{"id":731,"date":"2017-10-24T14:36:20","date_gmt":"2017-10-24T14:36:20","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/?post_type=chapter&#038;p=731"},"modified":"2018-10-03T17:36:31","modified_gmt":"2018-10-03T17:36:31","slug":"geometric-stereoisomers-cistrans","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/chapter\/geometric-stereoisomers-cistrans\/","title":{"raw":"Geometric Stereoisomers (cis\/trans)","rendered":"Geometric Stereoisomers (cis\/trans)"},"content":{"raw":"<div id=\"elm-main-content\" class=\"elm-content-container\">\r\n<div id=\"skills\">\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"boxtitle\">Skills to Develop<\/h3>\r\n<ul>\r\n \t<li>Recognize that alkenes that can exist as cis-trans isomers.<\/li>\r\n \t<li>Classify isomers as cis or trans.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_1\">\r\n<h4 class=\"editable\">Rotation of bonds?<\/h4>\r\nThere is free rotation about the carbon-to-carbon single bonds (C\u2013C) in alkanes. In contrast, the structure of alkenes requires that the carbon atoms of a double bond and the two atoms bonded to each carbon atom all lie in a single plane, and that each doubly bonded carbon atom lies in the center of a triangle. This part of the molecule\u2019s structure is rigid; rotation about doubly bonded carbon atoms is <em class=\"emphasis\">not<\/em> possible without rupturing the bond. Use a molecular model kit to show how single bonds rotate, and double bonds do not rotate without breaking. Look at the two chlorinated hydrocarbons in <em>Table 1<\/em>.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"659\"]<img class=\"internal\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131147\/3D13.2.1.jpg\" alt=\"\" width=\"659\" height=\"233\" \/> <strong>Table 1.<\/strong>\u00a0Rotation about Bonds. In 1,2-dichloroethane (a), free rotation about the C\u2013C bond allows the two structures to be interconverted by a twist of one end relative to the other. In 1,2-dichloroethene (b), restricted rotation about the double bond means that the relative positions of substituent groups above or below the double bond are significant.[\/caption]\r\n\r\nIn 1,2-dichloroethane (part (a) of <strong><em>Table 1<\/em>)<\/strong>, there is free rotation about the C\u2013C bond. The two models shown represent exactly the same molecule; they are <em class=\"emphasis\">not<\/em> isomers. You can draw structural formulas that look different, but if you bear in mind the possibility of this free rotation about single bonds, you should recognize that these two structures represent the same molecule:\r\n<div><img class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131149\/free_rotation.jpg\" alt=\"free rotation.jpg\" width=\"605\" height=\"118\" \/><\/div>\r\n<\/div>\r\n<div id=\"section_2\">\r\n<h4 class=\"editable\">Cis\/trans isomers<\/h4>\r\nIn 1,2-dichloroethene <em><strong>T<\/strong><\/em><strong><em>able 1<\/em><\/strong>, however, restricted rotation about the double bond means that the relative positions of substituent groups above or below the double bond become significant. This leads to a special kind of isomerism. The isomer in which the two chlorine (Cl) atoms lie on the same side of the molecule is called the <strong>cis isomer<\/strong> (Latin <em class=\"emphasis\">cis<\/em>, meaning \u201con this side\u201d) and is named cis-1,2-dichloroethene. The isomer with the two Cl atoms on opposite sides of the molecule is the <strong>trans isomer<\/strong> (Latin <em class=\"emphasis\">trans<\/em>, meaning \u201cacross\u201d) and is named <em class=\"emphasis\">trans<\/em>-1,2-dichloroethene. These two compounds are c<strong>is<\/strong><strong>-trans isomers<\/strong>, compounds that have different configurations (groups permanently in different places in space) because of the presence of a rigid structure in their molecule.\r\n\r\nConsider the alkene with the condensed structural formula CH<sub class=\"subscript\">3<\/sub>CH=CHCH<sub class=\"subscript\">3<\/sub>. We could name it 2-butene, but there are actually two such compounds; the double bond results in cis-trans isomerism <em><strong>Figure 2<\/strong><\/em>.\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"443\"]<img class=\"internal\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131151\/13.2.2.jpg\" alt=\"\" width=\"443\" height=\"168\" \/> <em><strong>Figure 2<\/strong><\/em>: Ball-and-Spring Models of (a) Cis-2-Butene and (b) Trans-2-Butene. Cis-trans isomers have different physical, chemical, and physiological properties.