{"id":1564,"date":"2018-03-21T15:27:06","date_gmt":"2018-03-21T15:27:06","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/chapter\/chemical-properties-of-carboxylic-acids-ionization-and-neutralization\/"},"modified":"2018-11-07T21:36:41","modified_gmt":"2018-11-07T21:36:41","slug":"chemical-properties-of-carboxylic-acids-ionization-and-neutralization","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/chapter\/chemical-properties-of-carboxylic-acids-ionization-and-neutralization\/","title":{"raw":"15.5 Chemical Properties of Carboxylic Acids: Ionization and Neutralization","rendered":"15.5 Chemical Properties of Carboxylic Acids: Ionization and Neutralization"},"content":{"raw":"<div id=\"book-content\">\r\n<div id=\"gob-ch15_s05\" class=\"section\" xml:lang=\"en\">\r\n<div class=\"textbox learning-objectives\">\r\n<h3 class=\"title editable block\">Learning Objectives<\/h3>\r\n<div id=\"gob-ch15_s05_n01\" class=\"learning_objectives editable block\">\r\n<ol id=\"gob-ch15_s05_l01\" class=\"orderedlist\">\r\n \t<li>Name the typical reactions that take place with carboxylic acids.<\/li>\r\n \t<li>Describe how carboxylic acids react with basic compounds.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<h3 class=\"title editable block\">Water-soluble carboxylic acids are weak acids that ionize slightly in water to form moderately acidic solutions.<\/h3>\r\n<span class=\"informalequation block\"> RCOOH+H<sub>2<\/sub>O\u21c4RCOO<sup>\u2212<\/sup>+H<sub>3<\/sub>O<sup>+ <\/sup><\/span>\r\n<p id=\"gob-ch15_s05_p02\" class=\"para editable block\">Their aqueous solutions exhibit the typical properties of acids, such as changing litmus from blue to red.<\/p>\r\n\r\n<div id=\"gob-ch15_s05_n02\" class=\"callout editable block\">\r\n<div class=\"textbox\">\r\n<h3 class=\"title\">Note<\/h3>\r\n<p id=\"gob-ch15_s05_p03\" class=\"para\">The anion formed when a carboxylic acid dissociates is called the <em class=\"emphasis\">carboxylate<\/em> anion (RCOO<sup class=\"superscript\">\u2212<\/sup>).\u00a0 The specific name of a carboxylate anion comes from the name of the acid.\u00a0 For example, ethanoic acid's anion is ethanoate.\u00a0 Pentanoic acid's anion is pentanoate, and so on.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"gob-ch15_s05_p04\" class=\"para editable block\">Whether soluble in water or not, carboxylic acids react with aqueous solutions of sodium hydroxide (NaOH), sodium carbonate (Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>), and sodium bicarbonate (NaHCO<sub class=\"subscript\">3<\/sub>) to form salts:<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">RCOOH + NaOH(aq) \u2192 RCOO<sup class=\"superscript\">\u2212<\/sup>Na<sup class=\"superscript\">+<\/sup>(aq) + H<sub class=\"subscript\">2<\/sub>O<\/span><\/span>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">2RCOOH + Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(aq) \u2192 2RCOO<sup class=\"superscript\">\u2212<\/sup>Na<sup class=\"superscript\">+<\/sup>(aq) + H<sub class=\"subscript\">2<\/sub>O + CO<sub class=\"subscript\">2<\/sub>(g)<\/span><\/span>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">RCOOH + NaHCO<sub class=\"subscript\">3<\/sub>(aq) \u2192 RCOO<sup class=\"superscript\">\u2212<\/sup>Na<sup class=\"superscript\">+<\/sup>(aq) + H<sub class=\"subscript\">2<\/sub>O + CO<sub class=\"subscript\">2<\/sub>(g)<\/span><\/span>\r\n<p id=\"gob-ch15_s05_p05\" class=\"para editable block\">In these reactions, the carboxylic acids act like inorganic acids: they neutralize basic compounds. With solutions of carbonate (CO<sub class=\"subscript\">3<\/sub>) and bicarbonate (HCO<sub class=\"subscript\">3<\/sub>) ions, they also form carbon dioxide gas.<\/p>\r\n<p id=\"gob-ch15_s05_p06\" class=\"para editable block\">Carboxylic acid salts are named in the same manner as inorganic salts: the name of the cation is followed by the name of the organic anion. The name of the anion is obtained by dropping the -<em class=\"emphasis\">ic<\/em> ending of the acid name and replacing it with the suffix -<em class=\"emphasis\">ate<\/em>. This rule applies whether we are using common names or International Union of Pure and Applied Chemistry (IUPAC) names:<\/p>\r\n\r\n<div class=\"informalfigure large block\"><img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21152659\/828706ddcf01975c52521ca58e9d1315.jpg\" alt=\"image\" \/><\/div>\r\n<div id=\"gob-ch15_s05_n03\" class=\"callout block\">\r\n<div class=\"textbox\">\r\n<h3 class=\"title\">Note<\/h3>\r\n<p id=\"gob-ch15_s05_p07\" class=\"para\">The salts of long-chain carboxylic acids are called soaps. We discuss the chemistry of soaps further in <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-17\">Chapter 17 \"Lipids\"<\/a>, <a class=\"xref\" href=\"gob-ch17_s02#gob-ch17_s02\">Section 17.2 \"Fats and Oils\"<\/a>.