{"id":1661,"date":"2017-10-10T16:26:21","date_gmt":"2017-10-10T16:26:21","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/?post_type=chapter&#038;p=1661"},"modified":"2018-10-05T19:24:52","modified_gmt":"2018-10-05T19:24:52","slug":"nuclear-magnetic-resonance-spectroscopy","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/chapter\/nuclear-magnetic-resonance-spectroscopy\/","title":{"raw":"Nuclear Magnetic Resonance  Spectroscopy","rendered":"Nuclear Magnetic Resonance  Spectroscopy"},"content":{"raw":"<div class=\"elm-header\">\r\n<div class=\"elm-header-custom\">\r\n<div class=\"textbox learning-objectives\">\r\n<h3>Objectives<\/h3>\r\n<div id=\"elm-main-content\" class=\"elm-content-container\">\r\n<div>\r\n<div id=\"skills\">\r\n\r\nAfter completing this section, you should be able to\r\n<ol>\r\n \t<li>discuss the principles of NMR spectroscopy.<\/li>\r\n \t<li>identify the two magnetic nuclei that are most important to an organic chemist.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"elm-main-content\" class=\"elm-content-container\">\r\n<div>\r\n<div>\r\n<div class=\"textbox key-takeaways\">\r\n<h3>Key Terms<\/h3>\r\nMake certain that you can define, and use in context, the key term below.\r\n<ul>\r\n \t<li>resonance<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<div id=\"note\">\r\n<div class=\"textbox\">\r\n<h3 class=\"boxtitle\">Study Notes<\/h3>\r\nNotice that the word \u201cresonance\u201d has a different meaning when we are discussing nuclear magnetic resonance spectroscopy than it does when discussing molecular structures.\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_1\">\r\n<h3 class=\"editable\">Introduction<\/h3>\r\nSome types of atomic nuclei act as though they spin on their axis similar to the Earth. Since they are positively charged they generate an electromagnetic field just as the Earth does. So, in effect, they will act as tiny bar magnetics. Not all nuclei act this way, but fortunately both <sup>1<\/sup>H and <sup>13<\/sup>C do have nuclear spins and will respond to this technique.\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05153759\/nmr.jpg\" alt=\"\" width=\"417px\" height=\"334px\" \/>\r\n\r\nNMR Spectrometer\r\n\r\nIn the absence of an external magnetic field the direction of the spin of the nuclei will be randomly oriented (see figure below left). However, when a sample of these nuclei is place in an external magnetic field, the nuclear spins will adopt specific orientations much as a compass needle responses to the Earth\u2019s magnetic field and aligns with it. Two possible orientations are possible, with the external field (<em>i.e.<\/em> parallel to and in the same direction as the external field) or against the field (<em>i.e.<\/em> antiparallel to the external field). See figure below right.\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05153801\/nmr-1.png\" alt=\"\" width=\"261px\" height=\"348px\" \/>\u00a0\u00a0\u00a0\u00a0\u00a0 <img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05153803\/nmr-2.png\" alt=\"\" width=\"261px\" height=\"319px\" \/>\r\n\r\n<strong>Figure 1:<\/strong> (Left) Random nuclear spin without an external magnetic field. (Right)Ordered nuclear spin in an external magnetic field\r\n\r\nIf the ordered nuclei are now subjected to EM radiation of the proper frequency the nuclei aligned with the field will absorb energy and \"spin-flip\" to align themselves against the field, a higher energy state. When this spin-flip occurs the nuclei are said to be in \"resonance\" with the field, hence the name for the technique, <strong>N<\/strong>uclear <strong>M<\/strong>agentic <strong>R<\/strong>esonance or NMR.\r\n\r\nThe amount of energy, and hence the exact frequency of EM radiation required for resonance to occur is dependent on both the strength of the magnetic field applied and the type of the nuclei being studied. As the strength of the magnetic field increases the energy difference between the two spin states increases and a higher frequency (more energy) EM radiation needs to be applied to achieve a spin-flip (see image below).