{"id":237,"date":"2018-03-19T16:07:27","date_gmt":"2018-03-19T16:07:27","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/chapter\/ionic-nomenclature\/"},"modified":"2018-08-08T16:54:38","modified_gmt":"2018-08-08T16:54:38","slug":"ionic-nomenclature","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/chapter\/ionic-nomenclature\/","title":{"raw":"3.4 Ionic Nomenclature","rendered":"3.4 Ionic Nomenclature"},"content":{"raw":"<div id=\"book-content\">\r\n<div id=\"gob-ch03_s04\" class=\"section\" xml:lang=\"en\">\r\n<div id=\"gob-ch03_s04_n01\" class=\"learning_objectives editable block\">\r\n<div class=\"textbox learning-objectives\" style=\"text-align: left\">\r\n<h3>Learning Objectives<\/h3>\r\n1. Use the rules for naming ionic compounds.\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_s01\" class=\"section\">\r\n<h2 class=\"title editable block\">Naming Ions<\/h2>\r\n<strong>Naming the Cation<\/strong>\r\n<p id=\"gob-ch03_s04_s01_p01\" class=\"para editable block\">The name of a monatomic cation is simply the name of the element followed by the word <em class=\"emphasis\">ion<\/em>. Thus, Na<sup class=\"superscript\">+<\/sup> is the sodium ion, Al<sup class=\"superscript\">3+<\/sup> is the aluminum ion, Ca<sup class=\"superscript\">2+<\/sup> is the calcium ion, and so forth.\u00a0 Metals ions from Group 1 always have a 1<sup>+<\/sup> charge, metals ions from Group 2 always have a 2<sup>+ <\/sup>charge, the only aluminum ion is 3<sup>+<\/sup>, zinc ions are\u00a0 2<sup>+<\/sup>, and silver ions are 1<sup>+<\/sup>.\u00a0 These are the <strong>fixed-charge metals<\/strong>.\u00a0 The names for fixed-charge metal ions must <em>never<\/em> be given a Roman numeral.<\/p>\r\n<p id=\"gob-ch03_s04_s01_p02\" class=\"para editable block\">Metals that can have several different charges as ions are referred to as <strong>variable-charge metals.\u00a0 <\/strong>Almost all transition metals plus the metals under the staircase are variable-charge metals. Iron, for example, can form two different cations, each of which, when combined with the same anion, makes a different compound with unique physical and chemical properties.\u00a0 For example, FeCl<sub>2<\/sub> and FeCl<sub>3<\/sub> differ in density, melting point, solubility, and color.\u00a0 Thus, we need a different name for each iron ion to distinguish Fe<sup class=\"superscript\">2+<\/sup> from Fe<sup class=\"superscript\">3+<\/sup>. The same issue arises for all of the variable-charge metals.<\/p>\r\n<p id=\"gob-ch03_s04_s01_p03\" class=\"para editable block\">\u00a0In the modern approach to naming compounds containing variable-charge metals, called the <span class=\"margin_term\"><strong><span class=\"glossterm\">Stock system<\/span><\/strong><\/span>, a variable-charge metal ion\u2019s positive charge is indicated by a Roman numeral in parentheses after the element name, followed by the word <em class=\"emphasis\">ion<\/em>. Thus, Fe<sup class=\"superscript\">2+<\/sup> is called the iron(II) ion, while Fe<sup class=\"superscript\">3+<\/sup> is called the iron(III) ion. The names for variable-charge metals must <em>always<\/em> be given a Roman numeral.<\/p>\r\n<p class=\"para editable block\">An older system used the endings -ic for when the metal had the larger of its possible negative charges and -ous for when the metal had the smaller of its possible negative charges instead of the Roman numerals.\u00a0 We will not use this older system.<\/p>\r\n<strong>Naming the Anion<\/strong>\r\n<p id=\"gob-ch03_s04_s01_p05\" class=\"para editable block\">The name of a monatomic anion consists of the stem of the element name, the suffix -<em class=\"emphasis\">ide<\/em>, and then the word <em class=\"emphasis\">ion<\/em>. Thus, as we have already seen, Cl<sup class=\"superscript\">\u2212<\/sup> is \u201cchlor-\u201d + \u201c-ide ion,\u201d or the chloride ion. Similarly, O<sup class=\"superscript\">2\u2212<\/sup> is the oxide ion, Se<sup class=\"superscript\">2\u2212<\/sup> is the selenide ion, and so forth. <a class=\"xref\" href=\"#gob-ch03_s04_s01_t02\">Table 3.3 \"Some Monatomic Anions\"<\/a> lists the names of some common monatomic ions.<\/p>\r\n\r\n<div id=\"gob-ch03_s04_s01_t02\" class=\"table block\">\r\n<h5 class=\"title\"><strong><span class=\"title-prefix\">Table 3.3<\/span> Some Monatomic Anions<\/strong><\/h5>\r\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Ion<\/th>\r\n<th>Name<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>F<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>fluoride ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Cl<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>chloride ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Br<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>bromide ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>I<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>iodide ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>O<sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<td>oxide ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>S<sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<td>sulfide ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>P<sup class=\"superscript\">3\u2212<\/sup><\/td>\r\n<td>phosphide ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>N<sup class=\"superscript\">3\u2212<\/sup><\/td>\r\n<td>nitride ion<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<p id=\"gob-ch03_s04_s01_p06\" class=\"para editable block\">The polyatomic ions have their own characteristic names, as we saw in <a class=\"xref\" href=\"gob-ch03_s03#gob-ch03_s03_s01_t01\">Table 3.1 \"Some Polyatomic Ions\"<\/a>.