{"id":835,"date":"2018-03-20T16:13:30","date_gmt":"2018-03-20T16:13:30","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/?post_type=chapter&#038;p=835"},"modified":"2018-05-08T15:40:14","modified_gmt":"2018-05-08T15:40:14","slug":"9-5-end-of-chapter-material","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/chapter\/9-5-end-of-chapter-material\/","title":{"raw":"9.5 End-of-Chapter Material","rendered":"9.5 End-of-Chapter Material"},"content":{"raw":"<div id=\"navbar-top\" class=\"navbar\">\r\n<div class=\"navbar-part left\"><\/div>\r\n<\/div>\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch09_s05\" class=\"section end-of-chapter\" xml:lang=\"en\">\r\n<h2 class=\"title editable block\"><span class=\"title-prefix\">9.5<\/span> End-of-Chapter Material<\/h2>\r\n<div id=\"gob-ch09_s05_n01\" class=\"callout editable block\">\r\n<div class=\"textbox shaded\">\r\n<div id=\"gob-ch09_s05_n01\" class=\"callout editable block\">\r\n<h3 class=\"title\">Chapter Summary<\/h3>\r\n<p id=\"gob-ch09_s05_p01\" class=\"para\"><em class=\"emphasis\">To ensure that you understand the material in this chapter, you should review the meanings of the bold terms in the following summary and ask yourself how they relate to the topics in the chapter.<\/em><\/p>\r\n<p id=\"gob-ch09_s05_p02\" class=\"para\">A <strong class=\"emphasis bold\">solution<\/strong> is a homogeneous mixture. The major component is the <strong class=\"emphasis bold\">solvent<\/strong>, while the minor component is the <strong class=\"emphasis bold\">solute<\/strong>. Solutions can have any phase; for example, an <strong class=\"emphasis bold\">alloy<\/strong> is a solid solution. Solutes are <strong class=\"emphasis bold\">soluble<\/strong> or <strong class=\"emphasis bold\">insoluble<\/strong>, meaning they dissolve or do not dissolve in a particular solvent. The terms <strong class=\"emphasis bold\">miscible<\/strong> and <strong class=\"emphasis bold\">immiscible<\/strong>, instead of soluble and insoluble, are used for liquid solutes and solvents. The statement <em class=\"emphasis\">like dissolves like<\/em> is a useful guide to predicting whether a solute will dissolve in a given solvent.<\/p>\r\n<p id=\"gob-ch09_s05_p03\" class=\"para\">The amount of solute in a solution is represented by the <strong class=\"emphasis bold\">concentration<\/strong> of the solution. The maximum amount of solute that will dissolve in a given amount of solvent is called the <strong class=\"emphasis bold\">solubility<\/strong> of the solute. Such solutions are <strong class=\"emphasis bold\">saturated<\/strong>. Solutions that have less than the maximum amount are <strong class=\"emphasis bold\">unsaturated<\/strong>. Most solutions are unsaturated, and there are various ways of stating their concentrations. <strong class=\"emphasis bold\">Mass\/mass percent<\/strong>, <strong class=\"emphasis bold\">volume\/volume percent<\/strong>, and <strong class=\"emphasis bold\">mass\/volume percent<\/strong> indicate the percentage of the overall solution that is solute. <strong class=\"emphasis bold\">Parts per million (ppm)<\/strong> and <strong class=\"emphasis bold\">parts per billion (ppb)<\/strong> are used to describe very small concentrations of a solute. <strong class=\"emphasis bold\">Molarity<\/strong>, defined as the number of moles of solute per liter of solution, is a common concentration unit in the chemistry laboratory. <strong class=\"emphasis bold\">Equivalents<\/strong> express concentrations in terms of moles of charge on ions. When a solution is diluted, we use the fact that the amount of solute remains constant to be able to determine the volume or concentration of the final diluted solution.<\/p>\r\n<p id=\"gob-ch09_s05_p04\" class=\"para\">Dissolving occurs by <strong class=\"emphasis bold\">solvation<\/strong>, the process in which particles of a solvent surround the individual particles of a solute, separating them to make a solution. For water solutions, the word <strong class=\"emphasis bold\">hydration<\/strong> is used. If the solute is molecular, it dissolves into individual molecules. If the solute is ionic, the individual ions separate from each other, forming a solution that conducts electricity. Such solutions are called <strong class=\"emphasis bold\">electrolytes<\/strong>. If the dissociation of ions is complete, the solution is a <strong class=\"emphasis bold\">strong electrolyte<\/strong>. If the dissociation is only partial, the solution is a <strong class=\"emphasis bold\">weak electrolyte<\/strong>. Solutions of molecules do not conduct electricity and are called <strong class=\"emphasis bold\">nonelectrolytes<\/strong>.