{"id":3990,"date":"2017-03-27T18:15:00","date_gmt":"2017-03-27T18:15:00","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/wm-biology2\/?post_type=chapter&#038;p=3990"},"modified":"2024-04-26T01:09:41","modified_gmt":"2024-04-26T01:09:41","slug":"action-potential","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/wm-biology2\/chapter\/action-potential\/","title":{"raw":"Action Potential","rendered":"Action Potential"},"content":{"raw":"<div class=\"textbox learning-objectives\">\r\n<h3>Learning Outcomes<\/h3>\r\n<ul>\r\n \t<li>Explain the stages of an action potential and how action potentials are propagated<\/li>\r\n<\/ul>\r\n<\/div>\r\nA neuron can receive input from other neurons and, if this input is strong enough, send the signal to downstream neurons. Transmission of a signal between neurons is generally carried by a chemical called a neurotransmitter. Transmission of a signal within a neuron (from dendrite to axon terminal) is carried by a brief reversal of the resting membrane potential called an <b>action potential<\/b>. When neurotransmitter molecules bind to receptors located on a neuron\u2019s dendrites, ion channels open. At excitatory synapses, this opening allows positive ions to enter the neuron and results in <b>depolarization<\/b> of the membrane\u2014a decrease in the difference in voltage between the inside and outside of the neuron. A stimulus from a sensory cell or another neuron depolarizes the target neuron to its threshold potential (\u221255 mV). Na<sup>+<\/sup> channels in the axon hillock open, allowing positive ions to enter the cell (Figure 1).\r\n\r\nOnce the sodium channels open, the neuron completely depolarizes to a membrane potential of about +40 mV. Action potentials are considered an \"all-or nothing\" event, in that, once the threshold potential is reached, the neuron always completely depolarizes. Once depolarization is complete, the cell must now \"reset\" its membrane voltage back to the resting potential. To accomplish this, the Na<sup>+<\/sup>channels close and cannot be opened. This begins the neuron's <b>refractory period<\/b>, in which it cannot produce another action potential because its sodium channels will not open. At the same time, voltage-gated K<sup>+<\/sup> channels open, allowing K<sup>+<\/sup> to leave the cell. As K<sup>+<\/sup> ions leave the cell, the membrane potential once again becomes negative. The diffusion of K<sup>+<\/sup> out of the cell actually <b>hyperpolarizes<\/b> the cell, in that the membrane potential becomes more negative than the cell's normal resting potential. At this point, the sodium channels will return to their resting state, meaning they are ready to open again if the membrane potential again exceeds the threshold potential. Eventually the extra K<sup>+<\/sup> ions diffuse out of the cell through the potassium leakage channels, bringing the cell from its hyperpolarized state, back to its resting membrane potential.\r\n<div class=\"textbox exercises\">\r\n<h3>Practice Question<\/h3>\r\nThe formation of an action potential can be divided into five steps, which can be seen in Figure 1.\r\n\r\n[caption id=\"attachment_2663\" align=\"aligncenter\" width=\"469\"]<img class=\"size-full wp-image-2663\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1223\/2017\/02\/07200525\/Figure_35_02_03.png\" alt=\"Graph plots membrane potential in millivolts versus time. The membrane remains at the resting potential of -70 millivolts until a nerve impulse occurs in step 1. Some sodium channels open, and the potential begins to rapidly climb past the threshold of excitation of -55 millivolts, at which point all the sodium channels open. At the peak action potential, the potential begins to rapidly drop as potassium channels open and sodium channels close. As a result, the membrane repolarizes past the resting membrane potential and becomes hyperpolarized. The membrane potential then gradually returns to normal.\" width=\"469\" height=\"351\" \/> Figure 1. Action Potential[\/caption]\r\n<ol>\r\n \t<li>A stimulus from a sensory cell or another neuron causes the target cell to depolarize toward the threshold potential.<\/li>\r\n \t<li>If the threshold of excitation is reached, all Na<sup>+<\/sup> channels open and the membrane depolarizes.<\/li>\r\n \t<li>At the peak action potential, K<sup>+<\/sup> channels open and K<sup>+<\/sup> begins to leave the cell. At the same time, Na<sup>+<\/sup> channels close.