{"id":2587,"date":"2016-08-24T13:45:48","date_gmt":"2016-08-24T13:45:48","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/?post_type=chapter&#038;p=2587"},"modified":"2017-08-28T21:45:14","modified_gmt":"2017-08-28T21:45:14","slug":"pressure-units-and-conversions","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/chapter\/pressure-units-and-conversions\/","title":{"raw":"Pressure Units and Conversions","rendered":"Pressure Units and Conversions"},"content":{"raw":"<div class=\"x-ck12-data-objectives\">\r\n<div class=\"textbox learning-objectives\">\r\n<h3>Learning Objectives<\/h3>\r\n<ul>\r\n \t<li>Be able to convert between different units of pressure.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<div class=\"textbox examples\">\r\n<h3>Examples<\/h3>\r\n<p id=\"x-ck12-MTQ2NmIzNTQ2MWJlZmRhNTEzNTE1NzNiYTQ1NjIyYjY.-shc\"><span class=\"x-ck12-img-inline\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212010\/20140811155423302953.jpeg\" alt=\"Maintaining higher tire pressure can extend the lifetime of a car\" width=\"400\" \/><\/span><\/p>\r\n\r\n<h4><span class=\"x-ck12-img-inline\">Can you guess how old this car is?\r\n<\/span><\/h4>\r\n<p id=\"x-ck12-NTNiNzc4NWJkZmIxY2M4YTJmYTc0MTFjNGZjN2I2MGM.-zhn\">There are several benefits to maintaining the proper air pressure in a car tire. The ride is smoother and safer than with lowered pressure. The car gets better gas mileage and the tires don\u2019t wear out as fast. The recommended pressure for that model of car (usually somewhere between 32-35 psi) is usually listed in the owner\u2019s manual or stamped somewhere inside the door. The pressure on the tire is the maximum pressure for that tire, not the recommended one. Tire pressure is best measured when the tire is cold since driving the car for a while will heat up the air in the tire and increase the pressure.<\/p>\r\n\r\n<\/div>\r\n<h3>Pressure Units and Conversion<\/h3>\r\n<p id=\"x-ck12-NjFlYjg0Y2Q4MDA0MDQ2OTJlYWQ0YmQ1MTFiNTRiOWI.-aog\">A barometer measures gas pressure by the height of the column of mercury. One unit of gas pressure is the millimeter of mercury (mmHg). An equivalent unit to the mmHg is called the torr, in honor of the inventor of the barometer, Evangelista Torricelli. The <strong>pascal <\/strong>(Pa) is the standard unit of pressure. A pascal is a very small amount of pressure, so the more useful unit for everyday gas pressures is the kilopascal (kPa). A kilopascal is equal to 1000 pascals. Another commonly used unit of pressure is the <strong>atmosphere <\/strong>(atm). Standard atmospheric pressure is called 1 atm of pressure and is equal to 760 mmHg and 101.3 kPa. Atmospheric pressure is also often stated as pounds\/square inch (psi). The atmospheric pressure at sea level is 14.7 psi.<\/p>\r\n<p id=\"x-ck12-hwz\"><img class=\"x-ck12-block-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212011\/becd273ccc08fdbfe4fd222fcd12ffb1.png\" alt=\"1 text{atm}=760 text{mmHg} = 760 text{torr} = 101.3 text{KPa} = 14.7 text{psi}\" width=\"429\" height=\"17\" \/><\/p>\r\n<p id=\"x-ck12-MTI4OTNjYWM3ODYzMTQwNDM0YjVmNGVmNWQxZWYxZDE.