{"id":1037,"date":"2017-10-19T14:29:40","date_gmt":"2017-10-19T14:29:40","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/?post_type=chapter&#038;p=1037"},"modified":"2018-10-03T20:05:36","modified_gmt":"2018-10-03T20:05:36","slug":"carbocation-structure-and-stability","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/chapter\/carbocation-structure-and-stability\/","title":{"raw":"Carbocation Structure and Stability","rendered":"Carbocation Structure and Stability"},"content":{"raw":"<div class=\"elm-header\">\r\n<div class=\"elm-header-custom\">\r\n<div class=\"textbox learning-objectives\">\r\n<h3>Objectives<\/h3>\r\n<div id=\"elm-main-content\" class=\"elm-content-container\">\r\n<div>\r\n<div id=\"skills\">\r\n\r\nAfter completing this section, you should be able to\r\n<ol>\r\n \t<li>describe the geometry of a given carbocation.<\/li>\r\n \t<li>arrange a given series of carbocations in order of increasing or decreasing stability.<\/li>\r\n \t<li>explain the relative stability of methyl, primary, secondary and tertiary carbocations in terms of hyperconjugation and inductive effects.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"elm-main-content\" class=\"elm-content-container\">\r\n<div id=\"note\">\r\n<div class=\"textbox\">\r\n<h3 class=\"boxtitle\">Study Notes<\/h3>\r\nAlthough hyperconjugation can be used to explain the relative stabilities of carbocations, this explanation is certainly not the only one, and is by no means universally accepted. A more common explanation, involving the concept of an inductive effect, is given below.\r\n\r\nIt is a general principle in chemistry that the more a charge is dispersed, the more stable is the species carrying the charge. Put simply, a species in which a positive charge is shared between two atoms would be more stable than a similar species in which the charge is borne wholly by a single atom. In a tertiary carbocation, the positively charged carbon atom attracts the bonding electrons in the three carbon-carbon sigma (<em>\u03c3<\/em>) bonds, and thus creates slight positive charges on the carbon atoms of the three surrounding alkyl groups (and, indeed, on the hydrogen atoms attached to them). Chemists sometimes use an arrow to represent this inductive release:<img class=\"aligncenter\" src=\"http:\/\/chem.libretexts.org\/@api\/deki\/files\/85534\/7-9.png?origin=mt-web\" alt=\"charge stabilization in a tertiary carbocation\" \/>\r\n\r\n&nbsp;\r\n<blockquote><strong>Note:<\/strong> These diagrams do not reflect the geometry of the carbocation. The overall charge on the carbocation remains unchanged, but some of the charge is now carried by the alkyl groups attached to the central carbon atom; that is, the charge has been dispersed.<\/blockquote>\r\nIn the tertiary carbocation shown above, the three alkyl groups help to stabilize the positive charge. In a secondary carbocation, only two alkyl groups would be available for this purpose, while a primary carbocation has only one alkyl group available. Thus the observed order of stability for carbocations is as follows:\r\n\r\ntertiary &gt; secondary &gt; primary &gt; methyl.\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_1\">\r\n<h3 class=\"editable\">Stability of carbocation intermediates<\/h3>\r\nWe know that the rate-limiting step of an S<sub>N<\/sub>1 reaction is the first step - formation of the this carbocation intermediate. The rate of this step \u2013 and therefore, the rate of the overall substitution reaction \u2013 depends on the activation energy for the process in which the bond between the carbon and the leaving group breaks and a carbocation forms.\u00a0 According to Hammond\u2019s postulate (<a title=\"Organic Chemistry\/Organic Chemistry With a Biological Emphasis\/Chapter 6: Introduction to organic reactivity and catalysis\/Section 6.2: Energy diagrams\" href=\"https:\/\/chem.libretexts.org\/Textbook_Maps\/Organic_Chemistry_Textbook_Maps\/Map%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)\/Chapter_06%3A_Introduction_to_organic_reactivity_and_catalysis\/6.2%3A_Energy_diagrams\" rel=\"internal\">section 6.2B<\/a>), the more stable the carbocation intermediate is, the faster this first bond-breaking step will occur. In other words, the likelihood of a nucleophilic substitution reaction proceeding by a dissociative (S<sub>N<\/sub>1) mechanism depends to a large degree on the stability of the carbocation intermediate that forms.\r\n\r\nThe critical question now becomes, <em>what stabilizes a carbocation<\/em>?