<\/p>\r\n\r\n<div class=\"informalfigure large\"><img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21152702\/69d5fa45b0586b3176a8740f67ef9ea3.jpg\" alt=\"image\" \/><\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch15_s05_n04\" class=\"exercises block\">\r\n<h3 class=\"title\">Example 3<\/h3>\r\n<p id=\"gob-ch15_s05_p08\" class=\"para\">Write an equation for each reaction.<\/p>\r\n\r\n<ol id=\"gob-ch15_s05_l02\" class=\"orderedlist\">\r\n \t<li>the ionization of propanoic acid in water (H<sub class=\"subscript\">2<\/sub>O)<\/li>\r\n \t<li>the neutralization of propanoic acid with aqueous sodium hydroxide (NaOH)<\/li>\r\n<\/ol>\r\n<p class=\"simpara\">[reveal-answer q=\"213789\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"213789\"]<\/p>\r\n<p class=\"simpara\">1. Propanoic acid has three carbon atoms, so its formula is CH<sub>2<\/sub>CH<sub>2<\/sub>COOH. Propanoic acid ionizes in water to form a propanoate ion and a hydronium (H3O+) ion.<\/p>\r\n<p class=\"simpara\" style=\"text-align: center\">CH<sub>3<\/sub>CH<sub>2<\/sub>COOH(aq) + H<sub>2<\/sub>O(\u2113) \u2192 CH<sub>3<\/sub>CH<sub>2<\/sub>COO<sup>\u2212<\/sup>(aq) + H<sub>3<\/sub>O<sup>+<\/sup>(aq)<\/p>\r\n<p class=\"simpara\">2. Propanoic acid reacts with NaOH(aq) to form sodium propanoate and water.<\/p>\r\n<p class=\"simpara\" style=\"text-align: center\">CH<sub>3<\/sub>CH<sub>2<\/sub>COOH(aq) + NaOH(aq) \u2192 CH<sub>3<\/sub>CH<sub>2<\/sub>COO<sup>\u2212<\/sup>Na<sup>+<\/sup>(aq) + H<sub>2<\/sub>O(\u2113)[\/hidden-answer]<\/p>\r\n\r\n<\/div>\r\n<div id=\"gob-ch15_s05_qs01\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<h3 class=\"title\">Skill-Building Exercise<\/h3>\r\n<p class=\"title\">Write an equation for each reaction.<\/p>\r\n\r\n<ol id=\"gob-ch15_s05_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch15_s05_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs01_p02\" class=\"para\">the ionization of methanoic acid in water<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch15_s05_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs01_p04\" class=\"para\">the ionization of 4-chlorobenzoic acid in water<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch15_s05_n06\" class=\"exercises block\">\r\n<h3 class=\"title\">Example 4<\/h3>\r\n<p id=\"gob-ch15_s05_p13\" class=\"para\">Write an equation for the reaction of decanoic acid with each compound.<\/p>\r\n\r\n<ol id=\"gob-ch15_s05_l05\" class=\"orderedlist\">\r\n \t<li>aqueous sodium hydoxide (NaOH)<\/li>\r\n \t<li>aqueous sodium bicarbonate (NaHCO<sub class=\"subscript\">3<\/sub>)<\/li>\r\n<\/ol>\r\n<p class=\"simpara\">[reveal-answer q=\"80260\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"80260\"]<\/p>\r\n<p class=\"simpara\">1. Decanoic acid has 10 carbon atoms. It reacts with NaOH to form a salt and water (H<sub>2<\/sub>O).<\/p>\r\n<p class=\"simpara\" style=\"text-align: center\"><span class=\"informalequation\"><span class=\"mathphrase\">CH<sub class=\"subscript\">3<\/sub>(CH<sub class=\"subscript\">2<\/sub>)<sub class=\"subscript\">8<\/sub>COOH + NaOH(aq) \u2192 CH<sub class=\"subscript\">3<\/sub>(CH<sub class=\"subscript\">2<\/sub>)<sub class=\"subscript\">8<\/sub>COO<sup class=\"superscript\">\u2212<\/sup>Na<sup class=\"superscript\">+<\/sup>(aq) + H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span><\/p>\r\n<p class=\"para\">2. With NaHCO<sub class=\"subscript\">3<\/sub>, the products are a salt, H<sub class=\"subscript\">2<\/sub>O, and carbon dioxide (CO<sub class=\"subscript\">2<\/sub>).<\/p>\r\n<p style=\"text-align: center\"><span class=\"informalequation\"><span class=\"mathphrase\">CH<sub class=\"subscript\">3<\/sub>(CH<sub class=\"subscript\">2<\/sub>)<sub class=\"subscript\">8<\/sub>COOH + NaHCO<sub class=\"subscript\">3<\/sub>(aq) \u2192 CH<sub class=\"subscript\">3<\/sub>(CH<sub class=\"subscript\">2<\/sub>)<sub class=\"subscript\">8<\/sub>COO<sup class=\"superscript\">\u2212<\/sup>Na<sup class=\"superscript\">+<\/sup>(aq) + H<sub class=\"subscript\">2<\/sub>O(\u2113) + CO<sub class=\"subscript\">2<\/sub>(g)\u00a0<\/span><\/span>[\/hidden-answer]<\/p>\r\n\r\n<\/div>\r\n<div id=\"gob-ch15_s05_qs02\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<h3 class=\"title\">Skill-Building Exercise<\/h3>\r\n<p class=\"title\">Write an equation for the reaction of benzoic acid with each compound.