{"id":828,"date":"2018-03-20T16:12:24","date_gmt":"2018-03-20T16:12:24","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/?post_type=chapter&#038;p=828"},"modified":"2018-03-28T15:32:16","modified_gmt":"2018-03-28T15:32:16","slug":"9-4-properties-of-solutions","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/chapter\/9-4-properties-of-solutions\/","title":{"raw":"9.4 Properties of Solutions","rendered":"9.4 Properties of Solutions"},"content":{"raw":"<div id=\"navbar-top\" class=\"navbar\">\r\n<div class=\"navbar-part left\"><span class=\"title-prefix\" style=\"text-align: initial;color: #077fab;font-size: 1.15em;font-weight: 600\">9.4<\/span><span style=\"text-align: initial;color: #077fab;font-size: 1.15em;font-weight: 600\"> Properties of Solutions<\/span><\/div>\r\n<\/div>\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch09_s04\" class=\"section\" xml:lang=\"en\">\r\n<div id=\"gob-ch09_s04_n01\" class=\"learning_objectives editable block\">\r\n<div class=\"textbox learning-objectives\">\r\n<h3 class=\"title\">Learning Objective<\/h3>\r\n<ol id=\"gob-ch09_s04_l01\" class=\"orderedlist\">\r\n \t<li>Describe how the properties of solutions differ from those of pure solvents.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<p id=\"gob-ch09_s04_p01\" class=\"para editable block\">Solutions are likely to have properties similar to those of their major component\u2014usually the solvent. However, some solution properties differ significantly from those of the solvent. Here, we will focus on liquid solutions that have a solid solute, but many of the effects we will discuss in this section are applicable to all solutions.<\/p>\r\n\r\n<div id=\"gob-ch09_s04_s01\" class=\"section\">\r\n<h2 class=\"title editable block\">Colligative Properties<\/h2>\r\n<p id=\"gob-ch09_s04_s01_p01\" class=\"para editable block\">Solutes affect some properties of solutions that depend only on the concentration of the dissolved particles. These properties are called <span class=\"margin_term\"><span class=\"glossterm\">colligative properties<\/span><\/span>. Four important colligative properties that we will examine here are vapor pressure depression, boiling point elevation, freezing point depression, and osmotic pressure.<\/p>\r\n<p id=\"gob-ch09_s04_s01_p02\" class=\"para editable block\">Molecular compounds separate into individual molecules when they are dissolved, so for every 1 mol of molecules dissolved, we get 1 mol of particles. In contrast, ionic compounds separate into their constituent ions when they dissolve, so 1 mol of an ionic compound will produce more than 1 mol of dissolved particles. For example, every mole of NaCl that dissolves yields 1 mol of Na<sup class=\"superscript\">+<\/sup> ions and 1 mol of Cl<sup class=\"superscript\">\u2212<\/sup> ions, for a total of 2 mol of particles in solution. Thus, the effect on a solution\u2019s properties by dissolving NaCl may be twice as large as the effect of dissolving the same amount of moles of glucose (C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub>).<\/p>\r\n\r\n<\/div>\r\n<div id=\"gob-ch09_s04_s02\" class=\"section\">\r\n<h2 class=\"title editable block\">Vapor Pressure Depression<\/h2>\r\n<p id=\"gob-ch09_s04_s02_p01\" class=\"para editable block\">All liquids evaporate. In fact, given enough volume, a liquid will turn completely into a vapor. If enough volume is not present, a liquid will evaporate only to the point where the rate of evaporation equals the rate of vapor condensing back into a liquid. The pressure of the vapor at this point is called the <span class=\"margin_term\"><span class=\"glossterm\">vapor pressure<\/span><\/span>\u00a0of the liquid.<\/p>\r\n<p id=\"gob-ch09_s04_s02_p02\" class=\"para editable block\">The presence of a dissolved solid lowers the characteristic vapor pressure of a liquid so that it evaporates more slowly. (The exceptions to this statement are if the solute itself is a liquid or a gas, in which case the solute will also contribute something to the evaporation process. We will not discuss such solutions here.) This property is called <span class=\"margin_term\"><span class=\"glossterm\">vapor pressure depression<\/span><\/span>\u00a0and is depicted in <a class=\"xref\" href=\"#gob-ch09_s04_s02_f01\">Figure 9.6 \"Vapor Pressure Depression\"<\/a>.<\/p>\r\n\r\n<div id=\"gob-ch09_s04_s02_f01\" class=\"figure large editable block\">\r\n\r\n[caption id=\"\" align=\"alignnone\" width=\"1138\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20161153\/b6e276ade4d5710e6627a9553ef4d11a.jpg\" alt=\"image\" width=\"1138\" height=\"734\" \/> <em>Figure 9.6 Vapor Pressure Depression <\/em>[\/caption]\r\n<p class=\"para\">The presence of solute particles blocks some of the ability for liquid particles to evaporate. Thus, solutions of solid solutes typically have a lower vapor pressure than the pure solvent.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch09_s04_s03\" class=\"section\">\r\n<h2 class=\"title editable block\">Boiling Point and Freezing Point Effects<\/h2>\r\n<p id=\"gob-ch09_s04_s03_p01\" class=\"para editable block\">A related property of solutions is that their boiling points are higher than the boiling point of the pure solvent. Because the presence of solute particles decreases the vapor pressure of the liquid solvent, a higher temperature is needed to reach the boiling point. This phenomenon is called <span class=\"margin_term\"><span class=\"glossterm\">boiling point elevation<\/span><\/span>. For every mole of particles dissolved in a liter of water, the boiling point of water increases by about 0.5\u00b0C.<\/p>\r\n\r\n<div id=\"gob-ch09_s04_s03_n01\" class=\"callout editable block\">\r\n<div class=\"textbox\">\r\n<h3 class=\"title\">Note<\/h3>\r\n<p id=\"gob-ch09_s04_s03_p02\" class=\"para\">Some people argue that putting a pinch or two of salt in water used to cook spaghetti or other pasta makes a solution that has a higher boiling point, so the pasta cooks faster. In actuality, the amount of solute is so small that the boiling point of the water is practically unchanged.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"gob-ch09_s04_s03_p03\" class=\"para editable block\">The presence of solute particles has the opposite effect on the freezing point of a solution. When a solution freezes, only the solvent particles come together to form a solid phase, and the presence of solute particles interferes with that process. Therefore, for the liquid solvent to freeze, more energy must be removed from the solution, which lowers the temperature. Thus, solutions have lower freezing points than pure solvents do. This phenomenon is called <span class=\"margin_term\"><span class=\"glossterm\">freezing point depression<\/span><\/span>. For every mole of particles in a liter of water, the freezing point decreases by about 1.9\u00b0C.<\/p>\r\n<p id=\"gob-ch09_s04_s03_p04\" class=\"para editable block\">Both boiling point elevation and freezing point depression have practical uses. For example, solutions of water and ethylene glycol (C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">6<\/sub>O<sub class=\"subscript\">2<\/sub>) are used as coolants in automobile engines because the boiling point of such a solution is greater than 100\u00b0C, the normal boiling point of water. In winter, salts like NaCl and CaCl<sub class=\"subscript\">2<\/sub> are sprinkled on the ground to melt ice or keep ice from forming on roads and sidewalks (<a class=\"xref\" href=\"#gob-ch09_s04_s03_f01\">Figure 9.7 \"Effect of Freezing Point Depression\"<\/a>). This is because the solution made by dissolving sodium chloride or calcium chloride in water has a lower freezing point than pure water, so the formation of ice is inhibited.