<\/li>\r\n \t<li>The membrane becomes hyperpolarized as K<sup>+<\/sup> ions continue to leave the cell. The hyperpolarized membrane is in a refractory period and cannot fire.<\/li>\r\n \t<li>The K<sup>+<\/sup> channels close and the Na<sup>+<\/sup>\/K<sup>+<\/sup> transporter restores the resting potential.<\/li>\r\n<\/ol>\r\nPotassium channel blockers, such as amiodarone and procainamide, which are used to treat abnormal electrical activity in the heart, called cardiac dysrhythmia, impede the movement of K<sup>+<\/sup> through voltage-gated K<sup>+<\/sup> channels. Which part of the action potential would you expect potassium channels to affect?\r\n[reveal-answer q=\"217786\"]Show Answer[\/reveal-answer]\r\n[hidden-answer a=\"217786\"]Potassium channel blockers slow the repolarization phase, but have no effect on depolarization.[\/hidden-answer]\r\n\r\n<\/div>\r\n\r\n[caption id=\"attachment_2664\" align=\"aligncenter\" width=\"1024\"]<img class=\"size-large wp-image-2664\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1223\/2017\/02\/07200629\/Figure_35_02_04-1024x714.png\" alt=\"The action potential travels from the soma down the axon to the axon terminal. The action potential is initiated when a signal from the soma causes the soma-end of the axon membrane to depolarize. The depolarization spreads down the axon. Meanwhile, the membrane at the start of the axon repolarizes. Because potassium channels are open, the membrane cannot depolarize again. The action potential continues to spread down the axon this way.\" width=\"1024\" height=\"714\" \/> Figure 2.\u00a0The action potential is conducted down the axon as the axon membrane depolarizes, then repolarizes.[\/caption]\r\n\r\n<div class=\"textbox\"><a href=\"https:\/\/www.youtube.com\/watch?v=POSPO8QbZI4\" target=\"_blank\" rel=\"noopener\">This video presents an overview of action potential<\/a>.<\/div>\r\n<h2>Myelin and the Propagation of the Action Potential<\/h2>\r\nFor an action potential to communicate information to another neuron, it must travel along the axon and reach the axon terminals where it can initiate neurotransmitter release. The speed of conduction of an action potential along an axon is influenced by both the diameter of the axon and the axon\u2019s resistance to current leak. Myelin acts as an insulator that prevents current from leaving the axon; this increases the speed of action potential conduction. In demyelinating diseases like multiple sclerosis, action potential conduction slows because current leaks from previously insulated axon areas.\r\n\r\n[caption id=\"attachment_2665\" align=\"alignright\" width=\"400\"]<img class=\"wp-image-2665\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1223\/2017\/02\/07200709\/Figure_35_02_05.jpg\" alt=\"Illustration shows an axon covered in three bands of myelin sheath. Between the sheath coverings the axon is exposed. The uncovered parts of the axon are called nodes of Ranvier. In the illustration, the left node of Ranvier is depolarized such that the membrane potential is positive inside and negative outside. The right membrane of the right node is at the resting potential, negative inside and positive outside. An arrow indicates that the depolarization jumps from the left node to the right, so that the right node becomes depolarized.\" width=\"400\" height=\"143\" \/> Figure 3.\u00a0Nodes of Ranvier are gaps in myelin coverage along axons. Nodes contain voltage-gated K<sup>+<\/sup> and Na<sup>+<\/sup> channels. Action potentials travel down the axon by jumping from one node to the next.[\/caption]\r\n\r\nThe nodes of Ranvier, illustrated in Figure 3\u00a0are gaps in the myelin sheath along the axon. These unmyelinated spaces are about one micrometer long and contain voltage gated Na<sup>+<\/sup> and K<sup>+<\/sup> channels. Flow of ions through these channels, particularly the Na<sup>+<\/sup> channels, regenerates the action potential over and over again along the axon. This \u2018jumping\u2019 of the action potential from one node to the next is called <b>saltatory conduction<\/b>. If nodes of Ranvier were not present along an axon, the action potential would propagate very slowly since Na<sup>+<\/sup> and K<sup>+<\/sup> channels would have to continuously regenerate action potentials at every point along the axon instead of at specific points. Nodes of Ranvier also save energy for the neuron since the channels only need to be present at the nodes and not along the entire axon.