{"id":848,"date":"2018-03-20T16:16:37","date_gmt":"2018-03-20T16:16:37","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/?post_type=chapter&#038;p=848"},"modified":"2018-10-03T13:52:53","modified_gmt":"2018-10-03T13:52:53","slug":"10-1-arrhenius-definition-of-acids-and-bases","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-monroecc-orgbiochemistry\/chapter\/10-1-arrhenius-definition-of-acids-and-bases\/","title":{"raw":"10.1 Arrhenius Definition of Acids and Bases","rendered":"10.1 Arrhenius Definition of Acids and Bases"},"content":{"raw":"<div id=\"navbar-top\" class=\"navbar\">\r\n<div class=\"navbar-part left\"><\/div>\r\n<\/div>\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch10_s01\" class=\"section\" xml:lang=\"en\">\r\n<h2 class=\"title editable block\"><span class=\"title-prefix\">10.1<\/span> Arrhenius Definition of Acids and Bases<\/h2>\r\n<div id=\"gob-ch10_s01_n01\" class=\"learning_objectives editable block\">\r\n<div class=\"textbox learning-objectives\">\r\n<h3 class=\"title\">Learning Objective<\/h3>\r\n<ol id=\"gob-ch10_s01_l01\" class=\"orderedlist\">\r\n \t<li>Recognize a compound as an Arrhenius acid or an Arrhenius base.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<p id=\"gob-ch10_s01_p01\" class=\"para editable block\">One way to define a class of compounds is by describing the various characteristics its members have in common. In the case of <strong>acids, the common characteristics include a sour taste, the ability to change the color of <em class=\"emphasis\">litmus<\/em> to red, and the ability to react with certain metals<\/strong>, eroding the metal and producing hydrogen gas and an ionic compound. For<strong> bases, the common characteristics are a slippery texture, a bitter taste, and the ability to change the color of litmus to blue.<\/strong>\u00a0 Acids and bases also react with each other in neutralization reactions, forming water and ionic compounds, also known as salts.<\/p>\r\n<strong>Indicators<\/strong> are compounds that exhibit different colors when placed in solutions with different acid\/base (pH) balances.\u00a0 As described in the previous paragraph, litmus, a compound obtained from lichens, is an indicator because it is blue when in a basic solutions and red when in an acidic solution. Juice from purple cabbage is another natural indicator, and it exhibits a wide range of colors based on the pH it experiences as seen in Figure 10.1 below.\u00a0 Other indicators include phenolphthalein and\u00a0 bromothymol blue.\u00a0 Indicaotrs are often used in<strong> titration<\/strong>, a measured form of\u00a0 neutralization reaction, to visually indicate that the moles of acid and moles of base are balanced at the equivalence point.\r\n<div class=\"textbox shaded\"><img class=\" wp-image-3453 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3331\/2018\/03\/03134610\/purple-cabbage-indicator1-300x182.jpg\" alt=\"\" width=\"508\" height=\"308\" \/>Figure 10.1 Purple Cabbage Juice Indicator at Various pH Levels.\u00a0 Attribution: By Indikator-Blaukraut.JPG: Supermartlderivative work: Haltopub (Indikator-Blaukraut.JPG) [CC BY-SA 3.0 (https:\/\/creativecommons.org\/licenses\/by-sa\/3.0) or GFDL (http:\/\/www.gnu.org\/copyleft\/fdl.html)], via Wikimedia Commons<\/div>\r\n<div id=\"gob-ch10_s01_n02\" class=\"callout editable block\">\r\n<div class=\"textbox\">\r\n<h3 class=\"title\">Note<\/h3>\r\n<p id=\"gob-ch10_s01_p02\" class=\"para\">Although tastes are included among the common characteristics of acids and bases, never taste an unknown chemical!<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"gob-ch10_s01_p03\" class=\"para editable block\">Chemists define acids and bases in terms of their chemical properties, but the definitions differ in models developed at different times.\u00a0 The Swedish chemist Svante Arrhenius developed the first chemical definitions of acids and bases in the late 1800s. <strong>Arrhenius<\/strong> defined an <strong><span class=\"margin_term\"><span class=\"glossterm\">acid<\/span><\/span>\u00a0as a compound that increases the concentration of hydrogen ion (H<sup class=\"superscript\">+<\/sup>) in aqueous solution<\/strong>. Many acids are simple compounds that release a hydrogen cation into solution when they dissolve. Similarly, Arrhenius defined a<strong> <span class=\"margin_term\"><span class=\"glossterm\">base<\/span><\/span>\u00a0as a compound that increases the concentration of hydroxide ion (OH<sup class=\"superscript\">\u2212<\/sup>) in aqueous solution.<\/strong> Many bases are ionic compounds that have the hydroxide ion as their anion, which is released when the base dissolves in water.<\/p>\r\n<p id=\"gob-ch10_s01_p04\" class=\"para editable block\">Many bases and their aqueous solutions are named using the normal rules of ionic compounds that were presented in <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-3\">Chapter 3 \"Ionic Bonding and Simple Ionic Compounds\"<\/a>, <a class=\"xref\" href=\"gob-ch03_s04#gob-ch03_s04\">Section 3.4 \"Ionic Nomenclature\".\u00a0<\/a> For example, the name sodium hydroxide (NaOH) is used as the name of the ionic compound <em>and<\/em> for an aqueous solution of the compound.<\/p>\r\n<p class=\"para editable block\">However, aqueous solutions of binary acids,\u00a0compounds with hydrogen and one other element in their formula, have one name for the compound alone and a different name when the compound is dissolved in water. Such a compound alone is named <em>hydrogen<span style=\"text-decoration: underline\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>ide<\/em> with the blank being filled with the element's root name.\u00a0 For example, HCl not dissolved in water is hydrogen chloride.But when hydrogen chloride dissolves in water, its name changes to hydrochloric acid, following the pattern\u00a0<em>hydro <span style=\"text-decoration: underline\"> \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <\/span>ic acid, <\/em> again with the blank being replaced by the element's root name.<\/p>\r\n<p class=\"para editable block\">Acids composed of more than two elements, typically one to three hydrogen atoms with a polyatomic ion. The name of an oxyacid is based on the name of the polyatomic ion.\u00a0 If the polyatomic ion name ends with <em>-ate<\/em>, name of its acid will end in <em>-ic acid<\/em>.\u00a0 If the polyatomic ion mane ends in <em>-ite<\/em>, the name of the acid ends in <em>-ous acid. <\/em>\u00a0 For example HNO<sub>3<\/sub> is nitric acid because it contains the nitrate polyatomic ion.\u00a0 HNO<sub>2<\/sub> is nitrous acid because it contains the polyatomic ion nitrite.<\/p>\r\n<p class=\"para editable block\">. <a class=\"xref\" href=\"#gob-ch10_s01_t01\">Table 10.1 \"Formulas and Names for Some Acids and Bases\"<\/a> lists some acids and bases and their names. Note that acids have hydrogen written first, as if it were the cation, while bases that have the negative hydroxide ion have it written last.