{"id":1373,"date":"2018-02-26T20:35:47","date_gmt":"2018-02-26T20:35:47","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/?post_type=back-matter&#038;p=1373"},"modified":"2018-02-26T20:35:51","modified_gmt":"2018-02-26T20:35:51","slug":"mathematical-formulas","status":"publish","type":"back-matter","link":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/back-matter\/mathematical-formulas\/","title":{"raw":"Mathematical Formulas","rendered":"Mathematical Formulas"},"content":{"raw":"<p id=\"fs-id1171238709218\"><strong>Quadratic formula<\/strong><\/p>\n<p id=\"fs-id1171241118332\">If $$ a{x}^{2}+bx+c=0, $$ then $$ x=\\frac{\\text{\u2212}b\u00b1\\sqrt{{b}^{2}-4ac}}{2a}$$<\/p>\n<table id=\"fs-id1171241121579\" summary=\"This table has three columns and four rows. The entry in the first row are: Triangle of base b and height h, Area equal to half bh. The third cell in the first row is blank. the second row has the following entries: Circle of radius r, Circumference equal to 2 pi r, Area equal to pi r squared. The third row has the following entries: Sphere of radius r, Surface area equal to 4 pi r squared, volume equal to 4 by 3 pi r cubed. The fourth row has the following entries: Cylinder of radius r and height h, Area of curved surface equal to 2 pi r h, Volume equal to pi r squared h.\"><caption><span>Geometry<\/span><\/caption>\n<thead><tr valign=\"top\"><th>Triangle of base $$ b $$ and height $$ h$$<\/th>\n<th>Area $$ =\\frac{1}{2}bh$$<\/th>\n<th \/>\n<\/tr><\/thead><tbody><tr valign=\"top\"><td>Circle of radius $$ r$$<\/td>\n<td>Circumference $$ =2\\pi r$$<\/td>\n<td>Area $$ =\\pi {r}^{2}$$<\/td>\n<\/tr><tr valign=\"top\"><td>Sphere of radius $$ r$$<\/td>\n<td>Surface area $$ =4\\pi {r}^{2}$$<\/td>\n<td>Volume $$ =\\frac{4}{3}\\pi {r}^{3}$$<\/td>\n<\/tr><tr valign=\"top\"><td>Cylinder of radius $$ r $$ and height $$ h$$<\/td>\n<td>Area of curved surface $$ =2\\pi rh$$<\/td>\n<td>Volume $$ =\\pi {r}^{2}h$$<\/td>\n<\/tr><\/tbody><\/table><p id=\"fs-id1171241192710\"><strong>Trigonometry<\/strong><\/p>\n<p id=\"fs-id1171241320523\"><em>Trigonometric Identities<\/em><\/p>\n<ol id=\"fs-id1171241111731\" type=\"1\"><li>$$\\text{sin}\\,\\theta =1\\text{\/}\\text{csc}\\,\\theta $$<\/li>\n<li>$$\\text{cos}\\,\\theta =1\\text{\/}\\text{sec}\\,\\theta $$<\/li>\n<li>$$\\text{tan}\\,\\theta =1\\text{\/}\\text{cot}\\,\\theta $$<\/li>\n<li>$$\\text{sin}({90}^{0}-\\theta )=\\text{cos}\\,\\theta $$<\/li>\n<li>$$\\text{cos}({90}^{0}-\\theta )=\\text{sin}\\,\\theta $$<\/li>\n<li>$$\\text{tan}({90}^{0}-\\theta )=\\text{cot}\\,\\theta $$<\/li>\n<li>$${\\text{sin}}^{2}\\,\\theta +{\\text{cos}}^{2}\\,\\theta =1$$<\/li>\n<li>$${\\text{sec}}^{2}\\,\\theta -{\\text{tan}}^{2}\\,\\theta =1$$<\/li>\n<li>$$\\text{tan}\\,\\theta =\\text{sin}\\,\\theta \\text{\/}\\text{cos}\\,\\theta $$<\/li>\n<li>$$\\text{sin}(\\alpha \u00b1\\beta )=\\text{sin}\\,\\alpha \\,\\text{cos}\\,\\beta \u00b1\\text{cos}\\,\\alpha \\,\\text{sin}\\,\\beta $$<\/li>\n<li>$$\\text{cos}(\\alpha \u00b1\\beta )=\\text{cos}\\,\\alpha \\,\\text{cos}\\,\\beta \\mp \\text{sin}\\,\\alpha \\,\\text{sin}\\,\\beta $$<\/li>\n<li>$$\\text{tan}(\\alpha \u00b1\\beta )=\\frac{\\text{tan}\\,\\alpha \u00b1\\text{tan}\\,\\beta }{1\\mp \\text{tan}\\,\\alpha \\,\\text{tan}\\,\\beta }$$<\/li>\n<li>$$\\text{sin}\\,2\\theta =2\\text{sin}\\,\\theta \\,\\text{cos}\\,\\theta $$<\/li>\n<li>$$\\text{cos}\\,2\\theta ={\\text{cos}}^{2}\\,\\theta -{\\text{sin}}^{2}\\,\\theta =2\\,{\\text{cos}}^{2}\\,\\theta -1=1-2\\,{\\text{sin}}^{2}\\,\\theta $$<\/li>\n<li>$$\\text{sin}\\,\\alpha +\\text{sin}\\,\\beta =2\\,\\text{sin}\\frac{1}{2}(\\alpha +\\beta )\\text{cos}\\frac{1}{2}(\\alpha -\\beta )$$<\/li>\n<li>$$\\text{cos}\\,\\alpha +\\text{cos}\\,\\beta =2\\,\\text{cos}\\frac{1}{2}(\\alpha +\\beta )\\text{cos}\\frac{1}{2}(\\alpha -\\beta )$$<\/li>\n<\/ol><p id=\"fs-id1171241012787\"><em>Triangles<\/em><\/p>\n<ol id=\"fs-id1171241129165\" type=\"1\"><li>Law of sines: $$ \\frac{a}{\\text{sin}\\,\\alpha }=\\frac{b}{\\text{sin}\\,\\beta }=\\frac{c}{\\text{sin}\\,\\gamma }$$<\/li>\n<li>Law of cosines: $$ {c}^{2}={a}^{2}+{b}^{2}-2ab\\,\\text{cos}\\,\\gamma $$\n\n<p><span id=\"fs-id1171241119734\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2952\/2018\/01\/31202216\/CNX_UPhysics_00_EE_Triangle1_img.jpg\" alt=\"Figure shows a triangle with three dissimilar sides labeled a, b and c. All three angles of the triangle are acute angles. The angle between b and c is alpha, the angle between a and c is beta and the angle between a and b is gamma.\" \/><\/span><\/p><\/li>\n<li>Pythagorean theorem: $$ {a}^{2}+{b}^{2}={c}^{2}$$\n\n<p><span id=\"fs-id1171241024569\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2952\/2018\/01\/31202220\/CNX_UPhysics_00_EE_Triangle2_img.jpg\" alt=\"Figure shows a right triangle. Its three sides are labeled a, b and c with c being the hypotenuse. The angle between a and c is labeled theta.\" \/><\/span><\/p><\/li>\n<\/ol><p id=\"fs-id1171241190802\"><strong>Series expansions<\/strong><\/p>\n<ol id=\"fs-id1171241016910\" type=\"1\"><li>Binomial theorem: $$ {(a+b)}^{n}={a}^{n}+n{a}^{n-1}b+\\frac{n(n-1){a}^{n-2}{b}^{2}}{2\\text{!