\r\n\r\n<iframe src=\"https:\/\/lumenlearning.h5p.com\/content\/1291231318201700648\/embed\" width=\"1088\" height=\"637\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\" allow=\"geolocation *; microphone *; camera *; midi *; encrypted-media *\"><\/iframe><script src=\"https:\/\/lumenlearning.h5p.com\/js\/h5p-resizer.js\" charset=\"UTF-8\"><\/script>&nbsp;\r\n<div class=\"textbox tryit\">\r\n<h3>Try It<\/h3>\r\nhttps:\/\/assess.lumenlearning.com\/practice\/0b3f76fe-2f36-48f1-a416-b4397f8cc4ae\r\n<\/div>","rendered":"<div class=\"textbox learning-objectives\">\n<h3>Learning Outcomes<\/h3>\n<ul>\n<li>Explain the stages of an action potential and how action potentials are propagated<\/li>\n<\/ul>\n<\/div>\n<p>A neuron can receive input from other neurons and, if this input is strong enough, send the signal to downstream neurons. Transmission of a signal between neurons is generally carried by a chemical called a neurotransmitter. Transmission of a signal within a neuron (from dendrite to axon terminal) is carried by a brief reversal of the resting membrane potential called an <b>action potential<\/b>. When neurotransmitter molecules bind to receptors located on a neuron\u2019s dendrites, ion channels open. At excitatory synapses, this opening allows positive ions to enter the neuron and results in <b>depolarization<\/b> of the membrane\u2014a decrease in the difference in voltage between the inside and outside of the neuron. A stimulus from a sensory cell or another neuron depolarizes the target neuron to its threshold potential (\u221255 mV). Na<sup>+<\/sup> channels in the axon hillock open, allowing positive ions to enter the cell (Figure 1).<\/p>\n<p>Once the sodium channels open, the neuron completely depolarizes to a membrane potential of about +40 mV. Action potentials are considered an &#8220;all-or nothing&#8221; event, in that, once the threshold potential is reached, the neuron always completely depolarizes. Once depolarization is complete, the cell must now &#8220;reset&#8221; its membrane voltage back to the resting potential. To accomplish this, the Na<sup>+<\/sup>channels close and cannot be opened. This begins the neuron&#8217;s <b>refractory period<\/b>, in which it cannot produce another action potential because its sodium channels will not open. At the same time, voltage-gated K<sup>+<\/sup> channels open, allowing K<sup>+<\/sup> to leave the cell. As K<sup>+<\/sup> ions leave the cell, the membrane potential once again becomes negative. The diffusion of K<sup>+<\/sup> out of the cell actually <b>hyperpolarizes<\/b> the cell, in that the membrane potential becomes more negative than the cell&#8217;s normal resting potential. At this point, the sodium channels will return to their resting state, meaning they are ready to open again if the membrane potential again exceeds the threshold potential. Eventually the extra K<sup>+<\/sup> ions diffuse out of the cell through the potassium leakage channels, bringing the cell from its hyperpolarized state, back to its resting membrane potential.<\/p>\n<div class=\"textbox exercises\">\n<h3>Practice Question<\/h3>\n<p>The formation of an action potential can be divided into five steps, which can be seen in Figure 1.<\/p>\n<div id=\"attachment_2663\" style=\"width: 479px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-2663\" class=\"size-full wp-image-2663\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1223\/2017\/02\/07200525\/Figure_35_02_03.png\" alt=\"Graph plots membrane potential in millivolts versus time. The membrane remains at the resting potential of -70 millivolts until a nerve impulse occurs in step 1. Some sodium channels open, and the potential begins to rapidly climb past the threshold of excitation of -55 millivolts, at which point all the sodium channels open. At the peak action potential, the potential begins to rapidly drop as potassium channels open and sodium channels close. As a result, the membrane repolarizes past the resting membrane potential and becomes hyperpolarized. The membrane potential then gradually returns to normal.\" width=\"469\" height=\"351\" \/><\/p>\n<p id=\"caption-attachment-2663\" class=\"wp-caption-text\">Figure 1. Action Potential<\/p>\n<\/div>\n<ol>\n<li>A stimulus from a sensory cell or another neuron causes the target cell to depolarize toward the threshold potential.