{"id":2690,"date":"2016-08-24T16:01:00","date_gmt":"2016-08-24T16:01:00","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/?post_type=chapter&#038;p=2690"},"modified":"2016-09-16T03:08:33","modified_gmt":"2016-09-16T03:08:33","slug":"stoichiometric-calculations-and-enthalpy-changes","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/chapter\/stoichiometric-calculations-and-enthalpy-changes\/","title":{"raw":"Stoichiometric Calculations and Enthalpy Changes","rendered":"Stoichiometric Calculations and Enthalpy Changes"},"content":{"raw":"<h1 id=\"x-ck12-Q2Fsb3JpbWV0cnk.\">Thermochemistry<\/h1>\r\n&nbsp;\r\n<div class=\"textbox learning-objectives\">\r\n<h3>Learning Objectives<\/h3>\r\n<h1 id=\"x-ck12-U3RvaWNoaW9tZXRyaWMgQ2FsY3VsYXRpb25zIGFuZCBFbnRoYWxweSBDaGFuZ2Vz\">Stoichiometric Calculations and Enthalpy Changes<\/h1>\r\n<div class=\"x-ck12-data-objectives\">\r\n<ul id=\"x-ck12-MTBhMGJkZTA0ZTVjMTQ4YTVlM2FlMjIxMWZhOTMwYmE.-5is\">\r\n \t<li>Perform calculations of enthalpy equations.<\/li>\r\n<\/ul>\r\n<\/div>\r\n<\/div>\r\n&nbsp;\r\n<div class=\"textbox examples\">\r\n<h3>Examples<\/h3>\r\n<p id=\"x-ck12-YWIwMmExMGQ1MWVmMzdkMzA1MmRjZGUzMzlmMWUzNjI.-qwb\"><span class=\"x-ck12-img-inline\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212641\/20140811155648489887.jpeg\" alt=\"Enthalpy changes are important in many fields\" width=\"400\" \/><\/span><\/p>\r\n<p id=\"x-ck12-NDI0YzMzOTllYTA4NWVlMTM4MzU3ZTc3MTgzNThlMzQ.-fqd\"><strong>What will it cost?<\/strong><\/p>\r\n<p id=\"x-ck12-MGU4N2IzYmY4MzA4YmVhZGQzODdiOTgxNzg5ZmE1YTc.-o5i\">There is a growing concern about the damage to the environment from emissions from manufacturing plants. Many companies are taking steps to reduce these harmful emissions by adding equipment that will trap the pollutants. In order to know what equipment (and how many) to order, studies need to be done to measure the amount of product currently produced. The since pollution is often both particulate and thermal, energy changes need to be determined in addition to the amounts of products released.<\/p>\r\n\r\n<\/div>\r\n&nbsp;\r\n<h3>Stoichiometric Calculations and Enthalpy Changes<\/h3>\r\n<p id=\"x-ck12-MDZiMjA1MjRiMjkwYjMwYzQyY2ZiZmU2ODBmNWM2NmY.-dip\">Chemistry problems that involve enthalpy changes can be solved by techniques similar to stoichiometry problems.\u00a0 Refer again to the combustion reaction of methane. Since the reaction of 1 mol of methane released 890.4 kJ, the reaction of 2 mol of methane would release <img id=\"x-ck12-MTM2Njk2NTMwNDkzNw..\" class=\"x-ck12-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212643\/03bfc49ec8ee20a13df5ba5e7fd497aa.png\" alt=\"2 times 890.4 text{ kJ} = 1781 text{ kJ}\" width=\"181\" height=\"14\" \/> . The reaction of 0.5 mol of methane would release <img class=\"x-ck12-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212643\/e374cba43baf8e5e74f51c1dede0aa37.png\" alt=\"frac{890.4 text{ kJ}}{2}= 445.2 text{ kJ}\" width=\"138\" height=\"24\" \/> . As with other stoichiometry problems, the moles of a reactant or product can be linked to mass or volume.