<\/p>\r\n\r\n<div id=\"gob-ch10_s01_n03\" class=\"callout editable block\">\r\n<div class=\"textbox\">\r\n<h3 class=\"title\">Note<\/h3>\r\n<p id=\"gob-ch10_s01_p05\" class=\"para\">The name <em class=\"emphasis\">oxygen<\/em> comes from the Latin meaning \u201cacid producer\u201d because its discoverer, Antoine Lavoisier, thought it was the essential element in acids. Lavoisier was wrong, but it is too late to change the name now.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch10_s01_t01\" class=\"table block\">\r\n<p class=\"title\"><span class=\"title-prefix\">Table 10.1<\/span> Formulas and Names for Some Acids and Bases<\/p>\r\n\r\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Formula<\/th>\r\n<th>Name<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td colspan=\"2\"><strong class=\"emphasis bold\">Acids<\/strong><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HCl(aq)<\/td>\r\n<td>hydrochloric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HBr(aq)<\/td>\r\n<td>hydrobromic acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HI(aq)<\/td>\r\n<td>hydriodic acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>H<sub class=\"subscript\">2<\/sub>S(aq)<\/td>\r\n<td>hydrosulfuric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HC<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">2<\/sub>(aq)<\/td>\r\n<td>acetic acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HNO<sub class=\"subscript\">3<\/sub>(aq)<\/td>\r\n<td>nitric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HNO<sub class=\"subscript\">2<\/sub>(aq)<\/td>\r\n<td>nitrous acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>(aq)<\/td>\r\n<td>sulfuric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">3<\/sub>(aq)<\/td>\r\n<td>sulfurous acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HClO<sub class=\"subscript\">3<\/sub>(aq)<\/td>\r\n<td>chloric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HClO<sub class=\"subscript\">4<\/sub>(aq)<\/td>\r\n<td>perchloric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>HClO<sub class=\"subscript\">2<\/sub>(aq)<\/td>\r\n<td>chlorous acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>H<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub>(aq)<\/td>\r\n<td>phosphoric acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>H<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">3<\/sub>(aq)<\/td>\r\n<td>phosphorous acid<\/td>\r\n<\/tr>\r\n<tr>\r\n<td colspan=\"2\"><strong class=\"emphasis bold\">Bases<\/strong><\/td>\r\n<\/tr>\r\n<tr>\r\n<td>NaOH(aq)<\/td>\r\n<td>sodium hydroxide<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>KOH(aq)<\/td>\r\n<td>potassium hydroxide<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Mg(OH)<sub class=\"subscript\">2<\/sub>(aq)<\/td>\r\n<td>magnesium hydroxide<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Ca(OH)<sub class=\"subscript\">2<\/sub>(aq)<\/td>\r\n<td>calcium hydroxide<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>NH<sub class=\"subscript\">3<\/sub>(aq)<\/td>\r\n<td>ammonia<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<div id=\"gob-ch10_s01_n04\" class=\"exercises editable block\">\r\n<h3 class=\"title\">Example 1<\/h3>\r\n<p id=\"gob-ch10_s01_p06\" class=\"para\">Name each substance.<\/p>\r\n\r\n<ol id=\"gob-ch10_s01_l02\" class=\"orderedlist\">\r\n \t<li>HF(aq)<\/li>\r\n \t<li>Sr(OH)<sub class=\"subscript\">2<\/sub>(aq)<\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution<\/p>\r\n\r\n<ol id=\"gob-ch10_s01_l03\" class=\"orderedlist\">\r\n \t<li>This acid has only two elements in its formula, so its name includes the <em class=\"emphasis\">hydro<\/em>- prefix. The stem of the other element\u2019s name, fluorine, is <em class=\"emphasis\">fluor<\/em>, followed by\u00a0 the -<em class=\"emphasis\">ic acid<\/em> ending. Its name is hydrofluoric acid.<\/li>\r\n \t<li>This base is named as an ionic compound between the strontium ion and the hydroxide ion: strontium hydroxide.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch10_s01_qs01\" class=\"qandaset block\">\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Skill-Building Exercise<\/h3>\r\n<ol id=\"gob-ch10_s01_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch10_s01_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs01_p02\" class=\"para\">H<sub class=\"subscript\">2<\/sub>Se(aq)<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs01_p04\" class=\"para\">Ba(OH)<sub class=\"subscript\">2<\/sub>(aq)<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<p id=\"gob-ch10_s01_p10\" class=\"para editable block\">Notice that one base listed in <a class=\"xref\" href=\"#gob-ch10_s01_t01\">Table 10.1 \"Formulas and Names for Some Acids and Bases\"<\/a>\u2014ammonia\u2014does not have hydroxide as part of its formula. How does this compound increase the amount of hydroxide ion in aqueous solution? Instead of dissociating into hydroxide ions, ammonia molecules react with water molecules by taking a hydrogen ion from the water molecule to produce an ammonium ion and a hydroxide ion:<\/p>\r\n<p style=\"text-align: center\"><span class=\"informalequation block\"><span class=\"mathphrase\">NH<sub class=\"subscript\">3<\/sub>(aq) + H<sub class=\"subscript\">2<\/sub>O(\u2113) \u21c6 NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup>(aq) + OH<sup class=\"superscript\">\u2212<\/sup>(aq)<\/span><\/span><\/p>\r\n<p id=\"gob-ch10_s01_p11\" class=\"para editable block\">Because this reaction of ammonia with water causes an increase in the concentration of hydroxide ions in solution, ammonia satisfies the Arrhenius definition of a base. Many other nitrogen-containing compounds are bases because they too react with water to produce hydroxide ions in aqueous solution.<\/p>\r\n<p id=\"gob-ch10_s01_p12\" class=\"para editable block\">As noted previously, acids and bases react chemically with each other to form <em class=\"emphasis\">salts<\/em>. A salt is a general chemical term for any ionic compound formed from an acid and a base. In reactions where the acid is a hydrogen ion containing compound and the base is a hydroxide ion containing compound, water is also a product. The general reaction is as follows:<\/p>\r\n<p style=\"text-align: center\"><span class=\"informalequation block\"><span class=\"mathphrase\">acid + base \u2192 water + salt<\/span><\/span><\/p>\r\n<p id=\"gob-ch10_s01_p13\" class=\"para editable block\">The reaction of acid and base to make water and a salt is called <span class=\"margin_term\"><span class=\"glossterm\">neutralization<\/span><\/span>. Like any chemical equation, a neutralization chemical equation must be properly balanced. For example, the neutralization reaction between sodium hydroxide and hydrochloric acid is as follows:<\/p>\r\n<p style=\"text-align: center\"><span class=\"informalequation block\"><span class=\"mathphrase\">NaOH(aq) + HCl(aq) \u2192 NaCl(aq) + H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span><\/p>\r\n<p id=\"gob-ch10_s01_p14\" class=\"para editable block\">with coefficients all understood to be one. The neutralization reaction between sodium hydroxide and sulfuric acid is as follows:<\/p>\r\n<p style=\"text-align: center\"><span class=\"informalequation block\"><span class=\"mathphrase\">2NaOH(aq) + H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>(aq) \u2192 Na<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>(aq) + 2H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span><\/p>\r\n<p id=\"gob-ch10_s01_p15\" class=\"para editable block\">Once a neutralization reaction is properly balanced, it can be used to perform stoichiometry calculations, such as the ones\u00a0 in <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-5\">Chapter 5 \"Introduction to Chemical Reactions\"<\/a> and <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-6\">Chapter 6 \"Quantities in Chemical Reactions\"<\/a>.