{"id":237,"date":"2018-03-19T16:07:27","date_gmt":"2018-03-19T16:07:27","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/chapter\/ionic-nomenclature\/"},"modified":"2018-04-05T15:42:11","modified_gmt":"2018-04-05T15:42:11","slug":"ionic-nomenclature","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/chapter\/ionic-nomenclature\/","title":{"raw":"3.4 Ionic Nomenclature","rendered":"3.4 Ionic Nomenclature"},"content":{"raw":"<div id=\"book-content\">\r\n<div id=\"gob-ch03_s04\" class=\"section\" xml:lang=\"en\">\r\n<div id=\"gob-ch03_s04_n01\" class=\"learning_objectives editable block\">\r\n<div class=\"textbox learning-objectives\" style=\"text-align: left\">\r\n<h3>Learning Objectives<\/h3>\r\n1. Use the rules for naming ionic compounds.\r\n\r\n<\/div>\r\n<span style=\"font-size: 1rem;text-align: initial\">After learning a few more details about the names of individual ions, you will be a step away from knowing how to name ionic compounds. This section begins the formal study of <\/span><span class=\"margin_term\" style=\"font-size: 1rem;text-align: initial\"><strong><span class=\"glossterm\">nomenclature<\/span><\/strong><\/span><span style=\"font-size: 1rem;text-align: initial\">, the systematic naming of chemical compounds.<\/span>\r\n\r\n<\/div>\r\n<div id=\"gob-ch03_s04_s01\" class=\"section\">\r\n<h2 class=\"title editable block\">Naming Ions<\/h2>\r\n<p id=\"gob-ch03_s04_s01_p01\" class=\"para editable block\">The name of a monatomic cation is simply the name of the element followed by the word <em class=\"emphasis\">ion<\/em>. Thus, Na<sup class=\"superscript\">+<\/sup> is the sodium ion, Al<sup class=\"superscript\">3+<\/sup> is the aluminum ion, Ca<sup class=\"superscript\">2+<\/sup> is the calcium ion, and so forth.<\/p>\r\n<p id=\"gob-ch03_s04_s01_p02\" class=\"para editable block\">We have seen that some elements lose different numbers of electrons, producing ions of different charges (<a class=\"xref\" href=\"gob-ch03_s02#gob-ch03_s02_s01_f03\">Figure 3.3 \"Predicting Ionic Charges\"<\/a>). Iron, for example, can form two cations, each of which, when combined with the same anion, makes a different compound with unique physical and chemical properties. Thus, we need a different name for each iron ion to distinguish Fe<sup class=\"superscript\">2+<\/sup> from Fe<sup class=\"superscript\">3+<\/sup>. The same issue arises for other ions with more than one possible charge.<\/p>\r\n<p id=\"gob-ch03_s04_s01_p03\" class=\"para editable block\">There are two ways to make this distinction. In the simpler, more modern approach, called the <span class=\"margin_term\"><strong><span class=\"glossterm\">Stock system<\/span><\/strong><\/span>, an ion\u2019s positive charge is indicated by a roman numeral in parentheses after the element name, followed by the word <em class=\"emphasis\">ion<\/em>. Thus, Fe<sup class=\"superscript\">2+<\/sup> is called the iron(II) ion, while Fe<sup class=\"superscript\">3+<\/sup> is called the iron(III) ion. This system is used only for elements that form more than one common positive ion. We do not call the Na<sup class=\"superscript\">+<\/sup> ion the sodium(I) ion because (I) is unnecessary. Sodium forms only a 1+ ion, so there is no ambiguity about the name <em class=\"emphasis\">sodium ion<\/em>.<\/p>\r\n<p id=\"gob-ch03_s04_s01_p04\" class=\"para editable block\">The second system, called the <strong class=\"emphasis bold\">common system<\/strong>, is not conventional but is still prevalent and used in the health sciences. This system recognizes that many metals have two common cations. The common system uses two suffixes (-<em class=\"emphasis\">ic<\/em> and -<em class=\"emphasis\">ous<\/em>) that are appended to the stem of the element name. The <em class=\"emphasis\">-ic<\/em> suffix represents the greater of the two cation charges, and the <em class=\"emphasis\">-ous<\/em> suffix represents the lower one. In many cases, the stem of the element name comes from the Latin name of the element. <a class=\"xref\" href=\"#gob-ch03_s04_s01_t01\">Table 3.2 \"The Common System of Cation Names\"<\/a> lists the elements that use the common system, along with their respective cation names.<\/p>\r\n\r\n<div id=\"gob-ch03_s04_s01_t01\" class=\"table block\">\r\n<h5 class=\"title\"><strong><span class=\"title-prefix\">Table 3.2<\/span> The Common System of Cation Names<\/strong><\/h5>\r\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Element<\/th>\r\n<th>Stem<\/th>\r\n<th align=\"right\">Charge<\/th>\r\n<th>Name<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td rowspan=\"2\">iron<\/td>\r\n<td rowspan=\"2\">ferr-<\/td>\r\n<td align=\"right\">2+<\/td>\r\n<td>ferrous ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>3+<\/td>\r\n<td>ferric ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td rowspan=\"2\">copper<\/td>\r\n<td rowspan=\"2\">cupr-<\/td>\r\n<td align=\"right\">1+<\/td>\r\n<td>cuprous ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>2+<\/td>\r\n<td>cupric ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td rowspan=\"2\">tin<\/td>\r\n<td rowspan=\"2\">stann-<\/td>\r\n<td align=\"right\">2+<\/td>\r\n<td>stannous ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>4+<\/td>\r\n<td>stannic ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td rowspan=\"2\">lead<\/td>\r\n<td rowspan=\"2\">plumb-<\/td>\r\n<td align=\"right\">2+<\/td>\r\n<td>plumbous ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>4+<\/td>\r\n<td>plumbic ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td rowspan=\"2\">chromium<\/td>\r\n<td rowspan=\"2\">chrom-<\/td>\r\n<td align=\"right\">2+<\/td>\r\n<td>chromous ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>3+<\/td>\r\n<td>chromic ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td rowspan=\"2\">gold<\/td>\r\n<td rowspan=\"2\">aur-<\/td>\r\n<td align=\"right\">1+<\/td>\r\n<td>aurous ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>3+<\/td>\r\n<td>auric ion<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<p id=\"gob-ch03_s04_s01_p05\" class=\"para editable block\">The name of a monatomic anion consists of the stem of the element name, the suffix -<em class=\"emphasis\">ide<\/em>, and then the word <em class=\"emphasis\">ion<\/em>. Thus, as we have already seen, Cl<sup class=\"superscript\">\u2212<\/sup> is \u201cchlor-\u201d + \u201c-ide ion,\u201d or the chloride ion. Similarly, O<sup class=\"superscript\">2\u2212<\/sup> is the oxide ion, Se<sup class=\"superscript\">2\u2212<\/sup> is the selenide ion, and so forth. <a class=\"xref\" href=\"#gob-ch03_s04_s01_t02\">Table 3.3 \"Some Monatomic Anions\"<\/a> lists the names of some common monatomic ions.