{"id":1161,"date":"2018-03-21T14:36:07","date_gmt":"2018-03-21T14:36:07","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/chapter\/cis-trans-isomers-geometric-isomers\/"},"modified":"2018-10-22T21:05:09","modified_gmt":"2018-10-22T21:05:09","slug":"cis-trans-isomers-geometric-isomers","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/chapter\/cis-trans-isomers-geometric-isomers\/","title":{"raw":"13.2 Cis-Trans Isomers (Geometric Isomers)","rendered":"13.2 Cis-Trans Isomers (Geometric Isomers)"},"content":{"raw":"<div id=\"navbar-top\" class=\"navbar\">\r\n<div class=\"navbar-part left\"><\/div>\r\n<\/div>\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch13_s02\" class=\"section\" xml:lang=\"en\">\r\n<div id=\"gob-ch13_s02_n01\" class=\"learning_objectives editable block\">\r\n<div class=\"textbox learning-objectives\">\r\n<h3>Learning Objectives<\/h3>\r\n<ol id=\"gob-ch13_s02_l01\" class=\"orderedlist\">\r\n \t<li>Recognize that alkenes that can exist as cis-trans isomers.<\/li>\r\n \t<li>Classify isomers as cis or trans.<\/li>\r\n \t<li>Draw structures for cis-trans isomers given their names.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<p id=\"gob-ch13_s02_p01\" class=\"para editable block\">As noted in <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-12\">Chapter 12 \"Organic Chemistry: Alkanes and Halogenated Hydrocarbons\"<\/a>, there is free rotation about the carbon-to-carbon single bonds (C\u2013C) in alkanes. In contrast, the structure of alkenes requires that the carbon atoms of a double bond and the two atoms bonded to each carbon atom all lie in a single plane, and that each doubly bonded carbon atom lies in the center of a triangle. This part of the molecule\u2019s structure is rigid; rotation about doubly bonded carbon atoms is <em class=\"emphasis\">not<\/em> possible without rupturing the bond. Look at the two chlorinated hydrocarbons in <a class=\"xref\" href=\"#gob-ch13_s02_f01\">Figure 13.2 \"Rotation about Bonds\"<\/a>.<\/p>\r\n\r\n<div id=\"gob-ch13_s02_f01\" class=\"figure large medium-height editable block\">\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"1028\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143516\/8ce2ef9b7324b1fddc98c74e71a5f9ef.jpg\" alt=\"image\" width=\"1028\" height=\"1409\" \/> Figure 13.2 Rotation about Bonds. In 1,2-dichloroethane (a), free rotation about the C\u2013C bond allows the two structures to be interconverted by a twist of one end relative to the other. In 1,2-dichloroethene (b), restricted rotation about the double bond means that the relative positions of substituent groups above or below the double bond are significant.[\/caption]\r\n\r\n<\/div>\r\n<p id=\"gob-ch13_s02_p02\" class=\"para editable block\">In 1,2-dichloroethane (part (a) of <a class=\"xref\" href=\"#gob-ch13_s02_f01\">Figure 13.2 \"Rotation about Bonds\"<\/a>), there is free rotation about the C\u2013C bond. The two models shown represent exactly the same molecule; they are <em class=\"emphasis\">not<\/em> isomers. You can draw structural formulas that look different, but if you bear in mind the possibility of this free rotation about single bonds, you should recognize that these two structures represent the same molecule:<\/p>\r\n\r\n<div class=\"informalfigure large block\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143519\/41f95e8e2c9df3d0abf8d3db2a6bc2a4.jpg\" alt=\"image\" \/><\/div>\r\n<p id=\"gob-ch13_s02_p03\" class=\"para editable block\">In 1,2-dichloroethene (part (b) of <a class=\"xref\" href=\"#gob-ch13_s02_f01\">Figure 13.2 \"Rotation about Bonds\"<\/a>), however, restricted rotation about the double bond means that the relative positions of substituent groups above or below the double bond become significant. This leads to a special kind of isomerism.\u00a0<span class=\"margin_term\"> <span class=\"glossdef\">An isomer in which two substituent groups are attached on the same side of a double bond or ring in an organic molecule is called a <strong>cis- isomer<\/strong>.<\/span><\/span> (Latin <em class=\"emphasis\">cis<\/em>, meaning \u201con this side\u201d) The molecule shown with two chlorine atoms on the same side of the double bond is named cis-1,2-dichloroethene. \u00a0<span class=\"margin_term\"><span class=\"glossdef\">An isomer in which two substituent groups are attached to opposite sides of a double bond or ring in a molecule is called a <strong>trans isomer.