{"id":1264,"date":"2016-04-29T20:21:59","date_gmt":"2016-04-29T20:21:59","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/biologyxwaymakerxmaster\/?post_type=chapter&#038;p=1264"},"modified":"2017-04-18T16:54:58","modified_gmt":"2017-04-18T16:54:58","slug":"chemical-reactions","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/chapter\/chemical-reactions\/","title":{"raw":"Chemical Reactions","rendered":"Chemical Reactions"},"content":{"raw":"<h2>Understand basic chemical reactions<\/h2>\r\nIn this outcome, we will discuss chemical bonds\u00a0and\u00a0reactions.\r\n<div class=\"textbox learning-objectives\">\r\n<h3>Learning Objectives<\/h3>\r\n<ul>\r\n \t<li>Identify the components of simple chemical reactions<\/li>\r\n \t<li>Differentiate between catabolic and anabolic reactions<\/li>\r\n \t<li>Identify enzymes and their role in chemical reactions<\/li>\r\n<\/ul>\r\n<\/div>\r\n<h2>\u00a0Chemical Reactions and Molecules<\/h2>\r\nAll elements are most stable when their outermost shell is filled with electrons according to the octet rule. This is because it is energetically favorable for atoms to be in that configuration and it makes them stable. However, since not all elements have enough electrons to fill their outermost shells, atoms form\u00a0<strong>chemical bonds<\/strong> with other atoms thereby obtaining the electrons they need to attain a stable electron configuration. When two or more atoms chemically bond with each other, the resultant chemical structure is a molecule. The familiar water molecule, H<sub>2<\/sub>O, consists of two hydrogen atoms and one oxygen atom; these bond together to form water, as illustrated in Figure 1. Atoms can form molecules by donating, accepting, or sharing electrons to fill their outer shells.\r\n\r\n[caption id=\"attachment_1537\" align=\"aligncenter\" width=\"800\"]<img class=\"size-full wp-image-1537\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/110\/2016\/05\/02205726\/Figure_02_01_08.jpg\" alt=\"In the first image, an oxygen atom is shown with six valence electrons. Four of these valence electrons form pairs at the top and right sides of the valence shell. The other two electrons are alone on the bottom and left sides. A hydrogen atom sits next to each the lone electron of the oxygen. Each hydrogen has only one valence electron. An arrow indicates that a reaction takes place. After the reaction, in the second image, each unpaired electron in the oxygen joins an electron from one of the hydrogen atoms so that the valence rings are now connected together. The bond that forms between oxygen and hydrogen can also be represented by a dash.\" width=\"800\" height=\"381\" \/> Figure 1. Two or more atoms may bond with each other to form a molecule. When two hydrogens and an oxygen share electrons via covalent bonds, a water molecule is formed.[\/caption]\r\n\r\n<strong>Chemical reactions<\/strong> occur when two or more atoms bond together to form molecules or when bonded atoms are broken apart. The substances used in the beginning of a chemical reaction are called the <strong>reactants<\/strong> (usually found on the left side of a chemical equation), and the substances found at the end of the reaction are known as the <strong>products<\/strong> (usually found on the right side of a chemical equation). An arrow is typically drawn between the reactants and products to indicate the direction of the chemical reaction; this direction is not always a \u201cone-way street.\u201d For the creation of the water molecule shown above, the chemical equation would be:\r\n<p style=\"text-align: center;\">2H + O \u2192 H<sub>2<\/sub>O<\/p>\r\nAn example of a simple chemical reaction is the breaking down of hydrogen peroxide molecules, each of which consists of two hydrogen atoms bonded to two oxygen atoms (H<sub>2<\/sub>O<sub>2<\/sub>). The reactant hydrogen peroxide is broken down into water, containing one oxygen atom bound to two hydrogen atoms (H<sub>2<\/sub>O), and oxygen, which consists of two bonded oxygen atoms (O<sub>2<\/sub>). In the equation below, the reaction includes two hydrogen peroxide molecules and two water molecules. This is an example of a\u00a0<strong>balanced chemical equation<\/strong>, wherein the number of atoms of each element is the same on each side of the equation. According to the law of conservation of matter, the number of atoms before and after a chemical reaction should be equal, such that no atoms are, under normal circumstances, created or destroyed.\r\n<p style=\"text-align: center;\"><span class=\"msub\"><span class=\"mrow\"><span class=\"mtext\">H<sub>2<\/sub>O<sub>2<\/sub>\u00a0(hydrogen peroxide) \u2192\u00a0H<sub>2<\/sub>O(water) + O<\/span><\/span><span class=\"mn\"><sub>2<\/sub><\/span><\/span> (oxygen)<\/p>\r\nEven though all of the reactants and products of this reaction are molecules (each atom remains bonded to at least one other atom), in this reaction only hydrogen peroxide and water are representative of a subclass of molecules known as\u00a0<strong>compounds<\/strong>: they contain atoms of more than one type of element. Molecular oxygen, on the other hand, as shown in Figure 2, consists of two doubly bonded oxygen atoms and is not classified as a compound but as an element.\r\n\r\n[caption id=\"attachment_1539\" align=\"aligncenter\" width=\"800\"]<img class=\"size-full wp-image-1539\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/110\/2016\/05\/02205803\/Figure_02_01_09.jpg\" alt=\" Two oxygen atoms are shown side-by-side. Each has six valence electrons, two that are paired and two that are unpaired. An arrow indicates that a reaction takes place. After the reaction, the four unpaired electrons join to form a double bond. This double bond can also be depicted by an equal sign between two Os.