<\/p>\r\n\r\n<div id=\"gob-ch03_s04_s01_t02\" class=\"table block\">\r\n<h5 class=\"title\"><strong><span class=\"title-prefix\">Table 3.3<\/span> Some Monatomic Anions<\/strong><\/h5>\r\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Ion<\/th>\r\n<th>Name<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>F<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>fluoride ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Cl<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>chloride ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Br<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>bromide ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>I<sup class=\"superscript\">\u2212<\/sup><\/td>\r\n<td>iodide ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>O<sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<td>oxide ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>S<sup class=\"superscript\">2\u2212<\/sup><\/td>\r\n<td>sulfide ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>P<sup class=\"superscript\">3\u2212<\/sup><\/td>\r\n<td>phosphide ion<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>N<sup class=\"superscript\">3\u2212<\/sup><\/td>\r\n<td>nitride ion<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\n<p id=\"gob-ch03_s04_s01_p06\" class=\"para editable block\">The polyatomic ions have their own characteristic names, as we saw in <a class=\"xref\" href=\"gob-ch03_s03#gob-ch03_s03_s01_t01\">Table 3.1 \"Some Polyatomic Ions\"<\/a>.<\/p>\r\n\r\n<div id=\"gob-ch03_s04_s01_n01\" class=\"exercises editable block\">\r\n<h3 class=\"title\">Example 6<\/h3>\r\n<p id=\"gob-ch03_s04_s01_p07\" class=\"para\">Name each ion.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_s01_l01\" class=\"orderedlist\">\r\n \t<li>Ca<sup class=\"superscript\">2+<\/sup><\/li>\r\n \t<li>S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>SO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup><\/li>\r\n \t<li>Cu<sup class=\"superscript\">+<\/sup><\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution<\/p>\r\n[reveal-answer q=\"964807\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"964807\"]\r\n<ol>\r\n \t<li>the calcium ion<\/li>\r\n \t<li>the sulfide ion (from Table 3.3 \"Some Monatomic Anions\")<\/li>\r\n \t<li>the sulfite ion (from Table 3.1 \"Some Polyatomic Ions\")<\/li>\r\n \t<li>the ammonium ion (from Table 3.1 \"Some Polyatomic Ions\")<\/li>\r\n \t<li>the copper(I) ion or the cuprous ion (Figure 3.5 \"Charges of the Monatomic Ions\" shows that copper can form cations with either a 1+ or 2+ charge, so we have to specify which charge this ion has)[\/hidden-answer]<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_qs01\" class=\"qandaset block\">\r\n<div class=\"question\">\r\n<div class=\"textbox exercises\">\r\n<h3>SKill Building Exercise<\/h3>\r\nName each Ion\r\n<div class=\"question\">\r\n<ol>\r\n \t<li>Fe<sup>2+<\/sup><\/li>\r\n \t<li id=\"gob-ch03_s04_qs01_p04\" class=\"para\">Fe<sup class=\"superscript\">3+<\/sup><\/li>\r\n \t<li class=\"para\">SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li class=\"para\">Ba<sup class=\"superscript\" style=\"text-align: initial\">2+<\/sup><\/li>\r\n \t<li class=\"para\">HCO<sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_s01_n03\" class=\"exercises editable block\">\r\n<h3 class=\"title\">Example 7<\/h3>\r\n<p id=\"gob-ch03_s04_s01_p14\" class=\"para\">Write the formula for each ion.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_s01_l04\" class=\"orderedlist\">\r\n \t<li>the bromide ion<\/li>\r\n \t<li>the phosphate ion<\/li>\r\n \t<li>the cupric ion<\/li>\r\n \t<li>the magnesium ion<\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution[reveal-answer q=\"634959\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"634959\"]<\/p>\r\n\r\n<ol>\r\n \t<li>Br\u2212<\/li>\r\n \t<li>PO43\u2212<\/li>\r\n \t<li>Cu2+ Mg2+[\/hidden-answer]<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_qs02\" class=\"qandaset block\">\r\n<div class=\"question\">\r\n<div class=\"textbox exercises\">\r\n<div id=\"gob-ch03_s04_s01\" class=\"section\">\r\n<div id=\"gob-ch03_s04_qs02\" class=\"qandaset block\">\r\n<div class=\"question\">\r\n<h3>SKILL-BUILDING EXERCISE<\/h3>\r\n<p id=\"gob-ch03_s04_qs02_p02\" class=\"para\">Write the formula for each ion.<\/p>\r\n\r\n<ol>\r\n \t<li class=\"para\">the fluoride ion<\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">the carbonate ion<\/span><\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">the stannous ion<\/span><\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">the potassium ion<\/span><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<h3 id=\"gob-ch03_s04_qs02_p02\" class=\"para\"><span style=\"color: #077fab;font-size: 1.15em;font-weight: 600\">Naming Compounds<\/span><\/h3>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_s02\" class=\"section\">\r\n<p id=\"gob-ch03_s04_s02_p01\" class=\"para editable block\">Now that we know how to name ions, we are ready to name ionic compounds. We do so by placing the name of the cation first, followed by the name of the anion, and dropping the word <em class=\"emphasis\">ion<\/em> from both parts.<\/p>\r\n<p id=\"gob-ch03_s04_s02_p02\" class=\"para editable block\">For example, what is the name of the compound whose formula is Ba(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>?