\u00a0 <\/strong><\/span><\/span>(Latin <em class=\"emphasis\">trans<\/em>, meaning \u201cacross\u201d) The isomer with the two Cl atoms on opposite sides of the molecule is named <em class=\"emphasis\">trans<\/em>-1,2-dichloroethene. These two compounds are <span class=\"margin_term\"><span class=\"glossterm\">cis-trans isomers (or geometric isomers).\u00a0 T<\/span><span class=\"glossdef\">he presence of a rigid structure such as a double bond or ring.<\/span><\/span>, compounds is necessary for cis-\/trans isomerism.\u00a0 Note that cis and trans isomers are different compounds with distinct physical and chemical properties.<\/p>\r\n<p id=\"gob-ch13_s02_p04\" class=\"para editable block\">Consider the alkene with the condensed structural formula CH<sub class=\"subscript\">3<\/sub>CH=CHCH<sub class=\"subscript\">3<\/sub>. We could name it 2-butene, but there are actually two such compounds; the double bond results in cis-trans isomerism (<a class=\"xref\" href=\"#gob-ch13_s02_f02\">Figure 13.3 \"Ball-and-Spring Models of (a) Cis-2-Butene and (b) Trans-2-Butene\"<\/a>).<\/p>\r\n\r\n<div id=\"gob-ch13_s02_f02\" class=\"figure large editable block\">\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"1333\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143522\/27419743a4c4ea46e76261ef7a760b5b.jpg\" alt=\"image\" width=\"1333\" height=\"557\" \/> Figure 13.3 Ball-and-Spring Models of (a) Cis-2-Butene and (b) Trans-2-Butene.\u00a0Cis-trans isomers have different physical, chemical, and physiological properties.[\/caption]\r\n\r\n<\/div>\r\n<p id=\"gob-ch13_s02_p05\" class=\"para editable block\"><em class=\"emphasis\">Cis<\/em>-2-butene has both methyl groups on the same side of the molecule. <em class=\"emphasis\">Trans<\/em>-2-butene has the methyl groups on opposite sides of the molecule. Their structural formulas are as follows:<\/p>\r\n\r\n<div class=\"informalfigure large block\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143525\/bcc8673ce6ab3f54d54f951023a68458.jpg\" alt=\"image\" \/><\/div>\r\n<p id=\"gob-ch13_s02_p06\" class=\"para editable block\">Note, however, that the presence of a double bond does not necessarily lead to cis-trans isomerism. We can draw two <em class=\"emphasis\">seemingly<\/em> different propenes:<\/p>\r\n\r\n<div class=\"informalfigure large block\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143528\/e5d2d78a636ba67a9cbbe6712c6d7d0b.jpg\" alt=\"image\" \/><\/div>\r\n<p id=\"gob-ch13_s02_p07\" class=\"para editable block\">However, these two structures are not really different from each other. If you could pick up either molecule from the page and flip it over top to bottom, you would see that the two formulas are identical.<\/p>\r\n<p id=\"gob-ch13_s02_p08\" class=\"para editable block\">Thus there are two requirements for cis-trans isomerism:<\/p>\r\n\r\n<ol id=\"gob-ch13_s02_l02\" class=\"orderedlist editable block\">\r\n \t<li>Rotation must be restricted in the molecule.<\/li>\r\n \t<li>There must be two nonidentical groups on <em class=\"emphasis\">each<\/em> doubly bonded carbon atom.<\/li>\r\n<\/ol>\r\n<p id=\"gob-ch13_s02_p09\" class=\"para editable block\">In these propene structures, the second requirement for cis-trans isomerism is not fulfilled. One of the doubly bonded carbon atoms does have two different groups attached, but the rules require that <em class=\"emphasis\">both<\/em> carbon atoms have two different groups.<\/p>\r\n<p id=\"gob-ch13_s02_p10\" class=\"para editable block\">In general, the following statements hold true in cis-trans isomerism:<\/p>\r\n\r\n<ul id=\"gob-ch13_s02_l03\" class=\"itemizedlist editable block\">\r\n \t<li>Alkenes with a C=CH<sub class=\"subscript\">2<\/sub> unit do not exist as cis-trans isomers.<\/li>\r\n \t<li>Alkenes with a C=CR<sub class=\"subscript\">2<\/sub> unit, where the two R groups are the same, do not exist as cis-trans isomers.<\/li>\r\n \t<li>Alkenes of the type R\u2013CH=CH\u2013R can exist as cis and trans isomers; cis if the two R groups are on the same side of the carbon-to-carbon double bond, and trans if the two R groups are on opposite sides of the carbon-to-carbon double bond.