[\/caption]\r\n<p class=\"pach13_s02_p05\"><em class=\"emphasis\">Cis<\/em>-2-butene has both methyl groups on the same side of the molecule. <em class=\"emphasis\">Trans<\/em>-2-butene has the methyl groups on opposite sides of the molecule. Their structural formulas are as follows:<\/p>\r\n\r\n<div class=\"informalfigure large block\">\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"544\"]<img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131153\/cis2C_trans.jpg\" alt=\"cis, trans.jpg\" width=\"544\" height=\"133\" \/> <em><strong>Figure 3<\/strong><\/em>:\u00a0Models of (left) Cis-2-Butene and (right) Trans-2-Butene.[\/caption]\r\n\r\n<\/div>\r\n<div class=\"informalfigure large block\"><\/div>\r\n<p class=\"pach13_s02_p06\">Note, however, that the presence of a double bond does <strong>not <\/strong>necessarily lead to cis-trans isomerism (<em><strong>Figure 4<\/strong><\/em>). We can draw two <em class=\"emphasis\">seemingly<\/em> different propenes:<\/p>\r\n\r\n<div class=\"informalfigure large block\">\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"598\"]<img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131155\/propene.jpg\" alt=\"propene.jpg\" width=\"598\" height=\"102\" \/> <em><strong>Figure 4:<\/strong><\/em>\u00a0Different views of the propene molecule (flip vertically). These are not isomers.[\/caption]\r\n\r\n<\/div>\r\n<div class=\"informalfigure large block\"><\/div>\r\n<p class=\"pach13_s02_p08\">However, these two structures are not really different from each other. If you could pick up either molecule from the page and flip it over top to bottom, you would see that the two formulas are identical.<\/p>\r\n\r\n<\/div>\r\n<div id=\"section_3\">\r\n<div class=\"textbox exercises\">\r\n<h3>Exercises<\/h3>\r\n<h3>Questions<\/h3>\r\n<div id=\"section_3\">\r\n<div id=\"gob-ch13_s02_qs02\" class=\"qandaset block\">\r\n<ol id=\"gob-ch13_s02_qs02_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch13_s02_qs02_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch13_s02_qs02_p01\" class=\"para\">What are cis-trans isomers?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch13_s02_qs02_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch13_s02_qs02_p03\" class=\"para\">Classify each compound as a cis isomer, a trans isomer, or neither.<\/p>\r\n\r\n<ol id=\"gob-ch13_s02_qs02_l01\" class=\"orderedlist\" start=\"1\">\r\n \t<li>\r\n<div class=\"informalfigure large\"><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131203\/2a.jpg\" alt=\"2a.jpg\" width=\"600px\" height=\"105px\" \/><\/div><\/li>\r\n \t<li>\r\n<div class=\"informalfigure large\"><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131206\/2b.jpg\" alt=\"2b.jpg\" width=\"600px\" height=\"99px\" \/><\/div><\/li>\r\n \t<li>\r\n<div class=\"informalfigure large\"><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131208\/2c.jpg\" alt=\"2c.jpg\" width=\"600px\" height=\"106px\" \/><\/div><\/li>\r\n \t<li>\r\n<div class=\"informalfigure large\"><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131211\/2d.jpg\" alt=\"2d.jpg\" width=\"600px\" height=\"144px\" \/><\/div><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_4\">\r\n<h4 class=\"editable\">Answers<\/h4>\r\n<p class=\"editable\">[reveal-answer q=\"963513\"]Show Answer[\/reveal-answer][hidden-answer a=\"963513\"]<\/p>\r\n\r\n<ol>\r\n \t<li class=\"editable\">Cis-trans isomers are compounds that have different configurations (groups permanently in different places in space) because of the inability of the double bond to rotate.<\/li>\r\n<\/ol>\r\n<div class=\"answer\">\r\n<p class=\"para\">2. 1. trans (the two hydrogen atoms are on opposite sides)<\/p>\r\n<p class=\"para\">\u00a0 \u00a0 2. cis (the two hydrogen atoms are on the same side, as are the two ethyl groups)<\/p>\r\n<p class=\"para\">\u00a0 \u00a0 3.cis (the two ethyl groups are on the same side)<\/p>\r\n<p class=\"para\">\u00a0 \u00a0 4.neither (fliping the bond does not change the molecule. There are no isomers for this molecule)[\/hidden-answer]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_5\"><\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_5\">\r\n<div class=\"textbox key-takeaways\">\r\n<h3 class=\"editable\">Key Takeaway<\/h3>\r\n<ul id=\"gob-ch13_s02_l10\" class=\"itemizedlist\">\r\n \t<li>Cis-trans isomers are different molecules of the same formula, with different properties, differing structurally only with the placement of groups around the double bond.<\/li>\r\n<\/ul>\r\n<\/div>\r\n&nbsp;\r\n\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"elm-main-content\" class=\"elm-content-container\">\n<div id=\"skills\">\n<div class=\"textbox shaded\">\n<h3 class=\"boxtitle\">Skills to Develop<\/h3>\n<ul>\n<li>Recognize that alkenes that can exist as cis-trans isomers.<\/li>\n<li>Classify isomers as cis or trans.