{"id":62,"date":"2018-11-19T20:16:58","date_gmt":"2018-11-19T20:16:58","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/chapter\/10-5-simple-addition-to-alkynes\/"},"modified":"2018-11-19T20:16:58","modified_gmt":"2018-11-19T20:16:58","slug":"10-5-simple-addition-to-alkynes","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-potsdam-organicchemistry2\/chapter\/10-5-simple-addition-to-alkynes\/","title":{"raw":"10.5. Simple addition to alkynes","rendered":"10.5. Simple addition to alkynes"},"content":{"raw":"\n<p>Addition of strong acids to alkynes is quite similar to the addition of strong acids to alkenes. The regiochemistry follows <em style=\"font-size: 16px\">Markovnikov\u2019s Rule<\/em><span style=\"font-size: 16px\">, but the stereochemistry is often different. Addition to alkenes is usually not stereospecific, whereas alkynes usually undergo <\/span><em style=\"font-size: 16px\">anti <\/em><span style=\"font-size: 16px\">addition.<\/span>\n<section class=\"mt-content-container\">\n<div id=\"s916\" class=\"mt-include\">\n<div class=\"mt-section\">\n<p>Now we will take a look at electrophilic addition reactions, particularly of alkynes. The reaction mechanisms, as you will notice, are quite similar to the electrophilic addition reactions of alkenes. The triple bonds of alkynes, because of its high electron density, are easily attacked by electrophiles, but are less reactive than alkenes due to the compact C-C electron cloud.As with <a class=\"internal mt-disabled\" title=\"Wikitexts\/UCD Chem 118B\/Chem 118B Topics\/Electrophilic Addition of Halogens to Alkenes\" rel=\"broken\">electrophilic addition to unsymmetrical alkenes<\/a>, the Markovnikov rule is followed, adding the electrophile to the less substituted carbon.<\/p>\n<p>For simplicity, we will show the mechanism going via a vinyl carbocation, by analogy with the alkyl carbocation formed when alkenes react.&nbsp; In fact, the vinyl carbocation is usually to unstable to be a real intermediate; the actual intermediate is more like a complex of the electrophile with the alkyne, which begins to place a partial positive charge on the nearby carbon.<\/p>\n<p>Here we will go through the following reactions listed below to learn the mechanisms behind these electrophilic additions of alkynes: (1) HX Addition to <a class=\"internal\" title=\"Organic Chemistry\/Hydrocarbons\/Alkenes\" href=\"https:\/\/chem.libretexts.org\/Core\/Organic_Chemistry\/Hydrocarbons\/Alkenes\" rel=\"internal\">alkenes<\/a>, (2) Halogenation of <a class=\"internal\" title=\"Organic Chemistry\/Hydrocarbons\/Alkynes\" href=\"https:\/\/chem.libretexts.org\/Core\/Organic_Chemistry\/Hydrocarbons\/Alkynes\" rel=\"internal\">alkynes<\/a> and (3) Hydration of alkynes.<\/p>\n<p><strong>Figure<br>\n<\/strong>\n<p><strong><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201644\/Alkene_Alkyne_1.jpg\" alt=\"Alkene_Alkyne (1).JPG\" width=\"694\" height=\"336\"><\/strong>\n<p>The addition of an electrophile to either an alkene or an alkyne will undergo the same steps listed below.<\/p>\n<ol>\n<li>Start with a reactant (either an alkene or an alkyne), which has $$\\pi$$ electrons. An electron pair moves from the $$\\pi$$ bond to the electrophilic proton to form a new covalent bond this is the electrophilic addition elementary step. A carbocation intermediate forms on the more stable carbon.&nbsp;As shown in the diagram above, the intermediate consists of hydrogen covalently bonded to the carbon and a positive charge on the other carbon.<\/li>\n<li>The addition of the halide ion to the positive charged intermediate forms the second covalent bond giving you the haloalkane product (as seen on the left of the above diagram) and a haloalkene product (as seen on the right of the above diagram). The halide ion acts as a nucleophile, which is attracted to the positive charged carbon because it has electrons to donate or share. So when the nucleophilic halide (represented as X<sup>-<\/sup>) attacks, it aims for the positively charged carbon resulting in that second covalent bond as seen above.<\/li>\n<\/ol>\n<p>Make Note: The way to determine where the addition of the proton and the halide takes place is based on Markovnikov\u2019s Rule, which states that the proton adds onto the carbon with the most hydrogens and the halogen prefers the most substituted carbon.<\/p>\n<p>Now let's take a look at our first reaction, the addition of Hydrogen Halide.<\/p>\n<\/div>\n<div class=\"mt-section\">\n<h3 id=\"Reaction_1:__Addition_of_Hydrogen_Halide_to_an_Alkyne-916\">Reaction 1:&nbsp; Addition of hydrogen halide to an alkyne<\/h3>\n<p><strong>Summary:<\/strong>&nbsp; Reactivity order of <strong><span class=\"internal\">hydrogen halides<\/span><strong>: HI &gt; HBr &gt; HCl &gt; HF.<\/strong><\/strong>\n<p>Follows Markovnikov\u2019s rule:<\/p>\n<ul>\n<li>Hydrogen adds to the carbon with the greatest number of hydrogens, the halogen adds to the carbon with fewer hydrogens.<\/li>\n<li>Protonation occurs on the more stable carbocation. With the addition of HX, haloalkenes form.<\/li>\n<li>With the addition of excess HX, you get <em>anti <\/em>addition forming a geminal dihaloalkane.