{"id":1496,"date":"2018-11-28T17:24:50","date_gmt":"2018-11-28T17:24:50","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/?post_type=chapter&#038;p=1496"},"modified":"2019-01-08T14:34:48","modified_gmt":"2019-01-08T14:34:48","slug":"20-5-addition-of-hcn-to-co","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/chapter\/20-5-addition-of-hcn-to-co\/","title":{"raw":"20.5. Addition of HCN to C=O","rendered":"20.5. Addition of HCN to C=O"},"content":{"raw":"<article id=\"elm-main-content\" class=\"elm-content-container\"><section class=\"mt-content-container\">Hydrogen cyanide adds across the carbon-oxygen double bond in aldehydes and some ketones to produce compounds known as hydroxynitriles. For example, with ethanal (an aldehyde) you get 2-hydroxypropanenitrile:\r\n<div id=\"section_1\" class=\"mt-section\">\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/28172339\/aldhcneq.gif\" alt=\"\" width=\"294px\" height=\"62px\" \/>\r\n\r\nWith acetone (a ketone) you get 2-hydroxy-2-methylpropanenitrile:\r\n\r\n<img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/28172341\/kethcneq.gif\" alt=\"\" width=\"296px\" height=\"65px\" \/>\r\n\r\nThe reaction isn't normally done using hydrogen cyanide itself, because this is an extremely poisonous gas. Instead, the aldehyde or ketone is mixed with a solution of sodium or potassium cyanide in water to which a little acid has been added. The pH of the solution is adjusted to about 4 - 5, because this gives the fastest reaction. The solution will contain hydrogen cyanide (from the reaction between the sodium or potassium cyanide and the acid), but still contains some free cyanide ions. This is important for the mechanism.\r\n\r\n<\/div>\r\n<div id=\"section_2\" class=\"mt-section\">\r\n<h2 class=\"editable\">Mechanism<\/h2>\r\nThese are examples of nucleophilic addition. The carbon-oxygen double bond is highly polar, and the slightly positive carbon atom is attacked by the cyanide ion acting as a nucleophile.\r\n<div id=\"section_3\" class=\"mt-section\">\r\n<h4 class=\"editable\">The Mechanism for the Addition of HCN to acetone<\/h4>\r\nIn the first stage, there is a nucleophilic attack by the cyanide ion on the slightly positive carbon atom.\r\n<p style=\"text-align: center\"><img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/28172344\/kethcnm1.gif\" alt=\"\" width=\"293px\" height=\"88px\" \/><\/p>\r\nThe negative ion formed then picks up a hydrogen ion from somewhere - for example, from a hydrogen cyanide molecule.\r\n<p style=\"text-align: center\"><img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/28172347\/kethcnm2.gif\" alt=\"\" width=\"385px\" height=\"67px\" \/><\/p>\r\nThe hydrogen ion could also come from the water or the H<sub>3<\/sub>O<sup>+<\/sup> ions present in the slightly acidic solution. You don't need to remember all of these. One equation is perfectly adequate.\r\n\r\n<\/div>\r\n<div id=\"section_4\" class=\"mt-section\">\r\n<h4 class=\"editable\">The Mechanism for the Addition of HCN to ethanal<\/h4>\r\nAs before, the reaction starts with a nucleophilic attack by the cyanide ion on the slightly positive carbon atom.\r\n<p style=\"text-align: center\"><img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/28172349\/aldhcnm1.gif\" alt=\"\" width=\"286px\" height=\"113px\" \/><\/p>\r\nIt is completed by the addition of a hydrogen ion from, for example, a hydrogen cyanide molecule.\r\n<p style=\"text-align: center\"><img class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/28172352\/aldhcnm2.gif\" alt=\"\" width=\"367px\" height=\"92px\" \/><\/p>\r\n\r\n<\/div>\r\n<\/div>\r\n<div id=\"section_6\" class=\"mt-section\">\r\n<h3 class=\"editable\">Contributors<\/h3>\r\n<ul>\r\n \t<li>Jim Clark (<a class=\"external\" title=\"http:\/\/www.chemguide.co.uk\" href=\"http:\/\/www.chemguide.co.uk\" target=\"_blank\" rel=\"external nofollow noopener\">Chemguide.co.uk<\/a>)<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/section><\/article>","rendered":"<article id=\"elm-main-content\" class=\"elm-content-container\">\n<section class=\"mt-content-container\">Hydrogen cyanide adds across the carbon-oxygen double bond in aldehydes and some ketones to produce compounds known as hydroxynitriles. For example, with ethanal (an aldehyde) you get 2-hydroxypropanenitrile:<\/p>\n<div id=\"section_1\" class=\"mt-section\">\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/28172339\/aldhcneq.gif\" alt=\"\" width=\"294px\" height=\"62px\" \/><\/p>\n<p>With acetone (a ketone) you get 2-hydroxy-2-methylpropanenitrile:<\/p>\n<p><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/28172341\/kethcneq.gif\" alt=\"\" width=\"296px\" height=\"65px\" \/><\/p>\n<p>The reaction isn&#8217;t normally done using hydrogen cyanide itself, because this is an extremely poisonous gas. Instead, the aldehyde or ketone is mixed with a solution of sodium or potassium cyanide in water to which a little acid has been added. The pH of the solution is adjusted to about 4 &#8211; 5, because this gives the fastest reaction. The solution will contain hydrogen cyanide (from the reaction between the sodium or potassium cyanide and the acid), but still contains some free cyanide ions. This is important for the mechanism.