<\/p>\r\n\r\n<div id=\"fwk-gob-eq03_008\" class=\"informalfigure large block\"><img class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/19160722\/fdbb7b949259eb63e08a13576430e0a1.jpg\" alt=\"image\" \/><\/div>\r\n<p id=\"gob-ch03_s04_s02_p03\" class=\"para editable block\">The compound\u2019s name does not indicate that there are two nitrate ions for every barium ion. You must determine the relative numbers of ions by balancing the positive and negative charges.<\/p>\r\n<p id=\"gob-ch03_s04_s02_p04\" class=\"para editable block\">If you are given a formula for an ionic compound whose cation can have more than one possible charge, you must first determine the charge on the cation before identifying its correct name. For example, consider FeCl<sub class=\"subscript\">2<\/sub> and FeCl<sub class=\"subscript\">3<\/sub>. In the first compound, the iron ion has a 2+ charge because there are two Cl<sup class=\"superscript\">\u2212<\/sup> ions in the formula (1\u2212 charge on each chloride ion). In the second compound, the iron ion has a 3+ charge, as indicated by the three Cl<sup class=\"superscript\">\u2212<\/sup> ions in the formula. These are two different compounds that need two different names. By the Stock system, the names are iron(II) chloride and iron(III) chloride. If we were to use the stems and suffixes of the common system, the names would be ferrous chloride and ferric chloride, respectively.<\/p>\r\n\r\n<div id=\"gob-ch03_s04_s02_n01\" class=\"exercises editable block\">\r\n<h3 class=\"title\">Example 8<\/h3>\r\n<p id=\"gob-ch03_s04_s02_p05\" class=\"para\">Name each ionic compound, using both Stock and common systems if necessary.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_s02_l01\" class=\"orderedlist\">\r\n \t<li>Ca<sub class=\"subscript\">3<\/sub>(PO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\r\n \t<li>(NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><\/li>\r\n \t<li>KCl<\/li>\r\n \t<li>CuCl<\/li>\r\n \t<li>SnF<sub class=\"subscript\">2<\/sub><\/li>\r\n<\/ol>\r\n<p class=\"simpara\">Solution<\/p>\r\n[reveal-answer q=\"167230\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"167230\"]\r\n<ol>\r\n \t<li>calcium phosphate<\/li>\r\n \t<li>ammonium dichromate (the prefix di- is part of the name of the anion, as in Table 3.1 \"Some Polyatomic Ions\")<\/li>\r\n \t<li>potassium chloride<\/li>\r\n \t<li>copper(I) chloride or cuprous chloride<\/li>\r\n \t<li>tin(II) fluoride or stannous fluoride[\/hidden-answer]<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_qs03\" class=\"qandaset block\">\r\n<div class=\"question\">\r\n<div class=\"textbox exercises\">\r\n<h3>Skill-building Exercise<\/h3>\r\n<div class=\"question\">\r\n\r\nName each ionic compound, using both Stock and common systems if neccessary.\r\n<ol>\r\n \t<li id=\"gob-ch03_s04_qs03_p02\" class=\"para\">ZnBr<sub class=\"subscript\">2<\/sub><\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">Fe(NO<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><span style=\"font-size: 1rem;text-align: initial\">)<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">Al<\/span><sub class=\"subscript\" style=\"text-align: initial\">2<\/sub><span style=\"font-size: 1rem;text-align: initial\">O<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">AuF<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\r\n \t<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">AgF<\/span><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<p id=\"gob-ch03_s04_s02_p12\" class=\"para editable block\"><a class=\"xref\" href=\"#gob-ch03_s04_s02_f01\">Figure 3.7 \"A Guide to Naming Simple Ionic Compounds\"<\/a> is a synopsis of how to name simple ionic compounds.<\/p>\r\n\r\n<div id=\"gob-ch03_s04_s02_f01\" class=\"figure full editable block\">\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"2076\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/19160725\/d24d77cd393891859fe7d1df57665927.jpg\" alt=\"image\" width=\"2076\" height=\"1076\" \/> <em>Figure 3.7 A Guide to Naming Simple Ionic Compounds.\u00a0<\/em>Follow these steps to name a simple ionic compound.[\/caption]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<h3 class=\"title\">Concept Review Exercises<\/h3>\r\n<ol id=\"gob-ch03_s04_qs04_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch03_s04_qs04_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs04_p01\" class=\"para\">Briefly describe the process for naming an ionic compound.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs04_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs04_p03\" class=\"para\">In what order do the names of ions appear in the names of ionic compounds?<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<div class=\"question\">\r\n<p class=\"para\">Which ionic compounds can be named using two different systems? Give an example.<\/p>\r\n&nbsp;\r\n<h3>ANswers<\/h3>\r\n[reveal-answer q=\"432731\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"432731\"]\r\n<ol>\r\n \t<li>Name the cation and then the anion but don\u2019t use numerical prefixes.<\/li>\r\n \t<li>the cation name followed by the anion name<\/li>\r\n \t<li>Ionic compounds in which the cation can have more than one possible charge have two naming systems. FeCl3 is either iron(III) chloride or ferric chloride (answers will vary).\u00a0[\/hidden-answer]\r\n<div class=\"answer\"><\/div><\/li>\r\n<\/ol>\r\n<div id=\"gob-ch03_s04_qs04_ans\" class=\"qandaset block\"><\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch03_s04\" class=\"section\" xml:lang=\"en\">\r\n<div id=\"gob-ch03_s04_s02\" class=\"section\">\r\n<div id=\"gob-ch03_s04_s02_n04\" class=\"key_takeaways editable block\">\r\n<div class=\"textbox key-takeaways\">\r\n<h3>Key Takeaway<\/h3>\r\n<ul id=\"gob-ch03_s04_s02_l05\" class=\"itemizedlist\">\r\n \t<li>Each ionic compound has its own unique name that comes from the names of the ions.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch03_s04_qs05\" class=\"qandaset block\">\r\n<div class=\"question\">\r\n<div class=\"textbox exercises\">\r\n<h3>Exercises<\/h3>\r\n<div id=\"gob-ch03_s04_qs05\" class=\"qandaset block\">\r\n<ol id=\"gob-ch03_s04_qs05_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p01\" class=\"para\">Name each ion.