{"id":1441,"date":"2023-06-05T14:51:46","date_gmt":"2023-06-05T14:51:46","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/chapter\/problem-set-68-rotation-of-axes\/"},"modified":"2023-06-05T14:51:46","modified_gmt":"2023-06-05T14:51:46","slug":"problem-set-68-rotation-of-axes","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/chapter\/problem-set-68-rotation-of-axes\/","title":{"raw":"Problem Set 68: Rotation of Axes","rendered":"Problem Set 68: Rotation of Axes"},"content":{"raw":"\n1. What effect does the [latex]xy[\/latex] term have on the graph of a conic section?\n\n2.&nbsp;If the equation of a conic section is written in the form [latex]A{x}^{2}+B{y}^{2}+Cx+Dy+E=0[\/latex] and [latex]AB=0[\/latex], what can we conclude?\n\n3. If the equation of a conic section is written in the form [latex]A{x}^{2}+Bxy+C{y}^{2}+Dx+Ey+F=0[\/latex], and [latex]{B}^{2}-4AC&gt;0[\/latex], what can we conclude?\n\n4.&nbsp;Given the equation [latex]a{x}^{2}+4x+3{y}^{2}-12=0[\/latex], what can we conclude if [latex]a&gt;0?[\/latex]\n\n5. For the equation [latex]A{x}^{2}+Bxy+C{y}^{2}+Dx+Ey+F=0[\/latex], the value of [latex]\\theta [\/latex] that satisfies [latex]\\cot \\left(2\\theta \\right)=\\frac{A-C}{B}[\/latex] gives us what information?\n\nFor the following exercises, determine which conic section is represented based on the given equation.\n\n6. [latex]9{x}^{2}+4{y}^{2}+72x+36y - 500=0[\/latex]\n\n7. [latex]{x}^{2}-10x+4y - 10=0[\/latex]\n\n8.&nbsp;[latex]2{x}^{2}-2{y}^{2}+4x - 6y - 2=0[\/latex]\n\n9. [latex]4{x}^{2}-{y}^{2}+8x - 1=0[\/latex]\n\n10.&nbsp;[latex]4{y}^{2}-5x+9y+1=0[\/latex]\n\n11. [latex]2{x}^{2}+3{y}^{2}-8x - 12y+2=0[\/latex]\n\n12.&nbsp;[latex]4{x}^{2}+9xy+4{y}^{2}-36y - 125=0[\/latex]\n\n13. [latex]3{x}^{2}+6xy+3{y}^{2}-36y - 125=0[\/latex]\n\n14.&nbsp;[latex]-3{x}^{2}+3\\sqrt{3}xy - 4{y}^{2}+9=0[\/latex]\n\n15. [latex]2{x}^{2}+4\\sqrt{3}xy+6{y}^{2}-6x - 3=0[\/latex]\n\n16.&nbsp;[latex]-{x}^{2}+4\\sqrt{2}xy+2{y}^{2}-2y+1=0[\/latex]\n\n17. [latex]8{x}^{2}+4\\sqrt{2}xy+4{y}^{2}-10x+1=0[\/latex]\n\nFor the following exercises, find a new representation of the given equation after rotating through the given angle.\n\n18. [latex]3{x}^{2}+xy+3{y}^{2}-5=0,\\theta =45^\\circ [\/latex]\n\n19. [latex]4{x}^{2}-xy+4{y}^{2}-2=0,\\theta =45^\\circ [\/latex]\n\n20.&nbsp;[latex]2{x}^{2}+8xy - 1=0,\\theta =30^\\circ [\/latex]\n\n21. [latex]-2{x}^{2}+8xy+1=0,\\theta =45^\\circ [\/latex]\n\n22.&nbsp;[latex]4{x}^{2}+\\sqrt{2}xy+4{y}^{2}+y+2=0,\\theta =45^\\circ [\/latex]\n\nFor the following exercises, determine the angle [latex]\\theta [\/latex] that will eliminate the [latex]xy[\/latex] term and write the corresponding equation without the [latex]xy[\/latex] term.