<\/p>\n<\/div>\n<div id=\"section_2\" class=\"mt-section\">\n<h2 class=\"editable\">Mechanism<\/h2>\n<p>These are examples of nucleophilic addition. The carbon-oxygen double bond is highly polar, and the slightly positive carbon atom is attacked by the cyanide ion acting as a nucleophile.<\/p>\n<div id=\"section_3\" class=\"mt-section\">\n<h4 class=\"editable\">The Mechanism for the Addition of HCN to acetone<\/h4>\n<p>In the first stage, there is a nucleophilic attack by the cyanide ion on the slightly positive carbon atom.<\/p>\n<p style=\"text-align: center\"><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/28172344\/kethcnm1.gif\" alt=\"\" width=\"293px\" height=\"88px\" \/><\/p>\n<p>The negative ion formed then picks up a hydrogen ion from somewhere &#8211; for example, from a hydrogen cyanide molecule.<\/p>\n<p style=\"text-align: center\"><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/28172347\/kethcnm2.gif\" alt=\"\" width=\"385px\" height=\"67px\" \/><\/p>\n<p>The hydrogen ion could also come from the water or the H<sub>3<\/sub>O<sup>+<\/sup> ions present in the slightly acidic solution. You don&#8217;t need to remember all of these. One equation is perfectly adequate.<\/p>\n<\/div>\n<div id=\"section_4\" class=\"mt-section\">\n<h4 class=\"editable\">The Mechanism for the Addition of HCN to ethanal<\/h4>\n<p>As before, the reaction starts with a nucleophilic attack by the cyanide ion on the slightly positive carbon atom.<\/p>\n<p style=\"text-align: center\"><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/28172349\/aldhcnm1.gif\" alt=\"\" width=\"286px\" height=\"113px\" \/><\/p>\n<p>It is completed by the addition of a hydrogen ion from, for example, a hydrogen cyanide molecule.<\/p>\n<p style=\"text-align: center\"><img decoding=\"async\" class=\"internal aligncenter\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/28172352\/aldhcnm2.gif\" alt=\"\" width=\"367px\" height=\"92px\" \/><\/p>\n<\/div>\n<\/div>\n<div id=\"section_6\" class=\"mt-section\">\n<h3 class=\"editable\">Contributors<\/h3>\n<ul>\n<li>Jim Clark (<a class=\"external\" title=\"http:\/\/www.chemguide.co.uk\" href=\"http:\/\/www.chemguide.co.uk\" target=\"_blank\" rel=\"external nofollow noopener\">Chemguide.co.uk<\/a>)<\/li>\n<\/ul>\n<\/div>\n<\/section>\n<\/article>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1496\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>The Addition of Hydrogen Cyanide to Aldehydes and Ketones. <strong>Authored by<\/strong>: Jim Clark. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/chem.libretexts.org\/Textbook_Maps\/Organic_Chemistry\/Supplemental_Modules_(Organic_Chemistry)\/Reactions\/Addition_Reactions\/Nucleophilic_Addition_Reactions\/The_Addition_of_Hydrogen_Cyanide_to_Aldehydes_and_Ketones\">https:\/\/chem.libretexts.org\/Textbook_Maps\/Organic_Chemistry\/Supplemental_Modules_(Organic_Chemistry)\/Reactions\/Addition_Reactions\/Nucleophilic_Addition_Reactions\/The_Addition_of_Hydrogen_Cyanide_to_Aldehydes_and_Ketones<\/a>. <strong>Project<\/strong>: Chemistry LibreTexts. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":53384,"menu_order":5,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"The Addition of Hydrogen Cyanide to Aldehydes and 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LibreTexts\",\"license\":\"cc-by-nc-sa\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1496","chapter","type-chapter","status-publish","hentry"],"part":1242,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/wp-json\/pressbooks\/v2\/chapters\/1496","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/wp-json\/wp\/v2\/users\/53384"}],"version-history":[{"count":5,"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/wp-json\/pressbooks\/v2\/chapters\/1496\/revisions"}],"predecessor-version":[{"id":2974,"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/wp-json\/pressbooks\/v2\/chapters\/1496\/revisions\/2974"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/wp-json\/pressbooks\/v2\/parts\/1242"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/wp-json\/pressbooks\/v2\/chapters\/1496\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/wp-json\/wp\/v2\/media?parent=1496"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/wp-json\/pressbooks\/v2\/chapter-type?post=1496"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/wp-json\/wp\/v2\/contributor?post=1496"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/wp-json\/wp\/v2\/license?post=1496"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}