{"id":6632,"date":"2017-05-02T20:10:04","date_gmt":"2017-05-02T20:10:04","guid":{"rendered":"https:\/\/courses.lumenlearning.com\/prealgebra\/?post_type=chapter&#038;p=6632"},"modified":"2019-05-24T18:02:55","modified_gmt":"2019-05-24T18:02:55","slug":"solve-equations-using-integers-the-division-property-of-equality","status":"publish","type":"chapter","link":"https:\/\/courses.lumenlearning.com\/wm-prealgebra\/chapter\/solve-equations-using-integers-the-division-property-of-equality\/","title":{"raw":"Introduction to Solving One-step Equations Using Integers","rendered":"Introduction to Solving One-step Equations Using Integers"},"content":{"raw":"<h2>What you'll learn to do: Solve one-step equations using integers<\/h2>\r\n[caption id=\"attachment_12953\" align=\"aligncenter\" width=\"744\"]<a href=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/277\/2017\/05\/22232205\/apple-2311042_960_720.jpg\"><img class=\"wp-image-12953 \" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/277\/2017\/05\/22232205\/apple-2311042_960_720.jpg\" alt=\"A basket of apples sitting in the grass\" width=\"744\" height=\"496\" \/><\/a> The apples are picked--now it's time to divvy them up![\/caption]\r\n\r\nAfter a day of apple picking, Jessica, Mark, and Kim decide to split up their apples equally. In their shared basket, they count [latex]39[\/latex] apples total. How many apples can each of them take home? To find out, they'll need to use division in a one-step variable equation. In this section, you'll learn\u00a0how to maintain equality on both sides of the equation and solve for a variable.\r\n\r\nBefore you get started, take this readiness quiz.\r\n<div class=\"textbox examples\">\r\n<h3>readiness quiz<\/h3>\r\n1)\r\n\r\n[ohm_question]144878[\/ohm_question]\r\n\r\nIf you missed this problem, review this example.\r\n<div class=\"textbox shaded\">\r\n\r\nEvaluate [latex]x+7[\/latex] when\r\n<ol>\r\n \t<li>[latex]x=3[\/latex]<\/li>\r\n \t<li>[latex]x=12[\/latex]<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"998927\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"998927\"]\r\n\r\nSolution:\r\n\r\n1. To evaluate, substitute [latex]3[\/latex] for [latex]x[\/latex] in the expression, and then simplify.\r\n<table id=\"eip-id1166566546426\" class=\"unnumbered unstyled\" summary=\"The image shows the given expression x plus 7. Substitute 3 for x. The expression becomes 3 plus x which is 10.\" data-label=\"\">\r\n<tbody>\r\n<tr>\r\n<td><\/td>\r\n<td>[latex]x+7[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Substitute.<\/td>\r\n<td>[latex]\\color{red}{3}+7[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Add.<\/td>\r\n<td>[latex]10[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\nWhen [latex]x=3[\/latex], the expression [latex]x+7[\/latex] has a value of [latex]10[\/latex].\r\n2. To evaluate, substitute [latex]12[\/latex] for [latex]x[\/latex] in the expression, and then simplify.\r\n<table id=\"eip-id1166566410105\" class=\"unnumbered unstyled\" summary=\"The image shows the given expression x plus 7, substitute 12 for x. The expression becomes 12 plus x which is 19.\" data-label=\"\">\r\n<tbody>\r\n<tr>\r\n<td><\/td>\r\n<td>[latex]x+7[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Substitute.<\/td>\r\n<td>[latex]\\color{red}{12}+7[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Add.<\/td>\r\n<td>[latex]19[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\nWhen [latex]x=12[\/latex], the expression [latex]x+7[\/latex] has a value of [latex]19[\/latex].\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n2)\r\n\r\n[ohm_question]141843[\/ohm_question]\r\n\r\nIf you missed this problem, review the example below.