{"id":1859,"date":"2017-10-10T16:08:15","date_gmt":"2017-10-10T16:08:15","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/?post_type=chapter&#038;p=1859"},"modified":"2018-10-05T19:30:02","modified_gmt":"2018-10-05T19:30:02","slug":"chemical-shifts-in-proton-nmr-spectroscopy","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/chapter\/chemical-shifts-in-proton-nmr-spectroscopy\/","title":{"raw":"Chemical Shifts in Proton NMR Spectroscopy","rendered":"Chemical Shifts in Proton NMR Spectroscopy"},"content":{"raw":"<div class=\"elm-header\">\r\n<div class=\"elm-header-custom\">\r\n<div class=\"textbox learning-objectives\">\r\n<h3>Objectives<\/h3>\r\n<div id=\"elm-main-content\" class=\"elm-content-container\">\r\n<div>\r\n<div id=\"skills\">\r\n\r\nAfter completing this section, you should be able to\r\n<ol>\r\n \t<li>state the approximate chemical shift (<em>\u03b4<\/em>) for the following types of protons:\r\n<ol>\r\n \t<li>aromatic.<\/li>\r\n \t<li>vinylic.<\/li>\r\n \t<li>those bonded to carbon atoms which are in turn bonded to a highly electronegative element.<\/li>\r\n \t<li>those bonded to carbons which are next to unsaturated centres.<\/li>\r\n \t<li>those bonded to carbons which are part of a saturated system.<\/li>\r\n<\/ol>\r\n<\/li>\r\n \t<li>predict the approximate chemical shifts of each of the protons in an organic compound, given its structure and a table of chemical shift correlations.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div class=\"elm-header-custom\">\r\n<div class=\"textbox\">\r\n<div class=\"elm-header\">\r\n<h3 class=\"elm-header-custom\">Study Notes<\/h3>\r\n<\/div>\r\n<div id=\"elm-main-content\" class=\"elm-content-container\">\r\n<div>\r\n<div id=\"note\">\r\n\r\nYou should not attempt to memorize the chemical shifts listed <u>in the table of this section<\/u>, although it is probable that you will need to refer to it quite frequently throughout the remainder of this course. To fulfill Objective 1, above, you should be familiar with the information presented in the <u>figure of chemical shift ranges for organic compounds<\/u>. If you have an approximate idea of the chemical shifts of some of the most common types of protons, you will find the interpretation of <sup>1<\/sup>H NMR spectra less arduous than it might otherwise be. Notice that we shall not try to understand why aromatic protons are deshielded or why alkynyl protons are not deshielded as much as vinylic protons. These phenomena can be explained, but the focus is on the interpretation of <sup>1<\/sup>H NMR spectra, not on the underlying theory.\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"elm-main-content\" class=\"elm-content-container\">\r\n<div>\r\n<div id=\"section_1\">\r\n<h3 class=\"editable\"><sup>1<\/sup>H NMR Chemical Shifts<\/h3>\r\nChemical shift is associated with the Larmor frequency of a nuclear spin to its chemical environment. Tetramethylsilan[TMS;(CH<sub>3<\/sub>)<sub>4<\/sub>Si] is generally used for standard to determine chemical shift of compounds: \u03b4<sub>TMS<\/sub>=0ppm. In other words, frequencies for chemicals are measured for a <sup>1<\/sup>H or <sup>13<\/sup>C nucleus of a sample from the <sup>1<\/sup>H or <sup>13<\/sup>C resonance of TMS. It is important to understand trend of chemical shift in terms of NMR interpretation. The proton NMR chemical shift is affect by nearness to electronegative atoms (O, N, halogen.) and unsaturated groups (C=C,C=O, aromatic). Electronegative groups move to the down field (left; increase in ppm). Unsaturated groups shift to downfield (left) when affecting nucleus is in the plane of the unsaturation, but reverse shift takes place in the regions above and below this plane. <sup>1<\/sup>H chemical shift play a role in identifying many functional groups. Figure 1. indicates important example to figure out the functional groups.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"2204\"]<img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143650\/NMR2_Ranges.png\" alt=\"\" width=\"2204\" height=\"782\" \/> Figure 1. H chemical shift ranges for organic compounds[\/caption]\r\n\r\nChemical shift values are in parts per million (ppm) relative to tetramethylsilane.