<\/p>\r\n\r\n<div id=\"gob-ch10_s01_n06\" class=\"exercises block\">\r\n<h3 class=\"title\">Example 2<\/h3>\r\n<p id=\"gob-ch10_s01_p16\" class=\"para\">Nitric acid, HNO<sub class=\"subscript\">3<\/sub>(aq), can be neutralized by calcium hydroxide Ca(OH)<sub class=\"subscript\">2<\/sub>(aq).<\/p>\r\n\r\n<ol id=\"gob-ch10_s01_l05\" class=\"orderedlist\">\r\n \t<li>Write a balanced chemical equation for the reaction between these two compounds and identify the salt it produces.<\/li>\r\n \t<li>For one reaction, 16.8 g of HNO<sub class=\"subscript\">3<\/sub> is present initially. How many grams of Ca(OH)<sub class=\"subscript\">2<\/sub> are needed to neutralize that much HNO<sub class=\"subscript\">3<\/sub>?<\/li>\r\n \t<li>In a second reaction, 805 mL of 0.672 M Ca(OH)<sub class=\"subscript\">2<\/sub> is present initially. What volume of 0.432 M HNO<sub class=\"subscript\">3<\/sub> solution is necessary to neutralize the Ca(OH)<sub class=\"subscript\">2<\/sub> solution?<\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution<\/p>\r\n\r\n<ol id=\"gob-ch10_s01_l06\" class=\"orderedlist\">\r\n \t<li>\r\n<p class=\"para\">Because there are two OH<sup class=\"superscript\">\u2212<\/sup> ions in the formula for Ca(OH)<sub class=\"subscript\">2<\/sub>, we need two moles of HNO<sub class=\"subscript\">3<\/sub> to provide enough H<sup class=\"superscript\">+<\/sup> ions. The balanced chemical equation is as follows:<\/p>\r\n<p style=\"text-align: center\"><span class=\"informalequation\"><span class=\"mathphrase\">Ca(OH)<sub class=\"subscript\">2<\/sub>(aq) + 2HNO<sub class=\"subscript\">3<\/sub>(aq) \u2192 Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>(aq) + 2H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span><\/p>\r\n<p id=\"gob-ch10_s01_p17\" class=\"para\">The salt formed is calcium nitrate.<\/p>\r\n<\/li>\r\n \t<li>\r\n<p class=\"para\">This calculation is much like the calculations in <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-6\">Chapter 6 \"Quantities in Chemical Reactions\"<\/a>. First convert the mass of HNO<sub class=\"subscript\">3<\/sub> to moles using its molar mass of 1.01 + 14.00 + 3(16.00) = 63.01 g\/mol; then use the balanced chemical equation to determine the related number of moles of Ca(OH)<sub class=\"subscript\">2<\/sub> needed to neutralize it; and then convert that number of moles of Ca(OH)<sub class=\"subscript\">2<\/sub> to the mass of Ca(OH)<sub class=\"subscript\">2<\/sub> using its molar mass of 40.08 + 2(1.01) + 2(16.00) = 74.10 g\/mol.<\/p>\r\n<span class=\"informalequation\"> [latex]16.8\\text{ g HNO}_3\\times{\\frac{1\\text{ mol HNO}_3}{63.01\\text{ gHNO}_3}}\\times\\frac{{1\\text{ mol Ca(OH)}_2}}{2\\text{ mol HNO}_3}\\times{\\frac{74.10\\text{ g Ca(OH)}_2}{1\\text{ mol Ca(OH)}_2}}=9.88\\text{ g Ca(OH)}_2[\/latex]\r\n<\/span><\/li>\r\n \t<li>\r\n<p class=\"para\">Having concentration information allows use of skills from\u00a0 <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-9\">Chapter 9 \"Solutions\"<\/a>. First, use the concentration and volume data to determine the number of moles of Ca(OH)<sub class=\"subscript\">2<\/sub> present. Recognizing that 805 mL = 0.805 L,<\/p>\r\n<span class=\"informalequation\">[latex]0.805\\text{ L Ca(OH)}_2\\text{ solution}\\times{\\frac{0.672\\text{ mol Ca(OH)}_2}{1\\text{ L Ca(OH)}_2\\text{ solution}}}\\times{\\frac{2\\text{ mol HNO}_3}{1\\text{ mol Ca(OH)}_2}}\\times{\\frac{1\\text{ L HNO}_3\\text{ solution}}{0.432\\text{ mol HNO}_3}}=2.50\\text{ L}[\/latex] \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>\r\n\r\n<span class=\"informalequation\">If the volume is required in mL, 2.50 x 10<sup>3<\/sup> mL expresses the correct value to the correct number of sig figs.<\/span><span class=\"informalequation\">\r\n<\/span><\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch10_s01_qs02\" class=\"qandaset block\">\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Skill-Building Exercise<\/h3>\r\n<ol id=\"gob-ch10_s01_qs02_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch10_s01_qs02_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs02_p02\" class=\"para\">Write a balanced chemical equation for the reaction between these two compounds and identify the salt it produces.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs02_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs02_p04\" class=\"para\">For one reaction, 37.5 g of HCN is present initially. How many grams of KOH are needed to neutralize that much HCN?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs02_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs02_p06\" class=\"para\">In a second reaction, 43.0 mL of 0.0663 M KOH is present initially. What volume of 0.107 M HCN solution is necessary to neutralize the KOH solution?<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch10_s01_n08\" class=\"callout editable block\">\r\n<div class=\"textbox\">\r\n<div id=\"gob-ch10_s01_n08\" class=\"callout editable block\">\r\n<h3 class=\"title\">Note<\/h3>\r\n<p id=\"gob-ch10_s01_p24\" class=\"para\">Hydrocyanic acid (HCN) is one exception to the acid-naming rules that specify using the prefix <em class=\"emphasis\">hydro-<\/em> for binary acids (acids composed of hydrogen and only one other element).<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<div id=\"gob-ch10_s01_n08\" class=\"callout editable block\">\r\n<h3 class=\"title\">Concept Review Exercises<\/h3>\r\n<\/div>\r\n<div id=\"gob-ch10_s01_qs03\" class=\"qandaset block\">\r\n<ol id=\"gob-ch10_s01_qs03_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch10_s01_qs03_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs03_p01\" class=\"para\">Give the Arrhenius definitions of an acid and a base.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs03_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs03_p03\" class=\"para\">What is neutralization?<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch10_s01_qs03_ans\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<h3 class=\"title\">Answers<\/h3>\r\n<ol class=\"qandadiv\">\r\n \t<li id=\"gob-ch10_s01_qs03_qd01_qa01_ans\" class=\"qandaentry\">\r\n<div class=\"answer\">\r\n<p id=\"gob-ch10_s01_qs03_p02_ans\" class=\"para\">Arrhenius acid: a compound that increases the concentration of hydrogen ion (H<sup class=\"superscript\">+<\/sup>) in aqueous solution; Arrhenius base: a compound that increases the concentration of hydroxide ion (OH<sup class=\"superscript\">\u2212<\/sup>) in aqueous solution.