<\/p>\r\n\r\n<div id=\"gob-ch03_s04_s01_n01\" class=\"exercises editable block\">\r\n<h3 class=\"title\">Example 6<\/h3>\r\n<p id=\"gob-ch03_s04_s01_p07\" class=\"para\">Name each ion.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_s01_l01\" class=\"orderedlist\">\r\n \t<li>Ca<sup class=\"superscript\">2+<\/sup><\/li>\r\n \t<li>S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>SO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup><\/li>\r\n \t<li>Cu<sup class=\"superscript\">+<\/sup><\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution<\/p>\r\n[reveal-answer q=\"964807\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"964807\"]\r\n<ol>\r\n \t<li>the calcium ion<\/li>\r\n \t<li>the sulfide ion (from Table 3.3 \"Some Monatomic Anions\")<\/li>\r\n \t<li>the sulfite ion (from Table 3.1 \"Some Polyatomic Ions\")<\/li>\r\n \t<li>the ammonium ion (from Table 3.1 \"Some Polyatomic Ions\")<\/li>\r\n \t<li>the copper(I) ion : Copper can form cations with either a 1+ or 2+ charge, so we have to specify the charge by using a Roman numeral.)[\/hidden-answer]<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_qs01\" class=\"qandaset block\">\r\n<div class=\"question\">\r\n<div class=\"textbox exercises\">\r\n<h3>SKill Building Exercise<\/h3>\r\nName each Ion\r\n<div class=\"question\">\r\n<ol>\r\n \t<li>Fe<sup>2+<\/sup><\/li>\r\n \t<li id=\"gob-ch03_s04_qs01_p04\" class=\"para\">Fe<sup class=\"superscript\">3+<\/sup><\/li>\r\n \t<li class=\"para\">SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li class=\"para\">Ba<sup class=\"superscript\" style=\"text-align: initial\">2+<\/sup><\/li>\r\n \t<li class=\"para\">HCO<sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><sup>-<\/sup><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_s01_n03\" class=\"exercises editable block\">\r\n<h3 class=\"title\">Example 7<\/h3>\r\n<p id=\"gob-ch03_s04_s01_p14\" class=\"para\">Write the formula for each ion.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_s01_l04\" class=\"orderedlist\">\r\n \t<li>the bromide ion<\/li>\r\n \t<li>the phosphate ion<\/li>\r\n \t<li>the copper 1<sup>+<\/sup> ion<\/li>\r\n \t<li>the magnesium ion<\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution[reveal-answer q=\"634959\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"634959\"]<\/p>\r\n\r\n<ol>\r\n \t<li>Br<sup>\u2212<\/sup><\/li>\r\n \t<li>PO<sub>4<\/sub><sup>3\u2212<\/sup><\/li>\r\n \t<li>Cu<sup>1+ <\/sup><\/li>\r\n \t<li>Mg<sup>2+<\/sup>[\/hidden-answer]<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_qs02\" class=\"qandaset block\">\r\n<div class=\"question\">\r\n<div class=\"textbox exercises\">\r\n<div id=\"gob-ch03_s04_s01\" class=\"section\">\r\n<div id=\"gob-ch03_s04_qs02\" class=\"qandaset block\">\r\n<div class=\"question\">\r\n<h3>SKILL-BUILDING EXERCISE<\/h3>\r\n<p id=\"gob-ch03_s04_qs02_p02\" class=\"para\">Write the formula for each ion.<\/p>\r\n\r\n<ol>\r\n \t<li class=\"para\">the fluoride ion<\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">the carbonate ion<\/span><\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">the tin<sup>4+<\/sup> ion<\/span><\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">the potassium ion<\/span><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<h3 id=\"gob-ch03_s04_qs02_p02\" class=\"para\"><span style=\"color: #077fab;font-size: 1.15em;font-weight: 600\">Naming Compounds<\/span><\/h3>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_s02\" class=\"section\">\r\n<p id=\"gob-ch03_s04_s02_p01\" class=\"para editable block\">Now that we know how to name ions, we are ready to name ionic compounds. We do so by placing the name of the cation first, followed by the name of the anion, and dropping the word <em class=\"emphasis\">ion<\/em> from both parts.<\/p>\r\n<p id=\"gob-ch03_s04_s02_p02\" class=\"para editable block\">For example, what is the name of the compound whose formula is Ba(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>?<\/p>\r\n\r\n<div id=\"fwk-gob-eq03_008\" class=\"informalfigure large block\"><img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/19160722\/fdbb7b949259eb63e08a13576430e0a1.jpg\" alt=\"image\" \/><\/div>\r\n<p id=\"gob-ch03_s04_s02_p03\" class=\"para editable block\">The compound\u2019s name does not indicate that there are two nitrate ions for every barium ion. You must determine the relative numbers of ions by balancing the positive and negative charges.<\/p>\r\n<p id=\"gob-ch03_s04_s02_p04\" class=\"para editable block\">If you are given a formula for an ionic compound whose cation can have more than one possible charge, you must first determine the charge on the cation before identifying its correct name. For example, consider FeCl<sub class=\"subscript\">2<\/sub> and FeCl<sub class=\"subscript\">3<\/sub>. In the first compound, the iron ion has a 2<sup>+<\/sup> charge because there are two Cl<sup class=\"superscript\">\u2212<\/sup> ions in the formula (1<sup>\u2212<\/sup> charge on each chloride ion). In the second compound, the iron ion has a 3<sup>+<\/sup> charge, as indicated by the three Cl<sup class=\"superscript\">\u2212<\/sup> ions in the formula. These are two different compounds that need two different names. By the Stock system, the names are iron(II) chloride and iron(III) chloride.