{"id":700,"date":"2018-03-20T15:24:47","date_gmt":"2018-03-20T15:24:47","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/?post_type=chapter&#038;p=700"},"modified":"2018-08-14T01:36:12","modified_gmt":"2018-08-14T01:36:12","slug":"6-6-end-of-chapter-material","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/chapter\/6-6-end-of-chapter-material\/","title":{"raw":"6.6 End-of-Chapter Material","rendered":"6.6 End-of-Chapter Material"},"content":{"raw":"<div id=\"book-content\">\r\n<div id=\"gob-ch06_s06\" class=\"section end-of-chapter\" xml:lang=\"en\">\r\n<div id=\"gob-ch06_s06_n01\" class=\"callout editable block\">\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Chapter Summary<\/h3>\r\n<p id=\"gob-ch06_s06_p01\" class=\"para\"><em class=\"emphasis\">To ensure that you understand the material in this chapter, you should review the meanings of the following bold terms in the following summary and ask yourself how they relate to the topics in the chapter.<\/em><\/p>\r\n<p id=\"gob-ch06_s06_p02\" class=\"para\">Chemical reactions relate quantities of reactants and products. Chemists use the <strong class=\"emphasis bold\">mole<\/strong> unit to represent 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> things, whether the things are atoms of elements or molecules of compounds. This number, called <strong class=\"emphasis bold\">Avogadro\u2019s number<\/strong>, is important because this number of atoms or molecules has the same mass in grams as one atom or molecule has in atomic mass units. <strong class=\"emphasis bold\">Molar masses<\/strong> of substances can be determined by summing the appropriate masses from the periodic table; the final molar mass will have units of grams.<\/p>\r\n<p id=\"gob-ch06_s06_p03\" class=\"para\">Because one mole of a substance will have a certain mass, we can use that relationship to construct conversion factors that will convert a mole amount into a mass amount, or vice versa. Such <strong class=\"emphasis bold\">mole-mass conversions<\/strong> typically take one algebraic step.<\/p>\r\n<p id=\"gob-ch06_s06_p04\" class=\"para\">Chemical reactions list reactants and products in molar amounts, not just molecular amounts. We can use the coefficients of a balanced chemical equation to relate moles of one substance in the reaction to moles of other substances (stoichiometry). In a <strong class=\"emphasis bold\">mole-mass calculation<\/strong>, we relate the number of moles of one substance to the mass of another substance. In a <strong class=\"emphasis bold\">mass-mass calculation<\/strong>, we relate the mass of one substance to the mass of another substance.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch06_s06_qs01\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch06_s06\" class=\"section end-of-chapter\" xml:lang=\"en\">\r\n<div id=\"gob-ch06_s06_qs01\" class=\"qandaset block\">\r\n<h3 class=\"title\">Additional Exercises<\/h3>\r\n<ol id=\"gob-ch06_s06_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch06_s06_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch06_s06_qs01_p01\" class=\"para\">If the average male has a body mass of 70 kg, of which 60% is water, how many moles of water are in an average male?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch06_s06_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch06_s06_qs01_p03\" class=\"para\">If the average female is 60.0 kg and contains 0.00174% iron, how many moles of iron are in an average female?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch06_s06_qs01_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch06_s06_qs01_p05\" class=\"para\">How many moles of each element are present in 2.67 mol of each compound?<\/p>\r\n\r\n<ol id=\"gob-ch06_s06_qs01_l01\" class=\"orderedlist\">\r\n \t<li>HCl<\/li>\r\n \t<li>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/li>\r\n \t<li>Al(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\r\n \t<li>Ga<sub class=\"subscript\">2<\/sub>(SO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch06_s06_qs01_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch06_s06_qs01_p06\" class=\"para\">How many moles of each element are present in 0.00445 mol of each compound?<\/p>\r\n\r\n<ol id=\"gob-ch06_s06_qs01_l03\" class=\"orderedlist\">\r\n \t<li>HCl<\/li>\r\n \t<li>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/li>\r\n \t<li>Al<sub class=\"subscript\">2<\/sub>(CO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\r\n \t<li>Ga<sub class=\"subscript\">2<\/sub>(SO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch06_s06_qs01_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch06_s06_qs01_p07\" class=\"para\">What is the mass of one hydrogen atom in grams? What is the mass of one oxygen atom in grams? Do these masses have a 1:16 ratio, as expected?