{"id":248,"date":"2018-03-19T16:08:52","date_gmt":"2018-03-19T16:08:52","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/chapter\/end-of-chapter-material-3\/"},"modified":"2018-05-08T15:32:59","modified_gmt":"2018-05-08T15:32:59","slug":"end-of-chapter-material-3","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/chapter\/end-of-chapter-material-3\/","title":{"raw":"3.6 End-of-Chapter Material","rendered":"3.6 End-of-Chapter Material"},"content":{"raw":"<div id=\"navbar-top\" class=\"navbar\">\r\n<div class=\"textbox shaded\">\r\n<div id=\"navbar-top\" class=\"navbar\">\r\n<h3 class=\"navbar-part left\"><span style=\"color: #6c64ad;font-size: 1.2em;font-weight: 600;background-color: #eeeeee\"><span style=\"color: #6c64ad;font-size: 1.2em;font-weight: 600;background-color: #eeeeee\">Chapter Summary<\/span><\/span><\/h3>\r\n<p id=\"gob-ch03_s06_p01\" class=\"para\"><em class=\"emphasis\">T<span style=\"color: #000000\">o ensure that you understand the material in this chapter, you should review the meanings of the following bold terms and ask yourself how they relate to the topics in the chapter.<\/span><\/em><\/p>\r\n<p id=\"gob-ch03_s06_p02\" class=\"para\"><span style=\"color: #000000\">Atoms combine into compounds by forming <strong class=\"emphasis bold\">chemical bonds<\/strong>. A survey of stable atoms and molecules leads to the <strong class=\"emphasis bold\">octet rule<\/strong>, which says that stable atoms tend to have eight electrons in their outermost, or valence, shell. One way atoms obtain eight electrons in the valence shell is for some atoms to lose electrons while other atoms gain them. When this happens, the atoms take on an electrical charge. Charged atoms are called <strong class=\"emphasis bold\">ions<\/strong>. Ions having opposite charges attract each other. This attraction is called <strong class=\"emphasis bold\">ionic bonding<\/strong>, and the compounds formed are called <strong class=\"emphasis bold\">ionic compounds<\/strong>.<\/span><\/p>\r\n<p id=\"gob-ch03_s06_p03\" class=\"para\"><span style=\"color: #000000\">Positively charged ions are called <strong class=\"emphasis bold\">cations<\/strong>, while negatively charged ions are called <strong class=\"emphasis bold\">anions<\/strong>. The formation of both cations and anions can be illustrated using electron configurations. Because elements in a column of the periodic table have the same valence shell electron configuration, atoms in the same column of the periodic table tend to form ions having the same charge. <strong class=\"emphasis bold\">Electron dot diagrams<\/strong>, or <strong class=\"emphasis bold\">Lewis diagrams<\/strong>, can also be used to illustrate the formation of cations and anions.<\/span><\/p>\r\n<p id=\"gob-ch03_s06_p04\" class=\"para\"><span style=\"color: #000000\">Ionic compounds are represented in writing by a <strong class=\"emphasis bold\">chemical formula<\/strong>, which gives the lowest ratio of cations and anions present in the compound. In a formula, the symbol of the cation is written first, followed by the symbol of the anion. <strong class=\"emphasis bold\">Formula unit<\/strong> is considered the basic unit of an ionic compound because ionic compounds do not exist as discrete units. Instead, they exist as <strong class=\"emphasis bold\">crystals<\/strong>, three-dimensional arrays of ions, with cations surrounded by anions and anions surrounded by cations. Chemical formulas for ionic compounds are determined by balancing the positive charge from the cation(s) with the negative charge from the anion(s). A subscript to the right of the ion indicates that more than one of that ion is present in the chemical formula.<\/span><\/p>\r\n<p id=\"gob-ch03_s06_p05\" class=\"para\"><span style=\"color: #000000\">Some ions are groups of atoms bonded together and having an overall electrical charge. These are called <strong class=\"emphasis bold\">polyatomic ions<\/strong>. Writing formulas with polyatomic ions follows the same rules as with monatomic ions, except that when more than one polyatomic ion is present in a chemical formula, the polyatomic ion is enclosed in parentheses and the subscript is outside the right parenthesis. Ionic compounds typically form between metals and nonmetals or between polyatomic ions.