<\/p>\r\n\r\n<h4>Sample Problem: Calculating Enthalpy Changes<\/h4>\r\n<p id=\"x-ck12-MGZhMjJmYjAzZjk0ODE3Zjk3NzVlZjRiM2FhYzE0M2I.-fvm\">Sulfur dioxide gas reacts with oxygen to form sulfur trioxide in an exothermic reaction according to the following thermochemical equation.<\/p>\r\n<p id=\"x-ck12-cs6\"><img class=\"x-ck12-block-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212644\/8bb42afd9ae6618e24d918c38be85ce1.png\" alt=\"2text{SO}_2(text{g}) + text{O}_2(text{g}) rightarrow 2text{SO}_3(text{g})+198 text{ kJ}\" width=\"293\" height=\"18\" \/><\/p>\r\n<p id=\"x-ck12-MWM5NzJkYzRhMGE3MTJmZjdiM2ZiZWEwM2FhZGZjNmU.-slo\">Calculate the enthalpy change that occurs when 58.0 g of sulfur dioxide is reacted with excess oxygen.<\/p>\r\n<p id=\"x-ck12-Y2VlNGQ1OTZkZWQ3ZDY1MzMyNmI1ODhhNWUzY2Q3NmU.-ufp\"><em>Step 1: List the known quantities and plan the problem <\/em>.<\/p>\r\n<p id=\"x-ck12-MmY1NjUwZTQ4NGZhMTk1OTQ5YWM2YzhkMTFkY2E0ZmQ.-dbh\"><span class=\"x-ck12-underline\">Known<\/span><\/p>\r\n\r\n<ul id=\"x-ck12-M2ZiMjJhMTBkYWY2MGViYjQyMDA4MjI3N2RjNDhkMzQ.-c9p\">\r\n \t<li>mass SO <sub>2 <\/sub>= 58.0 g<\/li>\r\n \t<li>molar mass SO <sub>2 <\/sub>= 64.07 g\/mol<\/li>\r\n \t<li><img class=\"x-ck12-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212647\/e158ceda959f8818aa041ad9ee9dee98.png\" alt=\"Delta H = -198 text{ kJ for the reaction of } 2 text{ mol SO}_2\" width=\"354\" height=\"16\" \/><\/li>\r\n<\/ul>\r\n<p id=\"x-ck12-ODgxODNiOTQ2Y2M1ZjBlOGM5NmIyZTY2ZTFjNzRhN2U.-eru\"><span class=\"x-ck12-underline\">Unknown<\/span><\/p>\r\n\r\n<ul id=\"x-ck12-qpy\">\r\n \t<li><img class=\"x-ck12-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212648\/b300f0495611e0feec35980a2ae4dc87.png\" alt=\"Delta H = ? text{ kJ}\" width=\"83\" height=\"14\" \/><\/li>\r\n<\/ul>\r\n<p id=\"x-ck12-NzYzMDZjYTg5NmE0ODYxMDBjZDI3MWNmOTQ3Yzg4OTU.-54h\">The calculation requires two steps. The mass of SO <sub>2 <\/sub>is converted to moles. Then the mol SO <sub>2 <\/sub>is multiplied by the conversion factor of <img class=\"x-ck12-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212649\/39c584c39cae806f96d4eff4fec98335.png\" alt=\"left(frac{-198 text{ kJ}}{2 text{ mol SO}_2} right)\" width=\"79\" height=\"34\" \/> .<\/p>\r\n<p id=\"x-ck12-ZmYxNjkxNzA3ODcxNDhkYjhmZGUyOTFlNDk1NmEzZjE.-kyb\"><em>Step 2: Solve <\/em>.<\/p>\r\n<p id=\"x-ck12-08a\"><img class=\"x-ck12-block-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212650\/34cb2d3e6b8ba0183747def3e70570b6.png\" alt=\"Delta H=58.0 text{ g SO}_2 times frac{1 text{ mol SO}_2}{64.07 text{ g SO}_2} times frac{-198 text{ kJ}}{2 text{ mol SO}_2}=-89.6 text{ kJ}\" width=\"458\" height=\"42\" \/><\/p>\r\n<p id=\"x-ck12-MGZhMzc5YjY2OWU0YzY0ZWM4YjYzZWNhYzc4OTQ3ZDA.