<\/li>\r\n<\/ul>\r\n<p id=\"gob-ch13_s02_p11\" class=\"para editable block\">Cis-trans isomerism also occurs in cyclic compounds. In ring structures, groups are unable to rotate about any of the ring carbon\u2013carbon bonds. Therefore, groups can be either on the same side of the ring (cis) or on opposite sides of the ring (trans). For our purposes here, we represent all cycloalkanes as planar structures, and we indicate the positions of the groups, either above or below the plane of the ring.<\/p>\r\n\r\n<div class=\"informalfigure large block\"><img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143531\/e1940700b64b899e90e00a80a33e9a2f.jpg\" alt=\"image\" \/><\/div>\r\n<div id=\"gob-ch13_s02_n02\" class=\"exercises editable block\">\r\n<h3 class=\"title\">Example 3<\/h3>\r\n<p id=\"gob-ch13_s02_p12\" class=\"para\">Which compounds can exist as cis-trans (geometric) isomers? Draw them.<\/p>\r\n\r\n<ol id=\"gob-ch13_s02_l04\" class=\"orderedlist\">\r\n \t<li>CHCl=CHBr<\/li>\r\n \t<li>CH<sub class=\"subscript\">2<\/sub>=CBrCH<sub class=\"subscript\">3<\/sub><\/li>\r\n \t<li>(CH<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>C=CHCH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub><\/li>\r\n \t<li>CH<sub class=\"subscript\">3<\/sub>CH=CHCH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub><\/li>\r\n<\/ol>\r\n<p class=\"simpara\">[reveal-answer q=\"136727\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"136727\"]<\/p>\r\n<p class=\"simpara\">All four structures have a double bond and thus meet rule 1 for cis-trans isomerism.<\/p>\r\n<p class=\"simpara\">1. This compound meets rule 2; it has two nonidentical groups on each carbon atom (H and Cl on one and H and Br on the other). It exists as both cis and trans isomers:<img style=\"font-size: 1em\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143534\/55bc5569d86c404436cae7b6ff1847da.jpg\" alt=\"image\" \/><\/p>\r\n2. This compound has two hydrogen atoms on one of its doubly bonded carbon atoms; it fails rule 2 and does not exist as cis and trans isomers.\r\n\r\n3. This compound has two methyl (CH<sub class=\"subscript\">3<\/sub>) groups on one of its doubly bonded carbon atoms. It fails rule 2 and does not exist as cis and trans isomers.\r\n<p class=\"para\">4. This compound meets rule 2; it has two nonidentical groups on <em class=\"emphasis\">each<\/em> carbon atom and exists as both cis and trans isomers:<\/p>\r\n\r\n<div class=\"informalfigure large\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143537\/456f8aaa42d41d3ddeedcd1e74c59d1a.jpg\" alt=\"image\" \/>\u00a0[\/hidden-answer]<\/div>\r\n<\/div>\r\n<div id=\"gob-ch13_s02_qs01\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<div id=\"gob-ch13_s02_qs01\" class=\"qandaset block\">\r\n<h3 class=\"title\">Skill-Building Exercise<\/h3>\r\n<div class=\"question\">\r\n<p id=\"gob-ch13_s02_qs01_p01\" class=\"para\">1. Which compounds can exist as cis-trans isomers? Draw them.<\/p>\r\n\r\n<\/div>\r\na. CH<sub class=\"subscript\">2<\/sub>=CHCH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub>\r\n\r\nb. CH<sub class=\"subscript\">3<\/sub>CH=CHCH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub>\r\n\r\nc. CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH=CHCH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub>\r\n<div class=\"informalfigure large\">d.\u00a0<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143540\/59e80798de70b739b0c8e4f2c5051f65.jpg\" alt=\"image\" \/><\/div>\r\n<div class=\"informalfigure large\">e.\u00a0<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143542\/cc2bacbaeec8ad121e37ef530e7ea4c3.jpg\" alt=\"image\" \/><\/div>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<div id=\"gob-ch13_s02_qs01\" class=\"qandaset block\">\r\n<h3 class=\"title\">Concept Review Exercises<\/h3>\r\n<\/div>\r\n<div id=\"gob-ch13_s02_qs02\" class=\"qandaset block\">\r\n<ol id=\"gob-ch13_s02_qs02_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch13_s02_qs02_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch13_s02_qs02_p01\" class=\"para\">What are cis-trans (geometric) isomers? What two types of compounds can exhibit cis-trans isomerism?