-kvz\">It is important to be able to convert between different units of pressure. To do so, we will use the equivalent standard pressures shown above.<\/p>\r\n\r\n<h4>Sample Problem: Pressure Unit Conversions<\/h4>\r\n<p id=\"x-ck12-NzAxNGUyMDI4OTU1ZjQ5ZmIzNDlhNTQxNDI1MjNlODE.-zig\">The atmospheric pressure in a mountainous location is measured to be 613 mmHg. What is this pressure in atm and in kPa?<\/p>\r\n<p id=\"x-ck12-OGU2YWEyYzY0NzAwMDUxZjI4NjFjY2E4MjYyNmNhN2I.-c56\"><em>Step 1: List the known quantities and plan the problem.<\/em><\/p>\r\n<p id=\"x-ck12-MmY1NjUwZTQ4NGZhMTk1OTQ5YWM2YzhkMTFkY2E0ZmQ.-jkw\"><span class=\"x-ck12-underline\">Known<\/span><\/p>\r\n\r\n<ul id=\"x-ck12-ZWU3YmEwZmJjYWNiOWE3ODhmYzZhNmE5MDE4MjNjYzU.-wxr\">\r\n \t<li>given: 613 mmHg<\/li>\r\n \t<li>1 atm = 760 mmHg<\/li>\r\n \t<li>101.3 kPa = 760 mmHg<\/li>\r\n<\/ul>\r\n<p id=\"x-ck12-ODgxODNiOTQ2Y2M1ZjBlOGM5NmIyZTY2ZTFjNzRhN2U.-ngq\"><span class=\"x-ck12-underline\">Unknown<\/span><\/p>\r\n\r\n<ul id=\"x-ck12-YWFhNmYzMDc4M2QyM2U3NmMzMjVlYmFhOTA2OTc4ZWU.-jzx\">\r\n \t<li>pressure = ? atm<\/li>\r\n \t<li>pressure = ? kPa<\/li>\r\n<\/ul>\r\n<p id=\"x-ck12-YzZlZTViMjkxMDAxN2FhYzg0MjJmZjBmMmJlODQyOTA.-c9o\">Use conversion factors from the equivalent pressure units to convert from mmHg to atm and from mmHg to kPa.<\/p>\r\n<p id=\"x-ck12-ZjZhN2M2ZWIzYjU5NWY1NDY2Yzg4ZDMxMDBjN2VkODc.-xap\"><em>Step 2: Solve.<\/em><\/p>\r\n<p id=\"x-ck12-6kv\" class=\"x-ck12-indent\"><img class=\"x-ck12-block-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212013\/fc6aceb69c3d915e9a58f2ec1e6ae645.png\" alt=\"613 text{mmHg}timesfrac{1 text{atm}}{760 text{mmHg}} &amp;=0.807 text{atm}\\613 text{mmHg}timesfrac{101.3 text{kPa}}{760 text{mmHg}} &amp;=81.7 text{kPa}\" width=\"298\" height=\"87\" \/><\/p>\r\n<p id=\"x-ck12-ZGJmYWE4NWM0YmIyZGJiOTdhZTZmY2NmYmJmYjM1MjI.-lie\"><em>Step 3: Think about your result.<\/em><\/p>\r\n<p id=\"x-ck12-YzI2Nzk4NWE1MmJhYTBiNDZkNTQwNWEzMTVkYTUyZmQ.-hky\">The air pressure is about 80% that of standard atmospheric pressure at sea level. For significant figure purposes, the standard pressure of 760 mmHg has three significant figures.<\/p>\r\n<p id=\"x-ck12-N2E3NWRlOTNmZjE1YzYxM2U5MWIwNzk2MjY4ZjdmZGE.-tai\">Watch the video to learn more about conversion factors:<\/p>\r\nhttps:\/\/youtu.be\/qv81QCGNnVo\r\n<div class=\"textbox key-takeaways\">\r\n<h3>Summary<\/h3>\r\n<ul id=\"x-ck12-MTQ5MDE0ODA2YTdmZDQ4YTE0YjhiYTA4NDVmNWViZDM.-coj\">\r\n \t<li>Calculations are described for converting between different pressure units.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<h3>Practice<\/h3>\r\n<p id=\"x-ck12-NDVlYjc4ZTg4MGRiYWUzNWEwNDQ4NzE2MGUyY2JkMzE.-wh4\">Use the link below to practice conversion calculations:<\/p>\r\n<p id=\"x-ck12-NzZlOTg5ZGE2Mjc3MmU2ZjhlZDdkYzczYzI1YmY1OTU.-h3p\"><a href=\"http:\/\/www.kentchemistry.com\/links\/GasLaws\/Pressure.htm\">http:\/\/www.kentchemistry.com\/links\/GasLaws\/Pressure.htm<\/a><\/p>\r\n\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<h3>Review<\/h3>\r\n<ol id=\"x-ck12-NWJlMmI1N2EyNzcyZGQ4YTkwMjM0NGI1MDRiNmQyNWY.