\r\n\r\nSo if it takes an electron <em>withdrawing<\/em> group to stabilize a negative charge, what will stabilize a positive charge?\u00a0 An electron <em>donating<\/em> group!\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141011\/image051.png\" alt=\"image052.png\" width=\"355px\" height=\"139px\" \/>\r\n\r\nA positively charged species such as a carbocation is very electron-poor, and thus anything which donates electron density to the center of electron poverty will help to stabilize it. Conversely, a carbocation will be <em>destabilized<\/em> by an electron withdrawing group.\r\n\r\nAlkyl groups \u2013 methyl, ethyl, and the like \u2013 are weak electron donating groups, and thus stabilize nearby carbocations. What this means is that, in general, <em>more substituted carbocations are more stable<\/em>:\u00a0 a tert-butyl carbocation, for example, is more stable than an isopropyl carbocation.\u00a0 Primary carbocations are highly unstable and not often observed as reaction intermediates; methyl carbocations are even less stable.\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141013\/image053.png\" alt=\"image054.png\" width=\"357px\" height=\"150px\" \/>\r\n\r\nAlkyl groups are electron donating and carbocation-stabilizing because the electrons around the neighboring carbons are drawn towards the nearby positive charge, thus slightly reducing the electron poverty of the positively-charged carbon.\r\n\r\nIt is not accurate to say, however, that carbocations with higher substitution are <em>always<\/em> more stable than those with less substitution. Just as electron-donating groups can stabilize a carbocation, electron-withdrawing groups act to destabilize carbocations. Carbonyl groups are electron-withdrawing by inductive effects, due to the polarity of the C=O double bond.\u00a0\u00a0 It is possible to demonstrate in the laboratory (see <a title=\"Organic Chemistry\/Organic Chemistry With a Biological Emphasis\/Chapter 16: Oxidation and reduction reactions\/Section 16.1: Oxidation and reduction of organic compounds - an overview\" href=\"https:\/\/chem.libretexts.org\/Textbook_Maps\/Organic_Chemistry_Textbook_Maps\/Map%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)\/16%3A_Oxidation_and_reduction_reactions\/16.01%3A__Oxidation_and_reduction_of_organic_compounds_-_an_overview\" rel=\"internal\">section 16.1D<\/a>) that carbocation A below is more stable than carbocation B, even though A is a primary carbocation and B is secondary.\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141015\/image055.png\" alt=\"image056.png\" width=\"301px\" height=\"146px\" \/>\r\n\r\nThe difference in stability can be explained by considering the electron-withdrawing inductive effect of the ester carbonyl. Recall that inductive effects - whether electron-withdrawing or donating - are relayed through covalent bonds and that the strength of the effect decreases rapidly as the number of intermediary bonds increases.\u00a0 In other words, the effect decreases with distance.\u00a0 In species B the positive charge is closer to the carbonyl group, thus the destabilizing electron-withdrawing effect is stronger than it is in species A.\r\n<div>\r\n<blockquote>\r\n<p class=\"boxtitle\">Note<\/p>\r\nIn the next chapter we will see how the carbocation-destabilizing effect of electron-withdrawing fluorine substituents can\u00a0 be\u00a0 used in experiments designed to address the question of whether a biochemical nucleophilic substitution reaction is S<sub>N<\/sub>1 or S<sub>N<\/sub>2.<\/blockquote>\r\n<\/div>\r\nStabilization of a carbocation can also occur through resonance effects, and as we have already discussed in the acid-base chapter, resonance effects as a rule are more powerful than inductive effects.\u00a0 Consider the simple case of a <strong>benzylic <\/strong>carbocation:\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141017\/image057.png\" alt=\"image058.png\" width=\"519px\" height=\"84px\" \/>\r\n\r\nThis carbocation is comparatively stable.\u00a0 In this case, electron donation is a resonance effect.\u00a0 Three additional resonance structures can be drawn for this carbocation in which the positive charge is located on one of three aromatic carbons. The positive charge is not isolated on the benzylic carbon, rather it is delocalized around the aromatic structure: this delocalization of charge results in significant stabilization.\u00a0 As a result, benzylic and <strong>allylic<\/strong> carbocations (where the positively charged carbon is conjugated to one or more non-aromatic double bonds) are significantly more stable than even tertiary alkyl carbocations.