{"id":3296,"date":"2018-07-04T13:42:16","date_gmt":"2018-07-04T13:42:16","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/?post_type=chapter&#038;p=3296"},"modified":"2020-06-24T02:07:42","modified_gmt":"2020-06-24T02:07:42","slug":"10-5-simple-addition-to-alkynes","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/chapter\/10-5-simple-addition-to-alkynes\/","title":{"raw":"10.5. Simple addition to alkynes","rendered":"10.5. Simple addition to alkynes"},"content":{"raw":"Addition of strong acids to alkynes is quite similar to the addition of strong acids to alkenes. The regiochemistry follows <em style=\"font-size: 16px\">Markovnikov\u2019s Rule<\/em><span style=\"font-size: 16px\">, but the stereochemistry is often different. Addition to alkenes is usually not stereospecific, whereas alkynes usually undergo <\/span><em style=\"font-size: 16px\">anti <\/em><span style=\"font-size: 16px\">addition.<\/span>\r\n\r\n<section class=\"mt-content-container\">\r\n<div id=\"s916\" class=\"mt-include\">\r\n<div class=\"mt-section\">\r\n\r\nNow we will take a look at electrophilic addition reactions, particularly of alkynes. The reaction mechanisms, as you will notice, are quite similar to the electrophilic addition reactions of alkenes. The triple bonds of alkynes, because of its high electron density, are easily attacked by electrophiles, but are less reactive than alkenes due to the compact C-C electron cloud.As with <a class=\"internal mt-disabled\" title=\"Wikitexts\/UCD Chem 118B\/Chem 118B Topics\/Electrophilic Addition of Halogens to Alkenes\" rel=\"broken\">electrophilic addition to unsymmetrical alkenes<\/a>, the Markovnikov rule is followed, adding the electrophile to the less substituted carbon.\r\n\r\nFor simplicity, we will show the mechanism going via a vinyl carbocation, by analogy with the alkyl carbocation formed when alkenes react.\u00a0 In fact, the vinyl carbocation is usually to unstable to be a real intermediate; the actual intermediate is more like a complex of the electrophile with the alkyne, which begins to place a partial positive charge on the nearby carbon.\r\n\r\nHere we will go through the following reactions listed below to learn the mechanisms behind these electrophilic additions of alkynes: (1) HX Addition to <a class=\"internal\" title=\"Organic Chemistry\/Hydrocarbons\/Alkenes\" href=\"https:\/\/chem.libretexts.org\/Core\/Organic_Chemistry\/Hydrocarbons\/Alkenes\" rel=\"internal\">alkenes<\/a>, (2) Halogenation of <a class=\"internal\" title=\"Organic Chemistry\/Hydrocarbons\/Alkynes\" href=\"https:\/\/chem.libretexts.org\/Core\/Organic_Chemistry\/Hydrocarbons\/Alkynes\" rel=\"internal\">alkynes<\/a> and (3) Hydration of alkynes.\r\n\r\n<strong>Figure\r\n<\/strong>\r\n\r\n<strong><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/06\/22200636\/Alkene_Alkyne_1.jpg\" alt=\"Alkene_Alkyne (1).JPG\" width=\"694\" height=\"336\" \/><\/strong>\r\n\r\nThe addition of an electrophile to either an alkene or an alkyne will undergo the same steps listed below.\r\n<ol>\r\n \t<li>Start with a reactant (either an alkene or an alkyne), which has\u00a0\u03c0 electrons. An electron pair moves from the \u03c0 bond to the electrophilic proton to form a new covalent bond this is the electrophilic addition elementary step. A carbocation intermediate forms on the more stable carbon.\u00a0As shown in the diagram above, the intermediate consists of hydrogen covalently bonded to the carbon and a positive charge on the other carbon.<\/li>\r\n \t<li>The addition of the halide ion to the positive charged intermediate forms the second covalent bond giving you the haloalkane product (as seen on the left of the above diagram) and a haloalkene product (as seen on the right of the above diagram). The halide ion acts as a nucleophile, which is attracted to the positive charged carbon because it has electrons to donate or share. So when the nucleophilic halide (represented as X<sup>-<\/sup>) attacks, it aims for the positively charged carbon resulting in that second covalent bond as seen above.<\/li>\r\n<\/ol>\r\nMake Note: The way to determine where the addition of the proton and the halide takes place is based on Markovnikov\u2019s Rule, which states that the proton adds onto the carbon with the most hydrogens and the halogen prefers the most substituted carbon.\r\n\r\nNow let's take a look at our first reaction, the addition of Hydrogen Halide.\r\n\r\n<\/div>\r\n<div class=\"mt-section\">\r\n<h3 id=\"Reaction_1:__Addition_of_Hydrogen_Halide_to_an_Alkyne-916\">Reaction 1:\u00a0 Addition of hydrogen halide to an alkyne<\/h3>\r\n<strong>Summary:<\/strong>\u00a0 Reactivity order of <strong><span class=\"internal\">hydrogen halides<\/span><strong>: HI &gt; HBr &gt; HCl &gt; HF.<\/strong><\/strong>\r\n\r\nFollows Markovnikov\u2019s rule:\r\n<ul>\r\n \t<li>Hydrogen adds to the carbon with the greatest number of hydrogens, the halogen adds to the carbon with fewer hydrogens.<\/li>\r\n \t<li>Protonation occurs on the more stable carbocation. With the addition of HX, haloalkenes form.<\/li>\r\n \t<li>With the addition of excess HX, you get <em>anti <\/em>addition forming a geminal dihaloalkane.<\/li>\r\n<\/ul>\r\n<div class=\"mt-section\">\r\n<h4 id=\"Addition_of_a_HX_to_an_Internal_Alkyne-916\">Addition of a HX to an internal alkyne<\/h4>\r\nAs described in Figure 1, the\u00a0\u03c0 electrons will attack the hydrogen of the HBr and because this is a symmetric molecule it will add to either carbon at a roughly equal rate.