<\/li>\n<li>If the threshold of excitation is reached, all Na<sup>+<\/sup> channels open and the membrane depolarizes.<\/li>\n<li>At the peak action potential, K<sup>+<\/sup> channels open and K<sup>+<\/sup> begins to leave the cell. At the same time, Na<sup>+<\/sup> channels close.<\/li>\n<li>The membrane becomes hyperpolarized as K<sup>+<\/sup> ions continue to leave the cell. The hyperpolarized membrane is in a refractory period and cannot fire.<\/li>\n<li>The K<sup>+<\/sup> channels close and the Na<sup>+<\/sup>\/K<sup>+<\/sup> transporter restores the resting potential.<\/li>\n<\/ol>\n<p>Potassium channel blockers, such as amiodarone and procainamide, which are used to treat abnormal electrical activity in the heart, called cardiac dysrhythmia, impede the movement of K<sup>+<\/sup> through voltage-gated K<sup>+<\/sup> channels. Which part of the action potential would you expect potassium channels to affect?<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q217786\">Show Answer<\/span><\/p>\n<div id=\"q217786\" class=\"hidden-answer\" style=\"display: none\">Potassium channel blockers slow the repolarization phase, but have no effect on depolarization.<\/div>\n<\/div>\n<\/div>\n<div id=\"attachment_2664\" style=\"width: 1034px\" class=\"wp-caption aligncenter\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-2664\" class=\"size-large wp-image-2664\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1223\/2017\/02\/07200629\/Figure_35_02_04-1024x714.png\" alt=\"The action potential travels from the soma down the axon to the axon terminal. The action potential is initiated when a signal from the soma causes the soma-end of the axon membrane to depolarize. The depolarization spreads down the axon. Meanwhile, the membrane at the start of the axon repolarizes. Because potassium channels are open, the membrane cannot depolarize again. The action potential continues to spread down the axon this way.\" width=\"1024\" height=\"714\" \/><\/p>\n<p id=\"caption-attachment-2664\" class=\"wp-caption-text\">Figure 2.\u00a0The action potential is conducted down the axon as the axon membrane depolarizes, then repolarizes.<\/p>\n<\/div>\n<div class=\"textbox\"><a href=\"https:\/\/www.youtube.com\/watch?v=POSPO8QbZI4\" target=\"_blank\" rel=\"noopener\">This video presents an overview of action potential<\/a>.<\/div>\n<h2>Myelin and the Propagation of the Action Potential<\/h2>\n<p>For an action potential to communicate information to another neuron, it must travel along the axon and reach the axon terminals where it can initiate neurotransmitter release. The speed of conduction of an action potential along an axon is influenced by both the diameter of the axon and the axon\u2019s resistance to current leak. Myelin acts as an insulator that prevents current from leaving the axon; this increases the speed of action potential conduction. In demyelinating diseases like multiple sclerosis, action potential conduction slows because current leaks from previously insulated axon areas.<\/p>\n<div id=\"attachment_2665\" style=\"width: 410px\" class=\"wp-caption alignright\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-2665\" class=\"wp-image-2665\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/1223\/2017\/02\/07200709\/Figure_35_02_05.jpg\" alt=\"Illustration shows an axon covered in three bands of myelin sheath. Between the sheath coverings the axon is exposed. The uncovered parts of the axon are called nodes of Ranvier. In the illustration, the left node of Ranvier is depolarized such that the membrane potential is positive inside and negative outside. The right membrane of the right node is at the resting potential, negative inside and positive outside. An arrow indicates that the depolarization jumps from the left node to the right, so that the right node becomes depolarized.\" width=\"400\" height=\"143\" \/><\/p>\n<p id=\"caption-attachment-2665\" class=\"wp-caption-text\">Figure 3.\u00a0Nodes of Ranvier are gaps in myelin coverage along axons. Nodes contain voltage-gated K<sup>+<\/sup> and Na<sup>+<\/sup> channels. Action potentials travel down the axon by jumping from one node to the next.