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div id=\"section_1\">\n<h4 class=\"editable\">Rotation of bonds?<\/h4>\n<p>There is free rotation about the carbon-to-carbon single bonds (C\u2013C) in alkanes. In contrast, the structure of alkenes requires that the carbon atoms of a double bond and the two atoms bonded to each carbon atom all lie in a single plane, and that each doubly bonded carbon atom lies in the center of a triangle. This part of the molecule\u2019s structure is rigid; rotation about doubly bonded carbon atoms is <em class=\"emphasis\">not<\/em> possible without rupturing the bond. Use a molecular model kit to show how single bonds rotate, and double bonds do not rotate without breaking. Look at the two chlorinated hydrocarbons in <em>Table 1<\/em>.<\/p>\n<div style=\"width: 669px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"internal\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131147\/3D13.2.1.jpg\" alt=\"\" width=\"659\" height=\"233\" \/><\/p>\n<p class=\"wp-caption-text\"><strong>Table 1.<\/strong>\u00a0Rotation about Bonds. In 1,2-dichloroethane (a), free rotation about the C\u2013C bond allows the two structures to be interconverted by a twist of one end relative to the other. In 1,2-dichloroethene (b), restricted rotation about the double bond means that the relative positions of substituent groups above or below the double bond are significant.<\/p>\n<\/div>\n<p>In 1,2-dichloroethane (part (a) of <strong><em>Table 1<\/em>)<\/strong>, there is free rotation about the C\u2013C bond. The two models shown represent exactly the same molecule; they are <em class=\"emphasis\">not<\/em> isomers. You can draw structural formulas that look different, but if you bear in mind the possibility of this free rotation about single bonds, you should recognize that these two structures represent the same molecule:<\/p>\n<div><img loading=\"lazy\" decoding=\"async\" class=\"internal default aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131149\/free_rotation.jpg\" alt=\"free rotation.jpg\" width=\"605\" height=\"118\" \/><\/div>\n<\/div>\n<div id=\"section_2\">\n<h4 class=\"editable\">Cis\/trans isomers<\/h4>\n<p>In 1,2-dichloroethene <em><strong>T<\/strong><\/em><strong><em>able 1<\/em><\/strong>, however, restricted rotation about the double bond means that the relative positions of substituent groups above or below the double bond become significant. This leads to a special kind of isomerism. The isomer in which the two chlorine (Cl) atoms lie on the same side of the molecule is called the <strong>cis isomer<\/strong> (Latin <em class=\"emphasis\">cis<\/em>, meaning \u201con this side\u201d) and is named cis-1,2-dichloroethene. The isomer with the two Cl atoms on opposite sides of the molecule is the <strong>trans isomer<\/strong> (Latin <em class=\"emphasis\">trans<\/em>, meaning \u201cacross\u201d) and is named <em class=\"emphasis\">trans<\/em>-1,2-dichloroethene. These two compounds are c<strong>is<\/strong><strong>-trans isomers<\/strong>, compounds that have different configurations (groups permanently in different places in space) because of the presence of a rigid structure in their molecule.<\/p>\n<p>Consider the alkene with the condensed structural formula CH<sub class=\"subscript\">3<\/sub>CH=CHCH<sub class=\"subscript\">3<\/sub>. We could name it 2-butene, but there are actually two such compounds; the double bond results in cis-trans isomerism <em><strong>Figure 2<\/strong><\/em>.<\/p>\n<div style=\"width: 453px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"internal\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131151\/13.2.2.jpg\" alt=\"\" width=\"443\" height=\"168\" \/><\/p>\n<p class=\"wp-caption-text\"><em><strong>Figure 2<\/strong><\/em>: Ball-and-Spring Models of (a) Cis-2-Butene and (b) Trans-2-Butene. Cis-trans isomers have different physical, chemical, and physiological properties.<\/p>\n<\/div>\n<p class=\"pach13_s02_p05\"><em class=\"emphasis\">Cis<\/em>-2-butene has both methyl groups on the same side of the molecule. <em class=\"emphasis\">Trans<\/em>-2-butene has the methyl groups on opposite sides of the molecule. Their structural formulas are as follows:<\/p>\n<div class=\"informalfigure large block\">\n<div style=\"width: 554px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131153\/cis2C_trans.jpg\" alt=\"cis, trans.jpg\" width=\"544\" height=\"133\" \/><\/p>\n<p class=\"wp-caption-text\"><em><strong>Figure 3<\/strong><\/em>:\u00a0Models of (left) Cis-2-Butene and (right) Trans-2-Butene.