\r\n<table style=\"margin: auto;border-spacing: 0px\" border=\"0\" cellpadding=\"0\">\r\n<tbody>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\"><strong>Hydrogen type<\/strong><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\"><strong>Chemical shift (ppm)<\/strong><\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\">RC<u><strong>H<\/strong><\/u><sub>3<\/sub><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">0.9 - 1.0<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\">RC<u><strong>H<\/strong><\/u><sub>2<\/sub>R<\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">1.2 - 1.7<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\">R<sub>3<\/sub>C<u><strong>H<\/strong><\/u><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">1.5 \u2013 2.0<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td><\/td>\r\n<td>\r\n<p style=\"text-align: center\">2.0 \u2013 2.3<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\"><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143652\/image003.png\" alt=\"image003.png\" width=\"138px\" height=\"75px\" \/><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">1.5 \u2013 1.8<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\">RN<strong><u>H<\/u><\/strong><sub>2<\/sub><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">1 - 3<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\">ArC<strong><u>H<\/u><\/strong><sub>3<\/sub><\/p>\r\n<p style=\"text-align: center\"><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">2.2 \u2013 2.4<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\"><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143653\/image005.png\" alt=\"image005.png\" width=\"139px\" height=\"29px\" \/><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">2.3 \u2013 3.0<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\">ROC<u><strong>H<\/strong><\/u><sub>3<\/sub><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">3.7 \u2013 3.9<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\"><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143655\/image009.png\" alt=\"image009.png\" width=\"140px\" height=\"75px\" \/><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">3.7 \u2013 3.9<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\">RO<strong><u>H<\/u><\/strong><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">1 - 5<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\"><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143656\/image011.png\" alt=\"image011.png\" width=\"113px\" height=\"76px\" \/><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">3.7 \u2013 6.5<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\"><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143657\/image013.png\" alt=\"image013.png\" width=\"120px\" height=\"120px\" \/><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">5 - 9<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\">Ar<strong><u>H<\/u><\/strong><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">6.0 \u2013 8.7<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\"><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143658\/image015.png\" alt=\"image015.png\" width=\"92px\" height=\"88px\" \/><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">9.5 \u2013 10.0<\/p>\r\n<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>\r\n<p style=\"text-align: center\"><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143659\/image017.png\" alt=\"image017.png\" width=\"112px\" height=\"88px\" \/><\/p>\r\n<\/td>\r\n<td>\r\n<p style=\"text-align: center\">10 - 13<\/p>\r\n<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<div><\/div>\r\n<\/div>\r\n<div id=\"section_2\">\r\n<div class=\"textbox exercises\">\r\n<h3>Exercises<\/h3>\r\n<div id=\"section_2\">\r\n<div id=\"s61718\">\r\n<div id=\"section_24\">\r\n\r\n<strong>1.<\/strong>The following have one H<sup>1<\/sup> NMR peak. In each case predict approximately where this peak would be in a spectra.\r\n\r\n<img class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143701\/13.9.png\" alt=\"\" width=\"407\" height=\"303\" \/>\r\n\r\n<b>2.\u00a0<\/b>Identify the different equivalent protons in the following molecule and predict their expected chemical shift.