{"id":16630,"date":"2019-10-03T20:16:55","date_gmt":"2019-10-03T20:16:55","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/chapter\/restricting-the-domain\/"},"modified":"2024-05-02T15:55:01","modified_gmt":"2024-05-02T15:55:01","slug":"restricting-the-domain","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/chapter\/restricting-the-domain\/","title":{"raw":"Domain Restrictions","rendered":"Domain Restrictions"},"content":{"raw":"<div class=\"textbox learning-objectives\">\r\n<h3>Learning Outcomes<\/h3>\r\n<ul>\r\n \t<li>Find the domain of a function algebraically<\/li>\r\n<\/ul>\r\n<\/div>\r\nFunctions are a correspondence between two sets, called the <strong>domain<\/strong> and the <strong>range<\/strong>. When defining a function, you usually state what kind of numbers the domain (<i>x<\/i>) and range (<i>f(x)<\/i>) values can be. But even if you say they are real numbers, that does not mean that <i>all<\/i> real numbers can be used for <i>x<\/i>. It also does not mean that all real numbers can be function values, <i>f<\/i>(<i>x<\/i>). There may be restrictions on the domain and range. The restrictions partly depend on the <i>type<\/i> of function.\r\n\r\nIn this topic, all functions will be restricted to real number values. That is, only real numbers can be used in the domain, and only real numbers can be in the range.\r\n\r\nThere are two main reasons why domains are restricted.\r\n<ul>\r\n \t<li>You cannot divide by\u00a0[latex]0[\/latex].<\/li>\r\n \t<li>You cannot take the square (or other even) root of a negative number, as the result will not be a real number.<\/li>\r\n<\/ul>\r\nThese two issues would be of concern when the function is either of the following:\r\n<div>\r\n<ul>\r\n \t<li>A rational function where the denominator could potentially become [latex]0[\/latex] for some value or values of <i>x.\u00a0<\/i>\u00a0An example of this is [latex]f\\left(x\\right)=\\dfrac{x+1}{2-x}[\/latex] is a rational function.<\/li>\r\n \t<li>A radical function with an even index (such as a square root), where the radicand (quantity under the radical) could potentially be negative for some value or values of <i>x<\/i>.\u00a0[latex]f\\left(x\\right)=\\sqrt{7-x}[\/latex] is a radical function.<\/li>\r\n<\/ul>\r\nThe following table gives examples of domain restrictions for several different rational functions. Note that a rational function has the variable present in the denominator.\r\n<table cellspacing=\"0\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Function<\/th>\r\n<th>Restrictions to the Domain<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>[latex] f(x)=\\dfrac{1}{x}[\/latex]<\/td>\r\n<td>If [latex]x=0[\/latex], you would be dividing by\u00a0[latex]0[\/latex], so [latex]x\\neq0[\/latex].<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>[latex] f(x)=\\dfrac{2+x}{x-3}[\/latex]<\/td>\r\n<td>If [latex]x=3[\/latex], you would be dividing by\u00a0[latex]0[\/latex], so [latex]x\\neq3[\/latex].<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>[latex] f(x)=\\dfrac{2(x-1)}{x-1}[\/latex]<\/td>\r\n<td>Although you can simplify this function to [latex]f(x)=2[\/latex], when [latex]x=1[\/latex], the original function would include division by\u00a0[latex]0[\/latex], so [latex]x\\neq1[\/latex].<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>[latex] f(x)=\\dfrac{x+1}{{{x}^{2}}-1}[\/latex]<\/td>\r\n<td>Both [latex]x=1[\/latex] and [latex]x=\u22121[\/latex] would make the denominator 0. Again, this function can be simplified to [latex] f(x)=\\dfrac{1}{x-1}[\/latex], but when [latex]x=1[\/latex] or [latex]x=\u22121[\/latex], the <i>original<\/i> function would include division by 0, so [latex]x\\neq1[\/latex] and [latex]x\\neq\u22121[\/latex].<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>[latex] f(x)=\\dfrac{2(x-1)}{{{x}^{2}}+1}[\/latex]<\/td>\r\n<td>This is an example with <i>no <\/i>domain<i> <\/i>restrictions, even though there is a variable in the denominator. Since\u00a0[latex]x^{2}\\geq0,x^{2}+1[\/latex] can never be\u00a0[latex]0[\/latex]. The least it can be is\u00a0[latex]1[\/latex], so there is no danger of division by\u00a0[latex]0[\/latex].