<\/p>\n<\/div>\n<\/div>\n<div class=\"informalfigure large block\"><\/div>\n<p class=\"pach13_s02_p06\">Note, however, that the presence of a double bond does <strong>not <\/strong>necessarily lead to cis-trans isomerism (<em><strong>Figure 4<\/strong><\/em>). We can draw two <em class=\"emphasis\">seemingly<\/em> different propenes:<\/p>\n<div class=\"informalfigure large block\">\n<div style=\"width: 608px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131155\/propene.jpg\" alt=\"propene.jpg\" width=\"598\" height=\"102\" \/><\/p>\n<p class=\"wp-caption-text\"><em><strong>Figure 4:<\/strong><\/em>\u00a0Different views of the propene molecule (flip vertically). These are not isomers.<\/p>\n<\/div>\n<\/div>\n<div class=\"informalfigure large block\"><\/div>\n<p class=\"pach13_s02_p08\">However, these two structures are not really different from each other. If you could pick up either molecule from the page and flip it over top to bottom, you would see that the two formulas are identical.<\/p>\n<\/div>\n<div id=\"section_3\">\n<div class=\"textbox exercises\">\n<h3>Exercises<\/h3>\n<h3>Questions<\/h3>\n<div id=\"section_3\">\n<div id=\"gob-ch13_s02_qs02\" class=\"qandaset block\">\n<ol id=\"gob-ch13_s02_qs02_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch13_s02_qs02_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch13_s02_qs02_p01\" class=\"para\">What are cis-trans isomers?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch13_s02_qs02_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch13_s02_qs02_p03\" class=\"para\">Classify each compound as a cis isomer, a trans isomer, or neither.<\/p>\n<ol id=\"gob-ch13_s02_qs02_l01\" class=\"orderedlist\" start=\"1\">\n<li>\n<div class=\"informalfigure large\"><img decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131203\/2a.jpg\" alt=\"2a.jpg\" width=\"600px\" height=\"105px\" \/><\/div>\n<\/li>\n<li>\n<div class=\"informalfigure large\"><img decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131206\/2b.jpg\" alt=\"2b.jpg\" width=\"600px\" height=\"99px\" \/><\/div>\n<\/li>\n<li>\n<div class=\"informalfigure large\"><img decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131208\/2c.jpg\" alt=\"2c.jpg\" width=\"600px\" height=\"106px\" \/><\/div>\n<\/li>\n<li>\n<div class=\"informalfigure large\"><img decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1518\/2017\/10\/05131211\/2d.jpg\" alt=\"2d.jpg\" width=\"600px\" height=\"144px\" \/><\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div id=\"section_4\">\n<h4 class=\"editable\">Answers<\/h4>\n<p class=\"editable\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q963513\">Show Answer<\/span><\/p>\n<div id=\"q963513\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li class=\"editable\">Cis-trans isomers are compounds that have different configurations (groups permanently in different places in space) because of the inability of the double bond to rotate.<\/li>\n<\/ol>\n<div class=\"answer\">\n<p class=\"para\">2. 1. trans (the two hydrogen atoms are on opposite sides)<\/p>\n<p class=\"para\">\u00a0 \u00a0 2. cis (the two hydrogen atoms are on the same side, as are the two ethyl groups)<\/p>\n<p class=\"para\">\u00a0 \u00a0 3.cis (the two ethyl groups are on the same side)<\/p>\n<p class=\"para\">\u00a0 \u00a0 4.neither (fliping the bond does not change the molecule. There are no isomers for this molecule)<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"section_5\"><\/div>\n<\/div>\n<\/div>\n<div id=\"section_5\">\n<div class=\"textbox key-takeaways\">\n<h3 class=\"editable\">Key Takeaway<\/h3>\n<ul id=\"gob-ch13_s02_l10\" class=\"itemizedlist\">\n<li>Cis-trans isomers are different molecules of the same formula, with different properties, differing structurally only with the placement of groups around the double bond.<\/li>\n<\/ul>\n<\/div>\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n","protected":false},"author":44985,"menu_order":1,"template":"","meta":{"_candela_citation":"[]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-731","chapter","type-chapter","status-publish","hentry"],"part":22,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/731","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/users\/44985"}],"version-history":[{"count":5,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/731\/revisions"}],"predecessor-version":[{"id":2254,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/731\/revisions\/2254"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/parts\/22"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/731\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/media?parent=731"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=731"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/contributor?post=731"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/wp-json\/wp\/v2\/license?post=731"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}