\u00a0\u00a0 Once the hydrogen is covalently bonded to one of the carbons, you will get a carbocation intermediate (not shown, but will look the same as depicted in the figure above) on the other carbon.\r\n\r\nThe final step is the addition of the bromide, which is a good nucleophile because it has electrons to donate or share.\u00a0 Bromide, therefore, attacks the carbocation intermediate placing the Br on that carbon. As a result, you get 2-bromobutene from your 2-butyne reactant, as shown below.\r\n\r\nFigure 2\r\n\r\n<img class=\"wp-image-5021 alignleft\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/06141601\/AlkyneSingleHBrAddition.png\" alt=\"Addition of one HBr to an internal alkene, giving a vinyl bromide\" width=\"271\" height=\"111\" \/>\r\n\r\n&nbsp;\r\n\r\n&nbsp;\r\n\r\n&nbsp;\r\n\r\nNow, what if you have excess HBr?\r\n\r\n<\/div>\r\n<div class=\"mt-section\">\r\n<h4 id=\"Addition_due_to_excess_HX_present_.3F_yields_a_geminal_dihaloalkane-916\">Addition due to excess HX present yields a geminal dihaloalkane<\/h4>\r\nFigure 3\r\n\r\n<img class=\"wp-image-5019 alignleft\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2020\/06\/06133141\/AlkyneHBrAddition.png\" alt=\"Addition of 1 HBr and 2 HBr to but-t-yne\" width=\"465\" height=\"115\" \/>\r\n\r\n&nbsp;\r\n\r\n&nbsp;\r\n\r\n&nbsp;\r\n\r\nHere, the electrophilic addition proceeds with the same steps used to achieve the product in addition of a HX to an internal alkyne.\u00a0 The\u00a0\u03c0 electrons attacked the hydrogen, adding it to the carbon on the left (shown in blue). The hydrogen is added to the left hand carbon forming a carbocation on the carbon with the Br, since this is stabilized by <a href=\"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/chapter\/6-2-resonance\/\">type III resonance<\/a>.\u00a0 Then the carbocation intermediate is attacked by the bromide resulting in a dihaloalkane product.\r\n\r\n<\/div>\r\n<div class=\"mt-section\">\r\n<h4 id=\"Addition_of_HX_to_Terminal_Alkyne-916\">Addition of HX to Terminal Alkyne<\/h4>\r\n<ul>\r\n \t<li>Here is an addition of HBr to an asymmetric molecule.<\/li>\r\n \t<li>First, try to make sense of how the reactant went to product and then take a look at the mechanism.<\/li>\r\n<\/ul>\r\n<strong><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2201\/Figure4.1.bmp?revision=1&amp;size=bestfit&amp;width=463&amp;height=252#fixme#fixme\" alt=\"Figure4.1.bmp\" width=\"463\" height=\"252\" \/><\/strong>\r\n\r\nThe\u00a0\u03c0 electrons are attacking the hydrogen, depicted by the electron pushing arrows and the bromine gains a negative charge.\u00a0 The carbocation intermediate forms a positive charge on the left carbon after the hydrogen was added to the carbon with the most hydrogen substituents.\r\n\r\n<strong>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2202\/Figure4.2.bmp?revision=1&amp;size=bestfit&amp;width=325&amp;height=100#fixme#fixme\" alt=\"Figure4.2.bmp\" width=\"325\" height=\"100\" \/>\u00a0\u00a0\u00a0<\/strong>\r\n\r\nThe bromine, which now exists as bromide with a negative charge, attacks the positively charged carbocation forming the final product with the nucleophile (Br) on the more substituted carbon.\r\n\r\n<\/div>\r\n<div class=\"mt-section\">\r\n<h4 id=\"Addition_due_to_excess_HBr_present-916\">Addition with excess HBr present<\/h4>\r\n<img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2205\/Figure5.bmp?revision=1&amp;size=bestfit&amp;width=515&amp;height=146#fixme#fixme\" alt=\"Figure5.bmp\" width=\"515\" height=\"146\" \/>\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"mt-section\">\r\n\r\n&nbsp;\r\n<h3 id=\"Reaction:__Halogenation_of_Alkynes-916\"><strong>Reaction:\u00a0 Halogenation of Alkynes<\/strong><\/h3>\r\n<strong>\u00a0Summary:<\/strong>\r\n\r\n<img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/06\/22200638\/Halogenation_of_Alynes_1.jpg\" alt=\"Halogenation of Alynes (1).JPG\" width=\"355\" height=\"80\" \/>\r\n<ul>\r\n \t<li>Stereoselectivity: anti addition<\/li>\r\n \t<li>Reaction proceeds via cyclic halonium ion<\/li>\r\n<\/ul>\r\n<div class=\"mt-section\">\r\n<h4 id=\"Addition_of_Br2-916\"><strong>Addition of <\/strong><strong>Br<\/strong><sub><strong>2<\/strong><\/sub><\/h4>\r\n<ul>\r\n \t<li>The addition of Br<sub>2<\/sub> to an alkyne is analogous to adding Br<sub>2<\/sub> to an alkene.<\/li>\r\n \t<li>Once Br<sub>2<\/sub> approaches the nucleophilic alkyne, it becomes polarized.<\/li>\r\n \t<li>The\u00a0\u03c0 electrons, from the triple bond, can now attack the polarized bromine forming a C-Br bond and displacing the bromide ion.<\/li>\r\n \t<li>Now, you will get an intermediate bromonium ion, which will immediately react with the bromide ion giving you the dibromo product.<\/li>\r\n<\/ul>\r\n<img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2207\/Figure6.bmp?revision=1&amp;size=bestfit&amp;width=465&amp;height=415#fixme#fixme\" alt=\"Figure6.bmp\" width=\"465\" height=\"415\" \/>\r\n\r\nFirst, you see the polarized Br<sub>2<\/sub> being attacked by the\u00a0\u03c0 electrons.\u00a0 Once you form the C-Br bond, the other bromine is released as a bromine ion.\u00a0 The intermediate here is a bromonium ion, which is electrophilic and reacts with the bromine ion giving you the dibromo product.\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_9\" class=\"mt-section\">\r\n<h3 id=\"Reaction:__Hydration_of_Alkynes-916\"><strong>Reaction:\u00a0 Hydration of Alkynes<\/strong><\/h3>\r\n<strong>Summary:\u00a0 <\/strong>With the addition of water, alkynes can be hydrated to form enols that spontaneously tautomerize to ketones. Reaction is catalyzed by mercury ions. Follows Markovnikov\u2019s Rule: Terminal alkynes give methyl ketones.