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch13_s02_qs02_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch13_s02_qs02_p03\" class=\"para\">Classify each compound as a cis isomer, a trans isomer, or neither.<\/p>\r\n\r\n<ol id=\"gob-ch13_s02_qs02_l01\" class=\"orderedlist\">\r\n \t<li>\r\n<div class=\"informalfigure large\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143546\/6e7abe999980c806f82c5935244b807c.jpg\" alt=\"image\" \/><\/div><\/li>\r\n \t<li>\r\n<div class=\"informalfigure large\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143548\/016dc6eea5f3ed34c0636f026475baa6.jpg\" alt=\"image\" \/><\/div><\/li>\r\n \t<li>\r\n<div class=\"informalfigure large\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143552\/6f4d0db663885ee6c499924970749b97.jpg\" alt=\"image\" \/><\/div><\/li>\r\n \t<li>\r\n<div class=\"informalfigure large\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143557\/7aec26f72a319418bb7402f0df3ff179.jpg\" alt=\"image\" \/><\/div><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch13_s02_qs02_ans\" class=\"qandaset block\">\r\n<div class=\"answer\">\r\n<p id=\"gob-ch13_s02_qs02_p02_ans\" class=\"para\">[reveal-answer q=\"337096\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"337096\"]1. Cis-trans isomers are compounds that have different configurations (groups permanently in different places in space) because of the presence of a rigid structure in their molecule. Alkenes and cyclic compounds can exhibit cis-trans isomerism.<\/p>\r\n<p class=\"para\">2. a.trans\u00a0 b. cis\u00a0 c. cis\u00a0 d. neither\u00a0[\/hidden-answer]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox key-takeaways\">\r\n<div id=\"gob-ch13_s02_qs01\" class=\"qandaset block\">\r\n<h3 class=\"title\">Key Takeaway<\/h3>\r\n<\/div>\r\n<div id=\"gob-ch13_s02_n05\" class=\"key_takeaways editable block\">\r\n<ul id=\"gob-ch13_s02_l10\" class=\"itemizedlist\">\r\n \t<li>Cis-trans (geometric) isomerism exists when there is restricted rotation in a molecule and there are two nonidentical groups on <em class=\"emphasis\">each<\/em> doubly bonded carbon atom.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch13_s02_qs03\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch13_s02\" class=\"section\" xml:lang=\"en\">\r\n<div id=\"gob-ch13_s02_qs03\" class=\"qandaset block\">\r\n<h3 class=\"title\">Exercises<\/h3>\r\n<ol id=\"gob-ch13_s02_qs03_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch13_s02_qs03_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch13_s02_qs03_p01\" class=\"para\">Draw the structures of the cis-trans isomers for each compound. Label them cis and trans. If no cis-trans isomers exist, write none.<\/p>\r\n\r\n<ol id=\"gob-ch13_s02_qs03_l01\" class=\"orderedlist\">\r\n \t<li>2-bromo-2-pentene<\/li>\r\n \t<li>3-heptene<\/li>\r\n \t<li>4-methyl-2-pentene<\/li>\r\n \t<li>1,1-dibromo-1-butene<\/li>\r\n \t<li>2-butenoic acid (CH<sub class=\"subscript\">3<\/sub>CH=CHCOOH)<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch13_s02_qs03_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch13_s02_qs03_p02\" class=\"para\">Draw the structures of the cis-trans isomers for each compound. Label them cis and trans. If no cis-trans isomers exist, write none.<\/p>\r\n\r\n<ol id=\"gob-ch13_s02_qs03_l03\" class=\"orderedlist\">\r\n \t<li>2,3-dimethyl-2-pentene<\/li>\r\n \t<li>1,1-dimethyl-2-ethylcyclopropane<\/li>\r\n \t<li>1,2-dimethylcyclohexane<\/li>\r\n \t<li>5-methyl-2-hexene<\/li>\r\n \t<li>1,2,3-trimethylcyclopropane<\/li>\r\n<\/ol>\r\n<\/div>\r\n&nbsp;<\/li>\r\n<\/ol>\r\n<\/div>\r\n[reveal-answer q=\"321781\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"321781\"]1.\r\n\r\na.\u00a0<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143600\/49b77e14f1a593612c72d43c42a9f409.jpg\" alt=\"image\" \/>\r\n<div id=\"gob-ch13_s02_qs03_ans\" class=\"qandaset block\">\r\n<div class=\"informalfigure large\">b.\u00a0<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143602\/052c8661866c7e061b36e51ea5710467.jpg\" alt=\"image\" \/><\/div>\r\nc. none\r\n\r\nd. none\r\n<div class=\"informalfigure large\">\r\n\r\ne.