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs03_qd01_qa02_ans\" class=\"qandaentry\">\r\n<div class=\"answer\">\r\n<p id=\"gob-ch10_s01_qs03_p04_ans\" class=\"para\">the reaction of an acid and a base<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch10_s01_n10\" class=\"key_takeaways editable block\">\r\n<div class=\"textbox key-takeaways\">\r\n<h3 class=\"title\">Key Takeaway<\/h3>\r\n<ul id=\"gob-ch10_s01_l09\" class=\"itemizedlist\">\r\n \t<li>An Arrhenius acid increases the H<sup class=\"superscript\">+<\/sup> ion concentration in water, while an Arrhenius base increases the OH<sup class=\"superscript\">\u2212<\/sup> ion concentration in water.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch10_s01_qs04\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<h3>Exercises<\/h3>\r\n<ol id=\"gob-ch10_s01_qs04_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p01\" class=\"para\">Give two examples of Arrhenius acids.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p03\" class=\"para\">Give two examples of Arrhenius bases.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p05\" class=\"para\">List the general properties of acids.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p07\" class=\"para\">List the general properties of bases.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p09\" class=\"para\">Name each compound.<\/p>\r\n\r\n<ol id=\"gob-ch10_s01_qs04_l01\" class=\"orderedlist\">\r\n \t<li>HBr(aq)<\/li>\r\n \t<li>Ca(OH)<sub class=\"subscript\">2<\/sub>(aq)<\/li>\r\n \t<li>HNO<sub class=\"subscript\">3<\/sub>(aq)<\/li>\r\n \t<li>Fe(OH)<sub class=\"subscript\">3<\/sub>(aq)<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa06\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p10\" class=\"para\">Name each compound.<\/p>\r\n\r\n<ol id=\"gob-ch10_s01_qs04_l03\" class=\"orderedlist\">\r\n \t<li>HI(aq)<\/li>\r\n \t<li>Cu(OH)<sub class=\"subscript\">2<\/sub>(aq)<\/li>\r\n \t<li>H<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub>(aq)<\/li>\r\n \t<li>CsOH(aq)\r\n<p id=\"gob-ch10_s01_qs04_p11\" class=\"para\"><\/p>\r\n<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa09\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p15\" class=\"para\">Write a balanced chemical equation for the neutralization of Ba(OH)<sub class=\"subscript\">2<\/sub>(aq) with HNO<sub class=\"subscript\">3<\/sub>(aq).<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa10\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p17\" class=\"para\">Write a balanced chemical equation for the neutralization of H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>(aq) with Cr(OH)<sub class=\"subscript\">3<\/sub>(aq).<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa11\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p19\" class=\"para\">How many moles of sodium hydroxide (NaOH) are needed to neutralize 0.844 mol of acetic acid (HC<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">2<\/sub>)? (Hint: begin by writing a balanced chemical equation for the process.)<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa12\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p21\" class=\"para\">How many moles of perchloric acid (HClO<sub class=\"subscript\">4<\/sub>) are needed to neutralize 0.052 mol of calcium hydroxide [Ca(OH)<sub class=\"subscript\">2<\/sub>]? (Hint: begin by writing a balanced chemical equation for the process.)<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa13\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p23\" class=\"para\">Hydrazoic acid (HN<sub class=\"subscript\">3<\/sub>) can be neutralized by a base.<\/p>\r\n\r\n<ol id=\"gob-ch10_s01_qs04_l05\" class=\"orderedlist\">\r\n \t<li>Write the balanced chemical equation for the reaction between hydrazoic acid and calcium hydroxide.<\/li>\r\n \t<li>How many milliliters of 0.0245 M Ca(OH)<sub class=\"subscript\">2<\/sub> are needed to neutralize 0.564 g of HN<sub class=\"subscript\">3<\/sub>?<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa14\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p24\" class=\"para\">Citric acid (H<sub class=\"subscript\">3<\/sub>C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">5<\/sub>O<sub class=\"subscript\">7<\/sub>) has three hydrogen atoms that can form hydrogen ions in solution.<\/p>\r\n\r\n<ol id=\"gob-ch10_s01_qs04_l07\" class=\"orderedlist\">\r\n \t<li>Write the balanced chemical equation for the reaction between citric acid and sodium hydroxide.<\/li>\r\n \t<li>If an orange contains 0.0675 g of H<sub class=\"subscript\">3<\/sub>C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">5<\/sub>O<sub class=\"subscript\">7<\/sub>, how many milliliters of 0.00332 M NaOH solution are needed to neutralize the acid?<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa15\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p25\" class=\"para\">Magnesium hydroxide [Mg(OH)<sub class=\"subscript\">2<\/sub>] is an ingredient in some antacids. How many grams of Mg(OH)<sub class=\"subscript\">2<\/sub> are needed to neutralize the acid in 158 mL of 0.106 M HCl(aq)? It might help to write the balanced chemical equation first.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch10_s01_qs04_qd01_qa16\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch10_s01_qs04_p27\" class=\"para\">Aluminum hydroxide [Al(OH)<sub class=\"subscript\">3<\/sub>] is an ingredient in some antacids. How many grams of Al(OH)<sub class=\"subscript\">3<\/sub> are needed to neutralize the acid in 96.5 mL of 0.556 M H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>(aq)? It might help to write the balanced chemical equation first.<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch10_s01_qs04_ans\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<h3><\/h3>\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch10_s01\" class=\"section\" xml:lang=\"en\">\r\n<div id=\"gob-ch10_s01_qs04_ans\" class=\"qandaset block\">\r\n<h3 class=\"title\">Answers<\/h3>\r\n<div class=\"answer\">\r\n<p id=\"gob-ch10_s01_qs04_p02_ans\" class=\"para\">1. HCl and HNO<sub class=\"subscript\">3<\/sub> (answers will vary)<\/p>\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n<p id=\"gob-ch10_s01_qs04_p06_ans\" class=\"para\">3. sour taste, react with metals, react with bases, and turn litmus red<\/p>\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n\r\n5. a. hydrobromic acid\r\n\r\nb. calcium hydroxide\r\n\r\nc. nitric acid\r\n\r\nd. iron(III) hydroxide\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n<p id=\"gob-ch10_s01_qs04_p16_ans\" class=\"para\">7. 2HNO<sub class=\"subscript\">3<\/sub>(aq) + Ba(OH)<sub class=\"subscript\">2<\/sub>(aq) \u2192 Ba(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>(aq) + 2H<sub class=\"subscript\">2<\/sub>O<\/p>\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n<p id=\"gob-ch10_s01_qs04_p20_ans\" class=\"para\">9. 0.844 mol<\/p>\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n\r\n11. a. 2HN<sub class=\"subscript\">3<\/sub>(aq) + Ca(OH)<sub class=\"subscript\">2<\/sub> \u2192 Ca(N<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> + 2H<sub class=\"subscript\">2<\/sub>O\r\n\r\nb. 268 mL\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n<p id=\"gob-ch10_s01_qs04_p26_ans\" class=\"para\">13. 