\r\n\r\n<strong>Figure 7<\/strong>\r\n\r\n<\/div>\r\n<img class=\"alignnone wp-image-5028\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/07023616\/But1yneMvHydration.png\" alt=\"But=1-yne adds H2O in presence of H2SO4\/HgSO4 to form an enol, and then butanone\" width=\"527\" height=\"144\" \/>\r\n<div id=\"section_9\" class=\"mt-section\">\r\n<ul>\r\n \t<li>The first step is an acid\/base reaction where the\u00a0\u03c0 electrons of the triple bond act as a Lewis base and attack the proton, protonating the carbon that has more hydrogens.\u00a0 (Electrophilic addition)<\/li>\r\n \t<li>The second step is the attack of the nucleophilic water molecule on the electrophilic carbocation, which creates an oxonium ion.\u00a0 (Coordination)<\/li>\r\n \t<li>Next, the positively charged oxygen is deprotonated by water (which is acting as a base), generating an C=C bonded alcohol called an enol.\u00a0 (Acid-base)<\/li>\r\n \t<li>The enol then tautomerizes into a ketone, via a mechanism that will be covered in <a href=\"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/\">part 2 of this textbook<\/a>.\u00a0 Tautomerization is a simultaneous proton and double bond shift, which goes from the enol form to the keto isomer form as shown above in Figure 7.<\/li>\r\n<\/ul>\r\nNow let's look at some examples of hydration Reactions.\r\n<div id=\"section_10\" class=\"mt-section\">\r\n<h4 id=\"Hydration_of_Terminal_Alkyne_produces_methyl_ketones-916\">Hydration of terminal alkyne produces methyl ketones<\/h4>\r\n<strong><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2210\/Figure8.bmp?revision=1&amp;size=bestfit&amp;width=462&amp;height=224#fixme#fixme\" alt=\"Figure8.bmp\" width=\"462\" height=\"224\" \/><\/strong>\r\n\r\nJust as described in Figure 7 the\u00a0\u03c0 electrons will attack a proton, forming a carbocation, which then gets attacked by the nucleophilic water molecules.\u00a0 After deprotonation, we generate an enol, which then tautomerizes into the ketone form shown.\r\n\r\n<\/div>\r\n<div id=\"section_11\" class=\"mt-section\">\r\n<h4 id=\"Hydration_of_Alkyne-916\">Hydration of but-1-yne<\/h4>\r\nThe\u00a0\u03c0 electrons of the triple bond attack the proton, which forms a covalent bond on the carbon with the most hydrogen substituents. This forms a carbocation, which is then attacked by the water molecule via a coordination step. This produces a positive charge on the oxygen, so another molecule of water is needed as a base to deprotonate the molecule and give a neutral product. The resultant enol is unstable, and it rapidly tautomerizes to the ketone (butanone).\r\n\r\n<\/div>\r\n<strong>Figure 9\r\n<\/strong>\r\n\r\n<img class=\"alignnone wp-image-5027\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/07023403\/But2yneMvHydration.png\" alt=\"But-2-yne adds H2O in presence of H2SO4 to form an enol, and then butanone\" width=\"524\" height=\"154\" \/>\r\n<div id=\"section_11\" class=\"mt-section\">\r\n\r\nOutside links\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_12\" class=\"mt-section\">\r\n<ul>\r\n \t<li><a title=\"http:\/\/www.cem.msu.edu\/~reusch\/VirtualText\/addyne1.htm\" href=\"http:\/\/www.cem.msu.edu\/~reusch\/VirtualText\/addyne1.htm\" target=\"_blank\" rel=\"external nofollow noopener\">http:\/\/www.cem.msu.edu\/~reusch\/VirtualText\/addyne1.htm<\/a><\/li>\r\n<\/ul>\r\n<img class=\"size-thumbnail wp-image-4675 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/01173315\/static_qr_code_without_logo6-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/>\r\n<ul>\r\n \t<li><a title=\"http:\/\/wikipremed.com\/03_organicmechanisms.php?mch_code=030203_010\" href=\"http:\/\/wikipremed.com\/03_organicmechanisms.php?mch_code=030203_010\" target=\"_blank\" rel=\"external nofollow noopener\">http:\/\/wikipremed.com\/03_organicmechanisms.php?mch_code=030203_010<\/a><\/li>\r\n<\/ul>\r\n<\/div>\r\n<div id=\"section_13\" class=\"mt-section\">\r\n<h3 id=\"References-916\">References<\/h3>\r\n<ol>\r\n \t<li>Vollhardt. Schore, Organic Chemistry Structure and Function Fifth Edition, New York: W.H. Freeman and Company, 2007.<\/li>\r\n \t<li>Solomons, T. W. Graham, and Craig B. Fryhle. Organic Chemistry Eighth Edition. Maryland: John Wiley and Sons Incorporated, 2008.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div id=\"section_14\" class=\"mt-section textbox exercises\">\r\n<h3 id=\"Practice_Problems-916\">Practice Problems<\/h3>\r\n<strong>1) Reaction:\u00a0 Addition of hydrogen halide to an alkyne<\/strong>\r\n\r\n<strong>1a)<\/strong>\u00a0 What product would result from the reaction of 1-pentyne with hydrogen bromide?\r\n\r\n<img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2222\/Practiceproblem1a.bmp?revision=1&amp;size=bestfit&amp;width=349&amp;height=100#fixme#fixme\" alt=\"Practiceproblem1a.bmp\" width=\"349\" height=\"100\" \/>\r\n\r\n<strong>1b)<\/strong>\u00a0 Take your answer from 1a and add an excess of hydrogen bromide.\u00a0 What would be the product?\r\n\r\n<img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2223\/Practiceproblem1b.bmp?revision=1&amp;size=bestfit&amp;width=200&amp;height=60#fixme#fixme\" alt=\"Practiceproblem1b.bmp\" width=\"200\" height=\"60\" \/>\r\n\r\n<strong>1c)<\/strong>\u00a0\u00a0 What is the mechanism for this reaction?\r\n\r\n<strong>2) Reaction:\u00a0 Addition of X<sub>2<\/sub> to alkynes<\/strong>\r\n\r\n<strong>2a)<\/strong>\u00a0 What product would result from the reaction of 1-pentyne with Br<sub>2<\/sub>?