals that can contain two electrons. Differences: Bonding orbitals result in holding two or more atoms together. Antibonding orbitals have the effect of destabilizing any bonding that has occurred.<\/li>\r\n<\/ol>\r\n4.\u00a0An odd number of electrons can never be paired, regardless of the arrangement of the molecular orbitals. It will always be paramagnetic.\r\n\r\n6.\u00a0Bonding orbitals have electron density in close proximity to more than one nucleus. The interaction between the bonding positively charged nuclei and negatively charged electrons stabilizes the system.\r\n\r\n8.\u00a0The pairing of the two bonding electrons lowers the energy of the system relative to the energy of the nonbonded electrons.\r\n\r\n10.\u00a0The bond order is equal to half the difference between the number of bonding electrons and the number of antibonding electrons. The bond with the greatest bond order is predicted to be the strongest.\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>H<sub>2<\/sub> bond order = 1, [latex]{\\text{H}}_{2}^{+}[\/latex] bond order = 0.5, [latex]{\\text{H}}_{2}^{-}[\/latex] bond order = 0.5, strongest bond is H<sub>2<\/sub>;<\/li>\r\n \t<li>O<sub>2<\/sub> bond order = 2, [latex]{\\text{O}}_{2}^{\\text{2+}}[\/latex] bond order = 3; [latex]{\\text{O}}_{2}^{2-}[\/latex] bond order = 1, strongest bond is [latex]{\\text{O}}_{2}^{\\text{2+}};[\/latex]<\/li>\r\n \t<li>Li<sub>2<\/sub> bond order = 1, [latex]{\\text{Be}}_{2}^{+}[\/latex] bond order = 0.5, Be<sub>2<\/sub> bond order = 0, Li<sub>2<\/sub> [latex]{\\text{Be}}_{2}^{+}[\/latex] have the same strength bond;<\/li>\r\n \t<li>F<sub>2<\/sub> bond order = 1, [latex]{\\text{F}}_{2}^{+}[\/latex] bond order = 1.5, [latex]{\\text{F}}_{2}^{-}[\/latex] bond order = 0.5, strongest bond is [latex]{\\text{F}}_{2}^{\\text{+}};[\/latex]<\/li>\r\n \t<li>N<sub>2<\/sub> bond order = 3, [latex]{\\text{N}}_{2}^{+}[\/latex] bond order = 2.5, [latex]{\\text{N}}_{2}^{-}[\/latex] bond order = 2.5, strongest bond is N<sub>2<\/sub>.<\/li>\r\n<\/ol>\r\n12. The substance with the\u00a0highest first ionization energy in each pair is as follows:\r\n<ol style=\"list-style-type: lower-alpha\">\r\n \t<li>H<sub>2<\/sub><\/li>\r\n \t<li>N<sub>2<\/sub><\/li>\r\n \t<li>O<\/li>\r\n \t<li>C<sub>2<\/sub><\/li>\r\n \t<li>B<sub>2<\/sub><\/li>\r\n<\/ol>\r\n14.\u00a0Yes, fluorine is a smaller atom than Li, so atoms in the 2<em>s<\/em> orbital are closer to the nucleus and more stable.\r\n\r\n16.\u00a02+\r\n\r\n18.\u00a0N<sub>2<\/sub> has s-p mixing, so the \u03c0 orbitals are the last filled in [latex]{\\text{N}}_{2}^{\\text{2+}}.[\/latex] O<sub>2<\/sub> does not have s-p mixing, so the \u03c3<em><sub>p<\/sub><\/em> orbital fills before the \u03c0 orbitals.\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n<h2>Glossary<\/h2>\r\n<strong>antibonding orbital:<\/strong> molecular orbital located outside of the region between two nuclei; electrons in an antibonding orbital destabilize the molecule\r\n\r\n<strong>bond order:<\/strong> number of pairs of electrons between two atoms; it can be found by the number of bonds in a Lewis structure or by the difference between the number of bonding and antibonding electrons divided by two\r\n\r\n<strong>bonding orbital:<\/strong> molecular orbital located between two nuclei; electrons in a bonding orbital stabilize a molecule\r\n\r\n<strong>degenerate orbitals:<\/strong> orbitals that have the same energy\r\n\r\n<strong>diamagnetism<strong>:<\/strong><\/strong> phenomenon in which a material is not magnetic itself but is repelled by a magnetic field; it occurs when there are only paired electrons present\r\n\r\n<strong>homonuclear diatomic molecule<strong>:<\/strong><\/strong> molecule consisting of two identical atoms\r\n\r\n<strong>linear combination of atomic orbitals<strong>:<\/strong><\/strong> technique for combining atomic orbitals to create molecular orbitals\r\n\r\n<strong>molecular orbital<strong>:<\/strong><\/strong> region of space in which an electron has a high probability of being found in a molecule\r\n\r\n<strong>molecular orbital diagram<strong>:<\/strong><\/strong> visual representation of the relative energy levels of molecular orbitals\r\n\r\n<strong>molecular orbital theory<strong>:<\/strong><\/strong> model that describes the behavior of electrons delocalized throughout a molecule in terms of the combination of atomic wave functions\r\n\r\n<strong>paramagnetism<strong>:<\/strong><\/strong> phenomenon in which a material is not magnetic itself but is attracted to a magnetic field; it occurs when there are unpaired electrons present\r\n\r\n<strong>\u03c0 bonding orbital<strong>:<\/strong><\/strong> molecular orbital formed by side-by-side overlap of atomic orbitals, in which the electron density is found on opposite sides of the internuclear axis\r\n\r\n<strong>\u03c0* bonding orbital<strong>:<\/strong><\/strong> antibonding molecular orbital formed by out of phase side-by-side overlap of atomic orbitals, in which the electron density is found on both sides of the internuclear axis, and there is a node between the nuclei\r\n\r\n<strong>\u03c3 bonding orbital<strong>:<\/strong><\/strong> molecular orbital in which the electron density is found along the axis of the bond\r\n\r\n<strong>\u03c3* bonding orbital<strong>:<\/strong><\/strong> antibonding molecular orbital formed by out-of-phase overlap of atomic orbital along the axis of the bond, generating a node between the nuclei\r\n\r\n<strong>s-p mixing:<\/strong> change that causes \u03c3<em><sub>p<\/sub><\/em> orbitals to be less stable than \u03c0<em><sub>p<\/sub><\/em> orbitals due to the mixing of <em>s<\/em> and <em>p<\/em>-based molecular orbitals of similar energies.","rendered":"<div class=\"textbox learning-objectives\">\n<h3>Learning Objectives<\/h3>\n<p>By the end of this section, you will be able to:<\/p>\n<ul>\n<li>Outline the basic quantum-mechanical approach to deriving molecular orbitals from atomic orbitals<\/li>\n<li>Describe traits of bonding and anti-bonding molecular orbitals<\/li>\n<li>Calculate bond orders based on molecular electron configurations<\/li>\n<li>Write molecular electron configurations for H<sub>2<\/sub> and He<sub>2<\/sub> molecules<\/li>\n<li>Relate these electron configurations to the molecules\u2019 stabilities and magnetic properties<\/li>\n<\/ul>\n<\/div>\n<p>For almost every covalent molecule that exists, we can now draw the Lewis structure, predict the electron-pair geometry, predict the molecular geometry, and come close to predicting bond angles. However, one of the most important molecules we know, the oxygen molecule O<sub>2<\/sub>, presents a problem with respect to its Lewis structure. We would write the following Lewis structure for O<sub>2<\/sub>:<\/p>\n<p><img decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211927\/CNX_Chem_08_04_O2_img1.jpg\" alt=\"A Lewis structure is shown. It is made up of two oxygen atoms, each with two lone pairs of electrons, bonded together with a double bond.\" \/><\/p>\n<p>This electronic structure adheres to all the rules governing Lewis theory. There is an O=O double bond, and each oxygen atom has eight electrons around it. However, this picture is at odds with the magnetic behavior of oxygen. By itself, O<sub>2<\/sub> is not magnetic, but it is attracted to magnetic fields. Thus, when we pour liquid oxygen past a strong magnet, it collects between the poles of the magnet and defies gravity, as in Figure 1. Such attraction to a magnetic field is called <strong>paramagnetism<\/strong>, and it arises in molecules that have unpaired electrons. And yet, the Lewis structure of O<sub>2<\/sub> indicates that all electrons are paired. How do we account for this discrepancy?