\r\n\r\n<img class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143703\/13.92.png\" alt=\"\" width=\"211\" height=\"155\" \/>\r\n<h3>Solutions<\/h3>\r\n[reveal-answer q=\"717233\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"717233\"]\r\n\r\n1. A. 5.20 \u03b4; B. 1.50 \u03b4; C. 6.40 \u03b4; D. 1.00 \u03b4\r\n\r\n2. There are 6 different protons in this molecule The shifts are (close) to the following: (a) 2 \u03b4; (b) 6 \u03b4; (c) 6.5 \u03b4; (d) 7 \u03b4; (e) 7.5 \u03b4; (f) 7 \u03b4\r\n<img class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143705\/13-9-2sol.png\" alt=\"\" width=\"247\" height=\"193\" \/>[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<h3 class=\"editable\">Contributors<\/h3>\r\n<\/div>\r\n<div id=\"section_3\">\r\n<ul>\r\n \t<li><a class=\"external\" title=\"http:\/\/science.athabascau.ca\/staff-pages\/dietmark\" href=\"http:\/\/science.athabascau.ca\/staff-pages\/dietmark\" target=\"_blank\" rel=\"external nofollow noopener\">Dr. Dietmar Kennepohl<\/a> FCIC (Professor of Chemistry, <a class=\"external\" title=\"http:\/\/www.athabascau.ca\/\" href=\"http:\/\/www.athabascau.ca\/\" target=\"_blank\" rel=\"external nofollow noopener\">Athabasca University<\/a>)<\/li>\r\n \t<li>Prof. Steven Farmer (<a class=\"external\" title=\"http:\/\/www.sonoma.edu\" href=\"http:\/\/www.sonoma.edu\" target=\"_blank\" rel=\"external nofollow noopener\">Sonoma State University<\/a>)<\/li>\r\n \t<li><a title=\"Organic_Chemistry_With_a_Biological_Emphasis\" href=\"https:\/\/chem.libretexts.org\/Textbook_Maps\/Organic_Chemistry_Textbook_Maps\/Map%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)\" rel=\"internal\">Organic Chemistry With a Biological Emphasis <\/a>by\u00a0<a class=\"external\" title=\"http:\/\/facultypages.morris.umn.edu\/~soderbt\/\" href=\"http:\/\/facultypages.morris.umn.edu\/%7Esoderbt\/\" target=\"_blank\" rel=\"external nofollow noopener\">Tim Soderberg<\/a>\u00a0(University of Minnesota, Morris)<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div class=\"elm-header\">\n<div class=\"elm-header-custom\">\n<div class=\"textbox learning-objectives\">\n<h3>Objectives<\/h3>\n<div id=\"elm-main-content\" class=\"elm-content-container\">\n<div>\n<div id=\"skills\">\n<p>After completing this section, you should be able to<\/p>\n<ol>\n<li>state the approximate chemical shift (<em>\u03b4<\/em>) for the following types of protons:\n<ol>\n<li>aromatic.<\/li>\n<li>vinylic.<\/li>\n<li>those bonded to carbon atoms which are in turn bonded to a highly electronegative element.<\/li>\n<li>those bonded to carbons which are next to unsaturated centres.<\/li>\n<li>those bonded to carbons which are part of a saturated system.<\/li>\n<\/ol>\n<\/li>\n<li>predict the approximate chemical shifts of each of the protons in an organic compound, given its structure and a table of chemical shift correlations.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"elm-header-custom\">\n<div class=\"textbox\">\n<div class=\"elm-header\">\n<h3 class=\"elm-header-custom\">Study Notes<\/h3>\n<\/div>\n<div id=\"elm-main-content\" class=\"elm-content-container\">\n<div>\n<div id=\"note\">\n<p>You should not attempt to memorize the chemical shifts listed <u>in the table of this section<\/u>, although it is probable that you will need to refer to it quite frequently throughout the remainder of this course. To fulfill Objective 1, above, you should be familiar with the information presented in the <u>figure of chemical shift ranges for organic compounds<\/u>. If you have an approximate idea of the chemical shifts of some of the most common types of protons, you will find the interpretation of <sup>1<\/sup>H NMR spectra less arduous than it might otherwise be. Notice that we shall not try to understand why aromatic protons are deshielded or why alkynyl protons are not deshielded as much as vinylic protons. These phenomena can be explained, but the focus is on the interpretation of <sup>1<\/sup>H NMR spectra, not on the underlying theory.