\r\n\r\n<img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2224\/Practiceproblem2a_(1).bmp?revision=1&amp;size=bestfit&amp;width=382&amp;height=74#fixme#fixme\" alt=\"Practiceproblem2a (1).bmp\" width=\"382\" height=\"74\" \/>\r\n\r\n<strong>2b)<\/strong>\u00a0 Take your answer from 2a and add an excess of Br<sub>2<\/sub>.\u00a0 What would be the product?\r\n\r\n<img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2223\/Practiceproblem1b.bmp?revision=1&amp;size=bestfit&amp;width=200&amp;height=60#fixme#fixme\" alt=\"Practiceproblem1b.bmp\" width=\"200\" height=\"60\" \/>\r\n\r\n<strong>2c)<\/strong>\u00a0\u00a0 What is the mechanism for this reaction?\r\n\r\n<strong>3) Reaction:\u00a0 Hydration of alkynes<\/strong>\r\n\r\n<strong>3a)<\/strong>\u00a0 If 1-Pentyne were to react with mercury(II) sulfate, water, and sulfuric acid, what would be the product?\r\n\r\n<img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/06\/22200640\/Practice3_1.jpg\" alt=\"Practice3 (1).JPG\" width=\"328\" height=\"90\" \/>\r\n\r\n<strong>4)<\/strong>\u00a0\u00a0 What is the product when 3-methylbutyne reacts with HCl? Include in your answer:\r\na)\u00a0\u00a0\u00a0 the reaction mechanism\r\nb)\u00a0\u00a0\u00a0 a clear explanation for why the hydrogen and chlorine bind to where they do\r\n\r\n<strong>5)<\/strong>\u00a0 a) Draw the enol form of the ketone below.\r\n\r\n<img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/06\/22200642\/Problem5a.jpg\" alt=\"Problem5a.JPG\" width=\"410\" height=\"170\" \/>\r\n\r\nb)\u00a0 Draw the keto form of the enol below.\r\n\r\n<img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/06\/22200644\/Practice5b.jpg\" alt=\"Practice5b.JPG\" width=\"410\" height=\"170\" \/>\r\n\r\n<\/div>\r\n<\/div>\r\n<div class=\"mt-section\">\r\n<div class=\"textbox examples\">\r\n<h3>Further reading<\/h3>\r\n<em>MasterOrganicChemistry<\/em>\r\n<ul>\r\n \t<li><a class=\"external\" title=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/24\/alkyne-reaction-patterns-the-carbocation-pathway\/\" href=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/24\/alkyne-reaction-patterns-the-carbocation-pathway\/\" target=\"_blank\" rel=\"external nofollow noopener\">Alkyne Reactions Patterns - The Carbocation Pathway<\/a><\/li>\r\n<\/ul>\r\n<img class=\"size-thumbnail wp-image-4676 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/01173426\/static_qr_code_without_logo7-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/>\r\n<ul>\r\n \t<li><a class=\"external\" title=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/29\/alkyne-addition-pathways-the-3-membered-ring-pathway\/\" href=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/29\/alkyne-addition-pathways-the-3-membered-ring-pathway\/\" target=\"_blank\" rel=\"external nofollow noopener\">Alkyne Reactions Patterns - The 3-Membered Ring Pathway<\/a><\/li>\r\n<\/ul>\r\n<img class=\"size-thumbnail wp-image-4677 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/01173627\/static_qr_code_without_logo2-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/>\r\n\r\n<em>Carey 5th Ed Online<\/em>\r\n<ul>\r\n \t<li><a class=\"external\" title=\"http:\/\/www.mhhe.com\/physsci\/chemistry\/carey\/student\/olc\/ch09additionreactionsofalkynes.html\" href=\"http:\/\/www.mhhe.com\/physsci\/chemistry\/carey\/student\/olc\/ch09additionreactionsofalkynes.html\" target=\"_blank\" rel=\"external nofollow noopener\">Addition Reactions of Alkynes<\/a><\/li>\r\n<\/ul>\r\n<img class=\"size-thumbnail wp-image-4678 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/01173807\/static_qr_code_without_logo7-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/>\r\n\r\n<\/div>\r\n<em>Videos<\/em>\r\n\r\n<img class=\"alignright size-thumbnail wp-image-4679\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/01174017\/static_qr_code_without_logo3-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/>\r\n\r\n[embed]https:\/\/www.youtube.com\/watch?v=S0ts6VK7Vyk[\/embed]\r\n\r\n<a class=\"link-https\" title=\"https:\/\/www.khanacademy.org\/science\/organic-chemistry\/alkenes-alkynes\/alkyne-reactions\/v\/hydration-of-alkynes\" href=\"https:\/\/www.khanacademy.org\/science\/organic-chemistry\/alkenes-alkynes\/alkyne-reactions\/v\/hydration-of-alkynes\" target=\"_blank\" rel=\"external nofollow noopener\">Hydration of Alkynes<\/a>\r\n\r\n<img class=\"alignright size-thumbnail wp-image-4680\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/01174353\/static_qr_code_without_logo8-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/>\r\n\r\nhttps:\/\/youtu.be\/AE1pkp-_cKE\r\n\r\n<\/div>\r\n<\/section>","rendered":"<p>Addition of strong acids to alkynes is quite similar to the addition of strong acids to alkenes. The regiochemistry follows <em style=\"font-size: 16px\">Markovnikov\u2019s Rule<\/em><span style=\"font-size: 16px\">, but the stereochemistry is often different. Addition to alkenes is usually not stereospecific, whereas alkynes usually undergo <\/span><em style=\"font-size: 16px\">anti <\/em><span style=\"font-size: 16px\">addition.<\/span><\/p>\n<section class=\"mt-content-container\">\n<div id=\"s916\" class=\"mt-include\">\n<div class=\"mt-section\">\n<p>Now we will take a look at electrophilic addition reactions, particularly of alkynes. The reaction mechanisms, as you will notice, are quite similar to the electrophilic addition reactions of alkenes. The triple bonds of alkynes, because of its high electron density, are easily attacked by electrophiles, but are less reactive than alkenes due to the compact C-C electron cloud.As with <a class=\"internal mt-disabled\" title=\"Wikitexts\/UCD Chem 118B\/Chem 118B Topics\/Electrophilic Addition of Halogens to Alkenes\" rel=\"broken\">electrophilic addition to unsymmetrical alkenes<\/a>, the Markovnikov rule is followed, adding the electrophile to the less substituted carbon.