\n\n23. [latex]{x}^{2}+3\\sqrt{3}xy+4{y}^{2}+y - 2=0[\/latex]\n\n24.&nbsp;[latex]4{x}^{2}+2\\sqrt{3}xy+6{y}^{2}+y - 2=0[\/latex]\n\n25. [latex]9{x}^{2}-3\\sqrt{3}xy+6{y}^{2}+4y - 3=0[\/latex]\n\n26.&nbsp;[latex]-3{x}^{2}-\\sqrt{3}xy - 2{y}^{2}-x=0[\/latex]\n\n27. [latex]16{x}^{2}+24xy+9{y}^{2}+6x - 6y+2=0[\/latex]\n\n28.&nbsp;[latex]{x}^{2}+4xy+4{y}^{2}+3x - 2=0[\/latex]\n\n29. [latex]{x}^{2}+4xy+{y}^{2}-2x+1=0[\/latex]\n\n30.&nbsp;[latex]4{x}^{2}-2\\sqrt{3}xy+6{y}^{2}-1=0[\/latex]\n\nFor the following exercises, rotate through the given angle based on the given equation. Give the new equation and graph the original and rotated equation.\n\n31. [latex]y=-{x}^{2},\\theta =-{45}^{\\circ }[\/latex]\n\n32. [latex]x={y}^{2},\\theta ={45}^{\\circ }[\/latex]\n\n33. [latex]\\frac{{x}^{2}}{4}+\\frac{{y}^{2}}{1}=1,\\theta ={45}^{\\circ }[\/latex]\n\n34. [latex]\\frac{{y}^{2}}{16}+\\frac{{x}^{2}}{9}=1,\\theta ={45}^{\\circ }[\/latex]\n\n35. [latex]{y}^{2}-{x}^{2}=1,\\theta ={45}^{\\circ }[\/latex]\n\n36. [latex]y=\\frac{{x}^{2}}{2},\\theta ={30}^{\\circ }[\/latex]\n\n37. [latex]x={\\left(y - 1\\right)}^{2},\\theta ={30}^{\\circ }[\/latex]\n\n38. [latex]\\frac{{x}^{2}}{9}+\\frac{{y}^{2}}{4}=1,\\theta ={30}^{\\circ }[\/latex]\n\nFor the following exercises, graph the equation relative to the [latex]\\begin{align}{x}^{\\prime }{y}^{\\prime }\\end{align}[\/latex] system in which the equation has no [latex]\\begin{align}{x}^{\\prime }{y}^{\\prime }\\end{align}[\/latex] term.\n\n39. [latex]xy=9[\/latex]\n\n40. [latex]{x}^{2}+10xy+{y}^{2}-6=0[\/latex]\n\n41. [latex]{x}^{2}-10xy+{y}^{2}-24=0[\/latex]\n\n42. [latex]4{x}^{2}-3\\sqrt{3}xy+{y}^{2}-22=0[\/latex]\n\n43. [latex]6{x}^{2}+2\\sqrt{3}xy+4{y}^{2}-21=0[\/latex]\n\n44. [latex]11{x}^{2}+10\\sqrt{3}xy+{y}^{2}-64=0[\/latex]\n\n45. [latex]21{x}^{2}+2\\sqrt{3}xy+19{y}^{2}-18=0[\/latex]\n\n46. [latex]16{x}^{2}+24xy+9{y}^{2}-130x+90y=0[\/latex]\n\n47. [latex]16{x}^{2}+24xy+9{y}^{2}-60x+80y=0[\/latex]\n\n48. [latex]13{x}^{2}-6\\sqrt{3}xy+7{y}^{2}-16=0[\/latex]\n\n49. [latex]4{x}^{2}-4xy+{y}^{2}-8\\sqrt{5}x - 16\\sqrt{5}y=0[\/latex]\n\nFor the following exercises, determine the angle of rotation in order to eliminate the [latex]xy[\/latex] term. Then graph the new set of axes.\n\n50. [latex]6{x}^{2}-5\\sqrt{3}xy+{y}^{2}+10x - 12y=0[\/latex]\n\n51. [latex]6{x}^{2}-5xy+6{y}^{2}+20x-y=0[\/latex]\n\n52. [latex]6{x}^{2}-8\\sqrt{3}xy+14{y}^{2}+10x - 3y=0[\/latex]\n\n53. [latex]4{x}^{2}+6\\sqrt{3}xy+10{y}^{2}+20x - 40y=0[\/latex]\n\n54. [latex]8{x}^{2}+3xy+4{y}^{2}+2x - 4=0[\/latex]\n\n55. [latex]16{x}^{2}+24xy+9{y}^{2}+20x - 44y=0[\/latex]\n\nFor the following exercises, determine the value of [latex]k[\/latex] based on the given equation.