{"id":248,"date":"2018-03-19T16:08:52","date_gmt":"2018-03-19T16:08:52","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/chapter\/end-of-chapter-material-3\/"},"modified":"2018-08-08T17:28:50","modified_gmt":"2018-08-08T17:28:50","slug":"end-of-chapter-material-3","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/chapter\/end-of-chapter-material-3\/","title":{"raw":"3.6 End-of-Chapter Material","rendered":"3.6 End-of-Chapter Material"},"content":{"raw":"<div id=\"navbar-top\" class=\"navbar\">\r\n<div class=\"textbox shaded\">\r\n<div id=\"navbar-top\" class=\"navbar\">\r\n<h3 class=\"navbar-part left\"><span style=\"color: #6c64ad;font-size: 1.2em;font-weight: 600;background-color: #eeeeee\"><span style=\"color: #6c64ad;font-size: 1.2em;font-weight: 600;background-color: #eeeeee\">Chapter Summary<\/span><\/span><\/h3>\r\n<p id=\"gob-ch03_s06_p01\" class=\"para\"><em class=\"emphasis\">T<span style=\"color: #000000\">o ensure that you understand the material in this chapter, you should review the meanings of the following bold terms and ask yourself how they relate to the topics in the chapter.<\/span><\/em><\/p>\r\n<p id=\"gob-ch03_s06_p02\" class=\"para\"><span style=\"color: #000000\">Atoms combine into compounds by forming <strong class=\"emphasis bold\">chemical bonds<\/strong>. A survey of stable atoms and molecules leads to the <strong class=\"emphasis bold\">octet rule<\/strong>, which says that stable atoms tend to have eight electrons in their outermost, or valence, shell. One way atoms obtain eight electrons in the valence shell is for some atoms to lose electrons while other atoms gain them. When this happens, the atoms take on an electrical charge. Charged atoms are called <strong class=\"emphasis bold\">ions<\/strong>. Ions having opposite charges attract each other. This attraction is called <strong class=\"emphasis bold\">ionic bonding<\/strong>, and the compounds formed are called <strong class=\"emphasis bold\">ionic compounds<\/strong>.<\/span><\/p>\r\n<p id=\"gob-ch03_s06_p03\" class=\"para\"><span style=\"color: #000000\">Positively charged ions are called <strong class=\"emphasis bold\">cations<\/strong>, while negatively charged ions are called <strong class=\"emphasis bold\">anions<\/strong>. The formation of both cations and anions can be illustrated using electron configurations. Because elements in a column of the periodic table have the same valence shell electron configuration, atoms in the same column of the periodic table tend to form ions having the same charge. <strong class=\"emphasis bold\">Electron dot diagrams<\/strong>, or <strong class=\"emphasis bold\">Lewis diagrams<\/strong>, can also be used to illustrate the formation of cations and anions.<\/span><\/p>\r\n<p id=\"gob-ch03_s06_p04\" class=\"para\"><span style=\"color: #000000\">Ionic compounds are represented in writing by a <strong class=\"emphasis bold\">chemical formula<\/strong>, which gives the lowest ratio of cations and anions present in the compound. In a formula, the symbol of the cation is written first, followed by the symbol of the anion. <strong class=\"emphasis bold\">Formula unit<\/strong> is considered the basic unit of an ionic compound because ionic compounds do not exist as discrete units. Instead, they exist as <strong class=\"emphasis bold\">crystals<\/strong>, three-dimensional arrays of ions, with cations surrounded by anions and anions surrounded by cations. Chemical formulas for ionic compounds are determined by balancing the positive charge from the cation(s) with the negative charge from the anion(s). A subscript to the right of the ion indicates that more than one of that ion is present in the chemical formula.<\/span><\/p>\r\n<p id=\"gob-ch03_s06_p05\" class=\"para\"><span style=\"color: #000000\">Some ions are groups of atoms bonded together and having an overall electrical charge. These are called <strong class=\"emphasis bold\">polyatomic ions<\/strong>. Writing formulas with polyatomic ions follows the same rules as with monatomic ions, except that when more than one polyatomic ion is present in a chemical formula, the polyatomic ion is enclosed in parentheses and the subscript is outside the right parenthesis. Ionic compounds typically form between metals and nonmetals or between polyatomic ions.