<\/p>\r\n<p id=\"gob-ch09_s05_p05\" class=\"para\">Solutions have properties that differ from those of the pure solvent. Some of these are <strong class=\"emphasis bold\">colligative<\/strong> properties, which are due to the number of solute particles dissolved, not the chemical identity of the solute. Colligative properties include <strong class=\"emphasis bold\">vapor pressure depression<\/strong>, <strong class=\"emphasis bold\">boiling point elevation<\/strong>, <strong class=\"emphasis bold\">freezing point depression<\/strong>, and <strong class=\"emphasis bold\">osmotic pressure<\/strong>. Osmotic pressure is particularly important in biological systems. It is caused by <strong class=\"emphasis bold\">osmosis<\/strong>, the passage of solvents through certain membranes like cell walls. The <strong class=\"emphasis bold\">osmolarity<\/strong> of a solution is the product of a solution\u2019s molarity and the number of particles a solute separates into when it dissolves. Osmosis can be reversed by the application of pressure; this reverse osmosis is used to make fresh water from saltwater in some parts of the world. Because of osmosis, red blood cells placed in hypotonic or hypertonic solutions lose function through either hemolysis or crenation. If they are placed in isotonic solutions, however, the cells are unaffected because osmotic pressure is equal on either side of the cell membrane.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<div id=\"gob-ch09_s05_n01\" class=\"callout editable block\">\r\n<h3 class=\"title\">Additional Exercises<\/h3>\r\n<\/div>\r\n<div id=\"gob-ch09_s05_qs01\" class=\"qandaset block\">\r\n<ol id=\"gob-ch09_s05_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch09_s05_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s05_qs01_p01\" class=\"para\">Calcium nitrate reacts with sodium carbonate to precipitate solid calcium carbonate:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>(aq) + Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(aq) \u2192 CaCO<sub class=\"subscript\">3<\/sub>(s) + NaNO<sub class=\"subscript\">3<\/sub>(aq)<\/span><\/span>\r\n<ol id=\"gob-ch09_s05_qs01_l01\" class=\"orderedlist\">\r\n \t<li>Balance the chemical equation.<\/li>\r\n \t<li>How many grams of Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub> are needed to react with 50.0 mL of 0.450 M Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>?<\/li>\r\n \t<li>Assuming that the Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub> has a negligible effect on the volume of the solution, find the osmolarity of the NaNO<sub class=\"subscript\">3<\/sub> solution remaining after the CaCO<sub class=\"subscript\">3<\/sub> precipitates from solution.<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s05_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s05_qs01_p02\" class=\"para\">The compound HCl reacts with sodium carbonate to generate carbon dioxide gas:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">HCl(aq) + Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(aq) \u2192 H<sub class=\"subscript\">2<\/sub>O(\u2113) + CO<sub class=\"subscript\">2<\/sub>(g) + NaCl(aq)<\/span><\/span>\r\n<ol id=\"gob-ch09_s05_qs01_l03\" class=\"orderedlist\">\r\n \t<li>Balance the chemical equation.<\/li>\r\n \t<li>How many grams of Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub> are needed to react with 250.0 mL of 0.755 M HCl?<\/li>\r\n \t<li>Assuming that the Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub> has a negligible effect on the volume of the solution, find the osmolarity of the NaCl solution remaining after the reaction is complete.<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s05_qs01_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s05_qs01_p03\" class=\"para\">Estimate the freezing point of concentrated aqueous HCl, which is usually sold as a 12 M solution. Assume complete ionization into H<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup> ions.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s05_qs01_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s05_qs01_p05\" class=\"para\">Estimate the boiling point of concentrated aqueous H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>, which is usually sold as an 18 M solution. Assume complete ionization into H<sup class=\"superscript\">+<\/sup> and HSO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup> ions.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s05_qs01_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s05_qs01_p07\" class=\"para\">Seawater can be approximated by a 3.0% m\/m solution of NaCl in water. Determine the molarity and osmolarity of seawater. Assume a density of 1.0 g\/mL.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s05_qs01_qd01_qa06\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s05_qs01_p09\" class=\"para\">Human blood can be approximated by a 0.90% m\/m solution of NaCl in water. Determine the molarity and osmolarity of blood. Assume a density of 1.0 g\/mL.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s05_qs01_qd01_qa07\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s05_qs01_p11\" class=\"para\">How much water must be added to 25.0 mL of a 1.00 M NaCl solution to make a resulting solution that has a concentration of 0.250 M?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s05_qs01_qd01_qa08\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s05_qs01_p13\" class=\"para\">Sports drinks like Gatorade are advertised as capable of resupplying the body with electrolytes lost by vigorous exercise. Find a label from a sports drink container and identify the electrolytes it contains. You should be able to identify several simple ionic compounds in the ingredients list.