\n\n56. Given [latex]4{x}^{2}+kxy+16{y}^{2}+8x+24y - 48=0[\/latex], find [latex]k[\/latex] for the graph to be a parabola.\n\n57. Given [latex]2{x}^{2}+kxy+12{y}^{2}+10x - 16y+28=0[\/latex], find [latex]k[\/latex] for the graph to be an ellipse.\n\n58.&nbsp;Given [latex]3{x}^{2}+kxy+4{y}^{2}-6x+20y+128=0[\/latex], find [latex]k[\/latex] for the graph to be a hyperbola.\n\n59. Given [latex]k{x}^{2}+8xy+8{y}^{2}-12x+16y+18=0[\/latex], find [latex]k[\/latex] for the graph to be a parabola.\n\n60.&nbsp;Given [latex]6{x}^{2}+12xy+k{y}^{2}+16x+10y+4=0[\/latex], find [latex]k[\/latex] for the graph to be an ellipse.\n","rendered":"<p>1. What effect does the [latex]xy[\/latex] term have on the graph of a conic section?<\/p>\n<p>2.&nbsp;If the equation of a conic section is written in the form [latex]A{x}^{2}+B{y}^{2}+Cx+Dy+E=0[\/latex] and [latex]AB=0[\/latex], what can we conclude?<\/p>\n<p>3. If the equation of a conic section is written in the form [latex]A{x}^{2}+Bxy+C{y}^{2}+Dx+Ey+F=0[\/latex], and [latex]{B}^{2}-4AC>0[\/latex], what can we conclude?<\/p>\n<p>4.&nbsp;Given the equation [latex]a{x}^{2}+4x+3{y}^{2}-12=0[\/latex], what can we conclude if [latex]a>0?[\/latex]<\/p>\n<p>5. For the equation [latex]A{x}^{2}+Bxy+C{y}^{2}+Dx+Ey+F=0[\/latex], the value of [latex]\\theta[\/latex] that satisfies [latex]\\cot \\left(2\\theta \\right)=\\frac{A-C}{B}[\/latex] gives us what information?<\/p>\n<p>For the following exercises, determine which conic section is represented based on the given equation.<\/p>\n<p>6. [latex]9{x}^{2}+4{y}^{2}+72x+36y - 500=0[\/latex]<\/p>\n<p>7. [latex]{x}^{2}-10x+4y - 10=0[\/latex]<\/p>\n<p>8.&nbsp;[latex]2{x}^{2}-2{y}^{2}+4x - 6y - 2=0[\/latex]<\/p>\n<p>9. [latex]4{x}^{2}-{y}^{2}+8x - 1=0[\/latex]<\/p>\n<p>10.&nbsp;[latex]4{y}^{2}-5x+9y+1=0[\/latex]<\/p>\n<p>11. [latex]2{x}^{2}+3{y}^{2}-8x - 12y+2=0[\/latex]<\/p>\n<p>12.&nbsp;[latex]4{x}^{2}+9xy+4{y}^{2}-36y - 125=0[\/latex]<\/p>\n<p>13. [latex]3{x}^{2}+6xy+3{y}^{2}-36y - 125=0[\/latex]<\/p>\n<p>14.&nbsp;[latex]-3{x}^{2}+3\\sqrt{3}xy - 4{y}^{2}+9=0[\/latex]<\/p>\n<p>15. [latex]2{x}^{2}+4\\sqrt{3}xy+6{y}^{2}-6x - 3=0[\/latex]<\/p>\n<p>16.&nbsp;[latex]-{x}^{2}+4\\sqrt{2}xy+2{y}^{2}-2y+1=0[\/latex]<\/p>\n<p>17. [latex]8{x}^{2}+4\\sqrt{2}xy+4{y}^{2}-10x+1=0[\/latex]<\/p>\n<p>For the following exercises, find a new representation of the given equation after rotating through the given angle.<\/p>\n<p>18. [latex]3{x}^{2}+xy+3{y}^{2}-5=0,\\theta =45^\\circ[\/latex]<\/p>\n<p>19. [latex]4{x}^{2}-xy+4{y}^{2}-2=0,\\theta =45^\\circ[\/latex]<\/p>\n<p>20.&nbsp;[latex]2{x}^{2}+8xy - 1=0,\\theta =30^\\circ[\/latex]<\/p>\n<p>21. [latex]-2{x}^{2}+8xy+1=0,\\theta =45^\\circ[\/latex]<\/p>\n<p>22.