<\/span><\/p>\r\n<p id=\"gob-ch03_s06_p06\" class=\"para\"><span style=\"color: #000000\">Names of ionic compounds are derived from the names of the ions, with the name of the cation coming first, followed by the name of the anion. If an element can form cations of different charges, there are two alternate systems for indicating the compound\u2019s name. In the <strong class=\"emphasis bold\">Stock system<\/strong>, a roman numeral in parentheses indicates the charge on the cation. An example is the name for FeCl<sub class=\"subscript\">2<\/sub>, which is iron(II) chloride. In the common system, the suffixes -<em class=\"emphasis\">ous<\/em> and -<em class=\"emphasis\">ic<\/em> are used to stand for the lower and higher possible charge of the cation, respectively. These suffixes are attached to a stem representing the element (which frequently comes from the Latin form of the element name). An example is the common name for FeCl<sub class=\"subscript\">2<\/sub>, which is ferrous chloride.<\/span><\/p>\r\n<p id=\"gob-ch03_s06_p07\" class=\"para\"><span style=\"color: #000000\">The <strong class=\"emphasis bold\">formula mass<\/strong> of an ionic compound is the sum of the masses of each individual atom in the formula. Care must be taken when calculating formula masses for formulas containing multiple polyatomic ions because the subscript outside the parentheses refers to all the atoms in the polyatomic ion.<\/span><span style=\"color: #6c64ad;font-size: 1.2em;font-weight: 600\">\u00a0<\/span><\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch03_s06\" class=\"section end-of-chapter\" xml:lang=\"en\">\r\n<div id=\"gob-ch03_s06_qs01\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<h3>Additional Exercises<\/h3>\r\n<div id=\"gob-ch03_s06_qs01\" class=\"qandaset block\">\r\n<ol id=\"gob-ch03_s06_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p01\" class=\"para\">What number shell is the valence electron shell of a sodium atom? What number shell is the valence shell of a sodium ion? Explain the difference.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p03\" class=\"para\">What number shell is the valence electron shell of a bromine atom? What number shell is the valence shell of a bromide ion? Explain the difference between these answers and the answers to Exercise 1.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p05\" class=\"para\">What is the electron configuration of each ion?<\/p>\r\n\r\n<ol id=\"gob-ch03_s06_qs01_l01\" class=\"orderedlist\">\r\n \t<li>K<sup class=\"superscript\">+<\/sup><\/li>\r\n \t<li>Mg<sup class=\"superscript\">2+<\/sup><\/li>\r\n \t<li>F<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>S<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p06\" class=\"para\">What is the electron configuration of each ion?<\/p>\r\n\r\n<ol id=\"gob-ch03_s06_qs01_l03\" class=\"orderedlist\">\r\n \t<li>Li<sup class=\"superscript\">+<\/sup><\/li>\r\n \t<li>Ca<sup class=\"superscript\">2+<\/sup><\/li>\r\n \t<li>Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\r\n \t<li>O<sup class=\"superscript\">2\u2212<\/sup><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<ol id=\"gob-ch03_s06_qs01_l05\" class=\"orderedlist\">\r\n \t<li>If a sodium atom were to lose two electrons, what would be the electron configuration of the resulting cation?<\/li>\r\n \t<li>Considering that electron shells are typically separated by large amounts of energy, use your answer to Exercise 5a to suggest why sodium atoms do not form a 2+ cation.<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa06\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<ol id=\"gob-ch03_s06_qs01_l07\" class=\"orderedlist\">\r\n \t<li>If a chlorine atom were to gain two electrons, what would be the electron configuration of the resulting anion?<\/li>\r\n \t<li>Considering that electron shells are typically separated by large amounts of energy, use your answer to Exercise 6a to suggest why chlorine atoms do not form a 2\u2212 anion.<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa07\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p09\" class=\"para\">Use Lewis diagrams and arrows to show the electron transfer that occurs during the formation of an ionic compound among Mg atoms and F atoms. (Hint: how many atoms of each will you need?)<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa08\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p10\" class=\"para\">Use Lewis diagrams and arrows to show the electron transfer that occurs during the formation of an ionic compound among K atoms and O atoms. (Hint: how many atoms of each will you need?)