Learning Outcomes
- Determine the role that the values and play in the graph of
Keywords
- Parent equation: the simplest form of a general equation
- Parabola: the shape of any quadratic equation
Graphing Quadratic Equations Using Transformations
In the previous section we learned that the shape of is called a parabola. The turning point on the graph is called the vertex. The vertical line that passes through the vertex and splits the parabola into two mirror images is called the line of symmetry. All quadratic functions have graphs in the shape of a parabola. However, in the general equation the values of , , and change the direction, shape, and position of the graph. Let’s discover how changing these values can transform a graph.
How affects the graph of
Figure 1 shows an animation of the graph as the value of moves between and . Click on the desmos logo at the bottom right corner of the graph to manipulate the value of .
Figure 1: Animation of as changes.
The value of tells us whether the parabola opens upwards () or downwards (). If is positive, the vertex is the turning point and the lowest point on the graph and the graph opens upward. If is negative, the vertex is the turning point and the highest point on the graph and the graph opens downward.
Figure 2. Graph of with different values of .
The value of also tells us about the width of the graph. When , as in in figure 2, the graph will appear more narrow than . When , as in in figure 2, the graph will appear wider than .
Example
Match each function with its graph.
1.
2.
3.
4.

Graph A

Graph B

Graph C

Graph D
Solution
1. opens upwards and passes through the point : Graph D
2. nopens downwards and passes through the point : Graph B
3. opens downwards and passes through the point : Graph C
4. opens upwards and passes through the point : Graph A
We can compare the graphs to the graph of the parent equation . If , the graph of will be thinner than that of . If , the graph of will be broader than that of . And remember that when the graph opens downwards.
Example
Given the graph of shown in black, determine the relative value of in the graph of shown in blue.

Graph 1

Graph 2

Graph 3
Graph 1. The blue graph is narrower than the graph of and opens upwards, which means that .
Graph 2. The blue graph opens downwards so has a negative value of . It is also broader that so . This means that [latex]-11[/latex].
Try It
Determine whether each statement is true or false. Support your answer.
1. The graph of is narrower than the graph of .
2. The graph of is broader than the graph of .
3. The graph of opens in the same direction as .
4. The graph of opens in the same direction as and is broader than .
Think about It
We said that:
If , the graph of will be thinner than that of . If , the graph of will be broader than that of . And remember that when the graph opens downwards. What about if ? What happens to the graph of when ?
How affects graphs of quadratic equations
When a quadratic equation is in the form , and there is no -term. Figure 3 shows an animation of the graph as the value of moves between and . Click on the desmos logo at the bottom right corner of the graph to manipulate the value of .
Figure 3: Animation of as changes.
Changing the value of moves the parabola up or down the -axis. If , the graph of moves up the axis units. If , the graph of moves down the axis units.
Figure 4. Graph of with different values of .
Example
Explain how the graph of the given equation is different from the graph of .
1.
2.
Solution
1. The graph of looks exactly like the graph of but it has been moved vertically up by units.
2. The graph of looks exactly like the graph of but it has been moved vertically down by units.
Try It
Explain how the graph of the given equation is different from the graph of .
1.
2.
Try It
Determine the equation of each graph, using the graph of shown in black as the parent graph.

Graph 1

Graph 2
When we are graphing any quadratic equation, it is also useful to know that corresponds to the -intercept of the graph of any quadratic equation. The -intercept occurs when and is the point at which the graph crosses the -axis. Recall that we determine the value of by substituting into the equation:
For a quadratic equation, the -intercept is always the point .
How affects graphs of quadratic equations
When a quadratic equation is in the form , and therefore the -intercept will always be . Figure 5 shows an animation of the graph as the value of moves between and . Click on the desmos logo at the bottom right corner of the graph to manipulate the value of .
Figure 5. Animation of as changes.
Changing moves the vertex and the line of symmetry, which is the vertical line that passes through the vertex of the parabola. When the vertex moves to the left. When the vertex moves to the right. However, the vertex doesn’t just move horizontally, but vertically as well. Notice that the vertex moves following a parabolic curve! Moving the vertex also moves the line of symmetry, since the line of symmetry passes through the vertex. In addition, notice that the – and -intercepts stay the same at , but the other -intercept moves between when to when .
To help explain this movement, let’s find the -intercepts by setting :
So the -intercepts are . is a fixed point so does not move as the value of changes. However, changes as changes. For example, when the intercept changes to and when the intercept changes to . Do you see the pattern?
Figure 6. Graph of with -intercepts at and .
Examples
State the -intercepts of the graph of the equation:
1.
2.
3.
Solution
The -intercepts of the graph of are and .
1. Since , the intercepts are and .
2. Since , the intercepts are and .
3. Since , the intercepts are and .
Try It
State the -intercepts of the graph of the equation:
1.
2.
3.
Because of symmetry, the vertex is always exactly halfway between the two -intercepts and . For example, in the graph the -intercepts are and (figure 7). The axis of symmetry is the vertical line that passes through the vertex and lies exactly halfway between and . i.e. the line of symmetry is .

Figure 7.
This also means that the vertex has an -value of since the line of symmetry passes through the vertex. The -coordinate of the vertex is found by substituting into the equation : . So the vertex is the point as can be seen on the graph in figure 7.
In the more general case of , the line of symmetry is exactly halfway between the two -intercepts and . i.e. the line of symmetry is . Of course, this assumes that and . If and take on different values, determining the exact movement of the graph becomes a little more difficult.
The following animation shows what happens to the graph of when the values of and are changed. Click on the desmos logo at the bottom right corner of the graph to manipulate the values.
Figure 8. Animation of as [a, b[/latex] and change.
Examples
Explain how the graph of the given equation is different from the graph of .
1.
2.
3.
4.
5.
Solution
- Since the graph looks the same as but since it has been moved vertically down by 7 units.
- SInce the graph is thinner than . The -value is 6 times larger than .
- Since is negative the graph looks like an upside down version of and since it has also been moved vertically up by 5 units.
- Since the graph is upside down compared to , is broader than , and since it has been moved vertically up by 3 units.
- Since the graph is thinner than and since has been moved vertically down by 8 units.
Try It
Explain how the graph of the given equation is different from the graph of .
1.
2.
3.
4.
5.
Examples
Given the -intercepts of a parabola, determine the axis of symmetry.
1. (-4, 0) and (0, 0)
2. (2, 0) and (8, 0)
3. (-3, 0) and (7, 0)
Solution
The axis of symmetry runs exactly halfway between the two intercepts.
- There are 4 units between -4 and 0, so the axis is 2 units away from both points:
- There are 6 units between 2 and 8, so the axis is 3 units away from both points:
- There are 10 units between -3 and 7, so the axis is 5 units away from both points:
Try It
Given the -intercepts of a parabola, determine the axis of symmetry.
1. (0, 0) and (4, 0)
2. (-2, 0) and (4, 0)
3. (-5, 0) and (1, 0)
Examples
Given two points on a parabola, determine the axis of symmetry.
1. (3, 4) and (9, 4)
2. (-2, 1) and (6, 1)
3. (-2, -5) and (3, -5)
Solution
Since the -values are the same in both points, the points are twins and the axis of symmetry runs exactly halfway between them.
- There are 6 units between 3 and 9, so the axis is 3 units away from both points:
- There are 8 units between -2 and 6, so the axis is 4 units away from both points:
- There are 5 units between -2 and 3, so the axis is 2.5 units away from both points:
Try It
Given two points on a parabola, determine the axis of symmetry.
1. (-2, 7) and (11, 7)
2. (-8, 1) and (-4, 1)
3. (-7, -8) and (1, -8)