<\/p>\r\n\r\n<ol id=\"gob-ch15_s05_qs02_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch15_s05_qs02_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs02_p02\" class=\"para\">aqueous sodium hydroxide (NaOH)<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch15_s05_qs02_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs02_p04\" class=\"para\">aqueous sodium bicarbonate (NaHCO<sub class=\"subscript\">3<\/sub>)<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch15_s05_n08\" class=\"callout block\">\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">To Your Health: Organic Salts as Preservatives<\/h3>\r\n<p id=\"gob-ch15_s05_p17\" class=\"para\">Some organic salts are used as preservatives in food products. They prevent spoilage by inhibiting the growth of bacteria and fungi. Calcium and sodium propionate, for example, are added to processed cheese and bakery goods; sodium benzoate is added to cider, jellies, pickles, and syrups; and sodium sorbate and potassium sorbate are added to fruit juices, sauerkraut, soft drinks, and wine. Look for them on ingredient labels the next time you shop for groceries.<\/p>\r\n\r\n<div class=\"informalfigure large\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21152705\/cbac8bd93df2c08c1bfef6ca665bcd8e.jpg\" alt=\"image\" \/><\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch15_s05_qs03\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<div id=\"gob-ch15_s05_qs03\" class=\"qandaset block\">\r\n<h3 class=\"title\">Concept Review Exercises<\/h3>\r\n<ol id=\"gob-ch15_s05_qs03_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch15_s05_qs03_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs03_p01\" class=\"para\">How does the neutralization of a carboxylic acid differ from that of an inorganic acid? How are they similar?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch15_s05_qs03_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs03_p03\" class=\"para\">What products are formed when a carboxylic acid is neutralized with a strong base? What additional product is formed when a carboxylic acid is neutralized with a carbonate or a bicarbonate compound?<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch15_s05_qs03_ans\" class=\"qandaset block\">\r\n<div class=\"answer\">\r\n<p id=\"gob-ch15_s05_qs03_p02_ans\" class=\"para\">[reveal-answer q=\"889280\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"889280\"]<\/p>\r\n\r\n<ol>\r\n \t<li class=\"para\">Similar: acid + base produces water + a salt.\u00a0 Different: Insoluble carboxylic acids often form soluble carboxylate salts.<\/li>\r\n \t<li class=\"para\">Both form a carboxylate salt and water; With a carbonate or bicarbonate compound, carbon dioxide is also formed.[\/hidden-answer]<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch15_s05_n10\" class=\"key_takeaways editable block\">\r\n<div class=\"textbox key-takeaways\">\r\n<h3 class=\"title\">Key Takeaways<\/h3>\r\n<ul id=\"gob-ch15_s05_l09\" class=\"itemizedlist\">\r\n \t<li>Soluble carboxylic acids are weak acids in aqueous solutions.<\/li>\r\n \t<li>Carboxylic acids neutralize bases, forming carboxylate\u00a0 salts.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch15_s05_qs04\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<div id=\"gob-ch15_s05_qs04\" class=\"qandaset block\">\r\n<h3 class=\"title\">Exercises<\/h3>\r\n<ol id=\"gob-ch15_s05_qs04_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch15_s05_qs04_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs04_p01\" class=\"para\">Write the equation for the ionization of CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>COOH in water.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch15_s05_qs04_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs04_p03\" class=\"para\">Write the equation for the neutralization of CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>COOH with sodium hydroxide [NaOH(aq)].