<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa09\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p11\" class=\"para\">Mercury forms two possible cations\u2014Hg<sup class=\"superscript\">2+<\/sup> and Hg<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2+<\/sup>, the second of which is actually a two-atom cation with a 2+ charge.<\/p>\r\n\r\n<ol id=\"gob-ch03_s06_qs01_l09\" class=\"orderedlist\">\r\n \t<li>Using common names, give the probable names of these ions.<\/li>\r\n \t<li>What are the chemical formulas of the ionic compounds these ions make with the oxide ion, O<sup class=\"superscript\">2\u2212<\/sup>?<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa10\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p12\" class=\"para\">The uranyl ion (UO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2+<\/sup>) is a common water-soluble form of uranium. What is the chemical formula of the ionic compound uranyl nitrate? What is the chemical formula of the ionic compound uranyl phosphate?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa11\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p14\" class=\"para\">The formal chemical name of the mineral <em class=\"emphasis\">strengite<\/em> is iron(III) phosphate dihydrate. What is the chemical formula of strengite? What is the formula mass of strengite?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa12\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p16\" class=\"para\">What is the formula mass of MgSO<sub class=\"subscript\">4<\/sub>\u00b77H<sub class=\"subscript\">2<\/sub>O?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa13\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p18\" class=\"para\">What is the formula mass of CaSO<sub class=\"subscript\">4<\/sub>\u00b7\u00bdH<sub class=\"subscript\">2<\/sub>O?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa14\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p20\" class=\"para\">What mass does 20 formula units of NaCl have?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa15\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p22\" class=\"para\">What mass does 75 formula units of K<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> have?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa16\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p24\" class=\"para\">If an atomic mass unit equals 1.66 \u00d7 10<sup class=\"superscript\">\u221224<\/sup> g, what is the mass in grams of one formula unit of NaCl?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa17\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p26\" class=\"para\">If an atomic mass unit equals 1.66 \u00d7 10<sup class=\"superscript\">\u221224<\/sup> g, what is the mass in grams of 5.00 \u00d7 10<sup class=\"superscript\">22<\/sup> formula units of NaOH?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa18\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p28\" class=\"para\">If an atomic mass unit equals 1.66 \u00d7 10<sup class=\"superscript\">\u221224<\/sup> g, what is the mass in grams of 3.96 \u00d7 10<sup class=\"superscript\">23<\/sup> formula units of (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa19\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p30\" class=\"para\">Both tin and lead acquire 2+ or 4+ charges when they become ions. Use the periodic table to explain why this should not surprise you.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa20\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p32\" class=\"para\">Which ion would you expect to be larger in size\u2014In<sup class=\"superscript\">3+<\/sup> or Tl<sup class=\"superscript\">3+<\/sup>? Explain.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa21\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p34\" class=\"para\">Which ion would you expect to be smaller in size\u2014I<sup class=\"superscript\">\u2212<\/sup> or Br<sup class=\"superscript\">\u2212<\/sup>? Explain.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa22\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p36\" class=\"para\">Which ion with a 2+ charge has the following electron configuration? 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch03_s06_qs01_qd01_qa23\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch03_s06_qs01_p38\" class=\"para\">Which ion with a 3\u2212 charge has the following electron configuration? 