<\/p>\n<div style=\"width: 760px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211747\/CNX_Chem_08_00_LiqO21.jpg\" alt=\"A pitcher is shown pouring liquid oxygen through the gap between two magnets, where it has formed a solid disk. A call out box near the stream of liquid oxygen shows an image of six pairs of spheres, spread apart from one another. Another call out box near the solid disk shows ten pairs of spheres much closer together.\" width=\"750\" height=\"346\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 1. Oxygen molecules orient randomly most of the time, as shown in the top magnified view. However, when we pour liquid oxygen through a magnet, the molecules line up with the magnetic field, and the attraction allows them to stay suspended between the poles of the magnet where the magnetic field is strongest. Other diatomic molecules (like N<sub>2<\/sub>) flow past the magnet. The detailed explanation of bonding described in this chapter allows us to understand this phenomenon. (credit: modification of work by Jefferson Lab)<\/p>\n<\/div>\n<p>Magnetic susceptibility measures the force experienced by a substance in a magnetic field. When we compare the weight of a sample to the weight measured in a magnetic field (Figure 2), paramagnetic samples that are attracted to the magnet will appear heavier because of the force exerted by the magnetic field. We can calculate the number of unpaired electrons based on the increase in weight.<\/p>\n<div style=\"width: 810px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211928\/CNX_Chem_08_04_Gouy1.jpg\" alt=\"A diagram depicts a stand supporting two objects that are held in balance by a horizontal bar. On the right, the bar supports a dish that is holding two weights. On the left there is a line attached to a test tube labeled, \u201cSample tube.\u201d The test tube has been lowered into the space labeled, \u201cMagnetic field,\u201d between two structures labeled, \u201cElectromagnets.\u201d\" width=\"800\" height=\"601\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 2. A Gouy balance compares the mass of a sample in the presence of a magnetic field with the mass with the electromagnet turned off to determine the number of unpaired electrons in a sample.<\/p>\n<\/div>\n<p>Experiments show that each O<sub>2<\/sub> molecule has two unpaired electrons. The Lewis-structure model does not predict the presence of these two unpaired electrons. Unlike oxygen, the apparent weight of most molecules decreases slightly in the presence of an inhomogeneous magnetic field. Materials in which all of the electrons are paired are <strong>diamagnetic<\/strong> and weakly repel a magnetic field. Paramagnetic and diamagnetic materials do not act as permanent magnets. Only in the presence of an applied magnetic field do they demonstrate attraction or repulsion.<\/p>\n<div class=\"textbox\">Water, like most molecules, contains all paired electrons. Living things contain a large percentage of water, so they demonstrate diamagnetic behavior. If you place a frog near a sufficiently large magnet, it will levitate. You can see videos of diamagnetic floating frogs, strawberries, and more at the <a href=\"http:\/\/www.ru.nl\/hfml\/research\/levitation\/diamagnetic\/\" target=\"_blank\" rel=\"noopener noreferrer\">Radboud University Diamagnetic Levitation website<\/a>.<\/div>\n<p>Molecular orbital theory (MO theory) provides an explanation of chemical bonding that accounts for the paramagnetism of the oxygen molecule. It also explains the bonding in a number of other molecules, such as violations of the octet rule and more molecules with more complicated bonding (beyond the scope of this text) that are difficult to describe with Lewis structures. Additionally, it provides a model for describing the energies of electrons in a molecule and the probable location of these electrons. Unlike valence bond theory, which uses hybrid orbitals that are assigned to one specific atom, MO theory uses the combination of atomic orbitals to yield molecular orbitals that are <em>delocalized<\/em> over the entire molecule rather than being localized on its constituent atoms. MO theory also helps us understand why some substances are electrical conductors, others are semiconductors, and still others are insulators. Table 1 summarizes the main points of the two complementary bonding theories. Both theories provide different, useful ways of describing molecular structure.<\/p>\n<table summary=\"A table is shown that is composed of two columns and six rows. The header row reads, \u201cValence Bond Theory,\u201d and, \u201cMolecular Orbital Theory.\u201d The first column contains the phrases: \u201cconsiders bonds as localized between one pair of atoms,\u201d \u201ccreates bonds from overlap of atomic orbitals ( s, p, d\u2026) and hybrid orbitals ( s p , s p superscript 2, s p superscript 3 \u2026 ) ,\u201d \u201cforms sigma or pi bonds,\u201d \u201cpredicts molecular shape based on the number of regions of electron density,\u201d and, \u201cneeds multiple structures are needed to describe resonance.\u201d The second column reads, \u201cconsiders electrons delocalized throughout the entire molecule,\u201d \u201ccombines atomic orbitals to form molecular orbitals ( sigma, sigma superscript asterik, pi, pi superscript asterisk ),\u201d \u201ccreates bonding and antibonding interactions based on which orbitals are filled,\u201d \u201cpredicts the arrangement of electrons in molecules.\u201d\">\n<thead>\n<tr>\n<th colspan=\"2\">Table 1. Comparison of Bonding Theories<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<th>Valence Bond Theory<\/th>\n<th>Molecular Orbital Theory<\/th>\n<\/tr>\n<tr>\n<td>considers bonds as localized between one pair of atoms<\/td>\n<td>considers electrons delocalized throughout the entire molecule<\/td>\n<\/tr>\n<tr>\n<td>creates bonds from overlap of atomic orbitals (<em>s, p, d<\/em>\u2026) and hybrid orbitals (<em>sp, sp<\/em><sup>2<\/sup>, <em>sp<\/em><sup>3<\/sup>\u2026)<\/td>\n<td>combines atomic orbitals to form molecular orbitals (\u03c3, \u03c3*, \u03c0, \u03c0*)<\/td>\n<\/tr>\n<tr>\n<td>forms \u03c3 or \u03c0 bonds<\/td>\n<td>creates bonding and antibonding interactions based on which orbitals are filled<\/td>\n<\/tr>\n<tr>\n<td>predicts molecular shape based on the number of regions of electron density<\/td>\n<td>predicts the arrangement of electrons in molecules<\/td>\n<\/tr>\n<tr>\n<td>needs multiple structures to describe resonance<\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><strong>Molecular orbital theory <\/strong>describes the distribution of electrons in molecules in much the same way that the distribution of electrons in atoms is described using atomic orbitals. Using quantum mechanics, the behavior of an electron in a molecule is still described by a wave function, <em>\u03a8<\/em>, analogous to the behavior in an atom. Just like electrons around isolated atoms, electrons around atoms in molecules are limited to discrete (quantized) energies. The region of space in which a valence electron in a molecule is likely to be found is called a<strong> molecular orbital (<em>\u03a8<\/em><sup>2<\/sup>)<\/strong>. Like an atomic orbital, a molecular orbital is full when it contains two electrons with opposite spin.