&nbsp;[latex]4{x}^{2}+\\sqrt{2}xy+4{y}^{2}+y+2=0,\\theta =45^\\circ[\/latex]<\/p>\n<p>For the following exercises, determine the angle [latex]\\theta[\/latex] that will eliminate the [latex]xy[\/latex] term and write the corresponding equation without the [latex]xy[\/latex] term.<\/p>\n<p>23. [latex]{x}^{2}+3\\sqrt{3}xy+4{y}^{2}+y - 2=0[\/latex]<\/p>\n<p>24.&nbsp;[latex]4{x}^{2}+2\\sqrt{3}xy+6{y}^{2}+y - 2=0[\/latex]<\/p>\n<p>25. [latex]9{x}^{2}-3\\sqrt{3}xy+6{y}^{2}+4y - 3=0[\/latex]<\/p>\n<p>26.&nbsp;[latex]-3{x}^{2}-\\sqrt{3}xy - 2{y}^{2}-x=0[\/latex]<\/p>\n<p>27. [latex]16{x}^{2}+24xy+9{y}^{2}+6x - 6y+2=0[\/latex]<\/p>\n<p>28.&nbsp;[latex]{x}^{2}+4xy+4{y}^{2}+3x - 2=0[\/latex]<\/p>\n<p>29. [latex]{x}^{2}+4xy+{y}^{2}-2x+1=0[\/latex]<\/p>\n<p>30.&nbsp;[latex]4{x}^{2}-2\\sqrt{3}xy+6{y}^{2}-1=0[\/latex]<\/p>\n<p>For the following exercises, rotate through the given angle based on the given equation. Give the new equation and graph the original and rotated equation.<\/p>\n<p>31. [latex]y=-{x}^{2},\\theta =-{45}^{\\circ }[\/latex]<\/p>\n<p>32. [latex]x={y}^{2},\\theta ={45}^{\\circ }[\/latex]<\/p>\n<p>33. [latex]\\frac{{x}^{2}}{4}+\\frac{{y}^{2}}{1}=1,\\theta ={45}^{\\circ }[\/latex]<\/p>\n<p>34. [latex]\\frac{{y}^{2}}{16}+\\frac{{x}^{2}}{9}=1,\\theta ={45}^{\\circ }[\/latex]<\/p>\n<p>35. [latex]{y}^{2}-{x}^{2}=1,\\theta ={45}^{\\circ }[\/latex]<\/p>\n<p>36. [latex]y=\\frac{{x}^{2}}{2},\\theta ={30}^{\\circ }[\/latex]<\/p>\n<p>37. [latex]x={\\left(y - 1\\right)}^{2},\\theta ={30}^{\\circ }[\/latex]<\/p>\n<p>38. [latex]\\frac{{x}^{2}}{9}+\\frac{{y}^{2}}{4}=1,\\theta ={30}^{\\circ }[\/latex]<\/p>\n<p>For the following exercises, graph the equation relative to the [latex]\\begin{align}{x}^{\\prime }{y}^{\\prime }\\end{align}[\/latex] system in which the equation has no [latex]\\begin{align}{x}^{\\prime }{y}^{\\prime }\\end{align}[\/latex] term.<\/p>\n<p>39. [latex]xy=9[\/latex]<\/p>\n<p>40. [latex]{x}^{2}+10xy+{y}^{2}-6=0[\/latex]<\/p>\n<p>41. [latex]{x}^{2}-10xy+{y}^{2}-24=0[\/latex]<\/p>\n<p>42. [latex]4{x}^{2}-3\\sqrt{3}xy+{y}^{2}-22=0[\/latex]<\/p>\n<p>43. [latex]6{x}^{2}+2\\sqrt{3}xy+4{y}^{2}-21=0[\/latex]<\/p>\n<p>44. [latex]11{x}^{2}+10\\sqrt{3}xy+{y}^{2}-64=0[\/latex]<\/p>\n<p>45. [latex]21{x}^{2}+2\\sqrt{3}xy+19{y}^{2}-18=0[\/latex]<\/p>\n<p>46. [latex]16{x}^{2}+24xy+9{y}^{2}-130x+90y=0[\/latex]<\/p>\n<p>47. [latex]16{x}^{2}+24xy+9{y}^{2}-60x+80y=0[\/latex]<\/p>\n<p>48. [latex]13{x}^{2}-6\\sqrt{3}xy+7{y}^{2}-16=0[\/latex]<\/p>\n<p>49. [latex]4{x}^{2}-4xy+{y}^{2}-8\\sqrt{5}x - 16\\sqrt{5}y=0[\/latex]<\/p>\n<p>For the following exercises, determine the angle of rotation in order to eliminate the [latex]xy[\/latex] term. Then graph the new set of axes.