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<h3>Answers<\/h3>\r\n[reveal-answer q=\"470410\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"470410\"]\r\n\r\n1. For sodium, the valence shell is the third shell; for the sodium ion, the valence shell is the second shell because it has lost all its third shell electrons.\r\n\r\n3.\r\n<ol id=\"gob-ch03_s06_qs01_l02_ans\" class=\"orderedlist\"><ol>\r\n \t<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\r\n \t<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\r\n \t<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\r\n \t<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\r\n<\/ol><\/ol>\r\n5. a.1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">5\u00a0 \u00a0 \u00a0<\/sup>b. It probably requires too much energy to form.\r\n\r\n7.\u00a0\u00a0<img class=\"aligncenter\" style=\"font-size: 0.9em\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/19160850\/be5ae655eb277d90fdc6744e062a4ce2.jpg\" alt=\"image\" \/>\r\n\r\n9. a. mercuric and mercurous, respectively b. HgO and Hg2O, respectively\r\n\r\n11.FePO<sub class=\"subscript\">4<\/sub>\u00b72H<sub class=\"subscript\">2<\/sub>O; 186.86 u\r\n\r\n13. 145.16 u\r\n\r\n15. 13,070.25 u\r\n\r\n17. 3.32 g\r\n\r\n19. Both tin and lead have two p electrons and two s electrons in their valence shells.\r\n\r\n21. Br<sup class=\"superscript\">\u2212<\/sup>\u00a0 because it is higher up on the periodic table\r\n\r\n23. N<sup class=\"superscript\">3\u2212<\/sup>[\/hidden-answer]\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"navbar-top\" class=\"navbar\">\n<div class=\"textbox shaded\">\n<div id=\"navbar-top\" class=\"navbar\">\n<h3 class=\"navbar-part left\"><span style=\"color: #6c64ad;font-size: 1.2em;font-weight: 600;background-color: #eeeeee\"><span style=\"color: #6c64ad;font-size: 1.2em;font-weight: 600;background-color: #eeeeee\">Chapter Summary<\/span><\/span><\/h3>\n<p id=\"gob-ch03_s06_p01\" class=\"para\"><em class=\"emphasis\">T<span style=\"color: #000000\">o ensure that you understand the material in this chapter, you should review the meanings of the following bold terms and ask yourself how they relate to the topics in the chapter.<\/span><\/em><\/p>\n<p id=\"gob-ch03_s06_p02\" class=\"para\"><span style=\"color: #000000\">Atoms combine into compounds by forming <strong class=\"emphasis bold\">chemical bonds<\/strong>. A survey of stable atoms and molecules leads to the <strong class=\"emphasis bold\">octet rule<\/strong>, which says that stable atoms tend to have eight electrons in their outermost, or valence, shell. One way atoms obtain eight electrons in the valence shell is for some atoms to lose electrons while other atoms gain them. When this happens, the atoms take on an electrical charge. Charged atoms are called <strong class=\"emphasis bold\">ions<\/strong>. Ions having opposite charges attract each other. This attraction is called <strong class=\"emphasis bold\">ionic bonding<\/strong>, and the compounds formed are called <strong class=\"emphasis bold\">ionic compounds<\/strong>.<\/span><\/p>\n<p id=\"gob-ch03_s06_p03\" class=\"para\"><span style=\"color: #000000\">Positively charged ions are called <strong class=\"emphasis bold\">cations<\/strong>, while negatively charged ions are called <strong class=\"emphasis bold\">anions<\/strong>. The formation of both cations and anions can be illustrated using electron configurations. Because elements in a column of the periodic table have the same valence shell electron configuration, atoms in the same column of the periodic table tend to form ions having the same charge. <strong class=\"emphasis bold\">Electron dot diagrams<\/strong>, or <strong class=\"emphasis bold\">Lewis diagrams<\/strong>, can also be used to illustrate the formation of cations and anions.<\/span><\/p>\n<p id=\"gob-ch03_s06_p04\" class=\"para\"><span style=\"color: #000000\">Ionic compounds are represented in writing by a <strong class=\"emphasis bold\">chemical formula<\/strong>, which gives the lowest ratio of cations and anions present in the compound. In a formula, the symbol of the cation is written first, followed by the symbol of the anion. <strong class=\"emphasis bold\">Formula unit<\/strong> is considered the basic unit of an ionic compound because ionic compounds do not exist as discrete units. Instead, they exist as <strong class=\"emphasis bold\">crystals<\/strong>, three-dimensional arrays of ions, with cations surrounded by anions and anions surrounded by cations. Chemical formulas for ionic compounds are determined by balancing the positive charge from the cation(s) with the negative charge from the anion(s). A subscript to the right of the ion indicates that more than one of that ion is present in the chemical formula.