<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch15_s05_qs04_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs04_p05\" class=\"para\">Write the equation for the reaction of CH<sub class=\"subscript\">3<\/sub>COOH with sodium carbonate [Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(aq)].<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch15_s05_qs04_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs04_p07\" class=\"para\">Write the equation for the reaction of CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>COOH with sodium bicarbonate [NaHCO<sub class=\"subscript\">3<\/sub>(aq)].<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch15_s05_qs04_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs04_p09\" class=\"para\">Write the equation for the ionization of propanoic acid in water.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch15_s05_qs04_qd01_qa06\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs04_p11\" class=\"para\">Write the equation for the ionization of \u03b3-chloropentanoic acid in water.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch15_s05_qs04_qd01_qa07\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs04_p13\" class=\"para\">Write an equation for the reaction of butanoic acid with each compound.<\/p>\r\n\r\n<ol id=\"gob-ch15_s05_qs04_l01\" class=\"orderedlist\">\r\n \t<li>aqueous NaOH<\/li>\r\n \t<li>aqueous NaHCO<sub class=\"subscript\">3<\/sub><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch15_s05_qs04_qd01_qa08\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs04_p14\" class=\"para\">Write the condensed structural formula for each compound.<\/p>\r\n\r\n<ol id=\"gob-ch15_s05_qs04_l03\" class=\"orderedlist\">\r\n \t<li>potassium acetate<\/li>\r\n \t<li>calcium propanoate<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch15_s05_qs04_qd01_qa09\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch15_s05_qs04_p15\" class=\"para\">Name each compound.<\/p>\r\n\r\n<ol id=\"gob-ch15_s05_qs04_l05\" class=\"orderedlist\">\r\n \t<li>CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>COO<sup class=\"superscript\">\u2212<\/sup>Li<sup class=\"superscript\">+<\/sup><\/li>\r\n \t<li>CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>COO<sup class=\"superscript\">\u2212<\/sup>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch15_s05_qs04_ans\" class=\"qandaset block\">\r\n<div class=\"answer\">\r\n<p id=\"gob-ch15_s05_qs04_p02_ans\" class=\"para\">[reveal-answer q=\"748043\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"748043\"]<\/p>\r\n<p class=\"para\">1. CH<sub>3<\/sub>CH<sub>2<\/sub>CH<sub>2<\/sub>COOH(aq) + H<sub>2<\/sub>O(\u2113) \u2192 CH<sub>3<\/sub>CH<sub>2<\/sub>CH<sub>2<\/sub>COO<sup>\u2212<\/sup>(aq) + H<sub>3<\/sub>O<sup>+<\/sup>(aq) (Note: should be double arrow.\u00a0 MK)<\/p>\r\n<p class=\"para\">3. 2CH<sub>3<\/sub>COOH + Na<sub>2<\/sub>CO<sub>3<\/sub>(aq) \u2192 2CH<sub>3<\/sub>COO<sup>\u2212<\/sup>Na<sup>+<\/sup>(aq) + H<sub>2<\/sub>O(\u2113) + CO<sub>2<\/sub>(g)<\/p>\r\n<p class=\"para\">5. CH<sub>3<\/sub>CH<sub>2<\/sub>COOH(aq) + H<sub>2<\/sub>O(\u2113) \u2192 CH<sub>3<\/sub>CH<sub>2<\/sub>COO<sup>\u2212<\/sup>(aq) + H<sub>3<\/sub>O<sup>+<\/sup>(aq)\u00a0 (Note: should be double arrow.\u00a0 MK)<\/p>\r\n<p class=\"para\">7. a. CH<sub>3<\/sub>CH<sub>2<\/sub>CH<sub>2<\/sub>COOH(aq) + NaOH(aq) \u2192 CH<sub>3<\/sub>CH<sub>2<\/sub>CH<sub>2<\/sub>COO\u2212Na+(aq) + H<sub>2<\/sub>O(\u2113)<\/p>\r\n<p class=\"para\">b. CH<sub>3<\/sub>(CH<sub>2<\/sub>)<sub>2<\/sub>COOH + NaHCO<sub>3<\/sub>(aq) \u2192 CH<sub>3<\/sub>(CH<sub>2<\/sub>)COO<sup>\u2212<\/sup>Na<sup>+<\/sup>(aq) + H<sub>2<\/sub>O(\u2113) + CO<sub>2<\/sub>(g)<\/p>\r\n<p class=\"para\">9. a. lithium butyrate (common)\u00a0 lithium butanoate (IUPAC)<\/p>\r\n<p class=\"para\">b. ammonium butanoate \u00a0(IUPAC) or ammonium butyrate\u00a0(common) [\/hidden-answer]<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"book-content\">\n<div id=\"gob-ch15_s05\" class=\"section\" xml:lang=\"en\">\n<div class=\"textbox learning-objectives\">\n<h3 class=\"title editable block\">Learning Objectives<\/h3>\n<div id=\"gob-ch15_s05_n01\" class=\"learning_objectives editable block\">\n<ol id=\"gob-ch15_s05_l01\" class=\"orderedlist\">\n<li>Name the typical reactions that take place with carboxylic acids.<\/li>\n<li>Describe how carboxylic acids react with basic compounds.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<h3 class=\"title editable block\">Water-soluble carboxylic acids are weak acids that ionize slightly in water to form moderately acidic solutions.