<\/p>\r\n\r\n<div id=\"gob-ch09_s04_s03_n02\" class=\"exercises editable block\">\r\n<h3 class=\"title\">Example 11<\/h3>\r\n<p id=\"gob-ch09_s04_s03_p05\" class=\"para\">Which solution\u2019s freezing point deviates more from that of pure water\u2014a 1 M solution of NaCl or a 1 M solution of CaCl<sub class=\"subscript\">2<\/sub>?<\/p>\r\n<p class=\"simpara\">Solution<\/p>\r\n<p id=\"gob-ch09_s04_s03_p06\" class=\"para\">Colligative properties depend on the number of dissolved particles, so the solution with the greater number of particles in solution will show the greatest deviation. When NaCl dissolves, it separates into two ions, Na<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup>. But when CaCl<sub class=\"subscript\">2<\/sub> dissolves, it separates into three ions\u2014one Ca<sup class=\"superscript\">2+<\/sup> ion and two Cl<sup class=\"superscript\">\u2212<\/sup> ions. Thus, mole for mole, CaCl<sub class=\"subscript\">2<\/sub> will have 50% more impact on freezing point depression than NaCl.<\/p>\r\n\r\n<\/div>\r\n<div id=\"gob-ch09_s04_qs01\" class=\"qandaset block\">\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Skill-Building Exercise<\/h3>\r\n<ol id=\"gob-ch09_s04_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch09_s04_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs01_p01\" class=\"para\">Which solution\u2019s boiling point deviates more from that of pure water\u2014a 1 M solution of CaCl<sub class=\"subscript\">2<\/sub> or a 1 M solution of MgSO<sub class=\"subscript\">4<\/sub>?<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch09_s04_s04\" class=\"section\">\r\n<h2 class=\"title editable block\">Osmotic Pressure<\/h2>\r\n<p id=\"gob-ch09_s04_s04_p01\" class=\"para editable block\">The last colligative property of solutions we will consider is a very important one for biological systems. It involves <span class=\"margin_term\"><span class=\"glossterm\">osmosis<\/span><\/span>, the process by which solvent molecules can pass through certain membranes but solute particles cannot. When two solutions of different concentration are present on either side of these membranes (called <em class=\"emphasis\">semipermeable membranes<\/em>), there is a tendency for solvent molecules to move from the more dilute solution to the more concentrated solution until the concentrations of the two solutions are equal. This tendency is called <span class=\"margin_term\"><span class=\"glossterm\">osmotic pressure<\/span><\/span>. External pressure can be exerted on a solution to counter the flow of solvent; the pressure required to halt the osmosis of a solvent is equal to the osmotic pressure of the solution.<\/p>\r\n<p id=\"gob-ch09_s04_s04_p02\" class=\"para editable block\"><span class=\"margin_term\"><span class=\"glossterm\">Osmolarity\u00a0<\/span><\/span>(osmol) is a way of reporting the total number of particles in a solution to determine osmotic pressure. It is defined as the molarity of a solute times the number of particles a formula unit of the solute makes when it dissolves (represented by <em class=\"emphasis\">i<\/em>):<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">osmol = M \u00d7 <em class=\"emphasis\">i<\/em> <\/span><\/span>\r\n<p id=\"gob-ch09_s04_s04_p03\" class=\"para editable block\">If more than one solute is present in a solution, the individual osmolarities are additive to get the total osmolarity of the solution. Solutions that have the same osmolarity have the same osmotic pressure. If solutions of differing osmolarities are present on opposite sides of a semipermeable membrane, solvent will transfer from the lower-osmolarity solution to the higher-osmolarity solution. Counterpressure exerted on the high-osmolarity solution will reduce or halt the solvent transfer. An even higher pressure can be exerted to force solvent from the high-osmolarity solution to the low-osmolarity solution, a process called <em class=\"emphasis\">reverse osmosis<\/em>. Reverse osmosis is used to make potable water from saltwater where sources of fresh water are scarce.<\/p>\r\n\r\n<div id=\"gob-ch09_s04_s04_n01\" class=\"exercises block\">\r\n<h3 class=\"title\">Example 12<\/h3>\r\n<p id=\"gob-ch09_s04_s04_p04\" class=\"para\">A 0.50 M NaCl aqueous solution and a 0.30 M Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> aqueous solution are placed on opposite sides of a semipermeable membrane. Determine the osmolarity of each solution and predict the direction of solvent flow.<\/p>\r\n<p class=\"simpara\">Solution<\/p>\r\n<p id=\"gob-ch09_s04_s04_p05\" class=\"para\">The solvent will flow into the solution of higher osmolarity. The NaCl solute separates into two ions\u2014Na<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup>\u2014when it dissolves, so its osmolarity is as follows:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">osmol (NaCl) = 0.50 M \u00d7 2 = 1.0 osmol<\/span><\/span>\r\n<p id=\"gob-ch09_s04_s04_p06\" class=\"para\">The Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> solute separates into three ions\u2014one Ca<sup class=\"superscript\">2+<\/sup> and two NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup>\u2014when it dissolves, so its osmolarity is as follows:<\/p>\r\n<span class=\"informalequation\"><span class=\"mathphrase\">osmol [Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>] = 0.30 M \u00d7 3 = 0.90 osmol<\/span><\/span>\r\n<p id=\"gob-ch09_s04_s04_p07\" class=\"para\">The osmolarity of the Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> solution is lower than that of the NaCl solution, so water will transfer through the membrane from the Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> solution to the NaCl solution.<\/p>\r\n\r\n<\/div>\r\n<div id=\"gob-ch09_s04_qs02\" class=\"qandaset block\">\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">skill-Building Exercise<\/h3>\r\n<ol id=\"gob-ch09_s04_qs02_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch09_s04_qs02_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs02_p01\" class=\"para\">A 1.5 M C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub> aqueous solution and a 0.40 M Al(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">3<\/sub> aqueous solution are placed on opposite sides of a semipermeable membrane. Determine the osmolarity of each solution and predict the direction of solvent flow.<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch09_s04_s04_n03\" class=\"callout block\">\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">To Your Health: Dialysis<\/h3>\r\n<p id=\"gob-ch09_s04_s04_p10\" class=\"para\">The main function of the kidneys is to filter the blood to remove wastes and extra water, which are then expelled from the body as urine. Some diseases rob the kidneys of their ability to perform this function, causing a buildup of waste materials in the bloodstream. If a kidney transplant is not available or desirable, a procedure called dialysis can be used to remove waste materials and excess water from the blood.