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l01\" class=\"orderedlist\">\r\n \t<li>Ra<sup class=\"superscript\">2+<\/sup><\/li>\r\n \t<li>P<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>H<sub class=\"subscript\">2<\/sub>PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Sn<sup class=\"superscript\">4+<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p02\" class=\"para\">Name each ion.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l03\" class=\"orderedlist\">\r\n \t<li>Cs<sup class=\"superscript\">+<\/sup><\/li>\r\n \t<li>As<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>HSO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Sn<sup class=\"superscript\">2+<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p03\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l05\" class=\"orderedlist\">\r\n \t<li>Na<sup class=\"superscript\">+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p04\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l07\" class=\"orderedlist\">\r\n \t<li>K<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup> and Se<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p05\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l09\" class=\"orderedlist\">\r\n \t<li>Na<sup class=\"superscript\">+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Al<sup class=\"superscript\">3+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa06\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p06\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l11\" class=\"orderedlist\">\r\n \t<li>Li<sup class=\"superscript\">+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup> and P<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Li<sup class=\"superscript\">+<\/sup> and P<sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa07\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p07\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l13\" class=\"orderedlist\">\r\n \t<li>Fe<sup class=\"superscript\">3+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Fe<sup class=\"superscript\">2+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Au<sup class=\"superscript\">3+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Au<sup class=\"superscript\">+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa08\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p08\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l15\" class=\"orderedlist\">\r\n \t<li>Cr<sup class=\"superscript\">3+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Cr<sup class=\"superscript\">2+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Pb<sup class=\"superscript\">2+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Pb<sup class=\"superscript\">4+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa09\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p09\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l17\" class=\"orderedlist\">\r\n \t<li>Cr<sup class=\"superscript\">3+<\/sup> and NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>Fe<sup class=\"superscript\">2+<\/sup> and PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/li>\r\n \t<li>Ca<sup class=\"superscript\">2+<\/sup> and CrO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Al<sup class=\"superscript\">3+<\/sup> and OH<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa10\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p10\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l19\" class=\"orderedlist\">\r\n \t<li>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>H<sup class=\"superscript\">+<\/sup> and Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Cu<sup class=\"superscript\">+<\/sup> and CO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n \t<li>Na<sup class=\"superscript\">+<\/sup> and HCO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s04_qs05_qd01_qa11\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p11\" class=\"para\">Give two names for each compound.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l21\" class=\"orderedlist\">\r\n \t<li>Al(HSO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\r\n \t<li>Mg(HSO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n<\/ol>\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s04_qs05_p12\" class=\"para\">Give two names for each compound.<\/p>\r\n\r\n<ol id=\"gob-ch03_s04_qs05_l23\" class=\"orderedlist\">\r\n \t<li>Co(HCO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\r\n \t<li>LiHCO<sub class=\"subscript\">3<\/sub><\/li>\r\n<\/ol>\r\n<h3>answers<\/h3>\r\n<\/div>\r\n[reveal-answer q=\"645823\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"645823\"]\r\n\r\n1. a. the radium ion\r\n\r\nb.the phosphide ion\r\n\r\nc. the dihydrogen phosphate ion\r\n\r\nd. the tin(IV) ion or the stannic ion\r\n\r\n&nbsp;\r\n\r\n3. a. sodium bromide\r\n\r\nb. magnesium bromide\r\n\r\nc. magnesium sulfide\r\n\r\n&nbsp;\r\n\r\n5. a. sodium nitride\r\n\r\nb. magnesium nitride\r\n\r\nc. aluminum sulfide\r\n\r\n&nbsp;\r\n\r\n7. a. iron(III) bromide or ferric bromide\r\n\r\nb.iron(II) bromide or ferrous bromide\r\n\r\nc. gold(III) sulfide or auric sulfide\r\n\r\nd. gold(I) sulfide or aurous sulfide\r\n\r\n&nbsp;\r\n\r\n9. a. chromium(III) nitrate or chromic nitrate\r\n\r\nb. iron(II) phosphate or ferrous phosphate\r\n\r\nc. calcium chromate\r\n\r\nd. aluminum hydroxide\r\n\r\n&nbsp;\r\n\r\n11. a. aluminum hydrogen sulfate or aluminum bisulfate\r\n\r\nb. magnesium hydrogen sulfate or magnesium bisulfate[\/hidden-answer]<span style=\"background-color: #ccd7dd;color: #000000;font-size: 1.2em;font-weight: 600;text-align: center\">\u00a0<\/span>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"book-content\">\n<div id=\"gob-ch03_s04\" class=\"section\" xml:lang=\"en\">\n<div id=\"gob-ch03_s04_n01\" class=\"learning_objectives editable block\">\n<div class=\"textbox learning-objectives\" style=\"text-align: left\">\n<h3>Learning Objectives<\/h3>\n<p>1. Use the rules for naming ionic compounds.