Solutions to Odd-Numbered Exercises
1. Yes, when the reference angle is [latex]\frac{\pi }{4}[/latex] and the terminal side of the angle is in quadrants I and III. Thus, at [latex]x=\frac{\pi }{4},\frac{5\pi }{4}[/latex], the sine and cosine values are equal.
3. Substitute the sine of the angle in for [latex]y[/latex] in the Pythagorean Theorem [latex]{x}^{2}+{y}^{2}=1[/latex]. Solve for [latex]x[/latex] and take the negative solution.
5. The outputs of tangent and cotangent will repeat every [latex]\pi[/latex] units.
7. [latex]\frac{2\sqrt{3}}{3}[/latex]
9. [latex]\sqrt{3}[/latex]
11. [latex]\sqrt{2}[/latex]
13. 1
15. 2
17. [latex]\frac{\sqrt{3}}{3}[/latex]
19. [latex]-\frac{2\sqrt{3}}{3}[/latex]
21. [latex]\sqrt{3}[/latex]
23. [latex]-\sqrt{2}[/latex]
25. −1
27. −2
29. [latex]-\frac{\sqrt{3}}{3}[/latex]
31. 2
33. [latex]\frac{\sqrt{3}}{3}[/latex]
35. −2
37. −1
39. If [latex]\sin t=-\frac{2\sqrt{2}}{3},\sec t=-3,\csc t=-\frac{3\sqrt{2}}{4},\tan t=2\sqrt{2},\cot t=\frac{\sqrt{2}}{4}[/latex]
41. [latex]\sec t=2,\csc t=\frac{2\sqrt{3}}{3},\tan t=\sqrt{3},\cot t=\frac{\sqrt{3}}{3}[/latex]
43. [latex]-\frac{\sqrt{2}}{2}[/latex]
45. 3.1
47. 1.4
49. [latex]\sin t=\frac{\sqrt{2}}{2},\cos t=\frac{\sqrt{2}}{2},\tan t=1,\cot t=1,\sec t=\sqrt{2},\csc t=\sqrt{2}[/latex]
51. [latex]\sin t=-\frac{\sqrt{3}}{2},\cos t=-\frac{1}{2},\tan t=\sqrt{3},\cot t=\frac{\sqrt{3}}{3},\sec t=-2,\csc t=-\frac{2\sqrt{3}}{3}[/latex]
53. –0.228
55. –2.414
57. 1.414
59. 1.540
61. 1.556
63. [latex]\sin \left(t\right)\approx 0.79[/latex]
65. [latex]\csc t\approx 1.16[/latex]
67. even
69. even
71. [latex]\frac{\sin t}{\cos t}=\tan t[/latex]
73. 13.77 hours, period: [latex]1000\pi[/latex]
75. 7.73 inches
Candela Citations
- Precalculus. Authored by: OpenStax College. Provided by: OpenStax. Located at: http://cnx.org/contents/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1/Preface. License: CC BY: Attribution