\" width=\"800\" height=\"198\" \/> Figure 2. The oxygen atoms in an O<sub>2<\/sub> molecule are joined by a double bond.[\/caption]\r\n\r\nSome chemical reactions, such as the one shown above, can proceed in one direction until the reactants are all used up. The equations that describe these reactions contain a unidirectional arrow and are\u00a0<strong>irreversible<\/strong>. <strong>Reversible reactions<\/strong> are those that can go in either direction. In reversible reactions, reactants are turned into products, but when the concentration of product goes beyond a certain threshold (characteristic of the particular reaction), some of these products will be converted back into reactants; at this point, the designations of products and reactants are reversed. This back and forth continues until a certain relative balance between reactants and products occurs\u2014a state called <strong>equilibrium<\/strong>. These situations of reversible reactions are often denoted by a chemical equation with a double headed arrow pointing towards both the reactants and products.\r\n\r\nFor example, in human blood, excess hydrogen ions (H<sup>+<\/sup>) bind to bicarbonate ions (HCO<sub>3<\/sub><sup>\u2013<\/sup>) forming an equilibrium state with carbonic acid (H<sub>2<\/sub>CO<sub>3<\/sub>). If carbonic acid were added to this system, some of it would be converted to bicarbonate and hydrogen ions.\r\n<p style=\"text-align: center;\">HCO<sub>3<\/sub><sup>\u2013<\/sup>\u00a0+ H<sup>+<\/sup> \u2194\u00a0H<sub>2<\/sub>CO<sub>3<\/sub><\/p>\r\nIn biological reactions, however, equilibrium is rarely obtained because the concentrations of the reactants or products or both are constantly changing, often with a product of one reaction being a reactant for another. To return to the example of excess hydrogen ions in the blood, the formation of carbonic acid will be the major direction of the reaction. However, the carbonic acid can also leave the body as carbon dioxide gas (via exhalation) instead of being converted back to bicarbonate ion, thus driving the reaction to the right by the chemical law known as\u00a0<strong>law of mass action<\/strong>. These reactions are important for maintaining the homeostasis of our blood.\r\n<p style=\"text-align: center;\">CO<sub>3<\/sub> \u2194 CO<sub>2<\/sub> + H<sub>2<\/sub>O<\/p>\r\n\r\n<h2>Anabolic and Catabolic Pathways<\/h2>\r\nAnabolic pathways require an input of energy to synthesize complex molecules from simpler ones. Synthesizing sugar from CO<sub>2<\/sub> is one example. Other examples are the synthesis of large proteins from amino acid building blocks, and the synthesis of new DNA strands from nucleic acid building blocks. These biosynthetic processes are critical to the life of the cell, take place constantly, and demand energy provided by ATP and other high-energy molecules like NADH (nicotinamide adenine dinucleotide) and NADPH (Figure 3).\r\n\r\nATP is an important molecule for cells to have in sufficient supply at all times. The breakdown of sugars illustrates how a single molecule of glucose can store enough energy to make a great deal of ATP, 36 to 38 molecules. This is a catabolic pathway. Catabolic pathways involve the degradation (or breakdown) of complex molecules into simpler ones. Molecular energy stored in the bonds of complex molecules is released in catabolic pathways and harvested in such a way that it can be used to produce ATP. Other energy-storing molecules, such as fats, are also broken down through similar catabolic reactions to release energy and make ATP (Figure 3).\r\n\r\n[caption id=\"attachment_1662\" align=\"aligncenter\" width=\"800\"]<img class=\"size-full wp-image-1662\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/110\/2016\/05\/02235219\/Figure_06_01_03.jpg\" alt=\"Anabolic and catabolic pathways are shown. In the anabolic pathway (top), four small molecules have energy added to them to make one large molecule. In the catabolic pathway (bottom), one large molecule is broken down into two components: four small molecules plus energy.\" width=\"800\" height=\"255\" \/> Figure 3. Anabolic pathways are those that require energy to synthesize larger molecules. Catabolic pathways are those that generate energy by breaking down larger molecules. Both types of pathways are required for maintaining the cell\u2019s energy balance.[\/caption]\r\n\r\nIt is important to know that the chemical reactions of metabolic pathways don\u2019t take place spontaneously. Each reaction step is facilitated, or catalyzed, by a protein called an enzyme. Enzymes are important for catalyzing all types of biological reactions\u2014those that require energy as well as those that release energy.\r\n<h2>Enzymes<\/h2>\r\nEnzymes are proteins that have the ability to bind substrate in their active site and then chemically modify the bound substrate, converting it to a different molecule \u2014 the <em class=\"bold\">product<\/em> of the reaction. <em class=\"bold\">Substrates<\/em> bind to enzymes just like ligands bind to proteins. However, when substrates bind to enzymes, they undergo an enzyme-induced chemical change, and are converted to products.\r\n\r\n[caption id=\"\" align=\"alignright\" width=\"346\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/110\/2016\/05\/04195107\/image12.png\" alt=\"A protein enveloping a ligand with a binding site (protein-ligand). An enzyme enveloping a substrate with an active site (enzyme-substrate).