<\/span><\/p>\n<p id=\"gob-ch03_s06_p05\" class=\"para\"><span style=\"color: #000000\">Some ions are groups of atoms bonded together and having an overall electrical charge. These are called <strong class=\"emphasis bold\">polyatomic ions<\/strong>. Writing formulas with polyatomic ions follows the same rules as with monatomic ions, except that when more than one polyatomic ion is present in a chemical formula, the polyatomic ion is enclosed in parentheses and the subscript is outside the right parenthesis. Ionic compounds typically form between metals and nonmetals or between polyatomic ions.<\/span><\/p>\n<p id=\"gob-ch03_s06_p06\" class=\"para\"><span style=\"color: #000000\">Names of ionic compounds are derived from the names of the ions, with the name of the cation coming first, followed by the name of the anion. If an element can form cations of different charges, there are two alternate systems for indicating the compound\u2019s name. In the <strong class=\"emphasis bold\">Stock system<\/strong>, a roman numeral in parentheses indicates the charge on the cation. An example is the name for FeCl<sub class=\"subscript\">2<\/sub>, which is iron(II) chloride. In the common system, the suffixes &#8211;<em class=\"emphasis\">ous<\/em> and &#8211;<em class=\"emphasis\">ic<\/em> are used to stand for the lower and higher possible charge of the cation, respectively. These suffixes are attached to a stem representing the element (which frequently comes from the Latin form of the element name). An example is the common name for FeCl<sub class=\"subscript\">2<\/sub>, which is ferrous chloride.<\/span><\/p>\n<p id=\"gob-ch03_s06_p07\" class=\"para\"><span style=\"color: #000000\">The <strong class=\"emphasis bold\">formula mass<\/strong> of an ionic compound is the sum of the masses of each individual atom in the formula. Care must be taken when calculating formula masses for formulas containing multiple polyatomic ions because the subscript outside the parentheses refers to all the atoms in the polyatomic ion.<\/span><span style=\"color: #6c64ad;font-size: 1.2em;font-weight: 600\">\u00a0<\/span><\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"book-content\">\n<div id=\"gob-ch03_s06\" class=\"section end-of-chapter\" xml:lang=\"en\">\n<div id=\"gob-ch03_s06_qs01\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<h3>Additional Exercises<\/h3>\n<div id=\"gob-ch03_s06_qs01\" class=\"qandaset block\">\n<ol id=\"gob-ch03_s06_qs01_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch03_s06_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p01\" class=\"para\">What number shell is the valence electron shell of a sodium atom? What number shell is the valence shell of a sodium ion? Explain the difference.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p03\" class=\"para\">What number shell is the valence electron shell of a bromine atom? What number shell is the valence shell of a bromide ion? Explain the difference between these answers and the answers to Exercise 1.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p05\" class=\"para\">What is the electron configuration of each ion?<\/p>\n<ol id=\"gob-ch03_s06_qs01_l01\" class=\"orderedlist\">\n<li>K<sup class=\"superscript\">+<\/sup><\/li>\n<li>Mg<sup class=\"superscript\">2+<\/sup><\/li>\n<li>F<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>S<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p06\" class=\"para\">What is the electron configuration of each ion?<\/p>\n<ol id=\"gob-ch03_s06_qs01_l03\" class=\"orderedlist\">\n<li>Li<sup class=\"superscript\">+<\/sup><\/li>\n<li>Ca<sup class=\"superscript\">2+<\/sup><\/li>\n<li>Cl<sup class=\"superscript\">\u2212<\/sup><\/li>\n<li>O<sup class=\"superscript\">2\u2212<\/sup><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<ol id=\"gob-ch03_s06_qs01_l05\" class=\"orderedlist\">\n<li>If a sodium atom were to lose two electrons, what would be the electron configuration of the resulting cation?<\/li>\n<li>Considering that electron shells are typically separated by large amounts of energy, use your answer to Exercise 5a to suggest why sodium atoms do not form a 2+ cation.