<\/li>\n<\/ul>\n<div class=\"mt-section\">\n<h4 id=\"Addition_of_a_HX_to_an_Internal_Alkyne-916\">Addition of a HX to an internal alkyne<\/h4>\n<p>As described in Figure 1, the $$\\pi$$ electrons will attack the hydrogen of the HBr and because this is a symmetric molecule it will add to either carbon at a roughly equal rate.&nbsp;&nbsp; Once the hydrogen is covalently bonded to one of the carbons, you will get a carbocation intermediate (not shown, but will look the same as depicted in the figure above) on the other carbon.<\/p>\n<p>The final step is the addition of the bromide, which is a good nucleophile because it has electrons to donate or share.&nbsp; Bromide, therefore, attacks the carbocation intermediate placing the Br on that carbon. As a result, you get 2-bromobutene from your 2-butyne reactant, as shown below.<br>\n<img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2199\/Figure2_(1).bmp?revision=1&amp;size=bestfit&amp;width=442&amp;height=160#fixme#fixme#fixme\" alt=\"Figure2 (1).bmp\" width=\"442\" height=\"160\"><\/p>\n<p>Now, what if you have excess HBr?<\/p>\n<\/div>\n<div class=\"mt-section\">\n<h4 id=\"Addition_due_to_excess_HX_present_.3F_yields_a_geminal_dihaloalkane-916\">Addition due to excess HX present yields a geminal dihaloalkane<\/h4>\n<p><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2200\/Figure3.bmp?revision=1&amp;size=bestfit&amp;width=473&amp;height=166#fixme#fixme#fixme\" alt=\"Figure3.bmp\" width=\"473\" height=\"166\"><\/p>\n<p>Here, the electrophilic addition proceeds with the same steps used to achieve the product in addition of a HX to an internal alkyne.&nbsp; The $$\\pi$$ electrons attacked the hydrogen, adding it to the carbon on the left (shown in blue). The hydrogen is added to the left hand carbon forming a carbocation on the carbon with the Br, since this is stabilized by type III resonance.&nbsp; Then the carbocation intermediate is attacked by the bromide resulting in a dihaloalkane product.<\/p>\n<\/div>\n<div class=\"mt-section\">\n<h4 id=\"Addition_of_HX_to_Terminal_Alkyne-916\">Addition of HX to Terminal Alkyne<\/h4>\n<ul>\n<li>Here is an addition of HBr to an asymmetric molecule.<\/li>\n<li>First, try to make sense of how the reactant went to product and then take a look at the mechanism.<\/li>\n<\/ul>\n<p><strong><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2201\/Figure4.1.bmp?revision=1&amp;size=bestfit&amp;width=463&amp;height=252#fixme#fixme#fixme\" alt=\"Figure4.1.bmp\" width=\"463\" height=\"252\"><\/strong>\n<p>The $$\\pi$$ electrons are attacking the hydrogen, depicted by the electron pushing arrows and the bromine gains a negative charge.&nbsp; The carbocation intermediate forms a positive charge on the left carbon after the hydrogen was added to the carbon with the most hydrogen substituents.<\/p>\n<p><strong>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2202\/Figure4.2.bmp?revision=1&amp;size=bestfit&amp;width=325&amp;height=100#fixme#fixme#fixme\" alt=\"Figure4.2.bmp\" width=\"325\" height=\"100\">&nbsp;&nbsp;&nbsp;<\/strong>\n<p>The bromine, which now exists as bromide with a negative charge, attacks the positively charged carbocation forming the final product with the nucleophile (Br) on the more substituted carbon.<\/p>\n<\/div>\n<div class=\"mt-section\">\n<h4 id=\"Addition_due_to_excess_HBr_present-916\">Addition with excess HBr present<\/h4>\n<p><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2205\/Figure5.bmp?revision=1&amp;size=bestfit&amp;width=515&amp;height=146#fixme#fixme#fixme\" alt=\"Figure5.bmp\" width=\"515\" height=\"146\"><\/p>\n<\/div>\n<\/div>\n<div class=\"mt-section\">\n<p>&nbsp;<\/p>\n<h3 id=\"Reaction:__Halogenation_of_Alkynes-916\"><strong>Reaction:&nbsp; Halogenation of Alkynes<\/strong><\/h3>\n<p><strong>&nbsp;Summary:<\/strong>\n<p><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201646\/Halogenation_of_Alynes_1.jpg\" alt=\"Halogenation of Alynes (1).JPG\" width=\"355\" height=\"80\"><\/p>\n<ul>\n<li>Stereoselectivity: anti addition<\/li>\n<li>Reaction proceeds via cyclic halonium ion<\/li>\n<\/ul>\n<div class=\"mt-section\">\n<h4 id=\"Addition_of_Br2-916\"><strong>Addition of <\/strong><strong>Br<\/strong><sub><strong>2<\/strong><\/sub><\/h4>\n<ul>\n<li>The addition of Br<sub>2<\/sub> to an alkyne is analogous to adding Br<sub>2<\/sub> to an alkene.<\/li>\n<li>Once Br<sub>2<\/sub> approaches the nucleophilic alkyne, it becomes polarized.<\/li>\n<li>The $$\\pi$$ electrons, from the triple bond, can now attack the polarized bromine forming a C-Br bond and displacing the bromide ion.<\/li>\n<li>Now, you will get an intermediate bromonium ion, which will immediately react with the bromide ion giving you the dibromo product.<\/li>\n<\/ul>\n<p><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2207\/Figure6.bmp?revision=1&amp;size=bestfit&amp;width=465&amp;height=415#fixme#fixme#fixme\" alt=\"Figure6.bmp\" width=\"465\" height=\"415\"><\/p>\n<p>First, you see the polarized Br<sub>2<\/sub> being attacked by the $$\\pi$$ electrons.&nbsp; Once you form the C-Br bond, the other bromine is released as a bromine ion.&nbsp; The intermediate here is a bromonium ion, which is electrophilic and reacts with the bromine ion giving you the dibromo product.