<\/p>\r\n\r\n<div id=\"gob-ch03_s04_s02_n01\" class=\"exercises editable block\">\r\n<h3 class=\"title\">Example 8<\/h3>\r\n<p id=\"gob-ch03_s04_s02_p05\" class=\"para\">Name each ionic compound.\u00a0 Use Roman numerals <em>only<\/em> when needed.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_s02_l01\" class=\"orderedlist\">\r\n \t<li>Ca<sub class=\"subscript\">3<\/sub>(PO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\r\n \t<li>(NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><\/li>\r\n \t<li>KCl<\/li>\r\n \t<li>CuCl<\/li>\r\n \t<li>SnF<sub class=\"subscript\">2<\/sub><\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution<\/p>\r\n[reveal-answer q=\"167230\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"167230\"]\r\n<ol>\r\n \t<li>calcium phosphate<\/li>\r\n \t<li>ammonium dichromate (the prefix di- is part of the name of the anion, as in Table 3.1 \"Some Polyatomic Ions\")<\/li>\r\n \t<li>potassium chloride<\/li>\r\n \t<li>copper(I) chloride<\/li>\r\n \t<li>tin(II) fluoride [\/hidden-answer]<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_qs03\" class=\"qandaset block\">\r\n<div class=\"question\">\r\n<div class=\"textbox exercises\">\r\n<h3>Skill-building Exercise<\/h3>\r\n<div class=\"question\">\r\n\r\nName each ionic compound. Use Roman numerals\u00a0<em>only<\/em> when neccessary.\r\n<ol>\r\n \t<li id=\"gob-ch03_s04_qs03_p02\" class=\"para\">ZnBr<sub class=\"subscript\">2<\/sub><\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">Fe(NO<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><span style=\"font-size: 1rem;text-align: initial\">)<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">Al<\/span><sub class=\"subscript\" style=\"text-align: initial\">2<\/sub><span style=\"font-size: 1rem;text-align: initial\">O<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">AuF<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">AgF<\/span><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<p id=\"gob-ch03_s04_s02_p12\" class=\"para editable block\"><a class=\"xref\" href=\"#gob-ch03_s04_s02_f01\">Figure 3.7 \"A Guide to Naming Simple Ionic Compounds\"<\/a> is a synopsis of how to name simple ionic compounds.<\/p>\r\n\r\n<div id=\"gob-ch03_s04_s02_f01\" class=\"figure full editable block\">\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"2076\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/19160725\/d24d77cd393891859fe7d1df57665927.jpg\" alt=\"image\" width=\"2076\" height=\"1076\" \/> <em>Figure 3.7 A Guide to Naming Simple Ionic Compounds.\u00a0<\/em>Follow these steps to name a simple ionic compound.[\/caption]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<h3 class=\"title\">Concept Review Exercises<\/h3>\r\n<div class=\"question\">\r\n<ol>\r\n \t<li class=\"para\">Briefly describe the process for naming an ionic compound.<\/li>\r\n \t<li class=\"para\">In what order do the names of ions appear in the names of ionic compounds?<\/li>\r\n \t<li class=\"para\">When do you need a Roman numeral in the name of an ionic compound? Give an example.\u00a0 When are you not allowed to have a Roman numeral in an ion compound name?<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"question\">\r\n\r\n&nbsp;\r\n<h3>ANswers<\/h3>\r\n[reveal-answer q=\"432731\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"432731\"]\r\n<ol>\r\n \t<li>Name the cation and then the anion.<\/li>\r\n \t<li>the cation name followed by the anion name<\/li>\r\n \t<li>An ionic compound in which the metal cation can have more than one possible charge must have a Roman numeral. For example FeCl<sub>3<\/sub> is iron(III) chloride but FeCl<sub>2<\/sub> is iron(II) chloride.\u00a0 Metals that always have the same charge as a cation\u00a0 are not given a Roman numeral,\u00a0 For example MgCl<sub>2<\/sub> is simply magnesium chloride because the magnesium ion is always Mg<sup>2<\/sup> .\u00a0[\/hidden-answer]\r\n<div class=\"answer\"><\/div><\/li>\r\n<\/ol>\r\n<div id=\"gob-ch03_s04_qs04_ans\" class=\"qandaset block\"><\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch03_s04\" class=\"section\" xml:lang=\"en\">\r\n<div id=\"gob-ch03_s04_s02\" class=\"section\">\r\n<div id=\"gob-ch03_s04_s02_n04\" class=\"key_takeaways editable block\">\r\n<div class=\"textbox key-takeaways\">\r\n<h3>Key Takeaway<\/h3>\r\n<ul id=\"gob-ch03_s04_s02_l05\" class=\"itemizedlist\">\r\n \t<li>Each ionic compound has its own unique name that comes from the names of the ions.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_qs05\" class=\"qandaset block\">\r\n<div class=\"question\">\r\n<div class=\"textbox exercises\">\r\n<h3>Exercises<\/h3>\r\n<div id=\"gob-ch03_s04_qs05\" class=\"qandaset block\">\r\n<ol id=\"gob-ch03_s04_qs05_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p01\" class=\"para\">Name each ion.