{"id":973,"date":"2018-03-20T16:49:52","date_gmt":"2018-03-20T16:49:52","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/?post_type=chapter&#038;p=973"},"modified":"2018-03-29T16:03:34","modified_gmt":"2018-03-29T16:03:34","slug":"12-3-branched-chain-alkanes","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/chapter\/12-3-branched-chain-alkanes\/","title":{"raw":"12.3 Branched-Chain Alkanes","rendered":"12.3 Branched-Chain Alkanes"},"content":{"raw":"<div id=\"navbar-top\" class=\"navbar\">\r\n<div class=\"navbar-part left\">\r\n<div class=\"textbox learning-objectives\">\r\n<h3>Learning Objective<\/h3>\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch12_s03\" class=\"section\" xml:lang=\"en\">\r\n<div id=\"gob-ch12_s03_n01\" class=\"learning_objectives editable block\">\r\n<ol id=\"gob-ch12_s03_l01\" class=\"orderedlist\">\r\n \t<li>Learn how alkane molecules can have branched chains and recognize compounds that are isomers.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch12_s03\" class=\"section\" xml:lang=\"en\">\r\n<p id=\"gob-ch12_s03_p01\" class=\"para editable block\">We can write the structure of butane (C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">10<\/sub>) by stringing four carbon atoms in a row,<\/p>\r\n<span class=\"informalequation block\"><span class=\"mathphrase\">\u2013C\u2013C\u2013C\u2013C\u2013<\/span><\/span>\r\n<p id=\"gob-ch12_s03_p02\" class=\"para editable block\">and then adding enough hydrogen atoms to give each carbon atom four bonds:<\/p>\r\n\r\n<div class=\"informalfigure large block\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164855\/29fd4abea1950382c70d69cd8a344553.jpg\" alt=\"image\" \/><\/div>\r\n<p id=\"gob-ch12_s03_p03\" class=\"para editable block\">The compound butane has this structure, but there is another way to put 4 carbon atoms and 10 hydrogen atoms together. Place 3 of the carbon atoms in a row and then branch the fourth one off the middle carbon atom:<\/p>\r\n\r\n<div class=\"informalfigure large block\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164857\/3dcf40975b53e8e43d15845baa63ec74.jpg\" alt=\"image\" \/><\/div>\r\n<p id=\"gob-ch12_s03_p04\" class=\"para editable block\">Now we add enough hydrogen atoms to give each carbon four bonds.<\/p>\r\n\r\n<div class=\"informalfigure large block\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164900\/c3556577ef9e4710216fab14285f486b.jpg\" alt=\"image\" \/><\/div>\r\n<p id=\"gob-ch12_s03_p05\" class=\"para editable block\">There is a hydrocarbon that corresponds to this structure, which means that two different compounds have the same molecular formula: C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">10<\/sub>. The two compounds have different properties\u2014for example, one boils at \u22120.5\u00b0C; the other at \u221211.7\u00b0C. Different compounds having the same molecular formula are called <span class=\"margin_term\"><strong><span class=\"glossterm\">isomers<\/span><\/strong><\/span>. The compound with this branched chain is called <em class=\"emphasis\">isobutane<\/em> (<a class=\"xref\" href=\"#gob-ch12_s03_f01\">Figure 12.4 \"Butane and Isobutane\"<\/a>).<\/p>\r\n\r\n<div id=\"gob-ch12_s03_f01\" class=\"figure large editable block\">\r\n\r\n[caption id=\"\" align=\"aligncenter\" width=\"1545\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164902\/92ca38faa079c802242a1bf649e6bc1e.jpg\" alt=\"image\" width=\"1545\" height=\"725\" \/> <em>Figure 12.4 Butane and Isobutane.<\/em>The ball-and-stick models of these two compounds show them to be isomers; both have the molecular formula C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">10<\/sub>.