Learning Objectives
- Determine the pattern of exponential growth
- Define and graph exponential functions
- Describe the asymptote of an exponential function
- Find the domain and range of an exponential function
Exponential Growth
In Chapter 2, we looked at linear growth where there is a constant rate of change. Unlike linear growth that increases by adding a constant value to yy for every unit increase in xx, exponential growth increases by multiplying by a constant that is neither equal to 0 nor 1. Table 1 shows exponential growth as each yy-value increases by a multiple of 2. Notice that the values in the xx column correspond to the exponents in the fourth column. This is because the values in the xx column record the number of times we have multiplied by 2.
xx | yy | ||
1 | 2 | =2=2 | =21=21 |
2 | 4 | =2⋅2=2⋅2 | =22=22 |
3 | 8 | =2⋅2⋅2=2⋅2⋅2 | =23=23 |
4 | 16 | =2⋅2⋅2⋅2=2⋅2⋅2⋅2 | =24=24 |
5 | 32 | =2⋅2⋅2⋅2⋅2=2⋅2⋅2⋅2⋅2 | =25=25 |
Table 1. Exponential growth |
The pattern shown in the fourth column of table 1 indicates that exponential growth is repeated multiplication by a factor of 2 so the equation for the pattern is y=2xy=2x.
Zero and Negative Exponents
Table 1 shows the pattern of exponential growth of 2x2x when xx is a natural number. But what is the value of 2x2x when the exponent xx is zero or a negative number? If we consider the pattern in Table 1 in the reverse direction we can find the value of y=2xy=2x when x=0,−1,−2,...x=0,−1,−2,.... As the exponent decreases by 1, the value of y=2xy=2x is divided by 2.
For example, 2x=82x=8 when the exponent xx is 3 (i.e., y=23=8y=23=8). As xx decreases by 1 to 2, the yy value is 4 (See Table 2). In other words, 8 is divided by 2 to get 4. Following this logic, the yy value will be 4 ÷ 2 = 2 when xx decreases by 1 again to 1. Following this pattern, the yy value will be 2 ÷ 2 = 1 when xx decreases by 1 again to zero. Therefore, 20=120=1. In fact, a0=1a0=1 for all values of aa, a≠0a≠0. 0000 is undefined.
Exponent of Zero
a0=1a0=1 for all values of aa, a≠0a≠0. 0000 is undefined.
Continuing this reverse pattern, the value of yy will be 1÷2=121÷2=12 when x=−1x=−1. Then, dividing by 2 again gives y=12÷2=12⋅12=14y=12÷2=12⋅12=14 when x=−2x=−2. Recall that dividing by 2 is equivalent to multiplying by 1212. This pattern shows that the value of yy is a fraction where y=12|x|y=12|x| when the exponent xx is a negative number (See Table 2). For example, y=2−3=12|−3|=123y=2−3=12|−3|=123. In fact, the value of y=axy=ax will alway be 1a|x|1a|x| when the exponent xx is a negative number and the base a≥0a≥0.
Negative Exponents
y=ax=1a|x|y=ax=1a|x| when the exponent xx is a negative number and a≥0a≥0.
Table 3 shows how the values of y=2xy=2x for the exponents x=0,−1,−2,−3...x=0,−1,−2,−3... are obtained following the reverse pattern starting at x=0x=0.
xx | yy | Method for Obtaining yy | Equation |
-3 | 1818 | =12⋅12⋅12=12⋅12⋅12 | 2−32−3 |
-2 | 1414 | =12⋅12=12⋅12 | 2−22−2 |
-1 | 1212 | =12=12 | 2−12−1 |
0 | 1 | =2⋅12=2⋅12 = 1 | 2020 |
1 | 2 | =2=2 | 2121 |
2 | 4 | =2⋅2=2⋅2 | 2222 |
3 | 8 | =2⋅2⋅2=2⋅2⋅2 | 2323 |
4 | 16 | =2⋅2⋅2⋅2=2⋅2⋅2⋅2 | 2424 |
5 | 32 | =2⋅2⋅2⋅2⋅2=2⋅2⋅2⋅2⋅2 | 2525 |
Table 2. Exponential growth with base 2 |
Zero and negative exponents will be discussed again in section 5.3.2 using the Product and Quotient Rule for Exponents.