<\/p>\n<p>We will consider the molecular orbitals in molecules composed of two identical atoms (H<sub>2<\/sub> or Cl<sub>2<\/sub>, for example). Such molecules are called <strong>homonuclear diatomic molecules<\/strong>. In these diatomic molecules, several types of molecular orbitals occur.<\/p>\n<p>The mathematical process of combining atomic orbitals to generate molecular orbitals is called the <strong>linear combination of atomic orbitals (LCAO)<\/strong>. The wave function describes the wavelike properties of an electron. Molecular orbitals are combinations of atomic orbital wave functions. Combining waves can lead to constructive interference, in which peaks line up with peaks, or destructive interference, in which peaks line up with troughs (Figure 3). In orbitals, the waves are three dimensional, and they combine with in-phase waves producing regions with a higher probability of electron density and out-of-phase waves producing nodes, or regions of no electron density.<\/p>\n<div style=\"width: 892px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211931\/CNX_Chem_08_04_waveadd1.jpg\" alt=\"A pair of diagrams are shown and labeled, \u201ca\u201d and \u201cb.\u201d Diagram a shows two identical waves with two crests and two troughs. They are drawn one above the other with a plus sign in between and an equal sign to the right. To the right of the equal sign is a much taller wave with a same number of troughs and crests. Diagram b shows two waves with two crests and two troughs, but they are mirror images of one another rotated over a horizontal axis. They are drawn one above the other with a plus sign in between and an equal sign to the right. To the right of the equal sign is a flat line.\" width=\"882\" height=\"186\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 3. (a) When in-phase waves combine, constructive interference produces a wave with greater amplitude. (b) When out-of-phase waves combine, destructive interference produces a wave with less (or no) amplitude.<\/p>\n<\/div>\n<p>There are two types of molecular orbitals that can form from the overlap of two atomic <em>s<\/em> orbitals on adjacent atoms. The two types are illustrated in Figure 4. The in-phase combination produces a lower energy <strong>\u03c3<sub><em>s<\/em><\/sub> molecular orbital<\/strong> (read as &#8220;sigma-s&#8221;) in which most of the electron density is directly between the nuclei. The out-of-phase addition (which can also be thought of as subtracting the wave functions) produces a higher energy [latex]{\\sigma}_{s}^\\ast[\/latex] <strong>molecular orbital<\/strong> (read as &#8220;sigma-s-star&#8221;) molecular orbital in which there is a node between the nuclei. The asterisk signifies that the orbital is an antibonding orbital. Electrons in a \u03c3<em><sub>s<\/sub><\/em> orbital are attracted by both nuclei at the same time and are more stable (of lower energy) than they would be in the isolated atoms. Adding electrons to these orbitals creates a force that holds the two nuclei together, so we call these orbitals <strong>bonding orbitals<\/strong>. Electrons in the [latex]{\\sigma}_{s}^\\ast[\/latex] orbitals are located well away from the region between the two nuclei. The attractive force between the nuclei and these electrons pulls the two nuclei apart. Hence, these orbitals are called<strong> antibonding orbitals<\/strong>. Electrons fill the lower-energy bonding orbital before the higher-energy antibonding orbital, just as they fill lower-energy atomic orbitals before they fill higher-energy atomic orbitals.<\/p>\n<div style=\"width: 889px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211933\/CNX_Chem_08_04_ssigma1.jpg\" alt=\"A diagram is shown that depicts a vertical upward-facing arrow that lies to the left of all the other portions of the diagram and is labeled, \u201cE.\u201d To the immediate right of the midpoint of the arrow are two circles each labeled with a positive sign, the letter S, and the phrase, \u201cAtomic orbitals.\u201d These are followed by a right-facing horizontal arrow that points to the same two circles labeled with plus signs, but they are now touching and are labeled, \u201cCombine atomic orbitals.\u201d Two right-facing arrows lead to the last portion of the diagram, one facing upward and one facing downward. The upper arrow is labeled, \u201cSubtract,\u201d and points to two oblong ovals labeled with plus signs, and the phrase, \u201cAntibonding orbitals sigma subscript s superscript asterisk.\u201d The lower arrow is labeled, \u201cAdd,\u201d and points to an elongated oval with two plus signs that is labeled, \u201cBonding orbital sigma subscript s.\u201d The heading over the last section of the diagram are the words, \u201cMolecular orbitals.\u201d\" width=\"879\" height=\"358\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 4. Sigma (\u03c3) and sigma-star (\u03c3*) molecular orbitals are formed by the combination of two s atomic orbitals. The dots (\u2022)\u00a0indicate the locations of nuclei.<\/p>\n<\/div>\n<p>You can watch animations visualizing the calculated atomic orbitals combining to form various molecular orbitals at the <a href=\"https:\/\/winter.group.shef.ac.uk\/orbitron\/MOs\/N2\/2s2s-sigma\/index.html\" target=\"_blank\" rel=\"noopener noreferrer\">University of Sheffield&#8217;s Orbitron website<\/a>.<\/p>\n<p>In <em>p<\/em> orbitals, the wave function gives rise to two lobes with opposite phases, analogous to how a two-dimensional wave has both parts above and below the average. We indicate the phases by shading the orbital lobes different colors. When orbital lobes of the same phase overlap, constructive wave interference increases the electron density. When regions of opposite phase overlap, the destructive wave interference decreases electron density and creates nodes. When <em>p<\/em> orbitals overlap end to end, they create \u03c3 and \u03c3* orbitals (Figure 5). If two atoms are located along the <em>x<\/em>-axis in a Cartesian coordinate system, the two <em>p<sub>x<\/sub><\/em> orbitals overlap end to end and form \u03c3<em><sub>px<\/sub><\/em> (bonding) and [latex]{\\sigma}_{px}^\\ast[\/latex] (antibonding) (read as &#8220;sigma-p-x&#8221; and &#8220;sigma-p-x star,&#8221; respectively). Just as with <em>s<\/em>-orbital overlap, the asterisk indicates the orbital with a node between the nuclei, which is a higher-energy, antibonding orbital.<\/p>\n<div style=\"width: 891px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211934\/CNX_Chem_08_04_pMOsigma1.jpg\" alt=\"Two horizontal rows of diagrams are shown. The upper diagram shows two equally-sized peanut-shaped orbitals with a plus sign in between them connected to a merged orbital diagram by a right facing arrow. The merged diagram has a much larger oval at the center and much smaller ovular orbitals on the edge. It is labeled, \u201csigma subscript p x.\u201d The lower diagram shows two equally-sized peanut-shaped orbitals with a plus sign in between them connected to a split orbital diagram by a right facing arrow. The split diagram has a much larger oval at the outer ends and much smaller ovular orbitals on the inner edges. It is labeled, \u201csigma subscript p x superscript asterisk\u201d.