\u00a0<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143605\/809028196c4d5e2b1007b3b5e975d376.jpg\" alt=\"image\" \/>[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"navbar-bottom\" class=\"navbar\">\r\n<div class=\"navbar-part right\">\r\n\r\n&nbsp;\r\n\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"navbar-top\" class=\"navbar\">\n<div class=\"navbar-part left\"><\/div>\n<\/div>\n<div id=\"book-content\">\n<div id=\"gob-ch13_s02\" class=\"section\" xml:lang=\"en\">\n<div id=\"gob-ch13_s02_n01\" class=\"learning_objectives editable block\">\n<div class=\"textbox learning-objectives\">\n<h3>Learning Objectives<\/h3>\n<ol id=\"gob-ch13_s02_l01\" class=\"orderedlist\">\n<li>Recognize that alkenes that can exist as cis-trans isomers.<\/li>\n<li>Classify isomers as cis or trans.<\/li>\n<li>Draw structures for cis-trans isomers given their names.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"gob-ch13_s02_p01\" class=\"para editable block\">As noted in <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-12\">Chapter 12 &#8220;Organic Chemistry: Alkanes and Halogenated Hydrocarbons&#8221;<\/a>, there is free rotation about the carbon-to-carbon single bonds (C\u2013C) in alkanes. In contrast, the structure of alkenes requires that the carbon atoms of a double bond and the two atoms bonded to each carbon atom all lie in a single plane, and that each doubly bonded carbon atom lies in the center of a triangle. This part of the molecule\u2019s structure is rigid; rotation about doubly bonded carbon atoms is <em class=\"emphasis\">not<\/em> possible without rupturing the bond. Look at the two chlorinated hydrocarbons in <a class=\"xref\" href=\"#gob-ch13_s02_f01\">Figure 13.2 &#8220;Rotation about Bonds&#8221;<\/a>.<\/p>\n<div id=\"gob-ch13_s02_f01\" class=\"figure large medium-height editable block\">\n<div style=\"width: 1038px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143516\/8ce2ef9b7324b1fddc98c74e71a5f9ef.jpg\" alt=\"image\" width=\"1028\" height=\"1409\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 13.2 Rotation about Bonds. In 1,2-dichloroethane (a), free rotation about the C\u2013C bond allows the two structures to be interconverted by a twist of one end relative to the other. In 1,2-dichloroethene (b), restricted rotation about the double bond means that the relative positions of substituent groups above or below the double bond are significant.<\/p>\n<\/div>\n<\/div>\n<p id=\"gob-ch13_s02_p02\" class=\"para editable block\">In 1,2-dichloroethane (part (a) of <a class=\"xref\" href=\"#gob-ch13_s02_f01\">Figure 13.2 &#8220;Rotation about Bonds&#8221;<\/a>), there is free rotation about the C\u2013C bond. The two models shown represent exactly the same molecule; they are <em class=\"emphasis\">not<\/em> isomers. You can draw structural formulas that look different, but if you bear in mind the possibility of this free rotation about single bonds, you should recognize that these two structures represent the same molecule:<\/p>\n<div class=\"informalfigure large block\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143519\/41f95e8e2c9df3d0abf8d3db2a6bc2a4.jpg\" alt=\"image\" \/><\/div>\n<p id=\"gob-ch13_s02_p03\" class=\"para editable block\">In 1,2-dichloroethene (part (b) of <a class=\"xref\" href=\"#gob-ch13_s02_f01\">Figure 13.2 &#8220;Rotation about Bonds&#8221;<\/a>), however, restricted rotation about the double bond means that the relative positions of substituent groups above or below the double bond become significant. This leads to a special kind of isomerism.\u00a0<span class=\"margin_term\"> <span class=\"glossdef\">An isomer in which two substituent groups are attached on the same side of a double bond or ring in an organic molecule is called a <strong>cis- isomer<\/strong>.<\/span><\/span> (Latin <em class=\"emphasis\">cis<\/em>, meaning \u201con this side\u201d) The molecule shown with two chlorine atoms on the same side of the double bond is named cis-1,2-dichloroethene. \u00a0<span class=\"margin_term\"><span class=\"glossdef\">An isomer in which two substituent groups are attached to opposite sides of a double bond or ring in a molecule is called a <strong>trans isomer.