\" width=\"346\" height=\"145\" \/> Figure 4. Compare the protein-ligand interaction to the enzyme-substrate interaction. Notice that both binding proteins and enzymes have binding sites for their ligands (L) and substrates (S), respectively. This area of the enzyme is called the active site because it also contains amino acids that are important for the conversion of substrate to product.[\/caption]\r\n\r\nThe substrate binds to the enzyme by interacting with amino acids in the <em class=\"bold\">binding site<\/em>. The binding site on enzymes is often referred to as the <em class=\"bold\">active site<\/em> because it contains amino acids that both bind the substrate and aid in its conversion to product.\r\n\r\nYou can often recognize that a protein is an enzyme by its name. Many enzyme names end with -<em>ase<\/em>. For example, the enzyme lactase is used to break down the sugar lactose, found in mammalian milk. Other enzymes are known by a common name, such as pepsin, which is an enzyme that aids in the digestion of proteins in your stomach by breaking the peptide bonds in the proteins.\r\n\r\nEnzymes are catalysts, meaning that they make a reaction go faster, but the enzymes themselves are not altered by the overall reaction. Examine this image to see how enzymes work.\r\n\r\n[caption id=\"attachment_1834\" align=\"aligncenter\" width=\"1024\"]<img class=\"size-large wp-image-1834\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/110\/2016\/05\/04194008\/1024px-Induced_fit_diagram.svg_-1024x400.png\" alt=\"A substrate fits onto the active site of an enzyme. Both the enzyme and substrate are uniquely shaped for one another. The enzyme breaks down the substrate to create products.\" width=\"1024\" height=\"400\" \/> Figure 5. Simplified enzymatic reaction. The substrate reversibly binds to the active site of the enzyme, forming the enzyme-substrate (ES) complex. The bound substrate is converted to product by catalytic groups in the active site, forming the enzyme-product complex (EP). The bound products are released, returning the enzyme to its unbound form, ready to catalyze another round of converting substrate to product.[\/caption]\r\n\r\nThe amino acids in the active site of enzymes play two roles, and sometimes those roles overlap. Some of the amino acids in the active site are responsible for binding of the substrate and others are responsible for facilitating the chemical reaction. Enzymes are generally quite specific for their substrates. Although lactase and pepsin both catalyze the same type of reaction, breaking a bond using water (hydrolysis: \"hydro\" means \"water\" and \"lysis\" means \"to break\"), lactase only functions when lactose is its substrate and pepsin can only break peptide bonds.\r\n<div class=\"textbox exercises\">\r\n<h3>Practice Question<\/h3>\r\nTwo substrates\u2014lactose and a short protein\u2014are shown on the left. Two enzymes are shown\u00a0on the right, labeled A and B. Which of the two enzymes is lactase?\r\n\r\n<img class=\"alignnone wp-image-843 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/414\/2015\/05\/21035018\/Screen-Shot-2015-05-28-at-12.13.27-PM.png\" alt=\"Lactose is shown as two hexagonal shapes bound together with a straight line. The short protein is four rectangles all connected in a straight line. Enzyme A has two indents shaped like the bottom of hexagons. Enyzme B has two indents each shaped like the bottom half of irregular four sided shapes.\" width=\"470\" height=\"71\" \/>\r\n[practice-area rows=\"2\"][\/practice-area]\r\n[reveal-answer q=\"551250\"]<strong>Show Answer<\/strong>[\/reveal-answer]\r\n[hidden-answer a=\"551250\"]Enzyme A. The active site on this enzyme is the same shape as lactose.\u00a0The hexagonal shape on the lactose is a poor fit for the rectangular shaped active site on\u00a0enzyme B.[\/hidden-answer]\r\n\r\n<\/div>\r\n<h3>How Enzymes Work<\/h3>\r\n[caption id=\"attachment_1835\" align=\"alignright\" width=\"504\"]<img class=\"wp-image-1835 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/110\/2016\/05\/04194237\/504px-Activation2_updated.svg_.png\" alt=\"A noncatalyzed reaction and an enzyme-catalyzed reaction.\" width=\"504\" height=\"395\" \/> Figure 6.\u00a0Diagram of a catalytic reaction showing difference in activation energy in uncatalysed and catalysed reaction. The enzyme reduces the energy barrier required to activate the substrate, allowing more substrates to become activated, which increases the rate of product formation. Note that the energy difference between the substrate and the product is not changed by the enzyme.[\/caption]\r\n\r\nIn all chemical reactions, there is an initial input of energy that is required before the reaction can occur. If this initial energy requirement (called the activation energy or energy barrier) is small, then the reaction will happen quickly and easily. If the activation energy is large, then the reaction will take longer to occur. Enzymes function to reduce the activation energy required for a chemical reaction to occur.\r\n\r\nFirst, the enzyme binds to the substrate and slightly distorts its shape. The change in shape activates the substrate molecule and decreases the total activation energy required for the substrate to be turned into product. As the number of activated substrate molecules increases, so does the conversion of substrate to product. An analogy for this effect is a ski hill, with skiers at the bottom of one side of the hill representing substrates, skiers on the top of the hill representing activated substrates, and the products being the number of skiers that ski down the other side. If the height of the hill is lowered (due to the presence of the enzyme), then more skiers can make it to the top, increasing the number that ski down to become products.