<\/h3>\n<p><span class=\"informalequation block\"> RCOOH+H<sub>2<\/sub>O\u21c4RCOO<sup>\u2212<\/sup>+H<sub>3<\/sub>O<sup>+ <\/sup><\/span><\/p>\n<p id=\"gob-ch15_s05_p02\" class=\"para editable block\">Their aqueous solutions exhibit the typical properties of acids, such as changing litmus from blue to red.<\/p>\n<div id=\"gob-ch15_s05_n02\" class=\"callout editable block\">\n<div class=\"textbox\">\n<h3 class=\"title\">Note<\/h3>\n<p id=\"gob-ch15_s05_p03\" class=\"para\">The anion formed when a carboxylic acid dissociates is called the <em class=\"emphasis\">carboxylate<\/em> anion (RCOO<sup class=\"superscript\">\u2212<\/sup>).\u00a0 The specific name of a carboxylate anion comes from the name of the acid.\u00a0 For example, ethanoic acid&#8217;s anion is ethanoate.\u00a0 Pentanoic acid&#8217;s anion is pentanoate, and so on.<\/p>\n<\/div>\n<\/div>\n<p id=\"gob-ch15_s05_p04\" class=\"para editable block\">Whether soluble in water or not, carboxylic acids react with aqueous solutions of sodium hydroxide (NaOH), sodium carbonate (Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>), and sodium bicarbonate (NaHCO<sub class=\"subscript\">3<\/sub>) to form salts:<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">RCOOH + NaOH(aq) \u2192 RCOO<sup class=\"superscript\">\u2212<\/sup>Na<sup class=\"superscript\">+<\/sup>(aq) + H<sub class=\"subscript\">2<\/sub>O<\/span><\/span><br \/>\n<span class=\"informalequation block\"><span class=\"mathphrase\">2RCOOH + Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(aq) \u2192 2RCOO<sup class=\"superscript\">\u2212<\/sup>Na<sup class=\"superscript\">+<\/sup>(aq) + H<sub class=\"subscript\">2<\/sub>O + CO<sub class=\"subscript\">2<\/sub>(g)<\/span><\/span><br \/>\n<span class=\"informalequation block\"><span class=\"mathphrase\">RCOOH + NaHCO<sub class=\"subscript\">3<\/sub>(aq) \u2192 RCOO<sup class=\"superscript\">\u2212<\/sup>Na<sup class=\"superscript\">+<\/sup>(aq) + H<sub class=\"subscript\">2<\/sub>O + CO<sub class=\"subscript\">2<\/sub>(g)<\/span><\/span><\/p>\n<p id=\"gob-ch15_s05_p05\" class=\"para editable block\">In these reactions, the carboxylic acids act like inorganic acids: they neutralize basic compounds. With solutions of carbonate (CO<sub class=\"subscript\">3<\/sub>) and bicarbonate (HCO<sub class=\"subscript\">3<\/sub>) ions, they also form carbon dioxide gas.<\/p>\n<p id=\"gob-ch15_s05_p06\" class=\"para editable block\">Carboxylic acid salts are named in the same manner as inorganic salts: the name of the cation is followed by the name of the organic anion. The name of the anion is obtained by dropping the &#8211;<em class=\"emphasis\">ic<\/em> ending of the acid name and replacing it with the suffix &#8211;<em class=\"emphasis\">ate<\/em>. This rule applies whether we are using common names or International Union of Pure and Applied Chemistry (IUPAC) names:<\/p>\n<div class=\"informalfigure large block\"><img decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21152659\/828706ddcf01975c52521ca58e9d1315.jpg\" alt=\"image\" \/><\/div>\n<div id=\"gob-ch15_s05_n03\" class=\"callout block\">\n<div class=\"textbox\">\n<h3 class=\"title\">Note<\/h3>\n<p id=\"gob-ch15_s05_p07\" class=\"para\">The salts of long-chain carboxylic acids are called soaps. We discuss the chemistry of soaps further in <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-17\">Chapter 17 &#8220;Lipids&#8221;<\/a>, <a class=\"xref\" href=\"gob-ch17_s02#gob-ch17_s02\">Section 17.2 &#8220;Fats and Oils&#8221;<\/a>.<\/p>\n<div class=\"informalfigure large\"><img decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21152702\/69d5fa45b0586b3176a8740f67ef9ea3.jpg\" alt=\"image\" \/><\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch15_s05_n04\" class=\"exercises block\">\n<h3 class=\"title\">Example 3<\/h3>\n<p id=\"gob-ch15_s05_p08\" class=\"para\">Write an equation for each reaction.<\/p>\n<ol id=\"gob-ch15_s05_l02\" class=\"orderedlist\">\n<li>the ionization of propanoic acid in water (H<sub class=\"subscript\">2<\/sub>O)<\/li>\n<li>the neutralization of propanoic acid with aqueous sodium hydroxide (NaOH)<\/li>\n<\/ol>\n<p class=\"simpara\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q213789\">Show Answer<\/span><\/p>\n<div id=\"q213789\" class=\"hidden-answer\" style=\"display: none\">\n<p class=\"simpara\">1. Propanoic acid has three carbon atoms, so its formula is CH<sub>2<\/sub>CH<sub>2<\/sub>COOH. Propanoic acid ionizes in water to form a propanoate ion and a hydronium (H3O+) ion.