<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<i>Square roots of negative numbers<\/i> could happen whenever the function has a variable under a radical with an even root. Look at the following examples and note that \u201csquare root of a negative variable\u201d doesn\u2019t necessarily mean that the value under the radical sign is negative. For example, if [latex]x=\u22124[\/latex], then [latex]\u2212x=\u2212(\u22124)=4[\/latex], a positive number.\r\n<table cellspacing=\"0\" cellpadding=\"0\">\r\n<thead>\r\n<tr>\r\n<th>Function<\/th>\r\n<th>Restrictions to the Domain<\/th>\r\n<\/tr>\r\n<\/thead>\r\n<tbody>\r\n<tr>\r\n<td>[latex] f(x)=\\sqrt{x}[\/latex]<\/td>\r\n<td>If [latex]x&lt;0[\/latex], you would be taking the square root of a negative number, so [latex]x\\geq0[\/latex].<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>[latex] f(x)=\\sqrt{x+10}[\/latex]<\/td>\r\n<td>If [latex]x&lt;\u221210[\/latex], you would be taking the square root of a negative number, so [latex]x\\geq\u221210[\/latex].<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>[latex] f(x)=\\sqrt{-x}[\/latex]<\/td>\r\n<td>When is [latex]-x[\/latex] negative? Only when x is positive. (For example, if [latex]x=1[\/latex], then [latex]\u2212x=-1[\/latex]. But if [latex]x=-3[\/latex], then [latex]\u2212x=3[\/latex]. This means [latex]x\\leq0[\/latex].<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>[latex] f(x)=\\sqrt{{{x}^{2}}-1}[\/latex]<\/td>\r\n<td>[latex]x^{2}\u20131[\/latex] must be positive, [latex]x^{2}\u20131&gt;0[\/latex]. So [latex]x^{2}&gt;1[\/latex]. This happens only when x is greater than 1 or less than [latex]\u22121[\/latex]:\u00a0[latex]x\\leq\u22121[\/latex] or [latex]x\\geq1[\/latex].<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>[latex] f(x)=\\sqrt{{{x}^{2}}+10}[\/latex]<\/td>\r\n<td>There are no domain restrictions even though there is a variable under the radical. Since [latex]x^{2}\\ge0[\/latex], [latex]x^{2}+10[\/latex]\u00a0can never be negative. The least it can be is [latex]\\sqrt{10}[\/latex], so there is no danger of taking the square root of a negative number.<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n<\/div>\r\nSo, how exactly do you define the domain of a function?\r\n<div class=\"textbox\">\r\n<h3>How To: Given a function written in equation form, find the domain<\/h3>\r\n<ol>\r\n \t<li>Identify the input values.<\/li>\r\n \t<li>Identify any restrictions on the input and exclude those values from the domain.\r\n<ul>\r\n \t<li>If there is a denominator in the function\u2019s formula, exclude any real numbers that cause the denominator to be equal to zero.\u00a0 To do this, set the denominator equal to zero and solve for [latex]x[\/latex] .<\/li>\r\n \t<li>If the function\u2019s formula contains an even root,\u00a0exclude any real numbers that result in a negative number in the radicand.\u00a0 To do this, set the radicand greater than or equal to\u00a0[latex]0[\/latex] and then solve.<\/li>\r\n<\/ul>\r\n<\/li>\r\n \t<li>Write the domain in interval form, making sure to exclude any restricted values from the domain.<\/li>\r\n<\/ol>\r\n<\/div>\r\n<div class=\"textbox exercises\">\r\n<h3>Example<\/h3>\r\nFind the domain of the function [latex]f\\left(x\\right)={x}^{2}-1[\/latex].\r\n\r\n[reveal-answer q=\"480036\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"480036\"]\r\n\r\nThe input value, shown by the variable [latex]x[\/latex] in the equation, is squared and then the result is lowered by one. Any real number may be squared and then be lowered by one, so there are no restrictions on the domain of this function. The domain is the set of real numbers.