[\/caption]\r\n<p class=\"para\"><\/p>\r\n\r\n<\/div>\r\n<p id=\"gob-ch12_s03_p06\" class=\"para editable block\">Notice that C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">10<\/sub> is depicted with a bent chain in <a class=\"xref\" href=\"#gob-ch12_s03_f01\">Figure 12.4 \"Butane and Isobutane\"<\/a>. The four-carbon chain may be bent in various ways because the groups can rotate freely about the C\u2013C bonds. However, this rotation does not change the identity of the compound. It is important to realize that bending a chain does <em class=\"emphasis\">not<\/em> change the identity of the compound; all of the following represent the same compound:<\/p>\r\n\r\n<div class=\"informalfigure large block\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164905\/141fbabea40922728ad040f7576ab911.jpg\" alt=\"image\" \/><\/div>\r\n<p id=\"gob-ch12_s03_p07\" class=\"para editable block\">The formula of isobutane shows a continuous chain of three carbon atoms only, with the fourth attached as a branch off the middle carbon atom of the continuous chain.<\/p>\r\n<p id=\"gob-ch12_s03_p08\" class=\"para editable block\">Unlike C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">10<\/sub>, the compounds methane (CH<sub class=\"subscript\">4<\/sub>), ethane (C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">6<\/sub>), and propane (C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">8<\/sub>) do not exist in isomeric forms because there is only one way to arrange the atoms in each formula so that each carbon atom has four bonds.<\/p>\r\n<p id=\"gob-ch12_s03_p09\" class=\"para editable block\">Next beyond C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">10<\/sub> in the homologous series is pentane. Each compound has the same molecular formula: C<sub class=\"subscript\">5<\/sub>H<sub class=\"subscript\">12<\/sub>. (<a class=\"xref\" href=\"gob-ch12_s02#gob-ch12_s02_t01\">Table 12.2 \"The First 10 Straight-Chain Alkanes\"<\/a> has a column identifying the number of possible isomers for the first 10 straight-chain alkanes.) The compound at the far left is pentane because it has all five carbon atoms in a continuous chain. The compound in the middle is isopentane; like isobutane, it has a one CH<sub class=\"subscript\">3<\/sub> branch off the second carbon atom of the continuous chain. The compound at the far right, discovered after the other two, was named neopentane (from the Greek <em class=\"emphasis\">neos<\/em>, meaning \u201cnew\u201d). Although all three have the same molecular formula, they have different properties, including boiling points: pentane, 36.1\u00b0C; isopentane, 27.7\u00b0C; and neopentane, 9.5\u00b0C.<\/p>\r\n\r\n<div class=\"informalfigure large block\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164908\/e240c001d4462cb0a3358fc60cea4231.jpg\" alt=\"image\" \/><\/div>\r\n<div id=\"gob-ch12_s03_n02\" class=\"callout editable block\">\r\n<div class=\"textbox\">\r\n<div id=\"gob-ch12_s03_n02\" class=\"callout editable block\">\r\n<h3 class=\"title\">Note<\/h3>\r\n<p id=\"gob-ch12_s03_p10\" class=\"para\">A continuous (unbranched) chain of carbon atoms is often called a <em class=\"emphasis\">straight chain<\/em> even though the tetrahedral arrangement about each carbon gives it a zigzag shape. Straight-chain alkanes are sometimes called <em class=\"emphasis\">normal alkanes<\/em>, and their names are given the prefix <em class=\"emphasis\">n<\/em>-. For example, butane is called <em class=\"emphasis\">n<\/em>-butane. We will not use that prefix here because it is not a part of the system established by the International Union of Pure and Applied Chemistry.<\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<div id=\"gob-ch12_s03_n02\" class=\"callout editable block\">\r\n<h3 class=\"title\">Concept Review Exercises<\/h3>\r\n<\/div>\r\n<div id=\"gob-ch12_s03_qs01\" class=\"qandaset block\">\r\n<ol id=\"gob-ch12_s03_qs01_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch12_s03_qs01_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch12_s03_qs01_p01\" class=\"para\">In alkanes, can there be a two-carbon branch off the second carbon atom of a four-carbon chain? Explain.