<\/p>\n<p class=\"simpara\" style=\"text-align: center\">CH<sub>3<\/sub>CH<sub>2<\/sub>COOH(aq) + H<sub>2<\/sub>O(\u2113) \u2192 CH<sub>3<\/sub>CH<sub>2<\/sub>COO<sup>\u2212<\/sup>(aq) + H<sub>3<\/sub>O<sup>+<\/sup>(aq)<\/p>\n<p class=\"simpara\">2. Propanoic acid reacts with NaOH(aq) to form sodium propanoate and water.<\/p>\n<p class=\"simpara\" style=\"text-align: center\">CH<sub>3<\/sub>CH<sub>2<\/sub>COOH(aq) + NaOH(aq) \u2192 CH<sub>3<\/sub>CH<sub>2<\/sub>COO<sup>\u2212<\/sup>Na<sup>+<\/sup>(aq) + H<sub>2<\/sub>O(\u2113)<\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch15_s05_qs01\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<h3 class=\"title\">Skill-Building Exercise<\/h3>\n<p class=\"title\">Write an equation for each reaction.<\/p>\n<ol id=\"gob-ch15_s05_qs01_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch15_s05_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs01_p02\" class=\"para\">the ionization of methanoic acid in water<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch15_s05_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs01_p04\" class=\"para\">the ionization of 4-chlorobenzoic acid in water<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div id=\"gob-ch15_s05_n06\" class=\"exercises block\">\n<h3 class=\"title\">Example 4<\/h3>\n<p id=\"gob-ch15_s05_p13\" class=\"para\">Write an equation for the reaction of decanoic acid with each compound.<\/p>\n<ol id=\"gob-ch15_s05_l05\" class=\"orderedlist\">\n<li>aqueous sodium hydoxide (NaOH)<\/li>\n<li>aqueous sodium bicarbonate (NaHCO<sub class=\"subscript\">3<\/sub>)<\/li>\n<\/ol>\n<p class=\"simpara\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q80260\">Show Answer<\/span><\/p>\n<div id=\"q80260\" class=\"hidden-answer\" style=\"display: none\">\n<p class=\"simpara\">1. Decanoic acid has 10 carbon atoms. It reacts with NaOH to form a salt and water (H<sub>2<\/sub>O).<\/p>\n<p class=\"simpara\" style=\"text-align: center\"><span class=\"informalequation\"><span class=\"mathphrase\">CH<sub class=\"subscript\">3<\/sub>(CH<sub class=\"subscript\">2<\/sub>)<sub class=\"subscript\">8<\/sub>COOH + NaOH(aq) \u2192 CH<sub class=\"subscript\">3<\/sub>(CH<sub class=\"subscript\">2<\/sub>)<sub class=\"subscript\">8<\/sub>COO<sup class=\"superscript\">\u2212<\/sup>Na<sup class=\"superscript\">+<\/sup>(aq) + H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span><\/p>\n<p class=\"para\">2. With NaHCO<sub class=\"subscript\">3<\/sub>, the products are a salt, H<sub class=\"subscript\">2<\/sub>O, and carbon dioxide (CO<sub class=\"subscript\">2<\/sub>).<\/p>\n<p style=\"text-align: center\"><span class=\"informalequation\"><span class=\"mathphrase\">CH<sub class=\"subscript\">3<\/sub>(CH<sub class=\"subscript\">2<\/sub>)<sub class=\"subscript\">8<\/sub>COOH + NaHCO<sub class=\"subscript\">3<\/sub>(aq) \u2192 CH<sub class=\"subscript\">3<\/sub>(CH<sub class=\"subscript\">2<\/sub>)<sub class=\"subscript\">8<\/sub>COO<sup class=\"superscript\">\u2212<\/sup>Na<sup class=\"superscript\">+<\/sup>(aq) + H<sub class=\"subscript\">2<\/sub>O(\u2113) + CO<sub class=\"subscript\">2<\/sub>(g)\u00a0<\/span><\/span><\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch15_s05_qs02\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<h3 class=\"title\">Skill-Building Exercise<\/h3>\n<p class=\"title\">Write an equation for the reaction of benzoic acid with each compound.<\/p>\n<ol id=\"gob-ch15_s05_qs02_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch15_s05_qs02_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs02_p02\" class=\"para\">aqueous sodium hydroxide (NaOH)<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch15_s05_qs02_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs02_p04\" class=\"para\">aqueous sodium bicarbonate (NaHCO<sub class=\"subscript\">3<\/sub>)<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div id=\"gob-ch15_s05_n08\" class=\"callout block\">\n<div class=\"textbox shaded\">\n<h3 class=\"title\">To Your Health: Organic Salts as Preservatives<\/h3>\n<p id=\"gob-ch15_s05_p17\" class=\"para\">Some organic salts are used as preservatives in food products. They prevent spoilage by inhibiting the growth of bacteria and fungi. Calcium and sodium propionate, for example, are added to processed cheese and bakery goods; sodium benzoate is added to cider, jellies, pickles, and syrups; and sodium sorbate and potassium sorbate are added to fruit juices, sauerkraut, soft drinks, and wine. Look for them on ingredient labels the next time you shop for groceries.