\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141019\/image059.png\" alt=\"image060.png\" width=\"289px\" height=\"80px\" \/>\r\n\r\nBecause heteroatoms such as oxygen and nitrogen are more electronegative than carbon, you might expect that they would by definition be electron withdrawing groups that destabilize carbocations. In fact, the opposite is often true: if the oxygen or nitrogen atom is in the correct position, the overall effect is carbocation stabilization. This is due to the fact that although these heteroatoms are electron <em>withdrawing<\/em> groups by induction, they are electron <em>donating<\/em> groups by resonance, and it is this resonance effect which is more powerful. (We previously encountered this same idea when considering the relative acidity and basicity of phenols and aromatic amines in <a title=\"Organic Chemistry\/Organic Chemistry With a Biological Emphasis\/Chapter 7: Organic compounds as acids and bases\/Section 7.4: More on resonance effects on acidity and basicity\" href=\"https:\/\/chem.libretexts.org\/Textbook_Maps\/Organic_Chemistry_Textbook_Maps\/Map%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)\/Chapter_07%3A_Organic_compounds_as_acids_and_bases\/7.4%3A_Acid-base_properties_of_phenols\" rel=\"internal\">section 7.4<\/a>).\u00a0 Consider the two pairs of carbocation species below:\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141021\/image061.png\" alt=\"image062.png\" width=\"393px\" height=\"189px\" \/>\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141023\/image063.png\" alt=\"image064.png\" width=\"407px\" height=\"189px\" \/>\r\n\r\nIn the more stable carbocations, the heteroatom acts as an electron donating group by resonance: in effect, the lone pair on the heteroatom is available to delocalize the positive charge.\u00a0 In the less stable carbocations the positively-charged carbon is more than one bond away from the heteroatom, and thus no resonance effects are possible.\u00a0 In fact, in these carbocation species the heteroatoms actually <em>destabilize <\/em>the positive charge, because they are electron withdrawing by induction.\r\n\r\nFinally, <strong>vinylic<\/strong> carbocations, in which the positive charge resides on a double-bonded carbon, are very unstable and thus unlikely to form as intermediates in any reaction.\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141024\/image065.png\" alt=\"image066.png\" width=\"145px\" height=\"114px\" \/>\r\n<div>\r\n<div id=\"example\">\r\n<div class=\"textbox examples\">\r\n<h3>Example<\/h3>\r\n<div>\r\n<div id=\"example\">\r\n\r\nIn which of the structures below is the carbocation expected to be more stable? Explain.\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141026\/image067.png\" alt=\"image068.png\" width=\"360px\" height=\"151px\" \/>\r\n<div>\r\n<dl>\r\n \t<dt><strong class=\"emphasis bold\">Answer:<\/strong><\/dt>\r\n \t<dd>[reveal-answer q=\"739784\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"739784\"]In the carbocation on the left, the positive charge is located in a position relative to the nitrogen such that the lone pair of electrons on the nitrogen can be donated to fill the empty orbital.\u00a0 This is not possible for the carbocation species on the right.\r\n<p style=\"text-align: center\"><img class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141028\/image419.png\" alt=\"image418.png\" width=\"388\" height=\"416\" \/>[\/hidden-answer]<\/p>\r\n<\/dd>\r\n<\/dl>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<p class=\"boxtitle\">For the most part, carbocations are very high-energy, transient intermediate species in organic reactions. However, there are some unusual examples of very stable carbocations that take the form of organic salts. Crystal violet is the common name for the chloride salt of\u00a0 the carbocation whose structure is shown below.\u00a0 Notice the structural possibilities for extensive resonance delocalization of the positive charge, and the presence of three electron-donating amine groups.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141030\/image069.png\" alt=\"image070.png\" width=\"275px\" height=\"225px\" \/>\r\n<div>\r\n<div class=\"textbox examples\">\r\n<h3>Example<\/h3>\r\nDraw a resonance structure of the crystal violet cation in which the positive charge is delocalized to one of the nitrogen atoms.