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch12_s03_qs01_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch12_s03_qs01_p03\" class=\"para\">A student is asked to write structural formulas for two different hydrocarbons having the molecular formula C<sub class=\"subscript\">5<\/sub>H<sub class=\"subscript\">12<\/sub>. She writes one formula with all five carbon atoms in a horizontal line and the other with four carbon atoms in a line, with a CH<sub class=\"subscript\">3<\/sub> group extending down from the first attached to the third carbon atom. Do these structural formulas represent different molecular formulas? Explain why or why not.<\/p>\r\n\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch12_s03_qs01_ans\" class=\"qandaset block\">\r\n<h3 class=\"title\">Answers<\/h3>\r\n[reveal-answer q=\"847431\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"847431\"]\r\n<ol>\r\n \t<li>No; the branch would make the longest continuous chain of five carbon atoms.<\/li>\r\n \t<li>No; both are five-carbon continuous chains.[\/hidden-answer]<\/li>\r\n<\/ol>\r\n<div class=\"answer\"><\/div>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch12_s03_n04\" class=\"key_takeaways editable block\">\r\n<div class=\"textbox key-takeaways\">\r\n<h3 class=\"title\">Key Takeaway<\/h3>\r\n<ul id=\"gob-ch12_s03_l03\" class=\"itemizedlist\">\r\n \t<li>Alkanes with four or more carbon atoms can exist in isomeric forms.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<div id=\"gob-ch12_s03_qs02\" class=\"qandaset block\">\r\n<div class=\"textbox exercises\">\r\n<div id=\"book-content\">\r\n<div id=\"gob-ch12_s03\" class=\"section\" xml:lang=\"en\">\r\n<div id=\"gob-ch12_s03_qs02\" class=\"qandaset block\">\r\n<h3 class=\"title\">Exercises<\/h3>\r\n<ol id=\"gob-ch12_s03_qs02_qd01\" class=\"qandadiv\">\r\n \t<li id=\"gob-ch12_s03_qs02_qd01_qa01\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch12_s03_qs02_p01\" class=\"para\">Briefly identify the important distinctions between a straight-chain alkane and a branched-chain alkane.<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch12_s03_qs02_qd01_qa02\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch12_s03_qs02_p03\" class=\"para\">How are butane and isobutane related? How do they differ?<\/p>\r\n\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch12_s03_qs02_qd01_qa03\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch12_s03_qs02_p05\" class=\"para\">Name each compound.<\/p>\r\n\r\n<ol id=\"gob-ch12_s03_qs02_l01\" class=\"orderedlist\">\r\n \t<li>\r\n<div class=\"informalfigure large\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164911\/f4e000cacc0fd570612e6713f728db25.jpg\" alt=\"image\" \/><\/div><\/li>\r\n \t<li>\r\n<div class=\"informalfigure large\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164914\/e2be06c2f6562f3104ee3c4ab6d2650c.jpg\" alt=\"image\" \/><\/div><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch12_s03_qs02_qd01_qa04\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch12_s03_qs02_p06\" class=\"para\">Write the structural formula for each compound.<\/p>\r\n\r\n<ol id=\"gob-ch12_s03_qs02_l03\" class=\"orderedlist\">\r\n \t<li>hexane<\/li>\r\n \t<li>octane<\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n \t<li id=\"gob-ch12_s03_qs02_qd01_qa05\" class=\"qandaentry\">\r\n<div class=\"question\">\r\n<p id=\"gob-ch12_s03_qs02_p07\" class=\"para\">Indicate whether the structures in each set represent the same compound or isomers.