0.488 g<\/p>\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"navbar-bottom\" class=\"navbar\"><\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"navbar-top\" class=\"navbar\">\n<div class=\"navbar-part left\"><\/div>\n<\/div>\n<div id=\"book-content\">\n<div id=\"gob-ch10_s01\" class=\"section\" xml:lang=\"en\">\n<h2 class=\"title editable block\"><span class=\"title-prefix\">10.1<\/span> Arrhenius Definition of Acids and Bases<\/h2>\n<div id=\"gob-ch10_s01_n01\" class=\"learning_objectives editable block\">\n<div class=\"textbox learning-objectives\">\n<h3 class=\"title\">Learning Objective<\/h3>\n<ol id=\"gob-ch10_s01_l01\" class=\"orderedlist\">\n<li>Recognize a compound as an Arrhenius acid or an Arrhenius base.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"gob-ch10_s01_p01\" class=\"para editable block\">One way to define a class of compounds is by describing the various characteristics its members have in common. In the case of <strong>acids, the common characteristics include a sour taste, the ability to change the color of <em class=\"emphasis\">litmus<\/em> to red, and the ability to react with certain metals<\/strong>, eroding the metal and producing hydrogen gas and an ionic compound. For<strong> bases, the common characteristics are a slippery texture, a bitter taste, and the ability to change the color of litmus to blue.<\/strong>\u00a0 Acids and bases also react with each other in neutralization reactions, forming water and ionic compounds, also known as salts.<\/p>\n<p><strong>Indicators<\/strong> are compounds that exhibit different colors when placed in solutions with different acid\/base (pH) balances.\u00a0 As described in the previous paragraph, litmus, a compound obtained from lichens, is an indicator because it is blue when in a basic solutions and red when in an acidic solution. Juice from purple cabbage is another natural indicator, and it exhibits a wide range of colors based on the pH it experiences as seen in Figure 10.1 below.\u00a0 Other indicators include phenolphthalein and\u00a0 bromothymol blue.\u00a0 Indicaotrs are often used in<strong> titration<\/strong>, a measured form of\u00a0 neutralization reaction, to visually indicate that the moles of acid and moles of base are balanced at the equivalence point.<\/p>\n<div class=\"textbox shaded\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-3453 aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3331\/2018\/03\/03134610\/purple-cabbage-indicator1-300x182.jpg\" alt=\"\" width=\"508\" height=\"308\" \/>Figure 10.1 Purple Cabbage Juice Indicator at Various pH Levels.\u00a0 Attribution: By Indikator-Blaukraut.JPG: Supermartlderivative work: Haltopub (Indikator-Blaukraut.JPG) [CC BY-SA 3.0 (https:\/\/creativecommons.org\/licenses\/by-sa\/3.0) or GFDL (http:\/\/www.gnu.org\/copyleft\/fdl.html)], via Wikimedia Commons<\/div>\n<div id=\"gob-ch10_s01_n02\" class=\"callout editable block\">\n<div class=\"textbox\">\n<h3 class=\"title\">Note<\/h3>\n<p id=\"gob-ch10_s01_p02\" class=\"para\">Although tastes are included among the common characteristics of acids and bases, never taste an unknown chemical!<\/p>\n<\/div>\n<\/div>\n<p id=\"gob-ch10_s01_p03\" class=\"para editable block\">Chemists define acids and bases in terms of their chemical properties, but the definitions differ in models developed at different times.\u00a0 The Swedish chemist Svante Arrhenius developed the first chemical definitions of acids and bases in the late 1800s. <strong>Arrhenius<\/strong> defined an <strong><span class=\"margin_term\"><span class=\"glossterm\">acid<\/span><\/span>\u00a0as a compound that increases the concentration of hydrogen ion (H<sup class=\"superscript\">+<\/sup>) in aqueous solution<\/strong>. Many acids are simple compounds that release a hydrogen cation into solution when they dissolve. Similarly, Arrhenius defined a<strong> <span class=\"margin_term\"><span class=\"glossterm\">base<\/span><\/span>\u00a0as a compound that increases the concentration of hydroxide ion (OH<sup class=\"superscript\">\u2212<\/sup>) in aqueous solution.<\/strong> Many bases are ionic compounds that have the hydroxide ion as their anion, which is released when the base dissolves in water.<\/p>\n<p id=\"gob-ch10_s01_p04\" class=\"para editable block\">Many bases and their aqueous solutions are named using the normal rules of ionic compounds that were presented in <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-3\">Chapter 3 &#8220;Ionic Bonding and Simple Ionic Compounds&#8221;<\/a>, <a class=\"xref\" href=\"gob-ch03_s04#gob-ch03_s04\">Section 3.4 &#8220;Ionic Nomenclature&#8221;.\u00a0<\/a> For example, the name sodium hydroxide (NaOH) is used as the name of the ionic compound <em>and<\/em> for an aqueous solution of the compound.<\/p>\n<p class=\"para editable block\">However, aqueous solutions of binary acids,\u00a0compounds with hydrogen and one other element in their formula, have one name for the compound alone and a different name when the compound is dissolved in water. Such a compound alone is named <em>hydrogen<span style=\"text-decoration: underline\">\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span>ide<\/em> with the blank being filled with the element&#8217;s root name.\u00a0 For example, HCl not dissolved in water is hydrogen chloride.But when hydrogen chloride dissolves in water, its name changes to hydrochloric acid, following the pattern\u00a0<em>hydro <span style=\"text-decoration: underline\"> \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 <\/span>ic acid, <\/em> again with the blank being replaced by the element&#8217;s root name.<\/p>\n<p class=\"para editable block\">Acids composed of more than two elements, typically one to three hydrogen atoms with a polyatomic ion. The name of an oxyacid is based on the name of the polyatomic ion.\u00a0 If the polyatomic ion name ends with <em>-ate<\/em>, name of its acid will end in <em>-ic acid<\/em>.\u00a0 If the polyatomic ion mane ends in <em>-ite<\/em>, the name of the acid ends in <em>-ous acid. <\/em>\u00a0 For example HNO<sub>3<\/sub> is nitric acid because it contains the nitrate polyatomic ion.\u00a0 HNO<sub>2<\/sub> is nitrous acid because it contains the polyatomic ion nitrite.<\/p>\n<p class=\"para editable block\">. <a class=\"xref\" href=\"#gob-ch10_s01_t01\">Table 10.1 &#8220;Formulas and Names for Some Acids and Bases&#8221;<\/a> lists some acids and bases and their names. Note that acids have hydrogen written first, as if it were the cation, while bases that have the negative hydroxide ion have it written last.<\/p>\n<div id=\"gob-ch10_s01_n03\" class=\"callout editable block\">\n<div class=\"textbox\">\n<h3 class=\"title\">Note<\/h3>\n<p id=\"gob-ch10_s01_p05\" class=\"para\">The name <em class=\"emphasis\">oxygen<\/em> comes from the Latin meaning \u201cacid producer\u201d because its discoverer, Antoine Lavoisier, thought it was the essential element in acids. Lavoisier was wrong, but it is too late to change the name now.