<\/span><\/p>\r\n<p id=\"gob-ch03_s06_p06\" class=\"para\"><span style=\"color: #000000\">Names of ionic compounds are derived from the names of the ions, with the name of the cation coming first, followed by the name of the anion. If an element can form cations of different charges, there are two alternate systems for indicating the compound\u2019s name. In the <strong class=\"emphasis bold\">Stock system<\/strong>, a roman numeral in parentheses indicates the charge on the cation. An example is the name for FeCl<sub class=\"subscript\">2<\/sub>, which is iron(II) chloride.\r\n<\/span><\/p>\r\n<p id=\"gob-ch03_s06_p07\" class=\"para\"><span style=\"color: #000000\">The <strong class=\"emphasis bold\">formula mass<\/strong> of an ionic compound is the sum of the masses of each individual atom in the formula. Care must be taken when calculating formula masses for formulas containing multiple polyatomic ions because the subscript outside the parentheses refers to all the atoms in the polyatomic ion.<\/span><span style=\"color: #6c64ad;font-size: 1.2em;font-weight: 600\">\u00a0<\/span><\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch03_s06\" class=\"section end-of-chapter\" xml:lang=\"en\">\r\n<div id=\"gob-ch03_s06_qs01\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<h3>Additional Exercises<\/h3>\r\n<div id=\"gob-ch03_s06_qs01\" class=\"qandaset block\">Which ion with a 2+ charge has the following electron configuration? 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>\r\n<ol id=\"gob-ch03_s06_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p01\" class=\"para\">What number shell is the valence electron shell of a sodium atom? What number shell is the valence shell of a sodium ion? Explain the difference.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p03\" class=\"para\">What number shell is the valence electron shell of a bromine atom? What number shell is the valence shell of a bromide ion? Explain the difference between these answers and the answers to Exercise 1.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p05\" class=\"para\">What is the electron configuration of each ion?<\/p>\r\n\r\n<ol id=\"gob-ch03_s06_qs01_l01\" class=\"orderedlist\">\r\n \t<li>K<sup class=\"superscript\">+<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup><\/li>\r\n \t<li>F<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p06\" class=\"para\">What is the electron configuration of each ion?<\/p>\r\n\r\n<ol id=\"gob-ch03_s06_qs01_l03\" class=\"orderedlist\">\r\n \t<li>Li<sup class=\"superscript\">+<\/sup><\/li>\r\n \t<li>Ca<sup class=\"superscript\">2+<\/sup><\/li>\r\n \t<li>Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>O<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa07\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p09\" class=\"para\">Use Lewis diagrams and arrows to show the electron transfer that occurs during the formation of an ionic compound among Mg atoms and F atoms. (Hint: how many atoms of each will you need?)<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa08\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p10\" class=\"para\">Use Lewis diagrams and arrows to show the electron transfer that occurs during the formation of an ionic compound among K atoms and O atoms. (Hint: how many atoms of each will you need?)<\/p>\r\n\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p38\" class=\"para\"><\/p>\r\n\r\n<\/div>\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<h3>Answers<\/h3>\r\n[reveal-answer q=\"470410\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"470410\"]\r\n\r\n1. For sodium, the valence shell is the third shell; for the sodium ion, the valence shell is the second shell because it has lost all its third shell electrons.\r\n\r\n3.\r\n<ol id=\"gob-ch03_s06_qs01_l02_ans\" class=\"orderedlist\">\r\n \t<li style=\"list-style-type: none\">\r\n<ol>\r\n \t<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\r\n \t<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\r\n \t<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\r\n \t<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n5.\u00a0 <img class=\"aligncenter\" style=\"font-size: 0.9em\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/19160850\/be5ae655eb277d90fdc6744e062a4ce2.jpg\" alt=\"image\" \/>]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"navbar-top\" class=\"navbar\">\n<div class=\"textbox shaded\">\n<div id=\"navbar-top\" class=\"navbar\">\n<h3 class=\"navbar-part left\"><span style=\"color: #6c64ad;font-size: 1.2em;font-weight: 600;background-color: #eeeeee\"><span style=\"color: #6c64ad;font-size: 1.2em;font-weight: 600;background-color: #eeeeee\">Chapter Summary<\/span><\/span><\/h3>\n<p id=\"gob-ch03_s06_p01\" class=\"para\"><em class=\"emphasis\">T<span style=\"color: #000000\">o ensure that you understand the material in this chapter, you should review the meanings of the following bold terms and ask yourself how they relate to the topics in the chapter.