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch06_s06_qs01_qd01_qa06\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch06_s06_qs01_p09\" class=\"para\">What is the mass of one sodium atom in grams?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch06_s06_qs01_qd01_qa07\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch06_s06_qs01_p11\" class=\"para\">If 6.63 \u00d7 10<sup class=\"superscript\">\u22126<\/sup> mol of a compound has a mass of 2.151 mg, what is the molar mass of the compound?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch06_s06_qs01_qd01_qa08\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch06_s06_qs01_p13\" class=\"para\">Hemoglobin (molar mass is approximately 64,000 g\/mol) is the major component of red blood cells that transports oxygen and carbon dioxide in the body. How many moles are in 0.034 g of hemoglobin?<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch06_s06_qs01_ans\" class=\"qandaset block\">\r\n<h3 class=\"title\">Answers<\/h3>\r\n[reveal-answer q=\"629436\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"629436\"]\r\n\r\n1.\u00a0\u00a0 2,330 mol\r\n\r\n3.\r\n<ol>\r\n \t<li style=\"list-style-type: none\">\r\n<ol>\r\n \t<li>2.67 mol of H and 2.67 mol of Cl<\/li>\r\n \t<li>5.34 mol of H, 2.67 mol of S, and 10.68 mol of O<\/li>\r\n \t<li>2.67 mol of Al, 8.01 mol of N, and 24.03 mol of O<\/li>\r\n \t<li>5.34 mol of Ga, 8.01 mol of S, and 32.04 mol of O<\/li>\r\n<\/ol>\r\n<\/li>\r\n<\/ol>\r\n5.\u00a0 H = 1.66 \u00d7 10<sup class=\"superscript\">\u221224<\/sup>\u00a0g and O = 2.66 \u00d7 10<sup class=\"superscript\">\u221223<\/sup>\u00a0g; yes, they are in a 1:16 ratio.\r\n\r\n7.\u00a0 324 g\/mol \u00a0 \u00a0[\/hidden-answer]\r\n<div class=\"answer\"><\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n&nbsp;\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"book-content\">\n<div id=\"gob-ch06_s06\" class=\"section end-of-chapter\" xml:lang=\"en\">\n<div id=\"gob-ch06_s06_n01\" class=\"callout editable block\">\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Chapter Summary<\/h3>\n<p id=\"gob-ch06_s06_p01\" class=\"para\"><em class=\"emphasis\">To ensure that you understand the material in this chapter, you should review the meanings of the following bold terms in the following summary and ask yourself how they relate to the topics in the chapter.<\/em><\/p>\n<p id=\"gob-ch06_s06_p02\" class=\"para\">Chemical reactions relate quantities of reactants and products. Chemists use the <strong class=\"emphasis bold\">mole<\/strong> unit to represent 6.022 \u00d7 10<sup class=\"superscript\">23<\/sup> things, whether the things are atoms of elements or molecules of compounds. This number, called <strong class=\"emphasis bold\">Avogadro\u2019s number<\/strong>, is important because this number of atoms or molecules has the same mass in grams as one atom or molecule has in atomic mass units. <strong class=\"emphasis bold\">Molar masses<\/strong> of substances can be determined by summing the appropriate masses from the periodic table; the final molar mass will have units of grams.<\/p>\n<p id=\"gob-ch06_s06_p03\" class=\"para\">Because one mole of a substance will have a certain mass, we can use that relationship to construct conversion factors that will convert a mole amount into a mass amount, or vice versa. Such <strong class=\"emphasis bold\">mole-mass conversions<\/strong> typically take one algebraic step.<\/p>\n<p id=\"gob-ch06_s06_p04\" class=\"para\">Chemical reactions list reactants and products in molar amounts, not just molecular amounts. We can use the coefficients of a balanced chemical equation to relate moles of one substance in the reaction to moles of other substances (stoichiometry). In a <strong class=\"emphasis bold\">mole-mass calculation<\/strong>, we relate the number of moles of one substance to the mass of another substance. In a <strong class=\"emphasis bold\">mass-mass calculation<\/strong>, we relate the mass of one substance to the mass of another substance.<\/p>\n<\/div>\n<\/div>\n<div id=\"gob-ch06_s06_qs01\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<div id=\"book-content\">\n<div id=\"gob-ch06_s06\" class=\"section end-of-chapter\" xml:lang=\"en\">\n<div id=\"gob-ch06_s06_qs01\" class=\"qandaset block\">\n<h3 class=\"title\">Additional Exercises<\/h3>\n<ol id=\"gob-ch06_s06_qs01_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch06_s06_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch06_s06_qs01_p01\" class=\"para\">If the average male has a body mass of 70 kg, of which 60% is water, how many moles of water are in an average male?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch06_s06_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch06_s06_qs01_p03\" class=\"para\">If the average female is 60.0 kg and contains 0.00174% iron, how many moles of iron are in an average female?