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s05_qs01_qd01_qa09\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s05_qs01_p15\" class=\"para\">Occasionally we hear a sensational news story about people stranded in a lifeboat on the ocean who had to drink their own urine to survive. While distasteful, this act was probably necessary for survival. Why not simply drink the ocean water? (Hint: See Exercise 5 and Exercise 6 above. What would happen if the two solutions in these exercises were on opposite sides of a semipermeable membrane, as we would find in our cell walls?)<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch09_s05\" class=\"section end-of-chapter\" xml:lang=\"en\">\r\n<div id=\"gob-ch09_s05_n01\" class=\"callout editable block\">\r\n<h3 class=\"title\">Answers<\/h3>\r\n<\/div>\r\n<div id=\"gob-ch09_s05_qs01_ans\" class=\"qandaset block\">\r\n\r\n1. a. Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>(aq) + Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(aq) \u2192 CaCO<sub class=\"subscript\">3<\/sub>(s) + 2NaNO<sub class=\"subscript\">3<\/sub>(aq)\r\n\r\nb. 2.39 g\r\n\r\nc. 1.80 osmol\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n<p id=\"gob-ch09_s05_qs01_p04_ans\" class=\"para\">3. \u221245.6\u00b0C<\/p>\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n<p id=\"gob-ch09_s05_qs01_p08_ans\" class=\"para\">5. 0.513 M; 1.026 osmol<\/p>\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n<p id=\"gob-ch09_s05_qs01_p12_ans\" class=\"para\">7. 75.0 mL<\/p>\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n<p id=\"gob-ch09_s05_qs01_p16_ans\" class=\"para\">9. The osmotic pressure of seawater is too high. Drinking seawater would cause water to go from inside our cells into the more concentrated seawater, ultimately killing the cells.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"navbar-bottom\" class=\"navbar\"><\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"navbar-top\" class=\"navbar\">\n<div class=\"navbar-part left\"><\/div>\n<\/div>\n<div id=\"book-content\">\n<div id=\"gob-ch09_s05\" class=\"section end-of-chapter\" xml:lang=\"en\">\n<h2 class=\"title editable block\"><span class=\"title-prefix\">9.5<\/span> End-of-Chapter Material<\/h2>\n<div id=\"gob-ch09_s05_n01\" class=\"callout editable block\">\n<div class=\"textbox shaded\">\n<div id=\"gob-ch09_s05_n01\" class=\"callout editable block\">\n<h3 class=\"title\">Chapter Summary<\/h3>\n<p id=\"gob-ch09_s05_p01\" class=\"para\"><em class=\"emphasis\">To ensure that you understand the material in this chapter, you should review the meanings of the bold terms in the following summary and ask yourself how they relate to the topics in the chapter.<\/em><\/p>\n<p id=\"gob-ch09_s05_p02\" class=\"para\">A <strong class=\"emphasis bold\">solution<\/strong> is a homogeneous mixture. The major component is the <strong class=\"emphasis bold\">solvent<\/strong>, while the minor component is the <strong class=\"emphasis bold\">solute<\/strong>. Solutions can have any phase; for example, an <strong class=\"emphasis bold\">alloy<\/strong> is a solid solution. Solutes are <strong class=\"emphasis bold\">soluble<\/strong> or <strong class=\"emphasis bold\">insoluble<\/strong>, meaning they dissolve or do not dissolve in a particular solvent. The terms <strong class=\"emphasis bold\">miscible<\/strong> and <strong class=\"emphasis bold\">immiscible<\/strong>, instead of soluble and insoluble, are used for liquid solutes and solvents. The statement <em class=\"emphasis\">like dissolves like<\/em> is a useful guide to predicting whether a solute will dissolve in a given solvent.<\/p>\n<p id=\"gob-ch09_s05_p03\" class=\"para\">The amount of solute in a solution is represented by the <strong class=\"emphasis bold\">concentration<\/strong> of the solution. The maximum amount of solute that will dissolve in a given amount of solvent is called the <strong class=\"emphasis bold\">solubility<\/strong> of the solute. Such solutions are <strong class=\"emphasis bold\">saturated<\/strong>. Solutions that have less than the maximum amount are <strong class=\"emphasis bold\">unsaturated<\/strong>. Most solutions are unsaturated, and there are various ways of stating their concentrations. <strong class=\"emphasis bold\">Mass\/mass percent<\/strong>, <strong class=\"emphasis bold\">volume\/volume percent<\/strong>, and <strong class=\"emphasis bold\">mass\/volume percent<\/strong> indicate the percentage of the overall solution that is solute. <strong class=\"emphasis bold\">Parts per million (ppm)<\/strong> and <strong class=\"emphasis bold\">parts per billion (ppb)<\/strong> are used to describe very small concentrations of a solute. <strong class=\"emphasis bold\">Molarity<\/strong>, defined as the number of moles of solute per liter of solution, is a common concentration unit in the chemistry laboratory. <strong class=\"emphasis bold\">Equivalents<\/strong> express concentrations in terms of moles of charge on ions. When a solution is diluted, we use the fact that the amount of solute remains constant to be able to determine the volume or concentration of the final diluted solution.