\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05153805\/nmr-3.png\" alt=\"\" width=\"652px\" height=\"326px\" \/>\r\n\r\nSuperconducting magnets can be used to produce very strong magnetic field, on the order of 21 tesla (T). Lower field strengths can also be used, in the range of 4 - 7 T. At these levels the energy required to bring the nuclei into resonance is in the MHz range and corresponds to radio wavelength energies, <em>i.e.<\/em> at a field strength of 4.7 T 200 MHz bring <sup>1<\/sup>H nuclei into resonance and 50 MHz bring <sup>13<\/sup>C into resonance. This is considerably less energy then is required for IR spectroscopy, ~10<sup>-4<\/sup> kJ\/mol versus ~5 - ~50 kJ\/mol.\r\n\r\n<sup>1<\/sup>H and <sup>13<\/sup>C are not unique in their ability to undergo NMR. All nuclei with an odd number of protons (<sup>1<\/sup>H, <sup>2<\/sup>H, <sup>14<\/sup>N, <sup>19<\/sup>F, <sup>31<\/sup>P ...) or nuclei with an odd number of neutrons (<em>i.e.<\/em> <sup>13<\/sup>C) show the magnetic properties required for NMR. Only nuclei with even number of both protons and neutrons (<sup>12<\/sup>C and <sup>16<\/sup>O) do not have the required magnetic properties.\r\n\r\n<\/div>\r\n<div id=\"section_2\">\r\n<div class=\"textbox exercises\">\r\n<h3>Exercises<\/h3>\r\n<div id=\"s61718\">\r\n<div id=\"section_5\">\r\n<h4 id=\"Questions-61718\">Questions<\/h4>\r\n<strong>1.<\/strong>If in a field strength of 4.7 T, H<sup>1 <\/sup>requires 200 MHz of energy to maintain resonance. If atom X requires 150 MHz, calculate the amount of energy required to spin flip atom X\u2019s nucleus. Is this amount greater than the energy required for hydrogen?\r\n\r\n<strong>2.\u00a0<\/strong>Calculate the energy required to spin flip at 400 MHz. Does changing the frequency to 500 MHz decrease or increase the energy required? What about 300 MHz.\r\n\r\n<\/div>\r\n<div id=\"section_6\">\r\n<h3>Solutions<\/h3>\r\n<p id=\"Solutions-61718\">[reveal-answer q=\"147150\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"147150\"]<\/p>\r\n1. E = h\u03c5 E = (6.62 \u00d7 10\u221234)(150 MHz) E = 9.93 \u00d7 10\u221226 J The energy is equal to 9.93x10-26 J. This value is smaller than the energy required for hydrogen (1.324 \u00d7 10\u221225 J).\r\n\r\n2. E = h\u03c5 E = (6.62 \u00d7 10\u221234)(400 MHz) E = 2.648 \u00d7 10\u221225 J The energy would increase if the frequency would increase to 500 MHz, and decrease if the frequency would decrease to 300 MHz. [\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_3\">\r\n<h3 class=\"editable\">Contributors<\/h3>\r\n<ul>\r\n \t<li><a class=\"external\" title=\"http:\/\/science.athabascau.ca\/staff-pages\/dietmark\" href=\"http:\/\/science.athabascau.ca\/staff-pages\/dietmark\" target=\"_blank\" rel=\"external nofollow noopener\">Dr. Dietmar Kennepohl<\/a> FCIC (Professor of Chemistry, <a class=\"external\" title=\"http:\/\/www.athabascau.ca\/\" href=\"http:\/\/www.athabascau.ca\/\" target=\"_blank\" rel=\"external nofollow noopener\">Athabasca University<\/a>)<\/li>\r\n \t<li>Prof. Steven Farmer (<a class=\"external\" title=\"http:\/\/www.sonoma.edu\" href=\"http:\/\/www.sonoma.edu\" target=\"_blank\" rel=\"external nofollow noopener\">Sonoma State University<\/a>)<\/li>\r\n \t<li><a class=\"external\" title=\"http:\/\/undergrad-ed.chemistry.ohio-state.edu\/\" href=\"http:\/\/undergrad-ed.chemistry.ohio-state.edu\/\" target=\"_blank\" rel=\"external nofollow noopener\">Dr. Richard Spinney<\/a> <a class=\"external\" title=\"http:\/\/chemistry.osu.edu\/\" href=\"http:\/\/chemistry.osu.edu\/\" target=\"_blank\" rel=\"external nofollow noopener\">(The Ohio State University)<\/a><\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div class=\"elm-header\">\n<div class=\"elm-header-custom\">\n<div class=\"textbox learning-objectives\">\n<h3>Objectives<\/h3>\n<div id=\"elm-main-content\" class=\"elm-content-container\">\n<div>\n<div id=\"skills\">\n<p>After completing this section, you should be able to<\/p>\n<ol>\n<li>discuss the principles of NMR spectroscopy.