<\/p>\n<\/div>\n<p><span style=\"font-size: 1rem;text-align: initial\">After learning a few more details about the names of individual ions, you will be a step away from knowing how to name ionic compounds. This section begins the formal study of <\/span><span class=\"margin_term\" style=\"font-size: 1rem;text-align: initial\"><strong><span class=\"glossterm\">nomenclature<\/span><\/strong><\/span><span style=\"font-size: 1rem;text-align: initial\">, the systematic naming of chemical compounds.<\/span><\/p>\n<\/div>\n<div id=\"gob-ch03_s04_s01\" class=\"section\">\n<h2 class=\"title editable block\">Naming Ions<\/h2>\n<p id=\"gob-ch03_s04_s01_p01\" class=\"para editable block\">The name of a monatomic cation is simply the name of the element followed by the word <em class=\"emphasis\">ion<\/em>. Thus, Na<sup class=\"superscript\">+<\/sup> is the sodium ion, Al<sup class=\"superscript\">3+<\/sup> is the aluminum ion, Ca<sup class=\"superscript\">2+<\/sup> is the calcium ion, and so forth.<\/p>\n<p id=\"gob-ch03_s04_s01_p02\" class=\"para editable block\">We have seen that some elements lose different numbers of electrons, producing ions of different charges (<a class=\"xref\" href=\"gob-ch03_s02#gob-ch03_s02_s01_f03\">Figure 3.3 &#8220;Predicting Ionic Charges&#8221;<\/a>). Iron, for example, can form two cations, each of which, when combined with the same anion, makes a different compound with unique physical and chemical properties. Thus, we need a different name for each iron ion to distinguish Fe<sup class=\"superscript\">2+<\/sup> from Fe<sup class=\"superscript\">3+<\/sup>. The same issue arises for other ions with more than one possible charge.<\/p>\n<p id=\"gob-ch03_s04_s01_p03\" class=\"para editable block\">There are two ways to make this distinction. In the simpler, more modern approach, called the <span class=\"margin_term\"><strong><span class=\"glossterm\">Stock system<\/span><\/strong><\/span>, an ion\u2019s positive charge is indicated by a roman numeral in parentheses after the element name, followed by the word <em class=\"emphasis\">ion<\/em>. Thus, Fe<sup class=\"superscript\">2+<\/sup> is called the iron(II) ion, while Fe<sup class=\"superscript\">3+<\/sup> is called the iron(III) ion. This system is used only for elements that form more than one common positive ion. We do not call the Na<sup class=\"superscript\">+<\/sup> ion the sodium(I) ion because (I) is unnecessary. Sodium forms only a 1+ ion, so there is no ambiguity about the name <em class=\"emphasis\">sodium ion<\/em>.<\/p>\n<p id=\"gob-ch03_s04_s01_p04\" class=\"para editable block\">The second system, called the <strong class=\"emphasis bold\">common system<\/strong>, is not conventional but is still prevalent and used in the health sciences. This system recognizes that many metals have two common cations. The common system uses two suffixes (-<em class=\"emphasis\">ic<\/em> and &#8211;<em class=\"emphasis\">ous<\/em>) that are appended to the stem of the element name. The <em class=\"emphasis\">-ic<\/em> suffix represents the greater of the two cation charges, and the <em class=\"emphasis\">-ous<\/em> suffix represents the lower one. In many cases, the stem of the element name comes from the Latin name of the element. <a class=\"xref\" href=\"#gob-ch03_s04_s01_t01\">Table 3.2 &#8220;The Common System of Cation Names&#8221;<\/a> lists the elements that use the common system, along with their respective cation names.<\/p>\n<div id=\"gob-ch03_s04_s01_t01\" class=\"table block\">\n<h5 class=\"title\"><strong><span class=\"title-prefix\">Table 3.2<\/span> The Common System of Cation Names<\/strong><\/h5>\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\n<thead>\n<tr>\n<th>Element<\/th>\n<th>Stem<\/th>\n<th align=\"right\">Charge<\/th>\n<th>Name<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td rowspan=\"2\">iron<\/td>\n<td rowspan=\"2\">ferr-<\/td>\n<td align=\"right\">2+<\/td>\n<td>ferrous ion<\/td>\n<\/tr>\n<tr>\n<td>3+<\/td>\n<td>ferric ion<\/td>\n<\/tr>\n<tr>\n<td rowspan=\"2\">copper<\/td>\n<td rowspan=\"2\">cupr-<\/td>\n<td align=\"right\">1+<\/td>\n<td>cuprous ion<\/td>\n<\/tr>\n<tr>\n<td>2+<\/td>\n<td>cupric ion<\/td>\n<\/tr>\n<tr>\n<td rowspan=\"2\">tin<\/td>\n<td rowspan=\"2\">stann-<\/td>\n<td align=\"right\">2+<\/td>\n<td>stannous ion<\/td>\n<\/tr>\n<tr>\n<td>4+<\/td>\n<td>stannic ion<\/td>\n<\/tr>\n<tr>\n<td rowspan=\"2\">lead<\/td>\n<td rowspan=\"2\">plumb-<\/td>\n<td align=\"right\">2+<\/td>\n<td>plumbous ion<\/td>\n<\/tr>\n<tr>\n<td>4+<\/td>\n<td>plumbic ion<\/td>\n<\/tr>\n<tr>\n<td rowspan=\"2\">chromium<\/td>\n<td rowspan=\"2\">chrom-<\/td>\n<td align=\"right\">2+<\/td>\n<td>chromous ion<\/td>\n<\/tr>\n<tr>\n<td>3+<\/td>\n<td>chromic ion<\/td>\n<\/tr>\n<tr>\n<td rowspan=\"2\">gold<\/td>\n<td rowspan=\"2\">aur-<\/td>\n<td align=\"right\">1+<\/td>\n<td>aurous ion<\/td>\n<\/tr>\n<tr>\n<td>3+<\/td>\n<td>auric ion<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p id=\"gob-ch03_s04_s01_p05\" class=\"para editable block\">The name of a monatomic anion consists of the stem of the element name, the suffix &#8211;<em class=\"emphasis\">ide<\/em>, and then the word <em class=\"emphasis\">ion<\/em>. Thus, as we have already seen, Cl<sup class=\"superscript\">\u2212<\/sup> is \u201cchlor-\u201d + \u201c-ide ion,\u201d or the chloride ion. Similarly, O<sup class=\"superscript\">2\u2212<\/sup> is the oxide ion, Se<sup class=\"superscript\">2\u2212<\/sup> is the selenide ion, and so forth. <a class=\"xref\" href=\"#gob-ch03_s04_s01_t02\">Table 3.3 &#8220;Some Monatomic Anions&#8221;<\/a> lists the names of some common monatomic ions.<\/p>\n<div id=\"gob-ch03_s04_s01_t02\" class=\"table block\">\n<h5 class=\"title\"><strong><span class=\"title-prefix\">Table 3.3<\/span> Some Monatomic Anions<\/strong><\/h5>\n<table style=\"border-spacing: 0px\" cellpadding=\"0\">\n<thead>\n<tr>\n<th>Ion<\/th>\n<th>Name<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>F<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>fluoride ion<\/td>\n<\/tr>\n<tr>\n<td>Cl<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>chloride ion<\/td>\n<\/tr>\n<tr>\n<td>Br<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>bromide ion<\/td>\n<\/tr>\n<tr>\n<td>I<sup class=\"superscript\">\u2212<\/sup><\/td>\n<td>iodide ion<\/td>\n<\/tr>\n<tr>\n<td>O<sup class=\"superscript\">2\u2212<\/sup><\/td>\n<td>oxide ion<\/td>\n<\/tr>\n<tr>\n<td>S<sup class=\"superscript\">2\u2212<\/sup><\/td>\n<td>sulfide ion<\/td>\n<\/tr>\n<tr>\n<td>P<sup class=\"superscript\">3\u2212<\/sup><\/td>\n<td>phosphide ion<\/td>\n<\/tr>\n<tr>\n<td>N<sup class=\"superscript\">3\u2212<\/sup><\/td>\n<td>nitride ion<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p id=\"gob-ch03_s04_s01_p06\" class=\"para editable block\">The polyatomic ions have their own characteristic names, as we saw in <a class=\"xref\" href=\"gob-ch03_s03#gob-ch03_s03_s01_t01\">Table 3.1 &#8220;Some Polyatomic Ions&#8221;<\/a>.