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l01\" class=\"orderedlist\">\r\n \t<li>Ra<sup class=\"superscript\">2+<\/sup><\/li>\r\n \t<li>P<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>H<sub class=\"subscript\">2<\/sub>PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Sn<sup class=\"superscript\">4+<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p02\" class=\"para\">Name each ion.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l03\" class=\"orderedlist\">\r\n \t<li>Cs<sup class=\"superscript\">+<\/sup><\/li>\r\n \t<li>As<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>HSO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Sn<sup class=\"superscript\">2+<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p03\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l05\" class=\"orderedlist\">\r\n \t<li>Na<sup class=\"superscript\">+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p04\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l07\" class=\"orderedlist\">\r\n \t<li>K<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup> and Se<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p05\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l09\" class=\"orderedlist\">\r\n \t<li>Na<sup class=\"superscript\">+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Al<sup class=\"superscript\">3+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa06\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p06\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l11\" class=\"orderedlist\">\r\n \t<li>Li<sup class=\"superscript\">+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup> and P<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Li<sup class=\"superscript\">+<\/sup> and P<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa07\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p07\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l13\" class=\"orderedlist\">\r\n \t<li>Fe<sup class=\"superscript\">3+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Fe<sup class=\"superscript\">2+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Au<sup class=\"superscript\">3+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Au<sup class=\"superscript\">+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa08\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p08\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l15\" class=\"orderedlist\">\r\n \t<li>Cr<sup class=\"superscript\">3+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Cr<sup class=\"superscript\">2+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Pb<sup class=\"superscript\">2+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Pb<sup class=\"superscript\">4+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa09\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p09\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l17\" class=\"orderedlist\">\r\n \t<li>Cr<sup class=\"superscript\">3+<\/sup> and NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Fe<sup class=\"superscript\">2+<\/sup> and PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Ca<sup class=\"superscript\">2+<\/sup> and CrO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Al<sup class=\"superscript\">3+<\/sup> and OH<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa10\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p10\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l19\" class=\"orderedlist\">\r\n \t<li>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>H<sup class=\"superscript\">+<\/sup> and Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Cu<sup class=\"superscript\">+<\/sup> and CO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Na<sup class=\"superscript\">+<\/sup> and HCO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa11\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p11\" class=\"para\">Name each compound.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l21\" class=\"orderedlist\">\r\n \t<li>Al(HSO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\r\n \t<li>Mn(HSO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa11\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p11\" class=\"para\">Name each compound.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l21\" class=\"orderedlist\">\r\n \t<li>Co(HCO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\r\n \t<li>LiHCO<sub class=\"subscript\">3<\/sub><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n<\/ol>\r\n<div class=\"question\">\r\n<h3>answers<\/h3>\r\n<\/div>\r\n[reveal-answer q=\"645823\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"645823\"]\r\n\r\n1. a. the radium ion\r\n\r\nb.the phosphide ion\r\n\r\nc. the dihydrogen phosphate ion\r\n\r\nd. the tin(IV) ion\r\n\r\n&nbsp;\r\n\r\n3. a. sodium bromide\r\n\r\nb. magnesium bromide\r\n\r\nc. magnesium sulfide\r\n\r\n&nbsp;\r\n\r\n5. a. sodium nitride\r\n\r\nb. magnesium nitride\r\n\r\nc. aluminum sulfide\r\n\r\n&nbsp;\r\n\r\n7. a. iron(III) bromide\r\n\r\nb.iron(II) bromide\r\n\r\nc. gold(III) sulfide\r\n\r\nd. gold(I) sulfide\r\n\r\n&nbsp;\r\n\r\n9. a. chromium(III) nitrate\r\n\r\nb. iron(II) phosphate\r\n\r\nc. calcium chromate\r\n\r\nd. aluminum hydroxide\r\n\r\n&nbsp;\r\n\r\n11. a. aluminum hydrogen sulfate or aluminum bisulfate\r\n\r\nb. magnesium hydrogen sulfate or magnesium bisulfate[\/hidden-answer]<span style=\"background-color: #ccd7dd;color: #000000;font-size: 1.2em;font-weight: 600;text-align: center\">\u00a0<\/span>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"book-content\">\n<div id=\"gob-ch03_s04\" class=\"section\" xml:lang=\"en\">\n<div id=\"gob-ch03_s04_n01\" class=\"learning_objectives editable block\">\n<div class=\"textbox learning-objectives\" style=\"text-align: left\">\n<h3>Learning Objectives<\/h3>\n<p>1. Use the rules for naming ionic compounds.