\r\n<dl>\r\n \t<dt><strong class=\"emphasis bold\"><strong class=\"emphasis bold\">[reveal-answer q=\"156516\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"156516\"]<\/strong><\/strong>\r\n<dl>\r\n \t<dd><\/dd>\r\n<\/dl>\r\n<strong class=\"emphasis bold\"><img class=\"internal default alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141033\/image421.png\" alt=\"image420.png\" width=\"572\" height=\"229\" \/> [\/hidden-answer]<\/strong><\/dt>\r\n<\/dl>\r\n<\/div>\r\n<\/div>\r\nWhen considering the possibility that a nucleophilic substitution reaction proceeds <em>via<\/em> an S<sub>N<\/sub>1 pathway, it is critical to evaluate the stability of the hypothetical carbocation intermediate.\u00a0 If this intermediate is not sufficiently stable, an S<sub>N<\/sub>1 mechanism must be considered unlikely, and the reaction probably proceeds by an S<sub>N<\/sub>2 mechanism.\u00a0 In the next chapter we will see several examples of biologically important S<sub>N<\/sub>1 reactions in which the positively charged intermediate is stabilized\u00a0 by inductive and resonance effects inherent in its own molecular structure.\r\n<div>\r\n<div class=\"textbox examples\">\r\n<h3>Examples<\/h3>\r\nState which carbocation in each pair below is more stable, or if they are expected to be approximately equal. Explain your reasoning.\r\n\r\n<img class=\"internal\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141036\/image071.png\" alt=\"image072.png\" width=\"531px\" height=\"350px\" \/>\r\n<div><\/div>\r\n<div>\r\n<dl>\r\n \t<dt><strong class=\"emphasis bold\">Answer:<\/strong><\/dt>\r\n \t<dd>[reveal-answer q=\"978413\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"978413\"]\r\n\r\na) 1 (tertiary vs. secondary carbocation)\r\n\r\nb) equal\r\n\r\nc) 1 (tertiary vs. secondary carbocation)\r\n\r\nd) 2 (positive charge is further from electron-withdrawing fluorine)\r\n\r\ne) 1 (lone pair on nitrogen can donate electrons by resonance)\r\n\r\nf)\u00a0 1 (allylic carbocation \u2013 positive charge can be delocalized to a second carbon)[\/hidden-answer]<\/dd>\r\n<\/dl>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_2\">\r\n<div class=\"textbox exercises\">\r\n<h3>Exercises<\/h3>\r\n<div id=\"section_2\">\r\n<div id=\"s61712\">\r\n<div id=\"section_29\">\r\n<h3 id=\"Questions-61712\">Question<\/h3>\r\nDraw the cationic intermediates that are seen in the following reactions:\r\n\r\n<img class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141038\/7-9qu.png\" alt=\"\" width=\"314\" height=\"252\" \/>\r\n\r\n<\/div>\r\n<div id=\"section_30\">\r\n<h3 id=\"Solutions-61712\">Solution<\/h3>\r\n[reveal-answer q=\"630324\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"630324\"]\r\n\r\n<img class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141042\/7-9sol.png\" alt=\"\" width=\"495\" height=\"235\" \/>[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_3\"><\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_3\">\r\n<h3 class=\"editable\">Contributors<\/h3>\r\n<ul>\r\n \t<li><a class=\"external\" title=\"http:\/\/science.athabascau.ca\/staff-pages\/dietmark\" href=\"http:\/\/science.athabascau.ca\/staff-pages\/dietmark\" target=\"_blank\" rel=\"external nofollow noopener\">Dr. Dietmar Kennepohl<\/a> FCIC (Professor of Chemistry, <a class=\"external\" title=\"http:\/\/www.athabascau.ca\/\" href=\"http:\/\/www.athabascau.ca\/\" target=\"_blank\" rel=\"external nofollow noopener\">Athabasca University<\/a>)<\/li>\r\n \t<li>Prof. Steven Farmer (<a class=\"external\" title=\"http:\/\/www.sonoma.edu\" href=\"http:\/\/www.sonoma.edu\" target=\"_blank\" rel=\"external nofollow noopener\">Sonoma State University<\/a>)<\/li>\r\n \t<li><a title=\"Organic_Chemistry_With_a_Biological_Emphasis\" href=\"https:\/\/chem.libretexts.org\/Textbook_Maps\/Organic_Chemistry_Textbook_Maps\/Map%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)\" rel=\"internal\">Organic Chemistry With a Biological Emphasis <\/a>by\u00a0<a class=\"external\" title=\"http:\/\/facultypages.morris.umn.edu\/~soderbt\/\" href=\"http:\/\/facultypages.morris.umn.edu\/%7Esoderbt\/\" target=\"_blank\" rel=\"external nofollow noopener\">Tim Soderberg<\/a>\u00a0(University of Minnesota, Morris)<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>","rendered":"<div class=\"elm-header\">\n<div class=\"elm-header-custom\">\n<div class=\"textbox learning-objectives\">\n<h3>Objectives<\/h3>\n<div id=\"elm-main-content\" class=\"elm-content-container\">\n<div>\n<div id=\"skills\">\n<p>After completing this section, you should be able to<\/p>\n<ol>\n<li>describe the geometry of a given carbocation.<\/li>\n<li>arrange a given series of carbocations in order of increasing or decreasing stability.