<\/p>\r\n<p id=\"gob-ch09_s04_s04_p11\" class=\"para\">In one form of dialysis, called <em class=\"emphasis\">hemodialysis<\/em>, a patient\u2019s blood is passed though a length of tubing that travels through an <em class=\"emphasis\">artificial kidney machine<\/em> (also called a <em class=\"emphasis\">dialysis machine<\/em>). A section of tubing composed of a semipermeable membrane is immersed in a solution of sterile water, glucose, amino acids, and certain electrolytes. The osmotic pressure of the blood forces waste molecules and excess water through the membrane into the sterile solution. Red and white blood cells are too large to pass through the membrane, so they remain in the blood. After being cleansed in this way, the blood is returned to the body.<\/p>\r\n<p id=\"gob-ch09_s04_s04_p12\" class=\"para\">Dialysis is a continuous process, as the osmosis of waste materials and excess water takes time. Typically, 5\u201310 lb of waste-containing fluid is removed in each dialysis session, which can last 2\u20138 hours and must be performed several times a week. Although some patients have been on dialysis for 30 or more years, dialysis is always a temporary solution because waste materials are constantly building up in the bloodstream. A more permanent solution is a kidney transplant.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"gob-ch09_s04_s04_p13\" class=\"para editable block\">Cell walls are semipermeable membranes, so the osmotic pressures of the body\u2019s fluids have important biological consequences. If solutions of different osmolarity exist on either side of the cells, solvent (water) may pass into or out of the cells, sometimes with disastrous results. Consider what happens if red blood cells are placed in a <em class=\"emphasis\">hypotonic<\/em> solution, meaning a solution of lower osmolarity than the liquid inside the cells. The cells swell up as water enters them, disrupting cellular activity and eventually causing the cells to burst. This process is called <em class=\"emphasis\">hemolysis<\/em>. If red blood cells are placed in a <em class=\"emphasis\">hypertonic<\/em> solution, meaning one having a higher osmolarity than exists inside the cells, water leaves the cells to dilute the external solution, and the red blood cells shrivel and die. This process is called <em class=\"emphasis\">crenation<\/em>. Only if red blood cells are placed in <em class=\"emphasis\">isotonic<\/em> solutions that have the same osmolarity as exists inside the cells are they unaffected by negative effects of osmotic pressure. Glucose solutions of about 0.31 M, or sodium chloride solutions of about 0.16 M, are isotonic with blood plasma.<\/p>\r\n\r\n<div id=\"gob-ch09_s04_s04_n04\" class=\"callout editable block\">\r\n<div class=\"textbox\">\r\n<h3 class=\"title\">Note<\/h3>\r\n<p id=\"gob-ch09_s04_s04_p14\" class=\"para\">The concentration of an isotonic sodium chloride (NaCl) solution is only half that of an isotonic glucose (C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub>) solution because NaCl produces two ions when a formula unit dissolves, while molecular C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub> produces only one particle when a formula unit dissolves. The osmolarities are therefore the same even though the concentrations of the two solutions are different.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<p id=\"gob-ch09_s04_s04_p15\" class=\"para editable block\">Osmotic pressure explains why you should not drink seawater if you are abandoned in a life raft in the middle of the ocean. Its osmolarity is about three times higher than most bodily fluids. You would actually become thirstier as water from your cells was drawn out to dilute the salty ocean water you ingested. Our bodies do a better job coping with hypotonic solutions than with hypertonic ones. The excess water is collected by our kidneys and excreted.<\/p>\r\n<p id=\"gob-ch09_s04_s04_p16\" class=\"para editable block\">Osmotic pressure effects are used in the food industry to make pickles from cucumbers and other vegetables and in brining meat to make corned beef. It is also a factor in the mechanism of getting water from the roots to the tops of trees!<\/p>\r\n\r\n<div id=\"gob-ch09_s04_s04_n05\" class=\"callout editable block\">\r\n<div class=\"textbox shaded\">\r\n<h3 class=\"title\">Career Focus: Perfusionist<\/h3>\r\n<p id=\"gob-ch09_s04_s04_p17\" class=\"para\">A perfusionist is a medical technician trained to assist during any medical procedure in which a patient\u2019s circulatory or breathing functions require support. The use of perfusionists has grown rapidly since the advent of open-heart surgery in 1953.<\/p>\r\n<p id=\"gob-ch09_s04_s04_p18\" class=\"para\">Most perfusionists work in operating rooms, where their main responsibility is to operate heart-lung machines. During many heart surgeries, the heart itself must be stopped. In these situations, a heart-lung machine keeps the patient alive by aerating the blood with oxygen and removing carbon dioxide. The perfusionist monitors both the machine and the status of the blood, notifying the surgeon and the anesthetist of any concerns and taking corrective action if the status of the blood becomes abnormal.<\/p>\r\n<p id=\"gob-ch09_s04_s04_p19\" class=\"para\">Despite the narrow parameters of their specialty, perfusionists must be highly trained. Certified perfusion education programs require a student to learn anatomy, physiology, pathology, chemistry, pharmacology, math, and physics. A college degree is usually required. Some perfusionists work with other external artificial organs, such as hemodialysis machines and artificial livers.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch09_s04_qs03\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<div id=\"gob-ch09_s04_qs03\" class=\"qandaset block\">\r\n<h3 class=\"title\">Concept Review Exercises<\/h3>\r\n<ol id=\"gob-ch09_s04_qs03_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch09_s04_qs03_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs03_p01\" class=\"para\">What are the colligative properties of solutions?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs03_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs03_p03\" class=\"para\">Explain how the following properties of solutions differ from those of the pure solvent: vapor pressure, boiling point, freezing point, and osmotic pressure.<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<div id=\"gob-ch09_s04_qs03\" class=\"qandaset block\">\r\n<h3 class=\"title\">Answers<\/h3>\r\n<\/div>\r\n<div id=\"gob-ch09_s04_qs03_ans\" class=\"qandaset block\">\r\n<ol class=\"qandadiv\">\r\n \t<li id=\"gob-ch09_s04_qs03_qd01_qa01_ans\" class=\"qandaentry\">\r\n<div class=\"answer\">\r\n<p id=\"gob-ch09_s04_qs03_p02_ans\" class=\"para\">Colligative properties are characteristics that a solution has that depend on the number, not the identity, of solute particles.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs03_qd01_qa02_ans\" class=\"qandaentry\">\r\n<div class=\"answer\">\r\n<p id=\"gob-ch09_s04_qs03_p04_ans\" class=\"para\">In solutions, the vapor pressure is lower, the boiling point is higher, the freezing point is lower, and the osmotic pressure is higher.<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch09_s04_s04_n07\" class=\"key_takeaways editable block\">\r\n<div class=\"textbox key-takeaways\">\r\n<div id=\"gob-ch09_s04_s04_n07\" class=\"key_takeaways editable block\">\r\n<h3 class=\"title\">Key Takeaway<\/h3>\r\n<ul id=\"gob-ch09_s04_s04_l02\" class=\"itemizedlist\">\r\n \t<li>Certain properties of solutions differ from those of pure solvents in predictable ways.