<\/p>\n<p>For simplicity, we will show the mechanism going via a vinyl carbocation, by analogy with the alkyl carbocation formed when alkenes react.\u00a0 In fact, the vinyl carbocation is usually to unstable to be a real intermediate; the actual intermediate is more like a complex of the electrophile with the alkyne, which begins to place a partial positive charge on the nearby carbon.<\/p>\n<p>Here we will go through the following reactions listed below to learn the mechanisms behind these electrophilic additions of alkynes: (1) HX Addition to <a class=\"internal\" title=\"Organic Chemistry\/Hydrocarbons\/Alkenes\" href=\"https:\/\/chem.libretexts.org\/Core\/Organic_Chemistry\/Hydrocarbons\/Alkenes\" rel=\"internal\">alkenes<\/a>, (2) Halogenation of <a class=\"internal\" title=\"Organic Chemistry\/Hydrocarbons\/Alkynes\" href=\"https:\/\/chem.libretexts.org\/Core\/Organic_Chemistry\/Hydrocarbons\/Alkynes\" rel=\"internal\">alkynes<\/a> and (3) Hydration of alkynes.<\/p>\n<p><strong>Figure<br \/>\n<\/strong><\/p>\n<p><strong><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/06\/22200636\/Alkene_Alkyne_1.jpg\" alt=\"Alkene_Alkyne (1).JPG\" width=\"694\" height=\"336\" \/><\/strong><\/p>\n<p>The addition of an electrophile to either an alkene or an alkyne will undergo the same steps listed below.<\/p>\n<ol>\n<li>Start with a reactant (either an alkene or an alkyne), which has\u00a0\u03c0 electrons. An electron pair moves from the \u03c0 bond to the electrophilic proton to form a new covalent bond this is the electrophilic addition elementary step. A carbocation intermediate forms on the more stable carbon.\u00a0As shown in the diagram above, the intermediate consists of hydrogen covalently bonded to the carbon and a positive charge on the other carbon.<\/li>\n<li>The addition of the halide ion to the positive charged intermediate forms the second covalent bond giving you the haloalkane product (as seen on the left of the above diagram) and a haloalkene product (as seen on the right of the above diagram). The halide ion acts as a nucleophile, which is attracted to the positive charged carbon because it has electrons to donate or share. So when the nucleophilic halide (represented as X<sup>&#8211;<\/sup>) attacks, it aims for the positively charged carbon resulting in that second covalent bond as seen above.<\/li>\n<\/ol>\n<p>Make Note: The way to determine where the addition of the proton and the halide takes place is based on Markovnikov\u2019s Rule, which states that the proton adds onto the carbon with the most hydrogens and the halogen prefers the most substituted carbon.<\/p>\n<p>Now let&#8217;s take a look at our first reaction, the addition of Hydrogen Halide.<\/p>\n<\/div>\n<div class=\"mt-section\">\n<h3 id=\"Reaction_1:__Addition_of_Hydrogen_Halide_to_an_Alkyne-916\">Reaction 1:\u00a0 Addition of hydrogen halide to an alkyne<\/h3>\n<p><strong>Summary:<\/strong>\u00a0 Reactivity order of <strong><span class=\"internal\">hydrogen halides<\/span><strong>: HI &gt; HBr &gt; HCl &gt; HF.<\/strong><\/strong><\/p>\n<p>Follows Markovnikov\u2019s rule:<\/p>\n<ul>\n<li>Hydrogen adds to the carbon with the greatest number of hydrogens, the halogen adds to the carbon with fewer hydrogens.<\/li>\n<li>Protonation occurs on the more stable carbocation. With the addition of HX, haloalkenes form.<\/li>\n<li>With the addition of excess HX, you get <em>anti <\/em>addition forming a geminal dihaloalkane.<\/li>\n<\/ul>\n<div class=\"mt-section\">\n<h4 id=\"Addition_of_a_HX_to_an_Internal_Alkyne-916\">Addition of a HX to an internal alkyne<\/h4>\n<p>As described in Figure 1, the\u00a0\u03c0 electrons will attack the hydrogen of the HBr and because this is a symmetric molecule it will add to either carbon at a roughly equal rate.\u00a0\u00a0 Once the hydrogen is covalently bonded to one of the carbons, you will get a carbocation intermediate (not shown, but will look the same as depicted in the figure above) on the other carbon.<\/p>\n<p>The final step is the addition of the bromide, which is a good nucleophile because it has electrons to donate or share.\u00a0 Bromide, therefore, attacks the carbocation intermediate placing the Br on that carbon. As a result, you get 2-bromobutene from your 2-butyne reactant, as shown below.<\/p>\n<p>Figure 2<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-5021 alignleft\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/06141601\/AlkyneSingleHBrAddition.png\" alt=\"Addition of one HBr to an internal alkene, giving a vinyl bromide\" width=\"271\" height=\"111\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>Now, what if you have excess HBr?<\/p>\n<\/div>\n<div class=\"mt-section\">\n<h4 id=\"Addition_due_to_excess_HX_present_.3F_yields_a_geminal_dihaloalkane-916\">Addition due to excess HX present yields a geminal dihaloalkane<\/h4>\n<p>Figure 3<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-5019 alignleft\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2020\/06\/06133141\/AlkyneHBrAddition.png\" alt=\"Addition of 1 HBr and 2 HBr to but-t-yne\" width=\"465\" height=\"115\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>Here, the electrophilic addition proceeds with the same steps used to achieve the product in addition of a HX to an internal alkyne.