<\/p>\n<\/div>\n<\/div>\n<div id=\"gob-ch10_s01_t01\" class=\"table block\">\n<p class=\"title\"><span class=\"title-prefix\">Table 10.1<\/span> Formulas and Names for Some Acids and Bases<\/p>\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\n<thead>\n<tr>\n<th>Formula<\/th>\n<th>Name<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td colspan=\"2\"><strong class=\"emphasis bold\">Acids<\/strong><\/td>\n<\/tr>\n<tr>\n<td>HCl(aq)<\/td>\n<td>hydrochloric acid<\/td>\n<\/tr>\n<tr>\n<td>HBr(aq)<\/td>\n<td>hydrobromic acid<\/td>\n<\/tr>\n<tr>\n<td>HI(aq)<\/td>\n<td>hydriodic acid<\/td>\n<\/tr>\n<tr>\n<td>H<sub class=\"subscript\">2<\/sub>S(aq)<\/td>\n<td>hydrosulfuric acid<\/td>\n<\/tr>\n<tr>\n<td>HC<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">2<\/sub>(aq)<\/td>\n<td>acetic acid<\/td>\n<\/tr>\n<tr>\n<td>HNO<sub class=\"subscript\">3<\/sub>(aq)<\/td>\n<td>nitric acid<\/td>\n<\/tr>\n<tr>\n<td>HNO<sub class=\"subscript\">2<\/sub>(aq)<\/td>\n<td>nitrous acid<\/td>\n<\/tr>\n<tr>\n<td>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>(aq)<\/td>\n<td>sulfuric acid<\/td>\n<\/tr>\n<tr>\n<td>H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">3<\/sub>(aq)<\/td>\n<td>sulfurous acid<\/td>\n<\/tr>\n<tr>\n<td>HClO<sub class=\"subscript\">3<\/sub>(aq)<\/td>\n<td>chloric acid<\/td>\n<\/tr>\n<tr>\n<td>HClO<sub class=\"subscript\">4<\/sub>(aq)<\/td>\n<td>perchloric acid<\/td>\n<\/tr>\n<tr>\n<td>HClO<sub class=\"subscript\">2<\/sub>(aq)<\/td>\n<td>chlorous acid<\/td>\n<\/tr>\n<tr>\n<td>H<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub>(aq)<\/td>\n<td>phosphoric acid<\/td>\n<\/tr>\n<tr>\n<td>H<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">3<\/sub>(aq)<\/td>\n<td>phosphorous acid<\/td>\n<\/tr>\n<tr>\n<td colspan=\"2\"><strong class=\"emphasis bold\">Bases<\/strong><\/td>\n<\/tr>\n<tr>\n<td>NaOH(aq)<\/td>\n<td>sodium hydroxide<\/td>\n<\/tr>\n<tr>\n<td>KOH(aq)<\/td>\n<td>potassium hydroxide<\/td>\n<\/tr>\n<tr>\n<td>Mg(OH)<sub class=\"subscript\">2<\/sub>(aq)<\/td>\n<td>magnesium hydroxide<\/td>\n<\/tr>\n<tr>\n<td>Ca(OH)<sub class=\"subscript\">2<\/sub>(aq)<\/td>\n<td>calcium hydroxide<\/td>\n<\/tr>\n<tr>\n<td>NH<sub class=\"subscript\">3<\/sub>(aq)<\/td>\n<td>ammonia<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<div id=\"gob-ch10_s01_n04\" class=\"exercises editable block\">\n<h3 class=\"title\">Example 1<\/h3>\n<p id=\"gob-ch10_s01_p06\" class=\"para\">Name each substance.<\/p>\n<ol id=\"gob-ch10_s01_l02\" class=\"orderedlist\">\n<li>HF(aq)<\/li>\n<li>Sr(OH)<sub class=\"subscript\">2<\/sub>(aq)<\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<ol id=\"gob-ch10_s01_l03\" class=\"orderedlist\">\n<li>This acid has only two elements in its formula, so its name includes the <em class=\"emphasis\">hydro<\/em>&#8211; prefix. The stem of the other element\u2019s name, fluorine, is <em class=\"emphasis\">fluor<\/em>, followed by\u00a0 the &#8211;<em class=\"emphasis\">ic acid<\/em> ending. Its name is hydrofluoric acid.<\/li>\n<li>This base is named as an ionic compound between the strontium ion and the hydroxide ion: strontium hydroxide.<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch10_s01_qs01\" class=\"qandaset block\">\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Skill-Building Exercise<\/h3>\n<ol id=\"gob-ch10_s01_qs01_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch10_s01_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs01_p02\" class=\"para\">H<sub class=\"subscript\">2<\/sub>Se(aq)<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs01_p04\" class=\"para\">Ba(OH)<sub class=\"subscript\">2<\/sub>(aq)<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"gob-ch10_s01_p10\" class=\"para editable block\">Notice that one base listed in <a class=\"xref\" href=\"#gob-ch10_s01_t01\">Table 10.1 &#8220;Formulas and Names for Some Acids and Bases&#8221;<\/a>\u2014ammonia\u2014does not have hydroxide as part of its formula. How does this compound increase the amount of hydroxide ion in aqueous solution? Instead of dissociating into hydroxide ions, ammonia molecules react with water molecules by taking a hydrogen ion from the water molecule to produce an ammonium ion and a hydroxide ion:<\/p>\n<p style=\"text-align: center\"><span class=\"informalequation block\"><span class=\"mathphrase\">NH<sub class=\"subscript\">3<\/sub>(aq) + H<sub class=\"subscript\">2<\/sub>O(\u2113) \u21c6 NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup>(aq) + OH<sup class=\"superscript\">\u2212<\/sup>(aq)<\/span><\/span><\/p>\n<p id=\"gob-ch10_s01_p11\" class=\"para editable block\">Because this reaction of ammonia with water causes an increase in the concentration of hydroxide ions in solution, ammonia satisfies the Arrhenius definition of a base. Many other nitrogen-containing compounds are bases because they too react with water to produce hydroxide ions in aqueous solution.<\/p>\n<p id=\"gob-ch10_s01_p12\" class=\"para editable block\">As noted previously, acids and bases react chemically with each other to form <em class=\"emphasis\">salts<\/em>. A salt is a general chemical term for any ionic compound formed from an acid and a base. In reactions where the acid is a hydrogen ion containing compound and the base is a hydroxide ion containing compound, water is also a product. The general reaction is as follows:<\/p>\n<p style=\"text-align: center\"><span class=\"informalequation block\"><span class=\"mathphrase\">acid + base \u2192 water + salt<\/span><\/span><\/p>\n<p id=\"gob-ch10_s01_p13\" class=\"para editable block\">The reaction of acid and base to make water and a salt is called <span class=\"margin_term\"><span class=\"glossterm\">neutralization<\/span><\/span>. Like any chemical equation, a neutralization chemical equation must be properly balanced. For example, the neutralization reaction between sodium hydroxide and hydrochloric acid is as follows:<\/p>\n<p style=\"text-align: center\"><span class=\"informalequation block\"><span class=\"mathphrase\">NaOH(aq) + HCl(aq) \u2192 NaCl(aq) + H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span><\/p>\n<p id=\"gob-ch10_s01_p14\" class=\"para editable block\">with coefficients all understood to be one. The neutralization reaction between sodium hydroxide and sulfuric acid is as follows:<\/p>\n<p style=\"text-align: center\"><span class=\"informalequation block\"><span class=\"mathphrase\">2NaOH(aq) + H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>(aq) \u2192 Na<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>(aq) + 2H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span><\/p>\n<p id=\"gob-ch10_s01_p15\" class=\"para editable block\">Once a neutralization reaction is properly balanced, it can be used to perform stoichiometry calculations, such as the ones\u00a0 in <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-5\">Chapter 5 &#8220;Introduction to Chemical Reactions&#8221;<\/a> and <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-6\">Chapter 6 &#8220;Quantities in Chemical Reactions&#8221;<\/a>.<\/p>\n<div id=\"gob-ch10_s01_n06\" class=\"exercises block\">\n<h3 class=\"title\">Example 2<\/h3>\n<p id=\"gob-ch10_s01_p16\" class=\"para\">Nitric acid, HNO<sub class=\"subscript\">3<\/sub>(aq), can be neutralized by calcium hydroxide Ca(OH)<sub class=\"subscript\">2<\/sub>(aq).