\r\n\r\nIn interval form, the domain of [latex]f[\/latex] is [latex]\\left(-\\infty ,\\infty \\right)[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\nIn our next example, we have a variable in the denominator, so we have to identify when the denominator will be equal to zero.\r\n<div class=\"textbox exercises\">\r\n<h3>Example<\/h3>\r\nFind the domain of the function [latex]f\\left(x\\right)=\\dfrac{x+1}{2-x}[\/latex].\r\n\r\n[reveal-answer q=\"995188\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"995188\"]\r\n\r\nWhen there is a denominator, we want to include only values of the input that do not cause the denominator to be zero. So, we will set the denominator equal to 0 and solve for [latex]x[\/latex].\r\n<p style=\"text-align: center;\">[latex]2-x=0[\/latex]<\/p>\r\n<p style=\"text-align: center;\">[latex]-x=-2[\/latex]<\/p>\r\n<p style=\"text-align: center;\">[latex]x=2[\/latex]<\/p>\r\nNow, we will exclude\u00a0[latex]2[\/latex] from the domain. The answers are all real numbers where [latex]x&lt;2[\/latex] or [latex]x&gt;2[\/latex]. We can use a symbol known as the union, [latex]\\cup [\/latex], to combine the two sets. In interval notation, we write the solution: [latex]\\left(\\mathrm{-\\infty },2\\right)\\cup \\left(2,\\infty \\right)[\/latex].\r\n\r\n<img class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25200611\/CNX_Precalc_Figure_01_02_028n2.jpg\" alt=\"x is less than 2 or x is greater than 2 graphed on a number line. An open dot is plotted on 2 and arrows extend in both directions on the number line. The inequality can be written in interval notation as parentheses negative infinity comma 2 end parentheses union parentheses 2 comma infinity end parentheses.\" width=\"487\" height=\"164\" \/>\r\n\r\nIn interval form, the domain of [latex]f[\/latex] is [latex]\\left(-\\infty ,2\\right)\\cup \\left(2,\\infty \\right)[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\nhttps:\/\/www.youtube.com\/watch?v=v0IhvIzCc_I&amp;feature=youtu.be\r\n\r\nIn our next example, we will need to determine when the radicand is less than 0.\r\n<div class=\"textbox exercises\">\r\n<h3>Example<\/h3>\r\nFind the domain of the function [latex]f\\left(x\\right)=\\sqrt{7-x}[\/latex].\r\n\r\n[reveal-answer q=\"275485\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"275485\"]\r\n\r\nWhen there is an even root in the formula, we exclude any real numbers that result in a negative number in the radicand.\r\n\r\nSet the radicand greater than or equal to zero and solve for [latex]x[\/latex].\r\n<p style=\"text-align: center;\">[latex]7-x\\ge 0[\/latex]<\/p>\r\n<p style=\"text-align: center;\">[latex]-x\\ge -7[\/latex]<\/p>\r\n<p style=\"text-align: center;\">[latex]x\\le 7[\/latex]<\/p>\r\nNow, we will exclude any number greater than 7 from the domain. The answers are all real numbers less than or equal to [latex]7[\/latex], or [latex]\\left(-\\infty ,7\\right][\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\nhttps:\/\/www.youtube.com\/watch?v=lj_JB8sfyIM&amp;feature=youtu.be\r\n","rendered":"<div class=\"textbox learning-objectives\">\n<h3>Learning Outcomes<\/h3>\n<ul>\n<li>Find the domain of a function algebraically<\/li>\n<\/ul>\n<\/div>\n<p>Functions are a correspondence between two sets, called the <strong>domain<\/strong> and the <strong>range<\/strong>. When defining a function, you usually state what kind of numbers the domain (<i>x<\/i>) and range (<i>f(x)<\/i>) values can be. But even if you say they are real numbers, that does not mean that <i>all<\/i> real numbers can be used for <i>x<\/i>. It also does not mean that all real numbers can be function values, <i>f<\/i>(<i>x<\/i>). There may be restrictions on the domain and range. The restrictions partly depend on the <i>type<\/i> of function.<\/p>\n<p>In this topic, all functions will be restricted to real number values. That is, only real numbers can be used in the domain, and only real numbers can be in the range.<\/p>\n<p>There are two main reasons why domains are restricted.