In the following exercises (1-6), evaluate each integral in terms of an inverse trigonometric function.
1. [latex]{\displaystyle\int }_{0}^{\sqrt{3}\text{/}2}\frac{dx}{\sqrt{1-{x}^{2}}}[/latex]
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2. [latex]{\displaystyle\int }_{-1\text{/}2}^{1\text{/}2}\frac{dx}{\sqrt{1-{x}^{2}}}[/latex]
3. [latex]{\displaystyle\int }_{\sqrt{3}}^{1}\frac{dx}{\sqrt{1+{x}^{2}}}[/latex]
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4. [latex]{\displaystyle\int }_{1\text{/}\sqrt{3}}^{\sqrt{3}}\frac{dx}{1+{x}^{2}}[/latex]
5. [latex]{\displaystyle\int }_{1}^{\sqrt{2}}\frac{dx}{|x|\sqrt{{x}^{2}-1}}[/latex]
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6. [latex]{\displaystyle\int }_{1}^{2\text{/}\sqrt{3}}\frac{dx}{|x|\sqrt{{x}^{2}-1}}[/latex]