-szg\"><em>Step 3: Think about your result <\/em>.<\/p>\r\n<p id=\"x-ck12-ZDk1Y2M1NThmNTg0NmU2NjNiYzkwNzU0NzJiOTY1YjY.-lsz\">The mass of sulfur dioxide is slightly less than 1 mol. Since 198 kJ is released for every 2 mol of SO <sub>2 <\/sub>that reacts, the heat released when about 1 mol reacts is one half of 198. The 89.6 kJ is slightly less than half of 198. The sign of\u00a0 <img id=\"x-ck12-MTM2Njk2NTMwNDkzOA..\" class=\"x-ck12-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212619\/58e2d6b1f6cbdc5e4c424671b4016000.png\" alt=\"Delta H\" width=\"31\" height=\"12\" \/> is negative because the reaction is exothermic.<\/p>\r\n\r\n<div class=\"textbox key-takeaways\">\r\n<h3>Key Takeaways<\/h3>\r\n<h4>Summary<\/h4>\r\n<ul id=\"x-ck12-ZDY2NzNjOGRmN2E5MDhmNDg1NmMxZGQ2MGExOTJlNjM.-uzb\">\r\n \t<li>Calculations of energy changes in enthalpy equations are described.<\/li>\r\n<\/ul>\r\n<\/div>\r\n&nbsp;\r\n<div class=\"textbox exercises\">\r\n<h3>Exercises<\/h3>\r\n<h4>Practice<\/h4>\r\n<p id=\"x-ck12-OTMxNmNlNTkxOTRhNDhiODhkYWE2MzgxNTlmMzI0ZGY.-obk\">Work on the problems at the site below. No peaking at the answers.<\/p>\r\n<p id=\"x-ck12-NTIyNzQwMjcwYmNmNzlkNDBiODRmMDI1N2Y1ZTE5Nzc.-nwm\"><a href=\"http:\/\/msmcraesscience.weebly.com\/uploads\/5\/1\/4\/4\/5144948\/enthalpy_stoichiometry_worksheet_1.pdf\">http:\/\/msmcraesscience.weebly.com\/uploads\/5\/1\/4\/4\/5144948\/enthalpy_stoichiometry_worksheet_1.pdf<\/a><\/p>\r\n\r\n<h4>Review<\/h4>\r\n<p id=\"x-ck12-NmNlM2JkYzM5ZTU0NDcyNTAzOGUwZTg3Yjc3MWRiMWU.-ckl\"><em>Questions<\/em><\/p>\r\n\r\n<ol id=\"x-ck12-NDk3NmEwMmU5YWE3YTVlODE5OTQ5MmRhNDc5ZDkwN2Y.-b5h\">\r\n \t<li>What do you need to determine to solve enthalpy stoichiometry problems?<\/li>\r\n \t<li>If I react 1.75 moles of methane, how much energy will be involved?<\/li>\r\n \t<li>I ran a reaction producing sulfur dioxide and releasing 267.3 kJ of energy. How many moles of sulfur dioxide were involved in the reaction?<\/li>\r\n<\/ol>\r\n<div class=\"x-ck12-data-problem-set\"><\/div>\r\n<\/div>\r\n&nbsp;\r\n<div class=\"x-ck12-data-vocabulary\"><\/div>\r\n<h1 id=\"x-ck12-SGVhdHMgb2YgRnVzaW9uIGFuZCBTb2xpZGlmaWNhdGlvbg..\"><\/h1>\r\n[reveal-answer q=\"836080\"]Show References[\/reveal-answer]\r\n[hidden-answer a=\"836080\"]\r\n<h2>References<\/h2>\r\n<ol>\r\n \t<li>Rennett Stowe. <a href=\"http:\/\/www.flickr.com\/photos\/tomsaint\/3518071026\/\">http:\/\/www.flickr.com\/photos\/tomsaint\/3518071026\/ <\/a>.<\/li>\r\n<\/ol>\r\n[\/hidden-answer]","rendered":"<h1 id=\"x-ck12-Q2Fsb3JpbWV0cnk.\">Thermochemistry<\/h1>\n<p>&nbsp;<\/p>\n<div class=\"textbox learning-objectives\">\n<h3>Learning Objectives<\/h3>\n<h1 id=\"x-ck12-U3RvaWNoaW9tZXRyaWMgQ2FsY3VsYXRpb25zIGFuZCBFbnRoYWxweSBDaGFuZ2Vz\">Stoichiometric Calculations and Enthalpy Changes<\/h1>\n<div class=\"x-ck12-data-objectives\">\n<ul id=\"x-ck12-MTBhMGJkZTA0ZTVjMTQ4YTVlM2FlMjIxMWZhOTMwYmE.-5is\">\n<li>Perform calculations of enthalpy equations.