\u00a0 The\u00a0\u03c0 electrons attacked the hydrogen, adding it to the carbon on the left (shown in blue). The hydrogen is added to the left hand carbon forming a carbocation on the carbon with the Br, since this is stabilized by <a href=\"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/chapter\/6-2-resonance\/\">type III resonance<\/a>.\u00a0 Then the carbocation intermediate is attacked by the bromide resulting in a dihaloalkane product.<\/p>\n<\/div>\n<div class=\"mt-section\">\n<h4 id=\"Addition_of_HX_to_Terminal_Alkyne-916\">Addition of HX to Terminal Alkyne<\/h4>\n<ul>\n<li>Here is an addition of HBr to an asymmetric molecule.<\/li>\n<li>First, try to make sense of how the reactant went to product and then take a look at the mechanism.<\/li>\n<\/ul>\n<p><strong><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2201\/Figure4.1.bmp?revision=1&amp;size=bestfit&amp;width=463&amp;height=252#fixme#fixme\" alt=\"Figure4.1.bmp\" width=\"463\" height=\"252\" \/><\/strong><\/p>\n<p>The\u00a0\u03c0 electrons are attacking the hydrogen, depicted by the electron pushing arrows and the bromine gains a negative charge.\u00a0 The carbocation intermediate forms a positive charge on the left carbon after the hydrogen was added to the carbon with the most hydrogen substituents.<\/p>\n<p><strong>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2202\/Figure4.2.bmp?revision=1&amp;size=bestfit&amp;width=325&amp;height=100#fixme#fixme\" alt=\"Figure4.2.bmp\" width=\"325\" height=\"100\" \/>\u00a0\u00a0\u00a0<\/strong><\/p>\n<p>The bromine, which now exists as bromide with a negative charge, attacks the positively charged carbocation forming the final product with the nucleophile (Br) on the more substituted carbon.<\/p>\n<\/div>\n<div class=\"mt-section\">\n<h4 id=\"Addition_due_to_excess_HBr_present-916\">Addition with excess HBr present<\/h4>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2205\/Figure5.bmp?revision=1&amp;size=bestfit&amp;width=515&amp;height=146#fixme#fixme\" alt=\"Figure5.bmp\" width=\"515\" height=\"146\" \/><\/p>\n<\/div>\n<\/div>\n<div class=\"mt-section\">\n<p>&nbsp;<\/p>\n<h3 id=\"Reaction:__Halogenation_of_Alkynes-916\"><strong>Reaction:\u00a0 Halogenation of Alkynes<\/strong><\/h3>\n<p><strong>\u00a0Summary:<\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/06\/22200638\/Halogenation_of_Alynes_1.jpg\" alt=\"Halogenation of Alynes (1).JPG\" width=\"355\" height=\"80\" \/><\/p>\n<ul>\n<li>Stereoselectivity: anti addition<\/li>\n<li>Reaction proceeds via cyclic halonium ion<\/li>\n<\/ul>\n<div class=\"mt-section\">\n<h4 id=\"Addition_of_Br2-916\"><strong>Addition of <\/strong><strong>Br<\/strong><sub><strong>2<\/strong><\/sub><\/h4>\n<ul>\n<li>The addition of Br<sub>2<\/sub> to an alkyne is analogous to adding Br<sub>2<\/sub> to an alkene.<\/li>\n<li>Once Br<sub>2<\/sub> approaches the nucleophilic alkyne, it becomes polarized.<\/li>\n<li>The\u00a0\u03c0 electrons, from the triple bond, can now attack the polarized bromine forming a C-Br bond and displacing the bromide ion.<\/li>\n<li>Now, you will get an intermediate bromonium ion, which will immediately react with the bromide ion giving you the dibromo product.<\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2207\/Figure6.bmp?revision=1&amp;size=bestfit&amp;width=465&amp;height=415#fixme#fixme\" alt=\"Figure6.bmp\" width=\"465\" height=\"415\" \/><\/p>\n<p>First, you see the polarized Br<sub>2<\/sub> being attacked by the\u00a0\u03c0 electrons.\u00a0 Once you form the C-Br bond, the other bromine is released as a bromine ion.\u00a0 The intermediate here is a bromonium ion, which is electrophilic and reacts with the bromine ion giving you the dibromo product.<\/p>\n<\/div>\n<\/div>\n<div id=\"section_9\" class=\"mt-section\">\n<h3 id=\"Reaction:__Hydration_of_Alkynes-916\"><strong>Reaction:\u00a0 Hydration of Alkynes<\/strong><\/h3>\n<p><strong>Summary:\u00a0 <\/strong>With the addition of water, alkynes can be hydrated to form enols that spontaneously tautomerize to ketones. Reaction is catalyzed by mercury ions. Follows Markovnikov\u2019s Rule: Terminal alkynes give methyl ketones.<\/p>\n<p><strong>Figure 7<\/strong><\/p>\n<\/div>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-5028\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/07023616\/But1yneMvHydration.png\" alt=\"But=1-yne adds H2O in presence of H2SO4\/HgSO4 to form an enol, and then butanone\" width=\"527\" height=\"144\" \/><\/p>\n<div id=\"section_9\" class=\"mt-section\">\n<ul>\n<li>The first step is an acid\/base reaction where the\u00a0\u03c0 electrons of the triple bond act as a Lewis base and attack the proton, protonating the carbon that has more hydrogens.\u00a0 (Electrophilic addition)<\/li>\n<li>The second step is the attack of the nucleophilic water molecule on the electrophilic carbocation, which creates an oxonium ion.\u00a0 (Coordination)<\/li>\n<li>Next, the positively charged oxygen is deprotonated by water (which is acting as a base), generating an C=C bonded alcohol called an enol.\u00a0 (Acid-base)<\/li>\n<li>The enol then tautomerizes into a ketone, via a mechanism that will be covered in <a href=\"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/\">part 2 of this textbook<\/a>.\u00a0 Tautomerization is a simultaneous proton and double bond shift, which goes from the enol form to the keto isomer form as shown above in Figure 7.<\/li>\n<\/ul>\n<p>Now let&#8217;s look at some examples of hydration Reactions.