<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<ol id=\"gob-ch03_s06_qs01_l07\" class=\"orderedlist\">\n<li>If a chlorine atom were to gain two electrons, what would be the electron configuration of the resulting anion?<\/li>\n<li>Considering that electron shells are typically separated by large amounts of energy, use your answer to Exercise 6a to suggest why chlorine atoms do not form a 2\u2212 anion.<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p09\" class=\"para\">Use Lewis diagrams and arrows to show the electron transfer that occurs during the formation of an ionic compound among Mg atoms and F atoms. (Hint: how many atoms of each will you need?)<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p10\" class=\"para\">Use Lewis diagrams and arrows to show the electron transfer that occurs during the formation of an ionic compound among K atoms and O atoms. (Hint: how many atoms of each will you need?)<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p11\" class=\"para\">Mercury forms two possible cations\u2014Hg<sup class=\"superscript\">2+<\/sup> and Hg<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2+<\/sup>, the second of which is actually a two-atom cation with a 2+ charge.<\/p>\n<ol id=\"gob-ch03_s06_qs01_l09\" class=\"orderedlist\">\n<li>Using common names, give the probable names of these ions.<\/li>\n<li>What are the chemical formulas of the ionic compounds these ions make with the oxide ion, O<sup class=\"superscript\">2\u2212<\/sup>?<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa10\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p12\" class=\"para\">The uranyl ion (UO<sub class=\"subscript\">2<\/sub><sup class=\"superscript\">2+<\/sup>) is a common water-soluble form of uranium. What is the chemical formula of the ionic compound uranyl nitrate? What is the chemical formula of the ionic compound uranyl phosphate?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa11\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p14\" class=\"para\">The formal chemical name of the mineral <em class=\"emphasis\">strengite<\/em> is iron(III) phosphate dihydrate. What is the chemical formula of strengite? What is the formula mass of strengite?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa12\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p16\" class=\"para\">What is the formula mass of MgSO<sub class=\"subscript\">4<\/sub>\u00b77H<sub class=\"subscript\">2<\/sub>O?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa13\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p18\" class=\"para\">What is the formula mass of CaSO<sub class=\"subscript\">4<\/sub>\u00b7\u00bdH<sub class=\"subscript\">2<\/sub>O?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa14\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p20\" class=\"para\">What mass does 20 formula units of NaCl have?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa15\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p22\" class=\"para\">What mass does 75 formula units of K<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub> have?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa16\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p24\" class=\"para\">If an atomic mass unit equals 1.66 \u00d7 10<sup class=\"superscript\">\u221224<\/sup> g, what is the mass in grams of one formula unit of NaCl?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa17\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p26\" class=\"para\">If an atomic mass unit equals 1.66 \u00d7 10<sup class=\"superscript\">\u221224<\/sup> g, what is the mass in grams of 5.00 \u00d7 10<sup class=\"superscript\">22<\/sup> formula units of NaOH?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa18\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p28\" class=\"para\">If an atomic mass unit equals 1.66 \u00d7 10<sup class=\"superscript\">\u221224<\/sup> g, what is the mass in grams of 3.96 \u00d7 10<sup class=\"superscript\">23<\/sup> formula units of (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub>?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa19\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p30\" class=\"para\">Both tin and lead acquire 2+ or 4+ charges when they become ions. Use the periodic table to explain why this should not surprise you.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa20\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p32\" class=\"para\">Which ion would you expect to be larger in size\u2014In<sup class=\"superscript\">3+<\/sup> or Tl<sup class=\"superscript\">3+<\/sup>? Explain.