Learning Objectives
- Explain what an equation in one variable represents.
- Determine if a given value for a variable is a solution of an equation.
- Classify an equation as conditional, a contradiction or an identity.
Key words
- solution: a value that can be substituted for a variable to make an equation true.
- unknown: a variable in an equation that needs to be solved for.
- equation: a mathematical statement that asserts the equivalence of two expressions.
- conditional equation: an equation that has a solution
- contradiction: an equation that has no solution
- identity: an equation that is always true
What is an Equation?
An equation is a mathematical statement that asserts the equivalence of two expressions. For example, the assertion that “two plus five equals seven” is represented by the equation [latex]2 + 5 = 7[/latex].
In most cases, an equation contains one or more variables. For example, the equation [latex]x + 3 = 5[/latex], read “[latex]x[/latex] plus three equals five”, asserts that the expression [latex]x+3[/latex] is equal to the value [latex]5[/latex].
It is possible for equations to have more than one variable. For example, [latex]x + y + 7 = 13[/latex] is an equation in two variables, while [latex]5x^2+y^2+9z^2=36[/latex] is an equation in three variables.
Solving Equations
When an equation contains a variable such as [latex]x[/latex], this variable is considered an unknown value. In many cases, we can find the values for [latex]x[/latex] that make the equation true. These values are called solutions of the equation.
For example, consider the equation we were talking about above: [latex]x + 3 =5[/latex]. You have probably already guessed that the only possible value of [latex]x[/latex] that makes the equation true is 2, because [latex]2 + 3 = 5[/latex]. We use an equals sign to show that we know the value of a given variable. In this case, [latex]x=2[/latex] is the only solution of the equation[latex]x + 3 =5[/latex].
The values of the variables that make an equation true are called the solutions of the equation. In turn, solving an equation means determining what values for the variables make the equation a true statement.
The equation above was fairly straightforward; it was easy for us to identify the solution as [latex]x = 2[/latex]. However, it becomes useful to have a process for finding solutions for unknowns as problems become more complex.
Verifying Solutions
If a number is found as a solution of an equation, then substituting that number back into the equation in place of the variable should make the equation true. Thus, we can easily check whether a number is a genuine solution to a given equation.
For example, let’s examine whether [latex]x=3[/latex] is a solution to the equation [latex]2x + 31 = 37[/latex].
Substituting 3 for [latex]x[/latex], we have:
[latex]2x + 31 = 37 \\ 2\color{blue}{(3)} + 31 = 37 \\ 6 + 31 = 37 \\ 37 = 37[/latex]
This equality is a true statement. Therefore, we can conclude that [latex]x = 3[/latex] is, in fact, a solution of the equation [latex]2x+31=37[/latex].
Examples
Determine whether or not [latex]x=-2[/latex] is a solution of the following equations:
1. [latex]3x+7=1[/latex]
2. [latex]-3x^2-x+10=0[/latex]
3. [latex]\sqrt{x^2}=x[/latex]
Solution
Replace [latex]x[/latex] i each equation with [latex]-2[/latex] and check if the equation is true.
1. [latex]3x+7=1 \\ 3\color{blue}{(-2)}+7=1 \\ -6+7=1 \\ 1=1[/latex] TRUE [latex]x=-2[/latex] is a solution.
2. [latex]-3x^2-x+10=0 \\ -3(\color{blue}{(-2)}^2-\color{blue}{(-2)}+10=0 \\ -3\cdot 4 + 2 + 10 = 0 \\ -12 + 2 + 10 = 0 \\ 0 = 0[/latex] TRUE [latex]x=-2[/latex] is a solution.
3. [latex]\sqrt{x^2}=x \\ \sqrt{\color{blue}{(-2)}^2}=\color{blue}{(-2)} \\ \sqrt{4}=-2 \\ 2=-2[/latex] FALSE [latex]x=-2[/latex] is NOT a solution.
Try It
Determine whether or not [latex]x=3[/latex] is a solution of the following equations:
1. [latex]-2x+5=-1[/latex]
2. [latex]-2x^2+4x+30=0[/latex]
3. [latex]\sqrt{4x^2}=2x[/latex]
Examples
Determine whether the pair of values [latex]x=1 \text{ and }y=-2[/latex] is a solution of the equation.
1. [latex]4x+y=2[/latex]
2. [latex]x^2 + y^2=-3[/latex]
Solution
Replace [latex]x[/latex] with [/altex]1[/latex] and [latex]y[/latex] with [latex]-2[/latex].
1. [latex]4x+y=2 \\ 4\color{blue}{(1)}+\color{blue}{(-2)}=2 \\ 4 + (-2) = 2 \\ 2 = 2[/latex] TRUE. [latex]x=1,\,y=-2[/latex] is a solution of the equation.
2.[latex]x^2 + y^2 = -3 \\\color{blue}{(1)}^2 +\color{blue}{(-2)}^2 = -3 \\ 1 + 4 = 3 \\ 5 = 3[/latex] FALSE. [latex]x=1,\,y=-2[/latex] is NOT a solution of the equation.
Try It
Determine whether the pair of values [latex]x=2 \text{ and }y=-3[/latex] is a solution of the equation.
1. [latex]x-y=-1[/latex]
2. [latex]x^2 - y^2=-5[/latex]
Classes of Equations
Equations can be broadly classified into three categories:
- Conditional equations
- Contradictions
- Identities
Let’s take a closer look at equations in each of these categories.
Candela Citations
- All examples and Try Its. Authored by: Hazel McKenna. Provided by: Utah Valley University. License: CC BY: Attribution
- Classes of Equations. Authored by: Leo Chang and Hazel McKenna. Provided by: Utah Valley University. License: CC BY: Attribution
- Curation and Revision. Authored by: Boundless.com. License: Public Domain: No Known Copyright