<\/p>\n<p id=\"gob-ch09_s05_p04\" class=\"para\">Dissolving occurs by <strong class=\"emphasis bold\">solvation<\/strong>, the process in which particles of a solvent surround the individual particles of a solute, separating them to make a solution. For water solutions, the word <strong class=\"emphasis bold\">hydration<\/strong> is used. If the solute is molecular, it dissolves into individual molecules. If the solute is ionic, the individual ions separate from each other, forming a solution that conducts electricity. Such solutions are called <strong class=\"emphasis bold\">electrolytes<\/strong>. If the dissociation of ions is complete, the solution is a <strong class=\"emphasis bold\">strong electrolyte<\/strong>. If the dissociation is only partial, the solution is a <strong class=\"emphasis bold\">weak electrolyte<\/strong>. Solutions of molecules do not conduct electricity and are called <strong class=\"emphasis bold\">nonelectrolytes<\/strong>.<\/p>\n<p id=\"gob-ch09_s05_p05\" class=\"para\">Solutions have properties that differ from those of the pure solvent. Some of these are <strong class=\"emphasis bold\">colligative<\/strong> properties, which are due to the number of solute particles dissolved, not the chemical identity of the solute. Colligative properties include <strong class=\"emphasis bold\">vapor pressure depression<\/strong>, <strong class=\"emphasis bold\">boiling point elevation<\/strong>, <strong class=\"emphasis bold\">freezing point depression<\/strong>, and <strong class=\"emphasis bold\">osmotic pressure<\/strong>. Osmotic pressure is particularly important in biological systems. It is caused by <strong class=\"emphasis bold\">osmosis<\/strong>, the passage of solvents through certain membranes like cell walls. The <strong class=\"emphasis bold\">osmolarity<\/strong> of a solution is the product of a solution\u2019s molarity and the number of particles a solute separates into when it dissolves. Osmosis can be reversed by the application of pressure; this reverse osmosis is used to make fresh water from saltwater in some parts of the world. Because of osmosis, red blood cells placed in hypotonic or hypertonic solutions lose function through either hemolysis or crenation. If they are placed in isotonic solutions, however, the cells are unaffected because osmotic pressure is equal on either side of the cell membrane.<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<div id=\"gob-ch09_s05_n01\" class=\"callout editable block\">\n<h3 class=\"title\">Additional Exercises<\/h3>\n<\/div>\n<div id=\"gob-ch09_s05_qs01\" class=\"qandaset block\">\n<ol id=\"gob-ch09_s05_qs01_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch09_s05_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s05_qs01_p01\" class=\"para\">Calcium nitrate reacts with sodium carbonate to precipitate solid calcium carbonate:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>(aq) + Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(aq) \u2192 CaCO<sub class=\"subscript\">3<\/sub>(s) + NaNO<sub class=\"subscript\">3<\/sub>(aq)<\/span><\/span><\/p>\n<ol id=\"gob-ch09_s05_qs01_l01\" class=\"orderedlist\">\n<li>Balance the chemical equation.<\/li>\n<li>How many grams of Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub> are needed to react with 50.0 mL of 0.450 M Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>?<\/li>\n<li>Assuming that the Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub> has a negligible effect on the volume of the solution, find the osmolarity of the NaNO<sub class=\"subscript\">3<\/sub> solution remaining after the CaCO<sub class=\"subscript\">3<\/sub> precipitates from solution.<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s05_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s05_qs01_p02\" class=\"para\">The compound HCl reacts with sodium carbonate to generate carbon dioxide gas:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">HCl(aq) + Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(aq) \u2192 H<sub class=\"subscript\">2<\/sub>O(\u2113) + CO<sub class=\"subscript\">2<\/sub>(g) + NaCl(aq)<\/span><\/span><\/p>\n<ol id=\"gob-ch09_s05_qs01_l03\" class=\"orderedlist\">\n<li>Balance the chemical equation.<\/li>\n<li>How many grams of Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub> are needed to react with 250.0 mL of 0.755 M HCl?<\/li>\n<li>Assuming that the Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub> has a negligible effect on the volume of the solution, find the osmolarity of the NaCl solution remaining after the reaction is complete.<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s05_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s05_qs01_p03\" class=\"para\">Estimate the freezing point of concentrated aqueous HCl, which is usually sold as a 12 M solution. Assume complete ionization into H<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup> ions.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s05_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s05_qs01_p05\" class=\"para\">Estimate the boiling point of concentrated aqueous H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>, which is usually sold as an 18 M solution. Assume complete ionization into H<sup class=\"superscript\">+<\/sup> and HSO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup> ions.