<\/p>\n<div id=\"gob-ch03_s04_s01_n01\" class=\"exercises editable block\">\n<h3 class=\"title\">Example 6<\/h3>\n<p id=\"gob-ch03_s04_s01_p07\" class=\"para\">Name each ion.<\/p>\n<ol id=\"gob-ch03_s04_s01_l01\" class=\"orderedlist\">\n<li>Ca<sup class=\"superscript\">2+<\/sup><\/li>\n<li>S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>SO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup><\/li>\n<li>Cu<sup class=\"superscript\">+<\/sup><\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q964807\">Show Answer<\/span><\/p>\n<div id=\"q964807\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>the calcium ion<\/li>\n<li>the sulfide ion (from Table 3.3 &#8220;Some Monatomic Anions&#8221;)<\/li>\n<li>the sulfite ion (from Table 3.1 &#8220;Some Polyatomic Ions&#8221;)<\/li>\n<li>the ammonium ion (from Table 3.1 &#8220;Some Polyatomic Ions&#8221;)<\/li>\n<li>the copper(I) ion or the cuprous ion (Figure 3.5 &#8220;Charges of the Monatomic Ions&#8221; shows that copper can form cations with either a 1+ or 2+ charge, so we have to specify which charge this ion has)<\/div>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch03_s04_qs01\" class=\"qandaset block\">\n<div class=\"question\">\n<div class=\"textbox exercises\">\n<h3>SKill Building Exercise<\/h3>\n<p>Name each Ion<\/p>\n<div class=\"question\">\n<ol>\n<li>Fe<sup>2+<\/sup><\/li>\n<li id=\"gob-ch03_s04_qs01_p04\" class=\"para\">Fe<sup class=\"superscript\">3+<\/sup><\/li>\n<li class=\"para\">SO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li class=\"para\">Ba<sup class=\"superscript\" style=\"text-align: initial\">2+<\/sup><\/li>\n<li class=\"para\">HCO<sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch03_s04_s01_n03\" class=\"exercises editable block\">\n<h3 class=\"title\">Example 7<\/h3>\n<p id=\"gob-ch03_s04_s01_p14\" class=\"para\">Write the formula for each ion.<\/p>\n<ol id=\"gob-ch03_s04_s01_l04\" class=\"orderedlist\">\n<li>the bromide ion<\/li>\n<li>the phosphate ion<\/li>\n<li>the cupric ion<\/li>\n<li>the magnesium ion<\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q634959\">Show Answer<\/span><\/p>\n<div id=\"q634959\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>Br\u2212<\/li>\n<li>PO43\u2212<\/li>\n<li>Cu2+ Mg2+<\/div>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch03_s04_qs02\" class=\"qandaset block\">\n<div class=\"question\">\n<div class=\"textbox exercises\">\n<div id=\"gob-ch03_s04_s01\" class=\"section\">\n<div id=\"gob-ch03_s04_qs02\" class=\"qandaset block\">\n<div class=\"question\">\n<h3>SKILL-BUILDING EXERCISE<\/h3>\n<p id=\"gob-ch03_s04_qs02_p02\" class=\"para\">Write the formula for each ion.<\/p>\n<ol>\n<li class=\"para\">the fluoride ion<\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">the carbonate ion<\/span><\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">the stannous ion<\/span><\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">the potassium ion<\/span><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<h3 id=\"gob-ch03_s04_qs02_p02\" class=\"para\"><span style=\"color: #077fab;font-size: 1.15em;font-weight: 600\">Naming Compounds<\/span><\/h3>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch03_s04_s02\" class=\"section\">\n<p id=\"gob-ch03_s04_s02_p01\" class=\"para editable block\">Now that we know how to name ions, we are ready to name ionic compounds. We do so by placing the name of the cation first, followed by the name of the anion, and dropping the word <em class=\"emphasis\">ion<\/em> from both parts.<\/p>\n<p id=\"gob-ch03_s04_s02_p02\" class=\"para editable block\">For example, what is the name of the compound whose formula is Ba(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>?<\/p>\n<div id=\"fwk-gob-eq03_008\" class=\"informalfigure large block\"><img decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/19160722\/fdbb7b949259eb63e08a13576430e0a1.jpg\" alt=\"image\" \/><\/div>\n<p id=\"gob-ch03_s04_s02_p03\" class=\"para editable block\">The compound\u2019s name does not indicate that there are two nitrate ions for every barium ion. You must determine the relative numbers of ions by balancing the positive and negative charges.<\/p>\n<p id=\"gob-ch03_s04_s02_p04\" class=\"para editable block\">If you are given a formula for an ionic compound whose cation can have more than one possible charge, you must first determine the charge on the cation before identifying its correct name. For example, consider FeCl<sub class=\"subscript\">2<\/sub> and FeCl<sub class=\"subscript\">3<\/sub>. In the first compound, the iron ion has a 2+ charge because there are two Cl<sup class=\"superscript\">\u2212<\/sup> ions in the formula (1\u2212 charge on each chloride ion). In the second compound, the iron ion has a 3+ charge, as indicated by the three Cl<sup class=\"superscript\">\u2212<\/sup> ions in the formula. These are two different compounds that need two different names. By the Stock system, the names are iron(II) chloride and iron(III) chloride. If we were to use the stems and suffixes of the common system, the names would be ferrous chloride and ferric chloride, respectively.<\/p>\n<div id=\"gob-ch03_s04_s02_n01\" class=\"exercises editable block\">\n<h3 class=\"title\">Example 8<\/h3>\n<p id=\"gob-ch03_s04_s02_p05\" class=\"para\">Name each ionic compound, using both Stock and common systems if necessary.