}}+\\frac{n(n-1)(n-2){a}^{n-3}{b}^{3}}{3\\text{!}}+\\text{\u00b7\u00b7\u00b7}$$<\/li>\n<li>$${(1\u00b1x)}^{n}=1\u00b1\\frac{nx}{1\\text{!}}+\\frac{n(n-1){x}^{2}}{2\\text{!}}\u00b1\\text{\u00b7\u00b7\u00b7}({x}^{2}&lt;1)$$<\/li>\n<li>$${(1\u00b1x)}^{\\text{\u2212}n}=1\\mp \\frac{nx}{1\\text{!}}+\\frac{n(n+1){x}^{2}}{2\\text{!}}\\mp \\text{\u00b7\u00b7\u00b7}({x}^{2}&lt;1)$$<\/li>\n<li>$$\\text{sin}\\,x=x-\\frac{{x}^{3}}{3\\text{!}}+\\frac{{x}^{5}}{5\\text{!}}-\\text{\u00b7\u00b7\u00b7}$$<\/li>\n<li>$$\\text{cos}\\,x=1-\\frac{{x}^{2}}{2\\text{!}}+\\frac{{x}^{4}}{4\\text{!}}-\\text{\u00b7\u00b7\u00b7}$$<\/li>\n<li>$$\\text{tan}\\,x=x+\\frac{{x}^{3}}{3}+\\frac{2{x}^{5}}{15}+\\text{\u00b7\u00b7\u00b7}$$<\/li>\n<li>$${e}^{x}=1+x+\\frac{{x}^{2}}{2\\text{!}}+\\text{\u00b7\u00b7\u00b7}$$<\/li>\n<li>$$\\text{ln}(1+x)=x-\\frac{1}{2}{x}^{2}+\\frac{1}{3}{x}^{3}-\\text{\u00b7\u00b7\u00b7}(|x|&lt;1)$$<\/li>\n<\/ol><p id=\"fs-id1171241003878\"><strong>Derivatives<\/strong><\/p>\n<ol id=\"fs-id1171241165751\" type=\"1\"><li>$$\\frac{d}{dx}[af(x)]=a\\frac{d}{dx}f(x)$$<\/li>\n<li>$$\\frac{d}{dx}[f(x)+g(x)]=\\frac{d}{dx}f(x)+\\frac{d}{dx}g(x)$$<\/li>\n<li>$$\\frac{d}{dx}[f(x)g(x)]=f(x)\\frac{d}{dx}g(x)+g(x)\\frac{d}{dx}f(x)$$<\/li>\n<li>$$\\frac{d}{dx}f(u)=[\\frac{d}{du}f(u)]\\frac{du}{dx}$$<\/li>\n<li>$$\\frac{d}{dx}{x}^{m}=m{x}^{m-1}$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{sin}\\,x=\\text{cos}\\,x$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{cos}\\,x=\\text{\u2212}\\text{sin}\\,x$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{tan}\\,x={\\text{sec}}^{2}\\,x$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{cot}\\,x=\\text{\u2212}{\\text{csc}}^{2}\\,x$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{sec}\\,x=\\text{tan}\\,x\\,\\text{sec}\\,x$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{csc}\\,x=\\text{\u2212}\\text{cot}\\,x\\,\\text{csc}\\,x$$<\/li>\n<li>$$\\frac{d}{dx}{e}^{x}={e}^{x}$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{ln}\\,x=\\frac{1}{x}$$<\/li>\n<li>$$\\frac{d}{dx}\\,{\\text{sin}}^{-1}\\,x=\\frac{1}{\\sqrt{1-{x}^{2}}}$$<\/li>\n<li>$$\\frac{d}{dx}\\,{\\text{cos}}^{-1}x=-\\frac{1}{\\sqrt{1-{x}^{2}}}$$<\/li>\n<li>$$\\frac{d}{dx}\\,{\\text{tan}}^{-1}x=-\\frac{1}{1+{x}^{2}}$$<\/li>\n<\/ol><p id=\"fs-id1171241165019\"><strong>Integrals<\/strong><\/p>\n<ol id=\"fs-id1171241242695\" type=\"1\"><li>$$\\int af(x)dx=a\\int f(x)dx$$<\/li>\n<li>$$\\int [f(x)+g(x)]dx=\\int f(x)dx+\\int g(x)dx$$<\/li>\n<li>$$\\begin{array}{cc}\\hfill \\int {x}^{m}dx&amp; =\\frac{{x}^{m+1}}{m+1}\\,(m\\ne \\text{\u2212}1)\\hfill \\\\ &amp; =\\text{ln}\\,x(m=-1)\\hfill \\end{array}$$<\/li>\n<li>$$\\int \\text{sin}\\,x\\,dx=\\text{\u2212}\\text{cos}\\,x$$<\/li>\n<li>$$\\int \\text{cos}\\,x\\,dx=\\text{sin}\\,x$$<\/li>\n<li>$$\\int \\text{tan}\\,x\\,dx=\\text{ln}|\\text{sec}\\,x|$$<\/li>\n<li>$$\\int {\\text{sin}}^{2}\\,ax\\,dx=\\frac{x}{2}-\\frac{\\text{sin}\\,2ax}{4a}$$<\/li>\n<li>$$\\int {\\text{cos}}^{2}\\,ax\\,dx=\\frac{x}{2}+\\frac{\\text{sin}\\,2ax}{4a}$$<\/li>\n<li>$$\\int \\text{sin}\\,ax\\,\\text{cos}\\,ax\\,dx=-\\frac{\\text{cos}2ax}{4a}$$<\/li>\n<li>$$\\int {e}^{ax}\\,dx=\\frac{1}{a}{e}^{ax}$$<\/li>\n<li>$$\\int x{e}^{ax}dx=\\frac{{e}^{ax}}{{a}^{2}}(ax-1)$$<\/li>\n<li>$$\\int \\text{ln}\\,ax\\,dx=x\\,\\text{ln}\\,ax-x$$<\/li>\n<li>$$\\int \\frac{dx}{{a}^{2}+{x}^{2}}=\\frac{1}{a}\\,{\\text{tan}}^{-1}\\frac{x}{a}$$<\/li>\n<li>$$\\int \\frac{dx}{{a}^{2}-{x}^{2}}=\\frac{1}{2a}\\,\\text{ln}|\\frac{x+a}{x-a}|$$<\/li>\n<li>$$\\int \\frac{dx}{\\sqrt{{a}^{2}+{x}^{2}}}={\\text{sinh}}^{-1}\\frac{x}{a}$$<\/li>\n<li>$$\\int \\frac{dx}{\\sqrt{{a}^{2}-{x}^{2}}}={\\text{sin}}^{-1}\\frac{x}{a}$$<\/li>\n<li>$$\\int \\sqrt{{a}^{2}+{x}^{2}}\\,dx=\\frac{x}{2}\\sqrt{{a}^{2}+{x}^{2}}+\\frac{{a}^{2}}{2}\\,{\\text{sinh}}^{-1}\\frac{x}{a}$$<\/li>\n<li>$$\\int \\sqrt{{a}^{2}-{x}^{2}}\\,dx=\\frac{x}{2}\\sqrt{{a}^{2}-{x}^{2}}+\\frac{{a}^{2}}{2}\\,{\\text{sin}}^{-1}\\frac{x}{a}$$<\/li>\n<\/ol>","rendered":"<p id=\"fs-id1171238709218\"><strong>Quadratic formula<\/strong><\/p>\n<p id=\"fs-id1171241118332\">If $$ a{x}^{2}+bx+c=0, $$ then $$ x=\\frac{\\text{\u2212}b\u00b1\\sqrt{{b}^{2}-4ac}}{2a}$$<\/p>\n<table id=\"fs-id1171241121579\" summary=\"This table has three columns and four rows. The entry in the first row are: Triangle of base b and height h, Area equal to half bh. The third cell in the first row is blank. the second row has the following entries: Circle of radius r, Circumference equal to 2 pi r, Area equal to pi r squared. The third row has the following entries: Sphere of radius r, Surface area equal to 4 pi r squared, volume equal to 4 by 3 pi r cubed. The fourth row has the following entries: Cylinder of radius r and height h, Area of curved surface equal to 2 pi r h, Volume equal to pi r squared h.