<\/p>\r\n\r\n<ol id=\"gob-ch12_s03_qs02_l05\" class=\"orderedlist\">\r\n \t<li>\r\n<p class=\"para\">CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub> and<\/p>\r\n\r\n<div class=\"informalfigure large\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164917\/cfa5bb309c438a57ce83ced2080e9320.jpg\" alt=\"image\" \/><\/div><\/li>\r\n \t<li>\r\n<p class=\"para\">CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub> and<\/p>\r\n\r\n<div class=\"informalfigure large\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164919\/80d3cfc03399873095a6f648297668d7.jpg\" alt=\"image\" \/><\/div><\/li>\r\n<\/ol>\r\n<\/div><\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"gob-ch12_s03_qs02_ans\" class=\"qandaset block\">\r\n<h3 class=\"title\">Answers<\/h3>\r\n[reveal-answer q=\"935776\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"935776\"]\r\n\r\n1. Straight-chain alkanes and branched-chain alkanes have different properties as well as different structures.\r\n\r\n3.\r\n<ol><ol>\r\n \t<li>pentane<\/li>\r\n \t<li>heptane<\/li>\r\n<\/ol><\/ol>\r\n5.\r\n<ol><ol>\r\n \t<li>no<\/li>\r\n \t<li>yes[\/hidden-answer]<\/li>\r\n<\/ol><\/ol>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n<div id=\"navbar-bottom\" class=\"navbar\">\r\n<div class=\"navbar-part right\">\r\n\r\n&nbsp;\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n&nbsp;\r\n\r\n<\/div>\r\n<\/div>\r\n<\/div>","rendered":"<div id=\"navbar-top\" class=\"navbar\">\n<div class=\"navbar-part left\">\n<div class=\"textbox learning-objectives\">\n<h3>Learning Objective<\/h3>\n<div id=\"book-content\">\n<div id=\"gob-ch12_s03\" class=\"section\" xml:lang=\"en\">\n<div id=\"gob-ch12_s03_n01\" class=\"learning_objectives editable block\">\n<ol id=\"gob-ch12_s03_l01\" class=\"orderedlist\">\n<li>Learn how alkane molecules can have branched chains and recognize compounds that are isomers.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"book-content\">\n<div id=\"gob-ch12_s03\" class=\"section\" xml:lang=\"en\">\n<p id=\"gob-ch12_s03_p01\" class=\"para editable block\">We can write the structure of butane (C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">10<\/sub>) by stringing four carbon atoms in a row,<\/p>\n<p><span class=\"informalequation block\"><span class=\"mathphrase\">\u2013C\u2013C\u2013C\u2013C\u2013<\/span><\/span><\/p>\n<p id=\"gob-ch12_s03_p02\" class=\"para editable block\">and then adding enough hydrogen atoms to give each carbon atom four bonds:<\/p>\n<div class=\"informalfigure large block\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164855\/29fd4abea1950382c70d69cd8a344553.jpg\" alt=\"image\" \/><\/div>\n<p id=\"gob-ch12_s03_p03\" class=\"para editable block\">The compound butane has this structure, but there is another way to put 4 carbon atoms and 10 hydrogen atoms together. Place 3 of the carbon atoms in a row and then branch the fourth one off the middle carbon atom:<\/p>\n<div class=\"informalfigure large block\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164857\/3dcf40975b53e8e43d15845baa63ec74.jpg\" alt=\"image\" \/><\/div>\n<p id=\"gob-ch12_s03_p04\" class=\"para editable block\">Now we add enough hydrogen atoms to give each carbon four bonds.<\/p>\n<div class=\"informalfigure large block\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164900\/c3556577ef9e4710216fab14285f486b.jpg\" alt=\"image\" \/><\/div>\n<p id=\"gob-ch12_s03_p05\" class=\"para editable block\">There is a hydrocarbon that corresponds to this structure, which means that two different compounds have the same molecular formula: C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">10<\/sub>. The two compounds have different properties\u2014for example, one boils at \u22120.5\u00b0C; the other at \u221211.7\u00b0C. Different compounds having the same molecular formula are called <span class=\"margin_term\"><strong><span class=\"glossterm\">isomers<\/span><\/strong><\/span>. The compound with this branched chain is called <em class=\"emphasis\">isobutane<\/em> (<a class=\"xref\" href=\"#gob-ch12_s03_f01\">Figure 12.4 &#8220;Butane and Isobutane&#8221;<\/a>).