<\/p>\n<ol id=\"gob-ch10_s01_l05\" class=\"orderedlist\">\n<li>Write a balanced chemical equation for the reaction between these two compounds and identify the salt it produces.<\/li>\n<li>For one reaction, 16.8 g of HNO<sub class=\"subscript\">3<\/sub> is present initially. How many grams of Ca(OH)<sub class=\"subscript\">2<\/sub> are needed to neutralize that much HNO<sub class=\"subscript\">3<\/sub>?<\/li>\n<li>In a second reaction, 805 mL of 0.672 M Ca(OH)<sub class=\"subscript\">2<\/sub> is present initially. What volume of 0.432 M HNO<sub class=\"subscript\">3<\/sub> solution is necessary to neutralize the Ca(OH)<sub class=\"subscript\">2<\/sub> solution?<\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<ol id=\"gob-ch10_s01_l06\" class=\"orderedlist\">\n<li>\n<p class=\"para\">Because there are two OH<sup class=\"superscript\">\u2212<\/sup> ions in the formula for Ca(OH)<sub class=\"subscript\">2<\/sub>, we need two moles of HNO<sub class=\"subscript\">3<\/sub> to provide enough H<sup class=\"superscript\">+<\/sup> ions. The balanced chemical equation is as follows:<\/p>\n<p style=\"text-align: center\"><span class=\"informalequation\"><span class=\"mathphrase\">Ca(OH)<sub class=\"subscript\">2<\/sub>(aq) + 2HNO<sub class=\"subscript\">3<\/sub>(aq) \u2192 Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>(aq) + 2H<sub class=\"subscript\">2<\/sub>O(\u2113)<\/span><\/span><\/p>\n<p id=\"gob-ch10_s01_p17\" class=\"para\">The salt formed is calcium nitrate.<\/p>\n<\/li>\n<li>\n<p class=\"para\">This calculation is much like the calculations in <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-6\">Chapter 6 &#8220;Quantities in Chemical Reactions&#8221;<\/a>. First convert the mass of HNO<sub class=\"subscript\">3<\/sub> to moles using its molar mass of 1.01 + 14.00 + 3(16.00) = 63.01 g\/mol; then use the balanced chemical equation to determine the related number of moles of Ca(OH)<sub class=\"subscript\">2<\/sub> needed to neutralize it; and then convert that number of moles of Ca(OH)<sub class=\"subscript\">2<\/sub> to the mass of Ca(OH)<sub class=\"subscript\">2<\/sub> using its molar mass of 40.08 + 2(1.01) + 2(16.00) = 74.10 g\/mol.<\/p>\n<p><span class=\"informalequation\"> [latex]16.8\\text{ g HNO}_3\\times{\\frac{1\\text{ mol HNO}_3}{63.01\\text{ gHNO}_3}}\\times\\frac{{1\\text{ mol Ca(OH)}_2}}{2\\text{ mol HNO}_3}\\times{\\frac{74.10\\text{ g Ca(OH)}_2}{1\\text{ mol Ca(OH)}_2}}=9.88\\text{ g Ca(OH)}_2[\/latex]<br \/>\n<\/span><\/li>\n<li>\n<p class=\"para\">Having concentration information allows use of skills from\u00a0 <a class=\"xref\" href=\"..\/suny-orgbiochemistry\/chapter\/introduction-9\">Chapter 9 &#8220;Solutions&#8221;<\/a>. First, use the concentration and volume data to determine the number of moles of Ca(OH)<sub class=\"subscript\">2<\/sub> present. Recognizing that 805 mL = 0.805 L,<\/p>\n<p><span class=\"informalequation\">[latex]0.805\\text{ L Ca(OH)}_2\\text{ solution}\\times{\\frac{0.672\\text{ mol Ca(OH)}_2}{1\\text{ L Ca(OH)}_2\\text{ solution}}}\\times{\\frac{2\\text{ mol HNO}_3}{1\\text{ mol Ca(OH)}_2}}\\times{\\frac{1\\text{ L HNO}_3\\text{ solution}}{0.432\\text{ mol HNO}_3}}=2.50\\text{ L}[\/latex] \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/span><\/p>\n<p><span class=\"informalequation\">If the volume is required in mL, 2.50 x 10<sup>3<\/sup> mL expresses the correct value to the correct number of sig figs.<\/span><span class=\"informalequation\"><br \/>\n<\/span><\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch10_s01_qs02\" class=\"qandaset block\">\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Skill-Building Exercise<\/h3>\n<ol id=\"gob-ch10_s01_qs02_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch10_s01_qs02_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs02_p02\" class=\"para\">Write a balanced chemical equation for the reaction between these two compounds and identify the salt it produces.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs02_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs02_p04\" class=\"para\">For one reaction, 37.5 g of HCN is present initially. How many grams of KOH are needed to neutralize that much HCN?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs02_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs02_p06\" class=\"para\">In a second reaction, 43.0 mL of 0.0663 M KOH is present initially. What volume of 0.107 M HCN solution is necessary to neutralize the KOH solution?<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div id=\"gob-ch10_s01_n08\" class=\"callout editable block\">\n<div class=\"textbox\">\n<div id=\"gob-ch10_s01_n08\" class=\"callout editable block\">\n<h3 class=\"title\">Note<\/h3>\n<p id=\"gob-ch10_s01_p24\" class=\"para\">Hydrocyanic acid (HCN) is one exception to the acid-naming rules that specify using the prefix <em class=\"emphasis\">hydro-<\/em> for binary acids (acids composed of hydrogen and only one other element).<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<div id=\"gob-ch10_s01_n08\" class=\"callout editable block\">\n<h3 class=\"title\">Concept Review Exercises<\/h3>\n<\/div>\n<div id=\"gob-ch10_s01_qs03\" class=\"qandaset block\">\n<ol id=\"gob-ch10_s01_qs03_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch10_s01_qs03_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs03_p01\" class=\"para\">Give the Arrhenius definitions of an acid and a base.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs03_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs03_p03\" class=\"para\">What is neutralization?<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch10_s01_qs03_ans\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<h3 class=\"title\">Answers<\/h3>\n<ol class=\"qandadiv\">\n<li id=\"gob-ch10_s01_qs03_qd01_qa01_ans\" class=\"qandaentry\">\n<div class=\"answer\">\n<p id=\"gob-ch10_s01_qs03_p02_ans\" class=\"para\">Arrhenius acid: a compound that increases the concentration of hydrogen ion (H<sup class=\"superscript\">+<\/sup>) in aqueous solution; Arrhenius base: a compound that increases the concentration of hydroxide ion (OH<sup class=\"superscript\">\u2212<\/sup>) in aqueous solution.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs03_qd01_qa02_ans\" class=\"qandaentry\">\n<div class=\"answer\">\n<p id=\"gob-ch10_s01_qs03_p04_ans\" class=\"para\">the reaction of an acid and a base<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div id=\"gob-ch10_s01_n10\" class=\"key_takeaways editable block\">\n<div class=\"textbox key-takeaways\">\n<h3 class=\"title\">Key Takeaway<\/h3>\n<ul id=\"gob-ch10_s01_l09\" class=\"itemizedlist\">\n<li>An Arrhenius acid increases the H<sup class=\"superscript\">+<\/sup> ion concentration in water, while an Arrhenius base increases the OH<sup class=\"superscript\">\u2212<\/sup> ion concentration in water.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div id=\"gob-ch10_s01_qs04\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<h3>Exercises<\/h3>\n<ol id=\"gob-ch10_s01_qs04_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch10_s01_qs04_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p01\" class=\"para\">Give two examples of Arrhenius acids.