<\/li>\n<li>explain the relative stability of methyl, primary, secondary and tertiary carbocations in terms of hyperconjugation and inductive effects.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"elm-main-content\" class=\"elm-content-container\">\n<div id=\"note\">\n<div class=\"textbox\">\n<h3 class=\"boxtitle\">Study Notes<\/h3>\n<p>Although hyperconjugation can be used to explain the relative stabilities of carbocations, this explanation is certainly not the only one, and is by no means universally accepted. A more common explanation, involving the concept of an inductive effect, is given below.<\/p>\n<p>It is a general principle in chemistry that the more a charge is dispersed, the more stable is the species carrying the charge. Put simply, a species in which a positive charge is shared between two atoms would be more stable than a similar species in which the charge is borne wholly by a single atom. In a tertiary carbocation, the positively charged carbon atom attracts the bonding electrons in the three carbon-carbon sigma (<em>\u03c3<\/em>) bonds, and thus creates slight positive charges on the carbon atoms of the three surrounding alkyl groups (and, indeed, on the hydrogen atoms attached to them). Chemists sometimes use an arrow to represent this inductive release:<img decoding=\"async\" class=\"aligncenter\" src=\"http:\/\/chem.libretexts.org\/@api\/deki\/files\/85534\/7-9.png?origin=mt-web\" alt=\"charge stabilization in a tertiary carbocation\" \/><\/p>\n<p>&nbsp;<\/p>\n<blockquote><p><strong>Note:<\/strong> These diagrams do not reflect the geometry of the carbocation. The overall charge on the carbocation remains unchanged, but some of the charge is now carried by the alkyl groups attached to the central carbon atom; that is, the charge has been dispersed.<\/p><\/blockquote>\n<p>In the tertiary carbocation shown above, the three alkyl groups help to stabilize the positive charge. In a secondary carbocation, only two alkyl groups would be available for this purpose, while a primary carbocation has only one alkyl group available. Thus the observed order of stability for carbocations is as follows:<\/p>\n<p>tertiary &gt; secondary &gt; primary &gt; methyl.<\/p>\n<\/div>\n<\/div>\n<div id=\"section_1\">\n<h3 class=\"editable\">Stability of carbocation intermediates<\/h3>\n<p>We know that the rate-limiting step of an S<sub>N<\/sub>1 reaction is the first step &#8211; formation of the this carbocation intermediate. The rate of this step \u2013 and therefore, the rate of the overall substitution reaction \u2013 depends on the activation energy for the process in which the bond between the carbon and the leaving group breaks and a carbocation forms.\u00a0 According to Hammond\u2019s postulate (<a title=\"Organic Chemistry\/Organic Chemistry With a Biological Emphasis\/Chapter 6: Introduction to organic reactivity and catalysis\/Section 6.2: Energy diagrams\" href=\"https:\/\/chem.libretexts.org\/Textbook_Maps\/Organic_Chemistry_Textbook_Maps\/Map%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)\/Chapter_06%3A_Introduction_to_organic_reactivity_and_catalysis\/6.2%3A_Energy_diagrams\" rel=\"internal\">section 6.2B<\/a>), the more stable the carbocation intermediate is, the faster this first bond-breaking step will occur. In other words, the likelihood of a nucleophilic substitution reaction proceeding by a dissociative (S<sub>N<\/sub>1) mechanism depends to a large degree on the stability of the carbocation intermediate that forms.<\/p>\n<p>The critical question now becomes, <em>what stabilizes a carbocation<\/em>?<\/p>\n<p>So if it takes an electron <em>withdrawing<\/em> group to stabilize a negative charge, what will stabilize a positive charge?\u00a0 An electron <em>donating<\/em> group!<\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141011\/image051.png\" alt=\"image052.png\" width=\"355px\" height=\"139px\" \/><\/p>\n<p>A positively charged species such as a carbocation is very electron-poor, and thus anything which donates electron density to the center of electron poverty will help to stabilize it. Conversely, a carbocation will be <em>destabilized<\/em> by an electron withdrawing group.<\/p>\n<p>Alkyl groups \u2013 methyl, ethyl, and the like \u2013 are weak electron donating groups, and thus stabilize nearby carbocations. What this means is that, in general, <em>more substituted carbocations are more stable<\/em>:\u00a0 a tert-butyl carbocation, for example, is more stable than an isopropyl carbocation.