<\/p>\n<div id=\"gob-ch12_s03_f01\" class=\"figure large editable block\">\n<div style=\"width: 1555px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164902\/92ca38faa079c802242a1bf649e6bc1e.jpg\" alt=\"image\" width=\"1545\" height=\"725\" \/><\/p>\n<p class=\"wp-caption-text\"><em>Figure 12.4 Butane and Isobutane.<\/em>The ball-and-stick models of these two compounds show them to be isomers; both have the molecular formula C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">10<\/sub>.<\/p>\n<\/div>\n<p class=\"para\">\n<\/div>\n<p id=\"gob-ch12_s03_p06\" class=\"para editable block\">Notice that C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">10<\/sub> is depicted with a bent chain in <a class=\"xref\" href=\"#gob-ch12_s03_f01\">Figure 12.4 &#8220;Butane and Isobutane&#8221;<\/a>. The four-carbon chain may be bent in various ways because the groups can rotate freely about the C\u2013C bonds. However, this rotation does not change the identity of the compound. It is important to realize that bending a chain does <em class=\"emphasis\">not<\/em> change the identity of the compound; all of the following represent the same compound:<\/p>\n<div class=\"informalfigure large block\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164905\/141fbabea40922728ad040f7576ab911.jpg\" alt=\"image\" \/><\/div>\n<p id=\"gob-ch12_s03_p07\" class=\"para editable block\">The formula of isobutane shows a continuous chain of three carbon atoms only, with the fourth attached as a branch off the middle carbon atom of the continuous chain.<\/p>\n<p id=\"gob-ch12_s03_p08\" class=\"para editable block\">Unlike C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">10<\/sub>, the compounds methane (CH<sub class=\"subscript\">4<\/sub>), ethane (C<sub class=\"subscript\">2<\/sub>H<sub class=\"subscript\">6<\/sub>), and propane (C<sub class=\"subscript\">3<\/sub>H<sub class=\"subscript\">8<\/sub>) do not exist in isomeric forms because there is only one way to arrange the atoms in each formula so that each carbon atom has four bonds.<\/p>\n<p id=\"gob-ch12_s03_p09\" class=\"para editable block\">Next beyond C<sub class=\"subscript\">4<\/sub>H<sub class=\"subscript\">10<\/sub> in the homologous series is pentane. Each compound has the same molecular formula: C<sub class=\"subscript\">5<\/sub>H<sub class=\"subscript\">12<\/sub>. (<a class=\"xref\" href=\"gob-ch12_s02#gob-ch12_s02_t01\">Table 12.2 &#8220;The First 10 Straight-Chain Alkanes&#8221;<\/a> has a column identifying the number of possible isomers for the first 10 straight-chain alkanes.) The compound at the far left is pentane because it has all five carbon atoms in a continuous chain. The compound in the middle is isopentane; like isobutane, it has a one CH<sub class=\"subscript\">3<\/sub> branch off the second carbon atom of the continuous chain. The compound at the far right, discovered after the other two, was named neopentane (from the Greek <em class=\"emphasis\">neos<\/em>, meaning \u201cnew\u201d). Although all three have the same molecular formula, they have different properties, including boiling points: pentane, 36.1\u00b0C; isopentane, 27.7\u00b0C; and neopentane, 9.5\u00b0C.<\/p>\n<div class=\"informalfigure large block\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164908\/e240c001d4462cb0a3358fc60cea4231.jpg\" alt=\"image\" \/><\/div>\n<div id=\"gob-ch12_s03_n02\" class=\"callout editable block\">\n<div class=\"textbox\">\n<div id=\"gob-ch12_s03_n02\" class=\"callout editable block\">\n<h3 class=\"title\">Note<\/h3>\n<p id=\"gob-ch12_s03_p10\" class=\"para\">A continuous (unbranched) chain of carbon atoms is often called a <em class=\"emphasis\">straight chain<\/em> even though the tetrahedral arrangement about each carbon gives it a zigzag shape. Straight-chain alkanes are sometimes called <em class=\"emphasis\">normal alkanes<\/em>, and their names are given the prefix <em class=\"emphasis\">n<\/em>-. For example, butane is called <em class=\"emphasis\">n<\/em>-butane. We will not use that prefix here because it is not a part of the system established by the International Union of Pure and Applied Chemistry.