\u00a0 <\/strong><\/span><\/span>(Latin <em class=\"emphasis\">trans<\/em>, meaning \u201cacross\u201d) The isomer with the two Cl atoms on opposite sides of the molecule is named <em class=\"emphasis\">trans<\/em>-1,2-dichloroethene. These two compounds are <span class=\"margin_term\"><span class=\"glossterm\">cis-trans isomers (or geometric isomers).\u00a0 T<\/span><span class=\"glossdef\">he presence of a rigid structure such as a double bond or ring.<\/span><\/span>, compounds is necessary for cis-\/trans isomerism.\u00a0 Note that cis and trans isomers are different compounds with distinct physical and chemical properties.<\/p>\n<p id=\"gob-ch13_s02_p04\" class=\"para editable block\">Consider the alkene with the condensed structural formula CH<sub class=\"subscript\">3<\/sub>CH=CHCH<sub class=\"subscript\">3<\/sub>. We could name it 2-butene, but there are actually two such compounds; the double bond results in cis-trans isomerism (<a class=\"xref\" href=\"#gob-ch13_s02_f02\">Figure 13.3 &#8220;Ball-and-Spring Models of (a) Cis-2-Butene and (b) Trans-2-Butene&#8221;<\/a>).<\/p>\n<div id=\"gob-ch13_s02_f02\" class=\"figure large editable block\">\n<div style=\"width: 1343px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143522\/27419743a4c4ea46e76261ef7a760b5b.jpg\" alt=\"image\" width=\"1333\" height=\"557\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 13.3 Ball-and-Spring Models of (a) Cis-2-Butene and (b) Trans-2-Butene.\u00a0Cis-trans isomers have different physical, chemical, and physiological properties.<\/p>\n<\/div>\n<\/div>\n<p id=\"gob-ch13_s02_p05\" class=\"para editable block\"><em class=\"emphasis\">Cis<\/em>-2-butene has both methyl groups on the same side of the molecule. <em class=\"emphasis\">Trans<\/em>-2-butene has the methyl groups on opposite sides of the molecule. Their structural formulas are as follows:<\/p>\n<div class=\"informalfigure large block\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143525\/bcc8673ce6ab3f54d54f951023a68458.jpg\" alt=\"image\" \/><\/div>\n<p id=\"gob-ch13_s02_p06\" class=\"para editable block\">Note, however, that the presence of a double bond does not necessarily lead to cis-trans isomerism. We can draw two <em class=\"emphasis\">seemingly<\/em> different propenes:<\/p>\n<div class=\"informalfigure large block\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143528\/e5d2d78a636ba67a9cbbe6712c6d7d0b.jpg\" alt=\"image\" \/><\/div>\n<p id=\"gob-ch13_s02_p07\" class=\"para editable block\">However, these two structures are not really different from each other. If you could pick up either molecule from the page and flip it over top to bottom, you would see that the two formulas are identical.<\/p>\n<p id=\"gob-ch13_s02_p08\" class=\"para editable block\">Thus there are two requirements for cis-trans isomerism:<\/p>\n<ol id=\"gob-ch13_s02_l02\" class=\"orderedlist editable block\">\n<li>Rotation must be restricted in the molecule.<\/li>\n<li>There must be two nonidentical groups on <em class=\"emphasis\">each<\/em> doubly bonded carbon atom.<\/li>\n<\/ol>\n<p id=\"gob-ch13_s02_p09\" class=\"para editable block\">In these propene structures, the second requirement for cis-trans isomerism is not fulfilled. One of the doubly bonded carbon atoms does have two different groups attached, but the rules require that <em class=\"emphasis\">both<\/em> carbon atoms have two different groups.<\/p>\n<p id=\"gob-ch13_s02_p10\" class=\"para editable block\">In general, the following statements hold true in cis-trans isomerism:<\/p>\n<ul id=\"gob-ch13_s02_l03\" class=\"itemizedlist editable block\">\n<li>Alkenes with a C=CH<sub class=\"subscript\">2<\/sub> unit do not exist as cis-trans isomers.<\/li>\n<li>Alkenes with a C=CR<sub class=\"subscript\">2<\/sub> unit, where the two R groups are the same, do not exist as cis-trans isomers.<\/li>\n<li>Alkenes of the type R\u2013CH=CH\u2013R can exist as cis and trans isomers; cis if the two R groups are on the same side of the carbon-to-carbon double bond, and trans if the two R groups are on opposite sides of the carbon-to-carbon double bond.<\/li>\n<\/ul>\n<p id=\"gob-ch13_s02_p11\" class=\"para editable block\">Cis-trans isomerism also occurs in cyclic compounds. In ring structures, groups are unable to rotate about any of the ring carbon\u2013carbon bonds. Therefore, groups can be either on the same side of the ring (cis) or on opposite sides of the ring (trans). For our purposes here, we represent all cycloalkanes as planar structures, and we indicate the positions of the groups, either above or below the plane of the ring.