### Learning Outcomes

- Use the substitution method to find solution(s) to a system of two linear equations.
- Use the addition method to find solution(s) to a system of linear equations.

## Solving Systems of Equations by Substitution

Solving a linear system in two variables by graphing works well when the solution consists of integer values, but if our solution contains decimals or fractions, it is not the most precise method. We will consider two more methods of solving a **system of linear equations** that are more precise than graphing. One such method is solving a system of equations by the **substitution method**, in which we solve one of the equations for one variable and then substitute the result into the second equation to solve for the second variable. Recall that we can solve for only one variable at a time, which is the reason the substitution method is both valuable and practical.

### How To: Given a system of two equations in two variables, solve using the substitution method.

- Solve one of the two equations for one of the variables in terms of the other.
- Substitute the expression for this variable into the second equation, then solve for the remaining variable.
- Substitute that solution into either of the original equations to find the value of the first variable. If possible, write the solution as an ordered pair.
- Check the solution in both equations.

### Example: Solving a System of Equations in Two Variables by Substitution

Solve the following system of equations by substitution.

[latex]\begin{align}-x+y&=-5 \\ 2x-5y&=1 \end{align}[/latex]

In the following video, you will be given an example of solving a system of two equations using the substitution method.

If you had chosen the other equation to start with in the previous example, you would still be able to find the same solution. It is really a matter of preference, because sometimes solving for a variable will result in having to work with fractions. As you become more experienced with algebra, you will be able to anticipate what choices will lead to more desirable outcomes.

### tip for success

Since the concepts in this module rely heavily upon those from earlier modules, feel free to go back to review information you may not have fully obtained the first time. Math is best digested over time with repetition that leads to deeper appreciation of the ideas involved.

Additional practice will also help you build skills using learned concepts in creative ways to make good choices of technique in different situations.

### Try It

You can use an online graphing calculator to help you solve a system of equations by substitution. We will use the following system to show you how:

[latex]\begin{align}x&=y+3 \\ 4&=3x - 2y \end{align}[/latex]

First, solve both equations for y:

[latex]\begin{align}y&=x-3 \\ y&=\frac{3}{2}x - 2 \end{align}[/latex]

Now enter [latex]x-3=\frac{3}{2}x - 2[/latex] into the calculator. You will see that calculator has provided you with [latex]x = -2[/latex].

You now can substitute [latex]x = -2[/latex] into both equations. If you get the same result for both, you have found an ordered pair solution. Give it a try.

https://ohm.lumenlearning.com/multiembedq.php?id=115164&theme=oea&iframe_resize_id=mom2

### Q & A

#### Can the substitution method be used to solve any linear system in two variables?

*Yes, but the method works best if one of the equations contains a coefficient of 1 or –1 so that we do not have to deal with fractions.*

The following video is ~10 minutes long and provides a mini-lesson on using the substitution method to solve a system of linear equations. We present three different examples, and also use a graphing tool to help summarize the solution for each example.

## Solving Systems of Equations in Two Variables by the Addition Method

A third method of **solving systems of linear equations** is the **addition method, **this method is also called the **elimination method**. In this method, we add two terms with the same variable, but opposite coefficients, so that the sum is zero. Of course, not all systems are set up with the two terms of one variable having opposite coefficients. Often we must adjust one or both of the equations by multiplication so that one variable will be eliminated by addition.

### How To: Given a system of equations, solve using the addition method.

- Write both equations with
*x*– and*y*-variables on the left side of the equal sign and constants on the right. - Write one equation above the other, lining up corresponding variables. If one of the variables in the top equation has the opposite coefficient of the same variable in the bottom equation, add the equations together, eliminating one variable. If not, use multiplication by a nonzero number so that one of the variables in the top equation has the opposite coefficient of the same variable in the bottom equation, then add the equations to eliminate the variable.
- Solve the resulting equation for the remaining variable.
- Substitute that value into one of the original equations and solve for the second variable.
- Check the solution by substituting the values into the other equation.

### Example: Solving a System by the Addition Method

Solve the given system of equations by addition.

[latex]\begin{align}x+2y&=-1 \\ -x+y&=3 \end{align}[/latex]

In the following video, you will see another example of how to use the method of elimination to solve a system of linear equations.

### Example: Using the Addition Method When Multiplication of One Equation Is Required

Solve the given system of equations by the **addition method**.

[latex]\begin{align}3x+5y&=-11 \\ x - 2y&=11 \end{align}[/latex]

Below is another video example of using the elimination method to solve a system of linear equations when multiplication of one equation is required.

### tip for success

Remember to work through the given examples and practice problems on paper and more than once to deepen your understanding.

### Try It

Solve the system of equations by addition.

[latex]\begin{align}2x - 7y&=2\\ 3x+y&=-20\end{align}[/latex]

https://ohm.lumenlearning.com/multiembedq.php?id=115120&theme=oea&iframe_resize_id=mom15

### Example: Using the Addition Method When Multiplication of Both Equations Is Required

Solve the given system of equations in two variables by addition.

[latex]\begin{align}2x+3y&=-16 \\ 5x - 10y&=30\end{align}[/latex]

### Example: Using the Addition Method in Systems of Equations Containing Fractions

Solve the given system of equations in two variables by addition.

[latex]\begin{align}\frac{x}{3}+\frac{y}{6}&=3 \\[1mm] \frac{x}{2}-\frac{y}{4}&=1 \end{align}[/latex]

In the following video, you will find one more example of using the elimination method to solve a system; this one has coefficients that are fractions.

### Try It

Solve the system of equations by addition.

[latex]\begin{align}2x+3y&=8\\ 3x+5y&=10\end{align}[/latex]

https://ohm.lumenlearning.com/multiembedq.php?id=115110&theme=oea&iframe_resize_id=mom10

in the following video we present more examples of how to use the addition (elimination) method to solve a system of two linear equations.