<\/p>\n<\/div>\n<\/div>\n<div class=\"textbox exercises\">\n<div id=\"gob-ch12_s03_n02\" class=\"callout editable block\">\n<h3 class=\"title\">Concept Review Exercises<\/h3>\n<\/div>\n<div id=\"gob-ch12_s03_qs01\" class=\"qandaset block\">\n<ol id=\"gob-ch12_s03_qs01_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch12_s03_qs01_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch12_s03_qs01_p01\" class=\"para\">In alkanes, can there be a two-carbon branch off the second carbon atom of a four-carbon chain? Explain.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch12_s03_qs01_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch12_s03_qs01_p03\" class=\"para\">A student is asked to write structural formulas for two different hydrocarbons having the molecular formula C<sub class=\"subscript\">5<\/sub>H<sub class=\"subscript\">12<\/sub>. She writes one formula with all five carbon atoms in a horizontal line and the other with four carbon atoms in a line, with a CH<sub class=\"subscript\">3<\/sub> group extending down from the first attached to the third carbon atom. Do these structural formulas represent different molecular formulas? Explain why or why not.<\/p>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch12_s03_qs01_ans\" class=\"qandaset block\">\n<h3 class=\"title\">Answers<\/h3>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q847431\">Show Answer<\/span><\/p>\n<div id=\"q847431\" class=\"hidden-answer\" style=\"display: none\">\n<ol>\n<li>No; the branch would make the longest continuous chain of five carbon atoms.<\/li>\n<li>No; both are five-carbon continuous chains.<\/div>\n<\/div>\n<\/li>\n<\/ol>\n<div class=\"answer\"><\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"gob-ch12_s03_n04\" class=\"key_takeaways editable block\">\n<div class=\"textbox key-takeaways\">\n<h3 class=\"title\">Key Takeaway<\/h3>\n<ul id=\"gob-ch12_s03_l03\" class=\"itemizedlist\">\n<li>Alkanes with four or more carbon atoms can exist in isomeric forms.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div id=\"gob-ch12_s03_qs02\" class=\"qandaset block\">\n<div class=\"textbox exercises\">\n<div id=\"book-content\">\n<div id=\"gob-ch12_s03\" class=\"section\" xml:lang=\"en\">\n<div id=\"gob-ch12_s03_qs02\" class=\"qandaset block\">\n<h3 class=\"title\">Exercises<\/h3>\n<ol id=\"gob-ch12_s03_qs02_qd01\" class=\"qandadiv\">\n<li id=\"gob-ch12_s03_qs02_qd01_qa01\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch12_s03_qs02_p01\" class=\"para\">Briefly identify the important distinctions between a straight-chain alkane and a branched-chain alkane.<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch12_s03_qs02_qd01_qa02\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch12_s03_qs02_p03\" class=\"para\">How are butane and isobutane related? How do they differ?<\/p>\n<\/div>\n<\/li>\n<li id=\"gob-ch12_s03_qs02_qd01_qa03\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch12_s03_qs02_p05\" class=\"para\">Name each compound.<\/p>\n<ol id=\"gob-ch12_s03_qs02_l01\" class=\"orderedlist\">\n<li>\n<div class=\"informalfigure large\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164911\/f4e000cacc0fd570612e6713f728db25.jpg\" alt=\"image\" \/><\/div>\n<\/li>\n<li>\n<div class=\"informalfigure large\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164914\/e2be06c2f6562f3104ee3c4ab6d2650c.jpg\" alt=\"image\" \/><\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch12_s03_qs02_qd01_qa04\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch12_s03_qs02_p06\" class=\"para\">Write the structural formula for each compound.