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<div id=\"gob-ch09_s04_s04_n07\" class=\"key_takeaways editable block\">\r\n<h3 class=\"title\">Exercises<\/h3>\r\n<\/div>\r\n<div id=\"gob-ch09_s04_qs04\" class=\"qandaset block\">\r\n<ol id=\"gob-ch09_s04_qs04_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch09_s04_qs04_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs04_p01\" class=\"para\">In each pair of aqueous systems, which will have the lower vapor pressure?<\/p>\r\n\r\n<ol id=\"gob-ch09_s04_qs04_l01\" class=\"orderedlist\">\r\n \t<li>pure water or 1.0 M NaCl<\/li>\r\n \t<li>1.0 M NaCl or 1.0 M C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub><\/li>\r\n \t<li>1.0 M CaCl<sub class=\"subscript\">2<\/sub> or 1.0 M (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs04_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs04_p02\" class=\"para\">In each pair of aqueous systems, which will have the lower vapor pressure?<\/p>\r\n\r\n<ol id=\"gob-ch09_s04_qs04_l03\" class=\"orderedlist\">\r\n \t<li>0.50 M Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> or 1.0 M KBr<\/li>\r\n \t<li>1.5 M C<sub class=\"subscript\">12<\/sub>H<sub class=\"subscript\">22<\/sub>O<sub class=\"subscript\">11<\/sub> or 0.75 M Ca(OH)<sub class=\"subscript\">2<\/sub><\/li>\r\n \t<li>0.10 M Cu(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> or pure water<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs04_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs04_p03\" class=\"para\">In each pair of aqueous systems, which will have the higher boiling point?<\/p>\r\n\r\n<ol id=\"gob-ch09_s04_qs04_l05\" class=\"orderedlist\">\r\n \t<li>pure water or a 1.0 M NaCl<\/li>\r\n \t<li>1.0 M NaCl or 1.0 M C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub><\/li>\r\n \t<li>1.0 M CaCl<sub class=\"subscript\">2<\/sub> or 1.0 M (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs04_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs04_p04\" class=\"para\">In each pair of aqueous systems, which will have the higher boiling point?<\/p>\r\n\r\n<ol id=\"gob-ch09_s04_qs04_l07\" class=\"orderedlist\">\r\n \t<li>1.0 M KBr<\/li>\r\n \t<li>1.5 M C<sub class=\"subscript\">12<\/sub>H<sub class=\"subscript\">22<\/sub>O<sub class=\"subscript\">11<\/sub> or 0.75 M Ca(OH)<sub class=\"subscript\">2<\/sub><\/li>\r\n \t<li>0.10 M Cu(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> or pure water<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs04_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs04_p05\" class=\"para\">Estimate the boiling point of each aqueous solution. The boiling point of pure water is 100.0\u00b0C.<\/p>\r\n\r\n<ol id=\"gob-ch09_s04_qs04_l09\" class=\"orderedlist\">\r\n \t<li>0.50 M NaCl<\/li>\r\n \t<li>1.5 M Na<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/li>\r\n \t<li>2.0 M C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs04_qd01_qa06\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs04_p06\" class=\"para\">Estimate the freezing point of each aqueous solution. The freezing point of pure water is 0.0\u00b0C.<\/p>\r\n\r\n<ol id=\"gob-ch09_s04_qs04_l11\" class=\"orderedlist\">\r\n \t<li>0.50 M NaCl<\/li>\r\n \t<li>1.5 M Na<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/li>\r\n \t<li>2.0 M C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs04_qd01_qa07\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs04_p07\" class=\"para\">Explain why salt (NaCl) is spread on roads and sidewalks to inhibit ice formation in cold weather.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs04_qd01_qa08\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs04_p09\" class=\"para\">Salt (NaCl) and calcium chloride (CaCl<sub class=\"subscript\">2<\/sub>) are used widely in some areas to minimize the formation of ice on sidewalks and roads. One of these ionic compounds is better, mole for mole, at inhibiting ice formation. Which is that likely to be? Why?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs04_qd01_qa09\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs04_p11\" class=\"para\">What is the osmolarity of each aqueous solution?<\/p>\r\n\r\n<ol id=\"gob-ch09_s04_qs04_l13\" class=\"orderedlist\">\r\n \t<li>0.500 M NH<sub class=\"subscript\">2<\/sub>CONH<sub class=\"subscript\">2<\/sub><\/li>\r\n \t<li>0.500 M NaBr<\/li>\r\n \t<li>0.500 M Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs04_qd01_qa10\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs04_p12\" class=\"para\">What is the osmolarity of each aqueous solution?<\/p>\r\n\r\n<ol id=\"gob-ch09_s04_qs04_l15\" class=\"orderedlist\">\r\n \t<li>0.150 M KCl<\/li>\r\n \t<li>0.450 M (CH<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>CHOH<\/li>\r\n \t<li>0.500 M Ca<sub class=\"subscript\">3<\/sub>(PO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs04_qd01_qa11\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs04_p13\" class=\"para\">A 1.0 M solution of an unknown soluble salt has an osmolarity of 3.0 osmol. What can you conclude about the salt?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch09_s04_qs04_qd01_qa12\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch09_s04_qs04_p15\" class=\"para\">A 1.5 M NaCl solution and a 0.75 M Al(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">3<\/sub> solution exist on opposite sides of a semipermeable membrane. Determine the osmolarity of each solution and the direction of solvent flow, if any, across the membrane.<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch09_s04\" class=\"section\" xml:lang=\"en\">\r\n<div id=\"gob-ch09_s04_s04\" class=\"section\">\r\n<div id=\"gob-ch09_s04_s04_n07\" class=\"key_takeaways editable block\">\r\n<h3 class=\"title\">Answers<\/h3>\r\n<\/div>\r\n<div id=\"gob-ch09_s04_qs04_ans\" class=\"qandaset block\">\r\n\r\n1. a. 1.0 M NaCl\r\n\r\nb. 1.0 M NaCl\r\n\r\nc. 1.0 M (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n\r\n3. a. 1.0 M NaCl\r\n\r\nb. 1.0 M NaCl\r\n\r\nc. 1.0 M (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub>\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n\r\n5. a. 100.5\u00b0C\r\n\r\nb. 102.3\u00b0C\r\n\r\nc. 101\u00b0C\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n<p id=\"gob-ch09_s04_qs04_p08_ans\" class=\"para\">7. NaCl lowers the freezing point of water, so it needs to be colder for the water to freeze.<\/p>\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n\r\n9. a. 0.500 osmol\r\n\r\nb. 1.000 osmol\r\n\r\nc. 1.500 osmol\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<div class=\"answer\">\r\n<p id=\"gob-ch09_s04_qs04_p14_ans\" class=\"para\">11. It must separate into three ions when it dissolves.<\/p>\r\n\r\n<\/div>\r\n<div class=\"answer\"><\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"navbar-bottom\" class=\"navbar\">\r\n<div class=\"navbar-part right\">\r\n\r\n&nbsp;\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n&nbsp;\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"navbar-top\" class=\"navbar\">\n<div class=\"navbar-part left\"><span class=\"title-prefix\" style=\"text-align: initial;color: #077fab;font-size: 1.15em;font-weight: 600\">9.4<\/span><span style=\"text-align: initial;color: #077fab;font-size: 1.15em;font-weight: 600\"> Properties of Solutions<\/span><\/div>\n<\/div>\n<div id=\"book-content\">\n<div id=\"gob-ch09_s04\" class=\"section\" xml:lang=\"en\">\n<div id=\"gob-ch09_s04_n01\" class=\"learning_objectives editable block\">\n<div class=\"textbox learning-objectives\">\n<h3 class=\"title\">Learning Objective<\/h3>\n<ol id=\"gob-ch09_s04_l01\" class=\"orderedlist\">\n<li>Describe how the properties of solutions differ from those of pure solvents.