<\/p>\n<div class=\"informalfigure large block\"><img decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143531\/e1940700b64b899e90e00a80a33e9a2f.jpg\" alt=\"image\" \/><\/div>\n<div id=\"gob-ch13_s02_n02\" class=\"exercises editable block\">\n<h3 class=\"title\">Example 3<\/h3>\n<p id=\"gob-ch13_s02_p12\" class=\"para\">Which compounds can exist as cis-trans (geometric) isomers? Draw them.<\/p>\n<ol id=\"gob-ch13_s02_l04\" class=\"orderedlist\">\n<li>CHCl=CHBr<\/li>\n<li>CH<sub class=\"subscript\">2<\/sub>=CBrCH<sub class=\"subscript\">3<\/sub><\/li>\n<li>(CH<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>C=CHCH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub><\/li>\n<li>CH<sub class=\"subscript\">3<\/sub>CH=CHCH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub><\/li>\n<\/ol>\n<p class=\"simpara\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q136727\">Show Answer<\/span><\/p>\n<div id=\"q136727\" class=\"hidden-answer\" style=\"display: none\">\n<p class=\"simpara\">All four structures have a double bond and thus meet rule 1 for cis-trans isomerism.<\/p>\n<p class=\"simpara\">1. This compound meets rule 2; it has two nonidentical groups on each carbon atom (H and Cl on one and H and Br on the other). It exists as both cis and trans isomers:<img decoding=\"async\" style=\"font-size: 1em\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143534\/55bc5569d86c404436cae7b6ff1847da.jpg\" alt=\"image\" \/><\/p>\n<p>2. This compound has two hydrogen atoms on one of its doubly bonded carbon atoms; it fails rule 2 and does not exist as cis and trans isomers.<\/p>\n<p>3. This compound has two methyl (CH<sub class=\"subscript\">3<\/sub>) groups on one of its doubly bonded carbon atoms. It fails rule 2 and does not exist as cis and trans isomers.<\/p>\n<p class=\"para\">4. This compound meets rule 2; it has two nonidentical groups on <em class=\"emphasis\">each<\/em> carbon atom and exists as both cis and trans isomers:<\/p>\n<div class=\"informalfigure large\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143537\/456f8aaa42d41d3ddeedcd1e74c59d1a.jpg\" alt=\"image\" \/>\u00a0<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch13_s02_qs01\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<div id=\"gob-ch13_s02_qs01\" class=\"qandaset block\">\n<h3 class=\"title\">Skill-Building Exercise<\/h3>\n<div class=\"question\">\n<p id=\"gob-ch13_s02_qs01_p01\" class=\"para\">1. Which compounds can exist as cis-trans isomers? Draw them.<\/p>\n<\/div>\n<p>a. CH<sub class=\"subscript\">2<\/sub>=CHCH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub><\/p>\n<p>b. CH<sub class=\"subscript\">3<\/sub>CH=CHCH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub><\/p>\n<p>c. CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH=CHCH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub><\/p>\n<div class=\"informalfigure large\">d.\u00a0<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143540\/59e80798de70b739b0c8e4f2c5051f65.jpg\" alt=\"image\" \/><\/div>\n<div class=\"informalfigure large\">e.\u00a0<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143542\/cc2bacbaeec8ad121e37ef530e7ea4c3.jpg\" alt=\"image\" \/><\/div>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<div id=\"gob-ch13_s02_qs01\" class=\"qandaset block\">\n<h3 class=\"title\">Concept Review Exercises<\/h3>\n<\/div>\n<div id=\"gob-ch13_s02_qs02\" class=\"qandaset block\">\n<ol id=\"gob-ch13_s02_qs02_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch13_s02_qs02_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch13_s02_qs02_p01\" class=\"para\">What are cis-trans (geometric) isomers? What two types of compounds can exhibit cis-trans isomerism?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch13_s02_qs02_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch13_s02_qs02_p03\" class=\"para\">Classify each compound as a cis isomer, a trans isomer, or neither.