<\/p>\n<div id=\"section_10\" class=\"mt-section\">\n<h4 id=\"Hydration_of_Terminal_Alkyne_produces_methyl_ketones-916\">Hydration of terminal alkyne produces methyl ketones<\/h4>\n<p><strong><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2210\/Figure8.bmp?revision=1&amp;size=bestfit&amp;width=462&amp;height=224#fixme#fixme\" alt=\"Figure8.bmp\" width=\"462\" height=\"224\" \/><\/strong><\/p>\n<p>Just as described in Figure 7 the\u00a0\u03c0 electrons will attack a proton, forming a carbocation, which then gets attacked by the nucleophilic water molecules.\u00a0 After deprotonation, we generate an enol, which then tautomerizes into the ketone form shown.<\/p>\n<\/div>\n<div id=\"section_11\" class=\"mt-section\">\n<h4 id=\"Hydration_of_Alkyne-916\">Hydration of but-1-yne<\/h4>\n<p>The\u00a0\u03c0 electrons of the triple bond attack the proton, which forms a covalent bond on the carbon with the most hydrogen substituents. This forms a carbocation, which is then attacked by the water molecule via a coordination step. This produces a positive charge on the oxygen, so another molecule of water is needed as a base to deprotonate the molecule and give a neutral product. The resultant enol is unstable, and it rapidly tautomerizes to the ketone (butanone).<\/p>\n<\/div>\n<p><strong>Figure 9<br \/>\n<\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-5027\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/07023403\/But2yneMvHydration.png\" alt=\"But-2-yne adds H2O in presence of H2SO4 to form an enol, and then butanone\" width=\"524\" height=\"154\" \/><\/p>\n<div id=\"section_11\" class=\"mt-section\">\n<p>Outside links<\/p>\n<\/div>\n<\/div>\n<div id=\"section_12\" class=\"mt-section\">\n<ul>\n<li><a title=\"http:\/\/www.cem.msu.edu\/~reusch\/VirtualText\/addyne1.htm\" href=\"http:\/\/www.cem.msu.edu\/~reusch\/VirtualText\/addyne1.htm\" target=\"_blank\" rel=\"external nofollow noopener\">http:\/\/www.cem.msu.edu\/~reusch\/VirtualText\/addyne1.htm<\/a><\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"size-thumbnail wp-image-4675 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/01173315\/static_qr_code_without_logo6-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<ul>\n<li><a title=\"http:\/\/wikipremed.com\/03_organicmechanisms.php?mch_code=030203_010\" href=\"http:\/\/wikipremed.com\/03_organicmechanisms.php?mch_code=030203_010\" target=\"_blank\" rel=\"external nofollow noopener\">http:\/\/wikipremed.com\/03_organicmechanisms.php?mch_code=030203_010<\/a><\/li>\n<\/ul>\n<\/div>\n<div id=\"section_13\" class=\"mt-section\">\n<h3 id=\"References-916\">References<\/h3>\n<ol>\n<li>Vollhardt. Schore, Organic Chemistry Structure and Function Fifth Edition, New York: W.H. Freeman and Company, 2007.<\/li>\n<li>Solomons, T. W. Graham, and Craig B. Fryhle. Organic Chemistry Eighth Edition. Maryland: John Wiley and Sons Incorporated, 2008.<\/li>\n<\/ol>\n<\/div>\n<div id=\"section_14\" class=\"mt-section textbox exercises\">\n<h3 id=\"Practice_Problems-916\">Practice Problems<\/h3>\n<p><strong>1) Reaction:\u00a0 Addition of hydrogen halide to an alkyne<\/strong><\/p>\n<p><strong>1a)<\/strong>\u00a0 What product would result from the reaction of 1-pentyne with hydrogen bromide?<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2222\/Practiceproblem1a.bmp?revision=1&amp;size=bestfit&amp;width=349&amp;height=100#fixme#fixme\" alt=\"Practiceproblem1a.bmp\" width=\"349\" height=\"100\" \/><\/p>\n<p><strong>1b)<\/strong>\u00a0 Take your answer from 1a and add an excess of hydrogen bromide.\u00a0 What would be the product?<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2223\/Practiceproblem1b.bmp?revision=1&amp;size=bestfit&amp;width=200&amp;height=60#fixme#fixme\" alt=\"Practiceproblem1b.bmp\" width=\"200\" height=\"60\" \/><\/p>\n<p><strong>1c)<\/strong>\u00a0\u00a0 What is the mechanism for this reaction?<\/p>\n<p><strong>2) Reaction:\u00a0 Addition of X<sub>2<\/sub> to alkynes<\/strong><\/p>\n<p><strong>2a)<\/strong>\u00a0 What product would result from the reaction of 1-pentyne with Br<sub>2<\/sub>?<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2224\/Practiceproblem2a_(1).bmp?revision=1&amp;size=bestfit&amp;width=382&amp;height=74#fixme#fixme\" alt=\"Practiceproblem2a (1).bmp\" width=\"382\" height=\"74\" \/><\/p>\n<p><strong>2b)<\/strong>\u00a0 Take your answer from 2a and add an excess of Br<sub>2<\/sub>.\u00a0 What would be the product?<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2223\/Practiceproblem1b.bmp?revision=1&amp;size=bestfit&amp;width=200&amp;height=60#fixme#fixme\" alt=\"Practiceproblem1b.bmp\" width=\"200\" height=\"60\" \/><\/p>\n<p><strong>2c)<\/strong>\u00a0\u00a0 What is the mechanism for this reaction?<\/p>\n<p><strong>3) Reaction:\u00a0 Hydration of alkynes<\/strong><\/p>\n<p><strong>3a)<\/strong>\u00a0 If 1-Pentyne were to react with mercury(II) sulfate, water, and sulfuric acid, what would be the product?<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/06\/22200640\/Practice3_1.jpg\" alt=\"Practice3 (1).JPG\" width=\"328\" height=\"90\" \/><\/p>\n<p><strong>4)<\/strong>\u00a0\u00a0 What is the product when 3-methylbutyne reacts with HCl? Include in your answer:<br \/>\na)\u00a0\u00a0\u00a0 the reaction mechanism<br \/>\nb)\u00a0\u00a0\u00a0 a clear explanation for why the hydrogen and chlorine bind to where they do<\/p>\n<p><strong>5)<\/strong>\u00a0 a) Draw the enol form of the ketone below.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/06\/22200642\/Problem5a.jpg\" alt=\"Problem5a.JPG\" width=\"410\" height=\"170\" \/><\/p>\n<p>b)\u00a0 Draw the keto form of the enol below.