\">\n<caption><span>Geometry<\/span><\/caption>\n<thead>\n<tr valign=\"top\">\n<th>Triangle of base $$ b $$ and height $$ h$$<\/th>\n<th>Area $$ =\\frac{1}{2}bh$$<\/th>\n<th>\n<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr valign=\"top\">\n<td>Circle of radius $$ r$$<\/td>\n<td>Circumference $$ =2\\pi r$$<\/td>\n<td>Area $$ =\\pi {r}^{2}$$<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td>Sphere of radius $$ r$$<\/td>\n<td>Surface area $$ =4\\pi {r}^{2}$$<\/td>\n<td>Volume $$ =\\frac{4}{3}\\pi {r}^{3}$$<\/td>\n<\/tr>\n<tr valign=\"top\">\n<td>Cylinder of radius $$ r $$ and height $$ h$$<\/td>\n<td>Area of curved surface $$ =2\\pi rh$$<\/td>\n<td>Volume $$ =\\pi {r}^{2}h$$<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p id=\"fs-id1171241192710\"><strong>Trigonometry<\/strong><\/p>\n<p id=\"fs-id1171241320523\"><em>Trigonometric Identities<\/em><\/p>\n<ol id=\"fs-id1171241111731\" type=\"1\">\n<li>$$\\text{sin}\\,\\theta =1\\text{\/}\\text{csc}\\,\\theta $$<\/li>\n<li>$$\\text{cos}\\,\\theta =1\\text{\/}\\text{sec}\\,\\theta $$<\/li>\n<li>$$\\text{tan}\\,\\theta =1\\text{\/}\\text{cot}\\,\\theta $$<\/li>\n<li>$$\\text{sin}({90}^{0}-\\theta )=\\text{cos}\\,\\theta $$<\/li>\n<li>$$\\text{cos}({90}^{0}-\\theta )=\\text{sin}\\,\\theta $$<\/li>\n<li>$$\\text{tan}({90}^{0}-\\theta )=\\text{cot}\\,\\theta $$<\/li>\n<li>$${\\text{sin}}^{2}\\,\\theta +{\\text{cos}}^{2}\\,\\theta =1$$<\/li>\n<li>$${\\text{sec}}^{2}\\,\\theta -{\\text{tan}}^{2}\\,\\theta =1$$<\/li>\n<li>$$\\text{tan}\\,\\theta =\\text{sin}\\,\\theta \\text{\/}\\text{cos}\\,\\theta $$<\/li>\n<li>$$\\text{sin}(\\alpha \u00b1\\beta )=\\text{sin}\\,\\alpha \\,\\text{cos}\\,\\beta \u00b1\\text{cos}\\,\\alpha \\,\\text{sin}\\,\\beta $$<\/li>\n<li>$$\\text{cos}(\\alpha \u00b1\\beta )=\\text{cos}\\,\\alpha \\,\\text{cos}\\,\\beta \\mp \\text{sin}\\,\\alpha \\,\\text{sin}\\,\\beta $$<\/li>\n<li>$$\\text{tan}(\\alpha \u00b1\\beta )=\\frac{\\text{tan}\\,\\alpha \u00b1\\text{tan}\\,\\beta }{1\\mp \\text{tan}\\,\\alpha \\,\\text{tan}\\,\\beta }$$<\/li>\n<li>$$\\text{sin}\\,2\\theta =2\\text{sin}\\,\\theta \\,\\text{cos}\\,\\theta $$<\/li>\n<li>$$\\text{cos}\\,2\\theta ={\\text{cos}}^{2}\\,\\theta -{\\text{sin}}^{2}\\,\\theta =2\\,{\\text{cos}}^{2}\\,\\theta -1=1-2\\,{\\text{sin}}^{2}\\,\\theta $$<\/li>\n<li>$$\\text{sin}\\,\\alpha +\\text{sin}\\,\\beta =2\\,\\text{sin}\\frac{1}{2}(\\alpha +\\beta )\\text{cos}\\frac{1}{2}(\\alpha -\\beta )$$<\/li>\n<li>$$\\text{cos}\\,\\alpha +\\text{cos}\\,\\beta =2\\,\\text{cos}\\frac{1}{2}(\\alpha +\\beta )\\text{cos}\\frac{1}{2}(\\alpha -\\beta )$$<\/li>\n<\/ol>\n<p id=\"fs-id1171241012787\"><em>Triangles<\/em><\/p>\n<ol