<\/p>\n<ul>\n<li>You cannot divide by\u00a0[latex]0[\/latex].<\/li>\n<li>You cannot take the square (or other even) root of a negative number, as the result will not be a real number.<\/li>\n<\/ul>\n<p>These two issues would be of concern when the function is either of the following:<\/p>\n<div>\n<ul>\n<li>A rational function where the denominator could potentially become [latex]0[\/latex] for some value or values of <i>x.\u00a0<\/i>\u00a0An example of this is [latex]f\\left(x\\right)=\\dfrac{x+1}{2-x}[\/latex] is a rational function.<\/li>\n<li>A radical function with an even index (such as a square root), where the radicand (quantity under the radical) could potentially be negative for some value or values of <i>x<\/i>.\u00a0[latex]f\\left(x\\right)=\\sqrt{7-x}[\/latex] is a radical function.<\/li>\n<\/ul>\n<p>The following table gives examples of domain restrictions for several different rational functions. Note that a rational function has the variable present in the denominator.<\/p>\n<table cellpadding=\"0\" style=\"border-spacing: 0px;\">\n<thead>\n<tr>\n<th>Function<\/th>\n<th>Restrictions to the Domain<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>[latex]f(x)=\\dfrac{1}{x}[\/latex]<\/td>\n<td>If [latex]x=0[\/latex], you would be dividing by\u00a0[latex]0[\/latex], so [latex]x\\neq0[\/latex].<\/td>\n<\/tr>\n<tr>\n<td>[latex]f(x)=\\dfrac{2+x}{x-3}[\/latex]<\/td>\n<td>If [latex]x=3[\/latex], you would be dividing by\u00a0[latex]0[\/latex], so [latex]x\\neq3[\/latex].<\/td>\n<\/tr>\n<tr>\n<td>[latex]f(x)=\\dfrac{2(x-1)}{x-1}[\/latex]<\/td>\n<td>Although you can simplify this function to [latex]f(x)=2[\/latex], when [latex]x=1[\/latex], the original function would include division by\u00a0[latex]0[\/latex], so [latex]x\\neq1[\/latex].<\/td>\n<\/tr>\n<tr>\n<td>[latex]f(x)=\\dfrac{x+1}{{{x}^{2}}-1}[\/latex]<\/td>\n<td>Both [latex]x=1[\/latex] and [latex]x=\u22121[\/latex] would make the denominator 0. Again, this function can be simplified to [latex]f(x)=\\dfrac{1}{x-1}[\/latex], but when [latex]x=1[\/latex] or [latex]x=\u22121[\/latex], the <i>original<\/i> function would include division by 0, so [latex]x\\neq1[\/latex] and [latex]x\\neq\u22121[\/latex].<\/td>\n<\/tr>\n<tr>\n<td>[latex]f(x)=\\dfrac{2(x-1)}{{{x}^{2}}+1}[\/latex]<\/td>\n<td>This is an example with <i>no <\/i>domain<i> <\/i>restrictions, even though there is a variable in the denominator. Since\u00a0[latex]x^{2}\\geq0,x^{2}+1[\/latex] can never be\u00a0[latex]0[\/latex]. The least it can be is\u00a0[latex]1[\/latex], so there is no danger of division by\u00a0[latex]0[\/latex].<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><i>Square roots of negative numbers<\/i> could happen whenever the function has a variable under a radical with an even root. Look at the following examples and note that \u201csquare root of a negative variable\u201d doesn\u2019t necessarily mean that the value under the radical sign is negative. For example, if [latex]x=\u22124[\/latex], then [latex]\u2212x=\u2212(\u22124)=4[\/latex], a positive number.<\/p>\n<table cellpadding=\"0\" style=\"border-spacing: 0px;\">\n<thead>\n<tr>\n<th>Function<\/th>\n<th>Restrictions to the Domain<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>[latex]f(x)=\\sqrt{x}[\/latex]<\/td>\n<td>If [latex]x<0[\/latex], you would be taking the square root of a negative number, so [latex]x\\geq0[\/latex].<\/td>\n<\/tr>\n<tr>\n<td>[latex]f(x)=\\sqrt{x+10}[\/latex]<\/td>\n<td>If [latex]x<\u221210[\/latex], you would be taking the square root of a negative number, so [latex]x\\geq\u221210[\/latex].<\/td>\n<\/tr>\n<tr>\n<td>[latex]f(x)=\\sqrt{-x}[\/latex]<\/td>\n<td>When is [latex]-x[\/latex] negative? Only when x is positive. (For example, if [latex]x=1[\/latex], then [latex]\u2212x=-1[\/latex]. But if [latex]x=-3[\/latex], then [latex]\u2212x=3[\/latex]. This means [latex]x\\leq0[\/latex].