\r\n<div class=\"textbox shaded\">\r\n\r\nEvaluate [latex]9x - 2,[\/latex] when\r\n<ol>\r\n \t<li>[latex]x=5[\/latex]<\/li>\r\n \t<li>[latex]x=1[\/latex]<\/li>\r\n<\/ol>\r\n[reveal-answer q=\"711463\"]Show Solution[\/reveal-answer]\r\n[hidden-answer a=\"711463\"]\r\n\r\nSolution\r\nRemember [latex]ab[\/latex] means [latex]a[\/latex] times [latex]b[\/latex], so [latex]9x[\/latex] means [latex]9[\/latex] times [latex]x[\/latex].\r\n1. To evaluate the expression when [latex]x=5[\/latex], we substitute [latex]5[\/latex] for [latex]x[\/latex], and then simplify.\r\n<table id=\"eip-id1168469462966\" class=\"unnumbered unstyled\" summary=\"The image shows the given expression nine x minus 2. Substitute 5 for x. The expression becomes 9 times 5 minus 2. Multiply first. Nine times 5 is 45 and the expression is now 45 minus 2. Subtract to get 43.\" data-label=\"\">\r\n<tbody>\r\n<tr>\r\n<td><\/td>\r\n<td>[latex]9x-2[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Substitute [latex]\\color{red}{5}[\/latex] for x.<\/td>\r\n<td>[latex]9\\cdot\\color{red}{5}-2[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Multiply.<\/td>\r\n<td>[latex]45-2[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Subtract.<\/td>\r\n<td>[latex]43[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\n2. To evaluate the expression when [latex]x=1[\/latex], we substitute [latex]1[\/latex] for [latex]x[\/latex], and then simplify.\r\n<table id=\"eip-id1168468440939\" class=\"unnumbered unstyled\" summary=\"The image shows the given expression nine x minus 2. Substitute 1 for x. The expression becomes 9 times 1 minus 2. Multiply first. Nine times 1 is 9 and the expression is now 9 minus 2. Subtract to get 7.\" data-label=\"\">\r\n<tbody>\r\n<tr>\r\n<td><\/td>\r\n<td>[latex]9x-2[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Substitute [latex]\\color{red}{1}[\/latex] for x.<\/td>\r\n<td>[latex]9(\\color{red}{1})-2[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Multiply.<\/td>\r\n<td>[latex]9-2[\/latex]<\/td>\r\n<\/tr>\r\n<tr>\r\n<td>Subtract.<\/td>\r\n<td>[latex]7[\/latex]<\/td>\r\n<\/tr>\r\n<\/tbody>\r\n<\/table>\r\nNotice that in part 1 that we wrote [latex]9\\cdot 5[\/latex] and in part 2 we wrote [latex]9\\left(1\\right)[\/latex]. Both the dot and the parentheses tell us to multiply.\r\n\r\n[\/hidden-answer]\r\n\r\n<\/div>\r\n3)\r\n\r\n[ohm_question]144907[\/ohm_question]\r\n\r\nIf you missed this problem, review the following video\r\n\r\nhttps:\/\/www.youtube.com\/watch?v=Hub7ku7UHT4&feature=youtu.be\r\n\r\n<\/div>","rendered":"<h2>What you&#8217;ll learn to do: Solve one-step equations using integers<\/h2>\n<div id=\"attachment_12953\" style=\"width: 754px\" class=\"wp-caption aligncenter\"><a href=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/277\/2017\/05\/22232205\/apple-2311042_960_720.jpg\"><img loading=\"lazy\" decoding=\"async\" aria-describedby=\"caption-attachment-12953\" class=\"wp-image-12953\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/277\/2017\/05\/22232205\/apple-2311042_960_720.jpg\" alt=\"A basket of apples sitting in the grass\" width=\"744\" height=\"496\" \/><\/a><\/p>\n<p id=\"caption-attachment-12953\" class=\"wp-caption-text\">The apples are picked&#8211;now it&#8217;s time to divvy them up!<\/p>\n<\/div>\n<p>After a day of apple picking, Jessica, Mark, and Kim decide to split up their apples equally. In their shared basket, they count [latex]39[\/latex] apples total. How many apples can each of them take home? To find out, they&#8217;ll need to use division in a one-step variable equation. In this section, you&#8217;ll learn\u00a0how to maintain equality on both sides of the equation and solve for a variable.