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<p id=\"gob-ch09_s04_p01\" class=\"para editable block\">Solutions are likely to have properties similar to those of their major component\u2014usually the solvent. However, some solution properties differ significantly from those of the solvent. Here, we will focus on liquid solutions that have a solid solute, but many of the effects we will discuss in this section are applicable to all solutions.<\/p>\n<div id=\"gob-ch09_s04_s01\" class=\"section\">\n<h2 class=\"title editable block\">Colligative Properties<\/h2>\n<p id=\"gob-ch09_s04_s01_p01\" class=\"para editable block\">Solutes affect some properties of solutions that depend only on the concentration of the dissolved particles. These properties are called <span class=\"margin_term\"><span class=\"glossterm\">colligative properties<\/span><\/span>. Four important colligative properties that we will examine here are vapor pressure depression, boiling point elevation, freezing point depression, and osmotic pressure.<\/p>\n<p id=\"gob-ch09_s04_s01_p02\" class=\"para editable block\">Molecular compounds separate into individual molecules when they are dissolved, so for every 1 mol of molecules dissolved, we get 1 mol of particles. In contrast, ionic compounds separate into their constituent ions when they dissolve, so 1 mol of an ionic compound will produce more than 1 mol of dissolved particles. For example, every mole of NaCl that dissolves yields 1 mol of Na<sup class=\"superscript\">+<\/sup> ions and 1 mol of Cl<sup class=\"superscript\">\u2212<\/sup> ions, for a total of 2 mol of particles in solution. Thus, the effect on a solution\u2019s properties by dissolving NaCl may be twice as large as the effect of dissolving the same amount of moles of glucose (C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub>).<\/p>\n<\/div>\n<div id=\"gob-ch09_s04_s02\" class=\"section\">\n<h2 class=\"title editable block\">Vapor Pressure Depression<\/h2>\n<p id=\"gob-ch09_s04_s02_p01\" class=\"para editable block\">All liquids evaporate. In fact, given enough volume, a liquid will turn completely into a vapor. If enough volume is not present, a liquid will evaporate only to the point where the rate of evaporation equals the rate of vapor condensing back into a liquid. The pressure of the vapor at this point is called the <span class=\"margin_term\"><span class=\"glossterm\">vapor pressure<\/span><\/span>\u00a0of the liquid.<\/p>\n<p id=\"gob-ch09_s04_s02_p02\" class=\"para editable block\">The presence of a dissolved solid lowers the characteristic vapor pressure of a liquid so that it evaporates more slowly. (The exceptions to this statement are if the solute itself is a liquid or a gas, in which case the solute will also contribute something to the evaporation process. We will not discuss such solutions here.) This property is called <span class=\"margin_term\"><span class=\"glossterm\">vapor pressure depression<\/span><\/span>\u00a0and is depicted in <a class=\"xref\" href=\"#gob-ch09_s04_s02_f01\">Figure 9.6 &#8220;Vapor Pressure Depression&#8221;<\/a>.<\/p>\n<div id=\"gob-ch09_s04_s02_f01\" class=\"figure large editable block\">\n<div style=\"width: 1148px\" class=\"wp-caption alignnone\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20161153\/b6e276ade4d5710e6627a9553ef4d11a.jpg\" alt=\"image\" width=\"1138\" height=\"734\" \/><\/p>\n<p class=\"wp-caption-text\"><em>Figure 9.6 Vapor Pressure Depression <\/em><\/p>\n<\/div>\n<p class=\"para\">The presence of solute particles blocks some of the ability for liquid particles to evaporate. Thus, solutions of solid solutes typically have a lower vapor pressure than the pure solvent.<\/p>\n<\/div>\n<\/div>\n<div id=\"gob-ch09_s04_s03\" class=\"section\">\n<h2 class=\"title editable block\">Boiling Point and Freezing Point Effects<\/h2>\n<p id=\"gob-ch09_s04_s03_p01\" class=\"para editable block\">A related property of solutions is that their boiling points are higher than the boiling point of the pure solvent. Because the presence of solute particles decreases the vapor pressure of the liquid solvent, a higher temperature is needed to reach the boiling point. This phenomenon is called <span class=\"margin_term\"><span class=\"glossterm\">boiling point elevation<\/span><\/span>. For every mole of particles dissolved in a liter of water, the boiling point of water increases by about 0.5\u00b0C.<\/p>\n<div id=\"gob-ch09_s04_s03_n01\" class=\"callout editable block\">\n<div class=\"textbox\">\n<h3 class=\"title\">Note<\/h3>\n<p id=\"gob-ch09_s04_s03_p02\" class=\"para\">Some people argue that putting a pinch or two of salt in water used to cook spaghetti or other pasta makes a solution that has a higher boiling point, so the pasta cooks faster. In actuality, the amount of solute is so small that the boiling point of the water is practically unchanged.<\/p>\n<\/div>\n<\/div>\n<p id=\"gob-ch09_s04_s03_p03\" class=\"para editable block\">The presence of solute particles has the opposite effect on the freezing point of a solution. When a solution freezes, only the solvent particles come together to form a solid phase, and the presence of solute particles interferes with that process. Therefore, for the liquid solvent to freeze, more energy must be removed from the solution, which lowers the temperature. Thus, solutions have lower freezing points than pure solvents do. This phenomenon is called <span class=\"margin_term\"><span class=\"glossterm\">freezing point depression<\/span><\/span>. For every mole of particles in a liter of water, the freezing point decreases by about 1.9\u00b0C.<\/p>\n<p id=\"gob-ch09_s04_s03_p04\" class=\"para editable block\">Both boiling point elevation and freezing point depression have practical uses. For example, solutions of water and ethylene glycol (C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">6<\/sub>O<sub class=\"subscript\">2<\/sub>) are used as coolants in automobile engines because the boiling point of such a solution is greater than 100\u00b0C, the normal boiling point of water. In winter, salts like NaCl and CaCl<sub class=\"subscript\">2<\/sub> are sprinkled on the ground to melt ice or keep ice from forming on roads and sidewalks (<a class=\"xref\" href=\"#gob-ch09_s04_s03_f01\">Figure 9.7 &#8220;Effect of Freezing Point Depression&#8221;<\/a>). This is because the solution made by dissolving sodium chloride or calcium chloride in water has a lower freezing point than pure water, so the formation of ice is inhibited.<\/p>\n<div id=\"gob-ch09_s04_s03_n02\" class=\"exercises editable block\">\n<h3 class=\"title\">Example 11<\/h3>\n<p id=\"gob-ch09_s04_s03_p05\" class=\"para\">Which solution\u2019s freezing point deviates more from that of pure water\u2014a 1 M solution of NaCl or a 1 M solution of CaCl<sub class=\"subscript\">2<\/sub>?<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"gob-ch09_s04_s03_p06\" class=\"para\">Colligative properties depend on the number of dissolved particles, so the solution with the greater number of particles in solution will show the greatest deviation. When NaCl dissolves, it separates into two ions, Na<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup>. But when CaCl<sub class=\"subscript\">2<\/sub> dissolves, it separates into three ions\u2014one Ca<sup class=\"superscript\">2+<\/sup> ion and two Cl<sup class=\"superscript\">\u2212<\/sup> ions. Thus, mole for mole, CaCl<sub class=\"subscript\">2<\/sub> will have 50% more impact on freezing point depression than NaCl.