<\/li>\n<\/ul>\n<\/div>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"textbox examples\">\n<h3>Examples<\/h3>\n<p id=\"x-ck12-YWIwMmExMGQ1MWVmMzdkMzA1MmRjZGUzMzlmMWUzNjI.-qwb\"><span class=\"x-ck12-img-inline\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212641\/20140811155648489887.jpeg\" alt=\"Enthalpy changes are important in many fields\" width=\"400\" \/><\/span><\/p>\n<p id=\"x-ck12-NDI0YzMzOTllYTA4NWVlMTM4MzU3ZTc3MTgzNThlMzQ.-fqd\"><strong>What will it cost?<\/strong><\/p>\n<p id=\"x-ck12-MGU4N2IzYmY4MzA4YmVhZGQzODdiOTgxNzg5ZmE1YTc.-o5i\">There is a growing concern about the damage to the environment from emissions from manufacturing plants. Many companies are taking steps to reduce these harmful emissions by adding equipment that will trap the pollutants. In order to know what equipment (and how many) to order, studies need to be done to measure the amount of product currently produced. The since pollution is often both particulate and thermal, energy changes need to be determined in addition to the amounts of products released.<\/p>\n<\/div>\n<p>&nbsp;<\/p>\n<h3>Stoichiometric Calculations and Enthalpy Changes<\/h3>\n<p id=\"x-ck12-MDZiMjA1MjRiMjkwYjMwYzQyY2ZiZmU2ODBmNWM2NmY.-dip\">Chemistry problems that involve enthalpy changes can be solved by techniques similar to stoichiometry problems.\u00a0 Refer again to the combustion reaction of methane. Since the reaction of 1 mol of methane released 890.4 kJ, the reaction of 2 mol of methane would release <img loading=\"lazy\" decoding=\"async\" id=\"x-ck12-MTM2Njk2NTMwNDkzNw..\" class=\"x-ck12-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212643\/03bfc49ec8ee20a13df5ba5e7fd497aa.png\" alt=\"2 times 890.4 text{ kJ} = 1781 text{ kJ}\" width=\"181\" height=\"14\" \/> . The reaction of 0.5 mol of methane would release <img loading=\"lazy\" decoding=\"async\" class=\"x-ck12-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212643\/e374cba43baf8e5e74f51c1dede0aa37.png\" alt=\"frac{890.4 text{ kJ}}{2}= 445.2 text{ kJ}\" width=\"138\" height=\"24\" \/> . As with other stoichiometry problems, the moles of a reactant or product can be linked to mass or volume.<\/p>\n<h4>Sample Problem: Calculating Enthalpy Changes<\/h4>\n<p id=\"x-ck12-MGZhMjJmYjAzZjk0ODE3Zjk3NzVlZjRiM2FhYzE0M2I.-fvm\">Sulfur dioxide gas reacts with oxygen to form sulfur trioxide in an exothermic reaction according to the following thermochemical equation.<\/p>\n<p id=\"x-ck12-cs6\"><img loading=\"lazy\" decoding=\"async\" class=\"x-ck12-block-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212644\/8bb42afd9ae6618e24d918c38be85ce1.png\" alt=\"2text{SO}_2(text{g}) + text{O}_2(text{g}) rightarrow 2text{SO}_3(text{g})+198 text{ kJ}\" width=\"293\" height=\"18\" \/><\/p>\n<p id=\"x-ck12-MWM5NzJkYzRhMGE3MTJmZjdiM2ZiZWEwM2FhZGZjNmU.-slo\">Calculate the enthalpy change that occurs when 58.0 g of sulfur dioxide is reacted with excess oxygen.