<\/li>\n<li>identify the two magnetic nuclei that are most important to an organic chemist.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"elm-main-content\" class=\"elm-content-container\">\n<div>\n<div>\n<div class=\"textbox key-takeaways\">\n<h3>Key Terms<\/h3>\n<p>Make certain that you can define, and use in context, the key term below.<\/p>\n<ul>\n<li>resonance<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div id=\"note\">\n<div class=\"textbox\">\n<h3 class=\"boxtitle\">Study Notes<\/h3>\n<p>Notice that the word \u201cresonance\u201d has a different meaning when we are discussing nuclear magnetic resonance spectroscopy than it does when discussing molecular structures.<\/p>\n<\/div>\n<\/div>\n<div id=\"section_1\">\n<h3 class=\"editable\">Introduction<\/h3>\n<p>Some types of atomic nuclei act as though they spin on their axis similar to the Earth. Since they are positively charged they generate an electromagnetic field just as the Earth does. So, in effect, they will act as tiny bar magnetics. Not all nuclei act this way, but fortunately both <sup>1<\/sup>H and <sup>13<\/sup>C do have nuclear spins and will respond to this technique.<\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05153759\/nmr.jpg\" alt=\"\" width=\"417px\" height=\"334px\" \/><\/p>\n<p>NMR Spectrometer<\/p>\n<p>In the absence of an external magnetic field the direction of the spin of the nuclei will be randomly oriented (see figure below left). However, when a sample of these nuclei is place in an external magnetic field, the nuclear spins will adopt specific orientations much as a compass needle responses to the Earth\u2019s magnetic field and aligns with it. Two possible orientations are possible, with the external field (<em>i.e.<\/em> parallel to and in the same direction as the external field) or against the field (<em>i.e.<\/em> antiparallel to the external field). See figure below right.<\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05153801\/nmr-1.png\" alt=\"\" width=\"261px\" height=\"348px\" \/>\u00a0\u00a0\u00a0\u00a0\u00a0 <img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05153803\/nmr-2.png\" alt=\"\" width=\"261px\" height=\"319px\" \/><\/p>\n<p><strong>Figure 1:<\/strong> (Left) Random nuclear spin without an external magnetic field. (Right)Ordered nuclear spin in an external magnetic field<\/p>\n<p>If the ordered nuclei are now subjected to EM radiation of the proper frequency the nuclei aligned with the field will absorb energy and &#8220;spin-flip&#8221; to align themselves against the field, a higher energy state. When this spin-flip occurs the nuclei are said to be in &#8220;resonance&#8221; with the field, hence the name for the technique, <strong>N<\/strong>uclear <strong>M<\/strong>agentic <strong>R<\/strong>esonance or NMR.<\/p>\n<p>The amount of energy, and hence the exact frequency of EM radiation required for resonance to occur is dependent on both the strength of the magnetic field applied and the type of the nuclei being studied. As the strength of the magnetic field increases the energy difference between the two spin states increases and a higher frequency (more energy) EM radiation needs to be applied to achieve a spin-flip (see image below).<\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05153805\/nmr-3.png\" alt=\"\" width=\"652px\" height=\"326px\" \/><\/p>\n<p>Superconducting magnets can be used to produce very strong magnetic field, on the order of 21 tesla (T). Lower field strengths can also be used, in the range of 4 &#8211; 7 T. At these levels the energy required to bring the nuclei into resonance is in the MHz range and corresponds to radio wavelength energies, <em>i.e.<\/em> at a field strength of 4.7 T 200 MHz bring <sup>1<\/sup>H nuclei into resonance and 50 MHz bring <sup>13<\/sup>C into resonance. This is considerably less energy then is required for IR spectroscopy, ~10<sup>-4<\/sup> kJ\/mol versus ~5 &#8211; ~50 kJ\/mol.