\r\n<div class=\"textbox exercises\">\r\n<h3>Practice Questions<\/h3>\r\nFill in the blank: When an enzyme catalyzes a reaction, ________.\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>it raises the activation energy of the reaction.<\/li>\r\n \t<li>it is used once and discarded.<\/li>\r\n \t<li>it becomes a product.<\/li>\r\n \t<li>it acts as a reactant.<\/li>\r\n \t<li>it lowers the activation energy of the reaction.<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"101995\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"101995\"]Answer e. When an enzyme catalyzes a reaction, it lowers the activation energy of the reaction; lowering the activation energy of a reaction makes it more likely to occur.\r\n\r\n[\/hidden-answer]\r\n\r\nWhat will happen to the rate at which a chemical reaction proceeds if the activation energy is increased?\r\n<ol style=\"list-style-type: lower-alpha;\">\r\n \t<li>The reaction will happen faster (at a higher rate).<\/li>\r\n \t<li>The reaction will happen slower (at a lower rate).<\/li>\r\n \t<li>The reaction rate will not change.<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"42089\"]<strong>Show Answers<\/strong>[\/reveal-answer]\r\n[hidden-answer a=\"42089\"]Answer b. If the activation energy goes up, then more energy is required for the reaction to occur, so it\u00a0will happen less often.[\/hidden-answer]\r\n\r\n<\/div>\r\n<div class=\"textbox learning-objectives\">\r\n<h3>In Summary: Chemical Reactions<\/h3>\r\nThe outer electron shell dictates how readily and what type of chemical bonds a particular atom will form. The formation of compounds is often visually outlined in chemical equations which show the reactants participating in chemical reactions to form products.\r\n\r\nAnabolic pathways assemble large molecules form smaller ones. Catabolic pathways break large molecules into small pieces.\r\n\r\nEnzymes are proteins that speed up reactions by reducing the activation energy. Each enzyme typically binds only one substrate. Enzymes are not consumed during a reaction; instead they are available to bind new substrates and catalyze the same reaction repeatedly.\r\n\r\n<\/div>\r\n<h2><strong>Check Your Understanding<\/strong><\/h2>\r\nAnswer the question(s) below to see how well you understand the topics covered in the previous section. This short quiz does\u00a0<strong>not<\/strong>\u00a0count toward your grade in the class, and you can retake it an unlimited number of times.\r\n\r\nUse this quiz to check your understanding and decide whether to (1) study the previous section further or (2) move on to the next section.\r\n\r\nhttps:\/\/assessments.lumenlearning.com\/assessments\/3315","rendered":"<h2>Understand basic chemical reactions<\/h2>\n<p>In this outcome, we will discuss chemical bonds\u00a0and\u00a0reactions.<\/p>\n<div class=\"textbox learning-objectives\">\n<h3>Learning Objectives<\/h3>\n<ul>\n<li>Identify the components of simple chemical reactions<\/li>\n<li>Differentiate between catabolic and anabolic reactions<\/li>\n<li>Identify enzymes and their role in chemical reactions<\/li>\n<\/ul>\n<\/div>\n<h2>\u00a0Chemical Reactions and Molecules<\/h2>\n<p>All elements are most stable when their outermost shell is filled with electrons according to the octet rule. This is because it is energetically favorable for atoms to be in that configuration and it makes them stable. However, since not all elements have enough electrons to fill their outermost shells, atoms form\u00a0<strong>chemical bonds<\/strong> with other atoms thereby obtaining the electrons they need to attain a stable electron configuration. When two or more atoms chemically bond with each other, the resultant chemical structure is a molecule. The familiar water molecule, H<sub>2<\/sub>O, consists of two hydrogen atoms and one oxygen atom; these bond together to form water, as illustrated in Figure 1. Atoms can form molecules by donating, accepting, or sharing electrons to fill their outer shells.<\/p>\n<div id=\"attachment_1537\" style=\"width: 810px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-1537\" class=\"size-full wp-image-1537\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/110\/2016\/05\/02205726\/Figure_02_01_08.jpg\" alt=\"In the first image, an oxygen atom is shown with six valence electrons. Four of these valence electrons form pairs at the top and right sides of the valence shell. The other two electrons are alone on the bottom and left sides. A hydrogen atom sits next to each the lone electron of the oxygen. Each hydrogen has only one valence electron. An arrow indicates that a reaction takes place. After the reaction, in the second image, each unpaired electron in the oxygen joins an electron from one of the hydrogen atoms so that the valence rings are now connected together. The bond that forms between oxygen and hydrogen can also be represented by a dash.\" width=\"800\" height=\"381\" \/><\/p>\n<p id=\"caption-attachment-1537\" class=\"wp-caption-text\">Figure 1. Two or more atoms may bond with each other to form a molecule. When two hydrogens and an oxygen share electrons via covalent bonds, a water molecule is formed.<\/p>\n<\/div>\n<p><strong>Chemical reactions<\/strong> occur when two or more atoms bond together to form molecules or when bonded atoms are broken apart. The substances used in the beginning of a chemical reaction are called the <strong>reactants<\/strong> (usually found on the left side of a chemical equation), and the substances found at the end of the reaction are known as the <strong>products<\/strong> (usually found on the right side of a chemical equation). An arrow is typically drawn between the reactants and products to indicate the direction of the chemical reaction; this direction is not always a \u201cone-way street.