<\/p>\n<\/div>\n<\/div>\n<div id=\"gob-ch03_s04_s01\" class=\"section\">\n<h2 class=\"title editable block\">Naming Ions<\/h2>\n<p><strong>Naming the Cation<\/strong><\/p>\n<p id=\"gob-ch03_s04_s01_p01\" class=\"para editable block\">The name of a monatomic cation is simply the name of the element followed by the word <em class=\"emphasis\">ion<\/em>. Thus, Na<sup class=\"superscript\">+<\/sup> is the sodium ion, Al<sup class=\"superscript\">3+<\/sup> is the aluminum ion, Ca<sup class=\"superscript\">2+<\/sup> is the calcium ion, and so forth.\u00a0 Metals ions from Group 1 always have a 1<sup>+<\/sup> charge, metals ions from Group 2 always have a 2<sup>+ <\/sup>charge, the only aluminum ion is 3<sup>+<\/sup>, zinc ions are\u00a0 2<sup>+<\/sup>, and silver ions are 1<sup>+<\/sup>.\u00a0 These are the <strong>fixed-charge metals<\/strong>.\u00a0 The names for fixed-charge metal ions must <em>never<\/em> be given a Roman numeral.<\/p>\n<p id=\"gob-ch03_s04_s01_p02\" class=\"para editable block\">Metals that can have several different charges as ions are referred to as <strong>variable-charge metals.\u00a0 <\/strong>Almost all transition metals plus the metals under the staircase are variable-charge metals. Iron, for example, can form two different cations, each of which, when combined with the same anion, makes a different compound with unique physical and chemical properties.\u00a0 For example, FeCl<sub>2<\/sub> and FeCl<sub>3<\/sub> differ in density, melting point, solubility, and color.\u00a0 Thus, we need a different name for each iron ion to distinguish Fe<sup class=\"superscript\">2+<\/sup> from Fe<sup class=\"superscript\">3+<\/sup>. The same issue arises for all of the variable-charge metals.<\/p>\n<p id=\"gob-ch03_s04_s01_p03\" class=\"para editable block\">\u00a0In the modern approach to naming compounds containing variable-charge metals, called the <span class=\"margin_term\"><strong><span class=\"glossterm\">Stock system<\/span><\/strong><\/span>, a variable-charge metal ion\u2019s positive charge is indicated by a Roman numeral in parentheses after the element name, followed by the word <em class=\"emphasis\">ion<\/em>. Thus, Fe<sup class=\"superscript\">2+<\/sup> is called the iron(II) ion, while Fe<sup class=\"superscript\">3+<\/sup> is called the iron(III) ion. The names for variable-charge metals must <em>always<\/em> be given a Roman numeral.<\/p>\n<p class=\"para editable block\">An older system used the endings -ic for when the metal had the larger of its possible negative charges and -ous for when the metal had the smaller of its possible negative charges instead of the Roman numerals.\u00a0 We will not use this older system.<\/p>\n<p><strong>Naming the Anion<\/strong><\/p>\n<p id=\"gob-ch03_s04_s01_p05\" class=\"para editable block\">The name of a monatomic anion consists of the stem of the element name, the suffix &#8211;<em class=\"emphasis\">ide<\/em>, and then the word <em class=\"emphasis\">ion<\/em>. Thus, as we have already seen, Cl<sup class=\"superscript\">\u2212<\/sup> is \u201cchlor-\u201d + \u201c-ide ion,\u201d or the chloride ion. Similarly, O<sup class=\"superscript\">2\u2212<\/sup> is the oxide ion, Se<sup class=\"superscript\">2\u2212<\/sup> is the selenide ion, and so forth. <a class=\"xref\" href=\"#gob-ch03_s04_s01_t02\">Table 3.3 &#8220;Some Monatomic Anions&#8221;<\/a> lists the names of some common monatomic ions.<\/p>\n<div id=\"gob-ch03_s04_s01_t02\" class=\"table block\">\n<h5 class=\"title\"><strong><span class=\"title-prefix\">Table 3.3<\/span> Some Monatomic Anions<\/strong><\/h5>\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\n<thead>\n<tr>\n<th>Ion<\/th>\n<th>Name<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>F<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>fluoride ion<\/td>\n<\/tr>\n<tr>\n<td>Cl<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>chloride ion<\/td>\n<\/tr>\n<tr>\n<td>Br<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>bromide ion<\/td>\n<\/tr>\n<tr>\n<td>I<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>iodide ion<\/td>\n<\/tr>\n<tr>\n<td>O<sup class=\"superscript\">2\u2212<\/sup><\/td>\n<td>oxide ion<\/td>\n<\/tr>\n<tr>\n<td>S<sup class=\"superscript\">2\u2212<\/sup><\/td>\n<td>sulfide ion<\/td>\n<\/tr>\n<tr>\n<td>P<sup class=\"superscript\">3\u2212<\/sup><\/td>\n<td>phosphide ion<\/td>\n<\/tr>\n<tr>\n<td>N<sup class=\"superscript\">3\u2212<\/sup><\/td>\n<td>nitride ion<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p id=\"gob-ch03_s04_s01_p06\" class=\"para editable block\">The polyatomic ions have their own characteristic names, as we saw in <a class=\"xref\" href=\"gob-ch03_s03#gob-ch03_s03_s01_t01\">Table 3.1 &#8220;Some Polyatomic Ions&#8221;<\/a>.<\/p>\n<div id=\"gob-ch03_s04_s01_n01\" class=\"exercises editable block\">\n<h3 class=\"title\">Example 6<\/h3>\n<p id=\"gob-ch03_s04_s01_p07\" class=\"para\">Name each ion.