<\/p>\n<\/div>\n<div id=\"gob-ch09_s04_qs01\" class=\"qandaset block\">\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Skill-Building Exercise<\/h3>\n<ol id=\"gob-ch09_s04_qs01_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch09_s04_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs01_p01\" class=\"para\">Which solution\u2019s boiling point deviates more from that of pure water\u2014a 1 M solution of CaCl<sub class=\"subscript\">2<\/sub> or a 1 M solution of MgSO<sub class=\"subscript\">4<\/sub>?<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch09_s04_s04\" class=\"section\">\n<h2 class=\"title editable block\">Osmotic Pressure<\/h2>\n<p id=\"gob-ch09_s04_s04_p01\" class=\"para editable block\">The last colligative property of solutions we will consider is a very important one for biological systems. It involves <span class=\"margin_term\"><span class=\"glossterm\">osmosis<\/span><\/span>, the process by which solvent molecules can pass through certain membranes but solute particles cannot. When two solutions of different concentration are present on either side of these membranes (called <em class=\"emphasis\">semipermeable membranes<\/em>), there is a tendency for solvent molecules to move from the more dilute solution to the more concentrated solution until the concentrations of the two solutions are equal. This tendency is called <span class=\"margin_term\"><span class=\"glossterm\">osmotic pressure<\/span><\/span>. External pressure can be exerted on a solution to counter the flow of solvent; the pressure required to halt the osmosis of a solvent is equal to the osmotic pressure of the solution.<\/p>\n<p id=\"gob-ch09_s04_s04_p02\" class=\"para editable block\"><span class=\"margin_term\"><span class=\"glossterm\">Osmolarity\u00a0<\/span><\/span>(osmol) is a way of reporting the total number of particles in a solution to determine osmotic pressure. It is defined as the molarity of a solute times the number of particles a formula unit of the solute makes when it dissolves (represented by <em class=\"emphasis\">i<\/em>):<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">osmol = M \u00d7 <em class=\"emphasis\">i<\/em> <\/span><\/span><\/p>\n<p id=\"gob-ch09_s04_s04_p03\" class=\"para editable block\">If more than one solute is present in a solution, the individual osmolarities are additive to get the total osmolarity of the solution. Solutions that have the same osmolarity have the same osmotic pressure. If solutions of differing osmolarities are present on opposite sides of a semipermeable membrane, solvent will transfer from the lower-osmolarity solution to the higher-osmolarity solution. Counterpressure exerted on the high-osmolarity solution will reduce or halt the solvent transfer. An even higher pressure can be exerted to force solvent from the high-osmolarity solution to the low-osmolarity solution, a process called <em class=\"emphasis\">reverse osmosis<\/em>. Reverse osmosis is used to make potable water from saltwater where sources of fresh water are scarce.<\/p>\n<div id=\"gob-ch09_s04_s04_n01\" class=\"exercises block\">\n<h3 class=\"title\">Example 12<\/h3>\n<p id=\"gob-ch09_s04_s04_p04\" class=\"para\">A 0.50 M NaCl aqueous solution and a 0.30 M Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> aqueous solution are placed on opposite sides of a semipermeable membrane. Determine the osmolarity of each solution and predict the direction of solvent flow.<\/p>\n<p class=\"simpara\">Solution<\/p>\n<p id=\"gob-ch09_s04_s04_p05\" class=\"para\">The solvent will flow into the solution of higher osmolarity. The NaCl solute separates into two ions\u2014Na<sup class=\"superscript\">+<\/sup> and Cl<sup class=\"superscript\">\u2212<\/sup>\u2014when it dissolves, so its osmolarity is as follows:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">osmol (NaCl) = 0.50 M \u00d7 2 = 1.0 osmol<\/span><\/span><\/p>\n<p id=\"gob-ch09_s04_s04_p06\" class=\"para\">The Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> solute separates into three ions\u2014one Ca<sup class=\"superscript\">2+<\/sup> and two NO<sub class=\"subscript\">3<\/sub><sup class=\"superscript\">\u2212<\/sup>\u2014when it dissolves, so its osmolarity is as follows:<\/p>\n<p><span class=\"informalequation\"><span class=\"mathphrase\">osmol [Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>] = 0.30 M \u00d7 3 = 0.90 osmol<\/span><\/span><\/p>\n<p id=\"gob-ch09_s04_s04_p07\" class=\"para\">The osmolarity of the Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> solution is lower than that of the NaCl solution, so water will transfer through the membrane from the Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> solution to the NaCl solution.<\/p>\n<\/div>\n<div id=\"gob-ch09_s04_qs02\" class=\"qandaset block\">\n<div class=\"textbox shaded\">\n<h3 class=\"title\">skill-Building Exercise<\/h3>\n<ol id=\"gob-ch09_s04_qs02_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch09_s04_qs02_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs02_p01\" class=\"para\">A 1.5 M C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub> aqueous solution and a 0.40 M Al(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">3<\/sub> aqueous solution are placed on opposite sides of a semipermeable membrane. Determine the osmolarity of each solution and predict the direction of solvent flow.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div id=\"gob-ch09_s04_s04_n03\" class=\"callout block\">\n<div class=\"textbox shaded\">\n<h3 class=\"title\">To Your Health: Dialysis<\/h3>\n<p id=\"gob-ch09_s04_s04_p10\" class=\"para\">The main function of the kidneys is to filter the blood to remove wastes and extra water, which are then expelled from the body as urine. Some diseases rob the kidneys of their ability to perform this function, causing a buildup of waste materials in the bloodstream. If a kidney transplant is not available or desirable, a procedure called dialysis can be used to remove waste materials and excess water from the blood.<\/p>\n<p id=\"gob-ch09_s04_s04_p11\" class=\"para\">In one form of dialysis, called <em class=\"emphasis\">hemodialysis<\/em>, a patient\u2019s blood is passed though a length of tubing that travels through an <em class=\"emphasis\">artificial kidney machine<\/em> (also called a <em class=\"emphasis\">dialysis machine<\/em>). A section of tubing composed of a semipermeable membrane is immersed in a solution of sterile water, glucose, amino acids, and certain electrolytes. The osmotic pressure of the blood forces waste molecules and excess water through the membrane into the sterile solution. Red and white blood cells are too large to pass through the membrane, so they remain in the blood. After being cleansed in this way, the blood is returned to the body.<\/p>\n<p id=\"gob-ch09_s04_s04_p12\" class=\"para\">Dialysis is a continuous process, as the osmosis of waste materials and excess water takes time. Typically, 5\u201310 lb of waste-containing fluid is removed in each dialysis session, which can last 2\u20138 hours and must be performed several times a week. Although some patients have been on dialysis for 30 or more years, dialysis is always a temporary solution because waste materials are constantly building up in the bloodstream. A more permanent solution is a kidney transplant.