id=\"fs-id1171241129165\" type=\"1\">\n<li>Law of sines: $$ \\frac{a}{\\text{sin}\\,\\alpha }=\\frac{b}{\\text{sin}\\,\\beta }=\\frac{c}{\\text{sin}\\,\\gamma }$$<\/li>\n<li>Law of cosines: $$ {c}^{2}={a}^{2}+{b}^{2}-2ab\\,\\text{cos}\\,\\gamma $$\n<p><span id=\"fs-id1171241119734\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2952\/2018\/01\/31202216\/CNX_UPhysics_00_EE_Triangle1_img.jpg\" alt=\"Figure shows a triangle with three dissimilar sides labeled a, b and c. All three angles of the triangle are acute angles. The angle between b and c is alpha, the angle between a and c is beta and the angle between a and b is gamma.\" \/><\/span><\/p>\n<\/li>\n<li>Pythagorean theorem: $$ {a}^{2}+{b}^{2}={c}^{2}$$\n<p><span id=\"fs-id1171241024569\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/2952\/2018\/01\/31202220\/CNX_UPhysics_00_EE_Triangle2_img.jpg\" alt=\"Figure shows a right triangle. Its three sides are labeled a, b and c with c being the hypotenuse. The angle between a and c is labeled theta.\" \/><\/span><\/p>\n<\/li>\n<\/ol>\n<p id=\"fs-id1171241190802\"><strong>Series expansions<\/strong><\/p>\n<ol id=\"fs-id1171241016910\" type=\"1\">\n<li>Binomial theorem: $$ {(a+b)}^{n}={a}^{n}+n{a}^{n-1}b+\\frac{n(n-1){a}^{n-2}{b}^{2}}{2\\text{!}}+\\frac{n(n-1)(n-2){a}^{n-3}{b}^{3}}{3\\text{!}}+\\text{\u00b7\u00b7\u00b7}$$<\/li>\n<li>$${(1\u00b1x)}^{n}=1\u00b1\\frac{nx}{1\\text{!}}+\\frac{n(n-1){x}^{2}}{2\\text{!}}\u00b1\\text{\u00b7\u00b7\u00b7}({x}^{2}&lt;1)$$<\/li>\n<li>$${(1\u00b1x)}^{\\text{\u2212}n}=1\\mp \\frac{nx}{1\\text{!}}+\\frac{n(n+1){x}^{2}}{2\\text{!}}\\mp \\text{\u00b7\u00b7\u00b7}({x}^{2}&lt;1)$$<\/li>\n<li>$$\\text{sin}\\,x=x-\\frac{{x}^{3}}{3\\text{!}}+\\frac{{x}^{5}}{5\\text{!}}-\\text{\u00b7\u00b7\u00b7}$$<\/li>\n<li>$$\\text{cos}\\,x=1-\\frac{{x}^{2}}{2\\text{!}}+\\frac{{x}^{4}}{4\\text{!}}-\\text{\u00b7\u00b7\u00b7}$$<\/li>\n<li>$$\\text{tan}\\,x=x+\\frac{{x}^{3}}{3}+\\frac{2{x}^{5}}{15}+\\text{\u00b7\u00b7\u00b7}$$<\/li>\n<li>$${e}^{x}=1+x+\\frac{{x}^{2}}{2\\text{!}}+\\text{\u00b7\u00b7\u00b7}$$<\/li>\n<li>$$\\text{ln}(1+x)=x-\\frac{1}{2}{x}^{2}+\\frac{1}{3}{x}^{3}-\\text{\u00b7\u00b7\u00b7}(|x|&lt;1)$$<\/li>\n<\/ol>\n<p id=\"fs-id1171241003878\"><strong>Derivatives<\/strong><\/p>\n<ol