<\/p>\n<ol id=\"gob-ch03_s04_s01_l01\" class=\"orderedlist\">\n<li>Ca<sup class=\"superscript\">2+<\/sup><\/li>\n<li>S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>SO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup><\/li>\n<li>Cu<sup class=\"superscript\">+<\/sup><\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q964807\">Show Answer<\/span><\/p>\n<div id=\"q964807\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>the calcium ion<\/li>\n<li>the sulfide ion (from Table 3.3 &#8220;Some Monatomic Anions&#8221;)<\/li>\n<li>the sulfite ion (from Table 3.1 &#8220;Some Polyatomic Ions&#8221;)<\/li>\n<li>the ammonium ion (from Table 3.1 &#8220;Some Polyatomic Ions&#8221;)<\/li>\n<li>the copper(I) ion : Copper can form cations with either a 1+ or 2+ charge, so we have to specify the charge by using a Roman numeral.)<\/div>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch03_s04_qs01\" class=\"qandaset block\">\n<div class=\"question\">\n<div class=\"textbox exercises\">\n<h3>SKill Building Exercise<\/h3>\n<p>Name each Ion<\/p>\n<div class=\"question\">\n<ol>\n<li>Fe<sup>2+<\/sup><\/li>\n<li id=\"gob-ch03_s04_qs01_p04\" class=\"para\">Fe<sup class=\"superscript\">3+<\/sup><\/li>\n<li class=\"para\">SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li class=\"para\">Ba<sup class=\"superscript\" style=\"text-align: initial\">2+<\/sup><\/li>\n<li class=\"para\">HCO<sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><sup>&#8211;<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch03_s04_s01_n03\" class=\"exercises editable block\">\n<h3 class=\"title\">Example 7<\/h3>\n<p id=\"gob-ch03_s04_s01_p14\" class=\"para\">Write the formula for each ion.<\/p>\n<ol id=\"gob-ch03_s04_s01_l04\" class=\"orderedlist\">\n<li>the bromide ion<\/li>\n<li>the phosphate ion<\/li>\n<li>the copper 1<sup>+<\/sup> ion<\/li>\n<li>the magnesium ion<\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q634959\">Show Answer<\/span><\/p>\n<div id=\"q634959\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>Br<sup>\u2212<\/sup><\/li>\n<li>PO<sub>4<\/sub><sup>3\u2212<\/sup><\/li>\n<li>Cu<sup>1+ <\/sup><\/li>\n<li>Mg<sup>2+<\/sup><\/div>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch03_s04_qs02\" class=\"qandaset block\">\n<div class=\"question\">\n<div class=\"textbox exercises\">\n<div id=\"gob-ch03_s04_s01\" class=\"section\">\n<div id=\"gob-ch03_s04_qs02\" class=\"qandaset block\">\n<div class=\"question\">\n<h3>SKILL-BUILDING EXERCISE<\/h3>\n<p id=\"gob-ch03_s04_qs02_p02\" class=\"para\">Write the formula for each ion.<\/p>\n<ol>\n<li class=\"para\">the fluoride ion<\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">the carbonate ion<\/span><\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">the tin<sup>4+<\/sup> ion<\/span><\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">the potassium ion<\/span><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<h3 id=\"gob-ch03_s04_qs02_p02\" class=\"para\"><span style=\"color: #077fab;font-size: 1.15em;font-weight: 600\">Naming Compounds<\/span><\/h3>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch03_s04_s02\" class=\"section\">\n<p id=\"gob-ch03_s04_s02_p01\" class=\"para editable block\">Now that we know how to name ions, we are ready to name ionic compounds. We do so by placing the name of the cation first, followed by the name of the anion, and dropping the word <em class=\"emphasis\">ion<\/em> from both parts.<\/p>\n<p id=\"gob-ch03_s04_s02_p02\" class=\"para editable block\">For example, what is the name of the compound whose formula is Ba(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>?<\/p>\n<div id=\"fwk-gob-eq03_008\" class=\"informalfigure large block\"><img decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/19160722\/fdbb7b949259eb63e08a13576430e0a1.jpg\" alt=\"image\" \/><\/div>\n<p id=\"gob-ch03_s04_s02_p03\" class=\"para editable block\">The compound\u2019s name does not indicate that there are two nitrate ions for every barium ion. You must determine the relative numbers of ions by balancing the positive and negative charges.<\/p>\n<p id=\"gob-ch03_s04_s02_p04\" class=\"para editable block\">If you are given a formula for an ionic compound whose cation can have more than one possible charge, you must first determine the charge on the cation before identifying its correct name. For example, consider FeCl<sub class=\"subscript\">2<\/sub> and FeCl<sub class=\"subscript\">3<\/sub>. In the first compound, the iron ion has a 2<sup>+<\/sup> charge because there are two Cl<sup class=\"superscript\">\u2212<\/sup> ions in the formula (1<sup>\u2212<\/sup> charge on each chloride ion). In the second compound, the iron ion has a 3<sup>+<\/sup> charge, as indicated by the three Cl<sup class=\"superscript\">\u2212<\/sup> ions in the formula. These are two different compounds that need two different names. By the Stock system, the names are iron(II) chloride and iron(III) chloride.<\/p>\n<div id=\"gob-ch03_s04_s02_n01\" class=\"exercises editable block\">\n<h3 class=\"title\">Example 8<\/h3>\n<p id=\"gob-ch03_s04_s02_p05\" class=\"para\">Name each ionic compound.\u00a0 Use Roman numerals <em>only<\/em> when needed.