<\/p>\n<div class=\"informalfigure large\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/21152705\/cbac8bd93df2c08c1bfef6ca665bcd8e.jpg\" alt=\"image\" \/><\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch15_s05_qs03\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<div id=\"gob-ch15_s05_qs03\" class=\"qandaset block\">\n<h3 class=\"title\">Concept Review Exercises<\/h3>\n<ol id=\"gob-ch15_s05_qs03_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch15_s05_qs03_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs03_p01\" class=\"para\">How does the neutralization of a carboxylic acid differ from that of an inorganic acid? How are they similar?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch15_s05_qs03_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs03_p03\" class=\"para\">What products are formed when a carboxylic acid is neutralized with a strong base? What additional product is formed when a carboxylic acid is neutralized with a carbonate or a bicarbonate compound?<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch15_s05_qs03_ans\" class=\"qandaset block\">\n<div class=\"answer\">\n<p id=\"gob-ch15_s05_qs03_p02_ans\" class=\"para\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q889280\">Show Answer<\/span><\/p>\n<div id=\"q889280\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li class=\"para\">Similar: acid + base produces water + a salt.\u00a0 Different: Insoluble carboxylic acids often form soluble carboxylate salts.<\/li>\n<li class=\"para\">Both form a carboxylate salt and water; With a carbonate or bicarbonate compound, carbon dioxide is also formed.<\/div>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch15_s05_n10\" class=\"key_takeaways editable block\">\n<div class=\"textbox key-takeaways\">\n<h3 class=\"title\">Key Takeaways<\/h3>\n<ul id=\"gob-ch15_s05_l09\" class=\"itemizedlist\">\n<li>Soluble carboxylic acids are weak acids in aqueous solutions.<\/li>\n<li>Carboxylic acids neutralize bases, forming carboxylate\u00a0 salts.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div id=\"gob-ch15_s05_qs04\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<div id=\"gob-ch15_s05_qs04\" class=\"qandaset block\">\n<h3 class=\"title\">Exercises<\/h3>\n<ol id=\"gob-ch15_s05_qs04_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch15_s05_qs04_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs04_p01\" class=\"para\">Write the equation for the ionization of CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>COOH in water.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch15_s05_qs04_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs04_p03\" class=\"para\">Write the equation for the neutralization of CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>COOH with sodium hydroxide [NaOH(aq)].<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch15_s05_qs04_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs04_p05\" class=\"para\">Write the equation for the reaction of CH<sub class=\"subscript\">3<\/sub>COOH with sodium carbonate [Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(aq)].<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch15_s05_qs04_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs04_p07\" class=\"para\">Write the equation for the reaction of CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>COOH with sodium bicarbonate [NaHCO<sub class=\"subscript\">3<\/sub>(aq)].<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch15_s05_qs04_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs04_p09\" class=\"para\">Write the equation for the ionization of propanoic acid in water.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch15_s05_qs04_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs04_p11\" class=\"para\">Write the equation for the ionization of \u03b3-chloropentanoic acid in water.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch15_s05_qs04_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs04_p13\" class=\"para\">Write an equation for the reaction of butanoic acid with each compound.