<\/p>\n<\/div>\n<\/div>\n<p id=\"gob-ch09_s04_s04_p13\" class=\"para editable block\">Cell walls are semipermeable membranes, so the osmotic pressures of the body\u2019s fluids have important biological consequences. If solutions of different osmolarity exist on either side of the cells, solvent (water) may pass into or out of the cells, sometimes with disastrous results. Consider what happens if red blood cells are placed in a <em class=\"emphasis\">hypotonic<\/em> solution, meaning a solution of lower osmolarity than the liquid inside the cells. The cells swell up as water enters them, disrupting cellular activity and eventually causing the cells to burst. This process is called <em class=\"emphasis\">hemolysis<\/em>. If red blood cells are placed in a <em class=\"emphasis\">hypertonic<\/em> solution, meaning one having a higher osmolarity than exists inside the cells, water leaves the cells to dilute the external solution, and the red blood cells shrivel and die. This process is called <em class=\"emphasis\">crenation<\/em>. Only if red blood cells are placed in <em class=\"emphasis\">isotonic<\/em> solutions that have the same osmolarity as exists inside the cells are they unaffected by negative effects of osmotic pressure. Glucose solutions of about 0.31 M, or sodium chloride solutions of about 0.16 M, are isotonic with blood plasma.<\/p>\n<div id=\"gob-ch09_s04_s04_n04\" class=\"callout editable block\">\n<div class=\"textbox\">\n<h3 class=\"title\">Note<\/h3>\n<p id=\"gob-ch09_s04_s04_p14\" class=\"para\">The concentration of an isotonic sodium chloride (NaCl) solution is only half that of an isotonic glucose (C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub>) solution because NaCl produces two ions when a formula unit dissolves, while molecular C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub> produces only one particle when a formula unit dissolves. The osmolarities are therefore the same even though the concentrations of the two solutions are different.<\/p>\n<\/div>\n<\/div>\n<p id=\"gob-ch09_s04_s04_p15\" class=\"para editable block\">Osmotic pressure explains why you should not drink seawater if you are abandoned in a life raft in the middle of the ocean. Its osmolarity is about three times higher than most bodily fluids. You would actually become thirstier as water from your cells was drawn out to dilute the salty ocean water you ingested. Our bodies do a better job coping with hypotonic solutions than with hypertonic ones. The excess water is collected by our kidneys and excreted.<\/p>\n<p id=\"gob-ch09_s04_s04_p16\" class=\"para editable block\">Osmotic pressure effects are used in the food industry to make pickles from cucumbers and other vegetables and in brining meat to make corned beef. It is also a factor in the mechanism of getting water from the roots to the tops of trees!<\/p>\n<div id=\"gob-ch09_s04_s04_n05\" class=\"callout editable block\">\n<div class=\"textbox shaded\">\n<h3 class=\"title\">Career Focus: Perfusionist<\/h3>\n<p id=\"gob-ch09_s04_s04_p17\" class=\"para\">A perfusionist is a medical technician trained to assist during any medical procedure in which a patient\u2019s circulatory or breathing functions require support. The use of perfusionists has grown rapidly since the advent of open-heart surgery in 1953.<\/p>\n<p id=\"gob-ch09_s04_s04_p18\" class=\"para\">Most perfusionists work in operating rooms, where their main responsibility is to operate heart-lung machines. During many heart surgeries, the heart itself must be stopped. In these situations, a heart-lung machine keeps the patient alive by aerating the blood with oxygen and removing carbon dioxide. The perfusionist monitors both the machine and the status of the blood, notifying the surgeon and the anesthetist of any concerns and taking corrective action if the status of the blood becomes abnormal.<\/p>\n<p id=\"gob-ch09_s04_s04_p19\" class=\"para\">Despite the narrow parameters of their specialty, perfusionists must be highly trained. Certified perfusion education programs require a student to learn anatomy, physiology, pathology, chemistry, pharmacology, math, and physics. A college degree is usually required. Some perfusionists work with other external artificial organs, such as hemodialysis machines and artificial livers.<\/p>\n<\/div>\n<\/div>\n<div id=\"gob-ch09_s04_qs03\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<div id=\"gob-ch09_s04_qs03\" class=\"qandaset block\">\n<h3 class=\"title\">Concept Review Exercises<\/h3>\n<ol id=\"gob-ch09_s04_qs03_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch09_s04_qs03_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs03_p01\" class=\"para\">What are the colligative properties of solutions?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs03_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs03_p03\" class=\"para\">Explain how the following properties of solutions differ from those of the pure solvent: vapor pressure, boiling point, freezing point, and osmotic pressure.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<div id=\"gob-ch09_s04_qs03\" class=\"qandaset block\">\n<h3 class=\"title\">Answers<\/h3>\n<\/div>\n<div id=\"gob-ch09_s04_qs03_ans\" class=\"qandaset block\">\n<ol class=\"qandadiv\">\n<li id=\"gob-ch09_s04_qs03_qd01_qa01_ans\" class=\"qandaentry\">\n<div class=\"answer\">\n<p id=\"gob-ch09_s04_qs03_p02_ans\" class=\"para\">Colligative properties are characteristics that a solution has that depend on the number, not the identity, of solute particles.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs03_qd01_qa02_ans\" class=\"qandaentry\">\n<div class=\"answer\">\n<p id=\"gob-ch09_s04_qs03_p04_ans\" class=\"para\">In solutions, the vapor pressure is lower, the boiling point is higher, the freezing point is lower, and the osmotic pressure is higher.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch09_s04_s04_n07\" class=\"key_takeaways editable block\">\n<div class=\"textbox key-takeaways\">\n<div id=\"gob-ch09_s04_s04_n07\" class=\"key_takeaways editable block\">\n<h3 class=\"title\">Key Takeaway<\/h3>\n<ul id=\"gob-ch09_s04_s04_l02\" class=\"itemizedlist\">\n<li>Certain properties of solutions differ from those of pure solvents in predictable ways.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<div id=\"gob-ch09_s04_s04_n07\" class=\"key_takeaways editable block\">\n<h3 class=\"title\">Exercises<\/h3>\n<\/div>\n<div id=\"gob-ch09_s04_qs04\" class=\"qandaset block\">\n<ol id=\"gob-ch09_s04_qs04_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch09_s04_qs04_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs04_p01\" class=\"para\">In each pair of aqueous systems, which will have the lower vapor pressure?<\/p>\n<ol id=\"gob-ch09_s04_qs04_l01\" class=\"orderedlist\">\n<li>pure water or 1.0 M NaCl<\/li>\n<li>1.0 M NaCl or 1.0 M C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub><\/li>\n<li>1.0 M CaCl<sub class=\"subscript\">2<\/sub> or 1.0 M (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs04_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs04_p02\" class=\"para\">In each pair of aqueous systems, which will have the lower vapor pressure?<\/p>\n<ol id=\"gob-ch09_s04_qs04_l03\" class=\"orderedlist\">\n<li>0.50 M Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> or 1.0 M KBr<\/li>\n<li>1.5 M C<sub class=\"subscript\">12<\/sub>H<sub class=\"subscript\">22<\/sub>O<sub class=\"subscript\">11<\/sub> or 0.75 M Ca(OH)<sub class=\"subscript\">2<\/sub><\/li>\n<li>0.10 M Cu(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> or pure water<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs04_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs04_p03\" class=\"para\">In each pair of aqueous systems, which will have the higher boiling point?