-bdy\">\r\n \t<li>Who invented the barometer?<\/li>\r\n \t<li>One atm = ___ torr?<\/li>\r\n \t<li>14.7 psi = ___ kPa<\/li>\r\n \t<li>760 mm = ___ psi?<\/li>\r\n \t<li>The pressure in a car tire is 35 psi. How many atmospheres is that?<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"x-ck12-data-problem-set\">\r\n<div class=\"textbox learning-objectives\">\r\n<h3>Glossary<\/h3>\r\n<div class=\"x-ck12-data-vocabulary\">\r\n<ul id=\"x-ck12-MWJhMjRiZDVhYzA0YjlmYjZjZjdlNjhhMTA4ZmE5ZTE.-w4s\">\r\n \t<li><strong>atmosphere: <\/strong>Common unit of pressure. Abbreviated as \u201catm.\u201d<\/li>\r\n \t<li><strong>pascal: <\/strong>The standard unit of pressure. Abbreviated as \u201cPa.\u201d<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n<\/div>\r\n[reveal-answer q=\"836080\"]Show References[\/reveal-answer]\r\n[hidden-answer a=\"836080\"]\r\n<h2>References<\/h2>\r\n<ol>\r\n \t<li>User:IFCAR\/Wikimedia Commons. <a href=\"http:\/\/commons.wikimedia.org\/wiki\/File:Mercury-Grand-Marquis.jpg\">http:\/\/commons.wikimedia.org\/wiki\/File:Mercury-Grand-Marquis.jpg<\/a>.<\/li>\r\n<\/ol>\r\n[\/hidden-answer]","rendered":"<div class=\"x-ck12-data-objectives\">\n<div class=\"textbox learning-objectives\">\n<h3>Learning Objectives<\/h3>\n<ul>\n<li>Be able to convert between different units of pressure.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div class=\"textbox examples\">\n<h3>Examples<\/h3>\n<p id=\"x-ck12-MTQ2NmIzNTQ2MWJlZmRhNTEzNTE1NzNiYTQ1NjIyYjY.-shc\"><span class=\"x-ck12-img-inline\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212010\/20140811155423302953.jpeg\" alt=\"Maintaining higher tire pressure can extend the lifetime of a car\" width=\"400\" \/><\/span><\/p>\n<h4><span class=\"x-ck12-img-inline\">Can you guess how old this car is?<br \/>\n<\/span><\/h4>\n<p id=\"x-ck12-NTNiNzc4NWJkZmIxY2M4YTJmYTc0MTFjNGZjN2I2MGM.-zhn\">There are several benefits to maintaining the proper air pressure in a car tire. The ride is smoother and safer than with lowered pressure. The car gets better gas mileage and the tires don\u2019t wear out as fast. The recommended pressure for that model of car (usually somewhere between 32-35 psi) is usually listed in the owner\u2019s manual or stamped somewhere inside the door. The pressure on the tire is the maximum pressure for that tire, not the recommended one. Tire pressure is best measured when the tire is cold since driving the car for a while will heat up the air in the tire and increase the pressure.<\/p>\n<\/div>\n<h3>Pressure Units and Conversion<\/h3>\n<p id=\"x-ck12-NjFlYjg0Y2Q4MDA0MDQ2OTJlYWQ0YmQ1MTFiNTRiOWI.-aog\">A barometer measures gas pressure by the height of the column of mercury. One unit of gas pressure is the millimeter of mercury (mmHg). An equivalent unit to the mmHg is called the torr, in honor of the inventor of the barometer, Evangelista Torricelli. The <strong>pascal <\/strong>(Pa) is the standard unit of pressure. A pascal is a very small amount of pressure, so the more useful unit for everyday gas pressures is the kilopascal (kPa). A kilopascal is equal to 1000 pascals. Another commonly used unit of pressure is the <strong>atmosphere <\/strong>(atm). Standard atmospheric pressure is called 1 atm of pressure and is equal to 760 mmHg and 101.3 kPa. Atmospheric pressure is also often stated as pounds\/square inch (psi). The atmospheric pressure at sea level is 14.7 psi.