<\/p>\n<\/div>\n<\/div>\n<div id=\"section_9\" class=\"mt-section\">\n<h3 id=\"Reaction:__Hydration_of_Alkynes-916\"><strong>Reaction:&nbsp; Hydration of Alkynes<\/strong><\/h3>\n<p><strong>Summary:&nbsp; <\/strong>With the addition of water, alkynes can be hydrated to form enols that spontaneously tautomerize to ketones. Reaction is catalyzed by mercury ions. Follows Markovnikov\u2019s Rule: Terminal alkynes give methyl ketones<\/p>\n<p><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2208\/Figure7.bmp?revision=1&amp;size=bestfit&amp;width=458&amp;height=212#fixme#fixme#fixme\" alt=\"Figure7.bmp\" width=\"458\" height=\"212\"><\/p>\n<ul>\n<li>The first step is an acid\/base reaction where the $$\\pi$$ electrons of the triple bond act as a Lewis base and attack the proton, protonating the carbon that has more hydrogens.&nbsp; (Electrophilic addition)<\/li>\n<li>The second step is the attack of the nucleophilic water molecule on the electrophilic carbocation, which creates an oxonium ion.&nbsp; (Coordination)<\/li>\n<li>Next, the positively charged oxygen is deprotonated by water (which is acting as a base), generating an C=C bonded alcohol called an enol.&nbsp; (Acid-base)<\/li>\n<li>The enol then tautomerizes into a ketone, via a mechanism that will be covered in the second semester.&nbsp; Tautomerization is a simultaneous proton and double bond shift, which goes from the enol form to the keto isomer form as shown above in Figure 7.<\/li>\n<\/ul>\n<p>Now let's look at some examples of hydration Reactions.<\/p>\n<div id=\"section_10\" class=\"mt-section\">\n<h4 id=\"Hydration_of_Terminal_Alkyne_produces_methyl_ketones-916\">Hydration of terminal alkyne produces methyl ketones<\/h4>\n<p><strong><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2210\/Figure8.bmp?revision=1&amp;size=bestfit&amp;width=462&amp;height=224#fixme#fixme#fixme\" alt=\"Figure8.bmp\" width=\"462\" height=\"224\"><\/strong>\n<p>Just as described in Figure 7 the $$\\pi$$ electrons will attack a proton, forming a carbocation, which then gets attacked by the nucleophilic water molecules.&nbsp; After deprotonation, we generate an enol, which then tautomerizes into the ketone form shown.<\/p>\n<\/div>\n<div id=\"section_11\" class=\"mt-section\">\n<h4 id=\"Hydration_of_Alkyne-916\">Hydration of propyne<\/h4>\n<p>As you can see here, the $$\\pi$$ electrons of the triple bond are attacking the proton, which forms a covalent bond on the carbon with the most hydrogen substituents. Once the hydrogen is bound you have a carbocation, which gets attacked by the water molecule. Now you have a positive charge on the oxygen which results in a base coming in and deprotinating the molecule. Once deprotonated, you have an enol, which then gets tautomerized.<\/p>\n<p><strong><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2211\/Figure9.bmp?revision=1&amp;size=bestfit&amp;width=518&amp;height=161#fixme#fixme#fixme\" alt=\"Figure9.bmp\" width=\"518\" height=\"161\"><\/strong>\n<p>Outside links<\/p>\n<\/div>\n<\/div>\n<div id=\"section_12\" class=\"mt-section\">\n<ul>\n<li><a title=\"http:\/\/www.cem.msu.edu\/~reusch\/VirtualText\/addyne1.htm\" href=\"http:\/\/www.cem.msu.edu\/~reusch\/VirtualText\/addyne1.htm\" target=\"_blank\" rel=\"external nofollow noopener\">http:\/\/www.cem.msu.edu\/~reusch\/VirtualText\/addyne1.htm<\/a><\/li>\n<\/ul>\n<p><img class=\"size-thumbnail wp-image-4675 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201648\/static_qr_code_without_logo6-150x150.png\" alt=\"\" width=\"150\" height=\"150\"><\/p>\n<ul>\n<li><a title=\"http:\/\/wikipremed.com\/03_organicmechanisms.php?mch_code=030203_010\" href=\"http:\/\/wikipremed.com\/03_organicmechanisms.php?mch_code=030203_010\" target=\"_blank\" rel=\"external nofollow noopener\">http:\/\/wikipremed.com\/03_organicmechanisms.php?mch_code=030203_010<\/a><\/li>\n<\/ul>\n<\/div>\n<div id=\"section_13\" class=\"mt-section\">\n<h3 id=\"References-916\">References<\/h3>\n<ol>\n<li>Vollhardt. Schore, Organic Chemistry Structure and Function Fifth Edition, New York: W.H. Freeman and Company, 2007.<\/li>\n<li>Solomons, T. W. Graham, and Craig B. Fryhle. Organic Chemistry Eighth Edition. Maryland: John Wiley and Sons Incorporated, 2008.<\/li>\n<\/ol>\n<\/div>\n<div id=\"section_14\" class=\"mt-section textbox exercises\">\n<h3 id=\"Practice_Problems-916\">Practice Problems<\/h3>\n<p><strong>1) Reaction:&nbsp; Addition of hydrogen halide to an alkyne<\/strong>\n<p><strong>1a)<\/strong>&nbsp; What product would result from the reaction of 1-pentyne with Hydrogen Bromide?<\/p>\n<p><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2222\/Practiceproblem1a.bmp?revision=1&amp;size=bestfit&amp;width=349&amp;height=100#fixme#fixme#fixme\" alt=\"Practiceproblem1a.bmp\" width=\"349\" height=\"100\"><\/p>\n<p><strong>1b)<\/strong>&nbsp; Take your answer from 1a and add an excess of Hydrogen Bromide.&nbsp; What would be the product?<\/p>\n<p><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2223\/Practiceproblem1b.bmp?revision=1&amp;size=bestfit&amp;width=200&amp;height=60#fixme#fixme#fixme\" alt=\"Practiceproblem1b.bmp\" width=\"200\" height=\"60\"><\/p>\n<p><strong>1c)<\/strong>&nbsp;&nbsp; What is the mechanism for this reaction?<\/p>\n<p><strong>2) Reaction:&nbsp; Addition of X<sub>2<\/sub> to alkynes<\/strong>\n<p><strong>2a)<\/strong>&nbsp; What product would result from the reaction of 1-Pentyne with Br2?