\u201d For the creation of the water molecule shown above, the chemical equation would be:<\/p>\n<p style=\"text-align: center;\">2H + O \u2192 H<sub>2<\/sub>O<\/p>\n<p>An example of a simple chemical reaction is the breaking down of hydrogen peroxide molecules, each of which consists of two hydrogen atoms bonded to two oxygen atoms (H<sub>2<\/sub>O<sub>2<\/sub>). The reactant hydrogen peroxide is broken down into water, containing one oxygen atom bound to two hydrogen atoms (H<sub>2<\/sub>O), and oxygen, which consists of two bonded oxygen atoms (O<sub>2<\/sub>). In the equation below, the reaction includes two hydrogen peroxide molecules and two water molecules. This is an example of a\u00a0<strong>balanced chemical equation<\/strong>, wherein the number of atoms of each element is the same on each side of the equation. According to the law of conservation of matter, the number of atoms before and after a chemical reaction should be equal, such that no atoms are, under normal circumstances, created or destroyed.<\/p>\n<p style=\"text-align: center;\"><span class=\"msub\"><span class=\"mrow\"><span class=\"mtext\">H<sub>2<\/sub>O<sub>2<\/sub>\u00a0(hydrogen peroxide) \u2192\u00a0H<sub>2<\/sub>O(water) + O<\/span><\/span><span class=\"mn\"><sub>2<\/sub><\/span><\/span> (oxygen)<\/p>\n<p>Even though all of the reactants and products of this reaction are molecules (each atom remains bonded to at least one other atom), in this reaction only hydrogen peroxide and water are representative of a subclass of molecules known as\u00a0<strong>compounds<\/strong>: they contain atoms of more than one type of element. Molecular oxygen, on the other hand, as shown in Figure 2, consists of two doubly bonded oxygen atoms and is not classified as a compound but as an element.<\/p>\n<div id=\"attachment_1539\" style=\"width: 810px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-1539\" class=\"size-full wp-image-1539\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/110\/2016\/05\/02205803\/Figure_02_01_09.jpg\" alt=\"Two oxygen atoms are shown side-by-side. Each has six valence electrons, two that are paired and two that are unpaired. An arrow indicates that a reaction takes place. After the reaction, the four unpaired electrons join to form a double bond. This double bond can also be depicted by an equal sign between two Os.\" width=\"800\" height=\"198\" \/><\/p>\n<p id=\"caption-attachment-1539\" class=\"wp-caption-text\">Figure 2. The oxygen atoms in an O<sub>2<\/sub> molecule are joined by a double bond.<\/p>\n<\/div>\n<p>Some chemical reactions, such as the one shown above, can proceed in one direction until the reactants are all used up. The equations that describe these reactions contain a unidirectional arrow and are\u00a0<strong>irreversible<\/strong>. <strong>Reversible reactions<\/strong> are those that can go in either direction. In reversible reactions, reactants are turned into products, but when the concentration of product goes beyond a certain threshold (characteristic of the particular reaction), some of these products will be converted back into reactants; at this point, the designations of products and reactants are reversed. This back and forth continues until a certain relative balance between reactants and products occurs\u2014a state called <strong>equilibrium<\/strong>. These situations of reversible reactions are often denoted by a chemical equation with a double headed arrow pointing towards both the reactants and products.<\/p>\n<p>For example, in human blood, excess hydrogen ions (H<sup>+<\/sup>) bind to bicarbonate ions (HCO<sub>3<\/sub><sup>\u2013<\/sup>) forming an equilibrium state with carbonic acid (H<sub>2<\/sub>CO<sub>3<\/sub>). If carbonic acid were added to this system, some of it would be converted to bicarbonate and hydrogen ions.<\/p>\n<p style=\"text-align: center;\">HCO<sub>3<\/sub><sup>\u2013<\/sup>\u00a0+ H<sup>+<\/sup> \u2194\u00a0H<sub>2<\/sub>CO<sub>3<\/sub><\/p>\n<p>In biological reactions, however, equilibrium is rarely obtained because the concentrations of the reactants or products or both are constantly changing, often with a product of one reaction being a reactant for another. To return to the example of excess hydrogen ions in the blood, the formation of carbonic acid will be the major direction of the reaction. However, the carbonic acid can also leave the body as carbon dioxide gas (via exhalation) instead of being converted back to bicarbonate ion, thus driving the reaction to the right by the chemical law known as\u00a0<strong>law of mass action<\/strong>. These reactions are important for maintaining the homeostasis of our blood.<\/p>\n<p style=\"text-align: center;\">CO<sub>3<\/sub> \u2194 CO<sub>2<\/sub> + H<sub>2<\/sub>O<\/p>\n<h2>Anabolic and Catabolic Pathways<\/h2>\n<p>Anabolic pathways require an input of energy to synthesize complex molecules from simpler ones. Synthesizing sugar from CO<sub>2<\/sub> is one example. Other examples are the synthesis of large proteins from amino acid building blocks, and the synthesis of new DNA strands from nucleic acid building blocks. These biosynthetic processes are critical to the life of the cell, take place constantly, and demand energy provided by ATP and other high-energy molecules like NADH (nicotinamide adenine dinucleotide) and NADPH (Figure 3).