<\/p>\n<ol id=\"gob-ch15_s05_qs04_l01\" class=\"orderedlist\">\n<li>aqueous NaOH<\/li>\n<li>aqueous NaHCO<sub class=\"subscript\">3<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch15_s05_qs04_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs04_p14\" class=\"para\">Write the condensed structural formula for each compound.<\/p>\n<ol id=\"gob-ch15_s05_qs04_l03\" class=\"orderedlist\">\n<li>potassium acetate<\/li>\n<li>calcium propanoate<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch15_s05_qs04_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch15_s05_qs04_p15\" class=\"para\">Name each compound.<\/p>\n<ol id=\"gob-ch15_s05_qs04_l05\" class=\"orderedlist\">\n<li>CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>COO<sup class=\"superscript\">\u2212<\/sup>Li<sup class=\"superscript\">+<\/sup><\/li>\n<li>CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>COO<sup class=\"superscript\">\u2212<\/sup>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch15_s05_qs04_ans\" class=\"qandaset block\">\n<div class=\"answer\">\n<p id=\"gob-ch15_s05_qs04_p02_ans\" class=\"para\">\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q748043\">Show Answer<\/span><\/p>\n<div id=\"q748043\" class=\"hidden-answer\" style=\"display: none\">\n<p class=\"para\">1. CH<sub>3<\/sub>CH<sub>2<\/sub>CH<sub>2<\/sub>COOH(aq) + H<sub>2<\/sub>O(\u2113) \u2192 CH<sub>3<\/sub>CH<sub>2<\/sub>CH<sub>2<\/sub>COO<sup>\u2212<\/sup>(aq) + H<sub>3<\/sub>O<sup>+<\/sup>(aq) (Note: should be double arrow.\u00a0 MK)<\/p>\n<p class=\"para\">3. 2CH<sub>3<\/sub>COOH + Na<sub>2<\/sub>CO<sub>3<\/sub>(aq) \u2192 2CH<sub>3<\/sub>COO<sup>\u2212<\/sup>Na<sup>+<\/sup>(aq) + H<sub>2<\/sub>O(\u2113) + CO<sub>2<\/sub>(g)<\/p>\n<p class=\"para\">5. CH<sub>3<\/sub>CH<sub>2<\/sub>COOH(aq) + H<sub>2<\/sub>O(\u2113) \u2192 CH<sub>3<\/sub>CH<sub>2<\/sub>COO<sup>\u2212<\/sup>(aq) + H<sub>3<\/sub>O<sup>+<\/sup>(aq)\u00a0 (Note: should be double arrow.\u00a0 MK)<\/p>\n<p class=\"para\">7. a. CH<sub>3<\/sub>CH<sub>2<\/sub>CH<sub>2<\/sub>COOH(aq) + NaOH(aq) \u2192 CH<sub>3<\/sub>CH<sub>2<\/sub>CH<sub>2<\/sub>COO\u2212Na+(aq) + H<sub>2<\/sub>O(\u2113)<\/p>\n<p class=\"para\">b. CH<sub>3<\/sub>(CH<sub>2<\/sub>)<sub>2<\/sub>COOH + NaHCO<sub>3<\/sub>(aq) \u2192 CH<sub>3<\/sub>(CH<sub>2<\/sub>)COO<sup>\u2212<\/sup>Na<sup>+<\/sup>(aq) + H<sub>2<\/sub>O(\u2113) + CO<sub>2<\/sub>(g)<\/p>\n<p class=\"para\">9. a. lithium butyrate (common)\u00a0 lithium butanoate (IUPAC)<\/p>\n<p class=\"para\">b. ammonium butanoate \u00a0(IUPAC) or ammonium butyrate\u00a0(common) <\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1564\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>The Basics of General, Organic, and Biological Chemistry v. 1.0. <strong>Provided by<\/strong>: Saylor Academy. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\">https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc\/4.0\/\">CC BY-NC: Attribution-NonCommercial<\/a><\/em>. <strong>License Terms<\/strong>: This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work&#039;s original creator or licensor.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":53384,"menu_order":6,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"The Basics of General, Organic, and Biological Chemistry v. 1.0\",\"author\":\"\",\"organization\":\"Saylor Academy\",\"url\":\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc\",\"license_terms\":\"This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work\\'s original creator or licensor.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1564","chapter","type-chapter","status-publish","hentry"],"part":1500,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/1564","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/users\/53384"}],"version-history":[{"count":8,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/1564\/revisions"}],"predecessor-version":[{"id":3538,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/1564\/revisions\/3538"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/parts\/1500"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/1564\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/media?parent=1564"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=1564"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/contributor?post=1564"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/license?post=1564"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}