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa21\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p34\" class=\"para\">Which ion would you expect to be smaller in size\u2014I<sup class=\"superscript\">\u2212<\/sup> or Br<sup class=\"superscript\">\u2212<\/sup>? Explain.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa22\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p36\" class=\"para\">Which ion with a 2+ charge has the following electron configuration? 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch03_s06_qs01_qd01_qa23\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch03_s06_qs01_p38\" class=\"para\">Which ion with a 3\u2212 charge has the following electron configuration? 1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<h3>Answers<\/h3>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q470410\">Show Answer<\/span><\/p>\n<div id=\"q470410\" class=\"hidden-answer\" style=\"display: none\">\n<p>1. For sodium, the valence shell is the third shell; for the sodium ion, the valence shell is the second shell because it has lost all its third shell electrons.<\/p>\n<p>3.<\/p>\n<ol id=\"gob-ch03_s06_qs01_l02_ans\" class=\"orderedlist\">\n<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\n<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\n<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\n<li>1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup>3<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>3<em class=\"emphasis\">p<\/em><sup class=\"superscript\">6<\/sup><\/li>\n<\/ol>\n<p>5. a.1<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">s<\/em><sup class=\"superscript\">2<\/sup>2<em class=\"emphasis\">p<\/em><sup class=\"superscript\">5\u00a0 \u00a0 \u00a0<\/sup>b. It probably requires too much energy to form.<\/p>\n<p>7.\u00a0\u00a0<img decoding=\"async\" class=\"aligncenter\" style=\"font-size: 0.9em\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/19160850\/be5ae655eb277d90fdc6744e062a4ce2.jpg\" alt=\"image\" \/><\/p>\n<p>9. a. mercuric and mercurous, respectively b. HgO and Hg2O, respectively<\/p>\n<p>11.FePO<sub class=\"subscript\">4<\/sub>\u00b72H<sub class=\"subscript\">2<\/sub>O; 186.86 u<\/p>\n<p>13. 145.16 u<\/p>\n<p>15. 13,070.25 u<\/p>\n<p>17. 3.32 g<\/p>\n<p>19. Both tin and lead have two p electrons and two s electrons in their valence shells.<\/p>\n<p>21. Br<sup class=\"superscript\">\u2212<\/sup>\u00a0 because it is higher up on the periodic table<\/p>\n<p>23. N<sup class=\"superscript\">3\u2212<\/sup><\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-248\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>The Basics of General, Organic, and Biological Chemistry v. 1.0. <strong>Provided by<\/strong>: Saylor Academy. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\">https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc\/4.0\/\">CC BY-NC: Attribution-NonCommercial<\/a><\/em>. <strong>License Terms<\/strong>: This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work&#039;s original creator or licensor.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":53384,"menu_order":7,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"The Basics of General, Organic, and Biological Chemistry v. 1.0\",\"author\":\"\",\"organization\":\"Saylor Academy\",\"url\":\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc\",\"license_terms\":\"This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work\\'s original creator or licensor.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-248","chapter","type-chapter","status-publish","hentry"],"part":191,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/248","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/users\/53384"}],"version-history":[{"count":12,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/248\/revisions"}],"predecessor-version":[{"id":2835,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/248\/revisions\/2835"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/parts\/191"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/248\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/media?parent=248"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=248"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/contributor?post=248"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/license?post=248"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}