<\/td>\n<\/tr>\n<tr>\n<td>[latex]f(x)=\\sqrt{{{x}^{2}}-1}[\/latex]<\/td>\n<td>[latex]x^{2}\u20131[\/latex] must be positive, [latex]x^{2}\u20131>0[\/latex]. So [latex]x^{2}>1[\/latex]. This happens only when x is greater than 1 or less than [latex]\u22121[\/latex]:\u00a0[latex]x\\leq\u22121[\/latex] or [latex]x\\geq1[\/latex].<\/td>\n<\/tr>\n<tr>\n<td>[latex]f(x)=\\sqrt{{{x}^{2}}+10}[\/latex]<\/td>\n<td>There are no domain restrictions even though there is a variable under the radical. Since [latex]x^{2}\\ge0[\/latex], [latex]x^{2}+10[\/latex]\u00a0can never be negative. The least it can be is [latex]\\sqrt{10}[\/latex], so there is no danger of taking the square root of a negative number.<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<p>So, how exactly do you define the domain of a function?<\/p>\n<div class=\"textbox\">\n<h3>How To: Given a function written in equation form, find the domain<\/h3>\n<ol>\n<li>Identify the input values.<\/li>\n<li>Identify any restrictions on the input and exclude those values from the domain.\n<ul>\n<li>If there is a denominator in the function\u2019s formula, exclude any real numbers that cause the denominator to be equal to zero.\u00a0 To do this, set the denominator equal to zero and solve for [latex]x[\/latex] .<\/li>\n<li>If the function\u2019s formula contains an even root,\u00a0exclude any real numbers that result in a negative number in the radicand.\u00a0 To do this, set the radicand greater than or equal to\u00a0[latex]0[\/latex] and then solve.<\/li>\n<\/ul>\n<\/li>\n<li>Write the domain in interval form, making sure to exclude any restricted values from the domain.<\/li>\n<\/ol>\n<\/div>\n<div class=\"textbox exercises\">\n<h3>Example<\/h3>\n<p>Find the domain of the function [latex]f\\left(x\\right)={x}^{2}-1[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q480036\">Show Solution<\/span><\/p>\n<div id=\"q480036\" class=\"hidden-answer\" style=\"display: none\">\n<p>The input value, shown by the variable [latex]x[\/latex] in the equation, is squared and then the result is lowered by one. Any real number may be squared and then be lowered by one, so there are no restrictions on the domain of this function. The domain is the set of real numbers.<\/p>\n<p>In interval form, the domain of [latex]f[\/latex] is [latex]\\left(-\\infty ,\\infty \\right)[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>In our next example, we have a variable in the denominator, so we have to identify when the denominator will be equal to zero.<\/p>\n<div class=\"textbox exercises\">\n<h3>Example<\/h3>\n<p>Find the domain of the function [latex]f\\left(x\\right)=\\dfrac{x+1}{2-x}[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q995188\">Show Solution<\/span><\/p>\n<div id=\"q995188\" class=\"hidden-answer\" style=\"display: none\">\n<p>When there is a denominator, we want to include only values of the input that do not cause the denominator to be zero. So, we will set the denominator equal to 0 and solve for [latex]x[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]2-x=0[\/latex]<\/p>\n<p style=\"text-align: center;\">[latex]-x=-2[\/latex]<\/p>\n<p style=\"text-align: center;\">[latex]x=2[\/latex]<\/p>\n<p>Now, we will exclude\u00a0[latex]2[\/latex] from the domain. The answers are all real numbers where [latex]x<2[\/latex] or [latex]x>2[\/latex]. We can use a symbol known as the union, [latex]\\cup[\/latex], to combine the two sets. In interval notation, we write the solution: [latex]\\left(\\mathrm{-\\infty },2\\right)\\cup \\left(2,\\infty \\right)[\/latex].<\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images-archive-read-only\/wp-content\/uploads\/sites\/924\/2015\/11\/25200611\/CNX_Precalc_Figure_01_02_028n2.jpg\" alt=\"x is less than 2 or x is greater than 2 graphed on a number line. An open dot is plotted on 2 and arrows extend in both directions on the number line. The inequality can be written in interval notation as parentheses negative infinity comma 2 end parentheses union parentheses 2 comma infinity end parentheses.