{"id":960,"date":"2017-10-19T15:03:12","date_gmt":"2017-10-19T15:03:12","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/?post_type=chapter&p=960"},"modified":"2018-10-03T19:32:10","modified_gmt":"2018-10-03T19:32:10","slug":"naming-alkenes","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-mcc-organicchemistry\/chapter\/naming-alkenes\/","title":{"raw":"Naming Alkenes","rendered":"Naming Alkenes"},"content":{"raw":"
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Objectives<\/h3>\r\n
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\r\n\r\nAfter completing this section, you should be able to\r\n
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  1. provide the correct IUPAC name for an acyclic or cyclic alkene, given its Kekul\u00e9, condensed or shorthand structure.<\/li>\r\n \t
  2. draw the Kekul\u00e9, condensed or shorthand structure of an alkene (cyclic or acyclic), given its IUPAC name.<\/li>\r\n \t
  3. give the IUPAC equivalent of the following trivial names: ethylene, propylene, isobutylene and isoprene.<\/li>\r\n \t
  4. draw the structure of a vinyl (ethenyl) and allyl (2-propenyl) group, and use these names in alkene nomenclature.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n
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    Study Notes<\/h3>\r\nThis course uses IUPAC nomenclature; therefore, you need not usually memorize a large number of trivial names. However, you will encounter some trivial names so frequently in books and articles that they soon become familiar.\r\n\r\nAn alkene that can exhibit geometric isomerism has not been properly named unless its name specifies whether the double bond (or bonds) is (or are) cis or trans. The most effective way of giving this information is discussed, and more details of cis and trans follow in Section 7.4.\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\nAlkenes contain carbon-carbon double bonds and are unsaturated<\/a> hydrocarbons with the molecular formula is Cn<\/sub>H2n<\/sub>. This is also the same molecular formula as cycloalkanes<\/a>. Alkenes are named by dropping the -ane ending of the parent and adding -ene.\r\n\r\n<\/div>\r\n
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    Introduction<\/h3>\r\nThe parent structure is the longest chain containing both carbon atoms of the double bond. The two carbon atoms of a double bond and the four atoms attached to them lie in a plane, with bond angles of approximately 120\u00b0 A double bond consists of one sigma bond formed by overlap of sp2<\/sup>hybrid orbitals<\/span><\/a> and one pi bond formed by overlap of parallel 2 p orbitals\r\n\r\n\"alkene7.png\"\r\n\r\n<\/div>\r\n
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    The Basic Rules<\/h3>\r\nFor straight chain alkenes, it is the same basic rules as nomenclature of alkanes<\/a> except change the suffix to \"-ene.\"\r\n
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    1. Find the Longest Carbon Chain that Contains the Carbon Carbon double bond. If you have two ties for longest Carbon chain, and both chains contain a Carbon Carbon double bond, then identify the most substituted chain.<\/li>\r\n \t
    2. Give the lowest possible number to the Carbon Carbon double bond.\r\n