Example 1
Complete the table for the equation y=10xy=10x.
xx | yy | Method for Obtaining yy | Equation |
-3 | y=10−3y=10−3 | ||
-2 | y=10−2y=10−2 | ||
-1 | y=10−1y=10−1 | ||
0 | y=100y=100 | ||
1 | 10 | =10=10 | y=101y=101 |
Solution
Since the base of the function is 10, we divide the yy-value by 10 as xx decreases by 1.
xx | yy | Method for Obtaining yy | Equation |
-3 | 1100011000 | 1100÷10=110001100÷10=11000 | y=10−3y=10−3 |
-2 | 11001100 | 110÷10=1100110÷10=1100 | y=10−2y=10−2 |
-1 | 110110 | 1÷10=1101÷10=110 | y=10−1y=10−1 |
0 | 1 | 10÷10=110÷10=1 | y=100y=100 |
1 | 10 | =10=10 | y=101y=101 |
Try It 1
Complete the table for the equation y=3xy=3x.
xx | yy | Method for Obtaining yy | Equation |
-3 | y=3−3y=3−3 | ||
-2 | y=3−2y=3−2 | ||
-1 | y=3−1y=3−1 | ||
0 | y=30y=30 | ||
1 | 3 | 33 | y=31y=31 |
Solution
Since the base of the function is 3, we divide the yy-value by 3 as xx decreases by 1.
xx | yy | Method for Obtaining yy | Equation |
-3 | 127127 | 19÷3=12719÷3=127 | y=3−3y=3−3 |
-2 | 1919 | 13÷3=1913÷3=19 | y=3−2y=3−2 |
-1 | 1313 | 1÷3=131÷3=13 | y=3−1y=3−1 |
0 | 1 | 3÷3=13÷3=1 | y=30y=30 |
1 | 3 | =3=3 | y=31y=31 |
Example 2
Evaluate y=4xy=4x when,
a) x=1x=1
b) x=3x=3
c) x=0x=0
d) x=−2x=−2
e) x=−3x=−3
Solution
a) 41=441=4
b) 43=4⋅4⋅4=6443=4⋅4⋅4=64
c) 40=140=1
d) 4−2=142=1164−2=142=116
e) 4−3=143=1644−3=143=164
Try It 2
Evaluate y=7xy=7x when,
a) x=1x=1
b) x=2x=2
c) x=0x=0
d) x=−2x=−2
e) x=−3x=−3
The Difference between Exponential Growth and Power Growth
In exponential growth, the variable is the exponent (e.g., 2x2x). In power growth, the variable is the base (e.g., x2x2). Exponential growth grows faster than power growth. For example, table 3 shows that the exponential growth 2x2x grows much faster than the power growth x2x2 while table 4 shows that the exponential growth 3x3x grows much faster than the power growth x3x3.
xx | x2x2 | 2x2x | xx | x3x3 | 3x3x | |
0 | 0 | 1 | 0 | 0 | 1 | |
1 | 1 | 2 | 1 | 1 | 3 | |
2 | 4 | 4 | 2 | 8 | 9 | |
3 | 9 | 8 | 3 | 27 | 27 | |
4 | 16 | 16 | 4 | 64 | 81 | |
5 | 25 | 32 | 5 | 125 | 243 | |
6 | 36 | 64 | 6 | 216 | 729 | |
7 | 49 | 128 | 7 | 343 | 2187 | |
8 | 64 | 256 | 8 | 512 | 6561 | |
Table 3. Exponential versus power growth | Table 4. Exponential versus power growth |
Initial Value
The initial value of exponential growth occurs at x=0x=0. So far we have considered only initial values of 1. Tables 1 and 2 show a pattern where y=1⋅2xy=1⋅2x. However, the initial value can be any real number.