<\/p>\n<p><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2224\/Practiceproblem2a_(1).bmp?revision=1&amp;size=bestfit&amp;width=382&amp;height=74#fixme#fixme#fixme\" alt=\"Practiceproblem2a (1).bmp\" width=\"382\" height=\"74\"><\/p>\n<p><strong>2b)<\/strong>&nbsp; Take your answer from 2a and add an excess of Br<sub>2<\/sub>.&nbsp; What would be the product?<\/p>\n<p><img class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2223\/Practiceproblem1b.bmp?revision=1&amp;size=bestfit&amp;width=200&amp;height=60#fixme#fixme#fixme\" alt=\"Practiceproblem1b.bmp\" width=\"200\" height=\"60\"><\/p>\n<p><strong>2c)<\/strong>&nbsp;&nbsp; What is the mechanism for this reaction?<\/p>\n<p><strong>3) Reaction:&nbsp; Hydration of alkynes<\/strong>\n<p><strong>3a)<\/strong>&nbsp; If 1-Pentyne were to react with mercury(I) sulfate, water, and sulfuric acid, what would be the product?<\/p>\n<p><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201649\/Practice3_1.jpg\" alt=\"Practice3 (1).JPG\" width=\"328\" height=\"90\"><\/p>\n<p><strong>4)<\/strong>&nbsp;&nbsp; What is the product when 3-methylbutyne reacts with HCl? Include in your answer:<br>\na)&nbsp;&nbsp;&nbsp; the reaction mechanism<br>\nb)&nbsp;&nbsp;&nbsp; a clear explanation for why the hydrogen and chlorine bind to where they do<\/p>\n<p><strong>5)<\/strong>&nbsp; a) Draw the enol form of the Ketone below.<\/p>\n<p><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201651\/Problem5a.jpg\" alt=\"Problem5a.JPG\" width=\"410\" height=\"170\"><\/p>\n<p>b)&nbsp; Draw the keto form of the enol below.<\/p>\n<p><img class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201653\/Practice5b.jpg\" alt=\"Practice5b.JPG\" width=\"410\" height=\"170\"><\/p>\n<\/div>\n<\/div>\n<div class=\"mt-section\">\n<div class=\"textbox examples\">\n<h3>Further reading<\/h3>\n<p><em>MasterOrganicChemistry<\/em>\n<ul>\n<li><a class=\"external\" title=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/24\/alkyne-reaction-patterns-the-carbocation-pathway\/\" href=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/24\/alkyne-reaction-patterns-the-carbocation-pathway\/\" target=\"_blank\" rel=\"external nofollow noopener\">Alkyne Reactions Patterns - The Carbocation Pathway<\/a><\/li>\n<\/ul>\n<p><img class=\"size-thumbnail wp-image-4676 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201655\/static_qr_code_without_logo7-150x150.png\" alt=\"\" width=\"150\" height=\"150\"><\/p>\n<ul>\n<li><a class=\"external\" title=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/29\/alkyne-addition-pathways-the-3-membered-ring-pathway\/\" href=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/29\/alkyne-addition-pathways-the-3-membered-ring-pathway\/\" target=\"_blank\" rel=\"external nofollow noopener\">Alkyne Reactions Patterns - The 3-Membered Ring Pathway<\/a><\/li>\n<\/ul>\n<p><img class=\"size-thumbnail wp-image-4677 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201656\/static_qr_code_without_logo2-150x150.png\" alt=\"\" width=\"150\" height=\"150\"><\/p>\n<p><em>Carey 5th Ed Online<\/em>\n<ul>\n<li><a class=\"external\" title=\"http:\/\/www.mhhe.com\/physsci\/chemistry\/carey\/student\/olc\/ch09additionreactionsofalkynes.html\" href=\"http:\/\/www.mhhe.com\/physsci\/chemistry\/carey\/student\/olc\/ch09additionreactionsofalkynes.html\" target=\"_blank\" rel=\"external nofollow noopener\">Addition Reactions of Alkynes<\/a><\/li>\n<\/ul>\n<p><img class=\"size-thumbnail wp-image-4678 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201656\/static_qr_code_without_logo7-150x150.png\" alt=\"\" width=\"150\" height=\"150\"><\/p>\n<\/div>\n<p><em>Videos<\/em>\n<p><img class=\"alignright size-thumbnail wp-image-4679\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201657\/static_qr_code_without_logo3-150x150.png\" alt=\"\" width=\"150\" height=\"150\"><\/p>\n[embed]https:\/\/www.youtube.com\/watch?v=S0ts6VK7Vyk[\/embed]\n<p><a class=\"link-https\" title=\"https:\/\/www.khanacademy.org\/science\/organic-chemistry\/alkenes-alkynes\/alkyne-reactions\/v\/hydration-of-alkynes\" href=\"https:\/\/www.khanacademy.org\/science\/organic-chemistry\/alkenes-alkynes\/alkyne-reactions\/v\/hydration-of-alkynes\" target=\"_blank\" rel=\"external nofollow noopener\">Hydration of Alkynes<\/a>\n<p><img class=\"alignright size-thumbnail wp-image-4680\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201658\/static_qr_code_without_logo8-150x150.png\" alt=\"\" width=\"150\" height=\"150\"><\/p>\nhttps:\/\/youtu.be\/AE1pkp-_cKE\n<\/div>\n<\/section>\n\n","rendered":"<p>Addition of strong acids to alkynes is quite similar to the addition of strong acids to alkenes. The regiochemistry follows <em style=\"font-size: 16px\">Markovnikov\u2019s Rule<\/em><span style=\"font-size: 16px\">, but the stereochemistry is often different. Addition to alkenes is usually not stereospecific, whereas alkynes usually undergo <\/span><em style=\"font-size: 16px\">anti <\/em><span style=\"font-size: 16px\">addition.