id=\"fs-id1171241165751\" type=\"1\">\n<li>$$\\frac{d}{dx}[af(x)]=a\\frac{d}{dx}f(x)$$<\/li>\n<li>$$\\frac{d}{dx}[f(x)+g(x)]=\\frac{d}{dx}f(x)+\\frac{d}{dx}g(x)$$<\/li>\n<li>$$\\frac{d}{dx}[f(x)g(x)]=f(x)\\frac{d}{dx}g(x)+g(x)\\frac{d}{dx}f(x)$$<\/li>\n<li>$$\\frac{d}{dx}f(u)=[\\frac{d}{du}f(u)]\\frac{du}{dx}$$<\/li>\n<li>$$\\frac{d}{dx}{x}^{m}=m{x}^{m-1}$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{sin}\\,x=\\text{cos}\\,x$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{cos}\\,x=\\text{\u2212}\\text{sin}\\,x$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{tan}\\,x={\\text{sec}}^{2}\\,x$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{cot}\\,x=\\text{\u2212}{\\text{csc}}^{2}\\,x$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{sec}\\,x=\\text{tan}\\,x\\,\\text{sec}\\,x$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{csc}\\,x=\\text{\u2212}\\text{cot}\\,x\\,\\text{csc}\\,x$$<\/li>\n<li>$$\\frac{d}{dx}{e}^{x}={e}^{x}$$<\/li>\n<li>$$\\frac{d}{dx}\\,\\text{ln}\\,x=\\frac{1}{x}$$<\/li>\n<li>$$\\frac{d}{dx}\\,{\\text{sin}}^{-1}\\,x=\\frac{1}{\\sqrt{1-{x}^{2}}}$$<\/li>\n<li>$$\\frac{d}{dx}\\,{\\text{cos}}^{-1}x=-\\frac{1}{\\sqrt{1-{x}^{2}}}$$<\/li>\n<li>$$\\frac{d}{dx}\\,{\\text{tan}}^{-1}x=-\\frac{1}{1+{x}^{2}}$$<\/li>\n<\/ol>\n<p id=\"fs-id1171241165019\"><strong>Integrals<\/strong><\/p>\n<ol id=\"fs-id1171241242695\" type=\"1\">\n<li>$$\\int af(x)dx=a\\int f(x)dx$$<\/li>\n<li>$$\\int [f(x)+g(x)]dx=\\int f(x)dx+\\int g(x)dx$$<\/li>\n<li>$$\\begin{array}{cc}\\hfill \\int {x}^{m}dx&amp; =\\frac{{x}^{m+1}}{m+1}\\,(m\\ne \\text{\u2212}1)\\hfill \\\\ &amp; =\\text{ln}\\,x(m=-1)\\hfill \\end{array}$$<\/li>\n<li>$$\\int \\text{sin}\\,x\\,dx=\\text{\u2212}\\text{cos}\\,x$$<\/li>\n<li>$$\\int \\text{cos}\\,x\\,dx=\\text{sin}\\,x$$<\/li>\n<li>$$\\int \\text{tan}\\,x\\,dx=\\text{ln}|\\text{sec}\\,x|$$<\/li>\n<li>$$\\int {\\text{sin}}^{2}\\,ax\\,dx=\\frac{x}{2}-\\frac{\\text{sin}\\,2ax}{4a}$$<\/li>\n<li>$$\\int {\\text{cos}}^{2}\\,ax\\,dx=\\frac{x}{2}+\\frac{\\text{sin}\\,2ax}{4a}$$<\/li>\n<li>$$\\int \\text{sin}\\,ax\\,\\text{cos}\\,ax\\,dx=-\\frac{\\text{cos}2ax}{4a}$$<\/li>\n<li>$$\\int {e}^{ax}\\,dx=\\frac{1}{a}{e}^{ax}$$<\/li>\n<li>$$\\int x{e}^{ax}dx=\\frac{{e}^{ax}}{{a}^{2}}(ax-1)$$<\/li>\n<li>$$\\int \\text{ln}\\,ax\\,dx=x\\,\\text{ln}\\,ax-x$$<\/li>\n<li>$$\\int \\frac{dx}{{a}^{2}+{x}^{2}}=\\frac{1}{a}\\,{\\text{tan}}^{-1}\\frac{x}{a}$$<\/li>\n<li>$$\\int \\frac{dx}{{a}^{2}-{x}^{2}}=\\frac{1}{2a}\\,\\text{ln}|\\frac{x+a}{x-a}|$$<\/li>\n<li>$$\\int \\frac{dx}{\\sqrt{{a}^{2}+{x}^{2}}}={\\text{sinh}}^{-1}\\frac{x}{a}$$<\/li>\n<li>$$\\int \\frac{dx}{\\sqrt{{a}^{2}-{x}^{2}}}={\\text{sin}}^{-1}\\frac{x}{a}$$<\/li>\n<li>$$\\int \\sqrt{{a}^{2}+{x}^{2}}\\,dx=\\frac{x}{2}\\sqrt{{a}^{2}+{x}^{2}}+\\frac{{a}^{2}}{2}\\,{\\text{sinh}}^{-1}\\frac{x}{a}$$<\/li>\n<li>$$\\int \\sqrt{{a}^{2}-{x}^{2}}\\,dx=\\frac{x}{2}\\sqrt{{a}^{2}-{x}^{2}}+\\frac{{a}^{2}}{2}\\,{\\text{sin}}^{-1}\\frac{x}{a}$$<\/li>\n<\/ol>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1373\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>OpenStax University Physics. <strong>Authored by<\/strong>: OpenStax CNX. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/cnx.org\/contents\/1Q9uMg_a@10.16:Gofkr9Oy@15\">https:\/\/cnx.org\/contents\/1Q9uMg_a@10.16:Gofkr9Oy@15<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download for free at http:\/\/cnx.org\/contents\/d50f6e32-0fda-46ef-a362-9bd36ca7c97d@10.16<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":311,"menu_order":5,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"OpenStax University Physics\",\"author\":\"OpenStax CNX\",\"organization\":\"\",\"url\":\"https:\/\/cnx.org\/contents\/1Q9uMg_a@10.16:Gofkr9Oy@15\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download for free at http:\/\/cnx.org\/contents\/d50f6e32-0fda-46ef-a362-9bd36ca7c97d@10.16\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":"all-rights-reserved"},"back-matter-type":[],"contributor":[],"license":[56],"class_list":["post-1373","back-matter","type-back-matter","status-publish","hentry","license-all-rights-reserved"],"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/wp-json\/pressbooks\/v2\/back-matter\/1373","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/wp-json\/pressbooks\/v2\/back-matter"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/wp-json\/wp\/v2\/types\/back-matter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/wp-json\/wp\/v2\/users\/311"}],"version-history":[{"count":1,"href":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/wp-json\/pressbooks\/v2\/back-matter\/1373\/revisions"}],"predecessor-version":[{"id":2089,"href":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/wp-json\/pressbooks\/v2\/back-matter\/1373\/revisions\/2089"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/wp-json\/pressbooks\/v2\/back-matter\/1373\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/wp-json\/wp\/v2\/media?parent=1373"}],"wp:term":[{"taxonomy":"back-matter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/wp-json\/pressbooks\/v2\/back-matter-type?post=1373"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/wp-json\/wp\/v2\/contributor?post=1373"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/wp-json\/wp\/v2\/license?post=1373"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}