<\/p>\n<ol id=\"gob-ch13_s02_qs02_l01\" class=\"orderedlist\">\n<li>\n<div class=\"informalfigure large\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143546\/6e7abe999980c806f82c5935244b807c.jpg\" alt=\"image\" \/><\/div>\n<\/li>\n<li>\n<div class=\"informalfigure large\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143548\/016dc6eea5f3ed34c0636f026475baa6.jpg\" alt=\"image\" \/><\/div>\n<\/li>\n<li>\n<div class=\"informalfigure large\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143552\/6f4d0db663885ee6c499924970749b97.jpg\" alt=\"image\" \/><\/div>\n<\/li>\n<li>\n<div class=\"informalfigure large\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143557\/7aec26f72a319418bb7402f0df3ff179.jpg\" alt=\"image\" \/><\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch13_s02_qs02_ans\" class=\"qandaset block\">\n<div class=\"answer\">\n<p id=\"gob-ch13_s02_qs02_p02_ans\" class=\"para\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q337096\">Show Answer<\/span><\/p>\n<div id=\"q337096\" class=\"hidden-answer\" style=\"display: none\">1. Cis-trans isomers are compounds that have different configurations (groups permanently in different places in space) because of the presence of a rigid structure in their molecule. Alkenes and cyclic compounds can exhibit cis-trans isomerism.<\/p>\n<p class=\"para\">2. a.trans\u00a0 b. cis\u00a0 c. cis\u00a0 d. neither\u00a0<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox key-takeaways\">\n<div id=\"gob-ch13_s02_qs01\" class=\"qandaset block\">\n<h3 class=\"title\">Key Takeaway<\/h3>\n<\/div>\n<div id=\"gob-ch13_s02_n05\" class=\"key_takeaways editable block\">\n<ul id=\"gob-ch13_s02_l10\" class=\"itemizedlist\">\n<li>Cis-trans (geometric) isomerism exists when there is restricted rotation in a molecule and there are two nonidentical groups on <em class=\"emphasis\">each<\/em> doubly bonded carbon atom.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch13_s02_qs03\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<div id=\"book-content\">\n<div id=\"gob-ch13_s02\" class=\"section\" xml:lang=\"en\">\n<div id=\"gob-ch13_s02_qs03\" class=\"qandaset block\">\n<h3 class=\"title\">Exercises<\/h3>\n<ol id=\"gob-ch13_s02_qs03_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch13_s02_qs03_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch13_s02_qs03_p01\" class=\"para\">Draw the structures of the cis-trans isomers for each compound. Label them cis and trans. If no cis-trans isomers exist, write none.<\/p>\n<ol id=\"gob-ch13_s02_qs03_l01\" class=\"orderedlist\">\n<li>2-bromo-2-pentene<\/li>\n<li>3-heptene<\/li>\n<li>4-methyl-2-pentene<\/li>\n<li>1,1-dibromo-1-butene<\/li>\n<li>2-butenoic acid (CH<sub class=\"subscript\">3<\/sub>CH=CHCOOH)<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch13_s02_qs03_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch13_s02_qs03_p02\" class=\"para\">Draw the structures of the cis-trans isomers for each compound. Label them cis and trans. If no cis-trans isomers exist, write none.<\/p>\n<ol id=\"gob-ch13_s02_qs03_l03\" class=\"orderedlist\">\n<li>2,3-dimethyl-2-pentene<\/li>\n<li>1,1-dimethyl-2-ethylcyclopropane<\/li>\n<li>1,2-dimethylcyclohexane<\/li>\n<li>5-methyl-2-hexene<\/li>\n<li>1,2,3-trimethylcyclopropane<\/li>\n<\/ol>\n<\/div>\n<p>&nbsp;<\/li>\n<\/ol>\n<\/div>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q321781\">Show Answer<\/span><\/p>\n<div id=\"q321781\" class=\"hidden-answer\" style=\"display: none\">1.<\/p>\n<p>a.\u00a0<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143600\/49b77e14f1a593612c72d43c42a9f409.jpg\" alt=\"image\" \/><\/p>\n<div id=\"gob-ch13_s02_qs03_ans\" class=\"qandaset block\">\n<div class=\"informalfigure large\">b.\u00a0<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143602\/052c8661866c7e061b36e51ea5710467.jpg\" alt=\"image\" \/><\/div>\n<p>c. none<\/p>\n<p>d. none<\/p>\n<div class=\"informalfigure large\">\n<p>e.\u00a0<img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21143605\/809028196c4d5e2b1007b3b5e975d376.jpg\" alt=\"image\" \/><\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"navbar-bottom\" class=\"navbar\">\n<div class=\"navbar-part right\">\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1161\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul 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