<\/span>\n<\/p>\n<section class=\"mt-content-container\">\n<div id=\"s916\" class=\"mt-include\">\n<div class=\"mt-section\">\n<p>Now we will take a look at electrophilic addition reactions, particularly of alkynes. The reaction mechanisms, as you will notice, are quite similar to the electrophilic addition reactions of alkenes. The triple bonds of alkynes, because of its high electron density, are easily attacked by electrophiles, but are less reactive than alkenes due to the compact C-C electron cloud.As with <a class=\"internal mt-disabled\" title=\"Wikitexts\/UCD Chem 118B\/Chem 118B Topics\/Electrophilic Addition of Halogens to Alkenes\" rel=\"broken\">electrophilic addition to unsymmetrical alkenes<\/a>, the Markovnikov rule is followed, adding the electrophile to the less substituted carbon.<\/p>\n<p>For simplicity, we will show the mechanism going via a vinyl carbocation, by analogy with the alkyl carbocation formed when alkenes react.&nbsp; In fact, the vinyl carbocation is usually to unstable to be a real intermediate; the actual intermediate is more like a complex of the electrophile with the alkyne, which begins to place a partial positive charge on the nearby carbon.<\/p>\n<p>Here we will go through the following reactions listed below to learn the mechanisms behind these electrophilic additions of alkynes: (1) HX Addition to <a class=\"internal\" title=\"Organic Chemistry\/Hydrocarbons\/Alkenes\" href=\"https:\/\/chem.libretexts.org\/Core\/Organic_Chemistry\/Hydrocarbons\/Alkenes\" rel=\"internal\">alkenes<\/a>, (2) Halogenation of <a class=\"internal\" title=\"Organic Chemistry\/Hydrocarbons\/Alkynes\" href=\"https:\/\/chem.libretexts.org\/Core\/Organic_Chemistry\/Hydrocarbons\/Alkynes\" rel=\"internal\">alkynes<\/a> and (3) Hydration of alkynes.<\/p>\n<p><strong>Figure<br \/>\n<\/strong>\n<\/p>\n<p><strong><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201644\/Alkene_Alkyne_1.jpg\" alt=\"Alkene_Alkyne (1).JPG\" width=\"694\" height=\"336\" \/><\/strong>\n<\/p>\n<p>The addition of an electrophile to either an alkene or an alkyne will undergo the same steps listed below.<\/p>\n<ol>\n<li>Start with a reactant (either an alkene or an alkyne), which has $$\\pi$$ electrons. An electron pair moves from the $$\\pi$$ bond to the electrophilic proton to form a new covalent bond this is the electrophilic addition elementary step. A carbocation intermediate forms on the more stable carbon.&nbsp;As shown in the diagram above, the intermediate consists of hydrogen covalently bonded to the carbon and a positive charge on the other carbon.<\/li>\n<li>The addition of the halide ion to the positive charged intermediate forms the second covalent bond giving you the haloalkane product (as seen on the left of the above diagram) and a haloalkene product (as seen on the right of the above diagram). The halide ion acts as a nucleophile, which is attracted to the positive charged carbon because it has electrons to donate or share. So when the nucleophilic halide (represented as X<sup>&#8211;<\/sup>) attacks, it aims for the positively charged carbon resulting in that second covalent bond as seen above.<\/li>\n<\/ol>\n<p>Make Note: The way to determine where the addition of the proton and the halide takes place is based on Markovnikov\u2019s Rule, which states that the proton adds onto the carbon with the most hydrogens and the halogen prefers the most substituted carbon.<\/p>\n<p>Now let&#8217;s take a look at our first reaction, the addition of Hydrogen Halide.<\/p>\n<\/div>\n<div class=\"mt-section\">\n<h3 id=\"Reaction_1:__Addition_of_Hydrogen_Halide_to_an_Alkyne-916\">Reaction 1:&nbsp; Addition of hydrogen halide to an alkyne<\/h3>\n<p><strong>Summary:<\/strong>&nbsp; Reactivity order of <strong><span class=\"internal\">hydrogen halides<\/span><strong>: HI &gt; HBr &gt; HCl &gt; HF.<\/strong><\/strong>\n<\/p>\n<p>Follows Markovnikov\u2019s rule:<\/p>\n<ul>\n<li>Hydrogen adds to the carbon with the greatest number of hydrogens, the halogen adds to the carbon with fewer hydrogens.<\/li>\n<li>Protonation occurs on the more stable carbocation. With the addition of HX, haloalkenes form.<\/li>\n<li>With the addition of excess HX, you get <em>anti <\/em>addition forming a geminal dihaloalkane.<\/li>\n<\/ul>\n<div class=\"mt-section\">\n<h4 id=\"Addition_of_a_HX_to_an_Internal_Alkyne-916\">Addition of a HX to an internal alkyne<\/h4>\n<p>As described in Figure 1, the $$\\pi$$ electrons will attack the hydrogen of the HBr and because this is a symmetric molecule it will add to either carbon at a roughly equal rate.&nbsp;&nbsp; Once the hydrogen is covalently bonded to one of the carbons, you will get a carbocation intermediate (not shown, but will look the same as depicted in the figure above) on the other carbon.<\/p>\n<p>The final step is the addition of the bromide, which is a good nucleophile because it has electrons to donate or share.&nbsp; Bromide, therefore, attacks the carbocation intermediate placing the Br on that carbon. As a result, you get 2-bromobutene from your 2-butyne reactant, as shown below.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2199\/Figure2_(1).bmp?revision=1&amp;size=bestfit&amp;width=442&amp;height=160#fixme#fixme#fixme\" alt=\"Figure2 (1).bmp\" width=\"442\" height=\"160\" \/><\/p>\n<p>Now, what if you have excess HBr?