\" width=\"881\" height=\"235\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 5. Combining wave functions of two p atomic orbitals along the internuclear axis creates two molecular orbitals, \u03c3<sub>p<\/sub> and \u03c3<sup>\u2217<\/sup><sub>p<\/sub>.<\/p>\n<\/div>\n<p>The side-by-side overlap of two <em>p<\/em> orbitals gives rise to a <strong>pi (\u03c0) bonding molecular orbital <\/strong>and a <strong>\u03c0* antibonding molecular orbital<\/strong>, as shown in Figure 6. In valence bond theory, we describe \u03c0 bonds as containing a nodal plane containing the internuclear axis and perpendicular to the lobes of the p\u2013 \u03c0 orbitals, with electron density on either side of the node. In molecular orbital theory, we describe the \u03c0 orbital by this same shape, and a \u03c0 bond exists when this orbital contains electrons. Electrons in this orbital interact with both nuclei and help hold the two atoms together, making it a bonding orbital. For the out-of-phase combination, there are two nodal planes created, one along the internuclear axis and a perpendicular one between the nuclei.<\/p>\n<div style=\"width: 660px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211935\/CNX_Chem_08_04_pMOpi1.jpg\" alt=\"Two horizontal rows of diagrams are shown. The upper and lower diagrams both begin with two vertical peanut-shaped orbitals with a plus sign in between followed by a right-facing arrow. The upper diagram shows the same vertical peanut orbitals bending slightly away from one another and separated by a dotted line. It is labeled, \u201cpi subscript p superscript asterisk.\u201d The lower diagram shows the horizontal overlap of the two orbitals and is labeled, \u201cpi subscript p.\u201d\" width=\"650\" height=\"511\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 6. Side-by-side overlap of each two p orbitals results in the formation of two \u03c0 molecular orbitals. Combining the out-of-phase orbitals results in an antibonding molecular orbital with two nodes. One contains the axis, and one contains the perpendicular. Combining the in-phase orbitals results in a bonding orbital. There is a node (blue line) directly along the internuclear axis, but the orbital is located between the nuclei (dots) above and below this node.<\/p>\n<\/div>\n<p>In the molecular orbitals of diatomic molecules, each atom also has two sets of <em>p<\/em> orbitals oriented side by side (<em>p<sub>y<\/sub><\/em> and <em>p<sub>z<\/sub><\/em>), so these four atomic orbitals combine pairwise to create two \u03c0 orbitals and two \u03c0* orbitals. The \u03c0<em><sub>py<\/sub><\/em> and [latex]{\\pi}_{py}^\\ast[\/latex] orbitals are oriented at right angles to the \u03c0<em><sub>pz<\/sub><\/em> and [latex]{\\pi}_{pz}^\\ast[\/latex] orbitals. Except for their orientation, the \u03c0<em><sub>py<\/sub><\/em> and \u03c0<em><sub>pz<\/sub><\/em> orbitals are identical and have the same energy; they are <strong>degenerate orbitals<\/strong>. The [latex]{\\pi}_{py}^\\ast[\/latex] and [latex]{\\pi}_{pz}^\\ast[\/latex] antibonding orbitals are also degenerate and identical except for their orientation. A total of six molecular orbitals results from the combination of the six atomic <em>p<\/em> orbitals in two atoms: \u03c3<em><sub>px<\/sub><\/em> and [latex]{\\sigma}_{px}^\\ast[\/latex], \u03c0<em><sub>py<\/sub><\/em> and [latex]{\\pi}_{py}^\\ast,[\/latex] \u03c0<em><sub>pz<\/sub><\/em> and [latex]{\\pi}_{pz}^\\ast[\/latex].<\/p>\n<div class=\"textbox examples\">\n<h3>Example 1:\u00a0Molecular Orbitals<\/h3>\n<p>Predict what type (if any) of molecular orbital would result from adding the wave functions so each pair of orbitals shown overlap. The orbitals are all similar in energy.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211937\/CNX_Chem_08_04_AOtype_img1.jpg\" alt=\"Three diagrams are shown and labeled \u201ca,\u201d \u201cb,\u201d and \u201cc.\u201d Diagram a shows two horizontal peanut-shaped orbitals laying side-by-side. They are labeled, \u201c3 p subscript x and 3 p subscript x.\u201d Diagram b shows one vertical and one horizontal peanut-shaped orbital which are at right angles to one another. They are labeled, \u201c3 p subscript x and 3 p subscript y.\u201d Diagram c shows two vertical peanut-shaped orbitals laying side-by-side and labeled, \u201c3 p subscript y and 3 p subscript y.\u201d\" width=\"799\" height=\"247\" \/><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q150712\">Show Answer<\/span><\/p>\n<div id=\"q150712\" class=\"hidden-answer\" style=\"display: none\">\n<ol style=\"list-style-type: lower-alpha\">\n<li>is an in-phase combination, resulting in a \u03c3<sub>3<em>p<\/em><\/sub> orbital<\/li>\n<li>will not result in a new orbital, because the in-phase component (bottom) and out-of-phase component (top) cancel out. Only orbitals with the correct alignment can combine.<\/li>\n<li>is an out-of-phase combination, resulting in a [latex]{\\pi}_{3p}^\\ast[\/latex] orbital.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<h4><strong>Check Your Learning<\/strong><\/h4>\n<p>Label the molecular orbital shown as <em>s<\/em> or \u03c0, bonding or antibonding. Indicate where the nuclei and nodes occur.<\/p>\n<p><img decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211938\/CNX_Chem_08_04_siganti_img1.jpg\" alt=\"Two orbitals are shown lying end-to-end. Each has one enlarged and one small side. The small sides are facing one another\" \/><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q606234\">Show Answer<\/span><\/p>\n<div id=\"q606234\" class=\"hidden-answer\" style=\"display: none\">\nNuclei are shown by plus signs. The orbital is along the internuclear axis, so it is a \u03c3 orbital. There is a node bisecting the internuclear axis, so it is an antibonding orbital.<\/p>\n<p><img decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211940\/CNX_Chem_08_04_salabel_img1.jpg\" alt=\"Two orbitals are shown lying end-to-end. Each has one enlarged and one small side. The small sides are facing one another and are separated by a vertical dotted line.\" \/><\/p>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Portrait of a Chemist: Walter Kohn: Nobel Laureate<\/h3>\n<div style=\"width: 210px\" class=\"wp-caption alignright\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211941\/CNX_Chem_08_04_Kohn1.jpg\" alt=\"A photograph of Walter Kohn is shown.\" width=\"200\" height=\"233\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 7. Walter Kohn developed methods to describe molecular orbitals. (credit: image courtesy of Walter Kohn)<\/p>\n<\/div>\n<p>Walter Kohn (Figure 7) is a theoretical physicist who studies the electronic structure of solids. His work combines the principles of quantum mechanics with advanced mathematical techniques. This technique, called density functional theory, makes it possible to compute properties of molecular orbitals, including their shape and energies.