<\/span><\/em><\/p>\n<p id=\"gob-ch03_s06_p02\" class=\"para\"><span style=\"color: #000000\">Atoms combine into compounds by forming <strong class=\"emphasis bold\">chemical bonds<\/strong>. A survey of stable atoms and molecules leads to the <strong class=\"emphasis bold\">octet rule<\/strong>, which says that stable atoms tend to have eight electrons in their outermost, or valence, shell. One way atoms obtain eight electrons in the valence shell is for some atoms to lose electrons while other atoms gain them. When this happens, the atoms take on an electrical charge. Charged atoms are called <strong class=\"emphasis bold\">ions<\/strong>. Ions having opposite charges attract each other. This attraction is called <strong class=\"emphasis bold\">ionic bonding<\/strong>, and the compounds formed are called <strong class=\"emphasis bold\">ionic compounds<\/strong>.<\/span><\/p>\n<p id=\"gob-ch03_s06_p03\" class=\"para\"><span style=\"color: #000000\">Positively charged ions are called <strong class=\"emphasis bold\">cations<\/strong>, while negatively charged ions are called <strong class=\"emphasis bold\">anions<\/strong>. The formation of both cations and anions can be illustrated using electron configurations. Because elements in a column of the periodic table have the same valence shell electron configuration, atoms in the same column of the periodic table tend to form ions having the same charge. <strong class=\"emphasis bold\">Electron dot diagrams<\/strong>, or <strong class=\"emphasis bold\">Lewis diagrams<\/strong>, can also be used to illustrate the formation of cations and anions.<\/span><\/p>\n<p id=\"gob-ch03_s06_p04\" class=\"para\"><span style=\"color: #000000\">Ionic compounds are represented in writing by a <strong class=\"emphasis bold\">chemical formula<\/strong>, which gives the lowest ratio of cations and anions present in the compound. In a formula, the symbol of the cation is written first, followed by the symbol of the anion. <strong class=\"emphasis bold\">Formula unit<\/strong> is considered the basic unit of an ionic compound because ionic compounds do not exist as discrete units. Instead, they exist as <strong class=\"emphasis bold\">crystals<\/strong>, three-dimensional arrays of ions, with cations surrounded by anions and anions surrounded by cations. Chemical formulas for ionic compounds are determined by balancing the positive charge from the cation(s) with the negative charge from the anion(s). A subscript to the right of the ion indicates that more than one of that ion is present in the chemical formula.<\/span><\/p>\n<p id=\"gob-ch03_s06_p05\" class=\"para\"><span style=\"color: #000000\">Some ions are groups of atoms bonded together and having an overall electrical charge. These are called <strong class=\"emphasis bold\">polyatomic ions<\/strong>. Writing formulas with polyatomic ions follows the same rules as with monatomic ions, except that when more than one polyatomic ion is present in a chemical formula, the polyatomic ion is enclosed in parentheses and the subscript is outside the right parenthesis. Ionic compounds typically form between metals and nonmetals or between polyatomic ions.<\/span><\/p>\n<p id=\"gob-ch03_s06_p06\" class=\"para\"><span style=\"color: #000000\">Names of ionic compounds are derived from the names of the ions, with the name of the cation coming first, followed by the name of the anion. If an element can form cations of different charges, there are two alternate systems for indicating the compound\u2019s name. In the <strong class=\"emphasis bold\">Stock system<\/strong>, a roman numeral in parentheses indicates the charge on the cation. An example is the name for FeCl<sub class=\"subscript\">2<\/sub>, which is iron(II) chloride.<br \/>\n<\/span><\/p>\n<p id=\"gob-ch03_s06_p07\" class=\"para\"><span style=\"color: #000000\">The <strong class=\"emphasis bold\">formula mass<\/strong> of an ionic compound is the sum of the masses of each individual atom in the formula. Care must be taken when calculating formula masses for formulas containing multiple polyatomic ions because the subscript outside the parentheses refers to all the atoms in the polyatomic ion.