For example, let’s consider an initial value of 8 and an exponential growth rate of 2. We can create a table that illustrates this scenario starting with y=8y=8 when x=0x=0, then multiplying each yy-value by 2:
xx | yy | Equation |
-2 | 4÷2=24÷2=2 | 8⋅2−28⋅2−2 |
-1 | 8÷2=48÷2=4 | 8⋅2−18⋅2−1 |
0 | 88 | y=8⋅20y=8⋅20 |
1 | 8⋅2=168⋅2=16 | 8⋅218⋅21 |
2 | 16⋅2=3216⋅2=32 | 8⋅228⋅22 |
3 | 32⋅2=6432⋅2=64 | 8⋅238⋅23 |
The equation that models an exponential growth rate of 2 with an initial value of 8 is y=8⋅2xy=8⋅2x.
Exponential Growth
The equation that models an exponential growth rate of rr with an initial value of aa is y=a⋅rxy=a⋅rx.
Example 3
Complete the table for an exponential growth of 4 and an initial value of 3. Then write an equation for the exponential growth pattern.
xx | yy |
–2–2 | |
–1–1 | |
00 | |
11 | |
22 | |
33 |
Solution
The initial value of 3 occurs when x=0x=0 so we can add that to the table. Then we can multiply by 4 each time to determine the yy-values for x=1,2x=1,2. To find the yy-values for x=−1,−2x=−1,−2, we work backwards by dividing the initial value by 4.
xx | yy |
–2–2 | 3÷4÷4=3163÷4÷4=316 |
–1–1 | 3÷4=343÷4=34 |
00 | 33 |
11 | 3⋅4=123⋅4=12 |
22 | 3⋅4⋅4=483⋅4⋅4=48 |
33 | 3⋅4⋅4⋅4=1923⋅4⋅4⋅4=192 |
The pattern is y=3⋅4xy=3⋅4x
Try It 3
Complete the table for an exponential growth of 3 and an initial value of 5. Then write an equation for the exponential growth pattern.
Try It 4
Write an equation for the following exponential growth patterns:
1. growth = 6; initial value = 4
2. growth = 2; initial value = 9
3. growth = 2323; initial value = 5
4. growth = 0.77; initial value = –5.4
Exponential Functions and Their Graphs
Exponential growth has an initial value and an exponential rate of change. The initial value occurs at x=0x=0. In table 1, the initial value is 1 (when x=0x=0), and the exponential rate of change is 2. This creates a pattern where y=1⋅2xy=1⋅2x. Consequently, the exponential growth in table 1 may be modeled or represented by the function f(x)=2xf(x)=2x.
If we graph the values (x,y)(x,y) from table 1, we can then connect the points to draw the graph the exponential function f(x)=2xf(x)=2x (figure 1).

Figure 1. The graph of the function f(x)=2xf(x)=2x.
Example 4
Create a table of values then graph the function f(x)=(12)xf(x)=(12)x.
Solution
We can choose any xx-values to create a table for y=f(x)y=f(x):
xx | yy |
00 | (12)0=1(12)0=1 |
11 | (12)1=12(12)1=12 |
22 | (12)2=14(12)2=14 |
−1−1 | (12)−1=21=2(12)−1=21=2 |
−2−2 | (12)−2=22=4(12)−2=22=4 |
−3−3 | (12)−3=23=8(12)−3=23=8 |
We plot the (x,y)(x,y) points from the table:
Then join the points with a smooth curve:
Try It 5
Create a table of values then graph the function f(x)=4xf(x)=4x.
The Definition of an Exponential Function
An exponential function has the form f(x)=rxf(x)=rx, where rr is a real number with r>0r>0 and r≠1r≠1.
Figure 2 illustrates how the graph changes as the value of rr changes. Move the red circle up or down to change the value of rr and watch what happens to the function.