<\/p>\n<\/div>\n<p>The nodes of Ranvier, illustrated in Figure 3\u00a0are gaps in the myelin sheath along the axon. These unmyelinated spaces are about one micrometer long and contain voltage gated Na<sup>+<\/sup> and K<sup>+<\/sup> channels. Flow of ions through these channels, particularly the Na<sup>+<\/sup> channels, regenerates the action potential over and over again along the axon. This \u2018jumping\u2019 of the action potential from one node to the next is called <b>saltatory conduction<\/b>. If nodes of Ranvier were not present along an axon, the action potential would propagate very slowly since Na<sup>+<\/sup> and K<sup>+<\/sup> channels would have to continuously regenerate action potentials at every point along the axon instead of at specific points. Nodes of Ranvier also save energy for the neuron since the channels only need to be present at the nodes and not along the entire axon.<\/p>\n<p><iframe loading=\"lazy\" src=\"https:\/\/lumenlearning.h5p.com\/content\/1291231318201700648\/embed\" width=\"1088\" height=\"637\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><script src=\"https:\/\/lumenlearning.h5p.com\/js\/h5p-resizer.js\" charset=\"UTF-8\"><\/script>&nbsp;<\/p>\n<div class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<p>\t<iframe id=\"assessment_practice_0b3f76fe-2f36-48f1-a416-b4397f8cc4ae\" class=\"resizable\" src=\"https:\/\/assess.lumenlearning.com\/practice\/0b3f76fe-2f36-48f1-a416-b4397f8cc4ae?iframe_resize_id=assessment_practice_id_0b3f76fe-2f36-48f1-a416-b4397f8cc4ae\" frameborder=\"0\" style=\"border:none;width:100%;height:100%;min-height:300px;\"><br \/>\n\t<\/iframe>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-3990\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Biology 2e. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/185cbf87-c72e-48f5-b51e-f14f21b5eabd@10.8\">http:\/\/cnx.org\/contents\/185cbf87-c72e-48f5-b51e-f14f21b5eabd@10.8<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Access for free at https:\/\/openstax.org\/books\/biology-2e\/pages\/1-introduction<\/li><\/ul><div class=\"license-attribution-dropdown-subheading\">All rights reserved content<\/div><ul class=\"citation-list\"><li>What is action potential. <strong>Provided by<\/strong>: Interactive Biology. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/www.youtube.com\/watch?v=POSPO8QbZI4\">https:\/\/www.youtube.com\/watch?v=POSPO8QbZI4<\/a>. <strong>License<\/strong>: <em>All Rights Reserved<\/em><\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":17,"menu_order":10,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"Biology 2e\",\"author\":\"\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/185cbf87-c72e-48f5-b51e-f14f21b5eabd@10.8\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Access for free at https:\/\/openstax.org\/books\/biology-2e\/pages\/1-introduction\"},{\"type\":\"copyrighted_video\",\"description\":\"What is action potential\",\"author\":\"\",\"organization\":\"Interactive Biology\",\"url\":\"https:\/\/www.youtube.com\/watch?v=POSPO8QbZI4\",\"project\":\"\",\"license\":\"arr\",\"license_terms\":\"\"}]","CANDELA_OUTCOMES_GUID":"7a128bdf-a3f9-4720-b7a0-6e6039800e1c, 41a9cd82-1135-4904-b013-b1637e5cfe39","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-3990","chapter","type-chapter","status-publish","hentry"],"part":3966,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/wm-biology2\/wp-json\/pressbooks\/v2\/chapters\/3990","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/wm-biology2\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/wm-biology2\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/wm-biology2\/wp-json\/wp\/v2\/users\/17"}],"version-history":[{"count":11,"href":"https:\/\/courses.lumenlearning.com\/wm-biology2\/wp-json\/pressbooks\/v2\/chapters\/3990\/revisions"}],"predecessor-version":[{"id":8509,"href":"https:\/\/courses.lumenlearning.com\/wm-biology2\/wp-json\/pressbooks\/v2\/chapters\/3990\/revisions\/8509"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/wm-biology2\/wp-json\/pressbooks\/v2\/parts\/3966"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/wm-biology2\/wp-json\/pressbooks\/v2\/chapters\/3990\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/wm-biology2\/wp-json\/wp\/v2\/media?parent=3990"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/wm-biology2\/wp-json\/pressbooks\/v2\/chapter-type?post=3990"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/wm-biology2\/wp-json\/wp\/v2\/contributor?post=3990"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/wm-biology2\/wp-json\/wp\/v2\/license?post=3990"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}