Learning Outcome
- Factor a trinomial using the ac-method
A method that is often used when the coefficient of the leading term (i.e., the coefficient of ) is not 1 is called the ac-method. This method splits the -term into the sum of two terms so that we can use grouping to factor the function. Determining how to split up the -term is done by finding two numbers whose product is and whose sum is , where are real number coefficients of the function .
Suppose we wish to factor . The first step is to figure out how to write the -term as the sum of two new terms. We are looking for two numbers, , with a product of and a sum of . We start by listing factors of 6, then look at their sum. A table can be useful to keep everything organized.
Factors: | Sum: |
---|---|
The pair and gives the correct -term of , so we will write :
Now we can group the polynomial into two binomials,
then factor by grouping:
Factoring using the ac-method
To factor a trinomial function of the form by grouping, we find two numbers with a product of and a sum of . We use these numbers to divide the -term into the sum of two terms and factor each portion of the expression separately. Then we factor out the GCF of the entire expression.
Example 1
Factor .
Solution
We have a trinomial with , and .
so we need to find two numbers , with a product of and a sum of . In the table, we list factors until we find a pair with the desired sum.
Factors: | Sum: |
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So and .
Now write in the function and factor by grouping:
We can check our work by multiplying. Use the distributive property to confirm that .
In this example, when we wrote , we can just as easily write . We will end up with the same factorization:
The commutative property of multiplication says , so we have the same result as before.
We can summarize our process in the following way:
factoring a trinomial function by the ac-method
To factor a trinomial function of the form ,
- List factors of .
- Find and , factors of with a sum of .
- Write the original expression as .
- Factor by grouping.
Factoring trinomials whose leading coefficient is not becomes quick and kind of fun once you get the idea.
Example 2
Factor .
Solution
Find two numbers, , such that and .
and are both positive, so we will only consider positive factors.
Factors of | |
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We can stop because we have found our factors.
Write the as , then factor by grouping:
Answer
Try It 1
Factor .
If the leading term is negative, we can pull out –1 as a GCF before we factor the trinomial.
Example 3
Factor .
Solution
Start by pulling –1 as a GCF. This will change all of the signs of the coefficients:
Now, so we need two numbers, , whose product is –84 and whose sum is –8.
Product: | Sum: |
Write as then factor by grouping:
Try It 2
Factor .
Sometimes we encounter polynomials that, despite our best efforts, cannot be factored into the product of two binomials. Such polynomials are said to be prime.
Example 4
Factor .
Solution
, . We need to find two numbers , where and .
Factors: | Sum: |
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None of the factors add up to so the trinomial cannot be factored.
is prime.
Before we jump head first into factoring a trinomial, we should always look to see if there is a GCF that can be “pulled out”.
Example 5
Factor .
Solution
The terms in the function have a GCF of 3x, so we will pull out the GCF first:
To factor the trinomial, and so, we need two numbers that multiply to -18 and add to 7: 9 and –2.
Write then factor by grouping:
Try It 3
Factor
Remember to always look for a GCF before jumping in to factoring any trinomial.
Example 6
Factor .
Solution
First notice that is common to all terms in the trinomial. Also 72, 168, and 144 have at least 2 in common. Let’s factor them to find the GCF:
Factor out the GCF of from the trinomial:
Now use the -method:
and : and
Write then factor by grouping:
Try It 4
Factor
Candela Citations
- Revision and Adaptation. Authored by: Hazel McKenna. Provided by: Utah Valley University. License: CC BY: Attribution
- Try It: hjm583; hjm108; hjm877; hjm647 Examples 5 and 6. Authored by: Hazel McKenna. Provided by: Utah Valley University. License: CC BY: Attribution
- Revision and Adaptation. Provided by: Lumen Learning. License: CC BY: Attribution
- Unit 12: Factoring, from Developmental Math: An Open Program. Provided by: Monterey Institute of Technology and Education. Located at: http://nrocnetwork.org/dm-opentext. License: CC BY: Attribution