\" width=\"487\" height=\"164\" \/><\/p>\n<p>In interval form, the domain of [latex]f[\/latex] is [latex]\\left(-\\infty ,2\\right)\\cup \\left(2,\\infty \\right)[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"Ex:  The Domain of Rational Functions\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/v0IhvIzCc_I?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<p>In our next example, we will need to determine when the radicand is less than 0.<\/p>\n<div class=\"textbox exercises\">\n<h3>Example<\/h3>\n<p>Find the domain of the function [latex]f\\left(x\\right)=\\sqrt{7-x}[\/latex].<\/p>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q275485\">Show Solution<\/span><\/p>\n<div id=\"q275485\" class=\"hidden-answer\" style=\"display: none\">\n<p>When there is an even root in the formula, we exclude any real numbers that result in a negative number in the radicand.<\/p>\n<p>Set the radicand greater than or equal to zero and solve for [latex]x[\/latex].<\/p>\n<p style=\"text-align: center;\">[latex]7-x\\ge 0[\/latex]<\/p>\n<p style=\"text-align: center;\">[latex]-x\\ge -7[\/latex]<\/p>\n<p style=\"text-align: center;\">[latex]x\\le 7[\/latex]<\/p>\n<p>Now, we will exclude any number greater than 7 from the domain. The answers are all real numbers less than or equal to [latex]7[\/latex], or [latex]\\left(-\\infty ,7\\right][\/latex].<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p><iframe loading=\"lazy\" id=\"oembed-2\" title=\"Ex: Domain and Range of Square Root Functions\" width=\"500\" height=\"375\" src=\"https:\/\/www.youtube.com\/embed\/lj_JB8sfyIM?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-16630\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>College Algebra. <strong>Authored by<\/strong>: Jay Abramson, et al.. <strong>Provided by<\/strong>: OpenStax. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\">http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download for Free at: http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t <\/section>","protected":false},"author":169554,"menu_order":14,"template":"","meta":{"_candela_citation":"[{\"type\":\"cc\",\"description\":\"College Algebra\",\"author\":\"Jay Abramson, et al.\",\"organization\":\"OpenStax\",\"url\":\"http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\",\"project\":\"\",\"license\":\"cc-by\",\"license_terms\":\"Download for Free at: http:\/\/cnx.org\/contents\/fd53eae1-fa23-47c7-bb1b-972349835c3c@5.175\"}]","CANDELA_OUTCOMES_GUID":"52cea8e435fd4e929118e848314a4c32, fe1bb8fb8baf42eeb8bc59f08f3f2d80","pb_show_title":"on","pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-16630","chapter","type-chapter","status-publish","hentry"],"part":16203,"_links":{"self":[{"href":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/wp-json\/pressbooks\/v2\/chapters\/16630","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/wp-json\/wp\/v2\/users\/169554"}],"version-history":[{"count":8,"href":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/wp-json\/pressbooks\/v2\/chapters\/16630\/revisions"}],"predecessor-version":[{"id":20518,"href":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/wp-json\/pressbooks\/v2\/chapters\/16630\/revisions\/20518"}],"part":[{"href":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/wp-json\/pressbooks\/v2\/parts\/16203"}],"metadata":[{"href":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/wp-json\/pressbooks\/v2\/chapters\/16630\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/wp-json\/wp\/v2\/media?parent=16630"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/wp-json\/pressbooks\/v2\/chapter-type?post=16630"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/wp-json\/wp\/v2\/contributor?post=16630"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/courses.lumenlearning.com\/wm-developmentalemporium\/wp-json\/wp\/v2\/license?post=16630"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}