<\/p>\n<p>ATP is an important molecule for cells to have in sufficient supply at all times. The breakdown of sugars illustrates how a single molecule of glucose can store enough energy to make a great deal of ATP, 36 to 38 molecules. This is a catabolic pathway. Catabolic pathways involve the degradation (or breakdown) of complex molecules into simpler ones. Molecular energy stored in the bonds of complex molecules is released in catabolic pathways and harvested in such a way that it can be used to produce ATP. Other energy-storing molecules, such as fats, are also broken down through similar catabolic reactions to release energy and make ATP (Figure 3).<\/p>\n<div id=\"attachment_1662\" style=\"width: 810px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-1662\" class=\"size-full wp-image-1662\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/110\/2016\/05\/02235219\/Figure_06_01_03.jpg\" alt=\"Anabolic and catabolic pathways are shown. In the anabolic pathway (top), four small molecules have energy added to them to make one large molecule. In the catabolic pathway (bottom), one large molecule is broken down into two components: four small molecules plus energy.\" width=\"800\" height=\"255\" \/><\/p>\n<p id=\"caption-attachment-1662\" class=\"wp-caption-text\">Figure 3. Anabolic pathways are those that require energy to synthesize larger molecules. Catabolic pathways are those that generate energy by breaking down larger molecules. Both types of pathways are required for maintaining the cell\u2019s energy balance.<\/p>\n<\/div>\n<p>It is important to know that the chemical reactions of metabolic pathways don\u2019t take place spontaneously. Each reaction step is facilitated, or catalyzed, by a protein called an enzyme. Enzymes are important for catalyzing all types of biological reactions\u2014those that require energy as well as those that release energy.<\/p>\n<h2>Enzymes<\/h2>\n<p>Enzymes are proteins that have the ability to bind substrate in their active site and then chemically modify the bound substrate, converting it to a different molecule \u2014 the <em class=\"bold\">product<\/em> of the reaction. <em class=\"bold\">Substrates<\/em> bind to enzymes just like ligands bind to proteins. However, when substrates bind to enzymes, they undergo an enzyme-induced chemical change, and are converted to products.<\/p>\n<div style=\"width: 356px\" class=\"wp-caption alignright\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/110\/2016\/05\/04195107\/image12.png\" alt=\"A protein enveloping a ligand with a binding site (protein-ligand). An enzyme enveloping a substrate with an active site (enzyme-substrate).\" width=\"346\" height=\"145\" \/><\/p>\n<p class=\"wp-caption-text\">Figure 4. Compare the protein-ligand interaction to the enzyme-substrate interaction. Notice that both binding proteins and enzymes have binding sites for their ligands (L) and substrates (S), respectively. This area of the enzyme is called the active site because it also contains amino acids that are important for the conversion of substrate to product.<\/p>\n<\/div>\n<p>The substrate binds to the enzyme by interacting with amino acids in the <em class=\"bold\">binding site<\/em>. The binding site on enzymes is often referred to as the <em class=\"bold\">active site<\/em> because it contains amino acids that both bind the substrate and aid in its conversion to product.<\/p>\n<p>You can often recognize that a protein is an enzyme by its name. Many enzyme names end with &#8211;<em>ase<\/em>. For example, the enzyme lactase is used to break down the sugar lactose, found in mammalian milk. Other enzymes are known by a common name, such as pepsin, which is an enzyme that aids in the digestion of proteins in your stomach by breaking the peptide bonds in the proteins.<\/p>\n<p>Enzymes are catalysts, meaning that they make a reaction go faster, but the enzymes themselves are not altered by the overall reaction. Examine this image to see how enzymes work.<\/p>\n<div id=\"attachment_1834\" style=\"width: 1034px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-1834\" class=\"size-large wp-image-1834\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/110\/2016\/05\/04194008\/1024px-Induced_fit_diagram.svg_-1024x400.png\" alt=\"A substrate fits onto the active site of an enzyme. Both the enzyme and substrate are uniquely shaped for one another. The enzyme breaks down the substrate to create products.\" width=\"1024\" height=\"400\" \/><\/p>\n<p id=\"caption-attachment-1834\" class=\"wp-caption-text\">Figure 5. Simplified enzymatic reaction. The substrate reversibly binds to the active site of the enzyme, forming the enzyme-substrate (ES) complex. The bound substrate is converted to product by catalytic groups in the active site, forming the enzyme-product complex (EP). The bound products are released, returning the enzyme to its unbound form, ready to catalyze another round of converting substrate to product.<\/p>\n<\/div>\n<p>The amino acids in the active site of enzymes play two roles, and sometimes those roles overlap. Some of the amino acids in the active site are responsible for binding of the substrate and others are responsible for facilitating the chemical reaction. Enzymes are generally quite specific for their substrates. Although lactase and pepsin both catalyze the same type of reaction, breaking a bond using water (hydrolysis: &#8220;hydro&#8221; means &#8220;water&#8221; and &#8220;lysis&#8221; means &#8220;to break&#8221;), lactase only functions when lactose is its substrate and pepsin can only break peptide bonds.