<\/span><span style=\"color: #6c64ad;font-size: 1.2em;font-weight: 600\">\u00a0<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"book-content\">\n<div id=\"gob-ch03_s06\" class=\"section end-of-chapter\" xml:lang=\"en\">\n<div id=\"gob-ch03_s06_qs01\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<h3>Additional Exercises<\/h3>\n<div id=\"gob-ch03_s06_qs01\" class=\"qandaset block\">Which ion with a 2+ charge has the following electron configuration? 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/p>\n<ol id=\"gob-ch03_s06_qs01_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch03_s06_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p01\" class=\"para\">What number shell is the valence electron shell of a sodium atom? What number shell is the valence shell of a sodium ion? Explain the difference.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p03\" class=\"para\">What number shell is the valence electron shell of a bromine atom? What number shell is the valence shell of a bromide ion? Explain the difference between these answers and the answers to Exercise 1.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p05\" class=\"para\">What is the electron configuration of each ion?<\/p>\n<ol id=\"gob-ch03_s06_qs01_l01\" class=\"orderedlist\">\n<li>K<sup class=\"superscript\">+<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup><\/li>\n<li>F<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p06\" class=\"para\">What is the electron configuration of each ion?<\/p>\n<ol id=\"gob-ch03_s06_qs01_l03\" class=\"orderedlist\">\n<li>Li<sup class=\"superscript\">+<\/sup><\/li>\n<li>Ca<sup class=\"superscript\">2+<\/sup><\/li>\n<li>Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>O<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p09\" class=\"para\">Use Lewis diagrams and arrows to show the electron transfer that occurs during the formation of an ionic compound among Mg atoms and F atoms. (Hint: how many atoms of each will you need?)<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p10\" class=\"para\">Use Lewis diagrams and arrows to show the electron transfer that occurs during the formation of an ionic compound among K atoms and O atoms. (Hint: how many atoms of each will you need?)<\/p>\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p38\" class=\"para\">\n<\/div>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<h3>Answers<\/h3>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q470410\">Show Answer<\/span><\/p>\n<div id=\"q470410\" class=\"hidden-answer\" style=\"display: none\"><\/div>\n<\/div>\n<p>1. For sodium, the valence shell is the third shell; for the sodium ion, the valence shell is the second shell because it has lost all its third shell electrons.<\/p>\n<p>3.<\/p>\n<ol id=\"gob-ch03_s06_qs01_l02_ans\" class=\"orderedlist\">\n<li style=\"list-style-type: none\">\n<ol>\n<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\n<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\n<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\n<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<p>5.\u00a0 <img decoding=\"async\" class=\"aligncenter\" style=\"font-size: 0.9em\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/19160850\/be5ae655eb277d90fdc6744e062a4ce2.jpg\" alt=\"image\" \/>]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-248\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>The Basics of General, Organic, and Biological Chemistry v. 1.0. <strong>Provided by<\/strong>: Saylor Academy. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\">https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc\/4.0\/\">CC BY-NC: Attribution-NonCommercial<\/a><\/em>. <strong>License Terms<\/strong>: This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work&#039;s original creator or licensor.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":53384,"menu_order":7,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"The Basics of General, Organic, and Biological Chemistry v. 1.0\",\"author\":\"\",\"organization\":\"Saylor Academy\",\"url\":\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc\",\"license_terms\":\"This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work\\'s original creator or 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