\u00a0 Primary carbocations are highly unstable and not often observed as reaction intermediates; methyl carbocations are even less stable.<\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141013\/image053.png\" alt=\"image054.png\" width=\"357px\" height=\"150px\" \/><\/p>\n<p>Alkyl groups are electron donating and carbocation-stabilizing because the electrons around the neighboring carbons are drawn towards the nearby positive charge, thus slightly reducing the electron poverty of the positively-charged carbon.<\/p>\n<p>It is not accurate to say, however, that carbocations with higher substitution are <em>always<\/em> more stable than those with less substitution. Just as electron-donating groups can stabilize a carbocation, electron-withdrawing groups act to destabilize carbocations. Carbonyl groups are electron-withdrawing by inductive effects, due to the polarity of the C=O double bond.\u00a0\u00a0 It is possible to demonstrate in the laboratory (see <a title=\"Organic Chemistry\/Organic Chemistry With a Biological Emphasis\/Chapter 16: Oxidation and reduction reactions\/Section 16.1: Oxidation and reduction of organic compounds - an overview\" href=\"https:\/\/chem.libretexts.org\/Textbook_Maps\/Organic_Chemistry_Textbook_Maps\/Map%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)\/16%3A_Oxidation_and_reduction_reactions\/16.01%3A__Oxidation_and_reduction_of_organic_compounds_-_an_overview\" rel=\"internal\">section 16.1D<\/a>) that carbocation A below is more stable than carbocation B, even though A is a primary carbocation and B is secondary.<\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141015\/image055.png\" alt=\"image056.png\" width=\"301px\" height=\"146px\" \/><\/p>\n<p>The difference in stability can be explained by considering the electron-withdrawing inductive effect of the ester carbonyl. Recall that inductive effects &#8211; whether electron-withdrawing or donating &#8211; are relayed through covalent bonds and that the strength of the effect decreases rapidly as the number of intermediary bonds increases.\u00a0 In other words, the effect decreases with distance.\u00a0 In species B the positive charge is closer to the carbonyl group, thus the destabilizing electron-withdrawing effect is stronger than it is in species A.<\/p>\n<div>\n<blockquote>\n<p class=\"boxtitle\">Note<\/p>\n<p>In the next chapter we will see how the carbocation-destabilizing effect of electron-withdrawing fluorine substituents can\u00a0 be\u00a0 used in experiments designed to address the question of whether a biochemical nucleophilic substitution reaction is S<sub>N<\/sub>1 or S<sub>N<\/sub>2.<\/p><\/blockquote>\n<\/div>\n<p>Stabilization of a carbocation can also occur through resonance effects, and as we have already discussed in the acid-base chapter, resonance effects as a rule are more powerful than inductive effects.\u00a0 Consider the simple case of a <strong>benzylic <\/strong>carbocation:<\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141017\/image057.png\" alt=\"image058.png\" width=\"519px\" height=\"84px\" \/><\/p>\n<p>This carbocation is comparatively stable.\u00a0 In this case, electron donation is a resonance effect.\u00a0 Three additional resonance structures can be drawn for this carbocation in which the positive charge is located on one of three aromatic carbons. The positive charge is not isolated on the benzylic carbon, rather it is delocalized around the aromatic structure: this delocalization of charge results in significant stabilization.\u00a0 As a result, benzylic and <strong>allylic<\/strong> carbocations (where the positively charged carbon is conjugated to one or more non-aromatic double bonds) are significantly more stable than even tertiary alkyl carbocations.<\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141019\/image059.png\" alt=\"image060.png\" width=\"289px\" height=\"80px\" \/><\/p>\n<p>Because heteroatoms such as oxygen and nitrogen are more electronegative than carbon, you might expect that they would by definition be electron withdrawing groups that destabilize carbocations. In fact, the opposite is often true: if the oxygen or nitrogen atom is in the correct position, the overall effect is carbocation stabilization. This is due to the fact that although these heteroatoms are electron <em>withdrawing<\/em> groups by induction, they are electron <em>donating<\/em> groups by resonance, and it is this resonance effect which is more powerful. (We previously encountered this same idea when considering the relative acidity and basicity of phenols and aromatic amines in <a title=\"Organic Chemistry\/Organic Chemistry With a Biological Emphasis\/Chapter 7: Organic compounds as acids and bases\/Section 7.4: More on resonance effects on acidity and basicity\" href=\"https:\/\/chem.libretexts.org\/Textbook_Maps\/Organic_Chemistry_Textbook_Maps\/Map%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)\/Chapter_07%3A_Organic_compounds_as_acids_and_bases\/7.4%3A_Acid-base_properties_of_phenols\" rel=\"internal\">section 7.4<\/a>).