<\/p>\n<p>Kohn and mathematician John Pople were awarded the Nobel Prize in Chemistry in 1998 for their contributions to our understanding of electronic structure. Kohn also made significant contributions to the physics of semiconductors.Kohn\u2019s biography has been remarkable outside the realm of physical chemistry as well. He was born in Austria, and during World War II he was part of the Kindertransport program that rescued 10,000 children from the Nazi regime. His summer jobs included discovering gold deposits in Canada and helping Polaroid explain how its instant film worked. Although he is now an emeritus professor, he is still actively working on projects involving global warming and renewable energy.<\/p>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>How Sciences Interconnect: Computational Chemistry in Drug Design<\/h3>\n<p>While the descriptions of bonding described in this chapter involve many theoretical concepts, they also have many practical, real-world applications. For example, drug design is an important field that uses our understanding of chemical bonding to develop pharmaceuticals. This interdisciplinary area of study uses biology (understanding diseases and how they operate) to identify specific targets, such as a binding site that is involved in a disease pathway. By modeling the structures of the binding site and potential drugs, computational chemists can predict which structures can fit together and how effectively they will bind (see Figure 8). Thousands of potential candidates can be narrowed down to a few of the most promising candidates. These candidate molecules are then carefully tested to determine side effects, how effectively they can be transported through the body, and other factors. Dozens of important new pharmaceuticals have been discovered with the aid of computational chemistry, and new research projects are underway.<\/p>\n<div style=\"width: 660px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211943\/CNX_Chem_08_04_HIVProteas1.jpg\" alt=\"A diagram of a molecule is shown. The image shows a tangle of ribbon-like, intertwined, pink and green curling lines with a complex ball and stick model in the center.\" width=\"650\" height=\"353\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 8. The molecule shown, HIV-1 protease, is an important target for pharmaceutical research. By designing molecules that bind to this protein, scientists are able to drastically inhibit the progress of the disease.<\/p>\n<\/div>\n<\/div>\n<h2>Molecular Orbital Energy Diagrams<\/h2>\n<p>The relative energy levels of atomic and molecular orbitals are typically shown in a <strong>molecular orbital diagram <\/strong>(Figure 9). For a diatomic molecule, the atomic orbitals of one atom are shown on the left, and those of the other atom are shown on the right. Each horizontal line represents one orbital that can hold two electrons. The molecular orbitals formed by the combination of the atomic orbitals are shown in the center. Dashed lines show which of the atomic orbitals combine to form the molecular orbitals. For each pair of atomic orbitals that combine, one lower-energy (bonding) molecular orbital and one higher-energy (antibonding) orbital result. Thus we can see that combining the six 2<em>p<\/em> atomic orbitals results in three bonding orbitals (one \u03c3 and two \u03c0) and three antibonding orbitals (one \u03c3* and two \u03c0*).We predict the distribution of electrons in these molecular orbitals by filling the orbitals in the same way that we fill atomic orbitals, by the Aufbau principle. Lower-energy orbitals fill first, electrons spread out among degenerate orbitals before pairing, and each orbital can hold a maximum of two electrons with opposite spins (Figure 9). Just as we write electron configurations for atoms, we can write the molecular electronic configuration by listing the orbitals with superscripts indicating the number of electrons present. For clarity, we place parentheses around molecular orbitals with the same energy. In this case, each orbital is at a different energy, so parentheses separate each orbital. Thus we would expect a diatomic molecule or ion containing seven electrons (such as [latex]{\\text{Be}}_{2}^{+}[\/latex] ) would have the molecular electron configuration [latex]{\\left({\\sigma}_{1s}\\right)}^{2}{\\left({\\sigma}_{1s}^\\ast\\right)}^{2}{\\left({\\sigma}_{2s}\\right)}^{2}{\\left({\\sigma}_{2s}^\\ast\\right)}^{1}.[\/latex] It is common to omit the core electrons from molecular orbital diagrams and configurations and include only the valence electrons.<\/p>\n<div style=\"width: 810px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211945\/CNX_Chem_08_04_FillMo1.jpg\" alt=\"A diagram is shown that has an upward-facing vertical arrow running along the left side labeled, \u201cE.\u201d At the bottom center of the diagram is a horizontal line labeled, \u201csigma subscript 2 s,\u201d that has two vertical half arrows drawn on it, one facing up and one facing down. This line is connected to the right and left by upward-facing, dotted lines to two more horizontal lines, each labeled, \u201c2 s.\u201d The line on the left has two vertical half arrows drawn on it, one facing up and one facing down while the line of the right has one half arrow facing up drawn on it. These two lines are connected by upward-facing dotted lines to another line in the center of the diagram, but further up from the first. It is labeled, \u201csigma subscript 2 s superscript asterisk.\u201d This horizontal line has one upward-facing vertical half-arrow drawn on it. Moving farther up the center of the diagram is a long horizontal line labeled, \u201csigma subscript 2 p subscript x,\u201d which lies below two horizontal lines. These two horizontal lines lie side-by-side, and labeled, \u201cpi subscript 2 p subscript y,\u201d and, \u201cpi subscript 2 p subscript z.\u201d Both the bottom and top lines are connected to the right and left by upward-facing, dotted lines to three more horizontal lines, each labeled, \u201c2 p.\u201d These sets of lines are connected by upward-facing dotted lines to another single line and then pair of double lines in the center of the diagram, but farther up from the lower lines. They are labeled, \u201csigma subscript 2 p subscript x superscript asterisk,\u201d and, \u201c\u201cpi subscript 2 p subscript y superscript asterisk,\u201d and, \u201cpi subscript 2 p subscript z superscript asterisk,\u201d respectively. The left and right sides of the diagram have headers that read, \u201dAtomic orbitals,\u201d while the center is header reads \u201cMolecular orbitals\u201d.\" width=\"800\" height=\"524\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 9. This is the molecular orbital diagram for the homonuclear diatomic Be<sub>2<\/sub><sup>+<\/sup>, showing the molecular orbitals of the valence shell only. The molecular orbitals are filled in the same manner as atomic orbitals, using the Aufbau principle and Hund\u2019s rule.<\/p>\n<\/div>\n<h2>Bond Order<\/h2>\n<p>The filled molecular orbital diagram shows the number of electrons in both bonding and antibonding molecular orbitals. The net contribution of the electrons to the bond strength of a molecule is identified by determining the <strong>bond order<\/strong> that results from the filling of the molecular orbitals by electrons.