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/06\/22200644\/Practice5b.jpg\" alt=\"Practice5b.JPG\" width=\"410\" height=\"170\" \/><\/p>\n<\/div>\n<\/div>\n<div class=\"mt-section\">\n<div class=\"textbox examples\">\n<h3>Further reading<\/h3>\n<p><em>MasterOrganicChemistry<\/em><\/p>\n<ul>\n<li><a class=\"external\" title=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/24\/alkyne-reaction-patterns-the-carbocation-pathway\/\" href=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/24\/alkyne-reaction-patterns-the-carbocation-pathway\/\" target=\"_blank\" rel=\"external nofollow noopener\">Alkyne Reactions Patterns &#8211; The Carbocation Pathway<\/a><\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"size-thumbnail wp-image-4676 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/01173426\/static_qr_code_without_logo7-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<ul>\n<li><a class=\"external\" title=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/29\/alkyne-addition-pathways-the-3-membered-ring-pathway\/\" href=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/29\/alkyne-addition-pathways-the-3-membered-ring-pathway\/\" target=\"_blank\" rel=\"external nofollow noopener\">Alkyne Reactions Patterns &#8211; The 3-Membered Ring Pathway<\/a><\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"size-thumbnail wp-image-4677 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/01173627\/static_qr_code_without_logo2-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<p><em>Carey 5th Ed Online<\/em><\/p>\n<ul>\n<li><a class=\"external\" title=\"http:\/\/www.mhhe.com\/physsci\/chemistry\/carey\/student\/olc\/ch09additionreactionsofalkynes.html\" href=\"http:\/\/www.mhhe.com\/physsci\/chemistry\/carey\/student\/olc\/ch09additionreactionsofalkynes.html\" target=\"_blank\" rel=\"external nofollow noopener\">Addition Reactions of Alkynes<\/a><\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"size-thumbnail wp-image-4678 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/01173807\/static_qr_code_without_logo7-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<\/div>\n<p><em>Videos<\/em><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignright size-thumbnail wp-image-4679\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/01174017\/static_qr_code_without_logo3-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"Electrophilic Addition of HCl, HBr, Br2 and Cl2 to Alkynes\" width=\"500\" height=\"375\" src=\"https:\/\/www.youtube.com\/embed\/S0ts6VK7Vyk?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<p><a class=\"link-https\" title=\"https:\/\/www.khanacademy.org\/science\/organic-chemistry\/alkenes-alkynes\/alkyne-reactions\/v\/hydration-of-alkynes\" href=\"https:\/\/www.khanacademy.org\/science\/organic-chemistry\/alkenes-alkynes\/alkyne-reactions\/v\/hydration-of-alkynes\" target=\"_blank\" rel=\"external nofollow noopener\">Hydration of Alkynes<\/a><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignright size-thumbnail wp-image-4680\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3369\/2018\/07\/01174353\/static_qr_code_without_logo8-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-2\" title=\"Hydration of alkynes | Alkenes and Alkynes | Organic chemistry | Khan Academy\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/AE1pkp-_cKE?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<\/div>\n<\/section>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-3296\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>11.1.3 Electrophilic Addition to Alkynes. <strong>Authored by<\/strong>: Prof. Hilton Weiss (Bard College), Aleksandra Milman. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/chem.libretexts.org\/LibreTexts\/Purdue\/Purdue%3A_Chem_26605%3A_Organic_Chemistry_II_(Lipton)\/Chapter_11.__Addition_to_pi_Systems\/11.1%3A_Electrophilic_Addition\/11.1.3_Electrophilic_Addition_to_Alkynes\">https:\/\/chem.libretexts.org\/LibreTexts\/Purdue\/Purdue%3A_Chem_26605%3A_Organic_Chemistry_II_(Lipton)\/Chapter_11.__Addition_to_pi_Systems\/11.1%3A_Electrophilic_Addition\/11.1.3_Electrophilic_Addition_to_Alkynes<\/a>. <strong>Project<\/strong>: Chemistry LibreTexts. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":311,"menu_order":5,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"11.1.3 Electrophilic Addition to Alkynes\",\"author\":\"Prof. Hilton Weiss (Bard College), Aleksandra Milman\",\"organization\":\"\",\"url\":\"https:\/\/chem.libretexts.org\/LibreTexts\/Purdue\/Purdue%3A_Chem_26605%3A_Organic_Chemistry_II_(Lipton)\/Chapter_11.__Addition_to_pi_Systems\/11.1%3A_Electrophilic_Addition\/11.1.3_Electrophilic_Addition_to_Alkynes\",\"project\":\"Chemistry LibreTexts\",\"license\":\"cc-by-nc-sa\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-3296","chapter","type-chapter","status-publish","hentry"],"part":27,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/3296","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/wp-json\/wp\/v2\/users\/311"}],"version-history":[{"count":29,"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/3296\/revisions"}],"predecessor-version":[{"id":5121,"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/3296\/revisions\/5121"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/wp-json\/pressbooks\/v2\/parts\/27"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/wp-json\/pressbooks\/v2\/chapters\/3296\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/wp-json\/wp\/v2\/media?parent=3296"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/wp-json\/pressbooks\/v2\/chapter-type?post=3296"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/wp-json\/wp\/v2\/contributor?post=3296"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry\/wp-json\/wp\/v2\/license?post=3296"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}