{"id":1428,"date":"2018-02-06T16:27:00","date_gmt":"2018-02-06T16:27:00","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/?post_type=chapter&p=1428"},"modified":"2018-02-28T16:12:16","modified_gmt":"2018-02-28T16:12:16","slug":"7-chapter-review","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-osuniversityphysics\/chapter\/7-chapter-review\/","title":{"raw":"7 Chapter Review","rendered":"7 Chapter Review"},"content":{"raw":"
\r\n
\r\n
\r\n

Key Terms<\/span><\/h3>\r\n
\r\n \t
average power<\/strong><\/dt>\r\n \t
work done in a time interval divided by the time interval<\/dd>\r\n<\/dl>\r\n
\r\n \t
kinetic energy<\/strong><\/dt>\r\n \t
energy of motion, one-half an object\u2019s mass times the square of its speed<\/dd>\r\n<\/dl>\r\n
\r\n \t
net work<\/strong><\/dt>\r\n \t
work done by all the forces acting on an object<\/dd>\r\n<\/dl>\r\n
\r\n \t
power<\/strong><\/dt>\r\n \t
(or instantaneous power) rate of doing work<\/dd>\r\n<\/dl>\r\n
\r\n \t
work<\/strong><\/dt>\r\n \t
done when a force acts on something that undergoes a displacement from one position to another<\/dd>\r\n<\/dl>\r\n
\r\n \t
work done by a force<\/strong><\/dt>\r\n \t
integral, from the initial position to the final position, of the dot product of the force and the infinitesimal displacement along the path over which the force acts<\/dd>\r\n<\/dl>\r\n
\r\n \t
work-energy theorem<\/strong><\/dt>\r\n \t
net work done on a particle is equal to the change in its kinetic energy<\/dd>\r\n<\/dl>\r\n<\/div>\r\n<\/div>\r\n
\r\n
\r\n

Key Equations<\/h3>\r\n<\/div>\r\n
\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n
Work done by a force over an infinitesimal displacement<\/td>\r\nd<\/span>W<\/span>=<\/span>F<\/span><\/span><\/span>\u20d7\u00a0<\/span><\/span>\u00b7<\/span>d<\/span>r<\/span><\/span><\/span>\u20d7\u00a0<\/span><\/span>=<\/span>\u2223\u2223<\/span>F<\/span><\/span><\/span>\u20d7\u00a0<\/span><\/span><\/span>\u2223\u2223<\/span><\/span>\u2223\u2223<\/span>d<\/span>r<\/span><\/span><\/span>\u20d7\u00a0<\/span><\/span><\/span>\u2223\u2223<\/span><\/span>cos<\/span><\/span>\u03b8<\/span><\/span><\/span><\/span><\/span><\/span>dW=F\u2192\u00b7dr\u2192=|F\u2192||dr\u2192|cos\u03b8<\/span><\/span><\/td>\r\n<\/tr>\r\n
Work done by a force acting along a path from\u00a0A<\/em>\u00a0to\u00a0B<\/em><\/td>\r\nW<\/span>A<\/span>B<\/span><\/span><\/span>=<\/span>\u222b<\/span>path<\/span>A<\/span>B<\/span><\/span><\/span>F<\/span>\u20d7\u00a0<\/span><\/span><\/span><\/span>\u00b7<\/span>d<\/span>r<\/span>\u20d7\u00a0<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>WAB=\u222bpathABF\u2192\u00b7dr\u2192<\/span><\/span><\/td>\r\n<\/tr>\r\n
Work done by a constant force of kinetic friction<\/td>\r\nW<\/span>fr<\/span><\/span><\/span>=<\/span>\u2212<\/span>f<\/span>k<\/span><\/span>\u2223\u2223<\/span>l<\/span>A<\/span>B<\/span><\/span><\/span><\/span>\u2223\u2223<\/span><\/span><\/span><\/span><\/span><\/span><\/span>Wfr=\u2212fk|lAB|<\/span><\/span><\/td>\r\n<\/tr>\r\n
Work done going from\u00a0A<\/em>\u00a0to\u00a0B<\/em>\u00a0by Earth\u2019s gravity, near its surface<\/td>\r\nW<\/span>grav,<\/span>A<\/span>B<\/span><\/span><\/span>=<\/span>\u2212<\/span>m<\/span>g<\/span>(<\/span>y<\/span>B<\/span><\/span>\u2212<\/span>y<\/span>A<\/span><\/span><\/span>)<\/span><\/span><\/span><\/span><\/span><\/span><\/span>Wgrav,AB=\u2212mg(yB\u2212yA)<\/span><\/span><\/td>\r\n<\/tr>\r\n
Work done going from\u00a0A<\/em>\u00a0to\u00a0B<\/em>\u00a0by one-dimensional spring force<\/td>\r\nW<\/span>spring,<\/span>A<\/span>B<\/span><\/span><\/span>=<\/span>\u2212<\/span>(<\/span>1<\/span>2<\/span><\/span>k<\/span><\/span>)<\/span><\/span>(<\/span>x<\/span>2<\/span>B<\/span><\/span>\u2212<\/span>x<\/span>2<\/span>A<\/span><\/span><\/span>)<\/span><\/span><\/span><\/span><\/span><\/span><\/span>Wspring,AB=\u2212(12k)(xB2\u2212xA2)<\/span><\/span><\/td>\r\n<\/tr>\r\n
Kinetic energy of a non-relativistic particle<\/td>\r\nK<\/span>=<\/span>1<\/span>2<\/span><\/span>m<\/span>v<\/span>2<\/span><\/span>=<\/span>p<\/span>2<\/span><\/span><\/span>2<\/span>m<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>K=12mv2=p22m<\/span><\/span><\/td>\r\n<\/tr>\r\n
Work-energy theorem<\/td>\r\nW<\/span>net<\/span><\/span><\/span>=<\/span>K<\/span>B<\/span><\/span>\u2212<\/span>K<\/span>A<\/span><\/span><\/span><\/span><\/span><\/span><\/span>Wnet=KB\u2212KA<\/span><\/span><\/td>\r\n<\/tr>\r\n
Power as rate of doing work<\/td>\r\nP<\/span>=<\/span>d<\/span>W<\/span><\/span>d<\/span>t<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>P=dWdt<\/span><\/span><\/td>\r\n<\/tr>\r\n
Power as the dot product of force and velocity<\/td>\r\nP<\/span>=<\/span>F<\/span>\u20d7\u00a0<\/span><\/span><\/span><\/span>\u00b7<\/span>v<\/span>\u20d7\u00a0<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/span>P=F\u2192\u00b7v\u2192<\/span><\/span><\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/section><\/div>\r\n<\/div>\r\n<\/div>\r\n
<\/div>\r\n
\r\n
\r\n

Summary<\/span><\/h3>\r\n
\r\n
\r\n

7.1<\/span>\u00a0<\/span>Work<\/span><\/h4>\r\n