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s05_qs01_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s05_qs01_p07\" class=\"para\">Seawater can be approximated by a 3.0% m\/m solution of NaCl in water. Determine the molarity and osmolarity of seawater. Assume a density of 1.0 g\/mL.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s05_qs01_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s05_qs01_p09\" class=\"para\">Human blood can be approximated by a 0.90% m\/m solution of NaCl in water. Determine the molarity and osmolarity of blood. Assume a density of 1.0 g\/mL.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s05_qs01_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s05_qs01_p11\" class=\"para\">How much water must be added to 25.0 mL of a 1.00 M NaCl solution to make a resulting solution that has a concentration of 0.250 M?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s05_qs01_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s05_qs01_p13\" class=\"para\">Sports drinks like Gatorade are advertised as capable of resupplying the body with electrolytes lost by vigorous exercise. Find a label from a sports drink container and identify the electrolytes it contains. You should be able to identify several simple ionic compounds in the ingredients list.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s05_qs01_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s05_qs01_p15\" class=\"para\">Occasionally we hear a sensational news story about people stranded in a lifeboat on the ocean who had to drink their own urine to survive. While distasteful, this act was probably necessary for survival. Why not simply drink the ocean water? (Hint: See Exercise 5 and Exercise 6 above. What would happen if the two solutions in these exercises were on opposite sides of a semipermeable membrane, as we would find in our cell walls?)<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<div id=\"book-content\">\n<div id=\"gob-ch09_s05\" class=\"section end-of-chapter\" xml:lang=\"en\">\n<div id=\"gob-ch09_s05_n01\" class=\"callout editable block\">\n<h3 class=\"title\">Answers<\/h3>\n<\/div>\n<div id=\"gob-ch09_s05_qs01_ans\" class=\"qandaset block\">\n<p>1. a. Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>(aq) + Na<sub class=\"subscript\">2<\/sub>CO<sub class=\"subscript\">3<\/sub>(aq) \u2192 CaCO<sub class=\"subscript\">3<\/sub>(s) + 2NaNO<sub class=\"subscript\">3<\/sub>(aq)<\/p>\n<p>b. 2.39 g<\/p>\n<p>c. 1.80 osmol<\/p>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p id=\"gob-ch09_s05_qs01_p04_ans\" class=\"para\">3. \u221245.6\u00b0C<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p id=\"gob-ch09_s05_qs01_p08_ans\" class=\"para\">5. 0.513 M; 1.026 osmol<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p id=\"gob-ch09_s05_qs01_p12_ans\" class=\"para\">7. 75.0 mL<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p id=\"gob-ch09_s05_qs01_p16_ans\" class=\"para\">9. The osmotic pressure of seawater is too high. Drinking seawater would cause water to go from inside our cells into the more concentrated seawater, ultimately killing the cells.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"navbar-bottom\" class=\"navbar\"><\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-835\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>The Basics of General, Organic, and Biological Chemistry v. 1.0. <strong>Provided by<\/strong>: Saylor Academy. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\">https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc\/4.0\/\">CC BY-NC: Attribution-NonCommercial<\/a><\/em>. <strong>License Terms<\/strong>: This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work&#039;s original creator or licensor.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":44985,"menu_order":6,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"The Basics of General, Organic, and Biological Chemistry v. 1.0\",\"author\":\"\",\"organization\":\"Saylor Academy\",\"url\":\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc\",\"license_terms\":\"This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work\\'s original creator or licensor.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-835","chapter","type-chapter","status-publish","hentry"],"part":796,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/835","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/users\/44985"}],"version-history":[{"count":4,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/835\/revisions"}],"predecessor-version":[{"id":2465,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/835\/revisions\/2465"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/parts\/796"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/835\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/media?parent=835"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=835"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/contributor?post=835"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/wp-json\/wp\/v2\/license?post=835"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}