\u00a0 Consider the two pairs of carbocation species below:<\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141021\/image061.png\" alt=\"image062.png\" width=\"393px\" height=\"189px\" \/><\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141023\/image063.png\" alt=\"image064.png\" width=\"407px\" height=\"189px\" \/><\/p>\n<p>In the more stable carbocations, the heteroatom acts as an electron donating group by resonance: in effect, the lone pair on the heteroatom is available to delocalize the positive charge.\u00a0 In the less stable carbocations the positively-charged carbon is more than one bond away from the heteroatom, and thus no resonance effects are possible.\u00a0 In fact, in these carbocation species the heteroatoms actually <em>destabilize <\/em>the positive charge, because they are electron withdrawing by induction.<\/p>\n<p>Finally, <strong>vinylic<\/strong> carbocations, in which the positive charge resides on a double-bonded carbon, are very unstable and thus unlikely to form as intermediates in any reaction.<\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141024\/image065.png\" alt=\"image066.png\" width=\"145px\" height=\"114px\" \/><\/p>\n<div>\n<div id=\"example\">\n<div class=\"textbox examples\">\n<h3>Example<\/h3>\n<div>\n<div id=\"example\">\n<p>In which of the structures below is the carbocation expected to be more stable? Explain.<\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141026\/image067.png\" alt=\"image068.png\" width=\"360px\" height=\"151px\" \/><\/p>\n<div>\n<dl>\n<dt><strong class=\"emphasis bold\">Answer:<\/strong><\/dt>\n<dd>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q739784\">Show Answer<\/span><\/p>\n<div id=\"q739784\" class=\"hidden-answer\" style=\"display: none\">In the carbocation on the left, the positive charge is located in a position relative to the nitrogen such that the lone pair of electrons on the nitrogen can be donated to fill the empty orbital.\u00a0 This is not possible for the carbocation species on the right.<\/p>\n<p style=\"text-align: center\"><img loading=\"lazy\" decoding=\"async\" class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141028\/image419.png\" alt=\"image418.png\" width=\"388\" height=\"416\" \/><\/div>\n<\/div>\n<\/dd>\n<\/dl>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p class=\"boxtitle\">For the most part, carbocations are very high-energy, transient intermediate species in organic reactions. However, there are some unusual examples of very stable carbocations that take the form of organic salts. Crystal violet is the common name for the chloride salt of\u00a0 the carbocation whose structure is shown below.\u00a0 Notice the structural possibilities for extensive resonance delocalization of the positive charge, and the presence of three electron-donating amine groups.<\/p>\n<\/div>\n<\/div>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141030\/image069.png\" alt=\"image070.png\" width=\"275px\" height=\"225px\" \/><\/p>\n<div>\n<div class=\"textbox examples\">\n<h3>Example<\/h3>\n<p>Draw a resonance structure of the crystal violet cation in which the positive charge is delocalized to one of the nitrogen atoms.<\/p>\n<dl>\n<dt><strong class=\"emphasis bold\"><strong class=\"emphasis bold\"><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q156516\">Show Answer<\/span><\/p>\n<div id=\"q156516\" class=\"hidden-answer\" style=\"display: none\"><\/strong><\/strong>\n<\/dt>\n<dd><\/dd>\n<\/dl>\n<p><strong class=\"emphasis bold\"><img loading=\"lazy\" decoding=\"async\" class=\"internal default alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141033\/image421.png\" alt=\"image420.png\" width=\"572\" height=\"229\" \/> <\/div>\n<\/div>\n<p><\/strong><\/p>\n<\/div>\n<\/div>\n<p>When considering the possibility that a nucleophilic substitution reaction proceeds <em>via<\/em> an S<sub>N<\/sub>1 pathway, it is critical to evaluate the stability of the hypothetical carbocation intermediate.\u00a0 If this intermediate is not sufficiently stable, an S<sub>N<\/sub>1 mechanism must be considered unlikely, and the reaction probably proceeds by an S<sub>N<\/sub>2 mechanism.