<\/p>\n<p id=\"x-ck12-hwz\"><img loading=\"lazy\" decoding=\"async\" class=\"x-ck12-block-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212011\/becd273ccc08fdbfe4fd222fcd12ffb1.png\" alt=\"1 text{atm}=760 text{mmHg} = 760 text{torr} = 101.3 text{KPa} = 14.7 text{psi}\" width=\"429\" height=\"17\" \/><\/p>\n<p id=\"x-ck12-MTI4OTNjYWM3ODYzMTQwNDM0YjVmNGVmNWQxZWYxZDE.-kvz\">It is important to be able to convert between different units of pressure. To do so, we will use the equivalent standard pressures shown above.<\/p>\n<h4>Sample Problem: Pressure Unit Conversions<\/h4>\n<p id=\"x-ck12-NzAxNGUyMDI4OTU1ZjQ5ZmIzNDlhNTQxNDI1MjNlODE.-zig\">The atmospheric pressure in a mountainous location is measured to be 613 mmHg. What is this pressure in atm and in kPa?<\/p>\n<p id=\"x-ck12-OGU2YWEyYzY0NzAwMDUxZjI4NjFjY2E4MjYyNmNhN2I.-c56\"><em>Step 1: List the known quantities and plan the problem.<\/em><\/p>\n<p id=\"x-ck12-MmY1NjUwZTQ4NGZhMTk1OTQ5YWM2YzhkMTFkY2E0ZmQ.-jkw\"><span class=\"x-ck12-underline\">Known<\/span><\/p>\n<ul id=\"x-ck12-ZWU3YmEwZmJjYWNiOWE3ODhmYzZhNmE5MDE4MjNjYzU.-wxr\">\n<li>given: 613 mmHg<\/li>\n<li>1 atm = 760 mmHg<\/li>\n<li>101.3 kPa = 760 mmHg<\/li>\n<\/ul>\n<p id=\"x-ck12-ODgxODNiOTQ2Y2M1ZjBlOGM5NmIyZTY2ZTFjNzRhN2U.-ngq\"><span class=\"x-ck12-underline\">Unknown<\/span><\/p>\n<ul id=\"x-ck12-YWFhNmYzMDc4M2QyM2U3NmMzMjVlYmFhOTA2OTc4ZWU.-jzx\">\n<li>pressure = ? atm<\/li>\n<li>pressure = ? kPa<\/li>\n<\/ul>\n<p id=\"x-ck12-YzZlZTViMjkxMDAxN2FhYzg0MjJmZjBmMmJlODQyOTA.-c9o\">Use conversion factors from the equivalent pressure units to convert from mmHg to atm and from mmHg to kPa.<\/p>\n<p id=\"x-ck12-ZjZhN2M2ZWIzYjU5NWY1NDY2Yzg4ZDMxMDBjN2VkODc.-xap\"><em>Step 2: Solve.<\/em><\/p>\n<p id=\"x-ck12-6kv\" class=\"x-ck12-indent\"><img loading=\"lazy\" decoding=\"async\" class=\"x-ck12-block-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212013\/fc6aceb69c3d915e9a58f2ec1e6ae645.png\" alt=\"613 text{mmHg}timesfrac{1 text{atm}}{760 text{mmHg}} &amp;=0.807 text{atm}\\613 text{mmHg}timesfrac{101.3 text{kPa}}{760 text{mmHg}} &amp;=81.7 text{kPa}\" width=\"298\" height=\"87\" \/><\/p>\n<p id=\"x-ck12-ZGJmYWE4NWM0YmIyZGJiOTdhZTZmY2NmYmJmYjM1MjI.-lie\"><em>Step 3: Think about your result.<\/em><\/p>\n<p id=\"x-ck12-YzI2Nzk4NWE1MmJhYTBiNDZkNTQwNWEzMTVkYTUyZmQ.-hky\">The air pressure is about 80% that of standard atmospheric pressure at sea level. For significant figure purposes, the standard pressure of 760 mmHg has three significant figures.<\/p>\n<p id=\"x-ck12-N2E3NWRlOTNmZjE1YzYxM2U5MWIwNzk2MjY4ZjdmZGE.-tai\">Watch the video to learn more about conversion factors:<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"Gas Pressure Conversions\" width=\"500\" height=\"375\" src=\"https:\/\/www.youtube.com\/embed\/qv81QCGNnVo?