<\/p>\n<ol id=\"gob-ch03_s04_s02_l01\" class=\"orderedlist\">\n<li>Ca<sub class=\"subscript\">3<\/sub>(PO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\n<li>(NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><\/li>\n<li>KCl<\/li>\n<li>CuCl<\/li>\n<li>SnF<sub class=\"subscript\">2<\/sub><\/li>\n<\/ol>\n<p class=\"simpara\">Solution<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q167230\">Show Answer<\/span><\/p>\n<div id=\"q167230\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>calcium phosphate<\/li>\n<li>ammonium dichromate (the prefix di- is part of the name of the anion, as in Table 3.1 &#8220;Some Polyatomic Ions&#8221;)<\/li>\n<li>potassium chloride<\/li>\n<li>copper(I) chloride or cuprous chloride<\/li>\n<li>tin(II) fluoride or stannous fluoride<\/div>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch03_s04_qs03\" class=\"qandaset block\">\n<div class=\"question\">\n<div class=\"textbox exercises\">\n<h3>Skill-building Exercise<\/h3>\n<div class=\"question\">\n<p>Name each ionic compound, using both Stock and common systems if neccessary.<\/p>\n<ol>\n<li id=\"gob-ch03_s04_qs03_p02\" class=\"para\">ZnBr<sub class=\"subscript\">2<\/sub><\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">Fe(NO<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><span style=\"font-size: 1rem;text-align: initial\">)<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">Al<\/span><sub class=\"subscript\" style=\"text-align: initial\">2<\/sub><span style=\"font-size: 1rem;text-align: initial\">O<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">AuF<\/span><sub class=\"subscript\" style=\"text-align: initial\">3<\/sub><\/li>\n<li class=\"para\"><span style=\"font-size: 1rem;text-align: initial\">AgF<\/span><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<p id=\"gob-ch03_s04_s02_p12\" class=\"para editable block\"><a class=\"xref\" href=\"#gob-ch03_s04_s02_f01\">Figure 3.7 &#8220;A Guide to Naming Simple Ionic Compounds&#8221;<\/a> is a synopsis of how to name simple ionic compounds.<\/p>\n<div id=\"gob-ch03_s04_s02_f01\" class=\"figure full editable block\">\n<div style=\"width: 2086px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/19160725\/d24d77cd393891859fe7d1df57665927.jpg\" alt=\"image\" width=\"2076\" height=\"1076\" \/><\/p>\n<p class=\"wp-caption-text\"><em>Figure 3.7 A Guide to Naming Simple Ionic Compounds.\u00a0<\/em>Follow these steps to name a simple ionic compound.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<h3 class=\"title\">Concept Review Exercises<\/h3>\n<ol id=\"gob-ch03_s04_qs04_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch03_s04_qs04_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs04_p01\" class=\"para\">Briefly describe the process for naming an ionic compound.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs04_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs04_p03\" class=\"para\">In what order do the names of ions appear in the names of ionic compounds?<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<div class=\"question\">\n<p class=\"para\">Which ionic compounds can be named using two different systems? Give an example.<\/p>\n<p>&nbsp;<\/p>\n<h3>ANswers<\/h3>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q432731\">Show Answer<\/span><\/p>\n<div id=\"q432731\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>Name the cation and then the anion but don\u2019t use numerical prefixes.<\/li>\n<li>the cation name followed by the anion name<\/li>\n<li>Ionic compounds in which the cation can have more than one possible charge have two naming systems. FeCl3 is either iron(III) chloride or ferric chloride (answers will vary).\u00a0<\/div>\n<\/div>\n<div class=\"answer\"><\/div>\n<\/li>\n<\/ol>\n<div id=\"gob-ch03_s04_qs04_ans\" class=\"qandaset block\"><\/div>\n<\/div>\n<\/div>\n<div id=\"book-content\">\n<div id=\"gob-ch03_s04\" class=\"section\" xml:lang=\"en\">\n<div id=\"gob-ch03_s04_s02\" class=\"section\">\n<div id=\"gob-ch03_s04_s02_n04\" class=\"key_takeaways editable block\">\n<div class=\"textbox key-takeaways\">\n<h3>Key Takeaway<\/h3>\n<ul id=\"gob-ch03_s04_s02_l05\" class=\"itemizedlist\">\n<li>Each ionic compound has its own unique name that comes from the names of the ions.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div id=\"gob-ch03_s04_qs05\" class=\"qandaset block\">\n<div class=\"question\">\n<div class=\"textbox exercises\">\n<h3>Exercises<\/h3>\n<div id=\"gob-ch03_s04_qs05\" class=\"qandaset block\">\n<ol id=\"gob-ch03_s04_qs05_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch03_s04_qs05_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p01\" class=\"para\">Name each ion.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l01\" class=\"orderedlist\">\n<li>Ra<sup class=\"superscript\">2+<\/sup><\/li>\n<li>P<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>H<sub class=\"subscript\">2<\/sub>PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Sn<sup class=\"superscript\">4+<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p02\" class=\"para\">Name each ion.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l03\" class=\"orderedlist\">\n<li>Cs<sup class=\"superscript\">+<\/sup><\/li>\n<li>As<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>HSO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Sn<sup class=\"superscript\">2+<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p03\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l05\" class=\"orderedlist\">\n<li>Na<sup class=\"superscript\">+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p04\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l07\" class=\"orderedlist\">\n<li>K<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup> and Se<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p05\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l09\" class=\"orderedlist\">\n<li>Na<sup class=\"superscript\">+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Al<sup class=\"superscript\">3+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p06\" class=\"para\">Name the ionic compound formed by each pair of ions.