\u00a0 In the next chapter we will see several examples of biologically important S<sub>N<\/sub>1 reactions in which the positively charged intermediate is stabilized\u00a0 by inductive and resonance effects inherent in its own molecular structure.<\/p>\n<div>\n<div class=\"textbox examples\">\n<h3>Examples<\/h3>\n<p>State which carbocation in each pair below is more stable, or if they are expected to be approximately equal. Explain your reasoning.<\/p>\n<p><img decoding=\"async\" class=\"internal\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141036\/image071.png\" alt=\"image072.png\" width=\"531px\" height=\"350px\" \/><\/p>\n<div><\/div>\n<div>\n<dl>\n<dt><strong class=\"emphasis bold\">Answer:<\/strong><\/dt>\n<dd>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q978413\">Show Answer<\/span><\/p>\n<div id=\"q978413\" class=\"hidden-answer\" style=\"display: none\">\n<p>a) 1 (tertiary vs. secondary carbocation)<\/p>\n<p>b) equal<\/p>\n<p>c) 1 (tertiary vs. secondary carbocation)<\/p>\n<p>d) 2 (positive charge is further from electron-withdrawing fluorine)<\/p>\n<p>e) 1 (lone pair on nitrogen can donate electrons by resonance)<\/p>\n<p>f)\u00a0 1 (allylic carbocation \u2013 positive charge can be delocalized to a second carbon)<\/p><\/div>\n<\/div>\n<\/dd>\n<\/dl>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"section_2\">\n<div class=\"textbox exercises\">\n<h3>Exercises<\/h3>\n<div id=\"section_2\">\n<div id=\"s61712\">\n<div id=\"section_29\">\n<h3 id=\"Questions-61712\">Question<\/h3>\n<p>Draw the cationic intermediates that are seen in the following reactions:<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141038\/7-9qu.png\" alt=\"\" width=\"314\" height=\"252\" \/><\/p>\n<\/div>\n<div id=\"section_30\">\n<h3 id=\"Solutions-61712\">Solution<\/h3>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q630324\">Show Answer<\/span><\/p>\n<div id=\"q630324\" class=\"hidden-answer\" style=\"display: none\">\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05141042\/7-9sol.png\" alt=\"\" width=\"495\" height=\"235\" \/><\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"section_3\"><\/div>\n<\/div>\n<\/div>\n<div id=\"section_3\">\n<h3 class=\"editable\">Contributors<\/h3>\n<ul>\n<li><a class=\"external\" title=\"http:\/\/science.athabascau.ca\/staff-pages\/dietmark\" href=\"http:\/\/science.athabascau.ca\/staff-pages\/dietmark\" target=\"_blank\" rel=\"external nofollow noopener\">Dr. Dietmar Kennepohl<\/a> FCIC (Professor of Chemistry, <a class=\"external\" title=\"http:\/\/www.athabascau.ca\/\" href=\"http:\/\/www.athabascau.ca\/\" target=\"_blank\" rel=\"external nofollow noopener\">Athabasca University<\/a>)<\/li>\n<li>Prof. Steven Farmer (<a class=\"external\" title=\"http:\/\/www.sonoma.edu\" href=\"http:\/\/www.sonoma.edu\" target=\"_blank\" rel=\"external nofollow noopener\">Sonoma State University<\/a>)<\/li>\n<li><a title=\"Organic_Chemistry_With_a_Biological_Emphasis\" href=\"https:\/\/chem.libretexts.org\/Textbook_Maps\/Organic_Chemistry_Textbook_Maps\/Map%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)\" rel=\"internal\">Organic Chemistry With a Biological Emphasis <\/a>by\u00a0<a class=\"external\" title=\"http:\/\/facultypages.morris.umn.edu\/~soderbt\/\" href=\"http:\/\/facultypages.morris.umn.edu\/%7Esoderbt\/\" target=\"_blank\" rel=\"external nofollow noopener\">Tim Soderberg<\/a>\u00a0(University of Minnesota, Morris)<\/li>\n<\/ul>\n<\/div>\n<\/div>\n","protected":false},"author":44985,"menu_order":10,"template":"","meta":{"_candela_citation":"[]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1037","chapter","type-chapter","status-publish","hentry"],"part":23,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/1037","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/users\/44985"}],"version-history":[{"count":5,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/1037\/revisions"}],"predecessor-version":[{"id":2291,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/1037\/revisions\/2291"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/parts\/23"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/1037\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/media?parent=1037"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=1037"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/contributor?post=1037"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/license?post=1037"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}