<\/p>\n<\/div>\n<div class=\"mt-section\">\n<h4 id=\"Addition_due_to_excess_HX_present_.3F_yields_a_geminal_dihaloalkane-916\">Addition due to excess HX present yields a geminal dihaloalkane<\/h4>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2200\/Figure3.bmp?revision=1&amp;size=bestfit&amp;width=473&amp;height=166#fixme#fixme#fixme\" alt=\"Figure3.bmp\" width=\"473\" height=\"166\" \/><\/p>\n<p>Here, the electrophilic addition proceeds with the same steps used to achieve the product in addition of a HX to an internal alkyne.&nbsp; The $$\\pi$$ electrons attacked the hydrogen, adding it to the carbon on the left (shown in blue). The hydrogen is added to the left hand carbon forming a carbocation on the carbon with the Br, since this is stabilized by type III resonance.&nbsp; Then the carbocation intermediate is attacked by the bromide resulting in a dihaloalkane product.<\/p>\n<\/div>\n<div class=\"mt-section\">\n<h4 id=\"Addition_of_HX_to_Terminal_Alkyne-916\">Addition of HX to Terminal Alkyne<\/h4>\n<ul>\n<li>Here is an addition of HBr to an asymmetric molecule.<\/li>\n<li>First, try to make sense of how the reactant went to product and then take a look at the mechanism.<\/li>\n<\/ul>\n<p><strong><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2201\/Figure4.1.bmp?revision=1&amp;size=bestfit&amp;width=463&amp;height=252#fixme#fixme#fixme\" alt=\"Figure4.1.bmp\" width=\"463\" height=\"252\" \/><\/strong>\n<\/p>\n<p>The $$\\pi$$ electrons are attacking the hydrogen, depicted by the electron pushing arrows and the bromine gains a negative charge.&nbsp; The carbocation intermediate forms a positive charge on the left carbon after the hydrogen was added to the carbon with the most hydrogen substituents.<\/p>\n<p><strong>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2202\/Figure4.2.bmp?revision=1&amp;size=bestfit&amp;width=325&amp;height=100#fixme#fixme#fixme\" alt=\"Figure4.2.bmp\" width=\"325\" height=\"100\" \/>&nbsp;&nbsp;&nbsp;<\/strong>\n<\/p>\n<p>The bromine, which now exists as bromide with a negative charge, attacks the positively charged carbocation forming the final product with the nucleophile (Br) on the more substituted carbon.<\/p>\n<\/div>\n<div class=\"mt-section\">\n<h4 id=\"Addition_due_to_excess_HBr_present-916\">Addition with excess HBr present<\/h4>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2205\/Figure5.bmp?revision=1&amp;size=bestfit&amp;width=515&amp;height=146#fixme#fixme#fixme\" alt=\"Figure5.bmp\" width=\"515\" height=\"146\" \/><\/p>\n<\/div>\n<\/div>\n<div class=\"mt-section\">\n<p>&nbsp;<\/p>\n<h3 id=\"Reaction:__Halogenation_of_Alkynes-916\"><strong>Reaction:&nbsp; Halogenation of Alkynes<\/strong><\/h3>\n<p><strong>&nbsp;Summary:<\/strong>\n<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201646\/Halogenation_of_Alynes_1.jpg\" alt=\"Halogenation of Alynes (1).JPG\" width=\"355\" height=\"80\" \/><\/p>\n<ul>\n<li>Stereoselectivity: anti addition<\/li>\n<li>Reaction proceeds via cyclic halonium ion<\/li>\n<\/ul>\n<div class=\"mt-section\">\n<h4 id=\"Addition_of_Br2-916\"><strong>Addition of <\/strong><strong>Br<\/strong><sub><strong>2<\/strong><\/sub><\/h4>\n<ul>\n<li>The addition of Br<sub>2<\/sub> to an alkyne is analogous to adding Br<sub>2<\/sub> to an alkene.<\/li>\n<li>Once Br<sub>2<\/sub> approaches the nucleophilic alkyne, it becomes polarized.<\/li>\n<li>The $$\\pi$$ electrons, from the triple bond, can now attack the polarized bromine forming a C-Br bond and displacing the bromide ion.<\/li>\n<li>Now, you will get an intermediate bromonium ion, which will immediately react with the bromide ion giving you the dibromo product.<\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2207\/Figure6.bmp?revision=1&amp;size=bestfit&amp;width=465&amp;height=415#fixme#fixme#fixme\" alt=\"Figure6.bmp\" width=\"465\" height=\"415\" \/><\/p>\n<p>First, you see the polarized Br<sub>2<\/sub> being attacked by the $$\\pi$$ electrons.&nbsp; Once you form the C-Br bond, the other bromine is released as a bromine ion.&nbsp; The intermediate here is a bromonium ion, which is electrophilic and reacts with the bromine ion giving you the dibromo product.<\/p>\n<\/div>\n<\/div>\n<div id=\"section_9\" class=\"mt-section\">\n<h3 id=\"Reaction:__Hydration_of_Alkynes-916\"><strong>Reaction:&nbsp; Hydration of Alkynes<\/strong><\/h3>\n<p><strong>Summary:&nbsp; <\/strong>With the addition of water, alkynes can be hydrated to form enols that spontaneously tautomerize to ketones. Reaction is catalyzed by mercury ions. Follows Markovnikov\u2019s Rule: Terminal alkynes give methyl ketones<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2208\/Figure7.bmp?revision=1&amp;size=bestfit&amp;width=458&amp;height=212#fixme#fixme#fixme\" alt=\"Figure7.bmp\" width=\"458\" height=\"212\" \/><\/p>\n<ul>\n<li>The first step is an acid\/base reaction where the $$\\pi$$ electrons of the triple bond act as a Lewis base and attack the proton, protonating the carbon that has more hydrogens.&nbsp; (Electrophilic addition)<\/li>\n<li>The second step is the attack of the nucleophilic water molecule on the electrophilic carbocation, which creates an oxonium ion.&nbsp; (Coordination)<\/li>\n<li>Next, the positively charged oxygen is deprotonated by water (which is acting as a base), generating an C=C bonded alcohol called an enol.&nbsp; (Acid-base)<\/li>\n<li>The enol then tautomerizes into a ketone, via a mechanism that will be covered in the second semester.&nbsp; Tautomerization is a simultaneous proton and double bond shift, which goes from the enol form to the keto isomer form as shown above in Figure 7.