<\/p>\n<p id=\"x-ck12-Y2VlNGQ1OTZkZWQ3ZDY1MzMyNmI1ODhhNWUzY2Q3NmU.-ufp\"><em>Step 1: List the known quantities and plan the problem <\/em>.<\/p>\n<p id=\"x-ck12-MmY1NjUwZTQ4NGZhMTk1OTQ5YWM2YzhkMTFkY2E0ZmQ.-dbh\"><span class=\"x-ck12-underline\">Known<\/span><\/p>\n<ul id=\"x-ck12-M2ZiMjJhMTBkYWY2MGViYjQyMDA4MjI3N2RjNDhkMzQ.-c9p\">\n<li>mass SO <sub>2 <\/sub>= 58.0 g<\/li>\n<li>molar mass SO <sub>2 <\/sub>= 64.07 g\/mol<\/li>\n<li><img loading=\"lazy\" decoding=\"async\" class=\"x-ck12-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212647\/e158ceda959f8818aa041ad9ee9dee98.png\" alt=\"Delta H = -198 text{ kJ for the reaction of } 2 text{ mol SO}_2\" width=\"354\" height=\"16\" \/><\/li>\n<\/ul>\n<p id=\"x-ck12-ODgxODNiOTQ2Y2M1ZjBlOGM5NmIyZTY2ZTFjNzRhN2U.-eru\"><span class=\"x-ck12-underline\">Unknown<\/span><\/p>\n<ul id=\"x-ck12-qpy\">\n<li><img loading=\"lazy\" decoding=\"async\" class=\"x-ck12-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212648\/b300f0495611e0feec35980a2ae4dc87.png\" alt=\"Delta H = ? text{ kJ}\" width=\"83\" height=\"14\" \/><\/li>\n<\/ul>\n<p id=\"x-ck12-NzYzMDZjYTg5NmE0ODYxMDBjZDI3MWNmOTQ3Yzg4OTU.-54h\">The calculation requires two steps. The mass of SO <sub>2 <\/sub>is converted to moles. Then the mol SO <sub>2 <\/sub>is multiplied by the conversion factor of <img loading=\"lazy\" decoding=\"async\" class=\"x-ck12-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212649\/39c584c39cae806f96d4eff4fec98335.png\" alt=\"left(frac{-198 text{ kJ}}{2 text{ mol SO}_2} right)\" width=\"79\" height=\"34\" \/> .<\/p>\n<p id=\"x-ck12-ZmYxNjkxNzA3ODcxNDhkYjhmZGUyOTFlNDk1NmEzZjE.-kyb\"><em>Step 2: Solve <\/em>.<\/p>\n<p id=\"x-ck12-08a\"><img loading=\"lazy\" decoding=\"async\" class=\"x-ck12-block-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212650\/34cb2d3e6b8ba0183747def3e70570b6.png\" alt=\"Delta H=58.0 text{ g SO}_2 times frac{1 text{ mol SO}_2}{64.07 text{ g SO}_2} times frac{-198 text{ kJ}}{2 text{ mol SO}_2}=-89.6 text{ kJ}\" width=\"458\" height=\"42\" \/><\/p>\n<p id=\"x-ck12-MGZhMzc5YjY2OWU0YzY0ZWM4YjYzZWNhYzc4OTQ3ZDA.-szg\"><em>Step 3: Think about your result <\/em>.<\/p>\n<p id=\"x-ck12-ZDk1Y2M1NThmNTg0NmU2NjNiYzkwNzU0NzJiOTY1YjY.-lsz\">The mass of sulfur dioxide is slightly less than 1 mol. Since 198 kJ is released for every 2 mol of SO <sub>2 <\/sub>that reacts, the heat released when about 1 mol reacts is one half of 198. The 89.6 kJ is slightly less than half of 198. The sign of\u00a0 <img loading=\"lazy\" decoding=\"async\" id=\"x-ck12-MTM2Njk2NTMwNDkzOA..\" class=\"x-ck12-math\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/53\/2014\/08\/19212619\/58e2d6b1f6cbdc5e4c424671b4016000.png\" alt=\"Delta H\" width=\"31\" height=\"12\" \/> is negative because the reaction is exothermic.<\/p>\n<div class=\"textbox key-takeaways\">\n<h3>Key Takeaways<\/h3>\n<h4>Summary<\/h4>\n<ul id=\"x-ck12-ZDY2NzNjOGRmN2E5MDhmNDg1NmMxZGQ2MGExOTJlNjM.