<\/p>\n<p><sup>1<\/sup>H and <sup>13<\/sup>C are not unique in their ability to undergo NMR. All nuclei with an odd number of protons (<sup>1<\/sup>H, <sup>2<\/sup>H, <sup>14<\/sup>N, <sup>19<\/sup>F, <sup>31<\/sup>P &#8230;) or nuclei with an odd number of neutrons (<em>i.e.<\/em> <sup>13<\/sup>C) show the magnetic properties required for NMR. Only nuclei with even number of both protons and neutrons (<sup>12<\/sup>C and <sup>16<\/sup>O) do not have the required magnetic properties.<\/p>\n<\/div>\n<div id=\"section_2\">\n<div class=\"textbox exercises\">\n<h3>Exercises<\/h3>\n<div id=\"s61718\">\n<div id=\"section_5\">\n<h4 id=\"Questions-61718\">Questions<\/h4>\n<p><strong>1.<\/strong>If in a field strength of 4.7 T, H<sup>1 <\/sup>requires 200 MHz of energy to maintain resonance. If atom X requires 150 MHz, calculate the amount of energy required to spin flip atom X\u2019s nucleus. Is this amount greater than the energy required for hydrogen?<\/p>\n<p><strong>2.\u00a0<\/strong>Calculate the energy required to spin flip at 400 MHz. Does changing the frequency to 500 MHz decrease or increase the energy required? What about 300 MHz.<\/p>\n<\/div>\n<div id=\"section_6\">\n<h3>Solutions<\/h3>\n<p id=\"Solutions-61718\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q147150\">Show Answer<\/span><\/p>\n<div id=\"q147150\" class=\"hidden-answer\" style=\"display: none\">\n<p>1. E = h\u03c5 E = (6.62 \u00d7 10\u221234)(150 MHz) E = 9.93 \u00d7 10\u221226 J The energy is equal to 9.93&#215;10-26 J. This value is smaller than the energy required for hydrogen (1.324 \u00d7 10\u221225 J).<\/p>\n<p>2. E = h\u03c5 E = (6.62 \u00d7 10\u221234)(400 MHz) E = 2.648 \u00d7 10\u221225 J The energy would increase if the frequency would increase to 500 MHz, and decrease if the frequency would decrease to 300 MHz. <\/p><\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"section_3\">\n<h3 class=\"editable\">Contributors<\/h3>\n<ul>\n<li><a class=\"external\" title=\"http:\/\/science.athabascau.ca\/staff-pages\/dietmark\" href=\"http:\/\/science.athabascau.ca\/staff-pages\/dietmark\" target=\"_blank\" rel=\"external nofollow noopener\">Dr. Dietmar Kennepohl<\/a> FCIC (Professor of Chemistry, <a class=\"external\" title=\"http:\/\/www.athabascau.ca\/\" href=\"http:\/\/www.athabascau.ca\/\" target=\"_blank\" rel=\"external nofollow noopener\">Athabasca University<\/a>)<\/li>\n<li>Prof. Steven Farmer (<a class=\"external\" title=\"http:\/\/www.sonoma.edu\" href=\"http:\/\/www.sonoma.edu\" target=\"_blank\" rel=\"external nofollow noopener\">Sonoma State University<\/a>)<\/li>\n<li><a class=\"external\" title=\"http:\/\/undergrad-ed.chemistry.ohio-state.edu\/\" href=\"http:\/\/undergrad-ed.chemistry.ohio-state.edu\/\" target=\"_blank\" rel=\"external nofollow noopener\">Dr. Richard Spinney<\/a> <a class=\"external\" title=\"http:\/\/chemistry.osu.edu\/\" href=\"http:\/\/chemistry.osu.edu\/\" target=\"_blank\" rel=\"external nofollow noopener\">(The Ohio State University)<\/a><\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"author":44985,"menu_order":5,"template":"","meta":{"_candela_citation":"[]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1661","chapter","type-chapter","status-publish","hentry"],"part":29,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/1661","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/users\/44985"}],"version-history":[{"count":7,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/1661\/revisions"}],"predecessor-version":[{"id":2347,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/1661\/revisions\/2347"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/parts\/29"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/1661\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/media?parent=1661"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=1661"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/contributor?post=1661"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/license?post=1661"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}