<\/p>\n<p>When using Lewis structures to describe the distribution of electrons in molecules, we define bond order as the number of bonding pairs of electrons between two atoms. Thus a single bond has a bond order of 1, a double bond has a bond order of 2, and a triple bond has a bond order of 3. We define bond order differently when we use the molecular orbital description of the distribution of electrons, but the resulting bond order is usually the same. The MO technique is more accurate and can handle cases when the Lewis structure method fails, but both methods describe the same phenomenon.<\/p>\n<p>In the molecular orbital model, an electron contributes to a bonding interaction if it occupies a bonding orbital and it contributes to an antibonding interaction if it occupies an antibonding orbital. The bond order is calculated by subtracting the destabilizing (antibonding) electrons from the stabilizing (bonding) electrons. Since a bond consists of two electrons, we divide by two to get the bond order. We can determine bond order with the following equation:<\/p>\n<p style=\"text-align: center\">[latex]\\text{bond order}=\\frac{\\left(\\text{number of bonding electrons}\\right)-\\left(\\text{number of antibonding electrons}\\right)}{2f}[\/latex]<\/p>\n<p>The order of a covalent bond is a guide to its strength; a bond between two given atoms becomes stronger as the bond order increases (Table 1). If the distribution of electrons in the molecular orbitals between two atoms is such that the resulting bond would have a bond order of zero, a stable bond does not form. We next look at some specific examples of MO diagrams and bond orders.<\/p>\n<h2>Bonding in Diatomic Molecules<\/h2>\n<p>A dihydrogen molecule (H<sub>2<\/sub>) forms from two hydrogen atoms. When the atomic orbitals of the two atoms combine, the electrons occupy the molecular orbital of lowest energy, the \u03c3<sub>1<em>s<\/em><\/sub> bonding orbital. A dihydrogen molecule, H<sub>2<\/sub>, readily forms, because the energy of a H<sub>2<\/sub> molecule is lower than that of two H atoms. The \u03c3<sub>1<em>s<\/em><\/sub> orbital that contains both electrons is lower in energy than either of the two 1<em>s<\/em> atomic orbitals.<\/p>\n<p>A molecular orbital can hold two electrons, so both electrons in the H<sub>2<\/sub> molecule are in the \u03c3<sub>1<em>s<\/em><\/sub> bonding orbital; the electron configuration is [latex]{\\left({\\sigma}_{1s}\\right)}^{2}.[\/latex] We represent this configuration by a molecular orbital energy diagram (Figure 10) in which a single upward arrow indicates one electron in an orbital, and two (upward and downward) arrows indicate two electrons of opposite spin.<\/p>\n<div style=\"width: 889px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211946\/CNX_Chem_08_04_H2MO1.jpg\" alt=\"A diagram is shown that has an upward-facing vertical arrow running along the left side labeled \u201cE.\u201d At the bottom center of the diagram is a horizontal line labeled, \u201csigma subscript 1 s,\u201d that has two vertical half arrows drawn on it, one facing up and one facing down. This line is connected to the right and left by upward-facing, dotted lines to two more horizontal lines, each labeled, \u201c1 s,\u201d and each with one vertical half-arrow facing up drawn on it. These two lines are connected by upward-facing dotted lines to another line in the center of the diagram, but farther up from the first, and labeled, \u201csigma subscript 1 s superscript asterisk.\u201d The left and right sides of the diagram have headers that read, \u201dAtomic orbitals,\u201d while the center header reads, \u201cMolecular orbitals.\u201d The bottom left and right are labeled \u201cH\u201d while the center is labeled \u201cH subscript 2.\u201d\" width=\"879\" height=\"253\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 10. The molecular orbital energy diagram predicts that H<sub>2<\/sub> will be a stable molecule with lower energy than the separated atoms.<\/p>\n<\/div>\n<p>A dihydrogen molecule contains two bonding electrons and no antibonding electrons so we have<\/p>\n<p style=\"text-align: center\">[latex]{\\text{bond order in H}}_{2}=\\frac{\\left(2-0\\right)}{2}=1[\/latex]<\/p>\n<p>Because the bond order for the H\u2013H bond is equal to 1, the bond is a single bond.<\/p>\n<p>A helium atom has two electrons, both of which are in its 1<em>s<\/em> orbital. Two helium atoms do not combine to form a dihelium molecule, He<sub>2<\/sub>, with four electrons, because the stabilizing effect of the two electrons in the lower-energy bonding orbital would be offset by the destabilizing effect of the two electrons in the higher-energy antibonding molecular orbital. We would write the hypothetical electron configuration of He<sub>2<\/sub> as [latex]{\\left({\\sigma}_{1s}\\right)}^{2}{\\left({\\sigma}_{1s}^\\ast\\right)}^{2}[\/latex] as in Figure 11.\u00a0The net energy change would be zero, so there is no driving force for helium atoms to form the diatomic molecule. In fact, helium exists as discrete atoms rather than as diatomic molecules. The bond order in a hypothetical dihelium molecule would be zero.<\/p>\n<p style=\"text-align: center\">[latex]{\\text{bond order in He}}_{2}=\\frac{\\left(2-2\\right)}{2}=0[\/latex]<\/p>\n<p>A bond order of zero indicates that no bond is formed between two atoms.<\/p>\n<div style=\"width: 889px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/887\/2015\/04\/23211948\/CNX_Chem_08_04_He2MO1.jpg\" alt=\"A diagram is shown that has an upward-facing vertical arrow running along the left side labeled, \u201cE.\u201d At the bottom center of the diagram is a horizontal line labeled, \u201csigma subscript 1 s,\u201d that has two vertical half arrows drawn on it, one facing up and one facing down. This line is connected to the right and left by upward-facing, dotted lines to two more horizontal lines, each labeled, \u201c1 s,\u201d and each with one vertical half-arrow facing up and one facing down drawn on it. These two lines are connected by upward-facing dotted lines to another line in the center of the diagram, but farther up from the first, and labeled, \u201csigma subscript 1 s superscript asterisk.\u201d This line has one upward-facing and one downward-facing vertical arrow drawn on it. The left and right sides of the diagram have headers that read, \u201cAtomic orbitals,\u201d while the center header reads, \u201cMolecular orbitals.\u201d The bottom left and right are labeled, \u201cH e,\u201d while the center is labeled, \u201cH e subscript 2.\u201d\" width=\"879\" height=\"297\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 11. The molecular orbital energy diagram predicts that He<sub>2<\/sub> will not be a stable molecule, since it has equal numbers of bonding and antibonding electrons.<\/p>\n<\/div>\n<h3><\/h3>\n<div class=\"textbox key-takeaways\">\n<h3>Key Concepts and Summary<\/h3>\n<p>Molecular orbital (MO) theory describes the behavior of electrons in a molecule in terms of combinations of the atomic wave functions. The resulting molecular orbitals may extend over all the atoms in the molecule. Bonding molecular orbitals are formed by in-phase combinations of atomic wave functions, and electrons in these orbitals stabilize a molecule. Antibonding molecular orbitals result from out-of-phase combinations of atomic wave functions and electrons in these orbitals make a molecule less stable. Molecular orbitals located along an internuclear axis are called \u03c3 MOs. They can be formed from <em>s<\/em> orbitals or from <em>p<\/em> orbitals oriented in an end-to-end fashion. Molecular orbitals formed from <em>p<\/em> orbitals oriented in a side-by-side fashion have electron density on opposite sides of the internuclear axis and are called \u03c0 orbitals.