<\/li>\n<\/ul>\n<p>Now let&#8217;s look at some examples of hydration Reactions.<\/p>\n<div id=\"section_10\" class=\"mt-section\">\n<h4 id=\"Hydration_of_Terminal_Alkyne_produces_methyl_ketones-916\">Hydration of terminal alkyne produces methyl ketones<\/h4>\n<p><strong><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2210\/Figure8.bmp?revision=1&amp;size=bestfit&amp;width=462&amp;height=224#fixme#fixme#fixme\" alt=\"Figure8.bmp\" width=\"462\" height=\"224\" \/><\/strong>\n<\/p>\n<p>Just as described in Figure 7 the $$\\pi$$ electrons will attack a proton, forming a carbocation, which then gets attacked by the nucleophilic water molecules.&nbsp; After deprotonation, we generate an enol, which then tautomerizes into the ketone form shown.<\/p>\n<\/div>\n<div id=\"section_11\" class=\"mt-section\">\n<h4 id=\"Hydration_of_Alkyne-916\">Hydration of propyne<\/h4>\n<p>As you can see here, the $$\\pi$$ electrons of the triple bond are attacking the proton, which forms a covalent bond on the carbon with the most hydrogen substituents. Once the hydrogen is bound you have a carbocation, which gets attacked by the water molecule. Now you have a positive charge on the oxygen which results in a base coming in and deprotinating the molecule. Once deprotonated, you have an enol, which then gets tautomerized.<\/p>\n<p><strong><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2211\/Figure9.bmp?revision=1&amp;size=bestfit&amp;width=518&amp;height=161#fixme#fixme#fixme\" alt=\"Figure9.bmp\" width=\"518\" height=\"161\" \/><\/strong>\n<\/p>\n<p>Outside links<\/p>\n<\/div>\n<\/div>\n<div id=\"section_12\" class=\"mt-section\">\n<ul>\n<li><a title=\"http:\/\/www.cem.msu.edu\/~reusch\/VirtualText\/addyne1.htm\" href=\"http:\/\/www.cem.msu.edu\/~reusch\/VirtualText\/addyne1.htm\" target=\"_blank\" rel=\"external nofollow noopener\">http:\/\/www.cem.msu.edu\/~reusch\/VirtualText\/addyne1.htm<\/a><\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"size-thumbnail wp-image-4675 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201648\/static_qr_code_without_logo6-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<ul>\n<li><a title=\"http:\/\/wikipremed.com\/03_organicmechanisms.php?mch_code=030203_010\" href=\"http:\/\/wikipremed.com\/03_organicmechanisms.php?mch_code=030203_010\" target=\"_blank\" rel=\"external nofollow noopener\">http:\/\/wikipremed.com\/03_organicmechanisms.php?mch_code=030203_010<\/a><\/li>\n<\/ul>\n<\/div>\n<div id=\"section_13\" class=\"mt-section\">\n<h3 id=\"References-916\">References<\/h3>\n<ol>\n<li>Vollhardt. Schore, Organic Chemistry Structure and Function Fifth Edition, New York: W.H. Freeman and Company, 2007.<\/li>\n<li>Solomons, T. W. Graham, and Craig B. Fryhle. Organic Chemistry Eighth Edition. Maryland: John Wiley and Sons Incorporated, 2008.<\/li>\n<\/ol>\n<\/div>\n<div id=\"section_14\" class=\"mt-section textbox exercises\">\n<h3 id=\"Practice_Problems-916\">Practice Problems<\/h3>\n<p><strong>1) Reaction:&nbsp; Addition of hydrogen halide to an alkyne<\/strong>\n<\/p>\n<p><strong>1a)<\/strong>&nbsp; What product would result from the reaction of 1-pentyne with Hydrogen Bromide?<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2222\/Practiceproblem1a.bmp?revision=1&amp;size=bestfit&amp;width=349&amp;height=100#fixme#fixme#fixme\" alt=\"Practiceproblem1a.bmp\" width=\"349\" height=\"100\" \/><\/p>\n<p><strong>1b)<\/strong>&nbsp; Take your answer from 1a and add an excess of Hydrogen Bromide.&nbsp; What would be the product?<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2223\/Practiceproblem1b.bmp?revision=1&amp;size=bestfit&amp;width=200&amp;height=60#fixme#fixme#fixme\" alt=\"Practiceproblem1b.bmp\" width=\"200\" height=\"60\" \/><\/p>\n<p><strong>1c)<\/strong>&nbsp;&nbsp; What is the mechanism for this reaction?<\/p>\n<p><strong>2) Reaction:&nbsp; Addition of X<sub>2<\/sub> to alkynes<\/strong>\n<\/p>\n<p><strong>2a)<\/strong>&nbsp; What product would result from the reaction of 1-Pentyne with Br2?<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2224\/Practiceproblem2a_(1).bmp?revision=1&amp;size=bestfit&amp;width=382&amp;height=74#fixme#fixme#fixme\" alt=\"Practiceproblem2a (1).bmp\" width=\"382\" height=\"74\" \/><\/p>\n<p><strong>2b)<\/strong>&nbsp; Take your answer from 2a and add an excess of Br<sub>2<\/sub>.&nbsp; What would be the product?<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/chem.libretexts.org\/@api\/deki\/files\/2223\/Practiceproblem1b.bmp?revision=1&amp;size=bestfit&amp;width=200&amp;height=60#fixme#fixme#fixme\" alt=\"Practiceproblem1b.bmp\" width=\"200\" height=\"60\" \/><\/p>\n<p><strong>2c)<\/strong>&nbsp;&nbsp; What is the mechanism for this reaction?<\/p>\n<p><strong>3) Reaction:&nbsp; Hydration of alkynes<\/strong>\n<\/p>\n<p><strong>3a)<\/strong>&nbsp; If 1-Pentyne were to react with mercury(I) sulfate, water, and sulfuric acid, what would be the product?<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201649\/Practice3_1.jpg\" alt=\"Practice3 (1).JPG\" width=\"328\" height=\"90\" \/><\/p>\n<p><strong>4)<\/strong>&nbsp;&nbsp; What is the product when 3-methylbutyne reacts with HCl? Include in your answer:<br \/>\na)&nbsp;&nbsp;&nbsp; the reaction mechanism<br \/>\nb)&nbsp;&nbsp;&nbsp; a clear explanation for why the hydrogen and chlorine bind to where they do<\/p>\n<p><strong>5)<\/strong>&nbsp; a) Draw the enol form of the Ketone below.