<\/p>\n<div class=\"textbox exercises\">\n<h3>Practice Question<\/h3>\n<p>Two substrates\u2014lactose and a short protein\u2014are shown on the left. Two enzymes are shown\u00a0on the right, labeled A and B. Which of the two enzymes is lactase?<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-843 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/414\/2015\/05\/21035018\/Screen-Shot-2015-05-28-at-12.13.27-PM.png\" alt=\"Lactose is shown as two hexagonal shapes bound together with a straight line. The short protein is four rectangles all connected in a straight line. Enzyme A has two indents shaped like the bottom of hexagons. Enyzme B has two indents each shaped like the bottom half of irregular four sided shapes.\" width=\"470\" height=\"71\" \/><br \/>\n<textarea aria-label=\"Your Answer\" rows=\"2\"><\/textarea><\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q551250\"><strong>Show Answer<\/strong><\/span><\/p>\n<div id=\"q551250\" class=\"hidden-answer\" style=\"display: none\">Enzyme A. The active site on this enzyme is the same shape as lactose.\u00a0The hexagonal shape on the lactose is a poor fit for the rectangular shaped active site on\u00a0enzyme B.<\/div>\n<\/div>\n<\/div>\n<h3>How Enzymes Work<\/h3>\n<div id=\"attachment_1835\" style=\"width: 514px\" class=\"wp-caption alignright\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-1835\" class=\"wp-image-1835 size-full\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/110\/2016\/05\/04194237\/504px-Activation2_updated.svg_.png\" alt=\"A noncatalyzed reaction and an enzyme-catalyzed reaction.\" width=\"504\" height=\"395\" \/><\/p>\n<p id=\"caption-attachment-1835\" class=\"wp-caption-text\">Figure 6.\u00a0Diagram of a catalytic reaction showing difference in activation energy in uncatalysed and catalysed reaction. The enzyme reduces the energy barrier required to activate the substrate, allowing more substrates to become activated, which increases the rate of product formation. Note that the energy difference between the substrate and the product is not changed by the enzyme.<\/p>\n<\/div>\n<p>In all chemical reactions, there is an initial input of energy that is required before the reaction can occur. If this initial energy requirement (called the activation energy or energy barrier) is small, then the reaction will happen quickly and easily. If the activation energy is large, then the reaction will take longer to occur. Enzymes function to reduce the activation energy required for a chemical reaction to occur.<\/p>\n<p>First, the enzyme binds to the substrate and slightly distorts its shape. The change in shape activates the substrate molecule and decreases the total activation energy required for the substrate to be turned into product. As the number of activated substrate molecules increases, so does the conversion of substrate to product. An analogy for this effect is a ski hill, with skiers at the bottom of one side of the hill representing substrates, skiers on the top of the hill representing activated substrates, and the products being the number of skiers that ski down the other side. If the height of the hill is lowered (due to the presence of the enzyme), then more skiers can make it to the top, increasing the number that ski down to become products.<\/p>\n<div class=\"textbox exercises\">\n<h3>Practice Questions<\/h3>\n<p>Fill in the blank: When an enzyme catalyzes a reaction, ________.<\/p>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>it raises the activation energy of the reaction.<\/li>\n<li>it is used once and discarded.<\/li>\n<li>it becomes a product.<\/li>\n<li>it acts as a reactant.<\/li>\n<li>it lowers the activation energy of the reaction.<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q101995\">Show Answer<\/span><\/p>\n<div id=\"q101995\" class=\"hidden-answer\" style=\"display: none\">Answer e. When an enzyme catalyzes a reaction, it lowers the activation energy of the reaction; lowering the activation energy of a reaction makes it more likely to occur.<\/p>\n<\/div>\n<\/div>\n<p>What will happen to the rate at which a chemical reaction proceeds if the activation energy is increased?<\/p>\n<ol style=\"list-style-type: lower-alpha;\">\n<li>The reaction will happen faster (at a higher rate).<\/li>\n<li>The reaction will happen slower (at a lower rate).<\/li>\n<li>The reaction rate will not change.<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q42089\"><strong>Show Answers<\/strong><\/span><\/p>\n<div id=\"q42089\" class=\"hidden-answer\" style=\"display: none\">Answer b. If the activation energy goes up, then more energy is required for the reaction to occur, so it\u00a0will happen less often.<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox learning-objectives\">\n<h3>In Summary: Chemical Reactions<\/h3>\n<p>The outer electron shell dictates how readily and what type of chemical bonds a particular atom will form. The formation of compounds is often visually outlined in chemical equations which show the reactants participating in chemical reactions to form products.<\/p>\n<p>Anabolic pathways assemble large molecules form smaller ones. Catabolic pathways break large molecules into small pieces.<\/p>\n<p>Enzymes are proteins that speed up reactions by reducing the activation energy. Each enzyme typically binds only one substrate. Enzymes are not consumed during a reaction; instead they are available to bind new substrates and catalyze the same reaction repeatedly.<\/p>\n<\/div>\n<h2><strong>Check Your Understanding<\/strong><\/h2>\n<p>Answer the question(s) below to see how well you understand the topics covered in the previous section. This short quiz does\u00a0<strong>not<\/strong>\u00a0count toward your grade in the class, and you can retake it an unlimited number of times.