<\/p>\n<p>We can describe the electronic structure of diatomic molecules by applying molecular orbital theory to the valence electrons of the atoms. Electrons fill molecular orbitals following the same rules that apply to filling atomic orbitals; Hund\u2019s rule and the Aufbau principle tell us that lower-energy orbitals will fill first, electrons will spread out before they pair up, and each orbital can hold a maximum of two electrons with opposite spins. Materials with unpaired electrons are paramagnetic and attracted to a magnetic field, while those with all-paired electrons are diamagnetic and repelled by a magnetic field. Correctly predicting the magnetic properties of molecules is in advantage of molecular orbital theory over Lewis structures and valence bond theory.<\/p>\n<h4>Key Equations<\/h4>\n<ul>\n<li>[latex]\\text{bond order}=\\frac{\\left(\\text{number of bonding electron}\\right)-\\left(\\text{number of antibonding electrons}\\right)}{2}[\/latex]<\/li>\n<\/ul>\n<\/div>\n<div class=\"textbox exercises\">\n<h3>Exercises<\/h3>\n<ol>\n<li>Sketch the distribution of electron density in the bonding and antibonding molecular orbitals formed from two <em>s<\/em> orbitals and from two <em>p<\/em> orbitals.<\/li>\n<li>How are the following similar, and how do they differ?\n<ol style=\"list-style-type: lower-alpha\">\n<li>\u03c3 molecular orbitals and \u03c0 molecular orbitals<\/li>\n<li>\u03c8 for an atomic orbital and \u03c8 for a molecular orbital<\/li>\n<li>bonding orbitals and antibonding orbitals<\/li>\n<\/ol>\n<\/li>\n<li>If molecular orbitals are created by combining five atomic orbitals from atom A and five atomic orbitals from atom B combine, how many molecular orbitals will result?<\/li>\n<li>Can a molecule with an odd number of electrons ever be diamagnetic? Explain why or why not.<\/li>\n<li>Can a molecule with an even number of electrons ever be paramagnetic? Explain why or why not.<\/li>\n<li>Why are bonding molecular orbitals lower in energy than the parent atomic orbitals?<\/li>\n<li>Calculate the bond order for an ion with this configuration: [latex]{\\left({\\sigma}_{2s}\\right)}^{2}{\\left({\\sigma}_{2s}^\\ast\\right)}^{2}{\\left({\\sigma}_{2px}\\right)}^{2}{\\left({\\pi}_{2py},{\\pi}_{2pz}\\right)}^{4}{\\left({\\pi}_{2py}^\\ast,{\\pi}_{2pz}^\\ast\\right)}^{3}[\/latex]<\/li>\n<li>Explain why an electron in the bonding molecular orbital in the H<sub>2<\/sub> molecule has a lower energy than an electron in the 1<em>s<\/em> atomic orbital of either of the separated hydrogen atoms.<\/li>\n<li>Predict the valence electron molecular orbital configurations for the following, and state whether they will be stable or unstable ions.\n<ol style=\"list-style-type: lower-alpha\">\n<li>[latex]{\\text{Na}}_{2}^{\\text{2+}}[\/latex]<\/li>\n<li>[latex]{\\text{Mg}}_{2}^{\\text{2+}}[\/latex]<\/li>\n<li>[latex]{\\text{Al}}_{2}^{\\text{2+}}[\/latex]<\/li>\n<li>[latex]{\\text{Si}}_{2}^{\\text{2+}}[\/latex]<\/li>\n<li>[latex]{\\text{P}}_{2}^{\\text{2+}}[\/latex]<\/li>\n<li>[latex]{\\text{S}}_{2}^{\\text{2+}}[\/latex]<\/li>\n<li>[latex]{\\text{F}}_{2}^{\\text{2+}}[\/latex]<\/li>\n<li>[latex]{\\text{Ar}}_{2}^{\\text{2+}}[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>Determine the bond order of each member of the following groups, and determine which member of each group is predicted by the molecular orbital model to have the strongest bond.\n<ol style=\"list-style-type: lower-alpha\">\n<li>H<sub>2<\/sub>, [latex]{\\text{H}}_{2}^{\\text{+}},[\/latex] [latex]{\\text{H}}_{2}^{-}[\/latex]<\/li>\n<li>O<sub>2<\/sub>, [latex]{\\text{O}}_{2}^{\\text{2+}},[\/latex] [latex]{\\text{O}}_{2}^{2-}[\/latex]<\/li>\n<li>Li<sub>2<\/sub>, [latex]{\\text{Be}}_{2}^{\\text{+}},[\/latex] Be<sub>2\u00a0<\/sub><\/li>\n<li>F<sub>2<\/sub>, [latex]{\\text{F}}_{2}^{\\text{+}},[\/latex] [latex]{\\text{F}}_{2}^{-}[\/latex]<\/li>\n<li>N<sub>2<\/sub>, [latex]{\\text{N}}_{2}^{\\text{+}},[\/latex] [latex]{\\text{N}}_{2}^{-}[\/latex]<\/li>\n<\/ol>\n<\/li>\n<li>For the first ionization energy for an N<sub>2<\/sub> molecule, what molecular orbital is the electron removed from?<\/li>\n<li>Compare the atomic and molecular orbital diagrams to identify the member of each of the following pairs that has the highest first ionization energy (the most tightly bound electron) in the gas phase:\n<ol style=\"list-style-type: lower-alpha\">\n<li>H and H<sub>2\u00a0<\/sub><\/li>\n<li>N and N<sub>2\u00a0<\/sub><\/li>\n<li>O and O<sub>2\u00a0<\/sub><\/li>\n<li>C and C<sub>2\u00a0<\/sub><\/li>\n<li>B and B<sub>2<\/sub><\/li>\n<\/ol>\n<\/li>\n<li>Which of the period 2 homonuclear diatomic molecules are predicted to be paramagnetic?<\/li>\n<li>A friend tells you that the 2<em>s<\/em> orbital for fluorine starts off at a much lower energy than the 2<em>s<\/em> orbital for lithium, so the resulting \u03c3<sub>2<em>s<\/em><\/sub> molecular orbital in F<sub>2<\/sub> is more stable than in Li<sub>2<\/sub>. Do you agree?<\/li>\n<li>True or false: Boron contains 2<em>s<\/em><sup>2<\/sup>2<em>p<\/em><sup>1<\/sup> valence electrons, so only one <em>p<\/em> orbital is needed to form molecular orbitals.<\/li>\n<li>What charge would be needed on F<sub>2<\/sub> to generate an ion with a bond order of 2?<\/li>\n<li>Predict whether the MO diagram for S<sub>2<\/sub> would show s-p mixing or not.<\/li>\n<li>Explain why [latex]{\\text{N}}_{2}^{\\text{2+}}[\/latex] is diamagnetic, while [latex]{\\text{O}}_{2}^{\\text{4+}},[\/latex] which has the same number of valence electrons, is paramagnetic.<\/li>\n<li>Using the MO diagrams, predict the bond order for the stronger bond in each pair:\n<ol style=\"list-style-type: lower-alpha\">\n<li>B<sub>2<\/sub> or [latex]{\\text{B}}_{2}^{+}[\/latex]<\/li>\n<li>F<sub>2<\/sub> or [latex]{\\text{F}}_{2}^{+}[\/latex]<\/li>\n<li>O<sub>2<\/sub> or [latex]{\\text{O}}_{2}^{\\text{2+}}[\/latex]<\/li>\n<li>[latex]{\\text{C}}_{2}^{+}[\/latex] or [latex]{\\text{C}}_{2}^{-}[\/latex]<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q503798\">Show Answer<\/span><\/p>\n<div id=\"q503798\" class=\"hidden-answer\" style=\"display: none\">\n<p>2. The similarities and differences are as follows:<\/p>\n<ol style=\"list-style-type: lower-alpha\">\n<li>Similarities: Both are bonding orbitals that can contain a maximum of two electrons. Differences: <em>\u03c3<\/em> orbitals are end-to-end combinations of atomic orbitals, whereas <em>\u03c0<\/em> orbitals are formed by side-by-side overlap of orbitals.<\/li>\n<li>Similarities: Both are quantum-mechanical constructs that represent the probability of finding the electron about the atom or the molecule. Differences: <em>\u03c8<\/em> for an atomic orbital describes the behavior of only one electron at a time based on the atom. For a molecule, <em>\u03c8<\/em> represents either a mathematical combination of atomic orbitals.<\/li>\n<li>Similarities: Both are orbitals that can contain two electrons. Differences: Bonding orbitals result in holding two or more atoms together. Antibonding orbitals have the effect of destabilizing any bonding that has occurred.<\/li>\n<\/ol>\n<p>4.\u00a0An odd number of electrons can never be paired, regardless of the arrangement of the molecular orbitals. It will always be paramagnetic.