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"elm-main-content\" class=\"elm-content-container\">\n<div>\n<div id=\"section_1\">\n<h3 class=\"editable\"><sup>1<\/sup>H NMR Chemical Shifts<\/h3>\n<p>Chemical shift is associated with the Larmor frequency of a nuclear spin to its chemical environment. Tetramethylsilan[TMS;(CH<sub>3<\/sub>)<sub>4<\/sub>Si] is generally used for standard to determine chemical shift of compounds: \u03b4<sub>TMS<\/sub>=0ppm. In other words, frequencies for chemicals are measured for a <sup>1<\/sup>H or <sup>13<\/sup>C nucleus of a sample from the <sup>1<\/sup>H or <sup>13<\/sup>C resonance of TMS. It is important to understand trend of chemical shift in terms of NMR interpretation. The proton NMR chemical shift is affect by nearness to electronegative atoms (O, N, halogen.) and unsaturated groups (C=C,C=O, aromatic). Electronegative groups move to the down field (left; increase in ppm). Unsaturated groups shift to downfield (left) when affecting nucleus is in the plane of the unsaturation, but reverse shift takes place in the regions above and below this plane. <sup>1<\/sup>H chemical shift play a role in identifying many functional groups. Figure 1. indicates important example to figure out the functional groups.<\/p>\n<div style=\"width: 2214px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143650\/NMR2_Ranges.png\" alt=\"\" width=\"2204\" height=\"782\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 1. H chemical shift ranges for organic compounds<\/p>\n<\/div>\n<p>Chemical shift values are in parts per million (ppm) relative to tetramethylsilane.<\/p>\n<table style=\"margin: auto;border-spacing: 0px\" cellpadding=\"0\">\n<tbody>\n<tr>\n<td>\n<p style=\"text-align: center\"><strong>Hydrogen type<\/strong><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\"><strong>Chemical shift (ppm)<\/strong><\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\">RC<u><strong>H<\/strong><\/u><sub>3<\/sub><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">0.9 &#8211; 1.0<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\">RC<u><strong>H<\/strong><\/u><sub>2<\/sub>R<\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">1.2 &#8211; 1.7<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\">R<sub>3<\/sub>C<u><strong>H<\/strong><\/u><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">1.5 \u2013 2.0<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>\n<p style=\"text-align: center\">2.0 \u2013 2.3<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\"><img decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143652\/image003.png\" alt=\"image003.png\" width=\"138px\" height=\"75px\" \/><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">1.5 \u2013 1.8<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\">RN<strong><u>H<\/u><\/strong><sub>2<\/sub><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">1 &#8211; 3<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\">ArC<strong><u>H<\/u><\/strong><sub>3<\/sub><\/p>\n<p style=\"text-align: center\">\n<\/td>\n<td>\n<p style=\"text-align: center\">2.2 \u2013 2.4<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\"><img decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143653\/image005.png\" alt=\"image005.png\" width=\"139px\" height=\"29px\" \/><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">2.3 \u2013 3.0<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\">ROC<u><strong>H<\/strong><\/u><sub>3<\/sub><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">3.7 \u2013 3.9<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\"><img decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143655\/image009.png\" alt=\"image009.png\" width=\"140px\" height=\"75px\" \/><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">3.7 \u2013 3.9<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\">RO<strong><u>H<\/u><\/strong><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">1 &#8211; 5<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\"><img decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143656\/image011.png\" alt=\"image011.png\" width=\"113px\" height=\"76px\" \/><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">3.7 \u2013 6.5<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\"><img decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143657\/image013.png\" alt=\"image013.png\" width=\"120px\" height=\"120px\" \/><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">5 &#8211; 9<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\">Ar<strong><u>H<\/u><\/strong><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">6.0 \u2013 8.7<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\"><img decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143658\/image015.png\" alt=\"image015.png\" width=\"92px\" height=\"88px\" \/><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">9.5 \u2013 10.0<\/p>\n<\/td>\n<\/tr>\n<tr>\n<td>\n<p style=\"text-align: center\"><img decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143659\/image017.png\" alt=\"image017.png\" width=\"112px\" height=\"88px\" \/><\/p>\n<\/td>\n<td>\n<p style=\"text-align: center\">10 &#8211; 13<\/p>\n<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<div><\/div>\n<\/div>\n<div id=\"section_2\">\n<div class=\"textbox exercises\">\n<h3>Exercises<\/h3>\n<div id=\"section_2\">\n<div id=\"s61718\">\n<div id=\"section_24\">\n<p><strong>1.<\/strong>The following have one H<sup>1<\/sup> NMR peak. In each case predict approximately where this peak would be in a spectra.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143701\/13.9.png\" alt=\"\" width=\"407\" height=\"303\" \/><\/p>\n<p><b>2.\u00a0<\/b>Identify the different equivalent protons in the following molecule and predict their expected chemical shift.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143703\/13.92.png\" alt=\"\" width=\"211\" height=\"155\" \/><\/p>\n<h3>Solutions<\/h3>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q717233\">Show Answer<\/span><\/p>\n<div id=\"q717233\" class=\"hidden-answer\" style=\"display: none\">\n<p>1. A. 5.20 \u03b4; B. 1.50 \u03b4; C. 6.40 \u03b4; D. 1.00 \u03b4<\/p>\n<p>2. There are 6 different protons in this molecule The shifts are (close) to the following: (a) 2 \u03b4; (b) 6 \u03b4; (c) 6.5 \u03b4; (d) 7 \u03b4; (e) 7.5 \u03b4; (f) 7 \u03b4<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/10143705\/13-9-2sol.png\" alt=\"\" width=\"247\" height=\"193\" \/><\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<h3 class=\"editable\">Contributors<\/h3>\n<\/div>\n<div id=\"section_3\">\n<ul>\n<li><a class=\"external\" title=\"http:\/\/science.athabascau.ca\/staff-pages\/dietmark\" href=\"http:\/\/science.athabascau.ca\/staff-pages\/dietmark\" target=\"_blank\" rel=\"external nofollow noopener\">Dr. Dietmar Kennepohl<\/a> FCIC (Professor of Chemistry, <a class=\"external\" title=\"http:\/\/www.athabascau.ca\/\" href=\"http:\/\/www.athabascau.ca\/\" target=\"_blank\" rel=\"external nofollow noopener\">Athabasca University<\/a>)<\/li>\n<li>Prof. Steven Farmer (<a class=\"external\" title=\"http:\/\/www.sonoma.edu\" href=\"http:\/\/www.sonoma.edu\" target=\"_blank\" rel=\"external nofollow noopener\">Sonoma State University<\/a>)<\/li>\n<li><a title=\"Organic_Chemistry_With_a_Biological_Emphasis\" href=\"https:\/\/chem.libretexts.org\/Textbook_Maps\/Organic_Chemistry_Textbook_Maps\/Map%3A_Organic_Chemistry_with_a_Biological_Emphasis_(Soderberg)\" rel=\"internal\">Organic Chemistry With a Biological Emphasis <\/a>by\u00a0<a class=\"external\" title=\"http:\/\/facultypages.morris.umn.edu\/~soderbt\/\" href=\"http:\/\/facultypages.morris.umn.edu\/%7Esoderbt\/\" target=\"_blank\" rel=\"external nofollow noopener\">Tim Soderberg<\/a>\u00a0(University of Minnesota, Morris)<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"author":44985,"menu_order":9,"template":"","meta":{"_candela_citation":"[]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1859","chapter","type-chapter","status-publish","hentry"],"part":29,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/1859","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/users\/44985"}],"version-history":[{"count":13,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/1859\/revisions"}],"predecessor-version":[{"id":2350,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/1859\/revisions\/2350"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/parts\/29"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/1859\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/media?parent=1859"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=1859"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/contributor?post=1859"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/license?post=1859"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}