<\/p>\n<p>Before you get started, take this readiness quiz.<\/p>\n<div class=\"textbox examples\">\n<h3>readiness quiz<\/h3>\n<p>1)<\/p>\n<p><iframe loading=\"lazy\" id=\"ohm144878\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=144878&theme=oea&iframe_resize_id=ohm144878&show_question_numbers\" width=\"100%\" height=\"150\"><\/iframe><\/p>\n<p>If you missed this problem, review this example.<\/p>\n<div class=\"textbox shaded\">\n<p>Evaluate [latex]x+7[\/latex] when<\/p>\n<ol>\n<li>[latex]x=3[\/latex]<\/li>\n<li>[latex]x=12[\/latex]<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q998927\">Show Solution<\/span><\/p>\n<div id=\"q998927\" class=\"hidden-answer\" style=\"display: none\">\n<p>Solution:<\/p>\n<p>1. To evaluate, substitute [latex]3[\/latex] for [latex]x[\/latex] in the expression, and then simplify.<\/p>\n<table id=\"eip-id1166566546426\" class=\"unnumbered unstyled\" summary=\"The image shows the given expression x plus 7. Substitute 3 for x. The expression becomes 3 plus x which is 10.\" data-label=\"\">\n<tbody>\n<tr>\n<td><\/td>\n<td>[latex]x+7[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Substitute.<\/td>\n<td>[latex]\\color{red}{3}+7[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Add.<\/td>\n<td>[latex]10[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>When [latex]x=3[\/latex], the expression [latex]x+7[\/latex] has a value of [latex]10[\/latex].<br \/>\n2. To evaluate, substitute [latex]12[\/latex] for [latex]x[\/latex] in the expression, and then simplify.<\/p>\n<table id=\"eip-id1166566410105\" class=\"unnumbered unstyled\" summary=\"The image shows the given expression x plus 7, substitute 12 for x. The expression becomes 12 plus x which is 19.\" data-label=\"\">\n<tbody>\n<tr>\n<td><\/td>\n<td>[latex]x+7[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Substitute.<\/td>\n<td>[latex]\\color{red}{12}+7[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Add.<\/td>\n<td>[latex]19[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>When [latex]x=12[\/latex], the expression [latex]x+7[\/latex] has a value of [latex]19[\/latex].<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>2)<\/p>\n<p><iframe loading=\"lazy\" id=\"ohm141843\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=141843&theme=oea&iframe_resize_id=ohm141843&show_question_numbers\" width=\"100%\" height=\"150\"><\/iframe><\/p>\n<p>If you missed this problem, review the example below.<\/p>\n<div class=\"textbox shaded\">\n<p>Evaluate [latex]9x - 2,[\/latex] when<\/p>\n<ol>\n<li>[latex]x=5[\/latex]<\/li>\n<li>[latex]x=1[\/latex]<\/li>\n<\/ol>\n<div class=\"qa-wrapper\" style=\"display: block\"><span class=\"show-answer collapsed\" style=\"cursor: pointer\" data-target=\"q711463\">Show Solution<\/span><\/p>\n<div id=\"q711463\" class=\"hidden-answer\" style=\"display: none\">\n<p>Solution<br \/>\nRemember [latex]ab[\/latex] means [latex]a[\/latex] times [latex]b[\/latex], so [latex]9x[\/latex] means [latex]9[\/latex] times [latex]x[\/latex].<br \/>\n1. To evaluate the expression when [latex]x=5[\/latex], we substitute [latex]5[\/latex] for [latex]x[\/latex], and then simplify.<\/p>\n<table id=\"eip-id1168469462966\" class=\"unnumbered unstyled\" summary=\"The image shows the given expression nine x minus 2. Substitute 5 for x. The expression becomes 9 times 5 minus 2. Multiply first. Nine times 5 is 45 and the expression is now 45 minus 2. Subtract to get 43.\" data-label=\"\">\n<tbody>\n<tr>\n<td><\/td>\n<td>[latex]9x-2[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Substitute [latex]\\color{red}{5}[\/latex] for x.