<\/p>\n<p>6.\u00a0Bonding orbitals have electron density in close proximity to more than one nucleus. The interaction between the bonding positively charged nuclei and negatively charged electrons stabilizes the system.<\/p>\n<p>8.\u00a0The pairing of the two bonding electrons lowers the energy of the system relative to the energy of the nonbonded electrons.<\/p>\n<p>10.\u00a0The bond order is equal to half the difference between the number of bonding electrons and the number of antibonding electrons. The bond with the greatest bond order is predicted to be the strongest.<\/p>\n<ol style=\"list-style-type: lower-alpha\">\n<li>H<sub>2<\/sub> bond order = 1, [latex]{\\text{H}}_{2}^{+}[\/latex] bond order = 0.5, [latex]{\\text{H}}_{2}^{-}[\/latex] bond order = 0.5, strongest bond is H<sub>2<\/sub>;<\/li>\n<li>O<sub>2<\/sub> bond order = 2, [latex]{\\text{O}}_{2}^{\\text{2+}}[\/latex] bond order = 3; [latex]{\\text{O}}_{2}^{2-}[\/latex] bond order = 1, strongest bond is [latex]{\\text{O}}_{2}^{\\text{2+}};[\/latex]<\/li>\n<li>Li<sub>2<\/sub> bond order = 1, [latex]{\\text{Be}}_{2}^{+}[\/latex] bond order = 0.5, Be<sub>2<\/sub> bond order = 0, Li<sub>2<\/sub> [latex]{\\text{Be}}_{2}^{+}[\/latex] have the same strength bond;<\/li>\n<li>F<sub>2<\/sub> bond order = 1, [latex]{\\text{F}}_{2}^{+}[\/latex] bond order = 1.5, [latex]{\\text{F}}_{2}^{-}[\/latex] bond order = 0.5, strongest bond is [latex]{\\text{F}}_{2}^{\\text{+}};[\/latex]<\/li>\n<li>N<sub>2<\/sub> bond order = 3, [latex]{\\text{N}}_{2}^{+}[\/latex] bond order = 2.5, [latex]{\\text{N}}_{2}^{-}[\/latex] bond order = 2.5, strongest bond is N<sub>2<\/sub>.<\/li>\n<\/ol>\n<p>12. The substance with the\u00a0highest first ionization energy in each pair is as follows:<\/p>\n<ol style=\"list-style-type: lower-alpha\">\n<li>H<sub>2<\/sub><\/li>\n<li>N<sub>2<\/sub><\/li>\n<li>O<\/li>\n<li>C<sub>2<\/sub><\/li>\n<li>B<sub>2<\/sub><\/li>\n<\/ol>\n<p>14.\u00a0Yes, fluorine is a smaller atom than Li, so atoms in the 2<em>s<\/em> orbital are closer to the nucleus and more stable.<\/p>\n<p>16.\u00a02+<\/p>\n<p>18.\u00a0N<sub>2<\/sub> has s-p mixing, so the \u03c0 orbitals are the last filled in [latex]{\\text{N}}_{2}^{\\text{2+}}.[\/latex] O<sub>2<\/sub> does not have s-p mixing, so the \u03c3<em><sub>p<\/sub><\/em> orbital fills before the \u03c0 orbitals.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<h2>Glossary<\/h2>\n<p><strong>antibonding orbital:<\/strong> molecular orbital located outside of the region between two nuclei; electrons in an antibonding orbital destabilize the molecule<\/p>\n<p><strong>bond order:<\/strong> number of pairs of electrons between two atoms; it can be found by the number of bonds in a Lewis structure or by the difference between the number of bonding and antibonding electrons divided by two<\/p>\n<p><strong>bonding orbital:<\/strong> molecular orbital located between two nuclei; electrons in a bonding orbital stabilize a molecule<\/p>\n<p><strong>degenerate orbitals:<\/strong> orbitals that have the same energy<\/p>\n<p><strong>diamagnetism<strong>:<\/strong><\/strong> phenomenon in which a material is not magnetic itself but is repelled by a magnetic field; it occurs when there are only paired electrons present<\/p>\n<p><strong>homonuclear diatomic molecule<strong>:<\/strong><\/strong> molecule consisting of two identical atoms<\/p>\n<p><strong>linear combination of atomic orbitals<strong>:<\/strong><\/strong> technique for combining atomic orbitals to create molecular orbitals<\/p>\n<p><strong>molecular orbital<strong>:<\/strong><\/strong> region of space in which an electron has a high probability of being found in a molecule<\/p>\n<p><strong>molecular orbital diagram<strong>:<\/strong><\/strong> visual representation of the relative energy levels of molecular orbitals<\/p>\n<p><strong>molecular orbital theory<strong>:<\/strong><\/strong> model that describes the behavior of electrons delocalized throughout a molecule in terms of the combination of atomic wave functions<\/p>\n<p><strong>paramagnetism<strong>:<\/strong><\/strong> phenomenon in which a material is not magnetic itself but is attracted to a magnetic field; it occurs when there are unpaired electrons present<\/p>\n<p><strong>\u03c0 bonding orbital<strong>:<\/strong><\/strong> molecular orbital formed by side-by-side overlap of atomic orbitals, in which the electron density is found on opposite sides of the internuclear axis<\/p>\n<p><strong>\u03c0* bonding orbital<strong>:<\/strong><\/strong> antibonding molecular orbital formed by out of phase side-by-side overlap of atomic orbitals, in which the electron density is found on both sides of the internuclear axis, and there is a node between the nuclei<\/p>\n<p><strong>\u03c3 bonding orbital<strong>:<\/strong><\/strong> molecular orbital in which the electron density is found along the axis of the bond<\/p>\n<p><strong>\u03c3* bonding orbital<strong>:<\/strong><\/strong> antibonding molecular orbital formed by out-of-phase overlap of atomic orbital along the axis of the bond, generating a node between the nuclei<\/p>\n<p><strong>s-p mixing:<\/strong> change that causes \u03c3<em><sub>p<\/sub><\/em> orbitals to be less stable than \u03c0<em><sub>p<\/sub><\/em> orbitals due to the mixing of <em>s<\/em> and <em>p<\/em>-based molecular orbitals of similar energies.<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-2057\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Chemistry. <strong>Provided by<\/strong>: OpenStax College. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/openstaxcollege.org\">http:\/\/openstaxcollege.org<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download for free at https:\/\/openstaxcollege.org\/textbooks\/chemistry\/get<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":17,"menu_order":8,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Chemistry\",\"author\":\"\",\"organization\":\"OpenStax College\",\"url\":\"http:\/\/openstaxcollege.org\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download for free at https:\/\/openstaxcollege.org\/textbooks\/chemistry\/get\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-2057","chapter","type-chapter","status-publish","hentry"],"part":3005,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/wp-json\/pressbooks\/v2\/chapters\/2057","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/wp-json\/wp\/v2\/users\/17"}],"version-history":[{"count":24,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/wp-json\/pressbooks\/v2\/chapters\/2057\/revisions"}],"predecessor-version":[{"id":6440,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/wp-json\/pressbooks\/v2\/chapters\/2057\/revisions\/6440"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/wp-json\/pressbooks\/v2\/parts\/3005"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/wp-json\/pressbooks\/v2\/chapters\/2057\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/wp-json\/wp\/v2\/media?parent=2057"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/wp-json\/pressbooks\/v2\/chapter-type?post=2057"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/wp-json\/wp\/v2\/contributor?post=2057"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-chemistryformajors-1\/wp-json\/wp\/v2\/license?post=2057"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}