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p03\" class=\"para\">Give two examples of Arrhenius bases.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p05\" class=\"para\">List the general properties of acids.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p07\" class=\"para\">List the general properties of bases.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p09\" class=\"para\">Name each compound.<\/p>\n<ol id=\"gob-ch10_s01_qs04_l01\" class=\"orderedlist\">\n<li>HBr(aq)<\/li>\n<li>Ca(OH)<sub class=\"subscript\">2<\/sub>(aq)<\/li>\n<li>HNO<sub class=\"subscript\">3<\/sub>(aq)<\/li>\n<li>Fe(OH)<sub class=\"subscript\">3<\/sub>(aq)<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p10\" class=\"para\">Name each compound.<\/p>\n<ol id=\"gob-ch10_s01_qs04_l03\" class=\"orderedlist\">\n<li>HI(aq)<\/li>\n<li>Cu(OH)<sub class=\"subscript\">2<\/sub>(aq)<\/li>\n<li>H<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub>(aq)<\/li>\n<li>CsOH(aq)\n<p id=\"gob-ch10_s01_qs04_p11\" class=\"para\">\n<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p15\" class=\"para\">Write a balanced chemical equation for the neutralization of Ba(OH)<sub class=\"subscript\">2<\/sub>(aq) with HNO<sub class=\"subscript\">3<\/sub>(aq).<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa10\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p17\" class=\"para\">Write a balanced chemical equation for the neutralization of H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>(aq) with Cr(OH)<sub class=\"subscript\">3<\/sub>(aq).<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa11\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p19\" class=\"para\">How many moles of sodium hydroxide (NaOH) are needed to neutralize 0.844 mol of acetic acid (HC<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">3<\/sub>O<sub class=\"subscript\">2<\/sub>)? (Hint: begin by writing a balanced chemical equation for the process.)<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa12\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p21\" class=\"para\">How many moles of perchloric acid (HClO<sub class=\"subscript\">4<\/sub>) are needed to neutralize 0.052 mol of calcium hydroxide [Ca(OH)<sub class=\"subscript\">2<\/sub>]? (Hint: begin by writing a balanced chemical equation for the process.)<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa13\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p23\" class=\"para\">Hydrazoic acid (HN<sub class=\"subscript\">3<\/sub>) can be neutralized by a base.<\/p>\n<ol id=\"gob-ch10_s01_qs04_l05\" class=\"orderedlist\">\n<li>Write the balanced chemical equation for the reaction between hydrazoic acid and calcium hydroxide.<\/li>\n<li>How many milliliters of 0.0245 M Ca(OH)<sub class=\"subscript\">2<\/sub> are needed to neutralize 0.564 g of HN<sub class=\"subscript\">3<\/sub>?<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa14\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p24\" class=\"para\">Citric acid (H<sub class=\"subscript\">3<\/sub>C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">5<\/sub>O<sub class=\"subscript\">7<\/sub>) has three hydrogen atoms that can form hydrogen ions in solution.<\/p>\n<ol id=\"gob-ch10_s01_qs04_l07\" class=\"orderedlist\">\n<li>Write the balanced chemical equation for the reaction between citric acid and sodium hydroxide.<\/li>\n<li>If an orange contains 0.0675 g of H<sub class=\"subscript\">3<\/sub>C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">5<\/sub>O<sub class=\"subscript\">7<\/sub>, how many milliliters of 0.00332 M NaOH solution are needed to neutralize the acid?<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa15\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p25\" class=\"para\">Magnesium hydroxide [Mg(OH)<sub class=\"subscript\">2<\/sub>] is an ingredient in some antacids. How many grams of Mg(OH)<sub class=\"subscript\">2<\/sub> are needed to neutralize the acid in 158 mL of 0.106 M HCl(aq)? It might help to write the balanced chemical equation first.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch10_s01_qs04_qd01_qa16\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch10_s01_qs04_p27\" class=\"para\">Aluminum hydroxide [Al(OH)<sub class=\"subscript\">3<\/sub>] is an ingredient in some antacids. How many grams of Al(OH)<sub class=\"subscript\">3<\/sub> are needed to neutralize the acid in 96.5 mL of 0.556 M H<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>(aq)? It might help to write the balanced chemical equation first.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div id=\"gob-ch10_s01_qs04_ans\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<h3><\/h3>\n<div id=\"book-content\">\n<div id=\"gob-ch10_s01\" class=\"section\" xml:lang=\"en\">\n<div id=\"gob-ch10_s01_qs04_ans\" class=\"qandaset block\">\n<h3 class=\"title\">Answers<\/h3>\n<div class=\"answer\">\n<p id=\"gob-ch10_s01_qs04_p02_ans\" class=\"para\">1. HCl and HNO<sub class=\"subscript\">3<\/sub> (answers will vary)<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p id=\"gob-ch10_s01_qs04_p06_ans\" class=\"para\">3. sour taste, react with metals, react with bases, and turn litmus red<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p>5. a. hydrobromic acid<\/p>\n<p>b. calcium hydroxide<\/p>\n<p>c. nitric acid<\/p>\n<p>d. iron(III) hydroxide<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p id=\"gob-ch10_s01_qs04_p16_ans\" class=\"para\">7. 2HNO<sub class=\"subscript\">3<\/sub>(aq) + Ba(OH)<sub class=\"subscript\">2<\/sub>(aq) \u2192 Ba(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>(aq) + 2H<sub class=\"subscript\">2<\/sub>O<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p id=\"gob-ch10_s01_qs04_p20_ans\" class=\"para\">9. 0.844 mol<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p>11. a. 2HN<sub class=\"subscript\">3<\/sub>(aq) + Ca(OH)<sub class=\"subscript\">2<\/sub> \u2192 Ca(N<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> + 2H<sub class=\"subscript\">2<\/sub>O<\/p>\n<p>b. 268 mL<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p id=\"gob-ch10_s01_qs04_p26_ans\" class=\"para\">13. 0.488 g<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"navbar-bottom\" class=\"navbar\"><\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-848\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>The Basics of General, Organic, and Biological Chemistry v. 1.0. <strong>Provided by<\/strong>: Saylor Academy. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\">https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc\/4.0\/\">CC BY-NC: Attribution-NonCommercial<\/a><\/em>. <strong>License Terms<\/strong>: This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work&#039;s original creator or licensor.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":44985,"menu_order":2,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"The Basics of General, Organic, and Biological Chemistry v. 1.0\",\"author\":\"\",\"organization\":\"Saylor 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