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch06_s06_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch06_s06_qs01_p05\" class=\"para\">How many moles of each element are present in 2.67 mol of each compound?<\/p>\n<ol id=\"gob-ch06_s06_qs01_l01\" class=\"orderedlist\">\n<li>HCl<\/li>\n<li>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/li>\n<li>Al(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\n<li>Ga<sub class=\"subscript\">2<\/sub>(SO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch06_s06_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch06_s06_qs01_p06\" class=\"para\">How many moles of each element are present in 0.00445 mol of each compound?<\/p>\n<ol id=\"gob-ch06_s06_qs01_l03\" class=\"orderedlist\">\n<li>HCl<\/li>\n<li>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/li>\n<li>Al<sub class=\"subscript\">2<\/sub>(CO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\n<li>Ga<sub class=\"subscript\">2<\/sub>(SO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch06_s06_qs01_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch06_s06_qs01_p07\" class=\"para\">What is the mass of one hydrogen atom in grams? What is the mass of one oxygen atom in grams? Do these masses have a 1:16 ratio, as expected?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch06_s06_qs01_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch06_s06_qs01_p09\" class=\"para\">What is the mass of one sodium atom in grams?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch06_s06_qs01_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch06_s06_qs01_p11\" class=\"para\">If 6.63 \u00d7 10<sup class=\"superscript\">\u22126<\/sup> mol of a compound has a mass of 2.151 mg, what is the molar mass of the compound?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch06_s06_qs01_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch06_s06_qs01_p13\" class=\"para\">Hemoglobin (molar mass is approximately 64,000 g\/mol) is the major component of red blood cells that transports oxygen and carbon dioxide in the body. How many moles are in 0.034 g of hemoglobin?<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch06_s06_qs01_ans\" class=\"qandaset block\">\n<h3 class=\"title\">Answers<\/h3>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q629436\">Show Answer<\/span><\/p>\n<div id=\"q629436\" class=\"hidden-answer\" style=\"display: none\">\n<p>1.\u00a0\u00a0 2,330 mol<\/p>\n<p>3.<\/p>\n<ol>\n<li style=\"list-style-type: none\">\n<ol>\n<li>2.67 mol of H and 2.67 mol of Cl<\/li>\n<li>5.34 mol of H, 2.67 mol of S, and 10.68 mol of O<\/li>\n<li>2.67 mol of Al, 8.01 mol of N, and 24.03 mol of O<\/li>\n<li>5.34 mol of Ga, 8.01 mol of S, and 32.04 mol of O<\/li>\n<\/ol>\n<\/li>\n<\/ol>\n<p>5.\u00a0 H = 1.66 \u00d7 10<sup class=\"superscript\">\u221224<\/sup>\u00a0g and O = 2.66 \u00d7 10<sup class=\"superscript\">\u221223<\/sup>\u00a0g; yes, they are in a 1:16 ratio.<\/p>\n<p>7.\u00a0 324 g\/mol \u00a0 \u00a0<\/p><\/div>\n<\/div>\n<div class=\"answer\"><\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-700\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>The Basics of General, Organic, and Biological Chemistry v. 1.0. <strong>Provided by<\/strong>: Saylor Academy. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\">https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc\/4.0\/\">CC BY-NC: Attribution-NonCommercial<\/a><\/em>. <strong>License Terms<\/strong>: This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work&#039;s original creator or licensor.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":44985,"menu_order":7,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"The Basics of General, Organic, and Biological Chemistry v. 1.0\",\"author\":\"\",\"organization\":\"Saylor Academy\",\"url\":\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc\",\"license_terms\":\"This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work\\'s original creator or licensor.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-700","chapter","type-chapter","status-publish","hentry"],"part":651,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/700","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/users\/44985"}],"version-history":[{"count":7,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/700\/revisions"}],"predecessor-version":[{"id":3245,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/700\/revisions\/3245"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/parts\/651"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/700\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/media?parent=700"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=700"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/contributor?post=700"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/license?post=700"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}