<\/p>\n<p>50. [latex]6{x}^{2}-5\\sqrt{3}xy+{y}^{2}+10x - 12y=0[\/latex]<\/p>\n<p>51. [latex]6{x}^{2}-5xy+6{y}^{2}+20x-y=0[\/latex]<\/p>\n<p>52. [latex]6{x}^{2}-8\\sqrt{3}xy+14{y}^{2}+10x - 3y=0[\/latex]<\/p>\n<p>53. [latex]4{x}^{2}+6\\sqrt{3}xy+10{y}^{2}+20x - 40y=0[\/latex]<\/p>\n<p>54. [latex]8{x}^{2}+3xy+4{y}^{2}+2x - 4=0[\/latex]<\/p>\n<p>55. [latex]16{x}^{2}+24xy+9{y}^{2}+20x - 44y=0[\/latex]<\/p>\n<p>For the following exercises, determine the value of [latex]k[\/latex] based on the given equation.<\/p>\n<p>56. Given [latex]4{x}^{2}+kxy+16{y}^{2}+8x+24y - 48=0[\/latex], find [latex]k[\/latex] for the graph to be a parabola.<\/p>\n<p>57. Given [latex]2{x}^{2}+kxy+12{y}^{2}+10x - 16y+28=0[\/latex], find [latex]k[\/latex] for the graph to be an ellipse.<\/p>\n<p>58.&nbsp;Given [latex]3{x}^{2}+kxy+4{y}^{2}-6x+20y+128=0[\/latex], find [latex]k[\/latex] for the graph to be a hyperbola.<\/p>\n<p>59. Given [latex]k{x}^{2}+8xy+8{y}^{2}-12x+16y+18=0[\/latex], find [latex]k[\/latex] for the graph to be a parabola.<\/p>\n<p>60.&nbsp;Given [latex]6{x}^{2}+12xy+k{y}^{2}+16x+10y+4=0[\/latex], find [latex]k[\/latex] for the graph to be an ellipse.<\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-1441\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Precalculus. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download for free at: http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":503070,"menu_order":12,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Precalculus\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download for free at: http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175:1\/Preface\"}]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-1441","chapter","type-chapter","status-publish","hentry"],"part":1429,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/wp-json\/pressbooks\/v2\/chapters\/1441","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/wp-json\/wp\/v2\/users\/503070"}],"version-history":[{"count":0,"href":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/wp-json\/pressbooks\/v2\/chapters\/1441\/revisions"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/wp-json\/pressbooks\/v2\/parts\/1429"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/wp-json\/pressbooks\/v2\/chapters\/1441\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/wp-json\/wp\/v2\/media?parent=1441"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/wp-json\/pressbooks\/v2\/chapter-type?post=1441"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/wp-json\/wp\/v2\/contributor?post=1441"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/tulsacc-math1613\/wp-json\/wp\/v2\/license?post=1441"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}