<\/p>\n<ol id=\"gob-ch12_s03_qs02_l03\" class=\"orderedlist\">\n<li>hexane<\/li>\n<li>octane<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<li id=\"gob-ch12_s03_qs02_qd01_qa05\" class=\"qandaentry\">\n<div class=\"question\">\n<p id=\"gob-ch12_s03_qs02_p07\" class=\"para\">Indicate whether the structures in each set represent the same compound or isomers.<\/p>\n<ol id=\"gob-ch12_s03_qs02_l05\" class=\"orderedlist\">\n<li>\n<p class=\"para\">CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub> and<\/p>\n<div class=\"informalfigure large\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164917\/cfa5bb309c438a57ce83ced2080e9320.jpg\" alt=\"image\" \/><\/div>\n<\/li>\n<li>\n<p class=\"para\">CH<sub class=\"subscript\">3<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">2<\/sub>CH<sub class=\"subscript\">3<\/sub> and<\/p>\n<div class=\"informalfigure large\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3101\/2018\/03\/20164919\/80d3cfc03399873095a6f648297668d7.jpg\" alt=\"image\" \/><\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<div id=\"gob-ch12_s03_qs02_ans\" class=\"qandaset block\">\n<h3 class=\"title\">Answers<\/h3>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q935776\">Show Answer<\/span><\/p>\n<div id=\"q935776\" class=\"hidden-answer\" style=\"display: none\">\n<p>1. Straight-chain alkanes and branched-chain alkanes have different properties as well as different structures.<\/p>\n<p>3.<\/p>\n<ol>\n<li>pentane<\/li>\n<li>heptane<\/li>\n<\/ol>\n<p>5.<\/p>\n<ol>\n<li>no<\/li>\n<li>yes<\/div>\n<\/div>\n<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"navbar-bottom\" class=\"navbar\">\n<div class=\"navbar-part right\">\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>&nbsp;<\/p>\n<\/div>\n<\/div>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-973\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>The Basics of General, Organic, and Biological Chemistry v. 1.0. <strong>Provided by<\/strong>: Saylor Academy. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\">https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc\/4.0\/\">CC BY-NC: Attribution-NonCommercial<\/a><\/em>. <strong>License Terms<\/strong>: This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work&#039;s original creator or licensor.<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":44985,"menu_order":4,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"The Basics of General, Organic, and Biological Chemistry v. 1.0\",\"author\":\"\",\"organization\":\"Saylor Academy\",\"url\":\"https:\/\/saylordotorg.github.io\/text_the-basics-of-general-organic-and-biological-chemistry\/\",\"project\":\"\",\"license\":\"cc-by-nc\",\"license_terms\":\"This text was adapted by Saylor Academy under a Creative Commons Attribution-NonCommercial-ShareAlike 3.0 License without attribution as requested by the work\\'s original creator or licensor.\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-973","chapter","type-chapter","status-publish","hentry"],"part":941,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/973","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/users\/44985"}],"version-history":[{"count":4,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/973\/revisions"}],"predecessor-version":[{"id":2504,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/973\/revisions\/2504"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/parts\/941"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapters\/973\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/media?parent=973"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=973"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/contributor?post=973"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-orgbiochemistry\/wp-json\/wp\/v2\/license?post=973"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}