<\/p>\n<ol id=\"gob-ch03_s04_s02_l01\" class=\"orderedlist\">\n<li>Ca<sub class=\"subscript\">3<\/sub>(PO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\n<li>(NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><\/li>\n<li>KCl<\/li>\n<li>CuCl<\/li>\n<li>SnF<sub class=\"subscript\">2<\/sub><\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q167230\">Show Answer<\/span><\/p>\n<div id=\"q167230\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>calcium phosphate<\/li>\n<li>ammonium dichromate (the prefix di- is part of the name of the anion, as in Table 3.1 &#8220;Some Polyatomic Ions&#8221;)<\/li>\n<li>potassium chloride<\/li>\n<li>copper(I) chloride<\/li>\n<li>tin(II) fluoride <\/div>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch03_s04_qs03\" class=\"qandaset block\">\n<div class=\"question\">\n<div class=\"textbox exercises\">\n<h3>Skill-building Exercise<\/h3>\n<div class=\"question\">\n<p>Name each ionic compound. Use Roman numerals\u00a0<em>only<\/em> when neccessary.<\/p>\n<ol>\n<li id=\"gob-ch03_s04_qs03_p02\" class=\"para\">ZnBr<sub class=\"subscript\">2<\/sub><\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">Fe(NO<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><span style=\"font-size: 1rem;text-align: initial\">)<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">Al<\/span><sub class=\"subscript\" style=\"text-align: initial\">2<\/sub><span style=\"font-size: 1rem;text-align: initial\">O<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">AuF<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">AgF<\/span><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p id=\"gob-ch03_s04_s02_p12\" class=\"para editable block\"><a class=\"xref\" href=\"#gob-ch03_s04_s02_f01\">Figure 3.7 &#8220;A Guide to Naming Simple Ionic Compounds&#8221;<\/a> is a synopsis of how to name simple ionic compounds.<\/p>\n<div id=\"gob-ch03_s04_s02_f01\" class=\"figure full editable block\">\n<div style=\"width: 2086px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/19160725\/d24d77cd393891859fe7d1df57665927.jpg\" alt=\"image\" width=\"2076\" height=\"1076\" \/><\/p>\n<p class=\"wp-caption-text\"><em>Figure 3.7 A Guide to Naming Simple Ionic Compounds.\u00a0<\/em>Follow these steps to name a simple ionic compound.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<h3 class=\"title\">Concept Review Exercises<\/h3>\n<div class=\"question\">\n<ol>\n<li class=\"para\">Briefly describe the process for naming an ionic compound.<\/li>\n<li class=\"para\">In what order do the names of ions appear in the names of ionic compounds?<\/li>\n<li class=\"para\">When do you need a Roman numeral in the name of an ionic compound? Give an example.\u00a0 When are you not allowed to have a Roman numeral in an ion compound name?<\/li>\n<\/ol>\n<\/div>\n<div class=\"question\">\n<p>&nbsp;<\/p>\n<h3>ANswers<\/h3>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q432731\">Show Answer<\/span><\/p>\n<div id=\"q432731\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>Name the cation and then the anion.<\/li>\n<li>the cation name followed by the anion name<\/li>\n<li>An ionic compound in which the metal cation can have more than one possible charge must have a Roman numeral. For example FeCl<sub>3<\/sub> is iron(III) chloride but FeCl<sub>2<\/sub> is iron(II) chloride.\u00a0 Metals that always have the same charge as a cation\u00a0 are not given a Roman numeral,\u00a0 For example MgCl<sub>2<\/sub> is simply magnesium chloride because the magnesium ion is always Mg<sup>2<\/sup> .\u00a0<\/div>\n<\/div>\n<div class=\"answer\"><\/div>\n<\/li>\n<\/ol>\n<div id=\"gob-ch03_s04_qs04_ans\" class=\"qandaset block\"><\/div>\n<\/div>\n<\/div>\n<div id=\"book-content\">\n<div id=\"gob-ch03_s04\" class=\"section\" xml:lang=\"en\">\n<div id=\"gob-ch03_s04_s02\" class=\"section\">\n<div id=\"gob-ch03_s04_s02_n04\" class=\"key_takeaways editable block\">\n<div class=\"textbox key-takeaways\">\n<h3>Key Takeaway<\/h3>\n<ul id=\"gob-ch03_s04_s02_l05\" class=\"itemizedlist\">\n<li>Each ionic compound has its own unique name that comes from the names of the ions.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div id=\"gob-ch03_s04_qs05\" class=\"qandaset block\">\n<div class=\"question\">\n<div class=\"textbox exercises\">\n<h3>Exercises<\/h3>\n<div id=\"gob-ch03_s04_qs05\" class=\"qandaset block\">\n<ol id=\"gob-ch03_s04_qs05_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch03_s04_qs05_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p01\" class=\"para\">Name each ion.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l01\" class=\"orderedlist\">\n<li>Ra<sup class=\"superscript\">2+<\/sup><\/li>\n<li>P<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>H<sub class=\"subscript\">2<\/sub>PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Sn<sup class=\"superscript\">4+<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p02\" class=\"para\">Name each ion.