<\/p>\n<p>Use this quiz to check your understanding and decide whether to (1) study the previous section further or (2) move on to the next section.<\/p>\n<p>\t<iframe id=\"lumen_assessment_3315\" class=\"resizable\" src=\"https:\/\/assessments.lumenlearning.com\/assessments\/load?assessment_id=3315&#38;embed=1&#38;external_user_id=&#38;external_context_id=&#38;iframe_resize_id=lumen_assessment_3315\" frameborder=\"0\" style=\"border:none;width:100%;height:100%;min-height:400px;\"><br \/>\n\t<\/iframe><\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1264\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Original<\/div><ul class=\"citation-list\"><li>Introduction to Chemical Reactions. <strong>Authored by<\/strong>: Shelli Carter and Lumen Learning. <strong>Provided by<\/strong>: Lumen Learning. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><\/ul><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Biology. <strong>Provided by<\/strong>: OpenStax CNX. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/185cbf87-c72e-48f5-b51e-f14f21b5eabd@10.8\">http:\/\/cnx.org\/contents\/185cbf87-c72e-48f5-b51e-f14f21b5eabd@10.8<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download for free at http:\/\/cnx.org\/contents\/185cbf87-c72e-48f5-b51e-f14f21b5eabd@10.8<\/li><li>How Enzymes Work. <strong>Provided by<\/strong>: Open Learning Initiative. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/oli.cmu.edu\/jcourse\/workbook\/activity\/page?context=434a5d6380020ca600f6190aedc2f27b\">https:\/\/oli.cmu.edu\/jcourse\/workbook\/activity\/page?context=434a5d6380020ca600f6190aedc2f27b<\/a>. <strong>Project<\/strong>: Introduction to Biology (Open + Free). <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-nc-sa\/4.0\/\">CC BY-NC-SA: Attribution-NonCommercial-ShareAlike<\/a><\/em><\/li><li>Induced fit diagram. <strong>Authored by<\/strong>: TimVickers; vectorized by Fvasconcellos. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/en.wikipedia.org\/wiki\/File:Induced_fit_diagram.svg\">https:\/\/en.wikipedia.org\/wiki\/File:Induced_fit_diagram.svg<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/about\/cc0\">CC0: No Rights Reserved<\/a><\/em><\/li><li>Activation2 updated. <strong>Authored by<\/strong>: Jerry Crimson Mann, vectorized by Tutmosis, corrected by Fvasconcellos. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/commons.wikimedia.org\/wiki\/File:Activation2_updated.svg\">https:\/\/commons.wikimedia.org\/wiki\/File:Activation2_updated.svg<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by-sa\/4.0\/\">CC BY-SA: Attribution-ShareAlike<\/a><\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":17,"menu_order":6,"template":"","meta":{"_candela_citation":"[{\"type\":\"original\",\"description\":\"Introduction to Chemical Reactions\",\"author\":\"Shelli Carter and Lumen Learning\",\"organization\":\"Lumen Learning\",\"url\":\"\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"\"},{\"type\":\"cc\",\"description\":\"Biology\",\"author\":\"\",\"organization\":\"OpenStax CNX\",\"url\":\"http:\/\/cnx.org\/contents\/185cbf87-c72e-48f5-b51e-f14f21b5eabd@10.8\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download for free at http:\/\/cnx.org\/contents\/185cbf87-c72e-48f5-b51e-f14f21b5eabd@10.8\"},{\"type\":\"cc\",\"description\":\"How Enzymes Work\",\"author\":\"\",\"organization\":\"Open Learning Initiative\",\"url\":\"https:\/\/oli.cmu.edu\/jcourse\/workbook\/activity\/page?context=434a5d6380020ca600f6190aedc2f27b\",\"project\":\"Introduction to Biology (Open + Free)\",\"license\":\"cc-by-nc-sa\",\"license_terms\":\"\"},{\"type\":\"cc\",\"description\":\"Induced fit diagram\",\"author\":\"TimVickers; vectorized by Fvasconcellos\",\"organization\":\"\",\"url\":\"https:\/\/en.wikipedia.org\/wiki\/File:Induced_fit_diagram.svg\",\"project\":\"\",\"license\":\"cc0\",\"license_terms\":\"\"},{\"type\":\"cc\",\"description\":\"Activation2 updated\",\"author\":\"Jerry Crimson Mann, vectorized by Tutmosis, corrected by Fvasconcellos\",\"organization\":\"\",\"url\":\"https:\/\/commons.wikimedia.org\/wiki\/File:Activation2_updated.svg\",\"project\":\"\",\"license\":\"cc-by-sa\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"71b6ddfa-4bcb-42e9-805a-cb42853c9bae, daddc33a-9e74-47b8-88e4-9f7f284fa006, 152e3c40-1e27-4f34-8b68-23f78a8ef0dd, 08c38772-d8e2-4279-8d8b-ac2f88b3b3ad","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1264","chapter","type-chapter","status-publish","hentry"],"part":43,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/wp-json\/pressbooks\/v2\/chapters\/1264","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/wp-json\/wp\/v2\/users\/17"}],"version-history":[{"count":9,"href":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/wp-json\/pressbooks\/v2\/chapters\/1264\/revisions"}],"predecessor-version":[{"id":4625,"href":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/wp-json\/pressbooks\/v2\/chapters\/1264\/revisions\/4625"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/wp-json\/pressbooks\/v2\/parts\/43"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/wp-json\/pressbooks\/v2\/chapters\/1264\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/wp-json\/wp\/v2\/media?parent=1264"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/wp-json\/pressbooks\/v2\/chapter-type?post=1264"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/wp-json\/wp\/v2\/contributor?post=1264"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/suny-wmopen-biology1\/wp-json\/wp\/v2\/license?post=1264"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}