<\/p>\n<ol id=\"gob-ch09_s04_qs04_l05\" class=\"orderedlist\">\n<li>pure water or a 1.0 M NaCl<\/li>\n<li>1.0 M NaCl or 1.0 M C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub><\/li>\n<li>1.0 M CaCl<sub class=\"subscript\">2<\/sub> or 1.0 M (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs04_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs04_p04\" class=\"para\">In each pair of aqueous systems, which will have the higher boiling point?<\/p>\n<ol id=\"gob-ch09_s04_qs04_l07\" class=\"orderedlist\">\n<li>1.0 M KBr<\/li>\n<li>1.5 M C<sub class=\"subscript\">12<\/sub>H<sub class=\"subscript\">22<\/sub>O<sub class=\"subscript\">11<\/sub> or 0.75 M Ca(OH)<sub class=\"subscript\">2<\/sub><\/li>\n<li>0.10 M Cu(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub> or pure water<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs04_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs04_p05\" class=\"para\">Estimate the boiling point of each aqueous solution. The boiling point of pure water is 100.0\u00b0C.<\/p>\n<ol id=\"gob-ch09_s04_qs04_l09\" class=\"orderedlist\">\n<li>0.50 M NaCl<\/li>\n<li>1.5 M Na<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/li>\n<li>2.0 M C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs04_qd01_qa06\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs04_p06\" class=\"para\">Estimate the freezing point of each aqueous solution. The freezing point of pure water is 0.0\u00b0C.<\/p>\n<ol id=\"gob-ch09_s04_qs04_l11\" class=\"orderedlist\">\n<li>0.50 M NaCl<\/li>\n<li>1.5 M Na<sub class=\"subscript\">2<\/sub>SO<sub class=\"subscript\">4<\/sub><\/li>\n<li>2.0 M C<sub class=\"subscript\">6<\/sub>H<sub class=\"subscript\">12<\/sub>O<sub class=\"subscript\">6<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs04_qd01_qa07\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs04_p07\" class=\"para\">Explain why salt (NaCl) is spread on roads and sidewalks to inhibit ice formation in cold weather.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs04_qd01_qa08\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs04_p09\" class=\"para\">Salt (NaCl) and calcium chloride (CaCl<sub class=\"subscript\">2<\/sub>) are used widely in some areas to minimize the formation of ice on sidewalks and roads. One of these ionic compounds is better, mole for mole, at inhibiting ice formation. Which is that likely to be? Why?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs04_qd01_qa09\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs04_p11\" class=\"para\">What is the osmolarity of each aqueous solution?<\/p>\n<ol id=\"gob-ch09_s04_qs04_l13\" class=\"orderedlist\">\n<li>0.500 M NH<sub class=\"subscript\">2<\/sub>CONH<sub class=\"subscript\">2<\/sub><\/li>\n<li>0.500 M NaBr<\/li>\n<li>0.500 M Ca(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs04_qd01_qa10\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs04_p12\" class=\"para\">What is the osmolarity of each aqueous solution?<\/p>\n<ol id=\"gob-ch09_s04_qs04_l15\" class=\"orderedlist\">\n<li>0.150 M KCl<\/li>\n<li>0.450 M (CH<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">2<\/sub>CHOH<\/li>\n<li>0.500 M Ca<sub class=\"subscript\">3<\/sub>(PO<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">2<\/sub><\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs04_qd01_qa11\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs04_p13\" class=\"para\">A 1.0 M solution of an unknown soluble salt has an osmolarity of 3.0 osmol. What can you conclude about the salt?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch09_s04_qs04_qd01_qa12\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch09_s04_qs04_p15\" class=\"para\">A 1.5 M NaCl solution and a 0.75 M Al(NO<sub class=\"subscript\">3<\/sub>)<sub class=\"subscript\">3<\/sub> solution exist on opposite sides of a semipermeable membrane. Determine the osmolarity of each solution and the direction of solvent flow, if any, across the membrane.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<div id=\"book-content\">\n<div id=\"gob-ch09_s04\" class=\"section\" xml:lang=\"en\">\n<div id=\"gob-ch09_s04_s04\" class=\"section\">\n<div id=\"gob-ch09_s04_s04_n07\" class=\"key_takeaways editable block\">\n<h3 class=\"title\">Answers<\/h3>\n<\/div>\n<div id=\"gob-ch09_s04_qs04_ans\" class=\"qandaset block\">\n<p>1. a. 1.0 M NaCl<\/p>\n<p>b. 1.0 M NaCl<\/p>\n<p>c. 1.0 M (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub><\/p>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p>3. a. 1.0 M NaCl<\/p>\n<p>b. 1.0 M NaCl<\/p>\n<p>c. 1.0 M (NH<sub class=\"subscript\">4<\/sub>)<sub class=\"subscript\">3<\/sub>PO<sub class=\"subscript\">4<\/sub><\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p>5. a. 100.5\u00b0C<\/p>\n<p>b. 102.3\u00b0C<\/p>\n<p>c. 101\u00b0C<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p id=\"gob-ch09_s04_qs04_p08_ans\" class=\"para\">7. NaCl lowers the freezing point of water, so it needs to be colder for the water to freeze.<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p>9. a. 0.500 osmol<\/p>\n<p>b. 1.000 osmol<\/p>\n<p>c. 1.500 osmol<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<div class=\"answer\">\n<p id=\"gob-ch09_s04_qs04_p14_ans\" class=\"para\">11. It must separate into three ions when it dissolves.<\/p>\n<\/div>\n<div class=\"answer\"><\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"navbar-bottom\" class=\"navbar\">\n<div class=\"navbar-part right\">\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-828\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>The Basics of General, Organic, and Biological Chemistry v. 1.0. <strong>Provided by<\/strong>: Saylor Academy. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\">https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc\/4.0\/\">CC BY-NC: Attribution-NonCommercial<\/a><\/em>. <strong>License Terms<\/strong>: This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work&#039;s original creator or licensor.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":44985,"menu_order":5,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"The Basics of General, Organic, and Biological Chemistry v. 1.0\",\"author\":\"\",\"organization\":\"Saylor Academy\",\"url\":\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc\",\"license_terms\":\"This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work\\'s original creator or licensor.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-828","chapter","type-chapter","status-publish","hentry"],"part":796,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/828","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/users\/44985"}],"version-history":[{"count":5,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/828\/revisions"}],"predecessor-version":[{"id":2463,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/828\/revisions\/2463"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/parts\/796"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/828\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/media?parent=828"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=828"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/contributor?post=828"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/license?post=828"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}