-uzb\">\n<li>Calculations of energy changes in enthalpy equations are described.<\/li>\n<\/ul>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"textbox exercises\">\n<h3>Exercises<\/h3>\n<h4>Practice<\/h4>\n<p id=\"x-ck12-OTMxNmNlNTkxOTRhNDhiODhkYWE2MzgxNTlmMzI0ZGY.-obk\">Work on the problems at the site below. No peaking at the answers.<\/p>\n<p id=\"x-ck12-NTIyNzQwMjcwYmNmNzlkNDBiODRmMDI1N2Y1ZTE5Nzc.-nwm\"><a href=\"http:\/\/msmcraesscience.weebly.com\/uploads\/5\/1\/4\/4\/5144948\/enthalpy_stoichiometry_worksheet_1.pdf\">http:\/\/msmcraesscience.weebly.com\/uploads\/5\/1\/4\/4\/5144948\/enthalpy_stoichiometry_worksheet_1.pdf<\/a><\/p>\n<h4>Review<\/h4>\n<p id=\"x-ck12-NmNlM2JkYzM5ZTU0NDcyNTAzOGUwZTg3Yjc3MWRiMWU.-ckl\"><em>Questions<\/em><\/p>\n<ol id=\"x-ck12-NDk3NmEwMmU5YWE3YTVlODE5OTQ5MmRhNDc5ZDkwN2Y.-b5h\">\n<li>What do you need to determine to solve enthalpy stoichiometry problems?<\/li>\n<li>If I react 1.75 moles of methane, how much energy will be involved?<\/li>\n<li>I ran a reaction producing sulfur dioxide and releasing 267.3 kJ of energy. How many moles of sulfur dioxide were involved in the reaction?<\/li>\n<\/ol>\n<div class=\"x-ck12-data-problem-set\"><\/div>\n<\/div>\n<p>&nbsp;<\/p>\n<div class=\"x-ck12-data-vocabulary\"><\/div>\n<h1 id=\"x-ck12-SGVhdHMgb2YgRnVzaW9uIGFuZCBTb2xpZGlmaWNhdGlvbg..\"><\/h1>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q836080\">Show References<\/span><\/p>\n<div id=\"q836080\" class=\"hidden-answer\" style=\"display: none\">\n<h2>References<\/h2>\n<ol>\n<li>Rennett Stowe. <a href=\"http:\/\/www.flickr.com\/photos\/tomsaint\/3518071026\/\">http:\/\/www.flickr.com\/photos\/tomsaint\/3518071026\/ <\/a>.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n","protected":false},"author":1507,"menu_order":11,"template":"","meta":{"_candela_citation":"[]","CANDELA_OUTCOMES_GUID":"","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-2690","chapter","type-chapter","status-publish","hentry"],"part":2338,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/chapters\/2690","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/wp\/v2\/users\/1507"}],"version-history":[{"count":4,"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/chapters\/2690\/revisions"}],"predecessor-version":[{"id":3557,"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/chapters\/2690\/revisions\/3557"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/parts\/2338"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/chapters\/2690\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/wp\/v2\/media?parent=2690"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/pressbooks\/v2\/chapter-type?post=2690"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/wp\/v2\/contributor?post=2690"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/umes-cheminter\/wp-json\/wp\/v2\/license?post=2690"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}