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l03\" class=\"orderedlist\">\n<li>Cs<sup class=\"superscript\">+<\/sup><\/li>\n<li>As<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>HSO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Sn<sup class=\"superscript\">2+<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p03\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l05\" class=\"orderedlist\">\n<li>Na<sup class=\"superscript\">+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p04\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l07\" class=\"orderedlist\">\n<li>K<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup> and Se<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p05\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l09\" class=\"orderedlist\">\n<li>Na<sup class=\"superscript\">+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Al<sup class=\"superscript\">3+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p06\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l11\" class=\"orderedlist\">\n<li>Li<sup class=\"superscript\">+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup> and P<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Li<sup class=\"superscript\">+<\/sup> and P<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p07\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l13\" class=\"orderedlist\">\n<li>Fe<sup class=\"superscript\">3+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Fe<sup class=\"superscript\">2+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Au<sup class=\"superscript\">3+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Au<sup class=\"superscript\">+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p08\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l15\" class=\"orderedlist\">\n<li>Cr<sup class=\"superscript\">3+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Cr<sup class=\"superscript\">2+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Pb<sup class=\"superscript\">2+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Pb<sup class=\"superscript\">4+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p09\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l17\" class=\"orderedlist\">\n<li>Cr<sup class=\"superscript\">3+<\/sup> and NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Fe<sup class=\"superscript\">2+<\/sup> and PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Ca<sup class=\"superscript\">2+<\/sup> and CrO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Al<sup class=\"superscript\">3+<\/sup> and OH<sup class=\"superscript\">\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa10\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p10\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l19\" class=\"orderedlist\">\n<li>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>H<sup class=\"superscript\">+<\/sup> and Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Cu<sup class=\"superscript\">+<\/sup> and CO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Na<sup class=\"superscript\">+<\/sup> and HCO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa11\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p11\" class=\"para\">Name each compound.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l21\" class=\"orderedlist\">\n<li>Al(HSO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\n<li>Mn(HSO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa11\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p11\" class=\"para\">Name each compound.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l21\" class=\"orderedlist\">\n<li>Co(HCO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\n<li>LiHCO<sub class=\"subscript\">3<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<div class=\"question\">\n<h3>answers<\/h3>\n<\/div>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q645823\">Show Answer<\/span><\/p>\n<div id=\"q645823\" class=\"hidden-answer\" style=\"display: none\">\n<p>1. a. the radium ion<\/p>\n<p>b.the phosphide ion<\/p>\n<p>c. the dihydrogen phosphate ion<\/p>\n<p>d. the tin(IV) ion<\/p>\n<p>&nbsp;<\/p>\n<p>3. a. sodium bromide<\/p>\n<p>b. magnesium bromide<\/p>\n<p>c. magnesium sulfide<\/p>\n<p>&nbsp;<\/p>\n<p>5. a. sodium nitride<\/p>\n<p>b. magnesium nitride<\/p>\n<p>c. aluminum sulfide<\/p>\n<p>&nbsp;<\/p>\n<p>7. a. iron(III) bromide<\/p>\n<p>b.iron(II) bromide<\/p>\n<p>c. gold(III) sulfide<\/p>\n<p>d. gold(I) sulfide<\/p>\n<p>&nbsp;<\/p>\n<p>9. a. chromium(III) nitrate<\/p>\n<p>b. iron(II) phosphate<\/p>\n<p>c. calcium chromate<\/p>\n<p>d. aluminum hydroxide<\/p>\n<p>&nbsp;<\/p>\n<p>11. a. aluminum hydrogen sulfate or aluminum bisulfate<\/p>\n<p>b. magnesium hydrogen sulfate or magnesium bisulfate<\/p><\/div>\n<\/div>\n<p><span style=\"background-color: #ccd7dd;color: #000000;font-size: 1.2em;font-weight: 600;text-align: center\">\u00a0<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-237\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>The Basics of General, Organic, and Biological Chemistry v. 1.0. <strong>Provided by<\/strong>: Saylor Academy. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\">https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc\/4.0\/\">CC BY-NC: Attribution-NonCommercial<\/a><\/em>. <strong>License Terms<\/strong>: This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work&#039;s original creator or licensor.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":53384,"menu_order":5,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"The Basics of General, Organic, and Biological Chemistry v. 1.0\",\"author\":\"\",\"organization\":\"Saylor Academy\",\"url\":\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc\",\"license_terms\":\"This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work\\'s original creator or 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