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201651\/Problem5a.jpg\" alt=\"Problem5a.JPG\" width=\"410\" height=\"170\" \/><\/p>\n<p>b)&nbsp; Draw the keto form of the enol below.<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"internal default\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201653\/Practice5b.jpg\" alt=\"Practice5b.JPG\" width=\"410\" height=\"170\" \/><\/p>\n<\/div>\n<\/div>\n<div class=\"mt-section\">\n<div class=\"textbox examples\">\n<h3>Further reading<\/h3>\n<p><em>MasterOrganicChemistry<\/em>\n<\/p>\n<ul>\n<li><a class=\"external\" title=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/24\/alkyne-reaction-patterns-the-carbocation-pathway\/\" href=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/24\/alkyne-reaction-patterns-the-carbocation-pathway\/\" target=\"_blank\" rel=\"external nofollow noopener\">Alkyne Reactions Patterns &#8211; The Carbocation Pathway<\/a><\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"size-thumbnail wp-image-4676 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201655\/static_qr_code_without_logo7-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<ul>\n<li><a class=\"external\" title=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/29\/alkyne-addition-pathways-the-3-membered-ring-pathway\/\" href=\"http:\/\/www.masterorganicchemistry.com\/2013\/05\/29\/alkyne-addition-pathways-the-3-membered-ring-pathway\/\" target=\"_blank\" rel=\"external nofollow noopener\">Alkyne Reactions Patterns &#8211; The 3-Membered Ring Pathway<\/a><\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"size-thumbnail wp-image-4677 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201656\/static_qr_code_without_logo2-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<p><em>Carey 5th Ed Online<\/em>\n<\/p>\n<ul>\n<li><a class=\"external\" title=\"http:\/\/www.mhhe.com\/physsci\/chemistry\/carey\/student\/olc\/ch09additionreactionsofalkynes.html\" href=\"http:\/\/www.mhhe.com\/physsci\/chemistry\/carey\/student\/olc\/ch09additionreactionsofalkynes.html\" target=\"_blank\" rel=\"external nofollow noopener\">Addition Reactions of Alkynes<\/a><\/li>\n<\/ul>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"size-thumbnail wp-image-4678 alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201656\/static_qr_code_without_logo7-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<\/div>\n<p><em>Videos<\/em>\n<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignright size-thumbnail wp-image-4679\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201657\/static_qr_code_without_logo3-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"Electrophilic Addition of HCl, HBr, Br2 and Cl2 to Alkynes\" width=\"500\" height=\"375\" src=\"https:\/\/www.youtube.com\/embed\/S0ts6VK7Vyk?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<p><a class=\"link-https\" title=\"https:\/\/www.khanacademy.org\/science\/organic-chemistry\/alkenes-alkynes\/alkyne-reactions\/v\/hydration-of-alkynes\" href=\"https:\/\/www.khanacademy.org\/science\/organic-chemistry\/alkenes-alkynes\/alkyne-reactions\/v\/hydration-of-alkynes\" target=\"_blank\" rel=\"external nofollow noopener\">Hydration of Alkynes<\/a>\n<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignright size-thumbnail wp-image-4680\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3773\/2018\/11\/19201658\/static_qr_code_without_logo8-150x150.png\" alt=\"\" width=\"150\" height=\"150\" \/><\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-2\" title=\"Hydration of alkynes | Alkenes and Alkynes | Organic chemistry | Khan Academy\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/AE1pkp-_cKE?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe>\n<\/div>\n<\/section>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-62\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>11.1.3 Electrophilic Addition to Alkynes. <strong>Authored by<\/strong>: Prof. Hilton Weiss (Bard College), Aleksandra Milman. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/chem.libretexts.org\/LibreTexts\/Purdue\/Purdue%3A_Chem_26605%3A_Organic_Chemistry_II_(Lipton)\/Chapter_11.__Addition_to_pi_Systems\/11.1%3A_Electrophilic_Addition\/11.1.3_Electrophilic_Addition_to_Alkynes\">https:\/\/chem.libretexts.org\/LibreTexts\/Purdue\/Purdue%3A_Chem_26605%3A_Organic_Chemistry_II_(Lipton)\/Chapter_11.__Addition_to_pi_Systems\/11.1%3A_Electrophilic_Addition\/11.1.3_Electrophilic_Addition_to_Alkynes<\/a>. <strong>Project<\/strong>: Chemistry LibreTexts. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":23485,"menu_order":5,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"11.1.3 Electrophilic Addition to Alkynes\",\"author\":\"Prof. Hilton Weiss (Bard College), Aleksandra Milman\",\"organization\":\"\",\"url\":\"https:\/\/chem.libretexts.org\/LibreTexts\/Purdue\/Purdue%3A_Chem_26605%3A_Organic_Chemistry_II_(Lipton)\/Chapter_11.__Addition_to_pi_Systems\/11.1%3A_Electrophilic_Addition\/11.1.3_Electrophilic_Addition_to_Alkynes\",\"project\":\"Chemistry 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