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l11\" class=\"orderedlist\">\n<li>Li<sup class=\"superscript\">+<\/sup> and N<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup> and P<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Li<sup class=\"superscript\">+<\/sup> and P<sup class=\"superscript\">3\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p07\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l13\" class=\"orderedlist\">\n<li>Fe<sup class=\"superscript\">3+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Fe<sup class=\"superscript\">2+<\/sup> and Br<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Au<sup class=\"superscript\">3+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Au<sup class=\"superscript\">+<\/sup> and S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p08\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l15\" class=\"orderedlist\">\n<li>Cr<sup class=\"superscript\">3+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Cr<sup class=\"superscript\">2+<\/sup> and O<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Pb<sup class=\"superscript\">2+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Pb<sup class=\"superscript\">4+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p09\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l17\" class=\"orderedlist\">\n<li>Cr<sup class=\"superscript\">3+<\/sup> and NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>Fe<sup class=\"superscript\">2+<\/sup> and PO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">3\u2212<\/sup><\/li>\n<li>Ca<sup class=\"superscript\">2+<\/sup> and CrO<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Al<sup class=\"superscript\">3+<\/sup> and OH<sup class=\"superscript\">\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa10\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p10\" class=\"para\">Name the ionic compound formed by each pair of ions. Use both the Stock and common systems, where appropriate.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l19\" class=\"orderedlist\">\n<li>NH<sub class=\"subscript\">4<\/sub><sup class=\"superscript\">+<\/sup> and NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>H<sup class=\"superscript\">+<\/sup> and Cr<sub class=\"subscript\">2<\/sub>O<sub class=\"subscript\">7<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Cu<sup class=\"superscript\">+<\/sup> and CO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">2\u2212<\/sup><\/li>\n<li>Na<sup class=\"superscript\">+<\/sup> and HCO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s04_qs05_qd01_qa11\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p11\" class=\"para\">Give two names for each compound.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l21\" class=\"orderedlist\">\n<li>Al(HSO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub><\/li>\n<li>Mg(HSO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<div class=\"question\">\n<p id=\"gob-ch03_s04_qs05_p12\" class=\"para\">Give two names for each compound.<\/p>\n<ol id=\"gob-ch03_s04_qs05_l23\" class=\"orderedlist\">\n<li>Co(HCO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\n<li>LiHCO<sub class=\"subscript\">3<\/sub><\/li>\n<\/ol>\n<h3>answers<\/h3>\n<\/div>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q645823\">Show Answer<\/span><\/p>\n<div id=\"q645823\" class=\"hidden-answer\" style=\"display: none\">\n<p>1. a. the radium ion<\/p>\n<p>b.the phosphide ion<\/p>\n<p>c. the dihydrogen phosphate ion<\/p>\n<p>d. the tin(IV) ion or the stannic ion<\/p>\n<p>&nbsp;<\/p>\n<p>3. a. sodium bromide<\/p>\n<p>b. magnesium bromide<\/p>\n<p>c. magnesium sulfide<\/p>\n<p>&nbsp;<\/p>\n<p>5. a. sodium nitride<\/p>\n<p>b. magnesium nitride<\/p>\n<p>c. aluminum sulfide<\/p>\n<p>&nbsp;<\/p>\n<p>7. a. iron(III) bromide or ferric bromide<\/p>\n<p>b.iron(II) bromide or ferrous bromide<\/p>\n<p>c. gold(III) sulfide or auric sulfide<\/p>\n<p>d. gold(I) sulfide or aurous sulfide<\/p>\n<p>&nbsp;<\/p>\n<p>9. a. chromium(III) nitrate or chromic nitrate<\/p>\n<p>b. iron(II) phosphate or ferrous phosphate<\/p>\n<p>c. calcium chromate<\/p>\n<p>d. aluminum hydroxide<\/p>\n<p>&nbsp;<\/p>\n<p>11. a. aluminum hydrogen sulfate or aluminum bisulfate<\/p>\n<p>b. magnesium hydrogen sulfate or magnesium bisulfate<\/p><\/div>\n<\/div>\n<p><span style=\"background-color: #ccd7dd;color: #000000;font-size: 1.2em;font-weight: 600;text-align: center\">\u00a0<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-237\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>The Basics of General, Organic, and Biological Chemistry v. 1.0. <strong>Provided by<\/strong>: Saylor Academy. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\">https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc\/4.0\/\">CC BY-NC: Attribution-NonCommercial<\/a><\/em>. <strong>License Terms<\/strong>: This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work&#039;s original creator or licensor.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":53384,"menu_order":5,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"The Basics of General, Organic, and Biological Chemistry v. 1.0\",\"author\":\"\",\"organization\":\"Saylor Academy\",\"url\":\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc\",\"license_terms\":\"This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work\\'s original creator or licensor.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-237","chapter","type-chapter","status-publish","hentry"],"part":191,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/237","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/users\/53384"}],"version-history":[{"count":8,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/237\/revisions"}],"predecessor-version":[{"id":2762,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/237\/revisions\/2762"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/parts\/191"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/237\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/media?parent=237"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=237"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/contributor?post=237"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/license?post=237"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}