Figure 2. Interactive graph f(x)=rxf(x)=rx
Manipulate the graph of f(x)=rxf(x)=rx in figure 2 to answer the following questions:
1. What happens to the point (0, 1) as rrchanges?
The point (0, 1) never changes. The point (0, 1) is always on the graph of f(x)=rxf(x)=rx.
2. What happens to the point on the graph at x=1x=1 as rrchanges?
At x=1x=1, the point on the graph will always be (1,r)(1,r), because f(1)=r1=rf(1)=r1=r.
3. What happens to the graph when r=1r=1?
If r=1r=1 we get a flat line; a linear equation y=1y=1. This is why rr is never allowed to equal 1.
4. What happens to the graph when r=0r=0?
If r=0r=0 we get a flat line starting at x>0x>0. f(0)=00f(0)=00 which is undefined. For any x<0x<0, 0negative number=10positive number=100negative number=10positive number=10, which is undefined. This is why rr is never allowed to equal 0.
5. What happens to the graph when r<0r<0?
When r<0r<0, the graph disappears!! This is why rr is a positive real number ≠ 0, 1.
6. What happens to the graph when r>1r>1?
The graph comes up from y=0y=0, passes through (0, 1) and (1, r), then quickly moves towards +∞+∞.
7. What happens to the graph when [latex]0
The Asymptote and Intercepts
A significant feature on the graph of any exponential function f(x)=rx (r>0,r≠1) is that the graph never crosses the x-axis. It continually approaches the x, getting closer and closer, but the graph never meets the x-axis. Figure 2 illustrates that when [latex]0
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Figure 3. f(x)=rx with [latex]0 | Figure 4. f(x)=rx with r>1 |
Why does the graph never meet the x-axis? Consider the following examples using the function f(x)=2x that was graphed in figure 1:
f(−10)=2−10=1210
f(−100)=2−100=12100
f(−100000)=2−100000=12100000
As the the value of x gets closer to negative infinity, the value of the function y is a fraction with a numerator of 1 and a denominator that is a very large positive number. The value of x gets more and more negative as it gets closer to negative infinity, so the value of the function will get smaller and smaller. It will get close to zero but will never be zero because 1very large positive number is always positive and therefore greater than zero.
Figure 2 shows that for all values of r>0 and r≠1, the graph gets close to but never crosses the x-axis, it is a horizontal asymptote of the function f(x)=rx. Also, since the graph never meets the x-axis, there is no x-intercept for the function. The y-intercept of the function f(x)=rx is always (0, 1).
We use a dotted line to show that a graph has a horizontal asymptote (figure 5).

FIgure 5. Exponential function with horizontal asymptote.
Domain and Range
Figure 5 shows the graph of f(x)=2x. The domain of the function is the set of all possible x-values, so domain = {x|x∈R}. Any x-value from −∞ to +∞ has a corresponding function value. It’s range, the set of all function values, lies above the line y=0. Consequently, the range ={f(x)|f(x)∈R+}, where R+ is the set of all positive real numbers.
DOMAIN and RANGE
The domain of any exponential function f(x)=rx is all real numbers, or {x|x∈R}, or (−∞,∞). The range of any exponential functionf(x)=rx is all real numbers that are above the horizontal asymptote. Range = {f(x)|f(x)∈R+}, or (0,∞).
The exponential function f(x)=rx is the parent function of all exponential functions. In the next section, we will see what happens to the graph of the function when we transform the parent function.
Candela Citations
- Exponential functions and Their Graphs. Authored by: Hazel McKenna and Leo Chang. Provided by: Utah Valley University. License: CC BY: Attribution
- All graphs created using desmos graphing calculator. Authored by: Hazel McKenna. Provided by: Utah Valley University. License: CC BY: Attribution
- All examples and Try its: hjm585; hjm469; hjm118. Authored by: Hazel McKenna. Provided by: Utah Valley University. License: CC BY: Attribution