<\/td>\n<td>[latex]9\\cdot\\color{red}{5}-2[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Multiply.<\/td>\n<td>[latex]45-2[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Subtract.<\/td>\n<td>[latex]43[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>2. To evaluate the expression when [latex]x=1[\/latex], we substitute [latex]1[\/latex] for [latex]x[\/latex], and then simplify.<\/p>\n<table id=\"eip-id1168468440939\" class=\"unnumbered unstyled\" summary=\"The image shows the given expression nine x minus 2. Substitute 1 for x. The expression becomes 9 times 1 minus 2. Multiply first. Nine times 1 is 9 and the expression is now 9 minus 2. Subtract to get 7.\" data-label=\"\">\n<tbody>\n<tr>\n<td><\/td>\n<td>[latex]9x-2[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Substitute [latex]\\color{red}{1}[\/latex] for x.<\/td>\n<td>[latex]9(\\color{red}{1})-2[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Multiply.<\/td>\n<td>[latex]9-2[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>Subtract.<\/td>\n<td>[latex]7[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Notice that in part 1 that we wrote [latex]9\\cdot 5[\/latex] and in part 2 we wrote [latex]9\\left(1\\right)[\/latex]. Both the dot and the parentheses tell us to multiply.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<p>3)<\/p>\n<p><iframe loading=\"lazy\" id=\"ohm144907\" class=\"resizable\" src=\"https:\/\/ohm.lumenlearning.com\/multiembedq.php?id=144907&theme=oea&iframe_resize_id=ohm144907&show_question_numbers\" width=\"100%\" height=\"150\"><\/iframe><\/p>\n<p>If you missed this problem, review the following video<\/p>\n<p><iframe loading=\"lazy\" id=\"oembed-1\" title=\"Write Algebraic Expressions from Statements: Form  ax+b and a(x+b)\" width=\"500\" height=\"281\" src=\"https:\/\/www.youtube.com\/embed\/Hub7ku7UHT4?feature=oembed&#38;rel=0\" frameborder=\"0\" allowfullscreen=\"allowfullscreen\"><\/iframe><\/p>\n<\/div>\n\n\t\t\t <section class=\"citations-section\" role=\"contentinfo\">\n\t\t\t <h3>Candela Citations<\/h3>\n\t\t\t\t\t <div>\n\t\t\t\t\t\t <div id=\"citation-list-6632\">\n\t\t\t\t\t\t\t <div class=\"licensing\"><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Shared previously<\/div><ul class=\"citation-list\"><li>Apple Basket. <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/pixabay.com\/p-2311042\/?no_redirect\">https:\/\/pixabay.com\/p-2311042\/?no_redirect<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/about\/cc0\">CC0: No Rights Reserved<\/a><\/em><\/li><li>Write Algebraic Expressions from Statements: Form ax+b and a(x+b). <strong>Authored by<\/strong>: James Sousa (Mathispower4u.com). <strong>Located at<\/strong>: <a target=\"_blank\" href=\"https:\/\/www.youtube.com\/watch?v=Hub7ku7UHT4&#038;feature=youtu.be\">https:\/\/www.youtube.com\/watch?v=Hub7ku7UHT4&#038;feature=youtu.be<\/a>. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em><\/li><li>Question ID: 144878, 141843, 144907. <strong>Authored by<\/strong>: Lumen Learning. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: IMathAS Community License CC-BY + GPL<\/li><\/ul><div class=\"license-attribution-dropdown-subheading\">CC licensed content, Specific attribution<\/div><ul class=\"citation-list\"><li>Prealgebra. <strong>Provided by<\/strong>: OpenStax. <strong>License<\/strong>: <em><a target=\"_blank\" rel=\"license\" href=\"https:\/\/creativecommons.org\/licenses\/by\/4.0\/\">CC BY: Attribution<\/a><\/em>. <strong>License Terms<\/strong>: Download for free at http:\/\/cnx.org\/contents\/caa57dab-41c7-455e-bd6f-f443cda5519c@9.757<\/li><\/ul><\/div>\n\t\t\t\t\t\t <\/div>\n\t\t\t\t\t <\/div>\n\t\t\t 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