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<div class=\"textbox key-takeaways\">\n<h3>Summary<\/h3>\n<ul id=\"x-ck12-MTQ5MDE0ODA2YTdmZDQ4YTE0YjhiYTA4NDVmNWViZDM.-coj\">\n<li>Calculations are described for converting between different pressure units.<\/li>\n<\/ul>\n<\/div>\n<div class=\"textbox exercises\">\n<h3>Practice<\/h3>\n<p id=\"x-ck12-NDVlYjc4ZTg4MGRiYWUzNWEwNDQ4NzE2MGUyY2JkMzE.-wh4\">Use the link below to practice conversion calculations:<\/p>\n<p id=\"x-ck12-NzZlOTg5ZGE2Mjc3MmU2ZjhlZDdkYzczYzI1YmY1OTU.-h3p\"><a href=\"http:\/\/www.kentchemistry.com\/links\/GasLaws\/Pressure.htm\">http:\/\/www.kentchemistry.com\/links\/GasLaws\/Pressure.htm<\/a><\/p>\n<\/div>\n<div class=\"textbox exercises\">\n<h3>Review<\/h3>\n<ol id=\"x-ck12-NWJlMmI1N2EyNzcyZGQ4YTkwMjM0NGI1MDRiNmQyNWY.-bdy\">\n<li>Who invented the barometer?<\/li>\n<li>One atm = ___ torr?<\/li>\n<li>14.7 psi = ___ kPa<\/li>\n<li>760 mm = ___ psi?<\/li>\n<li>The pressure in a car tire is 35 psi. How many atmospheres is that?<\/li>\n<\/ol>\n<\/div>\n<div class=\"x-ck12-data-problem-set\">\n<div class=\"textbox learning-objectives\">\n<h3>Glossary<\/h3>\n<div class=\"x-ck12-data-vocabulary\">\n<ul id=\"x-ck12-MWJhMjRiZDVhYzA0YjlmYjZjZjdlNjhhMTA4ZmE5ZTE.-w4s\">\n<li><strong>atmosphere: <\/strong>Common unit of pressure. Abbreviated as \u201catm.\u201d<\/li>\n<li><strong>pascal: <\/strong>The standard unit of pressure. Abbreviated as \u201cPa.\u201d<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q836080\">Show References<\/span><\/p>\n<div id=\"q836080\" class=\"hidden-answer\" style=\"display: none\">\n<h2>References<\/h2>\n<ol>\n<li>User:IFCAR\/Wikimedia Commons. <a href=\"http:\/\/commons.wikimedia.org\/wiki\/File:Mercury-Grand-Marquis.jpg\">http:\/\/commons.wikimedia.org\/wiki\/File:Mercury-Grand-Marquis.jpg<\/a>.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n","protected":false},"author":1507,"menu_order":5,"template":"","meta":{"_candela_citation":"[]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-2587","chapter","type-chapter","status-publish","hentry"],"part":2334,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/chapters\/2587","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/wp\/v2\/users\/1507"}],"version-history":[{"count":8,"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/chapters\/2587\/revisions"}],"predecessor-version":[{"id":3595,"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/chapters\/2587\/revisions\/3595"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/parts\/2334"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/chapters\/2587\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/wp\/v2\/media?parent=2587"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/chapter-type?post=2587"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/wp\/v2\/contributor?post=2587"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/wp\/v2\/license?post=2587"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}